The parallel line can intersect at infinite points when they are coincident with each other. Then option A is correct.
What is coordinate geometry?Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.
Students in Ms. Bell's geometry class created posters of geometric definitions. which of the following is a precise definition.
Parallel lines are lines that do not intersect.A line segment is part of a line that has an endpoint.An angle is formed by two lines, two segments, or two rays in one planePerpendicular lines are lines in the same plane that intersect at a right angle The parallel line can intersect at infinite points when they are coincident with each other.
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The total number of students enrolled at the carol high School is 1,400 students. If the ratio of boys to girls is also 3 to 4 for the school, what is the TOTAL number of students that are boys and TOTAL number of students that are girls at carol high School?
Question 23 options:
600 boys and 800 girls
467 boys and 350 girls
350 boys and 467 girls
800 boys and 600 girls
70 pupils in a sports centre are surveyed. The pupils can only use the swimming pool and the gym. 28 pupils use the swimming pool and the gym. 48 pupils use the swimming pool. 39 pupils use the gym. Find the probability to select a pupil that uses neither the swimming pool nor the gym.
The probability that a pupil uses neither pool nor gym is 11/70
What is Probability?Probability is the likelihood that an event will happen. This can range from an event being impossible to some likelihood to being absolutely certain. In math terms, probability is on a scale from 0 to 1. Zero means the event is impossible, like rolling a seven on a die that only has digits from 1 to 6.
Number of pupil that can use pool and gym = 28
Number of people that can use pool = 48
Number of people that can use gym = 39
Number of people that can use pool only = 48 - 28 which is 20
Number of people that can use gym only = 39 - 28 = 11
Total number of persons that can use either pool, gym or both = 20 + 11 + 28 which is 59
Number of people that cannot use either or both of the facilities = 70 - 59 which is 11.
Probability = required outcome / possible outcome
Required outcome = 11
possible outcome = 70
Probability = 11/70
In conclusion, the probability that a pupil uses neither swimming pool nor gym is 11/70
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An online pet store offers the hamster house shown in the figure below.
Choose all of the expressions that could be used to find the volume of the hamster house.
A solid shape is shown; two rectangular prisms are attached. The total length of the shape is 6 feet. One rectangular prism has a length of 1 foot, width of 3 feet and height of 4 feet. The second rectangular prism has a length as 6 feet, width as 3 feet and height as 2 feet.
A.
(
1
×
3
×
4
)
+
(
2
×
5
×
3
)
B.
(
1
×
3
)
+
(
4
×
2
)
+
(
5
×
3
)
C.
(
1
×
3
×
2
)
+
(
6
×
3
×
2
)
D.
3
×
(
1
+
4
)
+
2
×
(
5
+
3
)
E.
(
3
×
4
)
+
1
×
(
2
×
5
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+
3
11 / 14
10 of 14 Answered
All the correct expressions that could be used to find the volume of the hamster house are,
⇒ (1 × 3 × 4) + (6 × 3 × 2)
How to solveGiven that;
One rectangular prism has a length of 1 foot, a width of 3 feet and a height of 4 feet.
And, The second rectangular prism has a length as 6 feet, a width as 3 feet, and a height of 2 feet.
Hence, the Volume of first rectangular prism is,
⇒ 1 × 3 × 4
And, Volume of a second rectangular prism is,
⇒ 6 × 3 × 2
Thus, All the correct expressions that could be used to find the volume of the hamster house are,
⇒ (1 × 3 × 4) + (6 × 3 × 2)
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Solve for x.
−23(3x−4)+3x=56
A. x=−196
B. x=−116
C. x=216
D. x=296
Answer:
b
Step-by-step explanation:
12)If p and p' are the length of the perpendiculars drawn from the points (+-root a2-b2,0) to the line x/a cosA + y/b sinA = 1, prove that: p x p' = b2.
Answer:
Kindly refer to below explanation.
