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When Mendel crossed a plant with green peas and a plant with yellow peas, what color peas did the offspring have?
A)All offspring had green peas.
B)All offspring had yellow peas.
C)Half of the offspring had yellow peas and half had green peas.
D)Some of the offspring had yellow peas and some had yellow-green peas.

Answer:

When the parcel rises, its volume expands as it strives to maintain equilibrium with the lower pressure outside the air mass and pushes into the surrounding atmosphere. In this way, some of the thermal energy added to the air is used for expansion rather than warming.

Answer:

5

Explanation:

1

Generally, the coefficient of static friction should be at least 0.7 for a car traveling at this speed, but this value could be higher depending on the specific conditions.

The coefficient of static friction, or μs, is the ratio of the maximum static force that can be applied without causing slipping to the normal force between two surfaces. The coefficient is affected by the surfaces in contact and the material they are made of.

The tires of a car also have an effect on the coefficient of static friction. Tires with a greater tread depth can provide better grip on the road and therefore have a higher coefficient of static friction than tires with a shallow tread. Tire pressure also plays a role, as low pressure can reduce the coefficient of static friction.

The weight of the vehicle is also an important factor. Heavier vehicles tend to have a higher coefficient of static friction, as the greater mass increases the normal force between the car and the surface.

In conclusion, the coefficient of static friction for a car traveling at 115 km/h around a turn depends on several factors, including the road surface, the vehicle's tires, and the vehicle's weight.

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In the following question, among the various parts to solve on visible spectrum.- A. Red light has a longer wavelength than violet light. B. Violet light has a higher frequency than red light. C. Violet light has greater energy than red light.

Violet and red light from the visible spectrum can be compared based on their wavelengths, frequencies, and energies. Violet light has a shorter wavelength, higher frequency, and greater energy than red light. The answers to the specific questions are: Which has the longer wavelength? Red light has a longer wavelength than violet light. Which has the greater frequency? Violet light has a higher frequency than red light. Which has the greater energy? Violet light has greater energy than red light. An HTML-formatted answer would look like this:

Violet and red light from the visible spectrum can be compared based on their wavelengths, frequencies, and energies. Violet light has a shorter wavelength, higher frequency, and greater energy than red light. The answers to the specific questions are:

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The angular speed of the horse that which is 7 m from the cenetr of a merry go round is 252 m/s.

Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.

To calculate the angular speed of the horse, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

Hence, the angular speed of the horse is 252 m/s.

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Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

Answer:

The point at which rays or waves meet after reflection or refraction, or the point from which diverging rays or waves appear to proceed is called focal point

Answer:

\( \huge{ \boxed{ \bold{ \sf{90 \: joule}}}}\)

✑ First , Let's know what kinetic energy is :

⇾ The energy possessed by a body by the virtue of it's motion is called kinetic energy of the body. A flying bird , a moving car , running water , wind , a bullet fired from a gun , an arrow left from a bow , rolling stone etc are some examples of kinetic energy.

The Kinetic energy of a moving body is determined by the formula :

\( \boxed{ \underline{ \sf{KE= \frac{1}{2} m {v}^{2} }}}\)

Here ,

--------------------------------------------------------------

☇ Now , Let's solve :

☄ Given :

☄ To find :

⤿ \( \boxed{ \sf{KE= \frac{1}{2} m {v}^{2} }}\)

Plug the values and simplify :

→ \( \sf{ \frac{1}{2} \times 20 \times {(3)}^{2} }\)

→ \( \sf{ \frac{1}{2} \times 20 \times 9}\)

→ \( \boxed{ \bold{\sf{90 \: joule}}}\)

Hope I helped !

Have a wonderful day ! ツ

~TheAnimeGirl ♡

The standard volume of hydrogen peroxide used with permanent hair color is typically 20 volume (6%).

The standard volume of hydrogen peroxide used with permanent hair color is typically 20 volume (6%). It is important to note that different hair color brands or formulations may offer different volumes of hydrogen peroxide options, so it is always advisable to refer to the specific instructions and recommendations provided by the hair color manufacturer.

The percentage value, in this case, 6%, indicates the weight of hydrogen peroxide present in the formulation. In a 20 volume hydrogen peroxide solution, 6% of the total weight is hydrogen peroxide, while the remaining 94% consists of other components, such as water, stabilizers, and conditioners.

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Though Sodium is explosive in nature and chlorine is poisonous to human, after reaction they form Sodium chloride, which is common salt that use in kitchen.

So, Sodium chloride is neither explosive nor poisonous - it is common salt. People uses it in daily day life.

