QiC A wooden block of volume 5.24× 10⁻⁴ / m³ floats in water, and a small steel object of mass m is placed on top of the block. When m = 0.310kg, the system is in equilibrium and the top of the wooden block is at the level of the water.(a) What is the density of the wood?

Answer:

See below

Explanation:

F = ma

F / a = m

4000 / 65 = 61.5 kg    (pretty light car.....did you forget a decimal point in 'a')

B. move farther apart

Note that:

• The higher the temperature of a substance, the higher the kinetic energy possessed by its molecules

• The higher the kinetic energy possessed by the molecules, the higher their speed of motion

• The molecules of a gas have higher kinetic energy, hence they collide with each other and with the wall of the container.

When water is heated from 25°C to a gas at 100°C, the molecules posses higher kinetic energy(due to increase in temperature). Therefore, they move farther apart.

Answer:

8

Explanation:

112meters divided by 14

The amount of coal burnt to operate the mini fridge is 0.81 metric tons.

The term energy cost refers to the monetary cost of operating a particular electrical appliance. Let us now answer the questions one after the other.

a) Power consumption per hour = 100 watt or 0.1kW. To operate it for an hour we have  0.1kWhr × $0.10/kWh = 0.01$ Since it operates for twelve hours a day 12(0.01$)= 0.12$ per day. In five years; 0.12$× 5 × 365 = 219 $.

b) Electricity used for the five years = 5 × 365 × 12 × 0.1kWhr = 2190 kWhr

Since 1 metric ton of coal produces 2713 kWh(considering energy losses)

x metric tons of coal produces 2190 kWhr

x = 1 metric ton × 2190 kWhr/2713 kWh

x = 0.81 metric tons

c) In part 1 we did not include the cost of the environmental damage caused by the mining of coal and the social inconveniences caused by the sound of the mini fridge.

d) The college student could reduce the electricity use associated with having a mini fridge in his or her dorm room by turning it off for some hours within the day.

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Answer:

200

Explanation:

P = M x V

P = 8 x 25

P = 200

The equation dT/dt = -k(T - To) represents the rate of change of temperature with respect to time, where T is the temperature of the metal ball at a given time, To is the ambient temperature, k is the cooling constant, and dT/dt denotes the derivative of temperature with respect to time.

We can solve this first-order differential equation to find the time it takes for the metal ball to reach a temperature of 40°C.
Given:
Initial temperature (T0) = 100°C
Final temperature (T) = 40°C
Ambient temperature (To) = 30°C
The equation can be rewritten as:
dT / (T - To) = -k dtIntegrating both sides:
∫ dT / (T - To) = -k ∫ dt
Applying the natural logarithm:
ln|T - To| = -kt + C
To determine the constant C, we use the initial condition:
ln|T0 - To| = -k(0) + C
ln|T0 - To| = C
Substituting the values:
ln|100 - 30| = ln|70| = C
The equation becomes:
ln|T - To| = -kt + ln|70|
Now, we can solve for the time it takes for the metal ball to reach a temperature of 40°C.
ln|T - To| = -kt + ln|70|
ln|40 - 30| = -k(t) + ln|70|
ln|10| = -kt + ln|70|
ln(10) - ln(70) = -kt
Simplifying,
ln(10/70) = -kt
Rearranging the equation to solve for time (t):
t = -ln(10/70) / k
To find the value of the cooling constant k, we can use the given information that the metal ball cools from 100°C to 70°C in 15 minutes.
ln(70 - 30) = -k(15)
ln(40) = -15k
Solving for k:
k = -ln(40) / 15
Now we can substitute the value of k into the equation for time (t):
t = -ln(10/70) / (-ln(40) / 15)
t ≈ 10.97 minutes
Therefore, it will take approximately 10.97 minutes for the metal ball to reach a temperature of 40°C.

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Resonance

The function of the auditory canal is to enhance the intensities of some frequency sounds by means of Resonance.

Resonance happens when an object's oscillations become more intense because they are matched by the vibrations of another object.

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The time measurements for the bulb going out in Sections B and C were recorded. The durations varied depending on the capacitor configuration.

In Section B, the bulb stayed lit for approximately 1 minute and 9 seconds on average. In Section C, the bulb stayed lit for approximately 30 seconds on average. The results indicate that the capacitor configuration does make a difference in the duration that the bulb remains lit.

