please help me answer the question ​

The correct options for the given function are-

For the stated function;

f (x) = rootindex 4 startroot 162 endroot superscript x

This can be written as;

f(x) = ⁴√162ˣ

Using the property of indices;

ⁿ√aˣ = aˣ/ⁿ

(aˣ)ⁿ = aⁿˣ

f(x) = ⁴√162ˣ = 162ˣ/⁴

The number 162 can be written in form of the factors;

162 = 2x3⁴

Put the values;

f(x) = ⁴√(2x3⁴)ˣ

    = (2x3⁴)ˣ/⁴

    =  (2x3⁴)⁽¹/⁴⁾ˣ

f(x) = (3 ⁴√2)ˣ

Now,

f(x) = (3 ⁴√2)ˣ = (3.(2¹/⁴))ˣ

Thus, the expression equivalent to the functions are-

f(x) = ⁴√162ˣ

f(x) = (3 ⁴√2)ˣ

f(x) = (3.(2¹/⁴))ˣ

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Answer:

140J

Step-by-step explanation:

work done = Mass x acceleration x distance

mass = 7kg

acceleration = 10m/s^2

distance= 2m

work = 7 x 10 x 2

= 140j

Answer:

The answer is 140J or 140Nm

Step-by-step explanation:

Work done=mgh

W=7×10×2

W=140J or 140Nm

Answer:

all 3 options are true : A, B, C

Step-by-step explanation:

warning : it has come to my attention that some testing systems have an incorrect answer stored as right answer for this problem.

they say that A and C are correct.

but I am going to show you that if A and C are correct, then also B must be correct.

therefore, my given answer above is the actual correct answer (no matter what the test systems say).

originally the information about the alignment of the point F in relation to point E was missing.

therefore, I considered both options :

1. F is on the same vertical line as E.

2. F is not on the same vertical line as E.

because of optical reasons (and the - incomplete - expected correct answers of A and C confirm that) I used the 1. assumption for the provided answer :

the vertical line of EF is like a mirror between the left and the right half of the picture.

A is mirrored across the vertical line resulting in B. and vice versa.

the same for C and D.

this leads to the effect that all 3 given congruence relationships are true.

if we consider assumption 2, none of the 3 answer options could be true.

but if the assumptions are true, then all 3 options have to be true.

now, for the "why" :

remember what congruence means :

both shapes, after turning and rotating, can be laid on top of each other, and nothing "sticks out", they are covering each other perfectly.

for that to be possible, both shapes must have the same basic structure (like number of sides and vertices), both shapes must have the same side lengths and also equally sized angles.

so, when EF is a mirror, then each side is an exact copy of the other, just left/right being turned.

therefore, yes absolutely, CAD is congruent with CBD. and ACB is congruent to ADB.

but do you notice something ?

both mentioned triangles on the left side contain the side AC, and both triangles in the right side contain the side BD.

now, if the triangles are congruent, that means that each of the 3 sides must have an equally long corresponding side in the other triangle.

therefore, AC must be equal to BD.

and that means that AC is congruent to BD.

because lines have no other congruent criteria - only the lengths must be identical.

Answer:

254.5cm²

Step-by-step explanation:

I assumed that the units is cm.

hope it helps!!!

Answer: FALSE

Step-by-step explanation:

\(\\ \sf\longmapsto Discount=\dfrac{12.5(30}{100}\)

\(\\ \sf\longmapsto Discount=12.5(0.3)\)

\(\\ \sf\longmapsto Discount=125(3)/100\)

\(\\ \sf\longmapsto Discount=375/100\)

\(\\ \sf\longmapsto Discount=3.75\)

Answer:

discount = $3.75

Step-by-step explanation:

Given:

\(\sf \dfrac{discount \times 100}{100}=\dfrac{\$12.50 \times 30}{100}\)

Multiply both sides by 100 to eliminate the denominators:

\(\implies \sf discount \times 100=\$12.50 \times 30\)

Divide both sides by 10:

\(\implies \sf discount \times 10=\$12.50 \times 3\)

Carry out the multiplication on the right side:

\(\implies \sf discount \times 10=\$37.50\)

Divide both sides by 10:

\(\implies \sf \dfrac{discount \times 10}{10}=\dfrac{\$37.50}{10}\)

\(\implies \sf discount=\$3.75\)

Answer:  $35.75

Step-by-step explanation:

