Please help me solve this problem

The exponential function passing through the points (-3, 1/2) and (3, 32) can be represented by the equation \(f(x) = (2^{(5/6)}) * (2^{(x/6)})\).

To find the exponential function passing through the given points, we can start by assuming the general form of an exponential function, \(f(x) = a * (b^x)\), where a and b are constants to be determined. Plugging in the coordinates (-3, 1/2) into this equation gives us \(1/2 = a * (b^{(-3)})\), and plugging in (3, 32) gives us \(32 = a * (b^3)\).

Now, we can solve this system of equations to find the values of a and b. Taking the ratio of the two equations, we get \((1/2) / 32 = (a * (b^{(-3)})) / (a * (b^3))\), which simplifies to \(1/64 = 1/b^6\). Solving for b, we find \(b = 2^{(1/6)\).

Substituting this value back into either of the original equations, we can solve for a. Using the equation \(1/2 = a * (2^{(-3/6)})\), we find \(a = 2^{(5/6)\).

Therefore, the exponential function passing through the given points is \(f(x) = (2^{(5/6)}) * (2^{(x/6)})\).

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Answer:

a, x=3

Step-by-step explanation:

6x - 9 = 3x

-9 = 3x-6x

-9 = -3x

divide both sides by -3

3 = x

The butterfly spread is constructed using the following three calls: - Buy 1 call with an exercise price of 120 at a price of $15.40.- Sell 2 calls with an exercise price of 125 at a price of $13.50 each.- Buy 1 call with an exercise price of 130 at a price of $11.35.


A butterfly spread involves buying one option with a lower exercise price, selling two options with a middle exercise price, and buying one option with a higher exercise price. In this case, we buy the call with an exercise price of 120, sell two calls with an exercise price of 125, and buy the call with an exercise price of 130.

To analyze the strategy, we need to consider the stock price at expiration. The breakeven stock prices are calculated by adding and subtracting the net debit or credit from the middle exercise price. In this case, the net debit is $1.60 ($15.40 – 2*$13.50 + $11.35), so the breakeven prices are $121.40 ($125 - $1.60) and $128.60 ($125 + $1.60).

The maximum profit of $1.60 occurs when the stock price is exactly at the middle exercise price of 125 at expiration. In this case, the two sold calls expire worthless, and the two bought calls have intrinsic value of $5 each. The minimum profit of -$1.40 occurs when the stock price is below $121.40 or above $128.60 at expiration. In this situation, all the options expire worthless, resulting in a loss of the net debit.

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Answer:

1

2

3

4

6

12

43

86

129

172

258

516

Step-by-step explanation:

516 is divisible by?

When chromosomal DNA replication occurs, two identical copies of a chromosome that are linked by a common centromere form a sister chromatid.

DNA, commonly referred to as deoxyribonucleic acid, is the genetic material carried by humans and virtually all other organisms. A person's cells have almost the same DNA.

DNA are made molecular building blocks which are known as the nucleotides. These building blocks consist of a phosphate group, a sugar group, and one of four distinct nitrogen bases. To build DNA strands, nucleotides are linked together into chains with the phosphate and sugar groups swapping positions.

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High Voltage, Inc. should use the following notation to construct its null and alternative hypotheses:                           Null Hypothesis: H0: μ1 - μ2 = 0; Alternative Hypothesis: H1: μ1 - μ2 ≠ 0; where μ1 represents the mean life span of High Voltage's product and μ2 represents the mean life span of the competitor's product.

The notation High Voltage should use to construct its null and alternative hypotheses is:

(i) Null Hypothesis: H0: μ1−μ2=0

where μ1 represents the mean life span of High Voltage's product and μ2 represents the mean life span of the competitor's product.

(ii) Alternative Hypothesis: Ha: μ1−μ2≠0

Where,μ1 and μ2 are the mean lifespan of the light bulbs of High Voltage and its competitor, respectively.

In this problem, paired samples t-test should be used to test the hypotheses.

