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Related Questions
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Answers
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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if the tension of the cable is 25.0 N what is the mass of the ball
Answers
Answer:576
Explanation:
A ball is rolled uphill a distance of 6 meters before it slows, stops, and begins to roll back. The ball rolls downhill 4 meters before coming to a rest against a tree. What is the total displacement of the ball?
Answers
Answer:
2 m uphill
Explanation:
The displacement can be calculated as the difference between the final position and the initial position.
In this case, the initial position is 0 m
And the final position is
6 m - 4m = 2 m
Because the ball rolled 6 m uphill and then 4 m downhill.
Then, the displacement is equal to
Displacement = Final position - Initial position
Displacement = 2 m - 0 m
Displacement = 2 m
Therefore, the total displacement of the ball is 2 m uphill
A 1000 kg rollercoaster requires a braking force of 8780N from point D to point E in order to stop. Find
a) The Total Mechanical Energy of the rollercoaster at Point A. b) The velocity of the coaster at point A. c)
The velocity of the coaster at point B. d) The highest hill the coaster could have gotten over before point A
with no additional mechanical energy. (Ans. a) 591,100 J b) 2.5 m/s c) 34.4 m/s d) 60.3 m)
Answers
The total mechanical energy at point A is 617,400 J, and the velocity of the coaster at point A is 25 m/s, the velocity of the coaster at point B is 34.4 m/s. and the highest hill the coaster could have gotten over before point A with no additional mechanical energy is 63 m.
To solve this problem, we can use the conservation of mechanical energy, which states that the sum of kinetic energy and potential energy is constant in a closed system where there is no work done by non-conservative forces like friction. We can use this principle to find the answers to the questions.
a) The Total Mechanical Energy of the rollercoaster at Point A
The total mechanical energy of the rollercoaster at point A is the sum of its potential energy and kinetic energy. At point A, the rollercoaster is at its highest point, so its kinetic energy is zero. Therefore, the total mechanical energy at point A is equal to the potential energy, which is given by:
mgh = 1000 kg × 9.8 m/s^2 × 63 m = 617,400 J
b) The velocity of the coaster at point A
To find the velocity of the coaster at point A, we can use the conservation of mechanical energy principle again. At point A, all of the potential energy is converted into kinetic energy. Therefore, we can write:
1/2 mv^2 = mgh
where m is the mass of the rollercoaster, v is the velocity at point A, g is the acceleration due to gravity, and h is the height of point A relative to point E. Solving for v, we get:
v = sqrt(2gh) = sqrt(2 × 9.8 m/s^2 × 63 m) = 25 m/s
Therefore, the velocity of the coaster at point A is 25 m/s.
c) The velocity of the coaster at point B
To find the velocity of the coaster at point B, we can use the conservation of mechanical energy principle again. At point B, the rollercoaster is at a height of 42 m above the ground. Therefore, the potential energy at point B is:
mgh = 1000 kg × 9.8 m/s^2 × 42 m = 411,600 J
At point B, some of the potential energy is converted into kinetic energy, so we can write:
1/2 mv^2 + mgh = mgh_D
where v is the velocity at point B, h is the height of point B relative to point E, and h_D is the height of point D relative to point E. Solving for v, we get:
v = sqrt(2(mgh_D - mgh)/m) = sqrt(2(8780 J)/1000 kg + 2gh) = 34.4 m/s
Therefore, the velocity of the coaster at point B is 34.4 m/s.
d) The highest hill the coaster could have gotten over before point A with no additional mechanical energy
If the rollercoaster had no additional mechanical energy, its total mechanical energy at point A would be equal to its potential energy, which we calculated in part (a) to be 617,400 J. Therefore, the maximum height that the rollercoaster could reach without any additional mechanical energy is given by:
mgh_max = 617,400 J
Solving for h_max, we get:
h_max = 617,400 J / (1000 kg × 9.8 m/s^2) = 63 m
So, the highest hill the coaster could have gotten over before point A with no additional mechanical energy is 63 m.
Therefore, The coaster has a total mechanical energy of 617,400 J at point A, a velocity of 25 m/s, a velocity of 34.4 m/s, and a maximum hill height of 63 m that it could have traversed without using any further mechanical energy.
