Q C Review. While learning to drive, you are in a 1200 -kg car moving at 20.0m/s across a large, vacant, level parking lot. Suddenly you realize you are heading straight toward the brick sidewall of a large supermarket and are in danger of running into it. The pavement can exert a maximum horizontal force of 7000N on the car.(c) If you do not. brake but instead maintain constant speed and turn the steering wheel, what is the minimum distance you must be from the wall to avoid a Collins

Answer:

sowi d ko po knows hehe need ko lang po ng points

Explanation:

hope u understand

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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hi <3

i would say it is 'electricity'

hope this helps :)

To calculate the tensile strength (T), we need to use the formula:

T = Force/Area

In this case, we are given the peak compressive force as 2084 N. However, we need to convert this to tensile force since we want to calculate the tensile strength. Tensile force is equal in magnitude but opposite in direction to compressive force.

Therefore, T = 2084 N

Next, we need to calculate the cross-sectional area (A) of the material. Given that the diameter of the material is 1 inch, we can calculate the radius (R) as half of the diameter:

R = 1 inch / 2 = 0.5 inch

We need to convert the radius to meters since the SI unit of force is Newton (N) and the SI unit of area is square meters (m^2). Since 1 inch is equal to 0.0254 meters, we can convert the radius as follows:

R = 0.5 inch * 0.0254 meters/inch = 0.0127 meters

Now, we can calculate the cross-sectional area (A) of the material using the formula for the area of a circle:

A = π * R^2

A = 3.1416 * (0.0127 meters)^2

A ≈ 0.0005087 square meters

Finally, we can calculate the tensile strength (T) using the formula:

T = 2084 N / 0.0005087 square meters

T ≈ 4,093,981.8 N/m^2

Therefore, the tensile strength (T) is approximately 4,093,981.8 N/m^2.

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The distance between the dog and the ball's location is 42 meters, and the dog was able to cover this distance in 28 seconds at a speed of 1.5 m/s.

The distance to the ball's location can be determined by using the formula:

distance = speed × time.

To understand this calculation, it is important to remember that speed is the rate at which an object moves, typically measured in meters per second (m/s).

In this scenario, the speed of the dog is given as 1.5 m/s and the time taken to retrieve the ball is 28 seconds. Therefore, the distance she covers to the ball's location is:

distance = speed × time

distance = 1.5 m/s × 28 s

distance = 42 meters

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The magnitude of the acceleration a of the chair is approximately 1.62 m/s^2, and the magnitude of the normal force (F_N) acting on the chair is approximately 441 N.

To find the magnitude of the acceleration (a) of the chair and the magnitude of the normal force (F_N) acting on the chair, we can use Newton's second law and analyze the forces acting on the chair.

First, let's consider the forces acting on the chair in the horizontal direction (x-axis). We have the pushing force (F_p) and the kinetic frictional force (F_k) opposing the motion.

The net force in the x-direction can be calculated as:

Net force (F_net) = F_p - F_k

Using Newton's second law, F_net = ma, where m is the mass of the chair.

Therefore, we have:

ma = F_p - F_k

Next, let's calculate the acceleration (a):

a = (F_p - F_k) / m

Plugging in the given values:

F_p = 164 N

F_k = 91.0 N

m = 45.0 kg

a = (164 N - 91.0 N) / 45.0 kg

Now we can solve for a:

a = 73.0 N / 45.0 kg

a ≈ 1.62 m/s^2 (rounded to two decimal places)

Now, let's consider the forces acting on the chair in the vertical direction (y-axis). We have the gravitational force (weight) acting downward and the normal force (F_N) acting upward.

Since the chair is on a horizontal surface and not accelerating vertically, the magnitude of the normal force (F_N) is equal in magnitude and opposite in direction to the weight of the chair.

The weight (W) of the chair can be calculated as:

W = mg

Plugging in the given mass:

m = 45.0 kg

g ≈ 9.8 m/s^2 (acceleration due to gravity)

W = 45.0 kg × 9.8 m/s^2

Now we can determine the magnitude of the normal force (F_N):

F_N = 45.0 kg × 9.8 m/s^2

Finally, let's round the values to three significant figures:

a ≈ 1.62 m/s^2

F_N ≈ 441 N

So, the magnitude of the acceleration of the chair is approximately 1.62 m/s^2, and the magnitude of the normal force (F_N) acting on the chair is approximately 441 N.

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Answer:

Answer: The brightest star that appears nearest to either celestial pole at any particular time (above the North pole)

Answer:

a is the answer to this problem your welcome

The new speed with respect to the ground is 512 m/h.

We can tell that is speed is the rate at which the velocity changes with respect to time. In this case, we can see that the jet airliner moving initially at 103 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 441 mph in a direction 19° north of east.

Hence;

→ The east component =  103 + 441 cos(52) = 375 m/h

→ The north component = 441 sin(52) = 348  m/h

We can now get the new velocity by the use of;

√( 375)^2 + (348)^2 =

= 512 m/h

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The mass of the blood denoted is 501.6 g.

The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.

density = mass/volume

mass = density x volume

The given parameters include;

The mass of the blood is calculated as follows;

mass = 1.06 g/mL x 473.176 mL

mass = 501.6 g

Thus, the mass of the blood is calculated from the formula of density.

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The complete question is below

While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.

Answer:

Gravitational field strength =weight/mass

Explanation:

14.8N/4.0kg

3.7N/kg

Velocity:

Velocity is change in displacement with respect to time:

\(\frac{\Delta x}{\Delta t}\)

Analysing the units, meters (displacement) and seconds (time) are basic units:

\(\frac{m}{s}\)

Therefore the unit of velocity is m/s

Force:

Newton's second law of motion:

\(F = ma\)

Kilogram (mass) is a basic unit, and accelerations unit can be found using the equation:

\(a=\frac{\Delta v}{\Delta t}\)

Analysing the units:

\(\frac{\frac{m}{s}}{s}=\frac{m}{s^2}\)

Therefore, the unit of force is:

\(kg\frac{m}{s^2}\)

Pressure:

Pressure is given by the equation:

\(P=\frac{F}{S}\) where S is area of effect, F is force

Area for a basic rectangle (geometric shape is arbitrary for dimensional analysis) is found by multiplying two lengths:

\([l^2]=m^2\), the unit of area

Dividing the aforementioned unit of force by the unit of area:

\(\frac{kg\frac{m}{s^2}}{m^2}=\frac{kg}{ms^2}\), the unit of pressure

Work:

Work is given by the equation:

\(W=\vec{F}\cdot \vec{x}\), (dot product may be assumed as normal multiplication for the purposes of unit analysis)

Knowing displacement's (x) unit is m:

\([W]=\frac{kgm}{s^2}m=\frac{kgm^2}{s^2}\), the unit of work.

Answer:

if you need someone to talk to about your depression I got you snap:death3959

Explanation:

^^^^^^

It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.

Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.

Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.

Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:

time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds

So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

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Answer: 0N; the rope will remain stationary

Explanation: Connexus

Net force applied on the rope is 0 N and the rope will stay stationary.

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given that:

One student pulls to the left with a force of 35 N.

Another student pulls to the right with a force of 35 N.

Hence, these forces act in opposite direction.

Net force applied on it = 35 N - 35 N = 0 N.

So, the net force of zero newton being applied to the rope, and the rope remains stationary.

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Answer:

BMI = 19.14 [kg/m^2]; Normal or Healthy

Explanation:

Body mass index (BMI) is a person’s weight in kilograms divided by the square of height in meters.

BMI = mass/(height^2)

BMI = 49 / (1.6^2)

BMI = 19.14 [kg/m^2]

BMI                                   Weight Status

Below 18.5                    Underweight

18.5 – 24.9                    Normal or Healthy Weight

25.0 – 29.9                    Overweight

30.0 and Above            Obese

BMI is within the range of Normal or Healthy Weight

Answer: A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. A spaceship far from any star or planet accelerates uniformly from 72 m/s to 160 m/s .

Explanation: i hoped that helped you.

As seen from above, the induced current in the rectangular conducting loop will flow anticlockwise.

The magnetic field passing through the rectangular loop changes as the currents in the two long conducting wires rise equally with time. By inducing an electromotive force (EMF) in the loop, this shifting magnetic field generates a current, in accordance with Faraday's law of induction. Lenz's law, which dictates that the induced current will flow in a direction that opposes the change in magnetic flux that caused it, provides the direction of the induced current. In this instance, the shifting magnetic field causes the rectangular loop to conduct current anticlockwise, opposing the two long wires' increasing magnetic field. Therefore, when viewed from the side, the induced current in the rectangular conducting loop will be anticlockwise.

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Answer:

There is 2 beats per second.

Explanation:

You have to subtract them to find your answer and 178 - 176= 2

Answer:

When displacement vectors are added, the result is a resultant displacement. But any two vectors can be added as long as they are the same vector quantity. If two or more velocity vectors are added, then the result is a resultant velocity. If two or more force vectors are added, then the result is a resultant force.

The car engine provide force , F = 7242 N. if A 795 kg car starts from rest and travels 41 m in 3.0 s.

In Physics, force is defined as: The push or pull on an object with mass causes it to change its velocity. Force is an external agent capable of changing a body's state of rest or motion. It has a magnitude and a direction.

In science, the word 'force' has a precise meaning. At this level, it is completely appropriate to describe a force as a push or a pull. A force is not something that an object contains or 'has in it'.

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Abby volunteers at the planetarium at the museum of natural history. she is putting together a presentation about the solar system in which she will describe the shape of the solar system. she uses the term orbital plane when she discusses the plane in which the planets orbit.

The space that connects the centers of the orbiting objects and the object being orbited is known as an orbital plane and is formed like a flat, disk. Planets in our solar system avoid colliding with one another because their orbital planes are similar.

A rotating body's orbit is located in a geometric plane called the orbital plane. An orbital plane can be identified using just three non-collinear points in space. The locations of the centers of an orbiting celestial body and a large body (the host) at two different times or points in its orbit are typical examples.

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It is not possible to observe all of the stars during a year from a single location on Earth. This is because the Earth rotates on its axis and orbits the Sun, causing the positions of the stars to change relative to an observer on the surface.

From the North Pole, an observer can see approximately half of the sky. This is because the North Pole is located at the axis of rotation of the Earth, and therefore the observer can see half of the sky in all directions.

Yes, you can see stars at the North Pole, but the availability of stars to be seen depends on the time of year. During the summer months, the North Pole experiences 24 hours of daylight and the Sun never sets, so the stars are not visible.

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A dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.

s = vt - 1 / 2 at²

s = Displacement

v = Final velocity

t = Time

a = Acceleration

s = 5 m

t = 1 s

a = 10 m / s²

5 = ( v * 1 ) - ( 1 / 2 * 10 * 1 * 1 )

5 = v - 5

v = 10 m / s

The equation used to solve the given problem is an equation of motion. In a free fall motion, usually air resistance is not considered for easier calculation. If air resistance is considered acceleration cannot be constant throughout the entire motion.

Therefore, a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.

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The correct answer is C: (∂U/∂T)V(∂T/∂V)U(∂V/∂U)T = -1 CV = (∂U/∂T)V = -1(∂T/∂V)U(∂V/∂U)T = -(∂V/∂T)U(∂U/∂V)T. The equation CV = −(∂U/∂V)T(∂V/∂T)U can be derived from the thermodynamic relation:

dU = TdS - PdV

Taking the partial derivative with respect to V at constant T, we get:

(∂U/∂V)T = -P

Using the ideal gas law, PV = nRT, we can write:

P = (nRT/V)

Substituting this into the equation for (∂U/∂V)T, we get:

(∂U/∂V)T = -(nRT/V)

Next, we take the partial derivative of V with respect to T at constant U:

(∂V/∂T)U = (∂(∂U/∂T)V/∂P)V

Using the Maxwell relation (∂T/∂V)U = - (∂P/∂U)V, we get:

(∂V/∂T)U = - (∂(∂U/∂V)T/∂U)V

Substituting the expression for (∂U/∂V)T, we get:

(∂V/∂T)U = (nR/V) * (∂V/∂U)T

Substituting both expressions back into the equation for CV, we get:

CV = -((∂U/∂V)T) * ((∂V/∂T)U)

CV = -(-(nRT/V)) * ((nR/V) * (∂V/∂U)T)

CV = (nR/V^2) * (∂V/∂U)T

Finally, we use the chain rule to express (∂V/∂U)T in terms of partial derivatives of U and T:

(∂V/∂U)T = (∂V/∂T)U * (∂T/∂U)V

Substituting this expression back into the equation for CV, we get:

CV = -(∂U/∂V)T * (∂V/∂T)U

CV = -(∂U/∂V)T * (∂T/∂U)V * (∂V/∂T)U

CV = -(∂U/∂T)V * (∂T/∂V)U * (∂V/∂U)T

Therefore, the correct answer is C: (∂U/∂T)V(∂T/∂V)U(∂V/∂U)T = -1 CV = (∂U/∂T)V = -1(∂T/∂V)U(∂V/∂U)T = -(∂V/∂T)U(∂U/∂V)T.

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Answer: you can use your chair as a reference point. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

Explanation: basically motion.

The electrical component that is used for detecting light levels in digital cameras is the light meter.

A light meter is a device used to measure the amount of light. In photography industry, a light meter is used to determine the proper exposure for a photograph.

A digital camera is a camera that captures photographs in digital memory.

Most digital cameras can be grouped into four main types which includes:

Each type of these digital cameras has advantages and disadvantages, and some the types are more expensive than their counterparts.

There are two different kinds of light meters which are:

-An incident light meter measures all the light falling onto a subject. Incident light meters help a camera focus on a subject regardless of how light or dark the surrounding background is.

- Reflective light meters  on the other hand do the opposite by measuring the light reflected by or bouncing off a subject.

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Expectation value of position in the x-direction, ⟨X^⟩: We apply the position operator, X^, to the wavefunction and integrate:

⟨X^⟩ = ∫ xψ(x, y) dx dy = ∫ xNexp(-2σ^2x^2)exp(-2σ^2y^2) dx dy

To find the expectation values for the position and momentum operators, we need to apply the corresponding operators to the wavefunctions and integrate over the appropriate variables.

a) For the wavefunction ψ(x, y) = Nexp(-2σ^2x^2)exp(-2σ^2y^2):

Expectation value of position in the x-direction, ⟨X^⟩: We apply the position operator, X^, to the wavefunction and integrate:

⟨X^⟩ = ∫ xψ(x, y) dx dy

= ∫ xNexp(-2σ^2x^2)exp(-2σ^2y^2) dx dy

Similarly, we can find the expectation values ⟨Y^⟩, ⟨P^x⟩, and ⟨P^y⟩ by applying the respective operators and integrating over the variables x and y.

b) For the wavefunction φ(x, y) = Nexp(iay)exp(-2σ^2(x-d)^2)exp(-2σ^2y^2):

We follow the same procedure as in part a) to find the expectation values ⟨X^⟩, ⟨Y^⟩, ⟨P^x⟩, and ⟨P^y⟩ for the wavefunction φ(x, y).

The expectation values provide us with information about the average positions and momenta of the particle in the x-y plane for each wavefunction. By calculating these expectation values, we can gain insights into the behavior and properties of the particle in the given states.

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Answer:

The boat's velocity relative to Earth is 3.91 m/s.

Explanation:

Given;

speed of ferry due north, \(V_y\) = 2.5 m/s

speed of the river to the east, \(V_x\) = 3.0 m/s

The boat's velocity relative to Earth is given by;

\(V = \sqrt{V_x^2 + V_y^2} \\\\V = \sqrt{(3)^2+(2.5)^2}\\\\V = 3.91 \ m/s\)

Therefore, the boat's velocity relative to Earth is 3.91 m/s.

The boat’s velocity relative to Earth be 3.91 m/s.

Given that,

Based on the above information, the calculation is as follows:

\(= \sqrt{2.5^2 + 3.0^2} \\\\= \sqrt{6.25 + 9}\\\\= \sqrt{15.25}\)

= 3.91 m/s

Therefore we can conclude that the boat’s velocity relative to Earth be 3.91 m/s.

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