One type of sunburn occurs on exposure to UV light of wavelength in the vicinity of 320 nm
1.)How many photons are in a 1.15 mJ burst of this radiation?
2.)These UV photons can break chemical bonds in your skin to cause sunburn—a form of radiation damage. If the 320 nm radiation provides exactly the energy to break an average chemical bond in the skin, estimate the average energy of these bonds in kJ/mol.

The negative impact of polyurea is It needs to be reapplied to surfaces frequently. Option D.

Studies have shown that polyurea coatings can increase the deflection of steel components, especially when applied to the exterior facing the blast. Polyurea is a commonly used polymer in moisture-resistant coating systems. Polyurea does not emit CO2 or other harmful gases during manufacturing or use.

Basic components can be manufactured in a climate-neutral manner using renewable energy allowing timely action to be taken regarding the ecological footprint as well. Cured polyurea has a high glass transition temperature and heat distortion temperature, but will burn when exposed to an open flame. It will self-extinguish when the flame is removed. Polyurea coatings provide a fast-curing durable flexible protective barrier that prevents water damage and harmful chemicals from destroying virtually any structure.

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The notch sensitivity and fatigue stress concentration factors for the bar are calculated to determine the mean and alternating stresses and find the fatigue strength for different cycles.

To calculate the notch sensitivity and fatigue stress concentration factors, we need to consider the presence of the 10 mm hole in the center of the 30 mm side of the bar. The notch sensitivity factor quantifies the effect of the hole on the stress concentration, while the fatigue stress concentration factor determines the increase in stress due to cyclic loading.

The mean stress (σm) is the average of the minimum (F_min) and maximum (F_max) axial loads applied to the bar. The alternating stress (σa) is half the difference between F_max and F_min.

The fatigue strength for a certain number of cycles is determined by applying the appropriate factors to the ultimate tensile strength (S_Ut) or yield strength (S_y) of the material. The fatigue strength is typically given for a specified number of cycles, such as 100, 10,000, 100,000, or 1,000,000 cycles. The fatigue strength for infinite life refers to the stress level below which the material can withstand an unlimited number of cycles without failure.

To provide accurate values for the notch sensitivity, fatigue stress concentration factors, mean and alternating stresses, and fatigue strength for the specified number of cycles, further calculations and data specific to the material properties and geometry of the bar are required.

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Answer:

probaby not

Explanation:

you might get thrown in jail tho

After the collision, the two cars stick together. Find the final velocity of the two cars would be 0.667 meters per second as per the conservation of the momentum after the collision.

It is the type of collision in which the total momentum as well as the kinetic energy on the system is conserved.

As given in the problem we have to find the velocity of the two cars if, after the collision, the two cars stick together,

As per the conservation of the momentum,

The total initial momentum of the cars before the collision = The total final momentum of the cars after the collision

1 × 2 + 2 × 0  = ( 1 + 2 ) × V

2 + 0 = 3 × V

V = 2 / 3

V = 0.667 meters per second

Thus, after the collision, the two cars stick together, then the final velocity of the two cars would be 0.667 meters per second

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Answer:

Explanation:

Capacity: the max amount that something can contain.

"the capacity of the freezer is 1.1 cubic feet"

capacitor: device for storing electrical energy, includes two conductor that are close to one another and insulated from each other. A simple example is a parallel-plate capacitor.

Source: Britannica.com

Answer:

Explanation:

To raise the pH of 4.00 liters of 25 mM glycine, pH 1.90, to a final pH of 9.70, 1.06 moles of OH- are required.

In this case, we are starting with a solution of glycine that has a pH of 1.90, which is very acidic. To raise the pH to 9.70, we need to neutralize the H+ ions in the solution, which can be done by adding OH- ions. The number of moles of OH- ions required can be calculated using the formula:

Δn = ΔV * ΔC

where Δn is the change in moles, ΔV is the change in volume, and ΔC is the change in concentration. Since the volume of the solution is 4.00 liters, and the concentration of glycine is 25 mM, we can calculate the change in moles of OH- as follows:

Δn = 4.00 liters * (10^(9.70 - 1.90) * 25 mM) = 1.06 moles

So, to raise the pH of 4.00 liters of 25 mM glycine, pH 1.90, to a final pH of 9.70, 1.06 moles of OH- are required.