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The index of refraction of the gas is n = 1.00097

The ratio between the speed of light in medium to speed in a vacuum is the refractive index. When light travels in a medium other than the vacuum, the atoms of that medium continually absorb and re-emit the particles of light, slowing down the speed light.

The Michelson interferometer  is a precision instrument that produces interference fringes by splitting a light beam into two parts and then recombining them after they have traveled different optical paths.

Generally the  index of refraction of the gas  is mathematically represented as:  

                              n = 1 + (Nλ /2L)

Given:

  The wavelength of light is  λ = 580 nm = \(580 * 10^{-9} m\)

  The length of tube is  L = 4.90 cm = 0.049 m

  The number of fringes is  N = 164

Substituting these values in above equation we get: n = 1.00097

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The kinetic energy of the moving sled with the given value of mass and velocity is 7.84 × 10³ Joules.

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given the data in the question;

To determine the kinetic energy of the sled, we substitute our given values into the above expression.

K = (1/2)mv²

K = (1/2) × 20kg × (28.0m/s)²

K = 0.5 × 20kg × 784m²/s²

K = 7840kgm²/s²

K = 7.84 × 10³J

Therefore, the kinetic energy of the moving sled with the given value of mass and velocity is 7.84 × 10³ Joules.

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The change in entropy when the thermodynamic state of a gas changes configuration from one with 3.8x10¹⁸ microstates (W) to one with 7.9x10¹⁹ microstates (W) is 3.23x10⁻²² J/K.

The formula for entropy is:

S = KlnW

where S is the entropy of the system,

K is the Boltzmann constant,

and W is the number of microstates available.

Here, the initial number of microstates is 3.8 x 10¹⁸ and the final number of microstates is 7.9 x 10¹⁹. So, the change in entropy is:

ΔS = K ln(W₂/W₁) = (1.38 × 10⁻²³ J/K) ln(7.9 × 10¹⁹/3.8 × 10¹⁸) = (1.38 × 10⁻²³ J/K) ln(20.789) = 3.23 × 10⁻²² J/K

Given data: Number of microstates at the initial state,

W1 = 3.8x10¹⁸.

Number of microstates at the final state, W2 = 7.9x10¹⁹.

Boltzmann's constant, K = 1.38x10⁻²³ J/K.

Formula used: ΔS = Kln(W₂/W₁)

The entropy change of the system is given by the equation.

ΔS = Kln(W₂/W₁),

where W1 is the initial number of microstates,

W2 is the final number of microstates,

and K is Boltzmann's constant.

Substituting the given values in the equation, we get:

ΔS = (1.38x10⁻²³ J/K)ln(7.9x10¹⁹/3.8x10¹⁸)

ΔS = (1.38x10⁻²³ J/K)ln20.789= 3.23x10⁻²² J/K

Therefore, the change in entropy when the thermodynamic state of a gas changes configuration from one with 3.8x10¹⁸ microstates (W) to one with 7.9x10¹⁹ microstates (W) is 3.23x10⁻²² J/K.

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the temperature at which the average velocity of an H2 molecule would be sufficient to escape Earth is  9,990 Kelvin. And the temperature at which the average velocity of an O2 molecule would be sufficient to escape Earth is approximately 2,740 Kelvin.

The average velocity of a gas molecule can be calculated using the root mean square (RMS) velocity, which is given by the equation:

v_rms = √(3kT/m)

Where v_rms is the RMS velocity, k is the Boltzmann constant (1.38 x 10^-23 J/K), T is the temperature in Kelvin, and m is the mass of the molecule.

a) For an H2 molecule with a mass of approximately 3.32 x 10^-27 kg, we can rearrange the equation to solve for temperature:

T = (v_rms^2 * m) / (3k)

Substituting the threshold velocity v_rms = 1.07 x 10^4 m/s, and the mass of H2 molecule m = 3.32 x 10^-27 kg, we can calculate the temperature:

T = (1.07 x 10^4 m/s)^2 * (3.32 x 10^-27 kg) / (3 * 1.38 x 10^-23 J/K) ≈ 9,990 K

Therefore, the temperature at which the average velocity of an H2 molecule would be sufficient to escape Earth is approximately 9,990 Kelvin.

b) Similarly, for an O2 molecule with a mass of approximately 5.32 x 10^-26 kg:

T = (v_rms^2 * m) / (3k)

Substituting the threshold velocity v_rms = 1.07 x 10^4 m/s, and the mass of O2 molecule m = 5.32 x 10^-26 kg, we can calculate the temperature:

T = (1.07 x 10^4 m/s)^2 * (5.32 x 10^-26 kg) / (3 * 1.38 x 10^-23 J/K) ≈ 2,740 K

Therefore, the temperature at which the average velocity of an O2 molecule would be sufficient to escape Earth is approximately 2,740 Kelvin.

