PLEASE HELP!! 30 POINTS!!!!
People were asked to choose one of four activities they would prefer to do in hot weather. The table shows data about the responses. Which activity was chosen by most adults over 18 years old?
​
A
sports
B
movies
C
reading
D
walking

The interval notation for the solution set is (-∞, -4] and the number line is on the image at the end.

Here we want to find the solution set of the inequality below:

x ≤ -4

First let's do the interval notation. This will be the set that contains all the numbers from negative infinity to -4 (with -4 included, so  we need to have a closed set at that end)

This is written as:

(-∞, -4]

The use of the symbols [ ] means that the element belongs to the set.

Now to the number line, we will have a closed circle at x = -4 (because it is a solution) and a line that goes to the left of it. You can see an example in the graph at the end.

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The value of the given summation is:

\(\sum (29a_i - 13b_i) ]= -30\)

Here we know that the sums are:

\(\sum a_i = -10\\\\\sum b_i = -20\)

And we want to find the value of the sum:

\(\sum (29a_i - 13b_i)\)

First we can distribute the sum to get:

\(\sum 29a_i + \sum - 13b_i\)

And take the coefficients out of the sum:

\(29\sum a_i -13\sum b_i\)

Now replace the known values:

\(29\sum a_i -13\sum b_i = 29*-10 - 13*-20 = -290 + 260 = -30\)

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Answer:

15cm

Step-by-step explanation:

The formula to calculate the area of a parallelogram is base x height.

Since we know the height and area, we can write the equation:

135 = base x 9

Now we can just divide 9 from both sides to solve for base:

135/9=basex9/9

So we get:

Base = 135/9=15

The length of the base is 15cm.

Hope this helped!

Answer:

lol

Step-by-step explanation:

2. haha

3. haha.5.jsj

Answer:

-6x + 21

Step-by-step explanation:

9 - 3(2x - 4)

9 - 6x + 12

-6x + 21

The actual height of the statue is 0312.0 feet. Since the scale factor is 260/1.

What is meaning height?

Height, altitude, and elevation all refer to the vertical distance between something's top and bottom or its base and something above it. Height is used to describe everything that may be measured vertically, high or low.

Given that to draw a drawing the painter use the scale factor 260:1. It means if the height of a statue in the drawing is 1 unit then the actual height of the statue will be 260.

The height of a statue in the drawing is 1.2 feet.

Assume that the height of the statue be x feet.

Therefore,

x/1.2 = 260/1

x/1.2 = 260

Multiply both sides by 1.2:

x = 260 × 1.2

x = 312

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The correct option is B, 312.0

Expressions are said to be equivalent if the expressions are equal, and they hold the same value.

\(6x - \frac{2}{5}\) and \(\frac{6}{5x} -\frac{2}{5}\) are not equivalent.

The parameter is given as:

\(6x - \frac{2}{5}\)

Take LCM of both terms

\(6x - \frac{2}{5} = \frac{6 \times 5x -2}{5}\)

\(6x - \frac{2}{5} = \frac{6 \times 5x}{5} -\frac{2}{5}\)

\(6x - \frac{2}{5} = \frac{30x}{5} -\frac{2}{5}\)

By comparison of \(\frac{30x}{5} -\frac{2}{5}\) and \(\frac{6}{5x} -\frac{2}{5}\)

We see that \(\frac{30x}{5} -\frac{2}{5}\) is not equal to \(\frac{6}{5x} -\frac{2}{5}\)

i.e.

\(\frac{30x}{5} -\frac{2}{5} \ne \frac{6}{5x} -\frac{2}{5}\)

Hence,

We can conclude that the expressions \(6x - \frac{2}{5}\) and \(\frac{6}{5x} -\frac{2}{5}\) are not equivalent.

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..

I will solve this equation! Just provide the x value.