1)  $25 for the manicure

2)  $25*(0.20) = $5 for the tip

3)  $5.75 for the tip

$25 + $5 + $5.75 for the total

$35.75 total

a. The equilibrium price and quantity are 0.42 million litres and  136 cents per litre respectively. The monthly revenue for milk producers without government intervention is $5.712 million.

b. The quantity supplied and the quantity demanded at the guaranteed price are  0 million litres and 1.0897 million litres respectively.

a. To find the equilibrium price and quantity in the market for milk in Saskatchewan, we need to equate the demand and supply equations:

Demand: p = 220 - 200q

Supply: p* = 10 + 300q

Setting p equal to p*, we have:

220 - 200q = 10 + 300q

Combining like terms:

500q = 210

Dividing both sides by 500:

q = 0.42 (rounded to two decimal places)

So the equilibrium quantity is 0.42 million litres.

Substituting this value back into either the demand or supply equation, we can find the equilibrium price:

p = 220 - 200(0.42)

p = 136 (rounded to the nearest cent)

Therefore, the equilibrium price is 136 cents per litre.

To calculate the monthly revenue for milk producers without government intervention, we multiply the equilibrium quantity by the equilibrium price:

Revenue = 0.42 million litres * 136 cents per litre

Revenue = $5.712 million (rounded to one decimal place)

So the monthly revenue for milk producers without government intervention is $5.712 million.

b. If the government guarantees a price of $2.06 per litre, we can set this price equal to the supply equation and solve for the quantity supplied:

2.06 = 10 + 300q

Subtracting 10 from both sides:

300q = 2.06 - 10

300q = -7.94

Dividing both sides by 300:

q = -0.0265 (rounded to four decimal places)

Since quantity cannot be negative, the quantity supplied at the guaranteed price is 0 million litres.

To find the quantity demanded, we can substitute the guaranteed price into the demand equation:

p = 220 - 200q

2.06 = 220 - 200q

Subtracting 220 from both sides:

-217.94 = -200q

Dividing both sides by -200:

q = 1.0897 (rounded to four decimal places)

So the quantity demanded at the guaranteed price is 1.0897 million litres.

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Answer:

5 hours

Step-by-step explanation:

A car travels 120 miles in 3 hours (with a constant speed). How far will it take to travel 200 miles?

120/3 = 40 miles per hour

200 miles / 40 mph = 5 hours

With a constant speed, the car's speed is 120 : 3 = 40mph.

Therefore, it will take 200 : 40 = 5 hours to travel 200 miles.

The value of a in the expression will be 3750.

The value of b, rounded to 2 decimal places will be (75/23)^1/4

The value of n is 450.

An expression consists of one or more numbers or variables along with one more operation.

The value of a in the expression will be:

= 4200 - 450

= 3750.

The number of French words a student remembers never decreases below a certain number of words, n which is 450.

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Answer:

25%

Step-by-step explanation:

So first, 5 answers is 50% of 10 questions

Then, if these problems have only 2 choices then 50%/2=25%

The different simplified two-level gate circuits are as follows:
F(a, b, c, d) = (a'c)(b'd) + (ac)(bd') + (ab'c') + (ab'd') + (a'b'c') + (a'b'd) + (a'bc') + (a'b'd')

(a) F(w, x, y, z) = (x + y′ + z)(x′ + y + z)w
From the expression F(w, x, y, z) = (x + y′ + z)(x′ + y + z)w, the truth table can be derived.

Then Karnaugh Maps (K-map) can be applied to make the equations smaller.

In order to make the equations smaller, there are eight different simplified two-level gate circuits that can be used.

K-Map for (a):

The K-Map above is created for the given function F(w, x, y, z). This K-Map is used to create Boolean equations using the following steps:
1. Combine 1’s wherever possible to get two terms of two variables.
2. There are eight possible combinations of two variable equations.
3. Put these two-variable equations with a common variable together to get four-variable equations.
4. Finally, use the K-Map again to create two-variable equations to use in two-level gate circuits.