The data shows that the bulb remained lit for a longer duration in Section B compared to Section C. In Section B, three trials were conducted, and the bulb stayed lit for 1 minute and 3 seconds, 1 minute and 14 seconds, and 1 minute and 11 seconds respectively.

The average duration in Section B was approximately 1 minute and 9 seconds. On the other hand, in Section C, where a different capacitor configuration was used, the bulb stayed lit for 32 seconds, 28 seconds, and 31 seconds respectively in the three trials. The average duration in Section C was approximately 30 seconds.

The discrepancy in the durations suggests that the capacitor configuration does impact the time for which the bulb remains lit. Comparing the two configurations, it can be inferred that the configuration in Section B, with a single capacitor, allows the bulb to stay lit for a longer time than the configuration in Section C, with two capacitors in parallel.

However, it is important to consider the uncertainties in the measurements. Unfortunately, the provided data does not include information about uncertainties, which would be necessary to make a definitive conclusion regarding the significance of the observed differences.

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The semi-major axis of an ellipse is half the length of the longest diameter of the ellipse.

The semi-major axis of an ellipse is a fundamental parameter that determines its shape and size. It is defined as half the length of the longest diameter of the ellipse. The diameter of an ellipse is any line segment that passes through the center and has endpoints on the boundary of the ellipse. The longest diameter, also known as the major axis, is the diameter that has the largest length among all possible diameters of the ellipse.

To find the semi-major axis, we take half the length of the major axis. The major axis passes through the center of the ellipse and is the longest distance between any two points on the ellipse. By halving the length of the major axis, we obtain the semi-major axis, which represents the distance from the center to either focus of the ellipse.

The foci of an ellipse are two fixed points located on the major axis, equidistant from the center. The semi-major axis is indeed the distance between these two foci, as it is half the length of the longest diameter, which connects them. Thus, the semi-major axis provides a concise measure of the size and shape of an ellipse.

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A block of mass m oscillates on a With a period of T = 2.0 s, a block of mass m oscillates on a horizontal spring. The new period will be (D) 2.8 s if a second identical block is adhered on top of the first block.

When a second identical block is glued to the top of the first block, the new period of the oscillation will be affected. The period of an oscillating mass-spring system depends on the mass and the spring constant.

In this case, by adding the second block, the total mass of the system becomes 2m (since both blocks are identical). The spring constant, however, remains the same since the same spring is used.

The period of oscillation (T) is inversely proportional to the square root of the total mass (\(m_{\text{total}}\)) according to the formula \(T = 2\pi\sqrt{\frac{m_{\text{total}}}{k}}\), where k is the spring constant.

Therefore, the new period (\(T_{\text{new}}\)) can be calculated as follows:

\(T_{\text{new}} = 2\pi\sqrt{\frac{{2m}}{{k}}} = \sqrt{2} \cdot (2\pi\sqrt{\frac{{m}}{{k}}})\)

As we can see, the new period is √2 times the original period. Therefore, the new period will be:

\(T_{\text{new}}\) = √2 * T = √2 * 2.0 s ≈ 2.8 s

Therefore, the answer is D. 2.8 s.

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Answer:

so in 1 sec 2 times

so frequency = 2

Explanation:

Option-d).  it remains the same because both are at the same temperature. If the temperature does not increase while the ice melts, the internal energy of the ice and water mixture changes.

A temperature is a unit of hotness or coldness that can be described in terms of a variety of arbitrary scales. It also indicates the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature). Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a considerably higher temperature than a burning match, but it has a far larger total heat energy than a match. As opposed to extensive qualities like mass or volume, which are reliant on the amount of stuff being studied, the temperature is an intensive attribute, just like pressure or density.

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Ball will move 0.33 inches to the right due to Coriolis influence.

The Coriolis force, which operates on moving objects in a frame of reference that rotates relative to an inertial frame, is a hypothetical or inertial force in physics.  In a reference frame with clockwise rotation, the force acts to the left of the object's motion. The force acts to the right in an anticlockwise (or counterclockwise) reference frame. The Coriolis effect causes bending of objects.

The formula for calculating the Coriolis effect's quantity of deflection is as follows: omega=7.2921159 X 10-5/seconds; sin phi=0.529919264 V=15.23 m/s t=3 seconds, translating to 0.33 inches to the right.