The values of the variables are x = 36, a = 35, n = 87, n = 30 and y = 120

From the question, we have the following parameters that can be used in our computation:

20) x/4 = 9

21) a/5 = 7

22) n/3 = 29

23) n/3 = 10

24) y/5 = 24

To do this, we use the property of multiplication to solve for the variable in each equation

So, we have

x = 4*9 = 36

a = 5*7 = 35

n = 3*29 = 87

n = 3*10 = 30

y = 5*24 = 120

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In this example, process A completed its final quantum in q4, process B completed its final quantum in q4, and process C completed its final quantum in q4.

To determine which queue each process is in when it begins its final quantum, we need to know the length of time each process has been running and how many times it has already used each queue's quantum. Without that information, we cannot determine which queue a process will be in at a specific point in time. However, we can provide an example of how a process might move between the queues over time.

Let's consider the following three processes:

Process A - CPU burst time = 100s

Process B - CPU burst time = 30s

Process C - CPU burst time = 50s

Assume that all three processes arrive at the scheduler at the same time and are added to q1, the highest priority queue.

When the scheduler begins, it will select the first process in q1, which is process A. Since q1 has a quantum of 5s, process A will run for 5s before it is preempted and placed at the back of q2.

The next process in q1 is B. B will also run for 5s before being preempted and placed at the back of q2.

Next, the scheduler will select process C from q1. C will run for 5s before being preempted and placed at the back of q2.

Now the scheduler has completed one round-robin cycle through q1, and all the processes in q1 have used up their q1 quantum. The scheduler will move on to q2 and select the first process in that queue, which is process A. Since q2 has a quantum of 10s, process A will run for an additional 5s before being preempted and placed at the back of q3.

The next process in q2 is B. B will run for 10s before being preempted and placed at the back of q3.

Next, the scheduler will select process C from q2. C will run for 10s before being preempted and placed at the back of q3.

Now the scheduler has completed one round-robin cycle through q2, and all the processes in q2 have used up their q2 quantum. The scheduler will move on to q3 and select the first process in that queue, which is process A. Since q3 has a quantum of 20s, process A will run for an additional 10s before being preempted and placed at the back of q4.

The next process in q3 is B. B will run for 20s before being preempted and placed at the back of q4.

Next, the scheduler will select process C from q3. C will run for 20s before being preempted and placed at the back of q4.

Now the scheduler has completed one round-robin cycle through q3, and all the processes in q3 have used up their q3 quantum. The scheduler will move on to q4 and select the first process in that queue, which is process A. Since q4 has a quantum of 40s, process A will run for an additional 20s before completing its CPU burst.

The next process in q4 is B. B will run for 30s before completing its CPU burst.

Finally, the scheduler will select process C from q4. C will run for 40s before completing its CPU burst.

However, it's important to note that the exact behavior of the scheduler will depend on the length of time each process has been running and how many times it has already used each queue's.

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Answer:

what's the question?? I b.d ont get it

The solution set of this inequality is {x| x > -6.1}

Here we have the inequality:

2x + 8 > -4.2

To find the solution set, we need to isolate the variable x in one of the sides of the inequality. Doing that we will get:

2x + 8 > -4.2

2x > -4.2 - 8

2x > -12.2

x > -12.2/2

x > -6.1

So the set of all numbers larger than -6.1, this in number form is:

{x| x > -6.1}

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Answer:

It would be 6300000. I can't write this in standard form.

Step-by-step explanation:

Answer:

6.3 x 10^6

Step-by-step explanation:

\(\dfrac 28 x + \dfrac 38 (x-1) = 4\\\\\implies \dfrac 18(2x + 3x -3) = 4\\\\\implies 5x -3 = 32\\\\\implies 5x = 32 +3 \\\\\implies 5x = 35\\\\\implies x = \dfrac{35}5\\\\\implies x = 7\)

Answer:

The value of x is 7.

