The maximum length of foil will be 6639.8635 cm or 66.3986 m
To find the maximum length of the foil, the given datas are:
Width of roll of foil = 304 mm
Height or thickness = 0.020 mm
Density of foil = 2.7 g/cm³
Mass of foil = 1.09 Kg
What is Density?Density is the substance's mass per unit volume. It can be also described by measuring how the particles in the substances tightly packed together.
d = m/ v
v = length (l) × width (w) × height (h)
First of we will convert the Kg into gram and mm into cm.
For 1 Kg = 1000 g
1.09 × 1000 = 1090 g
For 1 cm = 10 mm
304 / 10 = 30.4 cm
0.020 / 10 = 0.0020 cm
Now we will put the values in formula:
d = m/ l× h× w
l = m / d × h× w
l = 1090 g / 2.7 g/cm³× 30.4 cm × 0.0020 cm
l = 1090 g/ 0.16416 g/cm
l = 6639.8635 cm or 66.3986 m
The maximum length of foil will be 6639.8635 cm or 66.3986 m
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A galaxy cluster contains between _____ galaxies. 5,000 to 10,000 50 to 1,000 1,000 to 5,000 5 to 50 10,000 to 50,000
A galaxy cluster contains between 50 to 1,000 galaxies.
How far apart are galaxy clusters?A supercluster's galaxy clusters are frequently millions of light years apart from one another, making it difficult to estimate their distance with accuracy. The distance between us and the galaxy clusters in the Hydra Supercluster, which is around 100 million light years long, ranges from 105 to 160 million light years.
In accordance with this theory, groupings of dozens of galaxies are gravitationally drawn together to create galaxy clusters, which then combine to form clusters of hundreds or even thousands of galaxies.
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Hi :)
Does anyone know the phases of an lunar eclipse
Pls answer quickly
A worker moves a table, sliding it across the level floor a distance of 3.0 m using a force of 45 N. Calculate the work done by the worker.
Answer:
135 J
Explanation:
Let's take a look at the formula for Work, W=Fd, F being force (N) and d being distance (m). We are given the force and distance so plugging it into the formula, W=45N(3.0m), we get 135 J of work.
Hope this helps!
Can someone do this for the football
Estimated volume
(cm3)
Estimated density
(g/cm3)
edge.
Answer:
0.10 g/cm3
TRUST ME GUYS
Help in timed!!!!
Which is the property of nonmetals to evaporate easily?
brittle
dense
liquid
volatile
Answer:
volatile
Explanation:
volatile means: (of a substance) easily evaporated at normal temperatures.
Answer:
The answer is D. Volatile
Explanation:
Which of the following descriptions apply to the Milky Way galaxy
A photon with energy 2.30 eV is absorbed by a hydrogen atom. A is 3
b) Find the speed of the electron released from the state in part (a) when it is far from the nucleus.
km/s
The speed of the photon has been obtained as 8.9 * 10^5 m/s.
What is the speed of the electron?We know that the energy of the photon would be converted to the kinetic energy of the photon s it is moving. We would now go ahead to obtain the energy in joule.
We now have;
Energy in joules = 2.30 * 1.6 * 10^-19
= 3.68 * 10^-19 J
Then we know that;
KE = 1/2mv^2
KE = kinetic energy
m = mass of the electron
v = speed of the electron
Then
v^2= 2KE/m
v = √2KE/m
v = √2 * 3.68 * 10^-19/9.11 * 10^-31
v = 8.9 * 10^5 m/s
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friction and normal force are examples of
Answer:
Friction is a force that tends to oppose the relative motion between two bodies in contact. Frictional force always acts on a moving body from the direction opposite to the direction of motion. It opposes the motion, and therefore, helps to reduce the speed of the moving object. It is a contact force.
The density of red wood is 15.27 g/cm'. A piece of red wood has the volume of 18.721 cm', what is the
mass?
An engineer wishes to design a roller coaster so that
the cars will not fall when they are at the top of their
circular path.
A 500 kg roller coaster car is designed to travel at 20
m/s at the top of the circle. The engineer wants to
make the circle as large as possible while still being
at least one quarter the maximum radius for safety
reasons. How large can the radius of the circle be?
To prevent cars from falling, the radius at the top of the circle should be
small such cars inverted at the top remain attached during motion.
Correct response;
The radius of the coaster can be C) 20 m
Method by which the above option is selectedMass of roller coaster car, m = 500 kg
Speed at the top of the circle, v = 20 m/s
Required:
The maximum radius of the circular path the roller coaster car.
