ou have not yet been cleared for the approach, but you are being vectored to the ILS approach course. It is clear that you will pass through the localizer course unless you take action. You should A. continue as assigned and query ATC. B. turn outbound and complete the procedure turn. C. turn inbound and join the final approach course.
Answers
Based on the given scenario, the appropriate action would be to B. turn outbound and complete the procedure turn.
Since you have not been cleared for the approach and are being vectored to the ILS approach course, it is clear that you will pass through the localizer course unless you take action. In this situation, the standard procedure is to turn outbound and complete the procedure turn.
The procedure turn allows you to safely maneuver and align with the final approach course. Once you have completed the procedure turn, you can then turn inbound and join the final approach course to continue the approach.
It is important to follow the prescribed procedures and communicate with air traffic control (ATC) for further guidance or clearance if needed. However, in this scenario, the most appropriate initial action would be to turn outbound and complete the procedure turn before proceeding further.
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Related Questions
What is the speed of a car that
accelerates at a rate of 10 m/s2 for a
total of 25 seconds?
Answers
Answer:
250 m/sExplanation:
The speed of the car can be found by using the formula
v = a × twhere
a is the acceleration
v is the speed
t is the time
From the question we have
v = 10 × 25
We have the final answer as
250 m/sHope this helps you
13.41 A 15 m long garden hose has an inner diameter of 2.5 cm. One end is connected to a spigot; 20 degree C water flows from the other end at a rate of 1.2 L/s. What is the gauge pressure at the spigot end of the hose?A 1900 paB 2700 paC 4200 paC 5800 paE 7300 pa
Answers
Answer: the gauge pressure at the spigot end of the hose is approximately 4204 Pa, which is closest to option C: 4200 Pa.
Explanation: We can use Bernoulli's equation to determine the gauge pressure at the spigot end of the hose. Bernoulli's equation relates the pressure, velocity, and height of a fluid in a horizontal pipe. For an incompressible fluid (like water) flowing through a horizontal pipe of constant diameter, Bernoulli's equation can be written as:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
where:
P1 = pressure at the spigot end (unknown)
v1 = velocity at the spigot end (0 m/s, since the water is not moving initially)
P2 = pressure at the end of the hose (unknown)
v2 = velocity at the end of the hose (1.2 L/s = 0.0012 m^3/s ÷ (π/4)(0.025 m)^2 = 1.215 m/s)
ρ = density of water at 20°C = 998 kg/m^3
We can simplify the equation by assuming that the pressure at the end of the hose (P2) is atmospheric pressure (101325 Pa), since the water is flowing out into the open air. Plugging in the values and solving for P1, we get:
P1 = P2 + (1/2)ρv2^2 - (1/2)ρv1^2
= 101325 Pa + (1/2)(998 kg/m^3)(1.215 m/s)^2 - (1/2)(998 kg/m^3)(0 m/s)^2
≈ 4204 Pa
Therefore, the gauge pressure at the spigot end of the hose is approximately 4204 Pa, which is closest to option C: 4200 Pa.
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A 5.0 kg bike moving 10 m/s comes to a complete stop in 2 seconds. What is the average force of the brakes on the bike?
Answers
Answer:
25 N
Explanation:
Force : This is defined as the product of mass and acceleration. The unit of force is Newton or kgm/s².
From the question,
F = ma......................... Equation 1
Where F = Force of the brake, m = mass of the break, a = acceleration.
But,
a = v/t.................. Equation 2
where v = velocity, t = time.
Substitute equation 2 into equation equation 1
F = m(v/t)................ Equation 3
Given: m = 5.0 kg, v = 10 m/s, t = 2 seconds
F = 5(10/2)
F = 25 N.
Hence the average force of the brakes on the bike is 25 N
Answer:
The average force of the brakes on the bike is 25.0 N
Explanation:
The parameters given in the question are,
Mass, m = 5.0kg
Initial velocity, u = 10 m/s
Time, t = 2 sec
Since the bike came to a complete stop, then
Final velocity, v = 0 m/s
To determine the average force of the brakes on the bike; From Newton's second law of motion, Force is given as
F = ma
Where F is the force in N (Newtons)
m is the mass in kg
and a is acceleration in m/s²
Hence, we will first determine the acceleration.