Step-by-step explanation:

Question :

\({\implies{\sf{\dfrac{2}{8} x + \dfrac{3}{8}(x - 1) = 4}}}\)

Solution :

\({\implies{\sf{\dfrac{2}{8} x + \dfrac{3}{8}(x - 1) = 4}}}\)

\({\implies{\sf{\dfrac{2}{8} \times x + \dfrac{3}{8}(x - 1) = 4}}}\)

\({\implies{\sf{\dfrac{2 \times x}{8} + \dfrac{3(x - 1)}{8} = 4}}}\)

\({\implies{\sf{\dfrac{2x}{8} + \dfrac{3x - 3}{8} = 4}}}\)

\({\implies{\sf{\dfrac{2x + 3x - 3}{8} = 4}}}\)

\({\implies{\sf{\dfrac{5x - 3}{8} = 4}}}\)

\({\implies{\sf{{5x - 3} = 4 \times 8}}}\)

\({\implies{\sf{{5x - 3} =32}}}\)

\({\implies{\sf{5x = 32 + 3}}}\)

\({\implies{\sf{5x = 35}}}\)

\({\implies{\sf{x = 35 \div 5}}}\)

\({\implies{\sf{x = \dfrac{35}{5}}}}\)

\({\implies{\sf{x = \cancel{\dfrac{35}{5}}}}}\)

\({\implies{\sf{x = 7}}}\)

\(\star{\underline{\boxed{\sf{\pink{x = 7}}}}}\)

Hence, the value of x is 7.

\(\rule{300}{1.5}\)

Answer:

B

Step-by-step explanation:

the answer is (15+11)+4=15+(11+4)

The expression (15+11) + 4 = 15 + (11+4) best represents the commutative property of addition. The correct option is B.

The cumulative property states that if the position of the numbers when they are in addition is changed then it will not affect the final result of the addition. If altering the operands' order has no effect on the outcome, the binary operation is commutative in mathematics.

The commutative property basically states that x+y can be flipped yet have the same meaning so x+y = y+x ~.

In the option B the expression (15+11) + 4 = 15 + (11+4) representing the cumulative property. On changing the summation terms the final answer will not change.

Therefore, the expression (15+11) + 4 = 15 + (11+4) best represents the commutative property of addition. The correct option is B.

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Answer:

Option 3: -2

Step-by-step explanation:

The slope of the graph is negative, and the only option with a negative term for the slope is -2.

So the slope of the graph is -2.

Answer:

Reflection across the y-axis

Answer:

So the diameter of the pipe with the insulation around it is approximately 18.84 inches / 2 = 9.42 inches.

Step-by-step explanation:

To find the diameter of the pipe with the insulation around it, we can use the formula for the circumference of a circle:

C = 2 * π * r

Where:

· C = circumference of the pipe

· π = the mathematical constant approximately equal to 3.14

· r = the radius of the pipe

Using the given information, we know that the pipe’s diameter is 2.5 inches and that the insulation around the pipe is 0.5 inch thick. Therefore, the radius of the pipe with the insulation around it is:

r = 2.5 inches + 0.5 inch = 3 inches

Plugging in the values:

C = 2 * π * 3

C = 6.28 * 3

C = 18.84 inches

Note that this is only an approximation, as the thickness of the insulation is slightly larger than the diameter of the pipe. To obtain a more accurate result, we would need to use a geometric area formula or a numerical integration technique.

Answer:

okay i'll keep this in mind

Step-by-step explanation:

Answer:

x=4

Step-by-step explanation:

\(\frac{16}{12}= \frac{6x}{5x-2}\)

assuming that the triangles are similar, we can create this ratio of 16 or 12+4 to 6x and 12 to 5x-2

we can cross multiply to get 16(5x-2)=6x(12)

that leaves you with 80x-32=72x

we can then subtract 80x to both sides to get -32= -8x

solve by diving -8 from both sides which means that x=4

Answer:

\(this \: triangles \: are \: similar \: so \\ sides \: must \: be \: in \: a \: ratio \\ \frac{16}{12} = \frac{6x}{5x - 2} \\ \frac{4}{3} = \frac{6x}{5x - 2} \\ 4(5x - 2) = 3 \times 6x \\ 20x - 8 = 18x \\ x \: terms \: togather \\ 20x - 18x = 8 \\ 2x = 8 \\ x = \frac{8}{2} \\ x = 4 \\ thank \: you\)

The dimensions of the garden that create the maximum area are 5 meters by 15 meters, and the maximum possible area is 75 square meters

What is measurement?