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Different tissues working together to perform a particular job are called:
A: Organ systems
B: Organelles
C: Organs
Answers
Answer:
C. Organs
Explanation:
Organs are groups of tissues that work together to perform a particular job.
hope this helps and is right; p.s. i really need brainliest :)
A 6.0 kg bag of cat food is dropped from 5.0 m ledge. How much mechanical energy does
it have just before it strikes the ground?
Answers
Answer:
294
Explanation:
5x9.8x6=294
potential energy=5(9.8)(6)
Equation
PE=MGH
While an object is in projectile motion (with upward being positive) with no air resistance.
Answers
Its vertical acceleration is equal to -g, while the horizontal component of its velocity is unchanged.
This is due to the projectile's dual components of vertical and horizontal velocities. But when the item moves, its vertical component of velocity changes but its horizontal component does not.
The projectile's horizontal component of velocity remains constant, therefore it only has a vertical component of acceleration and no horizontal component. The horizontal component of velocity remains unchanged as a result.
Since the only vertical force acting on the object is the weight, the vertical component of acceleration is equal to -g.
Therefore, the vertical component of its acceleration is equal to -g, while the horizontal component of its velocity remains constant.
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plss be qauick i give brainliest
Answers
Answer:
your questions are not clear
A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.
Answers
If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.
To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.
Given:
Mass of the box, m = 210 kg
Tension in the string, T = 1300 N
The angle of inclination, θ = 35°
Frictional force, f = 100 N
Initial speed, u = 0 m/s
Final speed, v = 10 m/s
First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:
T_parallel = T * cos(θ)
Next, let's calculate the net force acting on the box along the incline. The net force is given by:
Net force = T_parallel - f
Now, using Newton's second law, we can calculate the acceleration (a) of the box:
Net force = m * a
From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):
v^2 = u^2 + 2as
Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)
Now, let's plug in the given values and calculate the distance covered:
T_parallel = 1300 N * cos(35°) ≈ 1067.35 N
Net force = 1067.35 N - 100 N = 967.35 N
a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2
s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m
Therefore, the distance covered by the box is approximately 10.89 meters.
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To convert a Galvanometer of internal resistance RG = 200 2 into Ammeter a small resistance connected in parallel with the Galvanometer using a wire of resistance per length equal (2000/km). If the maximum current can be measured by the constructed Ammeter is 10A, assuming that the maximum current sustained by the Galvanometer is equal 0.8 mA. What is the length of the wire used to build up this ammeter?
Answers
To convert a galvanometer into an ammeter, a parallel resistance is added. With the given values, the resistance of the wire used to build the ammeter is 8 Ω/km, resulting in a wire length of 4 meters.
A galvanometer is an instrument that is used to detect and measure small amounts of electric current. It has a high resistance, which means that it only allows a small amount of current to flow through it. To convert a galvanometer into an ammeter, a small resistance is connected in parallel with the galvanometer. This reduces the overall resistance of the circuit, allowing more current to flow through it. The internal resistance of the galvanometer is given as RG = 200 Ω. Let the resistance of the wire used to build the ammeter be R. The maximum current that can be measured by the constructed ammeter is 10 A, and the maximum current sustained by the galvanometer is 0.8 mA.Using Kirchhoff's laws, we can find the total resistance of the circuit. Let this be RT: RT = RG + R, where RG is the internal resistance of the galvanometer and R is the resistance of the wire used to build the ammeter. Substituting the given values: RT = 200 Ω + R. The current through the ammeter is given by: I = V/RT, where V is the voltage across the circuit. Since the voltage is constant, we can write I = k/RT, where k is a constant.The maximum current that can be measured by the ammeter is 10 A. Substituting this value into the equation above 10 = k/(200 + R). The maximum current sustained by the galvanometer is 0.8 mA. This means that the total current through the circuit is 0.8 mA + I, where I is the current through the ammeter. Substituting the values into the equation above: 0.8 mA + k/RT = 10 mA, simplifying, we get k/RT = 9.2 mA.Substituting this value into the equation we derived earlier: 10 = (9.2 mA)/(200 Ω + R). Solving for R, we get R = 8 Ω/km. The resistance per unit length of the wire is given as 2000 Ω/km. Therefore, the length of the wire used to build the ammeter is given by:L = R/2000 = 8/2000 km = 4 m.For more such questions on ammeter:
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* ?Which object listed below has the greatest momentum.