From one of the equations of kinematics for linear motion,
\(v = u + at\)
Then, \(a = \frac{v - u}{t\\}\)
Putting the given parameters into the above equation, we get
\(a = \frac{0 - 10}{2}\)
\(a = \frac{-10}{2}\\ a = - 5\)m/s²
The negative sign indicates deceleration since the bike came to a stop,
Hence, \(a = 5\) m/s²
From,
F = ma
F = 5.0 × 5
F = 25.0 N
A friend frequently misses the morning
school bus. Use the scientific method to
address this problem.
Answers
Answer: Heyaa! ~
State of the problem is that your friend routinely misses the school bus.
Explanation:
What are the causes for his missing the school bus:
Not waking early enoughToo long breakfastToo far to the bus stop.Deliberately tries to miss the bus.Hopefully this helps you!
-Matthew ^^
two step dimensional analysis
(step by step)
convert :
4900mm to cm
5.59kL to quarts
Answers
When we convert 4900mm from two-step dimensional analysis it would be 490 cm and 5.59kL to 5923.667 quarts.
What is dimensional Analysis?Dimensional Analysis is a technique for analysis where physical quantities are expressed in terms of their basic dimensions and is frequently applied when there is insufficient data to create accurate equations.
As given in the problem we have to convert
4900mm to cm
As we know that there are 1000 mm in 1 m
1000 mm = 1 m
4900 mm = 4.9 m
1 m = 100 cm
4.9 m = 4.9×100
=490 cm
As we have to convert 5.59kL to quarts
1 Kiloliter = 1056.69 US liquid quart
5.59kL = 5.59 ×1056.69 quarts
=5923.667 quarts
Thus, we converted 4900mm to 490 cm and 5.59kL to 5923.667 quarts.
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The Sun has a temperature of 5780 K. What is the wavelength and frequency where its spectrum peaks? Which color does this correspond to? How does the energy flux of the Sun compare that of a red dwarf whose temperature is a mere 2,000 K, and is of the same size?
Answers
1) The wavelength at which the Sun's spectrum peaks is approximately 5.02 x 10^-7 m, and the frequency at which it peaks is approximately 5.99 x 10^14 H
2) The color corresponding to this wavelength is yellow-green
3) The energy flux of the Sun is much higher than that of a red dwarf of the same size, by a factor of approximately 1.9 x 10^4.
To determine the wavelength and frequency at which the Sun's spectrum peaks, we can use Wien's displacement law which states that the peak wavelength of blackbody radiation is inversely proportional to the temperature of the object. Mathematically,
λ_max = b/T
where λ_max is the peak wavelength, T is the temperature of the object, and b is Wien's displacement constant, which is equal to approximately 2.898 x 10^-3 m*K.
Substituting T = 5780 K and b = 2.898 x 10^-3 m*K, we get:
λ_max = (2.898 x 10^-3 m*K) / (5780 K) = 5.02 x 10^-7 m
Therefore, the wavelength at which the Sun's spectrum peaks is approximately 5.02 x 10^-7 m.
We can also use the relationship between wavelength and frequency of electromagnetic radiation:
c = λf
where c is the speed of light (3 x 10^8 m/s), λ is the wavelength, and f is the frequency.
Rearranging the equation to solve for f, we get:
f = c/λ = (3 x 10^8 m/s) / (5.02 x 10^-7 m) = 5.99 x 10^14 Hz
2) The color corresponding to this wavelength is yellow-green, which is in the middle of the visible spectrum.
