Predict the acceleration of a roller coaster that goes from 0 to 190km/h in 4 seconds. Express your answer in km/s^2. Round to three decimal places.

La energía no se crea ni se destruye solo se transforma

Explanation:

espero y te ayude

Answer:

to increase friction between the floor and the player's feet

Explanation:

It is important for basketball players to wear shoes with tread when playing in order to increase friction between the floor and the player's feet.

Friction between the floor and the player's feet will ensure that players do not trip easily during the course of playing. It also helps in such a way that players can stop quickly and run in the opposite direction without losing traction. Without this friction, it would be virtually impossible to play the game.

There is a thermal efficiency of 0.46 for a heat engine. With each cycle, it absorbs 780 J of heat from the high-temperature storage. B) 200 J waste heat it discard each cycle.

The thermal efficiency of a heat engine is defined as the ratio of the work output to the heat input, so in this case, the thermal efficiency is 0.46. Therefore, the work output is 0.46 * 780 J = 360 J.

The waste heat discarded each cycle is the difference between the heat input and the work output, so 780 J - 360 J = 200 J.

How much useful work does the heat engine perform in each cycle?

The useful work that the heat engine performs in each cycle can be determined by using the formula: thermal efficiency * heat absorbed = useful work. In this case, the thermal efficiency is 0.46, and the heat absorbed is 780 J.

Therefore, the useful work done by the engine is 0.46 * 780 J = 360 J.

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Answer:

22

Explanation:

Answer:

45.5 v

Explanation:

I = 1.3 A

R = 35 Ω

V = I * R

V = 1.3 * 35 = 45.5 v

By the help of Kinetic energy ,the ratio of the brick's mass to the pebble's mass is \(\frac{9}{25}M = m\)

A moving item or particle might have power of a certain sort called kinetic energy. An object gains kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. Kinetic energy is a characteristic of motion that depends on the mass and speed of an object or particle. Motion includes all combinations of vibration, axis rotation, translation, and movement (along a path from one location to another).

M should represent the brick mass.

Let m represent the pebble's mass.

.\(\frac{1}{2} M(v)^2\) =KE

\(\frac{1}{2} M(3)^2\)=KE

\(\frac{1}{2} m(5)^2\)= KE

\(\frac{1}{2} M(3)^2= \frac{1}{2} m(5)^2\)

9M = 25m

\(\frac{9}{25}M = m\)

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We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)

(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.

The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.

Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).

(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).

(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.

(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.

(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.

As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.

This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.

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Answer:

29.412m/s

Explanation:

\(F=ma\) where F= force, m= mass, and a=acceleration

we also know that,

a = Δv / t where Δv = change in velocity and t = time

thus F = m ( Δv / t)

\(50000=850(\frac{v}{0.5})\)

\(\frac{50000}{1700}=\) Δv

29.412m/s=Δv

Answer:

Confucius believe that kings should behave RIGHTLY

Explanation:

CONFUCIUS  believe that kings are supposed to behave rightly and rule justly ( according to the codes of ethics )  of the land and also live a right and just life.

Confucianism is an ancient philosophy established as far back as the fifth century by Confucius it's main aim was to guide the ancient and modern systems of government in the whole of Asia. it is called a religion by some while some call it a code of ethics and way of leadership

Answer:

CONFUCIUS  believe that kings are supposed to behave rightly and rule justly ( according to the codes of ethics )  of the land and also live a right and just life.

Confucianism is an ancient philosophy established as far back as the fifth century by Confucius it's main aim was to guide the ancient and modern systems of government in the whole of Asia. it is called a religion by some while some call it a code of ethics and way of leadership

Explanation:

The participants are being tested for kinesthetic intelligence through various activities and tasks that require them to use their body and physical movements.

These tasks can include things like dance, sports, or other physical activities that require coordination, balance, and control. The participants are evaluated on their ability to perform these tasks accurately and efficiently, as well as their ability to learn new movements and adapt to different physical challenges. By observing and evaluating their performance in these activities, the researchers can gain insight into the participants' kinesthetic intelligence and their ability to use their bodies in a coordinated and controlled manner.

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Answer:

→They are the followings :

This are some points that teacher should have mentally.

