Answer:
It is B
Explanation:
Answer:
the other guy is right im answering so you can give him brainliest have a nice day :)
Explanation:
an ideal transformer has 200 turns on its primary and 12 turns on its secondary. if the power input to the transformer is 120 kw, what is the power output?
An ideal transformer has no losses such as hysteresis loss, current flow loss, etc. Thus, the output power of an ideal transformer is exactly equal to the input power. So the efficiency is 100.
To answer your question regarding the power output of an ideal transformer with 200 turns on its primary and 12 turns on its secondary, given a power input of 120 kW:
In an ideal transformer, the power output is equal to the power input. Therefore, if the power input to the transformer is 120 kW, the power output of the transformer will also be 120 kW.
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You pull horizontally on a 50 kg crate with a force of 400N and the friction force on the crate in 150N. What is the acceleration of the crate?
If you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate of 150 N, then the acceleration of the crate would be 5 m / s² .
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem if you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate in 150 N.
The net force acting on the crate = 400 N - 150 N
= 250 N
The acceleration of the crate = 250 / 50
= 5 m / s²
Thus, the acceleration of the crate would be 5 m / s² .
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A red ball is thrown downwards with a large starting velocity. A blue ball is dropped from rest at the same time as the red ball. Which ball will reach the ground first?multiple choicethe blue ballthe red ballboth balls will reach the ground at the same time. It is impossible to determine without the mass of the balls
Answer:
Both balls will reach the ground at the same time
Explanation:
That is because the acceleration due to gravity of both balls are same.
Howard i moving a 90 kg wooden crate from one ide of hi office to the other. To accomplih thi, he tie a rope around hi wait and begin to walk, o that the crate i dragged horizontally acro the floor. If the coefficient of friction between the crate and the floor i 0. 159, what force mut Howard apply to to the rope to move at a contant peed?
The force exerted by Howard on the rope to make it move at a constant speed is 140.24 N.
The force that Howard must exert on the rope to move at a constant speed is calculated by applying Newton's second law of motion as follows:
F - Ff = ma
F: the applied force
Ff: the frictional force
m: the mass of the crate's mass
a: the acceleration of the crate (at a constant speed, acceleration: a = 0)
F = Ff
F = μmg
Given in question
Friction coefficient: μ = 0.159Gravity speed: g = 9.8 m/sCrate mass : m = 90 kgF = μmg
F = 0.159 x 90 x 9.8
F = 140.24 N
Then the force Howard exerts on the rope to move at a constant speed is 140.24 N
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Water comes of a tap of cross-sectional area 1.5 cm². After falling a vertical distance of 6.0 cm, the cros sectional area of the water column was found to have reduced to 0.45 cm². Calculate the speed of the water as it exited the tap.
The speed of the water as it exits the tap is approximately 1.89 m/s.
What is the speed of the water as it exited the tap?We can use the principle of conservation of mass and energy to solve this problem. Assuming that the water is incompressible and the flow is steady, the mass flow rate of water at the tap is constant. Therefore, the mass flow rate at the tap is equal to the mass flow rate at the exit:
ρ1A1v1 = ρ2A2v2
where:
ρ1 is the density of water at the tapA1 is the cross-sectional area of the tapv1 is the speed of water at the tapρ2 is the density of water at the exit (we assume it to be the same as ρ1)A2 is the cross-sectional area of the water column at the exitv2 is the speed of water at the exit (what we need to calculate)We can rearrange this equation to solve for v2:
v2 = (ρ1A1v1) / (ρ2A2)
We know that A1 = 1.5 cm², A2 = 0.45 cm², and the vertical distance fallen is 6.0 cm. We can find the speed of water at the tap using the equation for the potential energy:
mgh = (1/2)mv1²
where m is the mass of the water, g is the acceleration due to gravity, h is the vertical distance fallen, and v1 is the speed of water at the tap.