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Answer:

The answer is either looking glass or stained glass.

Explanation:

The popular glass used in astrology is stained glass which is popular in symbolization of huge astrology figures. As for looking glass, it's more popular in astrological souvenirs or objects.

Answer:

i think answer is pisces horoscope

The approximate length of the pendulum is 201.9 feet according to stated information.

The formula will be depicted as -

T = 2 π \( \sqrt{ \frac{l}{g} } \), where R represents period, L is length and g is acceleration due to gravity. Keep the values in formula to find the length of the pendulum -

\( \sqrt{ \frac{l}{g} } \) = 5/2π

Dividing the values

\( \sqrt{ \frac{l}{g} } \) = 0.796

Taking square on Right Hand Side of the equation

l/g = 0.796²

l/g = 0.63

Keep the given value of g in the formula

l = 32 × 0.63

Performing multiplication on Right Hand Side of the equation

l = 20.19 feet

Hence, the approximate length of pendulum is 20.19 feet.

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Answer:

Option 2

Explanation:

Since they want to know kinetic energy being increased, it cannot be Options 1 or 3. So now we're left with 2 and 4. 4 seems to be decreasing, so we can eliminate that. So, our answer is Option 2.

A person who figures out or investigates the properties of a physics particle is often referred to as a physicist or a particle physicist.

A physicist specializing in the study of particle physics is responsible for investigating the properties of physics particles. Particle physicists are dedicated to unraveling the fundamental building blocks of the universe and understanding the forces that govern their behavior. Through rigorous experimentation and analysis, they seek to uncover the properties, interactions, and underlying principles of these particles. They utilize sophisticated tools such as particle accelerators, detectors, and mathematical models to probe the subatomic realm. By advancing our understanding of particles, their properties, and the forces that shape our world, particle physicists contribute to the development of theories and models that explain the workings of the universe at its most fundamental level.

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Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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Tripling the tension in a guitar string will change its natural frequency by a factor of A. \(3^1^/^2\)

The natural frequency of a vibrating string, like a guitar string, is determined by its tension, length, and mass per unit length. This relationship is given by the formula:

f = (1/2L) × √(T/μ)

where f is the natural frequency, L is the length of the string, T is the tension, and μ is the mass per unit length.

Now, let's consider the case when the tension is tripled. Let f₁ be the original frequency and f₂ be the new frequency after tripling the tension. We have:

f₁ = (1/2L) × √(T/μ)
f₂ = (1/2L) × √(3T/μ)

To find the factor by which the natural frequency changes, divide f₂ by f₁:

(f₂ / f₁) = [√(3T/μ)] / [√(T/μ)] = √(3T/μ)×√(μ/T) = √3

So, tripling the tension in a guitar string will change its natural frequency by a factor of √3, which corresponds to option A. \(3^1^/^2\) .

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Answer:

función sinusoidal

Explanation:

En un circuito de CA, la corriente y el voltaje tienen un voltaje máximo y mínimo. A intervalos regulares, la corriente y el voltaje invierten la dirección y cambian su magnitud continuamente con el tiempo.

Por lo tanto, para representar la corriente y el voltaje en un circuito de CA, se utiliza una función sinusoidal. Una función seno es una función continua con oscilaciones periódicas.

Isaac Newton described the idea that the  universe as a giant clock with unified rules for gravity and motion.

The clockwork universe is commonly stated  with Sir Isaac Newton but it turns out that both he and his close philosophical supporter Samuel Clarke both strongly criticized the notion of the clockwork universe, because it left no room for Divine Providence.

The faster a clock moves, the slower time passes according to someone in a different frame of reference.

In the history of science, the clockwork universe compares the universe to a mechanical clock. It continues ticking along, as a perfect machine, with its gears governed by the laws of physics, making every aspect of the machine predictable.

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Answer:

because the car needs gas so why wouldnt it stop working

Explanation:

Answer:

The answer is "Y → X → Z".

Explanation:

In this question, the chart is missing and the question is not complete that's why we search this question and only give its correct answer that's is defined above, and please find the complete question in the attached file.

Answer:

First one is voltage

second is resistance

third is electric current

hope this helped!!

Answer: A.

Explanation: Because it is like when you rub your knees on a rug it is tensional so that would make it a not active force.