Solution:
\(\displaystyle Centrifugal \ force, \, F_{c} = \mathbf{\frac{m \cdot v^2}{r}}\)
Where;
r = The radius of the circular path.
Weight of the roller coaster car = m·g = The centripetal force
Where;
g = Acceleration due to gravity = 9.81 m/s²
At equilibrium, we have;
Centrifugal force = Centripetal force
\(\displaystyle \frac{m \cdot v^2}{r} = \mathbf{ m \cdot g}\)
Therefore;
\(\displaystyle r = \mathbf{ \frac{v^2}{g}}\)
Which gives;
\(\displaystyle r = \frac{20^2}{9.81} \approx 40.77\)
The maximum radius for safety of a roller coaster, r ≈ 40.77 meters
\(\displaystyle Range \ of \ radius \ of \ the \ circle = \frac{40.77}{4} \leq Radius \ of \ circle \leq 40.77\)
Which gives;
Range of the radius of the circle = 10.2 ≤ Radius of circle ≤ 40.77
The correct option for safety considerations is therefore;
C) 20 mThe possible question options are;
A) 5 m B) 10 m C) 20 m D) 40 m E) 80 m
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A power line carrying a high current falls
on a car, but the people inside are not
electrocuted. Explain.
A simple pendulum with a length of 2 m oscillates on the Earth's surface. What is the period of oscillations?
Answer:
Period, T = 27.84 seconds
Explanation:
Given the following data;
Length of pendulum = 2m
We know that acceleration due to gravity on earth is equal to 9.8 m/s²
To find the period of oscillation of the simple pendulum;
Mathematically, it is given by the formula;
\( Period, T = 2 \pi \sqrt {lg} \)
Substituting into the equation, we have;
\( Period, T = 2 * 3.142 * \sqrt {2*9.8} \)
\( Period, T = 6.284 * \sqrt {19.6} \)
\( Period, T = 6.284 * 4.43 \)
Period, T = 27.84 seconds
Can a apple fall from a tree and not break open?
Well as you've seen before most likely, an apple can fall right off a tree, and stay perfectly fine. its all dependent on the variables. What angle is the apple falling at? Whats the speed, height, even the size of the apple? We must take into aware anything can happen, but its all behind the variables.
Brainliest if helpful
P.S Fact Check with the second person who just answered
Answer:
yes
Explanation:
i had an apple tree and it happens all the time most often they don't break open.
Three resistors, 3.0 Ω, 12 Ω, and 4.0 Ω, are connected in parallel across a 6.0-V battery as shown above. What is the current through the battery?
Answer:
the current flowing through the battery is 4 A.
Explanation:
Given;
resistance of the three resistors in parallel, R₁, R₂ and R₃ = 3.0 Ω, 12 Ω, and 4.0 Ω
voltage of the battery, V = 6.0 V
The equivalent resistance is calculated as follows;
\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \\\\\frac{1}{R_T} = \frac{1}{3} + \frac{1}{12} + \frac{1}{4} \\\\\frac{1}{R_T} = \frac{4 \ + \ 1 \ + \ 3}{12} \\\\\frac{1}{R_T} = \frac{8}{12} \\\\\frac{1}{R_T} = \frac{2}{3} \\\\R_T = \frac{3}{2} \\\\R_T = 1.5 \ ohms\)
The current flowing through the battery is calculated as follows;
\(I = \frac{V}{R_T} \\\\I = \frac{6}{1.5} \\\\I = 4 \ A\)
Therefore, the current flowing through the battery is 4 A.
what is power, and what is its relationship to voltage and amperage?
when climbing a steep hill, would you want a larger or smaller bicycle gear?
Answer:
Usually when climbing, it's best to be in the small front ring and the largest back ring. If your cadence is about 100 rpm, then whatever gear you're in is fine. It depends on the road, but as long as your pedaling is at a level you're comfortable with, you're fine.
Explanation:
Google answer by the way.
can someone put these in the right order please
PLEASE if you see these people (they all seem to have the same profile picture) NOTIFY THE PERSON ASKING THE QUESTION THAT THIS IS MALWARE AND REPORT IT!!
Stay safe, everyone!
(posting this in all subjects)
Answer:
ʕ •ᴥ•ʔ
Explanation:
O
The speed of light inside a medium is (2.0x108m/s). What is the index of refraction (n) of the medium?
see
below
Explanation:
refractive index = speed of light in vacuum / speed of light in medium
light travels at a speed of 3.0 x 10^8 m/s in vacuum
refractive index = 3.0 x 10^8 / 2.0 x 10^8
refractive index = 1.5
hope this helps, please mark it
A charged object has 82 protons, 82 neutrons, and 109 electrons. What is its overall charge?
