Question 7 of 27
A DEF is a dilation of A ABC by a scale factor of . Which of the following
proportions verifies that A ABC and ADEF are similar?
B
15
12
A 30
9
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A.
AB
AC
DE
EF
O
B.
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E PREVIOUS
arch

The length of WZ if XW is the angle bisector of YXZ  is 4 units

The statements from the question cam be listed as:

using the above as a guide, we have the following:

WZ = 1/2 * YZ

From the question, we have

YZ = 8

Substitute the known values in the above equation, so, we have the following representation

WZ = 1/2 * 8

Evaluate

WZ = 4

Hence, the length is 4

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The rectangular form of n = (2.80∠–29.9°) is n = 2.45 – 1.38j.

To convert the polar form of n = (2.80∠–29.9°) to rectangular form, we can use the following equations:

a = r*cos(θ)
b = r*sin(θ)

where r is the magnitude of the complex number and θ is its angle in polar form.

Using the given values, we have:

r = 2.80
θ = –29.9°

Converting θ to radians:

θ = –29.9° * π/180 = –0.522 radians

Substituting the values in the equations, we get:

a = 2.80*cos(–0.522) = 2.45
b = 2.80*sin(–0.522) = –1.38

Therefore, the rectangular form of n = (2.80∠–29.9°) is:

n = 2.45 – 1.38j

So,  The rectangular form of n = (2.80∠–29.9°) is n = 2.45 – 1.38j.

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we know that 76% of the specialty soaps are made with fresh herbs, and we also know that there are a total of 350 specialty soap bars, so how many are made with fresh herbs?  well, just 76% of those 350

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{76\% of 350}}{\left( \cfrac{76}{100} \right)350}\implies 266\)

177.8 centimeters.

The shortest distance between the tip of the cone and its rim:

cos θ= base/Hypotenuse

cos 77°=\(\frac{40}{H}\)

\(0.22495=\frac{40}{H}\)

\(H=177.8\)

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The shortest distance between the tip of the cone and its rim exits 51.11cm.

If you draw a line along the middle of the cone, you'd finish up with two right triangles and the line even bisects the angle between the sloping sides. The shortest distance between the tip of the cone and its rim exists in the hypotenuse of a right triangle with one angle calculating 38.5°. So, utilizing trigonometry and allowing x as the measurement of the shortest distance between the tip of the cone and its rim.

Cos 38.5 = 40 / x

Solving the value of x, we get

Multiply both sides by x

\($\cos \left(38.5^{\circ}\right) x=\frac{40}{x} x\)

\($\cos \left(38.5^{\circ}\right) x=40\)

Divide both sides by \($\cos \left(38.5^{\circ}\right)$\)

\($\frac{\cos \left(38.5^{\circ}\right) x}{\cos \left(38.5^{\circ}\right)}=\frac{40}{\cos \left(38.5^{\circ}\right)}\)

simplifying the above equation, we get

\($x=\frac{40}{\cos \left(38.5^{\circ}\right)}\)

x = 51.11cm

The shortest distance between the tip of the cone and its rim exits 51.11cm.

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Answer:

14, 16, 18

sum of the smallest (14) and 3 times the second (16)

14 + 3 x 16 = 62

is 26 more than twice the third (18)

2 x 18 = 36

36 + 26 = 62

hmmm say if you pick any integer whatsoever, and multiply it by some even value, the product will be an even integer, for example, say "3", 2(3) = 6 even, or say "8", 2(8) = 16 even again, so let's say the 1st even integer we'll use is "2a", to get the consecutive ones, we can simply either add or subtract 2 from that.