In general, the statement that validation is not needed for single-use systems in a bioreactor is not accurate. Validation is an essential process in bioprocessing that ensures the reliability, consistency, and safety of the manufacturing process. Single-use systems, which are increasingly used in bioreactors, can introduce unique challenges and considerations.

Validation of single-use systems involves assessing their performance, integrity, and compatibility with the process requirements. Factors such as material integrity, sterile connections, and proper functioning of sensors and control systems should be evaluated to ensure the system's suitability for use.

While single-use systems offer advantages in terms of cost, flexibility, and minimizing cross-contamination risks, they still require validation to demonstrate their reliability and performance. It is essential to follow industry standards, regulatory guidelines, and good manufacturing practices to ensure the quality and safety of bioprocessing operations, regardless of the system being used.

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Answer:

This question appear incomplete

Explanation:

This question appear incomplete because there is no list of closest correct answer there. Although can still be well attempted.

The formula to be used here is

average speed = distance ÷ time

The unit of speed here would be meters per second (m/s). However, some of the lines do not really fall on a measurable line on the graph and can only be "best assumed".

A: distance is 1600 meters

time appear to be 4 seconds (definitely less than 5 seconds according to the graph).

speed = 1600 ÷ 4

speed = 400 m/s

B: distance is 1600 meters

time appear to be 18 seconds (definitely less than 20 seconds according to the graph)

speed = 1600 ÷ 18

speed = 88.89 m/s

C: distance is 1600 meters

time is 65 seconds

speed = 1600 ÷ 65

speed = 24.62 m/s

D:  distance is 1600 meters

time is 105 seconds

speed = 1600 ÷ 105

speed = 15.24 m/s

E: distance is 1100 meters

time is 120 seconds

speed = 1100 ÷ 120

speed = 9.17 m/s

F: distance is 500 meters

time is 120 seconds

speed = 500 ÷ 120

speed = 4.17 m/s

G: distance appear to be 250 meters

time is 120 seconds

speed = 250 ÷ 120

speed = 2.08 m/s

H: distance appear to be 50 meters

time is 120 seconds

speed = 50 ÷ 120

speed = 0.42 m/s

The average speed for each object are:

1. The average speed of A is 400 m/s

2. The average speed of B is 88.89 m/s

3. The average speed of C is 24.62 m/s

4. The average speed of D is 15.24 m/s

5. The average speed of E is 9.17 m/s

6. The average speed of F is 4.17 m/s

7. The average speed of G is 2.08 m/s

8. The average speed of H is 0.33 m/s

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

With the above formula, we can obtain the average speed for each object as follow:

1. Determination of average speed of A

Total distance = 1600

Total time = 4 s

Average speed = 1600 / 4

2. Determination of average speed of B

Total distance = 1600

Total time = 18 s

Average speed = 1600 / 18

3. Determination of average speed of C

Total distance = 1600

Total time = 65 s

Average speed = 1600 / 65

4. Determination of average speed of D

Total distance = 1600

Total time = 105 s

Average speed = 1600 / 105

5. Determination of average speed of E

Total distance = 1100

Total time = 120 s

Average speed = 1100 / 120

6. Determination of average speed of F

Total distance = 500

Total time = 120 s

Average speed = 500 / 120

7. Determination of average speed of G

Total distance = 250

Total time = 120 s

Average speed = 250 / 120

8. Determination of average speed of H

Total distance = 40

Total time = 120 s

Average speed = 40 / 120

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Answer:

1 : an object occupying a central position especially : an adornment in the center of a table. 2 : one that is of central importance or interest in a larger whole the centerpiece of a political agenda.

Explanation:

The spaceship is traveling at a speed of 1877.8 millimeters per second.

The spaceship is traveling at a speed of 4200 miles per hour. To convert this speed to millimeters per second, we need to perform a few conversions.

First, let's convert miles to kilometers. There are approximately 1.60934 kilometers in one mile.

So, the speed in kilometers per hour is 4200 miles per hour multiplied by 1.60934 kilometers per mile. Next, let's convert kilometers per hour to meters per second.

There are 1000 meters in one kilometer, and 3600 seconds in one hour. So, the speed in meters per second is the speed in kilometers per hour divided by 1000 meters per kilometer, and then divided by 3600 seconds per hour.

Finally, let's convert meters per second to millimeters per second. There are 1000 millimeters in one meter. So, the speed in millimeters per second is the speed in meters per second multiplied by 1000 millimeters per meter.