The different simplified two-level gate circuits are as follows:

F(w, x, y, z) = (w'z)(xy') + (wz')(x'y)  + (wz)(x + y')  + (wx)(y + z')  + (wx')(y' + z)  + (wy)(x + z')  + (wy')(x' + z)  + (w'x'z)(y + z)

(b) F(a, b, c, d) = Σ m(4, 5, 8, 9, 13)
The given expression F(a, b, c, d) = Σ m(4, 5, 8, 9, 13) can be simplified by using Karnaugh Maps to make the equations smaller. There are eight different simplified two-level gate circuits that can be used for the simplified expressions. K-Map for (b):

The K-Map above is created for the given function F(a, b, c, d). This K-Map is used to create Boolean equations using the following steps:
1. Combine 1’s wherever possible to get two terms of two variables.
2. There are eight possible combinations of two variable equations.
3. Put these two-variable equations with a common variable together to get four-variable equations.
4. Finally, use the K-Map again to create two-variable equations to use in two-level gate circuits.

The different simplified two-level gate circuits are as follows:
F(a, b, c, d) = (a'c)(b'd) + (ac)(bd') + (ab'c') + (ab'd') + (a'b'c') + (a'b'd) + (a'bc') + (a'b'd')

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Answer:

2.7156

Step-by-step explanation:

14.549 - (8.131 + 3.7024) =

14.549 - 11.8334 =

2.7156

Hope this helps!

Answer:

2.7156

Step-by-step explanation:

Answer:

$31.70

Step-by-step explanation:

To determine the critical value of F for a one-way between-subjects ANOVA with 5 levels and 48 people, we need to find the degrees of freedom for the numerator and the denominator.

The numerator degrees of freedom (df₁) is equal to the number of levels minus 1, which is 5 - 1 = 4.

The denominator degrees of freedom (df₂) is equal to the total number of people minus the number of levels, which is 48 - 5 = 43.

Using these degrees of freedom, we can look up the critical value of F from the F-distribution table or use statistical software.

For an alpha level of 0.01 and df₁ = 4 and df₂ = 43, the critical value of F is approximately 3.737.

Therefore, the correct answer is B. 3.737.

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Answer:

x = -2

Step-by-step explanation:

Step 1: Define

q(x) = 1/2x - 3

q(x) = -4

Step 2: Substitute and Evaluate

-4 = 1/2x - 3

-1 = 1/2x

-2 = x

x = -2

Step 3: Check

q(-2) = 1/2(-2) - 3

q(-2) = -1 - 3

q(-2) = -4

Hi, your question appears to be unclear. However, I inferred this to be a linear programming problem.

Answer:

$500

Step-by-step explanation:

To begin we need to state the system of inequalities for this situation (constraints):

From the question, we note we are required to find the maximum revenue that the craftsman can take in. In other words, the optimization equation is \(5b+7.5n\) = maximum revenue (taking note that a bracelet costs $5 and a necklace costs $7.50)

Next, we are to plot the inequalities on a graph to determine the feasible region: Doing so should give us these main vertices: (0,0) (0,40) (40,30 (100,0).

By substituting the vertices into the optimization equation (replacing b, and n) we can determine which quantity gives the maximum revenue:

For (0,40) ⇒ 5(0) + 7.5(0) = $0

For (0,40) ⇒ 5(0) + 7.5 (40) = $300

For (40, 30) ⇒ 5(40) + 7.5 (30) = $425

For (100, 0) ⇒ 5(100)+7.50(0) = $500

We notice that at point  (100, 0) we have a maximum revenue of $500.

The power set of {a, b}, or P({a, b}), is {{}, {a}, {b}, {a, b}}.P({a, b}) and P({0, 1}) are different sets.

The set of P({a,b}), also denoted as 2^{a,b}, represents the power set of the set {a, b}. The power set of a set is the set that contains all possible subsets of the original set, including the empty set and the set itself.

In this case, we have the set {a, b}, where a and b are elements of the set.

The power set of {a, b} is obtained by considering all possible combinations of elements from the original set.

The possible subsets of {a, b} are:

- The empty set: {}

- Individual elements: {a}, {b}

- The set itself: {a, b}

Therefore, the power set of {a, b}, or P({a, b}), is {{}, {a}, {b}, {a, b}}.

Now, let's consider P({0, 1}). Following the same process, we obtain the power set of {0, 1} as {{}, {0}, {1}, {0, 1}}.

Hence, P({a, b}) and P({0, 1}) are different sets.

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Answer:

There are 4 common factors of 30 and 72, that are 1, 2, 3, and 6. Therefore, the greatest common factor of 30 and 72 is 6.