We can rearrange this equation to solve for v1:
v1 = √(2gh)
where;
h = 6.0 cm and g = 9.81 m/s².We also know that the density of water at room temperature is approximately 1000 kg/m³, which is equivalent to 0.001 g/cm³.
Putting all these values into the equation for v2, we get:
v2 = (0.001 g/cm³ x 1.5 cm² x sqrt(2 x 9.81 m/s² x 6.0 cm)) / (0.001 g/cm³ x 0.45 cm²)
Simplifying this expression, we get:
v2 = 1.89 m/s
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What is 170 Degrees in Celsius to Fahrenheit?
"170 Degrees" is a temperature measurement unit commonly used in the Fahrenheit scale. If you are trying to convert "170 Degrees" from Fahrenheit to Celsius, it is important to understand how the two scales relate to each other.
The Fahrenheit scale is based on 32° being the temperature at which water freezes and 212° being the temperature at which water boils. In contrast, the Celsius scale has 0° as the temperature at which water freezes and 100° as the temperature at which water boils.
To convert "170 Degrees" from Fahrenheit to Celsius, you can use the formula:
C = (F - 32) * 5/9, where F is the temperature in Fahrenheit and C is the temperature in Celsius.
Plugging in "170 Degrees" for F, we get:
C = (170 - 32) * 5/9 = 76.67 * 5/9 = 76.67 * 0.5556 = 42.78°C.
So "170 Degrees" Fahrenheit is equivalent to 42.78°C in the Celsius scale.
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The fact that the speed of light is constant as it travels through a vacuum means that
a. photons with longer wavelengths have lower frequencies.
b. radio wave photons have shorter wavelengths than gamma ray photons.
c. X-rays can be transmitted through the atmosphere around the world.
d. ultraviolet photons have less energy than visible photons.
The fact that the speed of light is constant as it travels through a vacuum means that the relationship between the wavelength and frequency of photons is essential to understanding the electromagnetic spectrum. The correct options are a and b.
This constant speed of light is represented by the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency.
Option a is correct. Since the speed of light is constant, if the wavelength of a photon is longer, its frequency must be lower to maintain the constant speed. This inverse relationship means that photons with longer wavelengths indeed have lower frequencies.
Option b is also correct. Radio wave photons have longer wavelengths and lower frequencies than gamma ray photons. This is because gamma rays are at the higher energy end of the electromagnetic spectrum, while radio waves are at the lower energy end.
Option c is incorrect. X-rays have difficulty penetrating the Earth's atmosphere due to their high energy and short wavelengths. This means they cannot be transmitted through the atmosphere around the world as easily as radio waves or other lower energy waves.
Option d is incorrect. Ultraviolet photons actually have more energy than visible photons. They have shorter wavelengths and higher frequencies, which results in higher energy levels according to the equation E = hν, where E is energy and h is Planck's constant.
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Consider an incandescent lightbulb. If you wanted to turn a 10-w lightbulb into a 100-w lightbulb, how would you change the temperature of the filament inside the bulb?.
By using the blackbody radiation formula, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.
We need to know about black body radiation to solve this problem. The energy radiated by a black body object is proportional to the area and the fourth power of temperature. It can be determined as
P = A . e . σ . T⁴
where P is power, A is surface area, e is emissivity, σ is Stefan Boltzmann's constant ( 5.67 x 10¯⁸ W/m²K⁴) and T is temperature.
From the question above, we know that
P1 = 10 watt
P2 = 100 watt
T1 = T1
By using the black body radiation formula, the ratio of temperature is
T1⁴ / T2⁴ = P1 / P2
Hence,
T1⁴ / T2⁴ = P1 / P2
T1⁴ / T2⁴ = 10 / 100
T1⁴ / T2⁴ = 1 / 10
T2⁴ = 10T1⁴
T2 = ⁴√(10T1⁴)
T2 = T1 x 10⁰'²⁵
Thus, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.