Let's calculate the conversion step-by-step:

1. Convert miles to kilometers: 4200 miles/hour × 1.60934 kilometers/mile = 6758.048 kilometers/hour

2. Convert kilometers to meters and hours to seconds: 6758.048 kilometers/hour ÷ 1000 meters/kilometer ÷ 3600 seconds/hour = 1.8778 meters/second

3. Convert meters to millimeters: 1.8778 meters/second × 1000 millimeters/meter = 1877.8 millimeters/second

Therefore, the spaceship is traveling at a speed of 1877.8 millimeters per second.

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The given quantities are a = 3.0 m, b = 9.8 s, and c = 72 m/s. The value of the quantity is not provided, so it cannot be determined based solely on the given information.

The given quantities represent measurements in meters, seconds, and meters per second. However, without specifying the desired quantity or providing an equation or relationship involving these quantities, it is not possible to calculate a specific value. To determine the value of a specific quantity, additional information or context is needed. Please provide more details or specify the quantity you want to calculate.

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Answer:

 V = 2.52 10³ V

Explanation:

The electric potential for a point charge is

       V = k ∑ \(\frac{q_i}{r_i}\)

In this case the formula is

       V = k (\(\frac{q_1}{r_1} + \frac{q_2}{r_2}\))

distances are the absolute value

       r₁ =√ (7.1 -0)² = 7.1 m

       r₁ =√ (7.1 - 14.3)² = 7.2 m

we substitute

       V = 9 10⁹ (q₁ / 7.1 + q₂ / 7.2)

we have two possibilities

* different charges

         V = 9 10⁹ (q₁ / 7.1 + q₂ / 7.2)

* equal charges and same sign

          q₁ = q₂ = q

         V = 9 10⁹ q (1 / 7.1 + 1 / 7.2) = p 9 10⁹   0.2797

         V = 2.52 10⁹ q

if we assume a value of the charge, for example q = 1 10⁻⁶ c

           V = 2.52 10⁹ 1 10⁻⁶

            V = 2.52 10³ V

Answer:

Image result for What do executive departments do?​

Under Article II of the Constitution, the President is responsible for the execution and enforcement of laws created by Congress. Fifteen executive departments—each led by an appointed member of the President's Cabinet—carry out the day-to-day administration of the Federal Government.

Explanation:

The Cabinet and independent federal agencies are responsible for the day-to-day enforcement and administration of federal laws. ... Fifteen executive departments — each led by an appointed member of the President's Cabinet — carry out the day-to-day administration of the federal government.

The pressure acting on the top and bottom faces is\(0.1635 N/cm^2\), the pressure acting on the side faces is\(0.4905 N/cm^2,\) and the pressure acting on the front and back faces is \(0.981 N/cm^2.\)

To compute the pressure acting on each face of the rectangular block, we need to know the weight of the block and the area of each face.

The weight of the block can be calculated as follows:

Weight = Mass x Gravity

Weight = 0.3 kg x 9.81 \(m/s^2\)

Weight = 2.943 N

The area of each face can be calculated as follows:

Top and bottom face: length x width = 6 cm x 3 cm = 18 \(cm^2\)

Side faces: length x height = 6 cm x 1 cm = 6 \(cm^2\)

Front and back faces: width x height = 3 cm x 1 cm = 3\(cm^2\)

Now we can calculate the pressure acting on each face:

Top and bottom face: Pressure = Weight / Area = 2.943 N / \(18 cm^2\) = \(0.1635 N/cm^2\)

Side faces: Pressure = Weight / Area = 2.943 N / \(6 cm^2\) = 0.4905 \(N/cm^2\)

Front and back faces: Pressure = Weight / Area = 2.943 N / 3 cm^2 = 0.981 N/cm^2

Therefore, the pressure acting on the top and bottom faces is\(0.1635 N/cm^2\), the pressure acting on the side faces is\(0.4905 N/cm^2,\) and the pressure acting on the front and back faces is \(0.981 N/cm^2.\)

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The average angular acceleration of an object from t = 0.00s to t = 1.00s, with initial angular velocity 0 rad/s and final angular velocity 2 rad/s, is 2 rad/s².