Step-by-step explanation:
Given equation of line:
\(\dfrac{x}{a}cos\theta+ \dfrac{y}{b}sin\theta =1\\OR\\\dfrac{x}{a}cos\theta+ \dfrac{y}{b}sin\theta-1=0\)
Given points are:
\((\sqrt{a^2-b^2},0), (-\sqrt{a^2-b^2},0)\)
Formula for distance between a point and a line is:
If the point is \((m, n)\) and equation of line is \(Ax+By+C = 0\)
Then, perpendicular distance between line and points is:
\(Distance = \dfrac{|Am+Bn+C|}{\sqrt{A^2+B^2}}\)
Here,
\(A = \dfrac{x}{a}cos\theta\\B = \dfrac{y}{b}sin\theta\\C = -1\)
For the first point:
\(m = \sqrt{a^2-b^2}, n = 0\)
By the above formula:
\(p\) and \(p'\) can be calculated as:
\(p\times p' =\\\Rightarrow \dfrac{|\dfrac{cos\theta}{a}\times \sqrt{a^2-b^2}+ 0 -1|}{\sqrt{\dfrac{cos^2\theta}{a^2}+\dfrac{sin^2\theta}{b^2}}}\times \dfrac{|-\dfrac{cos\theta}{a}\times \sqrt{a^2-b^2}+ 0 -1|}{\sqrt{\dfrac{cos^2\theta}{a^2}+\dfrac{sin^2\theta}{b^2}}}\\\Rightarrow \dfrac{1-(\sqrt{a^2-b^2}\times \frac{cos\theta}{a})^2}{\dfrac{cos^2\theta}{a^2}+\dfrac{sin^2\theta}{b^2}}}\)
Formula used:
\((x+y)(x-y) = x^2 - y^2\)
\(\Rightarrow \dfrac{\dfrac{a^2-a^2cos^2\theta+b^2cos^2\theta}{a^2}}{\dfrac{b^2cos^2\theta+a^2sin^2\theta}{a^2b^2}}\\\Rightarrow b^2(\dfrac{a^2sin^2\theta+b^2cos^2\theta}{a^2sin^2\theta+b^2cos^2\theta})\\\Rightarrow b^2\)
(Using the identity:
\(sin^2\theta +cos^2\theta = 1\))
(Hence provded)
Five thousand tickets are sold at $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $600,3 prizes of $300,5 prizes of $40, and 20 prizes of $5. What is the expected value of this raffle if you buy 1 ticket? Let X be the random variable for the amount won on a single raffle ticket E(X)= dollars (Round to the nearest cent as needed)
The expected value of buying one ticket in this charity raffle is $0.42. This means that, on average, a person can expect to win approximately $0.42 if they purchase a single ticket.
To calculate the expected value, we need to consider the probability of winning each prize multiplied by the value of the prize. Let's break it down:
- There is a 1/5000 chance of winning the $600 prize, so the expected value contribution from this prize is (1/5000) * $600 = $0.12.
- There are 3/5000 chances of winning the $300 prize, so the expected value contribution from these prizes is (3/5000) * $300 = $0.18.
- There are 5/5000 chances of winning the $40 prize, so the expected value contribution from these prizes is (5/5000) * $40 = $0.04.
- Finally, there are 20/5000 chances of winning the $5 prize, so the expected value contribution from these prizes is (20/5000) * $5 = $0.08.
Summing up all the expected value contributions, we get $0.12 + $0.18 + $0.04 + $0.08 = $0.42.
Therefore, if you buy one ticket in this raffle, the expected value of your winnings is $0.42.
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Can the average rate of change of a function be constant ? Explain
Answer:
yes
Step-by-step explanation:
The average rate of change of any linear function is a constant. That fact is what makes it a linear function.
If:
JK = 6x + 2,
KL=7+4, and
JL= 45,
Find KL.
J
K
L
Answer: 25
Step-by-step explanation: got it wrong and got the answer Took 1 for the team
Answer:
25
Step-by-step explanation:
khan academy :D
in the united states, the mean birth weight for boys is kg, with a standard deviation of kg. assuming that the distribution of birth weight is approximately normal, complete parts a through e.
The proportion of baby boys in the United States that are born with low birth weight is 0.0495
In a set with mean u and standard deviation σ , the z score of a measure X is given by:
Z= X - u / σ
Z = 2.5- 3.41/ 0.55
Z= -1.6545
Z= -1.65 has a p value of 0.0495
The proportion of baby boys in the United States that are born with low birth weight is 0.0495.
the complete question is
In the United States, the mean birth weight for boys is 3.41 kg with a standard deviation of 0.55 kg. Assume that the distribution of birth weight is approximately normal. A baby is considered of low birth weight if it weighs less than 2.5 kg. What proportion of baby boys in the United States are born with low birth weight
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Answer all sub-questions:
a) Compare and contrast the "Monte Carlo" and "Historical" simulation as tools for measuring the risk. [11 grades]
b) Why in risk analysis the right choice of the probability distribution that describes the risk factor's values it is of paramount importance? Discuss [11 grades] [11 grades]
c) Describe how statistics are used in risk management.
