Answer:
top box: upthrust
right box: water resistance
bottom box:gravity / weight
left box: thrust
Explanation:
You too have a fruitful day! Hope I could help!
#Down
The weight of the ship is pulling downwards#Up
Upthrust or buyoant force of water#Left
The force of motor
#Right
Drag force of airTwo teams are having a tug of war. The team on the left is pulling with 700 N of force. The team on the right is pulling with 900 N of force.
Which direction will the rope move in?
a( nowhere, the forces are balanced
b( to the right
c( to the left
Answer:
B - to the right
Explanation:
Since the team on the right pulls with greater force than the team to the left, the rope will move to the right.
A human population profile shows the
Answer:
it shows the gorwth
Explanation:
ii) The contact area of ONE foot is 180 cm2 when his mass is 72kg . Find the pressure exerted by Clive in N/cm² when he stands on one foot.
The pressure exerted by Clive in N/cm² when he stands on one foot, given that one foot is 180 cm² and he has a mass of 72 Kg, is 3.92 N/cm²
How do i determine the pressure exerted?We'll begin by obtaining the weight of Clive. This is shown below:
Mass of Clive = 72 KgAcceleration due to gravity on Mars (g) = 9.8 m/s²Weight of Clive (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
W = 72 × 9.8
W = 705.6 N
Finally, we shall determine the pressure exerted. Details below:
Area of one foot = 180 cm² Weight of Clive = 705.6 NPressure exerted =?Pressure exerted = Weight of Clive / Area
Pressure exerted = 705.6 / 180
Pressure exerted = 3.92 N/cm²
Thus, from the calculation made above, we can conclude that the pressure exerted is 3.92 N/cm²
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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An object of height 5 cm is kept in front of a
lens. An inverted image of height 5 is formed. identity the lens and position of the
object and image.
Answer:
The type of lens involved is a convex lens and the object is positioned at the center of the curvature of the convex lens.
According to the question, a real, inverted, and same-sized image of the object is formed.
A concave lens is a diverging lens and always forms virtual images. But convex lenses are converging lenses and are the only type of lens that produce real and inverted images of the corresponding objects.
When an object is placed at the center of the curvature of a convex lens, its corresponding image is formed on the opposite side of the convex lens. The image formed is real and inverted.
The distance of the image from the lens is equal to the distance of the object from the lens.
For a convex lens, the distance of the center of curvature from the lens is double the focal length of the lens.
That's why the convex lens and center of curvature are the correct answer to this question.
Explanation:
What does the elasticity (stretchiness) of the resistance band determine?
The resistance band's elasticity (stretchiness) dictates how easily it can be stretched or can be flexible.
What does the resistance band's elasticity determine?It is the proportion of tensile stress to strain, where strain is the amount of deformation and tensile stress is the tension force applied to a surface area (amount of stretch of the resistance band).
Instead than requiring you to hold additional weight per se, resistance bands function by providing an external resistance force that can be imposed. They are flat, occasionally looping bands that might be thin or thick.
Both rubber bands and springs have a unique quality. The stretch distance affects how hard a band pulls back. The spring constant, denoted by the symbol k (in units of N/m), is a proportionality constant.
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the space Hubble Telescope is orbiting earth at a constant speed of 20m/s.The distance between it and planet earth is 100m.The radius of planet earth is 300km. How long will it take for the Space Hubble Telescope to make a complete rotation?
It will take the Hubble Telescope 94,247 seconds or 26.18 hours to complete one full rotation around the Earth.
Rotation time of the Space Hub TelescopeThe Hubble Telescope is in a circular orbit around the Earth at a constant speed of 20 m/s. The distance between the telescope and the center of the Earth is:
300 km + 100 m = 300,100 m.
Orbital period T of the Hubble Telescope = T = 2πr / v
where
r is the radius of the orbit v is the orbital speed.In this case, r = 300,100 m and v = 20 m/s, so:
T = 2π(300,100 m) / (20 m/s) = 94247 seconds
Thus, it will take the Hubble Telescope approximately 94,247 seconds, or about 26.18 hours, to complete one full rotation around the Earth.
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Which of the following statements are true about an object in two-dimensional projectile motion with no air resistance? (There could be more than one correct choice.) A) The speed of the object is constant but its velocity is not constant. B) The acceleration of the object is constant but its object is + g when the object is rising and -g when it is falling. C) The acceleration of the object is zero at its highest point. D) The speed of the object is zero at its highest point. E) The horizontal acceleration is always zero and the vertical acceleration is always a non-zero constant downward
The horizontal acceleration is always zero and the vertical acceleration is always a non-zero constant downward.
What is a acceleration ?Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.Frictional resistance to its motion in the horizontal direction is a constant resistance, hence the acceleration, even if it is negative acceleration, is a constant in the horizontal plane of motion.To learn more about Acceleration refer :
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child rocks back and forth on a porch swing with an amplitude of 0.290 m and a period of 2.20 s . You may want to review (Pages 425 - 430) . Part A Assuming the motion is approximately simple harmonic, find the child's maximum speed.