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Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      \(v_{oy}\) = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = \(v_{oy}\) - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

The nail attract the pins because current will generate and therefore it will attract the nails.

A stream of charged particles, such as electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current.

The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.  Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles.

Electrons flowing over a wire are frequently used as charge carriers in electric circuits. They can be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons are the charge carriers in plasma, an ionized gas.

Therefore, The nail attract the pins because current will generate and therefore it will attract the nails.

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There are many ways to report fraud like hotlines, online reporting, email or postal mail, and in person reporting.

There are several ways to report potential fraud, waste, and abuse (FWA) depending on the situation and the reporting individual's preference.

It is important for individuals to feel confident that their report will be taken seriously and treated confidentially.

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Given :

A car drives 10 km with a speed of 72 km/hr and then runs out of gas.

Then you walk 2 km for the next 30 min  until you find a gas station .

To Find :

The average speed of whole journey .

Solution :

Average speed is given by :

\(v_{avg}=\dfrac{\text{Total distance covered}}{\text{Total time taken}}\\\\v_{avg}=\dfrac{10+2}{\dfrac{10}{72}+\dfrac{1}{2}}\\\\\\v_{avg}=18.78\ km/hr\)

Hence , this is the required solution .

Answer:

Here you go! Hope it Helps

Explanation:

mixer, nuts, bolts, washers

and

rusted nails

Answer:

The Correct answer is rusted nails and pastries

Explanation:

I know because I had this as one of my questions and I did rusted nails and pastries and got it correct.

Hope this helps! :)

The complete nuclear equation is ⁴²₁₉K -> ⁴²₂₀Ca + ⁰₋₁e and the type of decay is beta decay (last option)

To obtain the complete equation, we first obtain the missing part. The missing part of the equation can be obtain as follow:

Thus, the equation becomes:

⁴²₁₉K -> ʸₓZ + ⁰₋₁e

Now, can obtain the value of x, y and Z. Details below::

for x

19 = x - 1

Collect like terms

x = 19 + 1

x = 20

For y

42 = y + 0

y = 42

For Z

ʸₓZ => ⁴²₂₀Z => ⁴²₂₀Ca

Thus, the complete equation is:

⁴²₁₉K -> ⁴²₂₀Ca + ⁰₋₁e

In nuclear reaction, the symbol ⁰₋₁e represents beta decay.

Therefore, we can conclude that the correct answer to the question is:

⁴²₁₉K -> ⁴²₂₀Ca + ⁰₋₁e, beta decay (last option)

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If the current in a long straight wire is increasing, the current is induced in the circular loop will be generated in the nearby circular loop.

Faraday's Law states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux passing through it. As the current in the straight wire increases, the magnetic field around it strengthens, and the change in magnetic flux through the circular loop causes an induced current. The direction of this induced current is determined by Lenz's Law, which states that the induced current will flow in such a way as to oppose the change in magnetic flux causing it.

In this case, as the magnetic field due to the straight wire increases, the induced current in the circular loop will flow in a direction that generates a magnetic field opposing the increase in the straight wire's magnetic field. The magnitude of the induced current depends on the rate of change of the magnetic field, the loop's size, shape, and distance from the straight wire, as well as the resistance of the loop's material. If the current in a long straight wire is increasing, the current is induced in the circular loop will be generated in the nearby circular loop.

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Let me try:

Normal force= 169.74N

Coefficient of kinetic friction= 0.577

Explanation

a. For a given inclined plane, normal friction is equal to the force perpendicular to the plane which is equal to

mgcos theta = 20×9.8× cos30 = 169.74N

b. The coefficient of kinetic friction for an inclined plane is given as

tan theta =tan 30 = 0.577

Holding Brick 2 in place requires more force than holding Brick 1 just beneath the water's surface due to the higher pressure and buoyant force acting on it at a greater depth.

The force needed to hold Brick 2 in place underwater is greater than the force needed to hold Brick 1 just beneath the surface. This difference in force is primarily due to the increased pressure acting on Brick 2 as a result of its deeper position in the water.