3) The energy flux of a star is proportional to its surface temperature to the fourth power (Stefan-Boltzmann law), so the energy flux of the Sun can be calculated as:
E_Sun = σT^4A
where σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2 K^4), T is the temperature of the Sun (5780 K), and A is the surface area of the Sun. Assuming the Sun has a radius of approximately 696,340 km, we get:
A_Sun = 4π(696,340 km)^2 = 6.09 x 10^18 m^2
Substituting these values, we get:
E_Sun = (5.67 x 10^-8 W/m^2 K^4) x (5780 K)^4 x (6.09 x 10^18 m^2) = 3.85 x 10^26 W
Now, let's compare this to the energy flux of a red dwarf with a temperature of 2000 K. Using the same equation, we get:
E_red dwarf = (5.67 x 10^-8 W/m^2 K^4) x (2000 K)^4 x (6.09 x 10^18 m^2) = 2.03 x 10^22 W
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Which of the following is a layer of the solid Earth? A. convecting mantle B. Ring of Fire C. biosphere D. atmosphere
Answers
Answer:
It's a cause that's the last layer
Answer:
I believe the answer is A
Explanation:
It is not the ring of fire because the ring of fire is the result of tectonic plates moving. It is not the biosphere because biosphere is the regions of the surface. The convecting mantle is the solid layer of the Earth because the mantle is mostly solid. The atmosphere is a solid plastic layer of the Earth. I hope this helps.
Your roof radiates heat away at night. At what net rate does the heat radiate from a 275 m² black roof on a night when the roof temperature is 33°C in the surrounding temperature is 14°C? The emissivity of the roof is 0.900.
Answers
We are asked to determine the net rate of radiation of a roof given its area and its emisivity. To do that we will use the following formula:
\(P_{net}=\sigma eA(T_0^4-T^4)\)Where:
\(\begin{gathered} P_{net}=\text{ net rate of radiation} \\ \sigma=\text{ Stefan-Boltzmann's constant} \\ e=\text{ emisivity} \\ A=\text{ area} \\ T_0=\text{ surrounding temperature} \\ T=\text{ temperature of the roof} \end{gathered}\)The Stefan-Boltzmann's constant is given by:
\(\sigma=5.67\times10^{-8}\frac{W}{m^2K^4}\)Now, we need to convert the temperature to Kelvin. To do that we use the following:
\(T_K=T_c+273.15\)Where:
\(\begin{gathered} T_K=\text{ temperature in Kelvin} \\ T_C=\text{ temperature in Celsius} \end{gathered}\)For the 33°C we have:
\(T_k(33)=33+273.15=306.15\)For the 14°C:
\(T_K(14)=14+273.15=287.15\)Now, we substitute the values:
\(P_{net}=(5.67\times10^{-8}\frac{W}{m^2K^4})(0.9)(275m^2)((287.15K)^4-(306.15K)^4)\)Solving the operation:
\(P_{net}=-27870.84W\)Therefore, the net rate of radiation is -27870.84 Watts.
What is a scientific theory?
Answers
Answer:
Scientific theories are explanations of some aspect of the natural world based on repeated observations.
Hope this helps!!!!
Answer:
The way that scientists use the word 'theory' is a little different than how it is commonly used in the lay public," said Jaime Tanner, a professor of biology at Marlboro College. "Most people use the word 'theory' to mean an idea or hunch that someone has, but in science the word 'theory' refers to the way that we interpret facts.
Explanation:
If a police car drives at a constant speed of 30 km/h, how long will it take to travel a distance of 96 km??
Answers
Answer:
3.2 hours
Explanation:
96÷30=3.2
so it should take 3.2 hours
a person with normal vision has an optical power of 60 diopters. if the person looks at an object 10m away, what can you say about the image?
Answers
When a person with normal vision looks at an object 10m away, the image is formed clearly on the retina. The reason is that the eye has an optical power of 60 diopters. Therefore, a person with normal vision can see an object 10 meters away clearly.
Optical power refers to the ability of a lens to bend light. It is measured in diopters (D). The greater the diopter, the greater the lens's ability to bend light. The human eye's lens and cornea both contribute to its optical power.The cornea contributes around 43 diopters, while the lens contributes the remaining 17 diopters. The human eye's total optical power is usually about 60 diopters.A person with normal vision has an optical power of 60 diopters. When they look at an object 10m away, the image is formed clearly on the retina. The reason is that the eye has an optical power of 60 diopters.
