Rewrite the equation in proper standard form equation 1/4x- 3/4y = -3

Answer:

1/110 =.6/x use cross multiplication and multiply

Step-by-step explanation

Your answer is x=66 miles

Hope this helps!!!

Brainliest???

On solving the provided question we can say that - as on doing the inequality equations we have 91 guests can attend.

By adjusting both sides until just the variables are left, you may eliminate many straightforward inequalities. However, several factors cause inequality: Divide or add negative values on both sides. Switch the left and right. When two values are compared, an inequality shows whether one is bigger than, less than, or equal to the other.

Here we have as,

By adjusting both sides until just the variables are left, you may eliminate many straightforward inequalities.

34 + x ≤ 125

x ≤ 91

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The value of the product of the "complex-numbers" (2i)(5+3i) is "-6+10i", Option(a) is correct.

The Complex numbers are defined as the numbers that can be expressed in the form "a + bi", where a and b are real numbers and "i" is the imaginary unit, which is defined as the square root of -1.

To multiply the two complex numbers (2i)(5+3i), we use the distributive property of multiplication:

⇒ (2i)×(5+3i) = (2i)×(5) + (2i)×(3i),

Simplifying this expression,

We get,

⇒ (2i)×(5+3i) = 10i + 6i²,

Since i² = -1, we substitute this value into the expression:

⇒ (2i)×(5+3i) = 10i + 6(-1) = -6 + 10i,

Therefore, the correct option is (a).

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The given question is incomplete, the complete question is

What is the value of the product (2i)×(5+3i)?

(a) -6 + 10i

(b) 10 + 6i

(c) -10 + 6i

(d) 10 - 6i

A. 8(p, phi, theta) = 8p sin(phi) cos(theta) / (1 + p^2 + 2p cos(phi))^(3/2)

B. ∫0^(2π) ∫0^π ∫0^1 8p sin(phi) cos(theta) / (1 + p^2 + 2p cos(phi))^(3/2) p^2 sin(phi) dp d(phi) d(theta)

C. the mass of the solid 8 enclosed within the sphere is approximately 8.378.

(a) Using the conversion formulas for spherical coordinates, we have:

x = p sin(phi) cos(theta)
y = p sin(phi) sin(theta)
z = p cos(phi)

Substituting these expressions into the given density function, we get:

8(x, y, z) = 8(p sin(phi) cos(theta), p sin(phi) sin(theta), p cos(phi))
            = 8p sin(phi) cos(theta) / (1 + p^2 + 2p cos(phi))^(3/2)

Therefore, the density 8 as a function of spherical coordinates is:

8(p, phi, theta) = 8p sin(phi) cos(theta) / (1 + p^2 + 2p cos(phi))^(3/2)

(b) Since the solid 8 is enclosed within a sphere of radius 1 centred at 2 the origin, we have:

0 ≤ p ≤ 1
0 ≤ theta ≤ 2π
0 ≤ phi ≤ π

Therefore, the bounds of integration in spherical coordinates are:

∫0^(2π) ∫0^π ∫0^1 8p sin(phi) cos(theta) / (1 + p^2 + 2p cos(phi))^(3/2) p^2 sin(phi) dp d(phi) d(theta)

(c) Evaluating the triple integral using a computer algebra system or numerical integration, we get:

M = 8π/3

Therefore, the mass of the solid 8 enclosed within the sphere is approximately 8.378.

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The system of equations are solved and the numbers are 15 and 7

Given data ,

The difference of the two numbers is 8, which can be expressed as:

x - y = 8

It is also given that twice the first number (2x) added to three times the second number (3y) equals 51:

2x + 3y = 51

We now have a system of two equations with two variables. We can solve this system using various methods, such as substitution or elimination.

Let's solve the system using the substitution method:

From equation (1), we can express x in terms of y:

x = y + 8

Substituting this expression for x into equation (2), we get:

2(y + 8) + 3y = 51

2y + 16 + 3y = 51

5y + 16 = 51

5y = 51 - 16

5y = 35

y = 35/5

y = 7

Substituting the value of y back into equation (1):

x - 7 = 8

x = 8 + 7

x = 15

Hence , the two numbers are x = 15 and y = 7

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Answer:

m = 1/2

Step-by-step explanation:

We need to solve the equation:

3/4 = m + 1/4

In order to solve for m, we must isolate the variable - in other words, we need to move all the m terms to one side and all the non-m terms to the other.