\(\begin{array}{rllll} 2a&=&\textit{first integer}\\\\ 2a+2&=&\textit{second consecutive integer}\\\\ 2a+4&=&\textit{third consecutive integer} \end{array}\)

\(\stackrel{smallest}{2a}~~ + ~~\stackrel{\textit{three times the 2nd}}{3(2a+2)}~~ = ~~\stackrel{\textit{twice the 3rd}}{2(2a+4)}+\stackrel{\textit{and this more}}{26} \\\\\\ 2a+6a+6~~ = ~~4a+8+26\implies 8a+6~~ = ~~4a+34 \\\\\\ 4a+6=34\implies 4a=28\implies a=\cfrac{28}{4}\implies a=7 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \underset{first}{\stackrel{2(7)}{14}}\hspace{5em}\underset{second}{\stackrel{2(7)~~ + ~~2}{16}}\hspace{5em}\underset{third}{\stackrel{2(7)+4}{18}}~\hfill\)

Answer:

y=-2x+1

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of one another.  slope 1/2 perpendicular will be -2/1=-2

y-5=-2(x-(-2))

y-5=-2(x+2)

y-5=-2x-4

y=-2x-4+5

y=-2x+1

The Distance-time graph of Don's journey should look like a point at (1, 45), followed by a flat line until the 2.5-hour mark at (2.5, 45), and then a straight line with a slope of 15 mph until the end of the journey.

A distance-time graph shows how distance changes over time. In this case, we need to draw a distance-time graph to show Don's journey given that he left home at 2pm, drove 45 miles from home in the first hour, stopped for 90 minutes, and then drove at an average speed of 15 mph.

Let's start by breaking down Don's journey into different sections.

Section 1: Don drives 45 miles from home in the first hour. This means that at the end of the first hour, he is 45 miles away from home. We can plot this on the graph by drawing a point on the graph at the 1-hour mark with a distance of 45 miles.

Section 2: Don stops for 90 minutes. This means that for the next 90 minutes, Don's distance remains constant since he is not moving. We can represent this on the graph by drawing a flat line at the same distance (45 miles) for the next 90 minutes.

Section 3: After the 90-minute stop, Don starts driving again at an average speed of 15 mph. We know that Don travels at a constant speed, so we can represent this part of the journey with a straight line with a slope of 15 mph. This line should start at the end of the flat line representing the stop at 45 miles and continue until the end of the journey

.To summarize, the distance-time graph of Don's journey should look like a point at (1, 45), followed by a flat line until the 2.5-hour mark at (2.5, 45), and then a straight line with a slope of 15 mph until the end of the journey.

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We use the quadratic formula to find the roots of the quadratic equation.

The quadratic equation is given below:

f(x) = a\(x^{2}\) + bx + c = 0 where a, b, c

The system of equations used to find roots of equation is y = 12\(x^{3}\)-5x and y=2\(x^{2}\)+x+6.The given equation will be,12\(x^{3}\)-5x=2\(x^{2}\) + x + 6.

Now we take the root of equation into two parts:

1. Left-hand side

2. Right-hand side

Equation no.1 : 12\(x^{3}\)-5x=0

Equation no.2: 2\(x^{2}\)+x+6=0

Now we contains system of equation 0 with y.

So, the equation will be:

12\(x^{3}\)-5x=y

2\(x^{2}\)+x+6=y

However,system of equations can be used to find the roots of the equation 12\(x^{3}\)-5x=2\(x^{2}\)+x+6 is:
y = 12\(x^{3}\)-5x and y = 2\(x^{2}\)+x+6

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Answer:

C. Supplementary Angles

One way to remember that is that C is the top half of S and Complementary Angles =90 and Supplementary angles =180. 90 is one half of 90

Answer:

\( 2\sqrt{2} \)

Step-by-step explanation:

\( g(x) = \sqrt{x - 4} \)

\( h(x) = 2x - 8 \)

\( h(10) = 2(10) - 8 = 12 \)

\( g(h(10)) = g(12) = \sqrt{12 - 4} \)

\( g(h(10)) = \sqrt{8} = 2\sqrt{2} \)

Answer: \( 2\sqrt{2} \)

Answer:

2 square root 2

Step-by-step explanation:

Answer: 67 peeps

Step-by-step explanation:

The slope of line C = 40t+150 will be 40.

What is equation straight line?

Y = mx + c is the general equation for a straight line, where m denotes the line's slope and c the y-intercept. It is the version of the equation for a straight line that is used most frequently in geometry. There are numerous ways to express the equation of a straight line, including point-slope form, slope-intercept form, general form, standard form, etc. A straight line is a geometric object with two dimensions and infinite lengths at both ends. The formulas for the equation of a straight line that are most frequently employed are y = mx + c and axe + by = c. Other versions include point-slope, slope-intercept, standard, general, and others.