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What is the Zenith angle at 45 degrees North during the Spring Equinox?
2. Calculate the Zenith angle, Solar elevation angle, and beam spreading at a site located at 45 Degrees North on the Autumnal eqinox on September 22nd.
3. At what latitude does daylight hours have the least variability?
4. true or false: The greater the solar angle (from 0 degrees to 90 degrees), the less spread out the solar beam is and the more concentrated solar radiation will be at that point.
Answers
The Zenith angle at 45 degrees North during the Spring Equinox is 45 degrees.
The Zenith angle is measured as the angle between the vertical line (directly overhead) and the line connecting the observer to the Sun. During the Spring Equinox, when the Sun is directly above the Equator, the Zenith angle at any latitude is equal to the latitude itself.
To calculate the Zenith angle, Solar elevation angle, and beam spreading at a site located at 45 degrees North on the Autumnal equinox (September 22nd), additional information is needed, such as the time of day and the observer's exact location (longitude). These factors affect the position of the Sun in the sky. The Zenith angle is the angle between the vertical line and the line connecting the observer to the Sun. The Solar elevation angle is the complement of the Zenith angle (90 degrees minus the Zenith angle). Beam spreading refers to the divergence of the solar beam as it travels through the atmosphere, which is influenced by factors such as atmospheric conditions and the Sun's position.
The latitude at which daylight hours have the least variability is the Equator (0 degrees latitude). At the Equator, the length of daylight hours remains relatively constant throughout the year, with minimal variation. In contrast, as you move farther away from the Equator towards the poles, the variability in daylight hours becomes more pronounced, with significant changes between the seasons.
False. The spread of the solar beam, known as beam spreading, is actually greater at higher solar angles (closer to 90 degrees) compared to lower solar angles (closer to 0 degrees). At higher solar angles, the solar beam covers a larger area due to the greater incidence angle, resulting in a larger spread of solar radiation. As the solar angle decreases and approaches 0 degrees, the solar beam becomes more concentrated and focused on a smaller area, leading to a higher intensity of solar radiation at that point.
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A boy on his skateboard is accelerating at a rate of 5 m/s2 and has a mass of 40kg. How much force does the boy on his skateboard have?
Answers
Answer:
The answer is 200 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 40 × 5
We have the final answer as
200 NHope this helps you
A substance a
wave travels through
is called a(n)
A. Solution
B. Medium
C. Matter
D. Element
B.
C
U
Gas
Answers
Answer:
B. Medium
Explanation:
I don't know how to explain it but I already did this lesson in school
Un automóvil de 14.500 kg es acelerado gracias a la fuerza de su motor, la que le imprime 21.750 N. Calcular la aceleración del auto.
Answers
The ____ method is described as a type of posthumous extirpation.
a. electrical stimulation
b. introspection
c. scientific
d. experimental
e. clinical
Answers
The d. experimental method is described as a type of posthumous extirpation.
Posthumous extirpation refers to the removal or extraction of a specific part of an organism's body after death, often for the purpose of scientific research. The experimental method is a systematic approach used by researchers to test hypotheses and draw conclusions about a particular phenomenon. It involves the manipulation of one or more independent variables to determine their effects on dependent variables.
This method allows scientists to gather empirical data, control for confounding factors, and establish causal relationships. By applying the experimental method to posthumous extirpation, researchers can gain valuable insights into the structure and function of various biological systems. This can lead to a better understanding of human and animal anatomy, as well as contribute to advancements in medical treatments and surgical procedures. So therefore described as a type of posthumous extirpation is d. experimental method.
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When all forces act on an object what's it called?
Answers
Answer:
Gravity
Explanation:
Help please this is due in an hour and I really don’t understand this
Answers
Answer:
2,3
Explanation:
2,3 3 is the definition of Archemedes' Principle
Question 1. Change in the shape or volume of rocks is
Group of answer choices Faulting Stress Folding Deformation
2.