So, subtract 1/4 from both sides to isolate m:

3/4 - 1/4 = m

m = 2/4 = 1/2

Thus, m = 1/2.

~ an aesthetics lover

Light bulbs is normally distributed with a variance of 625 and a mean lifetime of 520 hours, we need to calculate the cumulative probability up to 549 hours. The answer will be rounded to four decimal places.

Given a normally distributed lifetime with a mean of 520 hours and a variance of 625, we can determine the standard deviation (σ) by taking the square root of the variance, which gives us σ = √625 = 25.

To find the probability of a bulb lasting for at most 549 hours, we need to calculate the area under the normal distribution curve up to 549 hours. This can be done by evaluating the cumulative distribution function (CDF) of the normal distribution at the value 549, using the mean (520) and standard deviation (25).

The CDF will give us the probability that a bulb lasts up to a certain point. Rounding the result to four decimal places will provide the desired precision.

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The problem involves using normal distribution to find the probability of a given outcome. Using the Z-score, we can determine that the probability of a light bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%

Given the mean (µ) of the lifetime of a bulb is 520 hours. Also, the variance (σ²) is given as 625. Thus, the standard deviation (σ) is the square root of the variance, which is 25.

To find the probability of a bulb lasting for at most 549 hours, we first calculate the Z score. The Z-score formula is given as follows: Z = (X - µ) / σ, where X is the number of hours, which is 549. So substitute the given values into the formula. Z = (549 - 520) / 25, the Z value is 1.16.

We then look up the Z-table to find the probability associated with this Z-score (1.16), which is approximately 0.8770. Therefore, the probability of a bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%.

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Answer:

Option 4 is correct

Step-by-step explanation:

The formula of the Trigonometric Identity Sine is,

\(Sin\ \theta=\frac{perpendicular}{hypotenuse}\\\\sin\ 40 =\frac{x}{b}\)

Answer:

\(0.01\ ounce\)

Step-by-step explanation:

Step 1:  Determine the volume of 10 drops

\(1\ ounce / 1000\ drops\)

\(0.001\ ounce/drop\)

\(0.001\ ounce/drop * 10\ drops\)

\(0.01\ ounce\)

Answer:  \(0.01\ ounce\)

Answer:

The volume of 10 drops of a liquid is 0.1 fluid ounce.

Step-by-step explanation:

I hope this will help you

In the ancient city of Mohenjo-Daro, solid waste was collected in square brick pits located along the banks of the drains.

Mohenjo-Daro was an important urban settlement of the Indus Valley Civilization, which flourished around 2600 to 1900 BCE. The city featured a sophisticated system of drainage, with well-planned brick-lined channels or drains that were constructed to manage wastewater and rainwater runoff. Along these drains, square brick pits were strategically placed to collect solid waste.

These brick pits served as designated areas for waste disposal within the city. The square shape of the pits likely facilitated easy maintenance and cleaning. The waste would accumulate in these pits, and periodic cleaning and removal of the solid waste would help maintain the cleanliness and functionality of the drainage system.

The careful planning and implementation of waste management practices in Mohenjo-Daro reflect the advanced urban planning and sanitation systems of the Indus Valley Civilization. The square brick pits along the drains played a crucial role in effectively managing solid waste within the city.

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Question: In the ancient city of Mohenjo-Daro, a unique waste management system was observed. Solid waste was systematically collected in square brick pits positioned along the ______________ of the drains. Fill in the blank with the appropriate word.

Answer choices:

a) Banks

b) Sidelines

c) Middle

d) Corners

The unit price of the 80-ounce bottle of ketchup is $0.85 per 8 ounces.

To calculate the unit price of a product, we divide the total price by the quantity. In this case, the total price is $8.50 for an 80-ounce bottle of ketchup.

Unit price = Total price / Quantity

Unit price = $8.50 / 80 ounces

Unit price = $0.85 / 8 ounces

Therefore, the unit price of the 80-ounce bottle of ketchup is $0.85 per 8 ounces.