Monte Carlo and Historical simulation are widely used tools for risk measurement, generating random inputs based on probability distribution functions. Proper probability distributions are crucial for risk analysis, while statistics aids in risk management by obtaining probabilities and assessing results.
a) Monte Carlo and Historical simulation are the most extensively used tools for measuring risk. The significant difference between these two tools lies in their inputs. Monte Carlo simulation is based on generating random inputs based on a set of probability distribution functions. While Historical simulation, on the other hand, simulates based on the prior actual data inputs.\
b) In risk analysis, the right choice of probability distribution that explains the risk factor's values is of paramount importance as it can give rise to critical decision making and management of financial risks. Probability distributions such as the Normal distribution are used when modeling the return of an asset, or its log-returns. Normal distribution in financial modeling is essential because it best describes the distribution of price movements of liquid and high-frequency assets. Nonetheless, selecting the wrong distribution can lead to wrong decisions, which can be quite catastrophic for the organization.
c) Statistics are used in Risk Management to assist in decision-making by helping to obtain the probabilities of potential risks and assessing the results. Statistics can provide valuable insights and an objective evaluation of risks and help us quantify risks by considering the variability and uncertainty in all situations. With statistics, risks can be easily identified and properly evaluated, and it assists in making better decisions.
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Jose wrote that 9 + 9 = 18. Then he wrote that 9 + 9 + n = 18 − n. Are his equations balanced? Explain.
Answer: no
Step-by-step explanation:
jose added the same variable, (n) to the left side that he subtracted from the right side. so the eqation is not correct
A rectangular sheet of paper is 12 1/2 cm long and 10 2/3 cm wide.Find it's perimeter
pls pls help due in 1hr
Answer:
5.2 =x
Step-by-step explanation:
We know the opposite side and the hypotenuse
sin theta = opp/ hypotenuse
sin 48 = x/7
7 sin 48 =x
5.202013778 =x
Rounding to 1 decimal place
5.2 =x
A roller skating rink charges a flat rate of $5 to rent skates, plus $2.50 per hour to skate. You rent skates and skate for 3 hours. If you pay with a $20.00 bill, how much change do you get back?
Answer:
$7.50
Step-by-step explanation:
First, you multiply 3 and $2.50 (because you skate for 3 hours and it's $2.50 per HOUR to skate) 3 x 2.50 is $7.50 plus the flat rate of $5 is $12.50. So, your total altogether would be $12.50. So if you pay that total with $20, you have to subtract 12.50 from 20. 20 - 12.50 is $7.50. Your change will be $7.50. I hope this is correct! So sorry if it isn't!
Answer:
7.5
Step-by-step explanation:
First, you multiply 2.50 x 3. The answer to that is 7.50. Add on the renting skates, that is 12.50. Then, you subtract 12.50 from 20.00. The answer is 7.5.
Goal and scope A. Selecting an appropriate functional unit is important, but may not be straightforward. Here, our functional unit will be 200,000 miles driven - in other words, the amount of driving a person could expect to do if they bought a new car and drove it until the end of its life. As we know, however, a variety of functional units may be acceptable. a. Briefly explain ( 1 sentence each) why each of the following alternative functional units would or would not be appropriate for our purposes. - "one vehicle" - "distance traveled in one full gas tank or battery charge" - "one year of normal commuting" -1kg of vehicle" b. Now let's say that, in addition to a conventional automobile and an EV, we also wanted to consider riding the public bus as a personal transportation option. In this case, would 200,000 miles driven still be an appropriate choice of functional unit? Why or why not? Which of the functional units from the above list might be more suitable? B. In order to capture the major sources of environmental impacts from "cradle to grave" we will consider three phases of the life cycle: Production, Use, and End-of-life. What is one other phase we could consider? Do you think that omitting this phase will have a significant impact on our conclusions? Why or why not? C. Since our stated purpose is to evaluate which option is more "climate-friendly," we will consider the impact category of global warming potential (GWP, units: kgCO eq). a. Before we begin our LCA, let's form some hypotheses about what we expect to find. Do you expect that EVs or conventional automobiles will be "better" from the perspective of GWP? Do you think that the Production, Use, and End-of-life phases will all contribute equally to GWP for conventional vehicles? How about EVs? Explain your reasoning for each answer. b. What is one other impact category we could consider? Would your answers to the above questions be the same for this impact category, or different? Why?
The production phase could have a larger contribution to acidification potential than the use and end-of-life phases for both conventional vehicles and EVs. The distance traveled in one year of normal commuting could be more suitable in this case.