Stress is ________ . Strain is ________ .
Group of answer choices
The deformation;
Answers
1) Change in the shape or volume of rocks is Deformation
2) Stress is the deforming force. Strain is the deformation.
What is the change called?
Deformation is the term denoting a change in a rock's volume or shape. Geological processes including tectonic forces, compression, tension, and shearing are just a few that can cause it. Rocks may fold, fault, or fracture as a result of deformation, resulting in the production of geological features as mountains, valleys, and fault lines.
Stress is the term used to describe the internal pressure or force that external pressures apply to a material. It is the force acting on the substance per unit area. The distortion that takes place in a material when it is stressed is measured by strain.
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A 10,300 kg railroad car traveling at a velocity of 19 m/s strikes a second boxcar at rest. If the two cars stick together and move off with a velocity of 6 m/s, what is the mass of the second car?
Answers
The mass of the second box car from the calculation is 22317 Kg.
What is the mass of the second car?We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;
The momentum before Collison = Momentum after collision
We would then have from the question;
(10300 * 19) + (M * 0) = (10300 + M) * 6
Let the mass of the second box car be M
Then;
195700 = 61800 + 6M
M = 22317 Kg
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what is quantum physics and what is the equation for space time and travel?
Answers
Answer:
Im not smart
Explanation:
but im your bff
Answer:
it explain how everythings work you should work with the speed of light multiply with the distance of the equator
Find the mass of the mystery box D
Please show all work, thxs
Answers
The mass of box D, given that a 20 Kg block and two girls each of 20 Kg and 30 Kg sits on the sea-saw is 10 Kg
How do i determine the mass of box D?The mass of box D can be obtained as illustrated below:
Clockwise moment = (0.5 × box D) + (1.5 × 30)Anti-clockwise moment = (2 × 20) + (0.5 × 20)Mass of box D =?Clockwise moment = Anti-clockwise moment
(0.5 × box D) + (1.5 × 30) = (2 × 20) + (0.5 × 20)
0.5 × box D + 45 = 40 + 10
0.5 × box D + 45 = 50
Collect like terms
0.5 × box D = 50 - 45
0.5 × box D = 5
Divide both sides by 0.5
Box D = 5 / 0.5
Box D = 10 Kg
Thus, we can conclude that the mass of box D is 10 Kg
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Two forces act on an object. The force has a magnitude of 90N directed left. The other force has
a magnitude of 10N directed right. What is the net force on this object?
Answers
If a force has a magnitude of 90 N directed to the left, then it would be a negative number so -90N. If a force has a magnitude of 10 N directed to the right, then it would be a positive.
F = -90 +20 = -70 N
What is the marginal revenue and marginal cost, respectively, of the 7th unit of output?
Answers
The marginal revenue of the 7th unit of output is the additional revenue generated from producing and selling that unit. The marginal cost of the 7th unit of output is the additional cost incurred in producing that unit.
To determine the marginal revenue and marginal cost for the 7th unit, we would need more specific information about the revenue and cost functions or data associated with the production and sale of the units. Marginal revenue is typically calculated as the change in total revenue divided by the change in quantity, while marginal cost is calculated as the change in total cost divided by the change in quantity.
Without further information, it is not possible to provide an exact numerical answer for the marginal revenue and marginal cost of the 7th unit.
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If an object weighs 140N on the Moon, what will it weigh here on Earth?
Answers
On the moon you weigh 6 times lighter so for this problem you multiply 140n by 6.
What is weight on Moon?Your weight on the Moon is 16.5% what you would experience on Earth. In other words, if you weighed 100 kg on Earth, you would weigh a mere 16.5 kg on the Moon. For you imperial folks, imagine you tipped the scales at 200 pounds.
It’s because of the lower gravity on the Moon. Objects on the surface of the Moon experience only 16.5% of the gravity they would experience on Earth.
