Please Help Me With These Two Questions:
1. What should you expect when looking at a 1H NMR spectrum of a mixture of compounds?
A. The integrations for peaks will likely look "off" with respect to one another
B. All peaks will be broader and more upfield
C. Splitting will be doubled (singlets will become doublets, doublets will become quartets, etc)
D. Integrations for all peaks will double
2. In a 1:2 methanol-ethyl acetate mixture, what methyl group integration ratio would you expect for the methyl singlets of methanol and ethyl acetate on 1H NMR?
A. 3:6
B. 2:3
C. 1:3
D. 1:4

Answer:

Liquid volume is usually measured using either a graduated cylinder or a buret. As the name implies, a graduated cylinder is a cylindrical glass or plastic tube sealed at one end, with a calibrated scale etched (or marked) on the outside wall.

Answer:

Its high

Explanation:

Becuase if u times it what do u get

The position of element A is first group i.e. alkali metals whereas element B belongs to other groups.

It is because alkali metals reacts violently with water that leads to little explosion and also produced hydrogen gas while on the other hand, element B belongs to next groups in the periodic table. The reactivity of element A is higher than element B due to lack of one electron in the outermost shell which make it highly reactive as compared to element B which is less reactive in nature.

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Order from strongest to weakest, the intermolecular forces are: hydrogen bonding, dipole-dipole interactions, and London dispersion forces.

Hydrogen bonding: Hydrogen bonding is the strongest type of intermolecular force. It occurs when a hydrogen atom is covalently bonded to a highly electronegative atom (such as nitrogen, oxygen, or fluorine) and is attracted to another highly electronegative atom in a nearby molecule. Dipole-dipole interactions: Dipole-dipole interactions are slightly weaker than hydrogen bonding, but still stronger than London dispersion forces. They occur between molecules that have permanent dipoles, or regions of partial positive and negative charge. London dispersion forces: London dispersion forces are the weakest type of intermolecular force. They are attractive forces that occur between all types of molecules and result from the temporary separation of charge that occurs as a result of the movement of electrons within a molecule.

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The given statement exists as false. The temperature at which a liquid's vapor pressure equals the pressure of the gas above it exists comprehended as the boiling point of the liquid.

The temperature at which a liquid's vapor pressure equals the pressure around it and the liquid transforms into a vapor is known as the boiling point of a substance. A liquid's boiling point varies depending on the atmospheric pressure in the area.

The temperature at which a liquid's vapor pressure equals the pressure of the gas above it exists comprehended as the boiling point of the liquid. The temperature at which a liquid's vapor pressure equals one atmosphere is considered the liquid's typical boiling point (760 torr).

The element with the lowest temperature at which an element would smolder is helium, and the element with the highest temperature is tungsten. The melting point is measured in degrees Celsius (C).

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This suggests that the unknown starting material is likely an organic compound containing a carboxylic acid functional group.

Compound is a combination of two or more elements which are chemically bonded together. Compounds can exist in both organic and inorganic forms, and are formed when atoms of different elements combine to form molecules. Inorganic compounds are generally composed of metal and non-metal elements, while organic compounds are composed of only carbon and hydrogen atoms. Compounds can also be classified according to their physical state, such as solid, liquid, or gas. Compounds are important in many areas of science, such as chemistry, physics, and biology, and play an essential role in the production of many products, including medicines, plastics, and fuels.

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We are given:

Volume = 2 L

pH = 2.75

Finding the concentration required:

we know that pH is just the negative log of the hydrogen ion concentration

pH = -log[H⁺]

we are given that the pH is 2.75

2.75 = -log[H⁺]

log[H⁺] = -2.75                         [multiplying both sides by -1]

\(10^{log[H]} = 10^{-2.75}\)                      

[H⁺] = 1.78 * 10⁻³ Molar

Number of moles of Hydrogen ions:

[H⁺] = 1.78 * 10⁻³ Molar

which means that there are 1.78 * 10⁻³ moles of hydrogen ions in 1 liter solution

1.78 * 10⁻³ moles / L

multiplying and dividing by 2, we get:

3.56 * 10⁻³ moles / 2 L

Hence we need 3.56 * 10⁻³ moles of hydrogen ions  

Answer:

3.556x 10^-3mol

Explanation:

Using pH =-log [ H+], we can calculate the concentration of the hydrogen Ions.

pH =-log [ H+], pH = 2.75

2.75 = -log[H+], taking antilog of both sides

10^ — 2.75 = [H+]

[H+] =1. 778 x 10^-3M

Now that we have the concentration and also knows the volume, we can use the relation

Moles = concentration X volume

= 1. 778 x 10^-3M x 2L = 3.56x 10^-3mol

The moles of the hydrogen Ions is 3.56x 10^-3mol

Answer:

A

Explanation:

medal is a conductor so the heat will travl

Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.

Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.

ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).

Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.

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Theoretical mass (O₂)= H₂O₂ Volume×  H₂O₂ density× {( 1 mol O₂)/(2 mol H2O2)}×{( mol of  H₂O₂ /g  H₂O₂ )}

H2O2 Volume= 5 ml

Known density( H₂O₂ )= 1.02 g/ml

Molar mass ( H₂O₂ )= 34.01 g/mol

Reciprocal molar mass(  H₂O₂ )= 0.0294

Theoretical mass( O₂)= 5×1.02× 0.0294× 1/2= 0.0749 moles

Actual moles of O₂ and percentage of  H₂O₂

P= 753 mm Hg×1 atm/760 mm Hg= 0.991 atm

V= 45  ml× 1L /1000 ml= 0.045 L

n= PV/RT

Actual moles ( O₂)= (0.991×0.045)/(0.0821×296 K)= 0.0445/24.3016= 1.8×10^-3 moles

Percentage ( H₂O₂ )= Theoretical moles(O₂)×100= 0.0749×100= 7.49%

Mass of  H₂O₂ (percent)= 3%

Concentration by mass( H₂O₂ )= 3 gm H2O in 100 ml of H2O

Volume ( H₂O₂ )= 100 ml

1 mol ( H₂O₂ )= 34.02 g O2

(3g  H₂O₂ /100 ml Solution)×( 1 mol  H₂O₂ /34.02 g H2O2)

No. Of moles ( H₂O₂ )= 0.088 moles

Mass ( H₂O₂ )= 0.088 moles × 34.02 = 2.99 g

%  H₂O₂ = (2.99 g  H₂O₂ /100 ml Solution)×100= 2.99%

% error= (%  H₂O₂ from the bottle-experiment %  H₂O₂ )/(% H₂O₂ from bottle)×100

=[ (3-2.99)/(3) ]× 100= 0.34% error.

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If the mixing ratio of a sample of air is 2 grams/kilogram, and the temperature of the sample is 25 degrees Celsius, yielding a saturation mixing ratio of 20 grams/kilogram , then the relative humidity of the sample is 10%.

The mixing ratio of a sample of air = 2 grams/kilogram ; temperature of the sample = 25 degree Celsius

Saturation mixing ratio of air at 25 degree Celsius is 20 grams per kg.

Relative humidity is defined as the ratio of the pressure of water vapor in the air at a specific temperature to the maximum pressure of the water vapor that could be held at the same temperature and pressure. It is expressed as a percentage.

Mathematically, Relative Humidity = Mixing Ratio / Saturation Mixing Ratio * 100%

The relative humidity of the sample is obtained as follows :

Relative Humidity = 2/20 * 100%

Relative Humidity = 10%

Therefore, the relative humidity of the sample is 10%.

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Answer:

In the forward direction and releases carbondioxide gas from backside.

Explanation:

In the forward direction and the carbondioxide gas which is a waste material is removed from the engine at the back. The chemical energy of fuel is converted into mechanical energy with the help of engine which able the car to move in the forward direction so engine is the key component that is responsible for the movement of car.

Answer:

In the forward direction and releases carbondioxide gas from backside.

Explanation:

To calculate the total potential, simply add the reduction potential of the battery cell to the reduction potential of the electrolytic cell.

When one cell acts as a battery to power another as an electrolytic cell, metal plating occurs at the cathode (positive electrode). The metal being plated is the same as the metal used in the anode (negative electrode) of the battery cell.

To determine the total potential, we need to consider the individual potentials of the battery and the electrolytic cell. The total potential is the sum of these two potentials.

1. Identify the metals used in the anode and cathode of the battery cell.
2. Look up the standard reduction potentials for the metals.
3. The metal with the higher reduction potential will be plated onto the cathode.

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The balanced chemical equation of the reactions given is as follows:

Balancing of chemical equations is the process of adding numerical coefficients in front of moles of reactants and products to ensure that the moles of atoms of elements of the reactants is equal to the moles of atoms of products formed.

The balanced chemical equation of the reactions given is as follows:

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Answer:

1.39  × 10²³ molecules  of CaCl₂

Explanation:

Given data:

Number of moles of CaCl₂ = 0.23 mol

Number of molecules = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.23 mol × 6.022 × 10²³ molecules  / 1mol

1.39  × 10²³ molecules  

The number of moles present in 175ml of Ba(OH)₂ is 0.105 moles.