To find the average angular acceleration (a_avg), we can use the formula:

\(a_{avg} = (\omega_f - \omega_i)\) / Δt

where \(\omega_f\) is the final angular velocity, \(\omega_i\) is the initial angular velocity, and Δt is the change in time.

Given:

\(\omega_i\) = 0 rad/s (initial angular velocity)

\(\omega_f\) = 2 rad/s (final angular velocity)

Δt = 1.00 s (time interval)

Using the formula, we can calculate \(a_{avg\):

\(a_{avg\) = (\(\omega_f - \omega_i\)) / Δt

= (2 rad/s - 0 rad/s) / 1.00 s

= 2 rad/s / 1.00 s

= 2 rad/s²

Therefore, the average angular acceleration of the object from t = 0.00s to t = 1.00s is 2 rad/s².

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The appropriate question is:

What is the average angular acceleration of an object from t=0.00s to t=1.00s also \(\omega_i\) = 0 rad/s (initial angular velocity), \(\omega_f\) = 2 rad/s (final angular velocity).

Work Done (W) by the field is-6x 107 J,

A pair of opposite, non-coplanar, equally powerful electric charges that are in opposition to one another. An atom is said to have a "induced electric dipole" if the center of the negative cloud of electrons has moved a little bit away from the nucleus due to an external electric field. When the external field is taken away, dipolarity is lost.

Electric field (E) = 300 N/C

Dipole moment (p) = 2 x 10° Cm

Solution:

From the formula we know.

U = -pE cosФ

Here,

p Denotes Dipole moment.

E Denotes Electric field.

Ф Denotes angle b/w them

Now, as given, firstly the dipole is perpendicular to the electric field, so

angle (Ф1) will be 90° and now the dipole is rotated such that they are in same

direction so the angle (Ф2) will be 0°

So, let's find Change in Potential energy which will be equal to the work done

by the electric field.

ΔU = Uf - Ui

ΔU = [-pE*cos Ф2] - [-pE *cos Ф1]

ΔU = [-pE*cos Ф2] + pE *cos Ф1

ΔU = pE * [cos Ф2+ cos Ф1]

Substituting the values,

ΔU = pE * [cos 0° + cos 90°]

ΔU = pE * (-1 +0)

ΔU = -pE

ΔU = -2x 10^-9 × 300

ΔU = 6 x 10^(-9+2)

ΔU = 6 x 10^-7

W = ΔU = -6 x 10^-7

W = - 6 x 10 7 J

Work Done (W) by the field is - 6 x 10-7 J.

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By definition, protons are charged particle with positive charge. Protons are held toguether at the atomic nuclues do the strong nuclear force.

Then, you have:

Protons have a positive charge and are held toguether by the strong nuclear force.

The conditions for this two-sample game are independent random samples of her true score at the arcade and amusement park. The 10% condition is met for both groups. The distribution of scores at the arcade and amusement park has no outliers and no strong skewness. However, the normal/large sample condition is not met.

To perform a two-sample comparison, certain conditions need to be met. Let's analyze each condition based on the given information:

Independent Random Samples: The games played at the arcade and amusement park are described as random samples. This means that the scores obtained in each location are independent of each other.

10% Condition: The number of games played at the arcade (15) is less than 10% of all the games she could play at the arcade, and the number of games played at the amusement park (10) is less than 10% of all the games she could play there. Thus, the 10% condition is satisfied for both groups.

Distribution of Scores: There is no mention of outliers or a strong skewness in the distribution of scores at either the arcade or the amusement park. Therefore, we can assume that there are no outliers and no strong skewness in the data for both groups.

Normal/Large Sample Condition: The normal/large sample condition is not explicitly mentioned in the given information. Without additional details, we cannot determine whether this condition is met or not.

Based on the given information, the conditions for independent random samples and the 10% condition are met for both groups. However, we do not have enough information to determine whether the normal/large sample condition is met.

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1) Do > 2f

Do means object distance

2f means 2 x focal length

2 x focal length = radius of curvature

When an object is placed beyond the radius of curvature, a real image is formed between the radius of curvature and focus. The image size is reduced. The sketch is shown below

The normal force on the bead at point circled a is 0.046 N.the normal force acting on an object is equal to the object's weight when it is in equilibrium. In this case, the weight of the bead can be calculated using the formula: weight = mass × gravitational acceleration.

The mass of the bead is given as 4.70 grams, which is equal to 0.0047 kg. The gravitational acceleration is approximately 9.8 m/s². Thus, the weight of the bead is 0.0047 kg × 9.8 m/s² = 0.04606 N. Therefore, the normal force acting on the bead at point circled a is approximately 0.046 N.

Equilibrium occurs when an object is at rest or moving with a constant velocity. In this state, the forces acting on the object are balanced, resulting in a net force of zero. The normal force is one of the forces that can contribute to achieving equilibrium. It is the force exerted by a surface to support the weight of an object resting on it.

At point circled a, the normal force is equal in magnitude but opposite in direction to the weight of the bead. This is because the bead is in equilibrium, meaning the downward force of gravity is balanced by an equal and opposite upward force from the surface it rests on. Therefore, the normal force on the bead at point circled a is equal to its weight, which is 0.046 N.

In conclusion, the normal force on the bead at point circled a is 0.046 N. This value is obtained by calculating the weight of the bead based on its mass and the gravitational acceleration.

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Answer:

4 × 10^16 m

Explanation:

\(c=\frac{d}{t}\)

d = c × t

\(d = 3 * 10^{8} *4.3 * 365.25 * 24 * 60 60 = 4 * 10^{16} meters\)

Answer:

proxima centauri Is 40208000000000km or ( about 268.770AU.) away from our planet

so the resulting force of all the 3 forces is 11.7 N.

As shown in the figure below ther is 3 forces \(F_1 ,F_2 ,F_3\) are the forces so that the diagram is along the directions given in the question

so \(F_1\) = 3 j^ ( where j^ is unit vector along y axis)

\(F_2\) = 6 cos 45  i^ + 6 sin 45 j^ ( where i^ is unit vector along x axis)

\(F_3\)  = - 5 sin 30 i^ + 5 cos 30 j^

so the resultant force = \(F_1+ F_2 +F_3\)

=> 3 j^ + 4.24 i^ + 4.24 j^ + 4.33 j^ - 2.5 i^

=> 1.74 i^ + 11.57 j^

so resultant force = \(\sqrt{1.74^2 + 11.57^2}\)

=> \(\sqrt{136.89}\)

=> 11.7 N

so the resulting force of all the 3 forces is 11.7 N

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Answer:

False

Explanation:

It is actually I = V/R and V = I × R

Liquid vaporization and thermionic emission share certain similarities in their underlying principles and behavior. Here are three similarities between the two processes:

1. Energy Requirement: Both liquid vaporization and thermionic emission require an input of energy to occur. In the case of liquid vaporization, energy is needed to overcome the intermolecular forces holding the liquid molecules together, allowing them to escape the liquid phase and become vapor. This energy is typically provided through heating. Similarly, in thermionic emission, energy in the form of heat is required to liberate electrons from the surface of a metal. The heat energy increases the kinetic energy of the electrons, enabling them to overcome the work function of the metal and be emitted.

2. Temperature Dependence: Both liquid vaporization and thermionic emission are temperature-dependent processes. In liquid vaporization, as the temperature of a liquid increases, the average kinetic energy of its molecules also increases. This increased kinetic energy helps overcome the intermolecular forces, facilitating the transition from the liquid phase to the vapor phase. Similarly, in thermionic emission, raising the temperature of a metal increases the average thermal energy of its electrons. As a result, a greater number of electrons acquire sufficient energy to escape the metal's surface, increasing the emission rate.

3. Phase Transition: Another similarity between liquid vaporization and thermionic emission is that both involve a transition from one phase to another. In liquid vaporization, the liquid phase transforms into the gaseous phase. This transition occurs when the molecules have enough energy to break free from the liquid's cohesive forces and enter the gas phase. Similarly, in thermionic emission, electrons transition from the bound state within the metal to a free state in the surrounding space. The energy supplied in the form of heat enables the electrons to overcome the attractive forces of the metal and escape its surface, transitioning from the metal to the surrounding vacuum or gas.

While liquid vaporization and thermionic emission occur in different contexts and involve different materials, these three similarities highlight the fundamental principles that govern both processes. They underscore the importance of energy input, temperature effects, and phase transitions in understanding and describing the behavior of both liquid-vapor transitions and thermionic electron emission.

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Answer:

C

Explanation:

There is a decrease in temperature and daylight and plants produce less food.

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