The mass of the Moon is only 1.2% the mass of the Earth, so you might expect it to have only 1.2% of the gravity. But it’s only 27% of the size of the Earth, so when you’re standing on the surface of the Moon, you’re much closer to its center of gravity.
Therefore, On the moon you weigh 6 times lighter so for this problem you multiply 140n by 6.
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An object has a coefficient of kinetic friction of 0.2 and a normal force of 30N. Find the force of kinetic friction.
Answers
Answer:
Force of kinetic friction, Fk = 6N
Explanation:
Given the following data;
Coefficient of kinetic friction, μ = 0.2
Normal force, Fn=30N
To find the Force of kinetic friction;
Mathematically, the force of kinetic friction is given by the formula;
Fk = μFn
Where;
Fk represents the force of kinetic friction. μ represents the coefficient of friction. Fn represents the normal force.Substituting into the equation, we have;
Fk = 0.2*30
Fk = 6N
Therefore, the force of kinetic friction is 6N.
A force that is present between two moving objects or surfaces is called kinetic friction. It is estimated in newtons (N) and is calculated by:
\(\rm F_{k} =\rm \mu _{\rm k} F_{n}\)
Where, \(\rm F_{k}\) = frictional force, \(\mu _{\rm k}\) = coefficient, \(\rm F_{n}\) = normal force.
The kinetic friction of the object is 6N.
The kinetic friction can be estimated as:
Given,
Coefficient of kinetic friction (\(\mu\)) = 0.2Normal force \(\rm F_{n}\) = 30 NSubstituting values in the formula:
\(\rm F_{k} =\rm \mu _{\rm k} F_{n}\)
\(\begin{aligned}\rm F_{k} &= 0.2 \times 30\\\\\rm F_{k} &= 6 \rm N\end{aligned}\)
Therefore, 6N is the frictional force.
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What is a solute?
the liquid in a solution
the solid in a solution
the substance that gets dissolved
Answers
- The that gets dissolved
Answer:
C.) The substance that gets dissolved
Explanation:
Because i am a wise man
Imagine a piece of cake. Is it a solid, liquid, or gas, or is it in more than one state?
Explain your decision.
Answers
Answer:
its a solid because it doesn't melt and it doesnt turn into gas
Explanation:
Explanation:
it is in solid form because it has a definite shape
11. Eighth grade students are classifying stars by physical properties. They already learned that Betelgeuse is a cool, bright star. Which of the following are additional physical properties that
could be used by the students to classify Betelgeuse?
Answers
The required, out of the three options, the temperature is the most relevant physical property that can be used to classify Betelgeuse. Option C is correct.
What is Betelgeuse?Betelgeuse is a red supergiant star located in the constellation Orion, approximately 650 light-years away from Earth. It is one of the brightest and most recognizable stars in the night sky and is easily visible to the eye as a reddish-orange dot on the shoulder of the Orion constellation.
Here,
Out of the three options, the temperature is the most relevant physical property that can be used to classify Betelgeuse, as it is already known to be a cool star. Distance from Earth and rotational speed are not necessarily related to the physical properties of the star itself, and therefore, not as relevant for classification purposes. The shape is not a typical physical property used to classify stars, as stars are generally spherical in shape.
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Complete question,
11. Eighth-grade students are classifying stars by physical properties. They already learned that Betelgeuse is a cool, bright star. Which of the following are additional physical properties that
could be used by the students to classify Betelgeuse?
distance from Earth
rotational speed
temperature or shape
in dynamic study modules, how does a student demonstrate that they know or have "mastered" a question?
Answers
In dynamic study modules, a student can demonstrate mastery of a question by correctly answering it several times in a row.
As the student works through the module, they will encounter questions and receive immediate feedback on their responses. If the student answers a question correctly, they will move on to the next question. If they answer incorrectly, they will receive an explanation of the correct answer and will be given another opportunity to answer the same question.
In addition to the mastery-based approach, dynamic study modules may also use other measures to determine whether a student has mastered a question, such as tracking the time it takes the student to answer the question or the number of attempts it takes for the student to answer correctly.
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