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Ohm's Law relates the following:
A) current, mass, and time
B) volts, amperes and resistance
C) resistivity, area and length
D) resistance, current, and power
Ohm's Law relates the following: volts, amperes, and resistance. Ohm's Law relates the following: volts, amperes, and resistance.
Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. The formula for Ohm's Law is: V = IR.
In simpler terms, this means that if you increase the voltage, the current will also increase, but if you increase the resistance, the current will decrease. It can be mathematically expressed as I = V/R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms. This relationship is extremely important in understanding and designing electrical circuits. I hope this long answer helps to explain Ohm's Law!
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A rock with a mass of 10. 0kg falls 25. 0m to
the ground. What is the work done by the
gravitational force if the weight of the ball
is 98. 0N?
Answer:
Explanation:Potential Energy is the stored energy of an object given its position relative to a body. Gravitational potential energy is one type of potential energy and is equal to the product of the object's mass (m), the acceleration caused by gravity (g), and the object's height (h) as distance from the surface of the ground (the body).
mass m of 3 kilograms falling at gravity g of 9.81 meter per second squared from a height h of 5 meters. Solve for potential energy Pe with the equation PE equals m times g times h
In this example, a 3 kilogram mass, at a height of 5 meters, while acted on by Earth's gravity would have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.
9.81 meters per second squared (or more accurately 9.80665 m/s2) is widely accepted among scientists as a working average value for Earth's gravitational pull. This figure is based on a measure of gravity at sea level at a latitude of 45°.
At higher altitudes, gravity decreases slightly.
The effect of latitude on gravitational force is relevant as gravity increases with increasing distance from the Equator. At the Equator, the Earth's gravity is 9.780 m/s2 and at the poles it is 9.832 m/s2 (source: CRC Handbook of Chemistry and Physics).
Gravitational acceleration (to three significant figures) for other planets and bodies in the solar system is as follows:
m/s2 gn*
Sun 274 27.9
Mercury 3.70 0.38
Venus 8.87 0.90
Earth 9.81 1.00
Moon 1.62 0.17
Mars 3.71 0.38
Jupiter 24.9 2.54
Saturn 10.44 1.06
Uranus 8.87 0.90
Neptune 11.15 1.14
Pluto 0.58 0.06
(table source: NASA)
*Standard gravity (gn). 1.00gn is equal to 9.80665 m/s2
How does the flatter design make sweeping the floor easier
Answer:
there will be no cracks so the trash won't get stuck
Flat broom can cover more amount of area in every sweep. Hence, during sweeping the floor, it takes less time and less effort compere to the round one. Thus, the flatter design make sweeping the floor easier.
What is the engineering design process?Engineers go through a set of processes in the engineering design process in order to solve a problem. The procedures include techniques for solving problems, such as choosing your goals and limitations, prototyping, testing, and assessment.
Iterative design follows a set of planned processes, some of which may need to be repeated before going on to the next. This varies depending on the project at hand, but it enables mistakes to be learned from and advancements to be made.
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Your question is incomplete, but most probably your full question was:
The round broom was redesigned into a flat broom. How does the flatter design make sweeping the floor easier?
If you throw a ball up with a velocity of 3 m/s , how long will it take for the ball to reach the top of its path
Answer:
t = 0.306 s
Explanation:
Given that,
Initial velocity of the ball, u = 3 m/s
When it reaches the top of its path, its final velocity, v = 0
We need to find the time it takes the ball to reach the top of its path. It can be calculated using first equation of motion.
v = u +at
Here, a = -g
\(0=u-gt\\\\t=\dfrac{u}{g}\\\\t=\dfrac{3\ m/s}{9.8\ m/s^2}\\\\t=0.306\ s\)
So, the ball will take 0.306 s to reach the top of its path.
A freight train initially moving at +10m/s decelerates at a rate of -0.1m/s^2. How far does it move in 30 seconds?
Answer:
255 [m].