A. The functional unit, which is defined as the quantified performance of a product system or service that will be used as a reference for conducting the life cycle assessment, is important for evaluating the impacts of products or systems on the environment.
The following are the different functional units that are acceptable or not acceptable to assess the environmental impacts of the product or system.
The first functional unit, one vehicle, is not appropriate as it doesn't represent the amount of driving a person could expect to do if they bought a new car and drove it until the end of its life.
The second functional unit, distance traveled in one full gas tank or battery charge, would not be appropriate for our purpose as it is not clear what type of vehicle it will be used for.
The third functional unit, one year of normal commuting, would not be appropriate as it does not consider all the environmental impacts over the lifetime of the vehicle.
The fourth functional unit, 1 kg of vehicle, would not be appropriate as it is too small of a functional unit to evaluate the environmental impacts of the vehicle.
B. If we also wanted to consider riding the public bus as a personal transportation option, 200,000 miles driven would not be an appropriate choice of functional unit. This is because buses are used for transportation purposes, and they will have different environmental impacts than cars.
Therefore, the distance traveled in one year of normal commuting could be more suitable in this case.
C. One other impact category we could consider is the acidification potential. The production phase could have a larger contribution to acidification potential than the use and end-of-life phases for both conventional vehicles and EVs.
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Find the value of c such that:
SUM(e^nc)=10
The value of c that satisfies the equation \(\sum_{n=1}^{\infty} e^{nc}=10\) is approximately -0.0451.
What is a equation?
An equation is a mathematical statement that asserts the equality of two expressions.
To find the value of c such that the infinite series \(\sum_{n=1}^{\infty} e^{nc}\) is equal to 10, we can use the formula for the sum of an infinite geometric series with \(a = e^c\).
The formula for the sum of an infinite geometric series is given by:
S = a / (1 - r),
where S is the sum of the series, a is the first term, and r is the common ratio.
In this case, \(a = e^c\) and the common ratio \(r = e^c\).
We can rewrite the equation as:
\(10 = e^c / (1 - e^c)\)
Next, let's solve for c:
\(10(1 - e^c) = e^c\)
\(10 - 10e^c = e^c\)
\(10 = 11e^c\)
\(e^c = 10 / 11\)
Taking the natural logarithm (ln) of both sides:
\(c = ln(10 / 11)\)
Using a calculator, we can find the approximate value of c:
c ≈ -0.0451.
Therefore, the value of c that satisfies the equation \(\sum_{n=1}^{\infty} e^{nc}=10\) is approximately -0.0451.
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Write a unit rate for the situation.
102 beats per 2 minutes
:beats per minute
Answer:51
Step-by-step explanation:102 beats : 2 min
?beats :1 min
Do 102 times 1 which gives you 102 .Then divide by 2 and you get 51.
Hope it helps. :)
102 beats per 2 minutes then 51 beats per minute.
What is Division?A division is a process of splitting a specific amount into equal parts.
It is given that,
102 beats per 2 minutes
We need to calculate how many beats per minute.
To do this we just have to divide One hundred two by two
102/2
Fifty one beats.
51 beats per minute
Hence 51 beats per minute.
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What angle in degrees does the guy wire make with the ground?
Answer:
45? I'm not 1000% sure tog
Step-by-step explanation:
someone pls help me with question 5 PLEASE :(
Answer:
the third one
Step-by-step explanation:
the pattern is /5
3/5 and then
(3/5)/5 = 3/25
problem 6. let s = { m ∈ mnxn: m = ab −ba, for some a,b ∈ mnxn } . is the vector space mnxnspanned by the set s?
The set S does not span the vector space M_n×n.
To determine if the vector space of square matrices, denoted as M_n×n, is spanned by the set S, we need to check if every matrix in M_n×n can be expressed as a linear combination of matrices formed by the commutator operation.
The set S consists of matrices of the form m = ab − ba, where a and b are matrices in M_n×n. The commutator operation produces a new matrix by taking the difference between the matrix product ab and ba.
To show that S spans M_n×n, we need to demonstrate that any matrix M in M_n×n can be expressed as a linear combination of matrices from S. In other words, we need to find matrices a and b such that M = ab − ba.
However, it is not possible to express every matrix in M_n×n as a commutator of two matrices. This is because not all matrices have a well-defined commutator representation. Therefore, the set S does not span the vector space M_n×n.
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32-(3^2-1)+20 ÷ 2
I want the solving for this problem please.
By calculating the given expression , we get 5 as a final resultant.