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The mechanical advantage of the nutcracker is 3.5.

The Mechanical Advantage (MA) is a measure of how much a machine, such as a nutcracker, amplifies the input force. It is calculated by dividing the output force by the input force.

In your scenario, an input force of 75 N (Newtons) is applied to the nutcracker, and the output force exerted on the walnut is 262.5 N. To find the mechanical advantage, we will use the formula:

MA = Output Force / Input Force

Plugging in the values from your question, we have:

MA = 262.5 N / 75 N

MA = 3.5

The mechanical advantage of the nutcracker in this situation is 3.5. This means that the nutcracker amplifies the applied force by 3.5 times, allowing you to crack the walnut with greater ease. A higher mechanical advantage indicates that the machine is more effective at increasing the applied force, making tasks easier to accomplish.

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Answer:

The kinetic coefficient of friction between box and floor is 0.443.

Explanation:

Let suppose that the box is accelerated uniformly, the acceleration (\(a\)), measured in meters per square second, is determined by the following kinematic formula:

\(a = \frac{v_{f}-v_{o}}{t}\) (1)

Where:

\(v_{o}\), \(v_{f}\) - Initial and final speeds of the box, measured in meters per second.

\(t\) - Time, measured in seconds.

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 2\,\frac{m}{s}\) and \(t = 4\,s\), then the acceleration experimented by the box is:

\(a = \frac{2\,\frac{m}{s}-0\,\frac{m}{s} }{4\,s}\)

\(a = 0.5\,\frac{m}{s^{2}}\)

Based on the body diagram, we proceed to form the equations of equilibrium:

\(\Sigma F_{x} = P\cdot \cos \theta -\mu_{k}\cdot N = m\cdot a\) (1)

\(\Sigma F_{y} = N - m\cdot g - P\cdot \sin \theta = 0\) (2)

Where:

\(P\) - Magnitude of the force exerted on the box, measured in newtons.

\(\theta\) - Direction of the force exerted on the box, measured in sexagesimal degrees.

\(\mu_{k}\) - Kinetic coefficient of friction between box and floor, dimensionless.

\(N\) - Normal force from the floor to the box, measured in newtons.

\(m\) - Mass of the block, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

Now we proceed to solve the system of equation for the kinetic coefficient of friction between box and floor:

By (1)

\(\mu_{k}\cdot N = P\cdot \cos \theta -m\cdot a\)

\(\mu_{k} = \frac{P\cdot \cos \theta - m\cdot a}{N}\)

By (2)

\(N = m\cdot g +P\cdot \sin \theta\)

And then, we get the resulting expression:

\(\mu_{k} = \frac{P\cdot \cos \theta - m\cdot a}{m\cdot g + P\cdot \sin \theta}\) (3)

If we know that \(P = 400\,N\), \(\theta = 50^{\circ}\), \(m = 25\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(a = 0.5\,\frac{m}{s^{2}}\), then the kinetic coefficient of friction between box and floor is:

\(\mu_{k} = \frac{(400\,N)\cdot \cos 50^{\circ}-(25\,kg)\cdot \left(0.5\,\frac{m}{s^{2}} \right)}{(25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)+(400\,N)\cdot \sin 50^{\circ}}\)

\(\mu_{k} = 0.443\)

The kinetic coefficient of friction between box and floor is 0.443.

The kinetic coefficient of friction between box and floor is 0.443.It is the ratio of friction force and the normal recation force.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

F is the force =400 N

m is the mass of box= 25-kg

u is the velocity starting from rest=0

v is the velocity achieved = 2.0 m/s

t is the time = 4.0 s.

\(\rm \mu\) is  the coefficient of kinetic friction between box and floor.

The aceleration is found as;

\(\rm a= \frac{v_f-v_u}{t} \\\\ \rm a= \frac{2-0}{4} \\\\ \rm a= 0.5 m/sec^2\)

The normal reaction force is find as;

\(N= mg +P sin \theta\)

The cofficient of the kinetic coefficient of friction between box and floor;

\(\rm \mu_k = \frac{Pcos \theta - ma }{N } \\\\ \rm \mu_k = \frac{Pcos \theta - ma }{ mg +P sin \theta } \\\\ \rm \mu_k = \frac{400 cos 50^0 - 25 \times 0.5 }{ 25 \times 9.81 +400 \times sin 50^0 } \\\\ \rm \mu_k =0.443\)

Hence he kinetic coefficient of friction between box and floor is 0.443.