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Answer:

\(f^{-1} (x) = x - 3\)

Step-by-step explanation:

Answer:

Step-by-step explanation:

\(m\angle(A) + m\angle(B)=90\\34+(2x+22)=90\\\textrm{Solve for x.}\\\\34+2x+22=90\\2x+56=90\\2x=90-56\\2x=34\\x=17\\m\angle(B)=2x+22=2(17)+22=34+22=56\degree\)

The number in the numeric form will be 4,508,739.486.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Four times one million, plus five times one hundred thousand, plus eight times one thousand, plus seven times one hundred, plus three times ten, plus nine times one, plus four times one-tenth, plus eight times one-hundredth, plus six times one-thousandth in the numerical form, we have

⇒ 4 x 10⁶ + 5 x 10⁵ + 8 x 10³ + 7 x 10² + 3 x 10 + 9 x 1 + 4 x 10⁻¹ + 8 x 10⁻² + 6 x 10⁻³

Simplify the expression, then we have

⇒ 4,000,000 + 500,000 + 8,000 + 700 + 30 + 9 + 0.4 + 0.08 + 0.006

⇒ 4,508,739.486

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Step-by-step explanation:

The y-axis is intercepted when x = 0

put in '0' for 'x' and compute:

y = 29(5.2)^0  = 29

The numerical expression that describes the perimeter of Stephanie’s triangle is 1 / 2 (25)

The perimeter of Stephanie’s triangle is half the perimeter of Juan’s triangle.

The perimeter of a triangle is the sum of the whole sides of the triangle. A triangle has three sides.

The numerical expression to describe the perimeter of Stephanie’s triangle is as follows:

Perimeter of Juan's triangle = 5 + 8 + 12

Perimeter of Juan's triangle = 25 ft

The perimeter of Stephanie’s triangle is half the perimeter of Juan’s triangle.

Hence, the numeric expression for the perimeter of Stephanie’s triangle is 1 / 2 (25)

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Answer:

the 4th one

Step-by-step explanation:

Answer:

The answer is 40

Step-by-step explanation:

8+3+5+4=20

Once you added all the nunbers mutilpy by 2

20x2=40

that's how you get 40 as your answer

hope that helps ❤

The general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is: y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5

To solve this differential equation, we can use separation of variables.

First, we can rearrange the equation to get dy/dx on one side and the rest on the other side:

dy/dx = 1/3(sin x − xy^2)

dy/(sin x - xy^2) = dx/3

Now we can integrate both sides:

∫dy/(sin x - xy^2) = ∫dx/3

To integrate the left side, we can use substitution. Let u = xy^2, then du/dx = y^2 + 2xy(dy/dx). Substituting these expressions into the left side gives:

∫dy/(sin x - xy^2) = ∫du/(sin x - u)

= -1/2∫d(cos x - u/sin x)

= -1/2 ln|sin x - xy^2| + C1

For the right side, we simply integrate with respect to x:

∫dx/3 = x/3 + C2

Putting these together, we get:

-1/2 ln|sin x - xy^2| = x/3 + C

To solve for y, we can exponentiate both sides:

|sin x - xy^2|^-1/2 = e^(2C/3 - x/3)

|sin x - xy^2| = 1/e^(2C/3 - x/3)

Since the absolute value of sin x - xy^2 can be either positive or negative, we need to consider both cases.

Case 1: sin x - xy^2 > 0

In this case, we have:

sin x - xy^2 = 1/e^(2C/3 - x/3)

Solving for y, we get:

y = ±√[(sin x - 1/e^(2C/3 - x/3))/x]

Note that the initial condition y(0) = 5 only applies to the positive square root. We can use this condition to solve for C:

y(0) = √(sin 0 - 1/e^(2C/3)) = √(0 - 1/e^(2C/3)) = 5

Squaring both sides and solving for C, we get:

C = 3/2 ln(1/25)

Putting this value of C back into the expression for y, we get:

y = √[(sin x - e^(x/2)/25)/x]

Case 2: sin x - xy^2 < 0

In this case, we have:

- sin x + xy^2 = 1/e^(2C/3 - x/3)

Solving for y, we get:

y = ±√[(e^(2C/3 - x/3) - sin x)/x]

Again, using the initial condition y(0) = 5 and solving for C, we get:

C = 3/2 ln(1/25) + 2/3 ln(5)

Putting this value of C back into the expression for y, we get:

y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x]

So the general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is:

y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5

y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x], if sin x - xy^2 < 0 and y(0) = 5

Note that there is no solution for y when sin x - xy^2 = 0.

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Answer:C 2

Step-by-step explanation:

Answer:

\((\frac{2}{3},-\frac{160}{27})\)

Step-by-step explanation:

Given:

\(f(x)=x^{3}-2x^{2}-8x\)

Required:

Determine the point of inflection of the given function.

\(f'(x)=3x^{2}-4x-8\)

\(f^{11}(x)=6x-4=0\)

\(6x=4\)

\(x=\frac{4}{6}=\frac{2}{3}\)

Substitute for x in the function.

\(y=x^{3}-2x^{2}-8x=(\frac{2}{3})^{3}-2(\frac{2}{3})-8(\frac{2}{3})=-\frac{160}{27}\)

So, the point of inflection is:

\((\frac{2}{3},-\frac{160}{27})\)

Answer:

\((\frac{2}{3},-\frac{160}{27})\)

6th terms of given geometric progression whose common ratio is 3/2 and first term is 4  is 243/8 using the farmula ar^(n-1).

What is a geometric sequence?

A mathematical sequence known as a geometric progression (GP) is one in which each following phrase is generated by multiplying each preceding term by a fixed integer, or "common ratio." This progression is sometimes referred to as a pattern-following geometric sequence of numbers. Learn development in mathematics here as well. Here, each phrase is multiplied by the common ratio to generate the subsequent term, which is a non-zero value. A geometric series with a common ratio of 2 is 2, 4, 8, 16, 32, 64, etc.

Geometric Progression takes the following general form: a, ar, ar^2, ar^3, ar^4,..., ar^(n-1).

a = First term where

The common Ratio is r.

nth term = ar^(n-1)

6th terms ar^(6-1) = ar^5.

given is that r =3/2. a = 4.

6th term = 4 * (3/2)^5

= 4 * 3^5/2^5

=4*243/4*8

=243/8.

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Answer:

23.9

Step-by-step explanation:

(75 - 32) x 5/9 = 23.888888888888888888

The first scenario described is an example of a retrospective cohort study.  The second scenario suggests a retrospective cohort study as well. The third scenario represents a cross-sectional study, where researchers conduct a survey among high school students to assess the prevalence of obesity and diabetes.

1. In the first scenario, a retrospective cohort study is conducted by tracking individuals over a 20-year period. The study begins in 1960 and collects data on cigar smoking practices. After 20 years, the participants are followed up to determine if they developed any cancers. This type of study design allows researchers to examine the long-term effects of smoking Cuban cigars.

2. The second scenario involves a retrospective cohort study as well. The objective is to study the long-term neurological effects of a discontinued anesthetic agent. The researchers identify patients who received the drug before it was discontinued and then assess the occurrence of subsequent neurological disorders. This study design allows for the examination of the relationship between exposure to the anesthetic agent and the development of neurological disorders.

3. The third scenario represents a cross-sectional study. Researchers aim to assess the prevalence of obesity and diabetes among high school students during their junior year. They conduct a survey to gather information on the students' current weight, diabetes status, and other relevant factors. A cross-sectional study provides a snapshot of the population at a specific point in time, allowing researchers to examine the prevalence of certain conditions or characteristics.

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This is an incredibly long time, equivalent to about 111,000,000 years!  even with the ability to compute, store, and check for collisions at a rate of 2,000,000 instances per second, finding a collision in SHA3-256 with a probability of at least 1/100,000 is practically impossible.

The probability of finding a collision in a hash function with n-bit output, such as SHA3-256, is roughly proportional to the square root of the number of possible hash values is \(2^{(n/2)\).

SHA3-256, n is 256, so the number of possible hash values is

\(2^{(256/2)} = 2^{128.\)

Let t be the number of seconds we need to run the computation. In one second, we can compute 2,000,000 instances of SHA3-256.

In t seconds, we can compute 2,000,000t instances of SHA3-256.

The number of pairs of hash values that we can generate from 2,000,000t instances is

(2,000,000t choose 2) = (2,000,000t) × (2,000,000t - 1)/2.

To have a probability of at least 1/100,000 of finding a collision, we need the number of pairs of hash values to be at least 100,000 times the number of possible hash values, which is:

(2,000,000t) × (2,000,000t - 1)/2 >= 100,000 × 2¹²⁸

Simplifying and solving for t, we get:

\(t > = \sqrt{((100,000 \times 2^{128})/(2,000,000)^2 - 1/2,000,000)} \approx 3.52 \times 10^{15} seconds\)

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The probability at least 1/100,000 of finding a collision is 2.12 x \(10^{29\) seconds is approximately \(6.73 x 10^{21\) years

In cryptography, a collision occurs when two different inputs produce the same hash output.

The probability of finding a collision increases as the number of inputs increases, and this is what we want to calculate.
Assuming we can compute, store, and check for collisions 2,000,000 instances of SHA-3 (SHA3-256) in one second, we can compute the number of possible inputs that can be hashed in a given time frame.

If we assume a year contains 31,536,000 seconds, then in one year we can compute:
2,000,000 * 31,536,000 = 63,072,000,000,000
That is 63.07 trillion inputs hashed in one year.
Next, we need to calculate the probability of finding a collision among all these inputs.

To do this, we can use the birthday paradox formula, which states that the probability of finding a collision in a set of n items is approximately \(n^2\)/\(2^{(k+1)\).

Where k is the number of bits in the hash output.

For SHA3-256, k = 256.
So, the probability of finding a collision in our set of hashed inputs is:
63,072,000,00 / 2(256+1) = 0.01266
This is an extremely small probability, which means it would take a very long time to find a collision with a probability of at least 1/100,000.

In fact, we would need to compute and store billions of times more hashes than what we can currently achieve in a year.
Therefore, to answer your question, we can say that even with the ability to compute, store, and check for collisions 2,000,000 instances of SHA-3 (SHA3-256) in one second, it would take an impractical amount of time to find a collision with a probability of at least 1/100,000.

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Carl can select red marbles most likely.

Probability is a measure of the likelihood of an event occurring. The probability formula is defined as the possibility of an event happening is equal to the ratio of the number of favorable outcomes and the total number of outcomes. Probability of event to happen P(E) = Number of favorable outcomes/Total Number of outcomes.

Given Carl is going to select 1 marble,

total marbles in bag = 12

number of red marbles = 6

probability of red marbles = 6/12

number of blue marbles = 3

probability of blue marbles = 3/12

number of green marbles = 1

probability of green marbles = 1/12

number of yellow marbles = 2

probability of yellow marbles = 2/12

since the chances of red marble is more as compared than others.

Hence there of chances of selecting red marble.

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the image of bag is attached.

Answer:

The statement is true.

Step-by-step explanation:

Let us plug\(24=-4(8)-8\) in 8 for \(x\) and 24 for \(y\) in our equation: \(24 =-4 (8) - 8\).

Now we will solve in the order described by PEMDAS.

-4(8)=32

32-8=24

24=24

Thus, our statement is true.

Answer:

vertex  = ( 4  ,  25 )

Step-by-step explanation:

given a parabola in  standard form  y =  a x 2 + b x + c x ; a ≠ 0

then the x-coordinate of the vertex is

X vertex=-b/2a

y=-x2+8x+9 with a=-1 b=8 c=9

X vertex= -8/-2=4

substitute the value on the equation

Y vertex = -(4)squared+8(4)+9=25

The correct domain restriction that ensures f(x) has an inverse relation that is also a function is 0 ≤ x ≤ 2π.

A function that "undoes" the effect of another function, such as f(x), is said to have an inverse function. More specifically, the inverse function f inverse (x) translates elements of B back to elements of A if f(x) maps elements of A to elements of B.

In other words, (a,b) is a point on the graph of f(x), and (b,a) is a point on the graph of f inverse (x) if (a,b) is a point on the graph of f(x). In other words, the domain of f inverse(x) is the range of f(x), and vice versa. The domain and range of f(x) and f inverse(x) are interchanged.

Given the function of the graph is f(x) = cos x.

Now, cos x oscillates between -1 and 1, with a cycle of 2π.

To obtain the inverse relation we need to find an one to one specific interval.

The complete cycle is obtained for [0, 2π], thus giving the required specific interval.

Hence, the correct domain restriction that ensures f(x) has an inverse relation that is also a function is 0 ≤ x ≤ 2π.

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