Problem 23.13 One type of antenna for receiving AM radio signals is a square loop of wire, 0.16 m on a side, that has 20 turns. Part A If the magnetic field from the radio waves changes at a rate of 8.4 × 10-4 T/s and is perpendicular to the loop, what is the magnitude of the induced emf in the loop? Express your answer to two significant figures and include appropriate units. Value Units Submit My Answers Give Up back Continue

The Enron scandal drew attention to accounting and corporate fraud as its shareholders lost $74 billion in the four years leading up to its bankruptcy, and its employees lost billions in pension benefits.

Enron's Board of Directors failed to fulfil its fiduciary duties towards the corporation's shareholders. Secondly, the top executives of Enron were greedy and acted in their own self-interest.

Enron's downfall was attributed to its reckless use of derivatives and special purpose entities. By hedging its risks with special purpose entities which it owned, Enron retained the risks associated with the transactions. This arrangement had Enron implementing hedges with itself.

Enron raised fundamental issues about corporate fraud, accounting transparency, and investor protection.

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Local term mostly used for carving is Ukit.

Carving is a creative process that includes cutting or peeling away from a solid mass such as rock, wood, amber, or bone with tools to make a figure.

Wood carving has been practiced in the Philippines since pre-colonial periods. Native Filipinos etched beautiful designs onto boats, plows, darts, spears, and other necessary things for usage by the tribal leadership and to commemorate significant anniversaries.

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Answer:

"a tile company collects and recycles old tiles from large facilities and makes m"

Explanation:

While the first two sound sustainable, and they are, they're not necessarily part of creating new products. The third option where "a tile company collects and recycles old tiles from large facilities and makes m" which is cut off although I'm assuming "makes more?" making it part of the process of creating new products, although it's more sustainable as it uses old products.

It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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Answer:hydroelectric energy

Explanation:

Answer:

C

Explanation:

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The first-order red and blue fringes for the two dominant wavelengths are separated by 0.188 meters.

To determine how far the nth number dark fringe is from the screen's center fringe, Young's experiment is employed. With the following formula, which is written as,

dsinθ= mλ

Here, the screen's distance from the slits is (d) and the wavelength of the light is (λ).

A hydrogen discharge lamp emits light with the two most noticeable wavelengths at 486 nm and 656 nm (red) (blue).

530 line/mm diffraction grating illuminated by hydrogen lamp light. Consequently, the distance's value will be,

\(d = \frac{1}{530} = 1.8 * 10^{-3}\) mm

The angle value for the red light is,

\((1.8 * 10^{-6} )\)sinθ = \(1* 656 *10^{-9}\)

sinθ = 364.44 * \(10^{-3}\)

θ = 21.37

On a screen 1.50 m behind the grating, the light is visible. how far away the red light is,

Y = (1.7)tan 21.37 = 0.665 m

The angle value for the blue light is,

\((1.8 * 10^{-6} )\)sinθ = \(1* 486 *10^{-9}\)

sinθ = 270 * \(10^{-3}\)

θ = 15.66

On a screen 1.50 m behind the grating, the light is visible. how far away the red light is,

Y = (1.7)tan 15.66 = 0.476 m

The first-order red and blue fringes are separated by a distance of,

0.665 m - 0.476 m = 0.188 m

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Answer:

5 m/s

Explanation:

We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time

So, mass flow rate = 9000 kg / 1 minute = 150 kg/s

We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity

So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)

Solving for v (velocity):

v = 150/(1000*0.3) = 5 m/s

Therefore, the speed of water in the pipe is 5 m/s.

Answer:

i think its the top one

Explanation:

pls tell me if im wrong  

Explanation:

The absolute threshold of hearing is the minimum sound level of a pure tone that an average human ear with normal hearing can hear with no other sound present. The absolute threshold relates to the sound that can just be heard by the organism.

my bad I was in a herie last time can you please answer my question , I am going to give you the 5 points back for this question and extra 30 points ,

Explanation:

first its going to say 10 points for my question but after that I well make answer a small question and give you 30points. like whats your favorite color . stay tuned .

Answer:

The maximum height reached by the ride after it was pulled to the ground is 51.6 m.

The given parameters;

The distance half-way between the bands;

\(\frac{d}{2} = \frac{31}{2} = 15.5 \ m\)

The maximum length of the band when stretched is calculated as;

\(c^2 = 15.5^2 + 76^2\\\\c^2 = 6016.25\\\\c = \sqrt{6016.25} \\\\c = 77.57 \ m\)

The extension of the elastic band;

x = 77.57 m - 41 m

x = 36.37 m

The elastic potential energy stored in the band;

\(E = \frac{1}{2} kx^2\\\\E = \frac{1}{2} \times 310 \times (36.57)^2\\\\E = 207,291.56 \ J\)

The elastic potential energy of the elastic band will be converted into kinetic energy of the ride and the speed of the ride is calculated as;

\(E = \frac{1}{2} mv^2\\\\207,291.56 = \frac{1}{2} \times 410 \times v^2\\\\v^2 = \frac{207,291.56}{(0.5\times 410)} \\\\v^2 = 1011.178\\\\v = \sqrt{1011.178} \\\\v = 31.8 \ m/s\)

The maximum height reached by the ride is calculated as;

\(P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{(31.8)^2}{(2\times 9.8)} \\\\h = 51.6 \ m\)

Thus, the maximum height reached by the ride is 51.6 m.

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The ball is briefly at rest and has zero acceleration at the lowest point of its arc. When the ball is at its lowest position, there is 8330 N of tension in the cable.

There won't be any tension and weight will act downward and centrifugal force upward at the highest position. (as stated). As a result, the tension is 6 mg at the lower point and zero at the higher point.

Is the tension in the string higher, lower, or equal to the weight of the ball at its lowest point? The weight of the ball is outweighed by the strain in the string.

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The answers are (a) |q| = 58.2 cm, M = -1.50, virtual, upright, shrunk; (b) |q| =, M = -, actual, substantially magnified; and (c) |q| = 6.5 cm, M = -1.68, virtual, upright, enlarged.

We can use the magnification formula and the thin lens equation to solve:

Where f is the lens's focal length, d_i is the image distance, and d_o is the object distance, the equation is: 1/f = 1/d_i + 1/d_o.

The formula for magnification is M = -d_i/d_o, where M stands for magnification.

For part (a), the object distance is d_o = -38.8 cm and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-38.8

|d_i| = 58.2 cm

The image is virtual and smaller than the object (since the magnification is less than 1)

For part (b), the object distance is d_o = -19.4 cm, and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-19.4

|d_i| = ∞

The image is at infinity, which means it is a real image and highly magnified (since the object distance is close to the focal length).

For part (c), the object distance is d_o = -9.70 cm, and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-9.70

|d_i| = 6.5 cm

The image is virtual and larger than the object (since the magnification is greater than 1).
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Answer:

Explanation:

given

Mass of cart= 150kg

mass of each wheel=45kg

mass of 4 wheels= 180kg

angle of the track=  17 ∘

distance of track= 27m

The height  of the tracl is calculated thus:

sin 17° = h / 27

h = sin 17*27

h=7.89m

"Potential energy at top = kinetic energy of cart and wheels at bottom + rotational energy of wheels at bottom "

1. Potential energy at top= (M+4m)gh

2. kinetic energy of cart and wheels at bottom= 1/2 (M+4m) v²

3. rotational energy of wheels at bottom= 4(1/2 Iω²)

The total is expressed as

(M+4m)gh = 1/2 (M+4m) v² + 4(1/2 Iω²) -------------1

we know that  I = mr² / 2

Put I= mr² / 2

(M+4m)gh = 1/2 (M+4m)v² + 4(1/2 (mr² / 2) ω²)

(M+4m)gh = 1/2 (M+4m)v² +  m r² ω²

we know that  v²= r² ω²

(M+4m)gh = 1/2 (M+4m)v² +  m v²

(M+4m)gh = v² (M/2 + 2m + m)

(M+4m)gh = v² (M/2 + 3m)

v = √[(M+4m)gh / (3m + M/2)]

v = √[(150 + 4*45) * 9.8 m/s² * 7.89 m / (3*45 + 150/2)]

v=√25516.26/142.5

v=√179.06

v = 13.4 m/s

Answer:

The correct difference between chronic and acute stress is:

Acute stress is short-term, while chronic stress endures over time.

Explanation:

Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.

On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.

Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.

Answer:

1.) The reaction is at dynamic equilibrium.

A: Nitrogen and hydrogen combine at the same rate that ammonia breaks down.

2.) Which statement about the reaction is necessarily correct?

A: Both calcium carbonate and sodium carbonate are being produced.

3.) Both calcium carbonate and sodium carbonate are being produced.

A: The reaction is reversible.

4.) What is the fastest motion that can be measured in any frame of reference?

A: 300,000 km/s

5.) Two people are on a train that is moving at 10 m/s north. They are walking 1 m/s south relative to the train. Relative to the ground, their motion is 9 m/s north.

Why are we able to use these motions to describe the motion relative to the ground?

A: The people are moving much slower than the speed of light so the ground acts as a frame of reference.

Explanation:

these were mine i hope this helps ! :0

Answer:

(Question) A child is on a playground they start to slide down a large slide. At what point is the child in dynamic equilibrium with the slide?

(Answer) As the child is in motion as they are sliding down.

(Question) Which statement correctly defines dynamic equilibrium?

(Answer) Forces acting on a object are balanced and the object stays in motion.

(Question) While you push a box you begin to decrease the force you are exerting on the box. When will the box reach static equilibrium?

(Answer) When F^push = F^friction

(Question) What is the fastest motion that can be measured in any frame of reference?

(Answer) 300,000 km/s

(Question) Two people are on a train that is moving at 10 m/s north. They are walking 1 m/s south relative to the train. Relative to the ground, their motion is 9 m/s north;   Why are we able to use these motions to describe the motion relative to the ground?  

(Answer) The people are moving much slower than the speed of light so the ground acts as a frame of reference.

Explanation:

just finished the quick check UwU

Answer:

Distance, S = 440 meters.

Explanation:

Given the following data;

Initial velocity, u = 17m/s

Time, t = 20 seconds

Final velocity, v = 27m/s

To find the distance;

First of all, we would determine the acceleration of the truck.

Acceleration = (v-u)/t

Substituting the given values into the equation, we have;

Acceleration = (27 - 17)/20

Acceleration = 10/20

Acceleration = 0.5m/s²

Now, we would use the second equation of motion to find the distance traveled.

S = ut + ½at²

S = 17*20 + ½*0.5*20²

S = 340 + 0.25*400

S = 340 + 100

S = 440m

The equations of motion can be used to obtain the distance covered as 440 m.

We have to use of the equations that are used for uniformly accelerated motion in solving the problem. The chosen equation must be;

v^2 = u^2 + 2as and v = u + at

v = final velocity

u = initial velocity

a = acceleration

s = distance

To obtain the acceleration;

27 = 17 + 20(a)

27 - 17 = 20a

a = 0.5 ms-2

Now, to obtain the distance;

v^2 = u^2 + 2as

v^2 - u^2/as = s

s = (27)^2 - (17)^2/2(0.5)

s = 440 m

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Answer:

Solar radiation

Explanation:

Visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays.

==>  Energy

==>  Radio noise, heat, visible light, ultraviolet radiation, X-rays, gamma rays

==>  They carry all these kinds of energy wherever they go.  Not only to the Earth.

Answer:

Mag isip ka po wag Kang tanong ng tanong kac kami po Yung nahihirapan mag hanap ng answer

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer: 0.8 g/cm

Explanation:

p= m/V

= 4 kg/ 5 liter

= 0.8

Answer:

.8

Explanation:

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When Charles David Keeling first made measurements from the Mauna Loa Observatory, he was trying to show that the concentration of carbon dioxide (CO2) in the Earth's atmosphere was increasing over time.

Keeling was a geochemist who was interested in studying the exchange of CO2 between the atmosphere and the oceans, and he recognized the importance of measuring the concentration of CO2 in the atmosphere to understand this process. He set up a monitoring station on Mauna Loa, a remote volcanic mountain in Hawaii, and began taking measurements of CO2 concentration in 1958. He found that the concentration of CO2 was increasing steadily over time, and this trend became known as the "Keeling Curve". The Keeling Curve provided some of the earliest evidence of human impact on the global environment and has been a cornerstone of climate change research ever since.

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We can elminate when the position is constant tthatis B and D

Also, we can eliminate E because it is increasing

Therefore we only have A and C that are moving in a negative direction

Answer:

At the equator, linear speed with respect to the polar (day/night spin ) axis is 463.82 meter/s = 1521.8 feet/s, At latitude 15oNand15oS , this speed is 447.77 meter/s = 1469.1 feet/

The arrow should be fired with an initial speed of approximately 31.2 m/s to land 90.4 meters away when aimed at a 45.0-degree angle.

To calculate the initial speed required for an arrow fired at a 45.0-degree angle to land 90.4 meters away, we can utilize the principles of projectile motion.

In projectile motion, the horizontal and vertical components of motion are independent. We can break down the initial velocity into its horizontal and vertical components.

Angle of projection (θ) = 45.0 degrees

Range (horizontal distance) (R) = 90.4 meters

We can start by finding the horizontal component of the initial velocity (Vx) using the formula:

Vx = V * cos(θ)

Where V is the initial velocity.

Since the angle is 45.0 degrees, the cosine of 45.0 degrees is equal to 1 / √2.

Vx = V / √2

Next, we can find the vertical component of the initial velocity (Vy) using the formula:

Vy = V * sin(θ)

Again, since the angle is 45.0 degrees, the sine of 45.0 degrees is equal to 1 / √2.

Vy = V / √2

To determine the initial speed required, we need to consider the time of flight (T) for the arrow to reach the range. The time of flight can be calculated using the formula:

T = (2 * Vy) / g

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Once we have the time of flight, we can calculate the horizontal component of the initial velocity (Vx) using the formula:

Vx = R / T

Now, we can substitute the expressions for Vx and Vy into the original equation:

Vx = V / √2

Vx = R / T

Solving for V:

V = Vx * √2

V = (R / T) * √2

Plugging in the given values of R and T:

V = (90.4 m / T) * √2

Finally, substituting the value of T:

V = (90.4 m / [(2 * Vy) / g]) * √2

Simplifying further:

V = (90.4 m * g * √2) / (2 * Vy)

V = (90.4 m * 9.8 m/s^2 * √2) / (2 * (V / √2))

V = (90.4 m * 9.8 m/s^2) / V

Squaring both sides:

V^2 = (90.4 m * 9.8 m/s^2) / V

Rearranging the equation:

V^3 = 90.4 m * 9.8 m/s^2

Taking the cube root of both sides:

V = ∛(90.4 m * 9.8 m/s^2)

Using a calculator, the final answer is:

V ≈ 31.2 m/s

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Answer:

2.88 m/s

Explanation:

We can use equation of motion to solve this

\(v = u + at \\ v = 2.24 + (0.077)(8.29) \\ v = 2.88m {s}^{ - 1} \)

Vivian's speed after 8.29 s will be 2.88 meters per second.

Speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance traveled by an object to the time taken by it.

Given Vivian is walking to the hair salon at 2.24 m/s when she glances at her watch and realizes that she is going to be late for her appointment. Vivian gradually quickens her pace at a rate of 0.077 m/s².

The speed after 8.29 seconds will be calculated as follows:-

v = u + at

v = 2.74 + ( 0.077 x 8.29 )

v = 2.88 meter per seconds

Therefore, Vivian's speed after 8.29 s will be 2.88 meters per second.

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The impeachment process is described in Article I of the United States Constitution. Impeachment is the process by which senior political officials of the government can be removed from office, for reasons of treason, bribery or serious misconduct in the exercise of their functions.

The first step in this process is carried out by the House of Representatives, which is in charge of determining the origin of the impeachment, assessing the grounds and evidence that allow or not to prosecute the politician in question through a simple majority vote. Then, the Senate is in charge of the trial itself, determining the guilt or not of the official.

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The Founders divided the process into two steps which are impeachment

and conviction to ensure the affected person has a fair judgement and

subsequent trial.

The house of representatives are in charge of the impeach process if an

office holder commits an offence in which impeachment can suffice. The

members of the house of representatives vote and the office holder is

impeached if the majority vote in that direction.

The Senate then takes over and the person faces trial and the judgement is

passed according to the available evidences.

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