What is Algebraic expression ?
Algebraic expressions are the idea of expressing numbers the use of letters or alphabets without specifying their real values. The basics of algebra taught us the way to express an unknown fee the use of letters consisting of x, y, z, and so on. those letters are known as here as variables. An algebraic expression can be a aggregate of both variables and constants. Any fee that is placed earlier than and improved with the aid of a variable is a coefficient.
Given expression ,
32- (3^2 -1 ) + 20 / 2
So by using the BODMAS rule ,
32 - (3*3 - 1 ) + 20 / 2
23 - (9 - 1 ) + 10
23 - (8) + 10
23 - 18
23 - 18
= 5
Hence, By calculating the given expression , we get 5 as a final resultant.
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the product of z and the complex number 5-6i is a real number. find two possible nonzero values of z.
To find the values of z that make the product with the complex number 5-6i a real number, we need to consider the imaginary part of the product.
The product of z and 5-6i can be written as:
z * (5 - 6i)
Expanding this expression, we get:
5z - 6zi
For the product to be a real number, the imaginary part (-6zi) must be equal to zero. This means that the coefficient of the imaginary unit i, which is -6z, must be zero.
Setting -6z = 0, we find:
z = 0
So, one possible nonzero value of z is 0.
However, since we are looking for nonzero values of z, we need to find another value that satisfies the condition.
Let's consider the equation for the imaginary part:
-6z = 0
Dividing both sides of the equation by -6, we have:
z = 0/(-6)
z = 0
Again, we find z = 0, which is not a nonzero value.
Therefore, there are no other nonzero values of z that make the product with the complex number 5-6i a real number. The only value that satisfies the condition is z = 0.
Can someone help me to solve this question? Prove that the quadrilateral ABCD whose vertices are A(-2,-1), B(-2,-3), C( 5,6), and D(5,-1)is a trapezium.Find the area of trapezium ABCD. Also Can you tell how to find the height of trapezium with vertices without knowing the area? Thank you.
If the height of the trapezium is 7 units. Then the area of the trapezium will be 31.5 square units.
What is a trapezium?It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a trapezium, one pair of opposite sides are parallel.
The quadrilateral ABCD whose vertices are A(-2,-1), B(-2,-3), C( 5,6), and D(5,-1).
The lines AB and CD are parallel to the y-axis. Then the quadrilateral ABCD is a trapezium.
The height of the trapezium will be 7 units.
The area of the trapezium will be
Area = 1/2 (2 + 7) x 7
Area = 0.5 x 9 x 7
Area = 31.5 square units.
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Question 3 Let X1, X2,..., Xn be independent random variables, each having a uniform distri- bution over (0,1). Let M = maximum (X₁, X₂,..., Xn). Show that the distribution function of M, FM(-), is given by FM(x)=x, 0≤x≤1 What is the probability density function of M?
The distribution function of M, FM(-), is given by FM(x) = x, 0 ≤ x ≤ 1.
The probability density function of M is\(fM(x) = n * x^(^n^-^1^)\), 0 ≤ x ≤ 1.
In order to understand the distribution function of M, we need to consider the probability that M is less than or equal to a given value x. Since each Xi is uniformly distributed over (0,1), the probability that Xi is less than or equal to x is x.
For M to be less than or equal to x, all of the random variables Xi must be less than or equal to x. Since these variables are independent, their joint probability is the product of their individual probabilities. Therefore, the probability that M is less than or equal to x can be expressed as the product of n x's: P(M ≤ x) = x * x * ... * x = \(x^n\).
The distribution function FM(x) is defined as the probability that M is less than or equal to x. Therefore, FM(x) = P(M ≤ x) = \(x^n\).
To find the probability density function (PDF) of M, we differentiate the distribution function FM(x) with respect to x. Taking the derivative of \(x^n\)with respect to x gives us \(n * x^(^n^-^1^)\). Since the range of M is (0,1), the PDF is defined only within this range.
The distribution function of M is FM(x) = x, 0 ≤ x ≤ 1, and the probability density function of M is \(fM(x) = n * x^(^n^-^1^)\), 0 ≤ x ≤ 1.
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leo reads 13 pages 1/3 hour. What is the unit rate for pages per hour? For hours per page?
Answer:
33%
Step-by-step explanation:
Find the horizontal asymptote.
y =
3x - 1
x + 3
y = [?]
The horizontal asymptote of the equation y=\((3x-1)/(x+3)\) is 3.