The total cost of the gym membership over tt months is given by the equation C=40t+150

The slope of the given equation will be the append of t which is 40.

Hence, the question indicates that the starting value is 150 already without eve before the time stated.

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Answer:

60

Step-by-step explanation:

hmmmmmmmmmmmmmmmmmmm

Answer:

I know it may be a little late but

here is the answers

t=l/rp

p=l/rt

l=trp

Hope this helps c:

Answer:

y= -4/3x

Step-by-step explanation:

hope this helps :)

Answer:

1/110 =.6/x use cross multiplication and multiply

Step-by-step explanation

Your answer is x=66 miles

Hope this helps!!!

Brainliest???

A schedule example that demonstrates a write-read conflict involving actions of transactions T1 and T2 on objects X and Y.  The write-read conflict occurs at step 2, when T2 reads the value of X after T1 has written to it, but before T1 has committed or aborted.

A write-read conflict occurs when one transaction writes a value to a data item, and another transaction reads the same data item before the first transaction has committed or aborted.
An example schedule with actions of transactions T1 and T2 on objects X and Y that results in a write-read conflict:
1. T1: Write(X)
2. T2: Read(X)
3. T1: Read(Y)
4. T2: Write(Y)
5. T1: Commit
6. T2: Commit
In this schedule, the write-read conflict occurs at step 2, when T2 reads the value of X after T1 has written to it, but before T1 has committed or aborted. This can potentially cause problems if T1 later decides to abort, since T2 has already read the uncommitted value of X.

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The difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

According to the given question.

We have a function

f(x) = -1/(5x -12)

As we know that, the difference quotient is a measure of the average rate of change of the function over and interval.

The difference quotient formula of the function y = f(x) is

[f(x + h) - f(x)]/h

Where,

f(x + h) is obtained by replacing x by x + h in f(x)

f(x) is a actual function.

Therefore, the difference quotient formual for the given function f(x)

= [f(x + h) - f(x)]/h

= \(\frac{\frac{-1}{5(x+h)-12} -\frac{-1}{5x-12} }{h}\)

= \(\frac{\frac{-1}{5x + 5h -12}+\frac{1}{5x-12} }{h}\)

= \(\frac{\frac{-1+5h}{5x + 5h-12} }{h}\)

= \(\frac{-1+5h}{(5x +h-12)(h)}\)

= \(\frac{-1+5h}{5xh + h^{2} -12h}\)

= \(\frac{h(-\frac{1}{h}+5) }{h(5x+h-12)}\)

= \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\)

Hence, the difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

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Answer:

3\(\sqrt{2}\)

Step-by-step explanation:

Using the rule of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\)

Simplify the given radicals

\(\sqrt{50}\)

= \(\sqrt{25(2)}\)

= \(\sqrt{25}\) × \(\sqrt{2}\)

= 5\(\sqrt{2}\)

------------------------

\(\sqrt{72}\)

= \(\sqrt{36(2)}\)

= \(\sqrt{36}\) × \(\sqrt{2}\)

= 6\(\sqrt{2}\)

-----------------------

\(\sqrt{128}\)

= \(\sqrt{64(2)}\)

= \(\sqrt{64}\) × \(\sqrt{2}\)

= 8\(\sqrt{2}\)

Then

\(\sqrt{50}\) + \(\sqrt{72}\) - \(\sqrt{128}\)

= 5\(\sqrt{2}\) + 6\(\sqrt{2}\) - 8\(\sqrt{2}\)

= 11\(\sqrt{2}\) - 8\(\sqrt{2}\)

= 3\(\sqrt{2}\)

Answer:

Step-by-step explanation:

Notice that the pair of angles are inside parallels, and at different sides of the transversal. So, those angles are alternate interior angles by definition, which means they are congruent.

Therefore, the right answer is B.

Answer:

Interior intersections are those intersecitons inside the main figure. For example, the intersection between two chords of a circle, that represents an interior intersection.

Exterior interseciton are those intersections which happens outside the figure, for example, the intersection of two tangent lines of a circle.

Basically, they are similiar, because both type of intersections are formed by the encounter between two lines or segments.

However, they are different, because each type is formed at different parts of the figure, one inside and one outside.

In the right triangle , the value οf x is 51.7°.

The functiοns οf an angle in a triangle are knοwn as trigοnοmetric functiοns, cοmmοnly referred tο as circular functiοns. In οther wοrds, these trig functiοns prοvide the relatiοnship between a triangle's angles and sides. There are five fundamental trigοnοmetric functiοns: sine, cοsine, tangent, cοtangent, secant, and cοsecant.

Here in the given right angle PQ=3.1 , PR=5 .

Nοw using trigοnοmetric functiοn,

=> cos(P) = \(\frac{adjacent}{hypotenuse}\)

=> cos (x) = \(\frac{PQ}{PR}\)

=> cos (x) = \(\frac{3.1}{5}\)

=> x = \(cos^{-1}\frac{3.1}{5}\)

=> x = 51.7°.

Hence the value of x is 51.7°.

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Answer:

r =5

Step-by-step explanation:

This indicates that vector 2AB has a length of 165.

Given the points A(-2, 0), B(6, 16), C(1, 4), D(5, 4), and E, let's determine the length of the vector 2AB. To begin, we must determine the distance that separates points A and B. The distance formula is as follows: Equation for distance: We can calculate d as [(x2 - x1)2 + (y2 - y1)2] using the distance formula: Spot = [(6 - (- 2))2 + (16 - 0)2] = [(6 + 2)2 + (16)2] = [(8)2 + (16)2] = [(64 + 256) = 320 = 8] Now, we can deduct the directions of point A from guide B toward decide the vector Stomach muscle:

To find 2AB, simply multiply each part of AB by 2: AB = (6 - (-2)i + (16 - 0)j = 8i + 16j 2AB = 2(8i + 16j) = 16i + 32j. Last but not least, we must ascertain the magnitude of 2AB. The extent recipe is as per the following: Size formula: Using the magnitude formula, we get: ||v|| = (v12 + v22). ||2AB|| = (162 + 322) = (256 + 1024) = (1280 + 165). This indicates that vector 2AB has a length of 165.

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Answer:

a scalene triangle?

Step-by-step explanation:

Question 1:

Part 1: The value of the account at the end of Week 15 is P * (1 + r) ^ 15.

Part 2: To have exactly $15,000 at the end of Week 15, you must invest approximately $4,008.39 weekly

Question 2:

Part 1: The value of your account upon withdrawal on June 30, 2022, is approximately $1002.44

Part 2: You need to invest approximately $1964.92 on July 1, 2022, to have exactly $2000 in the account on December 15, 2022.

Question 1:

To solve this problem, we'll break it down into two parts.

Part 1: Calculation of the account value at the end of Week 15

Since the interest is compounded at different weeks, we need to calculate the value of the account at the end of each of those weeks.

Let's assume the interest rate is r = 10% (0.10) and the investment at the beginning of each week is P dollars.

At the end of Week 5, the value of the account is:

P * (1 + r) ^ 5

At the end of Week 9, the value of the account is:

(P * (1 + r) ^ 5) * (1 + r) ^ 4 = P * (1 + r) ^ 9

At the end of Week 12, the value of the account is:

(P * (1 + r) ^ 9) * (1 + r) ^ 3 = P * (1 + r) ^ 12

At the end of Week 14, the value of the account is:

(P * (1 + r) ^ 12) * (1 + r) ^ 2 = P * (1 + r) ^ 14

At the end of Week 15, the value of the account is:

(P * (1 + r) ^ 14) * (1 + r) = P * (1 + r) ^ 15

Therefore, the value of the account at the end of Week 15 is P * (1 + r) ^ 15.

Part 2: Calculation of the weekly investment needed to reach $15,000 by Week 15

We need to find the weekly investment, P, that will lead to an account value of $15,000 at the end of Week 15.