Paired sample t-test: It is a statistical procedure used to compare two population means with two samples of dependent observations, where the dependent variable is the same or the same subject measured under different conditions. It is used when the observations are paired, i.e., each pair of observations consists of two measurements made on a single subject or item.

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Answer: 0.6

Step-by-step explanation:

Answer:

For a 200 mile journey, 55.5 liters of fuel

is needed

Step-by-step explanation:

Here, we want to estimate the fuel needed for a 200 mile journey

we can use this by having an average

By adding all and dividing by 6

Mathematically, that will be;

(24 + 59 + 44 + 50 + 59 + 97)/6

= 55.5

The reason for this is because if we added all the lengths and divide by 6, what we get is 200

Thus, if we added the liters of fuel used per each and divide by 6, we can have an estimate for a 200-mile journey

Answer:

49 degrees

Step-by-step explanation

Answer:

I think 49 °F

Step-by-step explanation:

42 - (-7) = 49 °F

So the temperature raised 49 degrees since 7pm last night.

I think thats right. :)

Solution

For this case the confidence interval is given by:

(0.27; 0.33)

We can find the estimaed proportion in the following way:

then the sample proportion would be 0.30

The total cost of the pet fish and fish food is 9m + $30 + d.

The cost of each bag of pet fish is calculated by adding the cost of the mollies and bala. The cost of 1 molly is given to be $3 and the cost of 1 bala is given to be $10. Therefore, the cost of each bag of pet fish is (m x $3) + $10 = $3m + $10.

The total cost of three bags of pet fish can be found by multiplying the cost of one bag by 3. Therefore, the total cost of three bags of pet fish is 3(m x $3 + $10) = 9m + $30. The cost of the box of fish food is given to be d dollars. Therefore, the total cost of the pet fish and fish food is 9m + $30 + d.

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3)  since we don't have the information about the interest paid (I), we cannot determine the rate of interest at this time.

(1) To find the total amount Adrian paid in 36 months, we can multiply the monthly installment by the number of installments:

Total payment A = Monthly installment * Number of installments

              = $375 * 36

              = $13,500

Therefore, Adrian paid a total of $13,500 over the course of 36 months.

(2) In the simple interest formula I = Prt, the letters used represent the following variables:

I: Interest (the amount of interest paid)

P: Principal (the initial amount, or in this case, the car worth)

r: Rate of interest (expressed as a decimal)

t: Time (in years)

(3) To find the rate of interest in percentage, we need more information. The simple interest formula can be rearranged to solve for the rate of interest:

r = (I / Pt) * 100

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When zulaki recorded -3/10 degrees celcius as the starting temperature of a salt water solution and recorded 1/5 degrees as the. ending temperature, the change in temperature is 1/2 degree.

It should be noted that from the information, science class, zulaki recorded -3/10 degrees celcius as the starting temperature of a salt water solution and recorded 9/10 degrees as the. ending temperature.

Therefore,the change in temperature will be the subtraction of the temperature given. This will be illustrated as:

= 1/5 - (-3/10)

= 1/5 + 3/10

= 2/10 + 3/10

= 5/10

= 1/2

The change on temperature is 1/2 degree.

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In science class, zulaki recorded -3/10 degrees celcius as the starting temperature of a salt water solution and recorded 1/5 degrees as the. ending temperature. What was the change in temperature?

10,800 combinations of such choices are there.

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order. Permutations and combinations can be mixed up.

Given:

Rows= 10

Column = 5

Then, the way of selection can be

= (\(^{10}C_3\) x \(^3C_1\)) x (\((^5C_3\) x \(^3C_1\))

= (10!/ 7!3! x 3!/ 2!) x (5! / 3!2! x 3!/ 2!)

= 10 x 9 x 8/ 3 x 2  x 3  x  10 x 3

= 120 x 9 x 10

= 10, 800

Hence, there are 10, 800 ways.