This question involves the concepts of simple harmonic motion and maximum speed.
The maximum speed of the child is "0.83 m/s".
The maximum speed in the simple harmonic motion is given by the following formula:
\(v=A\omega\)
where,
v = maximum speed = ?
A = Amplitude = 0.29 m
T = period = 2.2 s
ω = angular frequency = \(\frac{2\pi}{T} = \frac{2\pi}{2.2\ s} = 2.86\ rad/s\)
Therefore,
v = (0.29 m)(2.86 rad/s)
v = 0.83 m/s
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The expressions of the simple harmonic movement allows to find the maximum speed of the swing is:
The maximum speed is: v = 0.828 m / s
The simple harmonic movement is a periodic movement where the restoring force is proportional to the elongation, in the case of a swing it can be approximated to a simple pendulum which is a mass with an inextensible chord., For small oscillations (θ <15º), is described by the expression.
θ = θ₀ cos (wt + Ф)
w² = L / g
Where θ are the angles, θ₀ the initial angle, w the angular velocity, t the time and Ф a phase constant that is determined by the initial conditions, g the acceleration of gravity and L the length of the pendulum.
Speed is defined in kinematics.
w =\(\frac{d \theta}{dt}\\\)
w = \(- \theta_o w \ \frac{d \theta }{dt}\)
The speed is maximum when the sine function is equal to ±1
w = \(\theta_o w\)
The angular velocity is related to the period.
w = \(\frac{2\pi }{T}\)
Let's replace.
w = \(\theta_o \ \frac{2 \pi }{T}\)
In rotational motion the eels must be in radians y and the linear and angular variables are related.
\(\theta = s/R\\s = R\theta\)
v = w R
w = \(\frac{v}{R}\)
We substitute.
v = \(\frac{2 \pi \ s}{T}\)
Let's calculate
v = \(2 \pi \frac{0.290}{2.20}\)2pi 0.290 / 2.20
v = 0.828 m / s
In conclusion using the expressions of the simple harmonic motion we can find the maximum speed of the swing is:
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A worker pushes a lawn mower with a force of 280 N. If the handle makes an angle of 40.0° with the lawn, what is the force pushing the lawn mover forward?
Interesting fact about the rib
Answer:
YOU CAN SNEEZE YOUR WAY TO A RIB FRACTURE.
Explanation:
A man is pulling a box with the force of 10N. There is nobody else on the other side of the box. What is the total amount of force on the box? *
How can a systematic error affect the reported data?
Answer:
A systematic error may result in a high degree of precision.
A systematic error will likely result in poor accuracy
Explanation:
It's what my work gave me when I got it wrong
An object on the surface of the earth weighs 90 lb. At two earth radii above the surface, It will welgh:
270 lb.
10 lb.
90 lb.
30 lb.
A 100 kg mass, initially at rest, is blown apart into two 50.0 kg pieces.
After the blast, the two masses are moving apart with a relative velocity
of 100 m/s. The total kinetic energy after the explosion is
Answer:
Since the center of mass is zero prior to the explosion, it must also be zero after the explosion because no external forces are present,
KE1 = 1/2 (M/2) * 50^2 m2/s^2= 25 * 2500 J = 62,500 J
The total KE will be 2 * 62,500 J = 125,000 J
An astronaut brings a cube from the Earth to the Moon.
What is true about the inertial mass and weight of the cube?
Note that the gravitational acceleration on the Moon is about 1.6m/s^2
A) The inertial mass increases but the weight decreases.
B) Both the inertial mass and weight decrease.
C) The inertial mass decreases but the weight increases.
D) The inertial mass remains constant but the weight decreases.
Answer:
Answer D. Inertial mass constant, weight decreases.
Explanation:
Khan Academy
A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.
If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.
To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.
Given:
Mass of the box, m = 210 kg
Tension in the string, T = 1300 N
The angle of inclination, θ = 35°
Frictional force, f = 100 N
Initial speed, u = 0 m/s
Final speed, v = 10 m/s
First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:
T_parallel = T * cos(θ)
Next, let's calculate the net force acting on the box along the incline. The net force is given by:
Net force = T_parallel - f
Now, using Newton's second law, we can calculate the acceleration (a) of the box:
Net force = m * a
From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):
v^2 = u^2 + 2as
Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)
Now, let's plug in the given values and calculate the distance covered:
T_parallel = 1300 N * cos(35°) ≈ 1067.35 N
Net force = 1067.35 N - 100 N = 967.35 N
a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2
s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m
Therefore, the distance covered by the box is approximately 10.89 meters.
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Two point charges, Q1 and Q2, are separated by a distance R. If the magnitudes of both charges are tripled and their separation is also tripled, what happens to the electrical force that each charge exerts on the other one
Answer:
Remains the same
Explanation:
Put Newton’s 1st Law in your own words
Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.