In this scenario, there are two main forces acting on the bricks: the gravitational force, also known as weight (W), and the buoyant force (Fb). The weight of the bricks remains constant regardless of their position, as it depends only on their mass and the acceleration due to gravity. The buoyant force, on the other hand, depends on the volume of fluid displaced by the bricks and the density of the fluid, which in this case is water.

The pressure in a fluid increases with depth, which means that the buoyant force acting on Brick 2 is greater than that acting on Brick 1. Consequently, to keep Brick 2 submerged at a depth of 2 feet, you would need to exert a greater force to counteract the increased buoyant force.

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The total distance travelled is 100 m.

We know that distance is a scalar quantity. Let us note that scalar quantities are the quantities that do not have a direction rather they do have  magnitude. This is where the vector is different from the scalar quantity in physics.

Looking at this description, we are told that the polar bear walks 40 meters North, then 20 meters East , then 40 meters south. We can see that the total distance can be obtained by the addition of all the distances travelled.

Total distance travelled is; 40 + 20 + 40 = 100 m

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A spherical interplanetary probe, with a diameter of 2 m, is sent out into the solar system.  If the electronics inside the probe is generating heat at a rate of 100 W/m3, determine the incident radiation rate on the probe surface is as follow:

The amount of incident radiation that falls on a spherical interplanetary probe can be determined using the following steps:

Step 1: Find the surface area of the probe.

The surface area of the probe can be found using the formula for the surface area of a sphere which is:

A = 4πr²

Where A is the surface area and r is the radius of the sphere.

Since the diameter of the probe is given, the radius can be found by dividing the diameter by

2.r = d/2 = 2/2 = 1 m

Hence, the surface area of the probe is:

A = 4πr²= 4π(1)²= 4π m²Step 2:

Find the net radiation heat transfer rate.The net radiation heat transfer rate can be found using the following formula:

Qnet = εσA(Tprobe⁴ − Ts⁴)

Where Qnet is the net radiation heat transfer rate, ε is the emissivity of the probe surface, σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴), A is the surface area of the probe, Tprobe is the temperature of the probe surface, and Ts is the temperature of space.

Here, the temperature of space is given as 0 K while the temperature of the probe surface is -40°C.

So, the temperatures need to be converted to Kelvin. Tprobe

= (−40 + 273.15) K= 233.15 KTs = 0 K

Hence, Qnet = εσA(Tprobe⁴ − Ts⁴)

= 0.9 × 5.67 × 10⁻⁸ × 4π × 1²(233.15⁴ − 0⁴)

= 629.21 W

Step 3: Find the heat generation rate of the electronics inside the probe.

The heat generation rate of the electronics inside the probe is given as 100 W/m³. Since the volume of the probe can be found using the formula for the volume of a sphere which is:

V = (4/3)πr³= (4/3)π(1)³= 4.19 m³

Then, the total heat generated by the electronics inside the probe is:

Qe = 100 W/m³ × 4.19 m³

= 419 W

Step 4: Find the incident radiation rate on the probe surface.The incident radiation rate on the probe surface is the sum of the net radiation heat transfer rate and the heat generation rate of the electronics inside the probe. Hence, the incident radiation rate is:

Qi = Qnet + Qe

= 629.21 W + 419 W

= 1048.21 W

Therefore, the incident radiation rate on the probe surface is 1048.21 W.

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False. Hydrostatic pressure force does not always act on the centroid of the area.

The statement that hydrostatic pressure force always acts on the centroid of the area is false. Hydrostatic pressure is the pressure exerted by a fluid at rest due to the weight of the fluid above it. It depends on the depth and density of the fluid and is perpendicular to any surface it acts upon.

When considering a submerged surface, such as a submerged plate or wall, the hydrostatic pressure force is indeed applied normal to the surface. However, this force does not necessarily act at the centroid of the area. The distribution of hydrostatic pressure forces depends on the shape and orientation of the surface.

For irregularly shaped surfaces or surfaces with varying depths, the hydrostatic pressure force acts differently at different points. It follows the principle of Pascal's law, which states that the pressure at a point in a fluid is transmitted equally in all directions. As a result, the force distribution can vary across the surface.