Explanation:
1) the formula is (d - requred distance, V₀ - initial velocity, t - elapsed time, a - deceleration):
\(d=V_0t+\frac{at^2}{2};\)
2) according to the formula above the required distance is:
d=10*30-0.5*0.1*900=300-45=255 [m].
Apply second equation of kinematics
\(\\ \tt\longmapsto s=ut+\dfrac{1}{2}at^2\)
\(\\ \tt\longmapsto s=10(30)+\dfrac{1}{2}(-0.1)(30)^2\)
\(\\ \tt\longmapsto s=300+(-0.1)(450)\)
\(\\ \tt\longmapsto s=300-45\)
\(\\ \tt\longmapsto s=255m\)
Select the best option to explain why the moon is described as a time capsule for Earth’s history?
Question 4 options:
The Apollo astronauts placed a time capsule on the moon’s surface.
The moon has not experienced any changes since its formation.
The moon does not have weather to erode the evidence of asteroid impacts.
Answer:
The moon does not have weather to erode the evidence of asteroid impacts.
what is the difference between copernicus and kepler description of planetary orbits?
Answer:
Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.
A potter’s wheel moves from rest to an angular speed of 0.40 rev/s in 37.5 s.
Assuming constant angular acceleration,
what is its angular acceleration in rad/s2
The angular acceleration of the potter's wheel is 0.067 rad/s².
The given parameters:
Final angular speed, ωf = 0.4 rev/sTime of motion, t = 37.5 sWhat is angular acceleration?Angular acceleration of an object is the rate of change of angular speed of the object.The angular acceleration of the potter's wheel is calculated as follows;
\(\alpha = \frac{\Delta \omega }{t} \\\\\alpha = (0.4\ rev/s \times \frac{2 \pi \ rad}{1 \ rev} ) \times \frac{1}{37.5 \ s} \\\\\alpha = 0.067 \ rad/s^2\)
Thus, the angular acceleration of the potter's wheel is 0.067 rad/s².
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A stone of 1 kg is thrown with a velocity of 40 m/s across the frozen surface of a lake and comes to rest after travelling a distance of 50 m. What is the force of friction between the stone and the ice? *
A)16 N
B)-4 N
C)-16 N
Answer:
C)-16 N
Explanation:
concepts used
force = mass* acceleration
equation of motion
\(v^2 = u^2 + 2as\)
where v is the final velocity
u is the initial velocity
and s is the distance moved
______________________________________________
Given
mass = 1 kg
initial velocity (u) = 40m/s
final velocity (v) = 0 as stones comes to rest
distance moved by stone (s) = 50m
using \(v^2 = u^2 + 2as\)
\(0 = 40^2 +2a*50\\=> -1600 = 100a\\=> a = -1600/100 = -16\)
Thus, acceleration is -16 m/s^2
here acceleration is negative as force of friction is opposing the motion.
Force of friction = mass of stone * acceleration of stone
Force of friction = 1*-16 kgm/s^2 = -16N ( kgm/s^2 = 1 N)
Thus, option c -16N is correct choice.
A 5.00kg firecracker explodes into two parts: one part has a mass of 3.00kg and moves at a velocity of 25.0m/stowards the west. The other part has a mass of 2.00kg. What is the velocity of the second piece as a result of the explosion?
The velocity of the second piece of the firecracker of mass 5.00kg as a result of explosion is 37.5 m/s.
What is velocity?Velocity can be defined as the rate of change of displacement of a body.
To calculate the velocity of the second piece, we use the formula below.
Formula:
MV = mv..............Equation 1Where:
M = Mass of the first part of the firecrackerV = Velocity of the first part of the firecrackerm = Mass of the second part of the firecrackerv = Velocity of the second part of the firecracker.Make v the subeject of the equation
v = MV/m.......... Equation 2From the question,
Given:
M = 3 kgV = 25 m/sm = 2 kgSubstitute these values into equation 2
v = (3×25)/2v = 37.5 m/sHence, the velocity of the second piece is 37.5 m/s.