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The amplitude of the alternating voltage across the secondary coil will depend on the ratio of the number of turns in the secondary coil to the number of turns in the primary coil. This ratio is known as the turns ratio, and it determines the voltage transformation that occurs between the primary and secondary coils.

Assuming that the turns ratio is Ns/Np, where Ns is the number of turns in the secondary coil and Np is the number of turns in the primary coil, the voltage transformation ratio can be expressed as Vp/Vs = Np/Ns, where Vp is the voltage across the primary coil and Vs is the voltage across the secondary coil.
If we assume that the primary coil is connected to a 240-V rms voltage, then the peak voltage across the primary coil will be Vp = 240 * sqrt(2) = 339 V. Using the turns ratio, we can calculate the peak voltage across the secondary coil as Vs = Vp * (Ns/Np) = 339 * (Ns/Np).
Therefore, the amplitude of the alternating voltage across the secondary coil will depend on the turns ratio, which in turn depends on the number of turns in each coil. It is important to note that the voltage transformation will also depend on the frequency of the input voltage, the magnetic properties of the core material, and other factors that can affect the efficiency of the transformer.

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Answer:

Three (3).

Explanation:

The octet rule is a rule in chemistry that states that, chemical elements would either gain or loss electrons in their outermost shell in order to attain a stable electronic configuration i.e having eight (8) valence electrons in their outermost shell such as chemical elements found in group 8 (2-8-8) known as noble gas.

A phosphorus atom needs to gain three (3) electrons to achieve a full octet because the atomic number of phosphorus is 15 and as such it has the electronic configuration of 2-8-5 and needs three electron in order to become a stable element.

Answer:

.21

Explanation:

i see everyone got it wrong so ill give you the answer, good luck :)

The units that would not be appropriate for describing rotational acceleration are \(rev/m^2\). Rotational acceleration, also known as angular acceleration, is a measure of how the angular velocity of an object changes with time.

The appropriate units for rotational acceleration are either radians per second squared \((rad/s^2)\) or degrees per second squared (\(degrees/s^2\)). These units are used because they describe the change in angular velocity (either in radians or degrees) per unit of time.

Revolutions per second squared (\(rev/s^2\)) is also an acceptable unit for rotational acceleration, as it indicates the change in the number of complete rotations an object makes per second, per unit of time (in seconds). This unit can be converted to \(rad/s^2\) or \(degrees/s^2\) if needed.

However, \(rev/m^2\) is not a suitable unit for rotational acceleration, as it incorrectly associates the acceleration with an area (square meters, \(m^2\)) rather than time. This unit does not provide a clear description of how the angular velocity is changing with respect to time and therefore should not be used to describe rotational acceleration.

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Answer:

Explanation:

The principle is that the slope of the line on a velocity-time graph reveals useful information about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration is positive, then the slope is positive (i.e., an upward sloping line).

The point of interest in the velocity time graph is the slope of the graph which represents the acceleration of the given moving body

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds², acceleration is defined as the ratio of velocity to time.

Only the constant acceleration is applicable to Newton's three equations of motion.

The acceleration of any item is represented by the slope of the velocity time graph.

The slope of the line on a velocity-time graph provides important details about the object's acceleration. The slope is 0 if the acceleration is zero. The slope is positive if the acceleration is positive and if the slope of the velocity time graph is negative the acceleration is negative

Thus, the point of interest in the velocity time graph is the slope of the graph which represents the acceleration of the given moving body.

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Answer:

60words/minute

Explanation:

If Sunitha can type 1800 words in half an hour, this can be expressed as;

1800 words = 30 minutes

To get her typing speed per minute, we will use the formula

Speed = Number of words/Time used

Typing speed = 1800/30

Typing speed = 60words/minute

Hence her typing speed in words per minute is 60words/minute

Answer:

D. All of the above

Explanation:

Because it's the most logical answer.

To determine the time required for the activity of a block of cheese containing 131I to decay to an acceptable level, we can use the concept of half-life. The half-life of 131I is given as 8.0 days.

Let's assume we have an initial activity A₀ for the block of cheese. After one half-life, the activity will be reduced to half, A₀/2. After two half-lives, it will be reduced to A₀/2^2, and so on.

To calculate the time required for the activity to decay to an acceptable level, we need to determine the number of half-lives it takes for the activity to reach that level.