In summary, the hydrostatic pressure force does not always act on the centroid of the area. Its distribution depends on the shape, orientation, and depth of the submerged surface, following the principles of Pascal's law.

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Answer:

1280m

Explanation:

Answer:

c.water and calcium chloride

Explanation:

i took the test

Answer:

water and calcium chloride

Explanation:

→ Pure substances can be made of atoms that are attracted to each other or atoms that are not attracted to each other. Which type of pure substance can create elaborate structures?

Option c) Atoms that are not attracted to each other because they will form bonds with each other and create a larger structure.

Answer:

Zero.

Explanation:

Given that a rock is thrown vertically upward at an initial velocity of 70 m/s. What is the approximate acceleration of the rock when it reaches its maximum height

(assume upward is the positive y direction)?

Since the reached the maximum height, the final velocity V will be equal to zero.

Using the first equation of motion to find the time.

And since it is a vertical direction, and not horizontal, the acceleration a will be equal to zero.

Answer:

Answer is given in this paper.

                                               Thank You

                                     Please mark me Brainlest.

Answer:

Ratio of wire 2 to wire 1 is 0.5 : 1

Explanation:

Wire 1:

length = L

radius = r

Wire 2:

length = 2L

radius = 2r

Resistance of a conductor varies directly as the length and inversely as the cross sectional area. Mathematically

\(R = \frac{pl}{a}\)

l = length of conductor

a = cross sectional area of the conductor

p = resistivity of the material with which the conductor is made.

since we are considering the same material, we can ignore the resistivity of the wire.

For wire 1

cross sectional area = \(\pi r^{2}\)

therefore,

resistance R = \(\frac{L}{\pi r^{2} }\)

For the second wire 2

cross sectional area = \(4\pi r^{2}\)

therefore,

resistance R = \(\frac{2L}{4\pi r^{2} }\)

Ratio of wire 2 to wire 1 will be

\(\frac{2L}{4\pi r^{2} }\) ÷ \(\frac{L}{\pi r^{2} }\) = \(\frac{2L}{4\pi r^{2} }\) x \(\frac{\pi r^{2} }{L}\)

Ratio of resistance of wire 2 to wire 1 = 2/4 = 0.5 : 1

The cross product of A and B is perpendicular to both A and B.

A × B = (4i + 2j + 2k) × (4i - 4j + 8k)

A × B = 16 (i × i) - 16 (i × j) + 32 (i × k) + 8 (j × i) - 8 (j × j) + 16 (j × k) + 8 (k × i) - 8 (k × j) + 16 (k × k)

A × B = -16 (i × j) - 32 (k × i) - 8 (i × j) + 16 (j × k) + 8 (k × i) + 8 (j × k)

A × B = -16k - 32j - 8k + 16i + 8j + 8i

A × B = 24i - 24j - 24k

The magnitude of A × B is

||A × B|| = 24 ||i - j - k|| = 24√3

Dividing A × B by its magnitude gives a unit vector,

(A × B)/||A × B|| = 1/√3 (i - j - k)

If the resistor in a simple circuit is replaced with another resistor that has 75% lower conductivity, the current (I) in the circuit would decrease.

In a simple circuit, the current flowing through a metallic resistor is determined by Ohm's Law, which states that the current (I) is directly proportional to the voltage (V) applied across the resistor and inversely proportional to the resistance (R) of the resistor (I = V/R).

When the resistor is replaced with another resistor that has 75% lower conductivity, it means that the new resistor has a higher resistance compared to the original resistor. Since resistance is in the denominator of the current equation, an increase in resistance leads to a decrease in current.

Therefore, the current (I) in the circuit would decrease when the resistor with lower conductivity is introduced. This relationship between resistance and current is consistent with Ohm's Law, which establishes the fundamental relationship between voltage, current, and resistance in a circuit.

By manipulating the resistance value, the current flowing through the circuit can be controlled.

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Answer:

true

Explanation:

is an important component of physical fitness and has many positive effects on the body

Answer:

It's True

Developing flexibility helps yourself:

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Answer:

Gravity

Explanation: