Question attached in image below

Answer:

P = 2 pi R / v    period of space station

F / m = v^2 / R    centripetal force per unit of mass

So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2

Also, F / m = 9.8 m/s^2   earth's gravitational attraction

So 9.8 = 4 pi^2 R / P^2    or    R = 9.8 P^2 / 4 * pi^2) = 195 m

Or D = 2 R = 390 m the diameter required

Despite being the same temperature, the swimming pool is a much larger thermal energy store than the beaker of water.

Thermal energy is the energy contained within a system that controls its temperature. The flow of thermal energy is defined as heat.

Thermodynamics is a branch of physics that deals with how heat is transferred between different systems and how work is done in the process.

Thermal energy sources include natural gas, coal, and oil, as well as solar, heat pump electric, and geothermal heat.

A swimming pool and a beaker of water can both be the same temperature.

Despite being the same temperature, the swimming pool contains significantly more thermal energy than the beaker of water. A heated swimming pool's thermal store contains a lot of energy.

Thus, If a pool and a cup of water had the same temperature, then swimming pool has a much larger thermal energy.

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The direction in which the 25 kg mass will move is to the Left. The correct option is A.

This is because the force pulling to the left is greater than that to the right.

The velocity of the mass after 1 second will be 0.4 m/s

The velocity of the mass after 2 seconds will be 0.8 m/s

The net force o the mass of 25 kg is given below:

Net force = 20 N - 10 N

Net force = 10 N

The velocity of the mass is given by the formula below:

Velocity = net force * time / mass

velocity after 1 second = 10 * 1 / 25

velocity after 1 second = 0.4 m/s

velocity after 2 seconds = 10 * 2 / 25

velocity after 2 seconds = 0.8 m/s

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 (c) n=3,1=2,m=1,s=+1/2 this set of quantum number represents the highest energy of atom

Correct option is C)

The sets of the quantum numbers and the corresponding orbitals are as shown below.

a)n=3,l=0 means 3s− orbital

b)n=3,l=1 means 3p− orbital

c)n=4,l=2 means 4d− orbital

d)n=4,l=0 means 4s− orbital

Increasing order of energy among three orbitals is 3s<3p<4s<4d

∴4d has highest energy.

Hence, the set c of quantum numbers (n=4,l=2,m=1,s=+1/2)  represents the highest energy of an atom.

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Answer:

Explanation:

26 - 18 + 12 = 20 m south

Answer:

Help out with the laundry himself.

Explanation:

In social learning theory, it's a process where people tend to observe the actions of others and then imitate them.

Now, since this father wants to teach his son to start helping his mother do the do laundry, what he can do according to social learning theory is to help with the laundry himself first.

A 25 kg block is pulled with an applied force of 200 N across a horizontal surface. The block experiences a frictional force of 75 N. The Net Force acting on the block is 125 N. The acceleration of the block is 5 m/s².

The term net force is defined as  the sum of all the forces acting on an object. Net force can speed up a mass. Some other force acts on a body either at rest or in motion. The net force is a term utilized in a system when there is a significant number of forces.

A. a Free Body Diagram for the block, including all forces acting on the block is attach in image below.

B.Net force acting on the block

F = 200 - 75

= 125 N

F = 125 N

C. Acceleration of the block

Ma = 125

a = 125/ 25

a = 5 m/s²

Thus, the Net Force acting on the block is 125 N. The acceleration of the block is 5 m/s².

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Answer:

a(acceleration)=-10m.s^-2

Explanation:

Provided in the attachment.

Answer:

0.198m

Explanation:

see picture for full solution

The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.

The groups in periodic table is the same as vertical columns in the periodic table

These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.

Examples of elements found in the same group with similar chemical properties include;

group 7 elements.

The valence electron of elements found in the group 7 of periodic table is negative 1 (-1).

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Answer:

Serotonin

___________

Answer:

a) The car’s speed just after leaving the icy portion of the road is the first part

Explanation:

Answer: C.

Correct me if I'm wrong.

Answer:

It can be either, depending on how much and how you add the electrons

Answer:

Momentum change of the rock = 3835 kgm/s

Chane in earth's velocity = 6.4 x 10⁻²² m/s

Explanation:

m = 50.0 kg, M = 6.0 x 10²⁴ kg

d = 300.0 m

final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s

Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s

Inital momentum of the rock+earth system = 0

final momentum = 0 (momentum conservation)

momentum of rock and momentum of earth are same magnitude and opposite directions.

mv - MV = 0

Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s

We have that the speed of the spaceship must be

\(V=2.47m/s\)

From the Question we are told that

Mass \(8.7*10^{17} kg\)

Positive charge of 4400 C

Spaceship mass m_s=3.3* 10^5 kg

Solar wind has given their spaceship a charge of -1.2 C.

Diameter d=8300-km-diameter

Generally the equation for the force of attraction   is mathematically given as

\(v^2=\frac{Gm}{r}+\frac{kQq}{rm}\\\\v^2=\frac{6.67*10^{-11}*8.7*10^{17}}{9.5*10^5}}+\frac{9*10^9*4400*-1.2}{9.5*10^5*3.3*10^{15}}\)

\(V=2.47m/s\)

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The speed will be "6.98 m/s". A complete solution is provided below.

The given values are:

Mass of asteroid,

Mass of spaceship,

Charge,

As we know,

→ \(F_G +F_E = \frac{mv^2}{R}\)

or,

→ \(\frac{GMm}{R_2} +\frac{kq_1 q_2}{R_2}=\frac{mv^2}{R}\)

By putting the given values, we get

→ \(\frac{6.67\times 10^{-11}\times 8.7\times 10^{17}\times 3.3\times 10^5}{\frac{8.3\times 10^6}{2} } +\frac{9\times 10^9\times 4400\times 1.2}{\frac{8.3\times 10^6}{2} } = 3.3\times 10^5\times v^2\)

→                                                                   \(v=6.98 \ m/s\)                                                                                                                                                      

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The velocity of the ball just before it hits the ground is 24.29m/s.

What is acceleration due to gravity?

The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s2.

Given:

Initial velocity u = 10m/s

height h = 25m

we know that the acceleration due to gravity g is : 9.8m/s

Therefore using the formula,

v² - u² = 2gs   where s is the height in this case and v is the final velocity.

v² - 10² = 2 x 9.8 x 25

=> v² = 490 + 100

=> v = √590

=> v = 24.29m/s

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The magnitude of the masses in planes B and E is 40 kg, and their positions are 120° and 240°, respectively, from the reference point on the shaft to achieve complete rotating balance.

To achieve complete rotating balance, the sum of the moments of the masses in planes A, C, D, B, and E should be equal to zero. Let's determine the magnitude of the masses in planes B and E and their positions.

Consider the moments of the masses in planes A, C, and D. The moment of a mass is given by the product of its magnitude and the sine of the angle between the mass and a reference line. The moments of masses A, C, and D are:

Moment of A = 50 kg * sin(0°) = 0 kg·m,

Moment of C = 40 kg * sin(90°) = 40 kg·m,

Moment of D = 80 kg * sin(135°) = -80 kg·m.

Since the moments of A, C, and D are known, we can use the principle of complete rotating balance to determine the magnitude and position of the masses in planes B and E.

Let's assume the magnitude of the masses in planes B and E as M. The moments of masses B and E can be represented as:

Moment of B = M * sin(120°) = M * √(3)/2,

Moment of E = M * sin(240°) = -M * √(3)/2.

Using the principle of complete rotating balance, the sum of the moments should be zero. Thus, we have:

Moment of A + Moment of C + Moment of D + Moment of B + Moment of E = 0.

0 + 40 kg·m + (-80 kg·m) + M * √(3)/2 + (-M * √(3)/2) = 0.

Simplifying the equation:

40 kg·m - 80 kg·m + M * √(3)/2 - M * √(3)/2 = 0,

-40 kg·m = 0.

From the equation, we can deduce that M must be equal to 40 kg to satisfy the condition of complete rotating balance.

Finally, we determine the positions of masses B and E. Since planes A, C, D, B, and E are equidistant from one another, and the angle between A and C is 90°, we divide the circle into 360°/5 = 72° sections. Thus, the positions of masses B and E are:

Position of B = 0° + 2 * 72° = 144°,

Position of E = 0° + 4 * 72° = 288°.

Therefore, the magnitude of the masses in planes B and E is 40 kg, and their positions to put the shaft in complete rotating balance are 144° and 288°, respectively, from the reference point on the shaft.

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The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0∘ above the horizontal. During the flight, the rocket explodes into two pieces of equal mass (see Fig. 8.32). (a) What horizontal distance from the launch point will the center of mass of the two pieces be after both have landed on the ground? (b) If one piece lands a horizontal distance of 26.0 m from the launch point, where does the other piece land?

Answer:

the rotation period is that one rotation,one day or 24 hrs.

the revolution period is that one revolution,one year

Answer:

The rotation period and revolution period of moon is same.

Explanation:

Because,The moon keeps the same face pointing towards the Earth bcoz it's rate of spin is tidally locked so that it is synchronised with it's rate of revolution.

Therefore it's rotation and revolution period is once about every 27 days.

Hope this helps u..

Answer:A

Explanation:

Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons. The number of protons in a nucleus determines the element's atomic number on the Periodic Table.

Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.

Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:

Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.

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Answer:

Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.

Explanation:

\(\\ \bull\tt\dashrightarrow 5.34\times 10^3\)

\(\\ \bull\tt\dashrightarrow 534\times 10^{-2}\times 10^3\)

\(\\ \bull\tt\dashrightarrow 534\times 10^{-2+3}\)

\(\\ \bull\tt\dashrightarrow 534\times 10^1\)

\(\\ \bull\tt\dashrightarrow 534\times 10\)

\(\\ \bull\tt\dashrightarrow 5340\)

Answer:

it is double the temperature change of iron

The number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

Electrons are particles of matter that carry a negative electrical charge. Electrons are the smallest particles in the atom and are responsible for most of the atom's mass. Electrons orbit around the nucleus of the atom and are held together by the electromagnetic force. Electrons have a property called spin, which can have a value of either +1/2 or -1/2. Electrons are found in all elements and are important in chemical reactions as they are able to move around and form bonds with other atoms. Electrons are also important in electricity and magnetism.

The number of excess electrons on the balloon is equal to the charge of the balloon divided by the charge of an electron. Since the charge of an electron is 1.60 x 10-19 Coulombs, the number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

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As per the given statement the gravitational potential energy added to the steel beam when the beam reaches height of 80 m is 320000 J or 3.2×105 J.

Gravitational potential energy is the energy possessed or acquired by an object due to a change in its position when it is present in a gravitational field.

Potential energy, in physics is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

Given data is:

Mass of steel beam is=400 kg

Height which it reaches= 80 m

So to find the gravitational potential energy added to the steel beam when the beam reaches height of 80 m we do as follows.

Use the given below formula to find gravitational potential energy

U = m × g × h where U is the GPE ,m is the mass, g is the gravitational constant and h is the height attained

So putting the given values in the equation we get:

U = m × g × h

U= 400×9.8×80

U=   320000 J

Hence, the gravitational potential energy added to the steel beam when the beam reaches height of 80 m is 320000J or 3.2×105 J.

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