The overall charge of an object that has 82 protons, 82 neutrons, and 109 electrons is -27. Details about charge can be found below.
How to calculate overall charge?The overall charge of an atom can be calculated by subtracting the number of electrons from the number of protons.
The proton number represents the number of positively charged atom while the electron number represents the number of negatively charged atom.
According to this question, a charged object has 82 protons, 82 neutrons, and 109 electrons. The overall charge of the atom is calculated as follows:
Overall charge = 82 - 109
Charge = -27
Therefore, the overall charge of an object that has 82 protons, 82 neutrons, and 109 electrons is -27.
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on a map, each township consists of 36 sections which have an approximate surface area of:
On a map, each township consists of 36 sections which have an approximate surface area of 1 square mile each.
In the United States Public Land Survey System (PLSS), a township is a unit of land measurement that is 6 miles by 6 miles, or 36 square miles. Each township is further divided into 36 sections, each of which is 1 square mile or 640 acres. This system was developed in the early 19th century to facilitate the survey and sale of public lands in the western United States. Today, the PLSS is still used in many western states for land management and property boundaries, as well as for mapping and geographic information systems (GIS).
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What is measurement ?
Answer:
Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events
Answer:
The comparison of an unknown quantity with a known quantity is called measurement
What is the velocity of an object that is falling to Earth for 8 seconds? 1.225 m/s b. 9.8 m/s2 c. 78.4 m/s d. 0.816 m/s2
Answer:
Explanation:
Just use the acceleration equation here:
\(a=-\frac{v}{t}\) where a = -9.8; velocity is also negative because it's falling down and down is negative. Filling in:
\(-9.8=-\frac{v}{8}\) so
-9.8(8) = -v and
v = 78.4 m/s downward (the word "downward" takes place of the negative sign)
Pls help pls !!
a raw potato was found to have a mass of 330 g. the potato was sliced and the slices or set an a single layer on a piece of screen wire to dry in the sun. the potato was measured after 7, 14, in 21 days and found to be at 212 g, 148 g, and 126 g.
what is the total mass of the potato likely to be on day 23?
then determine when the potatoes mass was 170 g
and finally what was the total mass of the potato slices after 3 days of drying time
The total mass of the potato slices after 3 days of drying time is approximately 304.71 grams.
The total mass of the potato on day 23 can be estimated by observing the trend in mass reduction over time.
From the given data, we can see that the mass of the potato decreased by 118 grams in the first 14 days (from 330 g to 212 g), and then by 64 grams in the next 7 days (from 212 g to 148 g). Therefore, we can assume that the mass reduction rate is constant.
To find the mass on day 23, we can calculate the mass reduction rate per day:
Mass reduction rate = (330 g - 212 g) / 14 days = 118 g / 14 days = 8.43 g/day
So, the mass on day 23 would be:
Mass on day 23 = 148 g - (8.43 g/day * 9 days) = 148 g - 75.87 g = 72.13 g
The estimated total mass of the potato on day 23 is approximately 72.13 grams.
To determine when the mass was 170 g, we need to find the number of days it took to reach that mass.
Mass reduction rate = (330 g - 170 g) / n days
Solving for n:
(330 g - 170 g) / n days = 8.43 g/day
160 g / n days = 8.43 g/day
n = 160 g / 8.43 g/day
n ≈ 19 days
Therefore, the mass of the potato was 170 g on day 19.
Finally, to find the total mass of the potato slices after 3 days of drying time, we can use the mass reduction rate:
Mass on day 3 = 330 g - (8.43 g/day * 3 days) = 330 g - 25.29 g = 304.71 g
The total mass of the potato slices after 3 days of drying time is approximately 304.71 grams.
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The figure shows the arrangement of master cylinder and slave cylinder of a part of braking system. The master cylinder piston, of surface area 8 cm2 exerts a force of 28 N on the brake fluid when the driver presses the brake pedal Calculate the pressure on the brake fluid produced by the master piston This pressure is transmitted to the slave piston that has surface area of 40 cm2. Calculate the force exerted on this piston State two methods of increasing the force produced by the slave cylinder piston.
Answer:
a) 35 kPa
d) 140 N
c) 1) Increasing the brake fluid pressure
2) Increasing the slave piston surface area.
Explanation:
The parameters given are;
a) Force applied to the master cylinder piston = 28 N
Cross sectional area of the master cylinder piston = 8 cm² = 8 × 10⁻⁴ m²
The pressure P on the brake fluid is given by the formula for pressure as follows;
\(P= \dfrac{Applied \ force}{Area \over \ which \ force \ is \ applied} = \dfrac{28 \, N}{8 \times 10^{-4} \, m^2} = 35,000 \, N/m^2 = 35,000 \, Pa\)
The pressure on the brake fluid, P, produced by the master cylinder piston = 35,000 Pa = 35 kPa
b) Given that the area of the slave piston = 40 cm² = 0.004 m², we have from the formula for pressure, P;
\(P= \dfrac{Applied \ force}{Area \over \ which \ force \ is \ applied} = \dfrac{Applied \ force}{4 \times 10^{-3} \, m^2} = 35,000 \, N/m^2\)
Therefore;
Applied force on the slave piston = 4 × 10⁻³ m² × 35,000 N/m² = 140 N
c) The force, F produced by the slave cylinder piston is given by the relation;
F = Pressure × Area
Therefore, the two ways of increasing the force produced by the slave cylinder piston is as follows;
1) Increasing the pressure in the brake fluid by increasing the force exerted by the master cylinder piston
2) Increasing the surface area of the slave piston.
you place your light soure 50 cm away from a converging lens an image is produced on a screen 100 behind the lens what is the focal length of the lens
The focal length of the converging lens is 33.3 cm.
In order to determine the focal length of the converging lens, we can use the lens equation:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the distance between the object (the light source) and the lens, and di is the distance between the image and the lens.
In this problem, we have do = 50 cm and di = 100 cm. Substituting these values into the lens equation, we get:
1/f = 1/50 cm + 1/100 cm
Simplifying this expression, we get:
1/f = 0.03\(cm^_-1\)
Multiplying both sides by f, we get:
f = 33.3 cm
Therefore, the focal length of the converging lens is 33.3 cm.
This result means that the lens is designed to focus parallel light rays onto a point located 33.3 cm away from the lens. The distance between the object and the lens affects the position and size of the image formed by the lens, while the focal length determines the degree of convergence of the light rays passing through the lens.
It is worth noting that the lens equation assumes that the lens is thin, meaning that its thickness is negligible compared to its radius of curvature. In addition, the lens equation assumes that the light rays passing through the lens are close to the optical axis and that the lens is made of a homogeneous material with a constant refractive index.
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The complete answer is:
You place your light source 50.0 cm away from a converging lens; an image is produced on a screen 100.0 cm behind the lens. What is the focal length of the lens? What is the magnification of the image?
Exam
You push on a shovel then the
shovel pushes on dirt. The force
you apply to the shovel is the
input force. The shovel then
pushing on the dirt is known as
what?
A. Output work
B. Input work
C. Input force
D. Output force
Sally runs 10,000 meter race at an average speed of 3.5m/s what does average speed mean
Answer:
The average speed of 3.5 m/s means that it takes Sally approximately 47.619 minutes to run 10,000 meters
Explanation:
Average speed is a scalar quantity that is given by dividing the total distance moved or traveled by an object by the time that it takes the object during the motion
The average peed indicates the rate at which the object makes a given amount of journey distance given that the journey is completed with varying speeds
With the knowledge of the average speed and the distance covered, the time for completion of the journey can be found as follows;
\(Average \ speed , \overline v = \dfrac{\Delta x}{\Delta t}\)
Where
\(\overline v\) = Average speed of the object = 3.5 m/s
Δt = The time it takes the Sally to run 10,000 meters
Δx = The total distance Sally runs = 10,000 meters
Therefore;
\(\Delta t = \dfrac{\Delta x}{ \overline v} = \dfrac{10,000 \ m}{3.5 \ m/s} = \dfrac{20,000}{7} \ s \approx 2,857.143 \ s\)
The time it takes the Sally to run 10,000 meters= Δt = 20,000/7 seconds ≈ 2,857.143 seconds
20,000/7 seconds ≈ 47.619 minutes
Therefore, the average speed of 3.5 m/s means that the time it takes the Sally to run 10,000 meters ≈ 47.619 minutes
what are you guy's zodiac sign ?!
Answer:
Capricorn what is yours
Answer:
leo
Explanation:
Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?
Answer:
El delfín nada a una profundidad de 22 m
Explanation:
El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.
Esto se expresa como:
P=ρ⋅g⋅h
donde:
P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.En este caso:
P= 2.22*10⁵ Paρ= 1,030 \(\frac{kg}{m^{3} }\)g= 9.8 \(\frac{m}{s^{2} }\)h= ?Reemplazando:
2.22*10⁵ Pa= 1,030 \(\frac{kg}{m^{3} }\) * 9.8 \(\frac{m}{s^{2} }\) * h
Resolviendo:
\(h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}\)
h= 21.993 m ≅ 22 m
El delfín nada a una profundidad de 22 m