To find the moles of Ba(OH)₂ present in 175 mL of 0.600 M Ba(OH)2 solution, you can use the formula:

Moles = Molarity × Volume (in liters)

Molarity = moles of solute/liters of solution

where "moles of solute" refers to the amount of substance being dissolved, measured in moles, and "liters of the solution" refers to the volume of the solution in liters.

First, convert the volume from mL to L:
175 mL = 175 / 1000 = 0.175 L

Next, put the values into the formula:
Moles = 0.600 M × 0.175 L

Moles = 0.105 moles of Ba(OH)₂

Therefore, there are 0.105 moles of Ba(OH)₂ present in 175 ml of 0.600 M Ba(OH)₂.

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Answer

10.6 liters

Explanation

What is given:

Density of the gasoline = 0.680 g/mL

Mass of the gasoline = 7.20 kg

What to find:

To find how large of a container, (volume) in liters needed to hold the gasoline.

Step-by-step solution:

Step 1: Convert the mass of gasoline from kg to g.

Conversion factor: 1 kg = 1000 g

So 7.20 kg = (7.20 kg/1 kg) x 1000 g = 7200 g

Step 2: Determine the volume in mL using the density equation.

Step 3: Convert the volume in step 2 from mL to liters.

Conversion factor: 1000 mL = 1 L

So, 10588.24 mL = (10588.24 mL/1000 mL) x 1 L = 10.58824 liters

How large of a container, (volume) in liters needed to hold 7.20 kg of gasoline is approximately 10.6 liters

There are 4.17 grams of ethane present in a sample containing 0.1376 moles if the molar mass of ethane is 30.067 g/mol.

The number of grams of ethane in a sample can be calculated by multiplying the number of moles of ethane by its molar mass. The molar mass of ethane is 30.067 g/mol, so the number of grams of ethane in the sample is:

0.1376 moles * 30.067 g/mol = 4.17 g

The molar mass of a substance is defined as the mass of one mole of that substance and is usually expressed in g/mol. A mole is a unit of measurement for the amount of a substance, defined as Avogadro's number of entities (atoms, molecules, ions, etc.). One mole of a substance contains Avogadro's number of entities of that substance.

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The functional unit is called a system.

The stomach, small intestine, and large intestine are all organs. When they work together to process food, they form a functional unit known as a system. The correct option is b.

The living body performs many functions. These functions are performed by different systems of the body. There are many systems in the body.

These systems are digestive systems, reproductive systems, circulatory systems, etc. These systems run the body and make an organism.

Here, the stomach, small intestine, and large intestine are all organs of the digestive system. Digestive system digest the food that we eat and provides us energy and removes the waste material from the excretory system, which excretes it out of the body.

Thus, the correct option is b. system.

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The estimated enthalpy change for the reaction CO(g) + Cl2(g) → COCl2(g) is approximately -296 kJ/mol. The negative sign indicates that the reaction is exothermic, meaning it releases heat to the surroundings.

To estimate the enthalpy change for the reaction CO(g) + Cl2(g) → COCl2(g) using bond energies, we need to consider the bonds broken and the bonds formed in the reaction. We will use the bond energies provided in the table.

In the reactants:

- Two C=O bonds in CO: 2 × 732 kJ/mol = 1464 kJ/mol

- One Cl-Cl bond in Cl2: 1 × 242 kJ/mol = 242 kJ/mol

In the product:

- One C=O bond in COCl2: 1 × 732 kJ/mol = 732 kJ/mol

- Two C-Cl bonds in COCl2: 2 × 339 kJ/mol = 678 kJ/mol

Now, let's calculate the overall enthalpy change:

ΔH = (Total energy of bonds broken) - (Total energy of bonds formed)

ΔH = (1464 kJ/mol) + (242 kJ/mol) - (732 kJ/mol) - (678 kJ/mol)

ΔH = 296 kJ/mol

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The specific rate constant of the second-order irreversible reaction is 122.34 L/mol.s.

A second-order irreversible reaction A-3R was studied in a PFR reactor, where reactant pure A (CAO=0.121 mol/lit) is fed with an inert gas (40%), and flow rate of 1 L/min (space velocity of 0.2 min-1). Product R was measured in the exit gas as 0.05 mol/sec.