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Shortly after receiving a traffic ticket for speeding, Fred made numerous comments about the road signs being inadequate and is GPS telling him a different speed limit. This would be an example of:
Answer:
External locus of control
Explanation:
External locus of control is an attitude people possess that makes them attribute their failures or successes to factors other than themselves. The opposite of this type of attitude is the Internal locus of control where the individuals take responsibility for the outcomes of their actions whether good or bad. One good thing about the external locus of control is that when the individuals with this characteristic record successes, they attribute it to others and this presents them as people with team spirit. However, when they record failures, they do not want to take the blame, but rather attribute it to others.
Fred exhibits an external locus of control because he attributed his speeding to other factors like the road signs and GPS instead of fully admitting that it was his fault.
A compass taken to Earth's moon does not point in a specific direction on the moon.
What is the most likely reason for the difference between how the compass works on Earth and on the moon?
A) The moon lacks an atmosphere.
B) The moon contains no rocks that have iron.
C) The moon does not have a strong magnetic field.
D) The moon has no bodies of water.
Answer:
C.
Explanation:
The moon does not have a strong magnetic field. This is the most likely reason for the difference between how the compass works on Earth and on the moon. Hence option C is correct.
What is magnetic field ?The magnetic impact on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it while the charge is travelling through a magnetic field The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. Paramagnetism, diamagnetism, and antiferromagnetism are three additional magnetic effects that a nonuniform magnetic field may have on "nonmagnetic" materials, albeit these forces are often so minute that they can only be detected by laboratory equipment. Electric currents, such those utilised in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetised objects.
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earths mass is aproximately 81 times the mass of the moon. if earth exerts a gravtational force of magnitude f on the moon, the magnitude of the gravitational force of the moon on earth is
The magnitude of the gravitational force of the Moon on Earth is also 1.99 x 10^20 N. The gravitational force of the moon on Earth.
The magnitude of the gravitational force of the moon on Earth is the same as the magnitude of the gravitational force of Earth on the moon, as stated by Newton's third law. However, let's look at how the gravitational force between these two celestial objects is calculated.
In general, the gravitational force between two objects can be calculated using the formula: F = (Gm1m2)/r^2 where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.
The mass of the Earth is approximately 81 times greater than that of the Moon. The mass of the Earth is about 5.97 x 10^24 kg, while the mass of the Moon is approximately 7.34 x 10^22 kg.
As a result, we may use these values to calculate the magnitude of the gravitational force exerted by Earth on the Moon.
Assume that the distance between the centers of mass of Earth and Moon is 384,400 km.
Furthermore, G has a value of 6.67 x 10^-11 Nm^2/kg^2.
Using the formula: F = (Gm1m2)/r^2
we get: F = (6.67 x 10^-11 Nm^2/kg^2)(5.97 x 10^24 kg)(7.34 x 10^22 kg)/(384,400,000 m)^2
= 1.99 x 10^20 N
The magnitude of the gravitational force of Earth on the Moon is about 1.99 x 10^20 N.
Again, due to Newton's third law, the magnitude of the gravitational force of the Moon on Earth is also 1.99 x 10^20 N.
Therefore, this is our final answer.
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1 L of air, initially at room temperature (300 K) and atmospheric pressure (1 atm), is heated at constant pressure until it doubles in volume. (a) Calculate the temperature of the air after it has doubled in volume. You can assume that air is an ideal gas.
To calculate the temperature of the air after it has doubled in volume, we need to use the Ideal Gas Law which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature. Since we know that the pressure is constant and the volume has doubled.