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Answer:

1) (x + 1)(2x + 3) | 2) (3x + 4)(x + 2) | 3) (2x+3)(x+2) | 4) (3x + 4)(2x + 3)

Step-by-step explanation:

Question 1: (x + 1)(2x + 3)

Question 2: (3x + 4)(x + 2)

Question 3: (2x+3)(x+2)

Question 4: (3x + 4)(2x + 3)

(If you need explanation reply to the message)

Answer:

B

Step-by-step explanation:

Ethical concerns!

Good luck on your assignment hope this helps!:)

The equation shows that the value of x and y will be 34 and 16.

From the information given, we are told that the sum of two numbers is 50 and the first number is 2 more than twice the second number.

This will be:

x + y = 50 .... i

x = 2y + 2 ..... ii

Put equation ii into i

x + y = 50

2y + 2 + y = 50

3y = 50 - 2

3y = 48

y = 48/3

y = 16

x + y = 50

x + 16 = 50

x = 50 - 16

x = 34

Therefore, the equation shows that the value of x and y will be 34 and 16.

Complete question:

The sum of two numbers is 50. The first number is 2 more than twice the second number. Formulate a system of equations from the description. Let be the first number and y be the second number

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Answer:

264 cubic metres

Step-by-step explanation:

We need to find the volume of both aquariums and add them up.

The aquariums are shaped as rectangular prisms.

The volume of a rectangular prism is:

V = L * W * H

where L = length, W = width, H = height

The first aquarium is 6 m long, 4 m wide, and 2 m high. Its volume is:

V = 6 * 4 * 2 = 48 cubic metres

The second aquarium is 8 m long, 9 m wide and 3 m high. Its volume is:

V = 8 * 9 * 3 = 216 cubic metres

The amount of space the turtles have is therefore:

V = 48 + 216 = 264 cubic metres

Answer:

Number of students who uses pencils = 64 students

Step-by-step explanation:

Pens : pencils = 3 : 2

Pen = 3

Pencil = 2

Total = 3 + 2 = 5

If there is a total of 160 middles school students how many of them used pencils?

Number of students who uses pencils = ratio of pencil / Total × number of students

= 2 / 5 × 160

= (2 * 160) / 5

= 320/5

= 64

Number of students who uses pencils = 64 students

Number of students who uses pen = ratio of pen / Total × number of students

= 3/5 × 160

= (3*160)/5

= 480/5

= 96 students

To draw the horizontal alignment for the curve on that shape on 12D, follow these steps:

Step 1: First of all, we have to determine the horizontal alignment for the curve. The horizontal alignment consists of a series of tangents, curves, and spirals.

Step 2: After that, we have to select the appropriate curve radius for the design speed, the superelevation, and the allowable sight distance.

Step 3: Next, plot the vertical curves with the curve layout. A design speed of 50 mph and a curve radius of 1200 ft will be used in this example.

Step 4: Next, we have to calculate the curve length using the formula Lc = Rθ. Here, Lc is the curve length, R is the radius, and θ is the curve angle. In this case, the curve angle is 4 degrees, so the curve length will be 83.775 ft.

Step 5: Then, we will plot the curve using a tangent-tangent-radius (TTR) method. The TTR method involves drawing a tangent to the curve's point of intersection, then drawing another tangent to the next point of intersection, and finally drawing the curve's arc with the given radius. This process is repeated until the curve's entire length is completed.

Step 6: Finally, label the horizontal and vertical curves, including the stationing and curve radius.

That's how we draw the horizontal alignment for the curve on that shape on 12D.

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Step-by-step explanation:

the answer is (x+7)cm

your welcome

\(\bold{\boxed{\huge{\blue{\underline{Answer }}}}}\)

\(\bold{\underline{Given :- }}\)

\(\sf{The \: perimeter\:of\:the\:rectangle = 88}\)

\(\sf{The \: length \: is\: 5 \:more \:than \: 2 × width }\)

\(\bold{\underline{To \: Find :- }}\)

\(\bold{\underline{Let's \:Begin :- }}\)

\(\sf{ Let\: the\: breath \:be \: x }\)

\(\sf{\underline{ We\: know\: that, }}\)

\(\sf{\red{ Perimeter\: of \: rectangle = 2( L + W)}}\)