Let's denote the acceptable activity level as A_acceptable. The number of half-lives (n) can be calculated using the formula:

A₀ / 2^n = A_acceptable

Rearranging the equation, we get:

2^n = A₀ / A_acceptable

Taking the logarithm base 2 of both sides:

n = log₂(A₀ / A_acceptable)

Finally, we can substitute the half-life of 131I (8.0 days) into the equation:

n = log₂(A₀ / A_acceptable) / (8.0 days / half-life)

Once we have the value of n, we can calculate the time required by multiplying n with the half-life of 131I.

It's important to note that the acceptable activity level will depend on regulatory guidelines or safety standards specific to the situation.

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Answer:

Explanation:

Reactants

BaSO4 has 4 oxygens and only 1 sulfur. That's a good thing to notice.

H2SO4 has 4 oxygens and only 1 sulfur.

The reactants have 4 + 4 oxygens = 8 oxygens.

Products

It is right, but you might struggle a bit with the answer.

Notice that HSO4 is in brackets followed by a two

(HSO4)2        

When the 2 is outside the brackets, everything inside the brackets get's doubled.

There are 2 Hs

There are 2 Ss

There are 4 * 2 Oxygens = 8 oxygens, some as the reactants.

Break the product into simplified form

\(\\ \sf\longmapsto Ba(HSO_4)_2\)

\(\\ \sf\longmapsto BaH_2S_2O_8\)

Oxygen on products side=8

#2.

Oxygen on reactant side=4+4=8atoms

Answer:

Calcium chloride is very effective, working at temperatures below most products, and is significantly more effective than sodium chloride because of its ability to extract moisture from its surroundings and to cause exothermic or heat generating reactions.

Explanation:

Hope this helps

A student is pulling a wagon and records the force vs time values in the table, then the acceleration of the wagon would remain constant, therefore the correct answer is option D.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem if a student is pulling a wagon and records the force vs time values in the table,

As the Force of the pulling is constant and assuming the mass of the wagon to be constant the acceleration of the wagon would not change.

Thus, the correct answer is option D.

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The question is incomplete, the complete question is,

A student is pulling a wagon and records the force vs time values in the table, which of the following will also remain constant for the wagon

A. Displacement

B. velocity

C. Momentum

D. Acceleration

The absolute maximum bending stress in the shaft if it is subjected to the pulley loadings is (P1 + P2 + RA + RB) / (π x (2)^2/4).

The maximum bending stress in a steel shaft with a diameter of 2 in, subjected to pulley loadings, can be determined using the following equation:

σ = P/(π x d^2/4)

where P is the load in pounds, and d is the diameter of the shaft in inches.

In this case, P is the sum of the two pulley loads. Since the bearings A and B are only exerting vertical reactions on the shaft, these should be included in the calculation.

Therefore, the maximum bending stress in the steel shaft is σ = (P1 + P2 + RA + RB) / (π x (2)^2/4). This value should be compared to the allowable bending stress for the material to ensure that the shaft is designed to handle the applied loads without exceeding the material's strength properties.

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Answer:

(i) It will take longer (75/22 times) the time to boil a given quantity of water compared to when the current is working at its rated capacity

(ii) The reasons are;

(1) For economy; most of the appliances in the home only require low power circuitry with thinner wire while a separate high power circuitry is created directly from the main supply for the high electric power rated appliances

(2) For safety; to prevent the over heating of the electric circuits when an high electric power appliance needs to be connected an high power electric power outlet has to be specified

Explanation:

(i) The power rating of the kettle = 3 kW

The voltage rating of the circuit, V = 220 V

The current rating, I = 4 A

The formula for electric power = I² × R = I × V

Therefore, we have;

Power produced = 220 V × 4 A = 880 V·A = 800 W

Hence, since the power produced is below the power rating of the electric kettle, it will take a longer time to boil a given amount of water than specified by the kettle manufacturer

The energy supplied H = V×I×t

Where:

t = Time in seconds

Therefore, we have;

3 kW = 3000 W;

3000 × t₁ = 880 × t₂

t₂/t₁ =3000/880 = 75/22

Hence the kettle will take 75/22 multiplied by the time it takes when working at rating capacity to boil a given quantity of water

(ii) This is so because the power consumption already factored in the electrical installation as well as the type of appliances utilized in the home allow for several low power rating consumption and few high power rating consumption

Therefore, for both economy and safety the electrical circuit are split to allow for the use of very thick copper or aluminium electric cables in the high power rating electric circuits to which can be plugged high electric power consuming devices such as the water heater and electric cooker

The low electric power consuming devices, such as the electric bulb and fans are connected to the low or "regular" power rating electric circuit outlets

The current required for high power and low power appliances is different and also the fuse rating required for both the appliances different, so two separate circuits are used for high power and low power appliances.