(P)(2V) = (n)(R)(T2) where T2 is the temperature after the air has doubled in volume. We can simplify this equation by dividing both sides by PV and using the fact that PV = nRT, which gives: 2 = (T2 / T) where T is the initial temperature of the air. Solving for T2, we get: T2 = 2T Substituting the initial temperature T = 300 K, we get: T2 = 2(300 K) = 600 K To calculate the temperature of the air after it has doubled in volume, we will use the following ideal gas law formula:
PV = nRT
where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature. Since the pressure is constant, we can set up the following proportion: V1/T1 = V2/T Given the initial conditions: V1 = 1 L (initial volume) T1 = 300 K (initial temperature) V2 = 2 L (final volume, since the volume doubled) We want to find T2 (the final temperature). To do this, plug the values into the proportion: (1 L)/(300 K) = (2 L)/T2 Now, solve for T2: T2 = (2 L) * (300 K) / (1 L) T2 = 600 K The temperature of the air after it has doubled in volume is 600 K.
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The temperature of the air after it has doubled in volume is 600 K.
Given that air is an ideal gas, we can use the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the amount of gas, R is the ideal gas constant, and T is temperature. In this case, we have the initial state and final state of the gas, and we want to calculate the final temperature.
Initial state:
P1 = 1 atm
V1 = 1 L
T1 = 300 K
Final state:
P2 = 1 atm (constant pressure)
V2 = 2 L (doubled volume)
T2 = ? (we need to find this)
Since the pressure is constant, we can set up a ratio using the initial and final states:
(V1/T1) = (V2/T2)
Plugging in the known values:
(1 L / 300 K) = (2 L / T2)
Now we can solve for T2:
T2 = (2 L * 300 K) / 1 L
T2 = 600 K
So, the temperature of the air after it has doubled in volume is 600 K.
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An object with a mass of 20 kg is accelerating at a rate of 6 m/s/s. What is the amount of force?
Answer:
120 Newtons
Explanation:
m = 20 kg
a = 6 m/s
F = ?
F = m x a
F = 20 x 6
F = 120 Newtons
What is another name for an alpha particle? Include the atomic number and mass number
Answer:
Alpha particles are Helium nuclei consisting of 2 protons and two neutrons (mass number 4, atomic number 2, no electrons and so carry a 2+ charge).
Explanation:
Marine science what is climate change?
Answer:
In marine ecosystems, climate change is associated with concurrent shifts in temperature, circulation, stratification, nutrient input, oxygen content, and ocean acidification. There are also strong linkages between climate and species distributions, phenology, and demography.
Explanation:
Mark her brainliest
find the magnitude of the acceleration acm of the center of mass of the spherical shell. take the free-fall acceleration to be g
Take the free-fall acceleration to be gg = 9.80 m/s2m/s2.
In geometry, a round shell is a generalization of an annulus to three dimensions. it's far the area of a ball among concentric spheres of differing radii.
A round shell is an area among two concentric spheres of differing radii while a sphere is a spherical strong determine, or its floor, with every factor on its surface equidistant from its center. example: A stable cylinder of glass, the radius of whose base is 9cm and the peak is 12cm, is melted and changed into a sphere.
Something spherical is like a sphere in being round, or extra or less spherical, in 3 dimensions. Apples and oranges are both spherical, for example, despite the fact that they're in no way flawlessly round. A spheroid has a more or less spherical shape; so an asteroid, for instance, is regularly spherical, however lumpy.
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The mass of the Moon is 7.35 × 1022 kg and its radius is 1738 km. What is the gravitational field strength on the surface of the Moon?
Answer:
g = 1.62 N/kg
Explanation:
g = GM/r²
= (6.67 x 10⁻¹¹ x 7.35 x 10²²) / (1738 x 10³)²
= 1.62 N/kg
Hope this helps!