Measurement is the process of assigning numerical values to physical quantities, such as length, mass, time, temperature, and volume, in order to describe and quantify the properties of objects and phenomena.

Let's assume that the rock wall is the width of the garden and the wire fencing is used for the length and the other two sides. Let's denote the length of the garden as L and the width as W.

Since we have 30 meters of fencing available, the total length of wire fencing used is:

L + 2W = 30 - W

Simplifying this equation, we get:

L = 30 - 3W

The area of the garden is:

A = LW

Substituting the expression for L from the previous equation, we get:

A = W(30 - 3W)

Expanding the expression, we get:

A = 30W - 3W²

To find the maximum area, we need to take the derivative of A with respect to W and set it equal to zero:

dA/dW = 30 - 6W = 0

Solving for W, we get:

W = 5

Substituting this value back into the expression for L, we get:

L = 15

Therefore, the dimensions of the garden that create the maximum area are 5 meters by 15 meters, and the maximum possible area is:

A = 5(15) = 75 square meters

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Answer:

I believe it is B.

Step-by-step explanation:

When you solve B, you get the expression that you are supposed to factor.

Answer:

(x-3)²+(y+2)²=4

Step-by-step explanation:

x²+y²-6x+4y-3=0
x²-6x+y²+4y=3

(x²-6x+9)+(y²+4y+4)=3+9+4

(x-3)²+(y+2)²=16
(x-3)²+(y+2)²=4

Answer:

In this case, we do not have the table, so i will answer in a general way:

First, let's describe the transformation.

Vertical shift.

If we have a function f(x), a vertical shift of N units is written as:

g(x) = f(x) + N

This will move the graph of f(x) up or down a distance of N units.

if N is positive, then the shift is upwards

if N is negative, then the shift is downwards.

Then a shift of 3 units up, is written as:

g(x) = f(x) + 3

This would be translated to the table in the next way:

You need to add 3 to all the values of y (or f(x)) in the table:

So if for example, the original table was:

x            f(x)

0             5

1              7

2             10

3              15

The table of the transformation will be:

x              g(x)

0              5 + 3 = 8

1               7 + 3 = 10

2              10 + 3 = 13

3               15 + 3 = 18

Given:

A circle with a center at C.

Required:

We need to find the names of the given parts.

Explanation:

Recall that radius is a line segment extending from the center of a circle to the circumference.

Line segment AC extends from the center C of a circle to the circumference.

Recall that the arc of a circle is defined as the part of the circumference of a circle.

AE is the part of the circumference of a circle.

Recall that a straight line segment joins and is included between two points on a circle.

D and E are two points on a circle.

A straight line DE line segment joins and is included between two points D and E on a circle.

Recall that meeting a curve or surface in a single point if a sufficiently small interval is considered a straight line tangent to a curve.

AB is tangent.

Recall that an inscribed angle is an angle with its vertex "on" the circle, formed by two intersecting chords.

Recall that a central angle is an angle formed by two radii with the vertex at the center of the circle.

Recall that an angle formed by an intersecting tangent and chord has its vertex "on" the circle.

Final answer:

Answer:

  see attached

Step-by-step explanation:

You want the graph of the circle defined by the equation ...

  (x-2)^2 + (y-7)^2 = 4.

The equation of a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

Comparing this to the given equation, we see ...

  h = 2, k = 7, r² = 4

Then r = √4 = 2.

The circle will have its center at (2, 7) and will have a radius of 2. It is shown in the attached graph.

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