To calculate the specific rate constant, we use the following equation:0.05 mol/sec = -rA * V * (1-X). The negative sign is used to represent that reactants decrease with time. This equation represents the principle of conservation of mass.Here, V= volume of the PFR. X= degree of conversion. And -rA= the rate of disappearance of A= k.CA^2.To calculate the specific rate constant, k, we need to use a few equations. We know that -rA = k.CA^2.We can also calculate CA from the volumetric flow rate and inlet concentration, which is CAO. CA = (CAO*Q)/(Q+V)The volumetric flow rate, Q = V * Space velocity (SV) = 1 * 0.2 = 0.2 L/min.

Using this, we get,CA = (0.121*0.2)/(1+0.2) = 0.0202 mol/LNow, we can substitute these values in the equation of rate.0.05 = k * (0.0202)^2 * V * (1 - X)The volume of PFR is not given, so we cannot find the exact value of k. However, we can calculate the specific rate constant, which is independent of volume, and gives the rate of reaction per unit concentration of reactants per unit time.k = (-rA)/(CA^2) = 0.05/(0.0202)^2 = 122.34 L/mol.

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Answer:

protein sysnthesis

Explanation:

A 2 g sample of \(CoCl_{2} .xH_{2} O\) is dried in the oven when the anhydrous salt is removed from the oven its mass is 1.565 g then the value of x is 0.024  .

Calculation ,

mass =  2 g ( given )

molar mass = 134.45 + x × 18

After dehydration or when the anhydrous salt is removed from the oven  mass remain = 1.565 g

Molar mass = 134.45

Thus mass of \(H_{2} O\) = 2 g - 1.565 g = 0.435 g

Number of moles of water =  0.435 g / 18  = 0.024 moles

Therefore value of x = 0.024

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Answer:

1.505746561978472

Explanation:

Answer:

in number 7 its Gas because the molecules are afloat and/or moving rapidly.

Explanation:

Answer:

Digestive

Explanation:

The mass of 4. 50*\(10^{22\) formula units of \(CoSO_4\) is approximately 6. 835 x \(10^{26\)g.  

The mass of 4. 50*\(10^{22\) formula units of  \(CoSO_4\) can be calculated using the molar mass of  \(CoSO_4\), which is 154. 99 g/mol.

The formula units of a substance are the ratio of the number of atoms of each element in the compound to the atomic mass of the element. To convert the number of formula units of a substance to mass, we need to know the molar mass of the substance and the molarity of the solution.

The molar mass of a substance is the mass of one mole of that substance, and is typically reported in grams per mole (g/mol). To convert the number of formula units of a substance to mass, we can use the following formula:

Mass (g) = number of formula units x molar mass

For example, if we have 4. 50*\(10^{22\) formula units of  \(CoSO_4\) in a solution with a molarity of 1. 0 M, the mass of  in the solution can be calculated using the following formula:

Mass (g) = 4. 50*\(10^{22\) x 154. 99 g/mol = 6. 835 x \(10^{26\)g.  

Therefore, The mass of 4. 50*\(10^{22\) formula units of \(CoSO_4\) is approximately 6. 835 x \(10^{26\)g.  

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The value of b in the equation \(\( f(t) = 85 \cdot b^t \)\) represents the decay factor of the radioactive substance. To determine the value of \( b \), we can use the information that the half-life of the substance is 21 years.

The half-life of a radioactive substance is the time it takes for half of the substance to decay. In this case, the half-life is 21 years, which means that after 21 years, the amount of the substance remaining will be half of the initial amount.

We can use this information to set up an equation:

\(\(\frac{1}{2} = b^{21}\)\)

To solve for b, we need to take the 21st root of both sides of the equation:

\(\(b = \left(\frac{1}{2}\right)^{\frac{1}{21}}\)\)

Using a calculator, we can evaluate this expression:

\(\(b \approx 0.965\)\)

Therefore, the value of b in the equation \(\( f(t) = 85 \cdot b^t \)\) is approximately 0.965.

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Answer: Aspartame

Explanation:

This leads to the calculation of the mass of aluminium sulphate produced from 250 g of sulfuric acid, as illustrated below. As a result, 290. 71g of aluminium sulphate were produced.

6*48.45=290.71

Al2(SO4)3 is the chemical formula for it. The number of ions produced when a molecule of a solute dissociates in a solvent is equal to the Van't Hoff factor. Al2(SO4)3 completely dissociates into 2 ions of aluminium and 3 ions of sulphate. Hence, the Van't Hoff factor for aluminium sulphate is 5.

The ratio of a substance's mass concentration to the concentration of the particles that are produced when it dissolves is known as the Van't Hoff factor.

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