A 0.50 g object rolling at 0.72 km/hr O
A 0:15 kg object rolling at 2 m/s O
A 0.15 kg object rolling at 3.6 km/hr
A 400 g object rolling at 2 m/s
Answers
Answer:
rolling at 0.2 m/s. A 0.15 kg object rolling at 2 m/s.
Explanation:
answer choices. A 0.05 kg object
Help me out on this?
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Equipotential lines are usually shown in a manner similar to topographical contour lines, in which the difference in the value of consecutive lines is constant. Clear the equipotential lines using the Erase button on the voltage tool. Place the first equipotential line 1 m away from the charge. It should have a value of roughly 9 V. Now, produce several additional equipotential lines, increasing and decreasing by an interval of 3 V (e.g., one with 12 V, one with 15 V, and one with 6 V). Don't worry about getting these exact values. You can be off by a few tenths of a volt. Which statement best describes the distribution of the equipotential lines?
1. The equipotential lines are closer together in regions where the electric field is weaker.
2. The equipotential lines are closer together in regions where the electric field is stronger.
3. The equipotential lines are equally spaced. The distance between each line is the same for all adjacent lines.
Answers
Answer:
B or 2
Explanation:
HELP PLEASE!!!!!!!!!!!!!!
Answers
B. convex lens forms larger virtual image, is the correct answer.
An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, (a) the temperature of the gas remains constant and the pressure decreases. (b) both the temperature and pressure of the gas decrease. (c) the temperature of the gas decreases and the pressure increases. (d) both the temperature and volume of the gas increase. (e) both the temperature and pressure of the gas increase. Group of answer choices a b c d e
Answers
Answer:
(b) both the temperature and pressure of the gas decrease.
Explanation:
An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.
Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
\( PT = K\)
Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.
WHAT IS THE MEAING OF- Grouping Data
Answers
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
Answers
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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An elevator is moving with an acceleration of 2.5 m/s. Find the tension in the cables if the total mass of a man and elevator is 80kg. When;
a) Moving up
b) Moving down
Answers
The tension in the cables are : a) 984 N when moving up,
b) 584 N when movng down
Given data:
mass = 80 kg
Acceleration = 2.5 m/s
Determine the tension in the cablesA) When moving up
Tension in the cable = m*g + m*a
= 80 * 9.8 + 80 * 2.5
= 984 N
B) When moving down
Tension in the cable = m*g - m*a
= 80 * 9.8 - 80 * 2.5
= 584 N
Hence we can conclude that the tension in the cable are 984 N moving up and 584 moving down.
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What is the net force on a skydiver falling with a constant velocity of 0 m/s downward?
Answers
1.What is the heat energy needed to change 36g of water 8.0°C to 34.0°C?2. What is the amount of heat necessary to melt 34kg of ice at 0.0 °C to water at 0.0 °C?
Answers
1)
Answer:
3912.48 J
Explanation:
The formula for calculating the quantity of heat is expressed as
H = mcθ
where
m is the mass of the substance
c is the specific heat capacity of the substance
θ is the change in temperature of the substance
From the information given,
m = 36
initial temperature = 8
final temperature = 34
θ = 34 - 8 = 26
c = 4.18J/g/C
By substituting these values into the formula,
H = 36 x 4.18 x 26
H = 3912.48 J
Quantity of heat energy needed = 3912.48 J
A 0.1 kg tennis ball is brought from a speed of 15 m/s to a speed of 45 m/s when hit by a tennis racket. If this done over 0.05 seconds, what is the power generated by the tennis racket
Answers
In the figure, a baseball is hit at a height h = 1.20 m and then caught at the same height. It travels alongside a wall, moving up past the top of the wall 1.1 s after it is hit and then down past the top of the wall 4.8 s later, at distance D = 54 m farther along the wall. (a) What horizontal distance is traveled by the ball from hit to catch? What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's velocity just after being hit? (d) How high is the wall?
Answers
Answer:
D.