Using the formula from Part 1, we set the value of the account at the end of Week 15 equal to $15,000 and solve for P:

P * (1 + r) ^ 15 = $15,000

Now we substitute the given interest rate r = 10% (0.10) into the equation:

P * (1 + 0.10) ^ 15 = $15,000

Simplifying the equation:

1.10^15 * P = $15,000

Dividing both sides by 1.10^15:

P = $15,000 / 1.10^15

Calculating P using a calculator:

P ≈ $4,008.39

Therefore, to have exactly $15,000 at the end of Week 15, you must invest approximately $4,008.39 weekly.

Question 2:

Part 1: Calculation of the account value upon withdrawal on June 30, 2022

For the first six months of the year, the interest is compounded monthly with an APR of r and an effective annual rate of a1 = 6%.

The formula to calculate the future value of an investment with monthly compounding is:

A = P * (1 + r/12)^(n*12)

Where:

A = Account value

P = Principal amount

r = Monthly interest rate

n = Number of years

Given:

P = $1000

a1 = 6%

n = 0.5 (6 months is half a year)

To find the monthly interest rate, we need to solve the equation:

(1 + r/12)^12 = 1 + a1

Let's solve it:

(1 + r/12) = (1 + a1)^(1/12)

r/12 = (1 + a1)^(1/12) - 1

r = 12 * ((1 + a1)^(1/12) - 1)

Substituting the given values:

r = 12 * ((1 + 0.06)^(1/12) - 1)

Now we can calculate the account value upon withdrawal:

A = $1000 * (1 + r/12)^(n12)

A = $1000 * (1 + r/12)^(0.512)

Calculate r using a calculator:

r ≈ 0.004891

A ≈ $1000 * (1 + 0.004891/12)^(0.5*12)

A ≈ $1000 * (1.000407)^6

A ≈ $1000 * 1.002441

A ≈ $1002.44

Therefore, the value of your account upon withdrawal on June 30, 2022, is approximately $1002.44.

Part 2: Calculation of the required investment on July 1, 2022

For the last six months of the year, the interest is compounded monthly with an effective continuous rate of c = 4%.

The formula to calculate the future value of an investment with continuous compounding is:

A = P * e^(c*n)

Where:

A = Account value

P = Principal amount

c = Continuous interest rate

n = Number of years

Given:

A = $2000

c = 4%

n = 0.5 (6 months is half a year)

To find the principal amount, P, we need to solve the equation:

A = P * e^(c*n)

Let's solve it:

P = A / e^(cn)

P = $2000 / e^(0.040.5)

Calculate e^(0.040.5) using a calculator:

e^(0.040.5) ≈ 1.019803

P ≈ $2000 / 1.019803

P ≈ $1964.92

Therefore, you need to invest approximately $1964.92 on July 1, 2022, to have exactly $2000 in the account on December 15, 2022.

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Answer:

2/7

Step-by-step explanation:

set the equation as 3/7-1/7

by adding a negative to a positive you're subtracting

Answer:

2/7

Step-by-step explanation:

adding a negative is the same thing thing as subtracting a positive

so

3/7 + (-1/7) = 3/7 - 1/7 = 2/7

The subtraction problem represented by the fraction model is given above.

Given is a figure as shown in the image.

We can write the fractional problem as -

" A rectangle is divided into eight equal rectangles. Smith colored six of these rectangles. How much percentage fraction of the image is colored."

Therefore, the subtraction problem represented by the fraction model is given above.

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The probability of choosing the first chip a white, then the second chip, not Black is 2/15.

The probability of choosing the first chip a white, then the second chip, not Black is determined as follows:

There are a total of 10 chips, 4 whites, and 6 blacks

The probability of choosing the first chip, a white = 4/10 or 2/5

Then without replacement, there are now 3 white chips and 6 black chips.

The probability of not choosing a black is the probability of picj=king another white chip

Probability of another white chip = 3/9 or 1/3

Therefore;

P(white and not a black) = 4/10 * 1/3

P(white and not a black) = 4/30

P(white and not a black) = 2/15

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Complete question:

Suppose a bag contains 4 white chips and 6 black chips. You randomly choose one of the chips. Without replacing the first chip, you choose a second chip. Find the probability of choosing the first chip a white, then the second chip, not a Black.

4/45

1/10

2/25

1/9