A stone of weight $w$ is thrown vertically upward into the air with an initial speed $v_0$. Suppose that the air drag force $f$ dissipates an amount $fy$ of mechanical energy as the stone travels a distance $y$. What is the speed of the stone upon impact with the ground
The speed of the stone upon impact with the ground \({V_f}={V_o} (\frac{w-f}{w+f})^{\frac{1}{2}}\)
GivenThe initial speed = \({V_o}\)
Explanation
Acceleration
The state of going quickly or taking place quickly.acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.Acceleration when ball is moving upward = (w + f)/m
\($\mathrm{V}_{\mathrm{f}}^{2}-\mathrm{V}_{\mathrm{i}}^{2}=2 \overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{s}}$\)
\($=0-\mathrm{V}_{0}^{2}=-2 \mathrm{~s}\left(\frac{\mathrm{w}+\mathrm{f}}{\mathrm{m}}\right)$\) ..... (i)
\($\mathrm{s}=\frac{\mathrm{V}_{0}^{2}}{2\left[\frac{\mathrm{w}+\mathrm{f}}{\mathrm{m}}\right]}$\)
While coming down
\({V_i=0}\)
\($\mathrm{V}_{\mathrm{f}}^{2}-\mathrm{V}_{\mathrm{i}}^{2}=2 \overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{s}} ; \mathrm{a}=(\mathrm{w}+\mathrm{f})$\)
\($\mathrm{V}_{\mathrm{f}}=\sqrt{\frac{2 \times(\mathrm{w}-\mathrm{f}) \mathrm{V}_{0}^{2}}{2(\mathrm{w}+\mathrm{f})}}$\)
\($\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\circ}\left(\frac{\mathrm{w}-\mathrm{f}}{\mathrm{w}+\mathrm{f}}\right)^{1 / 2}$\)
The speed of the stone upon impact with the ground
\($\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\circ}\left(\frac{\mathrm{w}-\mathrm{f}}{\mathrm{w}+\mathrm{f}}\right)^{1 / 2}$\)
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in your drawings for the field of the bar magnet, where are the field lines closest together? where are they farthest apart? what is the significance of a concentration of field lines?
The magnetic field is the strongest at the poles of a magnet, so the lines are closer to each other at poles, and farthest at the center outside the magma.
Magnetic lines being close together mean a strong magnetic field and lines far apart from each other mean a weak magnetic field.
Magnetic field lines are like streamlines in fluid flow, they represent something continuous, and a different resolution would show more or fewer lines. Various phenomena have the effect of displaying magnetic field lines as though the field lines were physical phenomena.
Magnetic field Magnetic field strength is one of two ways that the intensity of a magnetic field can be expressed. Technically, a distinction is made between magnetic field strength H, measured in amperes per meter (A/m), and magnetic flux density B, measured in Newton-meters per ampere (Nm/A), also called teslas (T).
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a tuning fork is used to produce a sound wave having a frequency of 512 hertz what is the wavelength of the sound wave in the air at stp
A tuning fork produces a sound wave with a frequency of 512 Hz. To find the wavelength of this sound wave in the air at standard temperature and pressure (STP), we can use the formula:
Speed of sound (v) = Frequency (f) × Wavelength (λ)
At STP, the speed of sound in air is approximately 331 m/s. We have the frequency (f) as 512 Hz. To calculate the wavelength (λ), we rearrange the formula:
Wavelength (λ) = Speed of sound (v) / Frequency (f)
Substitute the values into the formula:
λ = 331 m/s / 512 Hz
λ ≈ 0.646 m
So, the wavelength of the sound wave produced by the tuning fork in the air at STP is approximately 0.646 meters.
STP standard temperature for popular temperature and pressure, and it refers to the environment's nominal circumstances at sea level. These settings are absolute zero and one atmosphere of pressure. Given that 1982, the preferred definition is 273.15 ok and 1 bar (100 kPa = 750.06 Torr) (134, a 335. STP is defined by the national Institute of standards and generation as occurring at 1 atm and 20 oC (293.15 k, or 68 oF).
STP is defined as the trend temperature and strain at 0oC. The extent of 1 mole of a petrol at STP is the molar extent of a fuel. An area of 22.4L is occupied by one mole (6.021023 typical particles) of any fuel at STP.
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