\(\sf{\underline{ According\: to\: the \:question }}\)

\(\sf{The \: length \: is \: 5 \:more \:than \: 2 × width }\)

\(\sf{\underline{That \:is }}\)

\(\sf{ Length = 2x + 5 }\)

\(\sf{\underline{Subsitute the \:required \:values }}\)

\(\sf{ Perimeter \:of\: rectangle = 2( L + W) }\)

\(\sf{ 88 = 2( 2x + 5 + x) }\)

\(\sf{ 88 = 4x + 10 + 2x }\)

\(\sf{ 88 = 6x + 10 }\)

\(\sf{ 88 - 10 = 6x }\)

\(\sf{ 78 = 6x }\)

\(\sf{ x = 78/6 }\)

\(\sf{ x = 13 }\)

\(\sf{ Thus,\: the \:width \:is \:13\: feet }\)

\(\bold{\underline{ Now }}\)

\(\sf{ Length = 2x + 5 }\)

\(\sf{ Length = 2(13) + 5 }\)

\(\sf{ Length = 26 + 5 }\)

\(\sf{ Length = 31 }\)

\(\sf{\pink{ Hence, \: Length\: and \:breath \:are\: 13 \:and\: 31 \: feet}}\)

Correct Question:-

The length is 5more than twice the width.

Solution:-

ATQ

\(\\ \tt\hookrightarrow 2(L+B)=88\)

\(\\ \tt\hookrightarrow 2(x+2x+5)=88\)

\(\\ \tt\hookrightarrow 2(3x+5)=88\)

\(\\ \tt\hookrightarrow 6x+10=88\)

\(\\ \tt\hookrightarrow 6x=78\)

\(\\ \tt\hookrightarrow x=13\)

The length of C'B' after dilation using a scale factor of 3 is: D. 15 units.

Dilation is the reduction or enlargement of an image by a scale factor, whereby the original and new images are similar.

Applying the distance formula, we have:

BC = √[(8−12)² + (10−13)²]

BC = √(−4)² + (−3)²]

BC = √(16+9)

BC = √25

BC = 5 units

Applying the scale factor:

Length of C'B' = 3(5) = 15 units.

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For given function g(x) = x^4 - 2x^3 - 3x the value of x such that g'(x) = 12 is x = 2.24

In this question, we have been given a function g(x) = x^4 - 2x^3 - 3x

We need to find the value of x such that g'(x) = 12

First we find the derivative of given function g(x) with respect to x

g'(x) = 4x³ - 6x² - 3

When g'(x) = 12

4x³ - 6x² - 3 = 12

4x³ - 6x² - 3 + 3 = 12 + 3

4x³ - 6x² - 15 = 0

After solving given polynomial we get,

x = 2.24

Therefore,  the value of x is 2.24

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Answer:

0.09125%

Step-by-step explanation:

Divide 73 by 800 and you will get 0.09125

Answer:

It should be %9.75

Answer:

p = 3.2

Step-by-step explanation:

8 = 2.5p ( isolate p by dividing both sides by 2.5 )

\(\frac{8}{2.5}\)= p , that is

p = 3.2

The required  value of the third side of the triangle is x = 11.78.

We can use the law of cosines to find the value of the third side of the triangle. The law of cosines states that for any triangle with sides a, b, and c and angle C opposite side c,

\($c^2 = a^2 + b^2 - 2ab\cos(C)$\)

In this case, we have sides a = 2 and b = 10 and angle C = 120 degrees. Therefore, we can plug in these values to get:

\($x^2 = 3^2 + 10^2 - 2(3)(10)\cos(120^\circ)$\)

Simplifying the expression inside the parentheses gives:

\($\cos(120^\circ) = -\frac{1}{2}$\)

Plugging this in and simplifying further gives:

\($x^2 = 9 + 100 + 30 = 139$\)

Taking the square root of both sides gives:

\($x = \sqrt{144} = 12$\)\($x = \sqrt{139} = 11.78$\)

Therefore, the value of the third side of the triangle is x = 11.78.

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