Explanation:
The ball travels distance D in ∆t = 2.60 s. Therefore, the x component of the initial velocity is D =v
ox
⇒ ∆t = D/∆t = 15.4 m/s Due to the symmetry of projectile motions, it takes 1.2 seconds the ball to reach the initial height after passing the top of the wall downward. Therefore, the total flight time is t
tot
= 1.2 + 2.6 +1.2 = 5 s The horizontal range is R = v
ox
t
tot
= 77.0 m
By symmetry, the ball reaches the peak of the motion at time t
top
= t
tot
/2 = 2.5 s At the peak, the y component of the velocity is zero. Thus we have 0 = v
oy
– gt
top
⇒ v
oy
= gt
top
= 24.5 m/s The height of the wall is equal to the height of the ball at t = 1.2 s h = y (t = 1.2 s) = v
oy
+v
oy
t – (1/2)gt
2
= 23.3 m
What strength of magnetic field is used in a cyclotron in which protons make 2.8×10^7 revolutions per second?
Answers
The magnetic field in the cyclotron, is 0.292 T.
Angular velocity, ω = 2.8 x 10⁷rev/s
Charge of a proton, q = 1.6 x 10⁻¹⁹C
Mass of a proton, m = 1.67 x 10⁻²⁷kg
A cyclotron is a device that strongly accelerates the charge on charged particles or ions. The cyclotron amplifies the energy of the charged particles through the application of both magnetic and electric fields.
The expression for the angular velocity of the cyclotron is given by,
ω = qB/m
Therefore, the magnetic field in the cyclotron,
B = ωm/q
B = 2.8 x 10⁷x 1.67 x 10⁻²⁷/1.6 x 10⁻¹⁹
B = 0.292 T
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The road runner was being chased and outsmart the coyote. He ran past the road runner an fell straight down off a cliff. He fell with the same acceleration as gravity (9.8). Calculate his displacement if he fell for 4 seconds
Answers
The displacement of the runner after four seconds is 78.4 m.
What is the displacement after 4 seconds?We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.
Acceleration of the runner (g) = 9.8 m/s^2
Initial velocity of the runner (u) = 0 m/s
Time take (t) = 4 seconds
We then have;
h = ut + 1/2gt^2
If we then know that the initial velocity of the person is zero, then we have;
h = 1/2gt^2
h = 0.5 * 9.8 * (4)^2
h = 78.4 m
The height is 78.4 m.
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Sounds waves are an example of which type of wave? Longitudinal Transverse O Electromagnetic
Answers
Answer:
Happy now?
Explanation:
Correct answer:
Sound waves are longitudinal waves, meaning that the waves propagate by compression and rarefaction of their medium. They are termed longitudinal waves because the particles in the medium through which the wave travels (air molecules in our case) oscillate parallel to the direction of motion.
describe why people are better off not consuming an additional good or service if the marginal cost is greater than the marginal benefit.
Answers
how many males are color blind one in 50 1 and 10 one hundred one and 12
Answers
One in twelve males have color blindness whereas One in two-hundred females have color blindness. Thus, Option D is correct.
Color blindness is the ability to distinguish different colors. It is hard to differentiate the colors between the same color family. A person with color blindness can not able to see red and green, and can able to see grey, black, and white. It is often inherited.
A person with color blindness can not able to differentiate the colors between red and green. There are three types of color blindness they are Deuteranomaly (difficulty with red-green color blindness and it makes green look redder), Protanomaly(red look greener), Protanopia, and deuteranopia (difficulty in identifying red and green). It is cured by using proper contact lenses.
Thus, One in twelve males has color blindness. Hence, the ideal solution is option D.
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
Answers
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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What's Wrong With This? Suppose you're watching a science fiction movie and one of the scenes involves a spaceship battle in outer space. Spaceship A launches a successful strike on spaceship B. The scene is presented from the perspective of spaceship A. The occupants of spaceship A view spaceship B blowing up as the result of the successful missile strike. They see the flames of the explosion and shortly thereafter hear the thunderous sound of the explosion.
While the scene is definitely exciting, there is a significant fault with it in terms of the physics. What law of physics was violated in the filming of the scene? Explain.
Answers
PLEASE ASAAAAAP
Just do the last part I have filled in the rest
Fill in the last one please
Answers
Based on the equation D = ΔT 8.4 and the information provided, the distance to the epicenter of the earthquake would be is 16.8 kilometers.
What is the epicenter of an earthquake?The epicenter refers to the location on the earth's surface that is vertically aligned with the original location of this event. This means the epicenter does not determine the exact location of origin but the location on the earth's surface.
What is the distance to the epicenter?The equation to know this is D =ΔT 8.4. In this equation:
T = difference in time between the P and the S waveNow, let's calculate the distance:
D =ΔT 8.4
D = 2 x 8.4
D = 16.8 km
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