Step-by-step explanation:

84/18=14/3

60/32=15/8

Answer:

Step-by-step explanation:

Answer: 1

Step-by-step explanation: 1.27 is 27 hundredths from 1, but 73 hundredths from 2. Therefore it's nearest whole number is 1.00 = 1.

Answer:

n/2>8

Step-by-step explanation:

Half of N is N/2

And if 8 is less that half of N or N/2

then

N/2 has to be greater than 8

N/2>8

Answer:

Multiply the volume of the cone by 3

Step-by-step explanation:

Required

Volume of a cylinder from a cone of the same dimension

The volume of a cone is:

\(V_1 = \frac{1}{3}\pi r^2h\)

The volume of a cylinder is:

\(V_2 = \pi r^2h\)

Recall that:

\(V_1 = \frac{1}{3}\pi r^2h\)

Split:

\(V_1 = \frac{1}{3}*[\pi r^2h]\)

Substitute: \(V_2 = \pi r^2h\)

\(V_1 = \frac{1}{3}*V_2\)

Make V2 the subject

\(V_2 =3V_1\)

This implies that, we simply multiply the volume of the cone by 3

Answer:

median  

interquartile range

mode          

mean

Mean

Median

mode

Interquartile range

General formula is IQR3-IQR1

We can solve this problem by using casework on the number of collinear points in each triangle.

If all three points are collinear, the triangle has zero area, so we want to count triangles with no more than two collinear points.

Case 1: Three points in a row (horizontal)

There are $4$ rows of points, and each row has $\binom{3}{1} = 3$ ways to choose a set of $3$ points. Therefore, there are $4 \cdot 3 = 12$ triangles with three points in a row.

Case 2: Three points in a column (vertical)

This case is the same as Case 1, so there are also $12$ triangles with three points in a column.

Case 3: Two points in a row, one point in a different row

There are $4$ rows of points, and each row has $\binom{3}{2} = 3$ ways to choose a set of $2$ points. For each choice of two points, there are two other rows that contain the third point of the triangle. Therefore, there are $4 \cdot 3 \cdot 2 = 24$ triangles in this case.

Case 4: Two points in a column, one point in a different column

This case is the same as Case 3, so there are also $24$ triangles with two points in a column.

Case 5: Two points in a diagonal, one point not on the diagonal

There are two diagonals that contain $4$ points each. Each diagonal has $\binom{4}{2} = 6$ ways to choose a set of $2$ points. For each choice of two points, there are $2$ other points that can be paired with it to form a triangle. Therefore, there are $2 \cdot 6 \cdot 2 = 24$ triangles in this case.

Case 6: All other triangles

All other triangles have one point in each of three different rows, or one point in each of three different columns. There are $\binom{4}{3} = 4$ ways to choose $3$ rows, and each row has $4$ points, so there are $4^3 = 64$ triangles with one point in each of three different rows. The same is true for triangles with one point in each of three different columns. Therefore, there are $2 \cdot 64 = 128$ triangles in this case.

Putting it all together, the total number of triangles with positive area is $12+12+24+24+128=\boxed{200}$.

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Answer:

About 15 minutes

Step-by-step explanation:

It takes her 6 minutes to read 20 pgs. If she reads 20 more pages (which will be 40 now) she will have been reading for 12 minutes. This leaves you with 7 pages left, about 3 or 4 minutes.

Answer:

2/5 thats the answer i think

Answer:

2/5

Step-by-step explanation:

\(\frac{7}{8}\)×\(\frac{16}{35}\)

7×16=112

8×35=280

Simplify:

\(\frac{112}{280}\) 112÷4=28 280÷4=70

\(\frac{28}{70}\) Continue simplifying → 28÷2=14 70÷2=35 14/35 continue simplifying 14÷7=2 35÷7=5 2/5 You cannot continue simplifying.  

So, \(\frac{2}{5}\) is the answer.

The statement "interpolation is used to determine values beyond a given set of data points" is true

The given statement is " interpolation is used to determine values beyond a given set of data points"

The interpolation is a method in statistics that used to determine or estimate the unknown values in the given set of values. So it is usually used to estimate the price and the potential yield of security

In the interpolation, we use the values from the given set of the data point and estimate the unknown values or values beyond the given set of data points

Therefore, the given statement is true

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Answer:o

Step-by-step explanation:

wait what????

Answer:

.....................................

Answer:

Nina has read 45% of the book

Step-by-step explanation:

sorry i don't know how to do the problem