Explanation:Here I dont know
Which of the following objects
transforms chemical energy into
mechanical energy?
A. Battery powered clock
B. Cell phone
C. Washing machine
D. Windmill
Battery-powered clocks and Washing machines are objects that transform chemical energy into mechanical energy.
What are chemical energy and mechanical energy?Chemical energy is a type of energy that is stored in the bonds of a chemical. It is converted into thermal energy when people burn wood or burn gasoline in the engine of a car. Mechanical energy is a type of energy that is stored in objects by tension. Compressed springs and stretched bands are examples of mechanical energy.
Mechanical energy i.e. kinetic energy or potential energy is the energy that is present in an object in motion or the energy that is stored in objects due to their position. Mechanical energy is a type of renewable energy.
So we can conclude that options A and C are the correct answers.
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What are the possible causes of generator voltage not building up?
Answer:
The most common causes of a generator producing no power are the loss of residual magnetism in the alternator and a failed AVR or another excitation component. If the voltage is around 50-70V on each phase, then it is likely the AVR needs replacement.
Please solve with explanation
There are 14025 x10^6 grains of sand in the sand box when it is full when there was present on average 55 grains in the box initially.
How come the total grains of sand be 92,812,50 grains of sand when it is full?To solve this question we will be converting the sides to mm , 1.5 x 1000 = 1500 m.For 10 x 10 =100 , 1500x 1500x100= 25,50,00,000 mm^3, this is the volume of the box in cubic mm.Then 25,50,00,000 x55= 14025 x10^6 grains of sand in the sand box when it is full.To solve out this kind of question converting the units to mm will be better to know the precise value.To know more about mm^3 units visit:
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What does it mean when an object is magnified?
The object appears darker.
The object appears larger.
The object appears lighter.
The object appears smaller.
Answer:
The object appears larger
Explanation:
B
Why was the government in giving support to addressing and researching the HIV epidemic ?
Running at 2.0 m/s, Burce, the 45.0 kg quarterback, collides with Max, the 90.0 kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision, Max continues to travel forward at 1.0 m/s. Draw or describe simply the diagram before and after collision including objects, mass, velocity, and velocity vectors.
Answer:
max
Explanation:
because its right 90/7
When only the force of gravity dose work on a system, the total mechanical energy of that system is conserved : true or false ?
your answer is going to be False
In the image which element is the most massive ?
Answer:
fluorine
Explanation: it has the largest mass number which is almost rounded to 19.
The tailgate of a car is supported by the hydraulic lift BC. If the lift exerts a 132-lb force directed along its centerline on the ball and socket at B, determine the moment of the force about A.
The moment of the force about point A found using the moments formula, \(|M| = |F| \cdot \: d \perp\) is 67.695 ft–lb.
What is the moment of a force?The moment of a force is the turning effect of the force about a point.
The moment of the force is given by the formula;
\(|M| = |F| \cdot \: d \perp\)
Where;
d = The perpendicular distance from the point to the line of action of the force.
The length of the sides of ∆ABC are;
AB = √(20.5²+4.38²) ≈ 20.9626907
BC = √(17.2²+7.62²) ≈ 18.812347
AC = √((7.62+4.38)²+(20.5-17.2)²) ≈ 12.4454811
The semi–perimeter of triangle ABC = (20.9626907 + 18.812347 + 12.4454811)/2 ≈ 26.1102594
The area, A, of triangle ∆ABC found using Heron's formula is therefore;
A = √((26.1102594×(26.1102594-20.9626907)×(26.1102594-18.812347)×(26.1102594-12.4454811)) ≈ 115.773
The perpendicular distance, d, from point A to BC is therefore;
d = A/(BC)
Which gives;
d = 115.773/18.812347 ≈ 6.15409696
The magnitude of the moment about point A is therefore;
M = 132 lb × 0.51284138 ft. ≈ 67.695 ft.–lb
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Please help me out with this.
True or False?
You are helping a friend push a couch across their living room floor.
Gravity is a field force acting downward on the couch.
Friction from the carpeted floor is a contact force acting against your push.
We have that Gravity a force acting down ward against any object and frictional force is a force acting a against movement, Hence
TrueTrueGravity and frictional forceGenerally, Gravity a force acting down ward against any object on earth at an acceleration of about 9.8m/s
and frictional force is a force acting a against the movement based on contact with another surface
Therefore
Gravity is a field force acting downward on the couch:
This is True
Friction from the carpeted floor is a contact force acting against your push.
This is True
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While Kepler supported the Copernican model of the universe Kepler concluded the following
A the circular orbits of the copernican model weren’t correct paths of planets were elliptical
B all other bodies in the universe move around the earth in circular paths
C all other bodies in the universe move around the moon in triangular paths
D the circular orbits of the Copernican model weren’t correct paths of planets were rectangular
Answer:
Explanation: because Keller concluded that the circular obits of the Copernican model weren't correct paths of planets were elleptical