Given an equation y=\((3x-1)/(x+3)\) and we are required to find the horizontal asymptote of the equation.
Equation is like a relationship between two or more variables expressed in equal to form. It may be linear equation, quadratic equation or cubic equation. Equation of two variables look like ax+by=c.
Put x=0 in the equation,
y=\((3x-1)/(x+3)\)
Horizontal asymptote can be found by dividing the coefficients of the leading terms of the equation. We have to divide the coefficients.
Horizontal asymptote=3x/x
=3
Hence the horizontal asymptote of the equation y=\((3x-1)/(x+3)\) is 3
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A ball is thrown straight up with an initial velocity of 24.25 m/s so that it reaches a maximum height of 30m. How fast was it going when it was 10m high from the ground?
As per the equation of motion, the ball was 28.284 m/s speed when it was 10m high from the ground
The term equation refers the mathematical statement that is made up of two expressions connected by an equal sign.
Here we have given that a ball is thrown straight up with an initial velocity of 24.25 m/s so that it reaches a maximum height of 30m.
And we need to find how fast was it going when it was 10m high from the ground.
While we looking into the given question, we have identified the following values,
Maximum height reached by the ball s = 30 m
Here we know that the gravity always acts downward so the acceleration of the ball
⇒ a = g = −10 m/s²
And the initial velocity = 24.495 m/s
Then the speed is calculated as,
=> v² = u²+2as
Therefore, the velocity of the ball at 10 m is:
=> v = √u²+2as
=> v = √(24.495 m/s)² − 2(−10 m/s²)(10 m)
=> v ≈ 28.284 m/s
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1.
In the equation below, what is the value of x
20=x+(2 x 8) - 6
Answer:
x=10
Step-by-step explanation:
20=x+(2x8)-6
20=x+16-6
20=16x-6
20=10x
x=10
A security car is parked 25 ft from a movie theater. Find at what speed the reflection of the security strobe lights is moving along the wall of the movie theater when the reflection is 30 ft from the car. The strobe lights are rotating with the speed 2 revolutions per second.
Answer:
v=20π ft/s
Step-by-step explanation:
Given:
Distance from the security car to the movie theater, D=25 ft
Distance of the reflection from the car, d=30 ft
Speed of rotation of the strobe lights, 2 rev/s
To find the speed at which the reflection of the security strobe lights is moving along the wall of the movie theater, we need to calculate the linear velocity of the reflection when it is 30 ft from the car.
We can start by finding the angular velocity in radians per second. Since the strobe lights rotate at 2 revolutions per second, we can convert this to radians per second.
ω=2πf
=> ω=2π(2)
=> ω=4π rad/s
The distance between the security car and the reflection on the wall of the theater is...
r=30-25= 5 ft
The speed of reflection is given as (this is the linear velocity)...
v=ωr
Plug our know values into the equation.
v=ωr
=> v=(4π)(5)
∴ v=20π ft/s
Thus, the problem is solved.
The speed of the reflection of the security strobe lights along the wall of the movie theater is 2π ft/s.
To solve this problem, we can use the concept of related rates. Let's consider the following variables:
x: Distance between the security car and the movie theater wall
y: Distance between the reflection of the security strobe lights and the security car
θ: Angle between the line connecting the security car and the movie theater wall and the line connecting the security car and the reflection of the strobe lights
We are given:
x = 25 ft (constant)
y = 30 ft (changing)
θ = 2 revolutions per second (constant)
We need to find the speed at which the reflection of the security strobe lights is moving along the wall (dy/dt) when the reflection is 30 ft from the car.
Since we have a right triangle formed by the security car, the movie theater wall, and the reflection of the strobe lights, we can use the Pythagorean theorem:
x^2 + y^2 = z^2
Differentiating both sides of the equation with respect to time (t), we get:
2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)
Since x is constant, dx/dt = 0. Also, dz/dt is the rate at which the angle θ is changing, which is given as 2 revolutions per second.
Plugging in the known values, we have:
2(25)(0) + 2(30)(dy/dt) = 2(30)(2π)
Simplifying the equation, we find:
60(dy/dt) = 120π
Dividing both sides by 60, we get:
dy/dt = 2π ft/s
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A proportional relationship between y and x. When x = 5, y=−7 .
What is the constant of proportionality, k?
Enter your answer as a simplified or improper fraction in the box.
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Answer:
The number
5
7
tells you that when
x
increases of
1
then
y
always increases of
5
7
.
Graphically:
graph{7/7*x [-10, 10, -5, 5]}
Step-by-step explanation: