select an expression for the impulse I that the baseball experiences when it bounces off the concrete

a tendency of a body to do nothing or to remain unchanged.

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

Answer:5.45X10^3m

Explanation:So use the formula,v= fλ

3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer

Answer:

5.45X10^3m

Explanation:

To determine the semimajor axis and period of the planet's elliptic orbit, as well as the speeds at aphelion and perihelion, we can use Kepler's laws of planetary motion.

a) To find the semimajor axis (a) of the elliptic orbit, we use the equation:

a = r / (1 - e²)

where r is the distance of the planet from the star and e is the eccentricity of the orbit. Substituting the given values, we can calculate the semimajor axis.

To determine the period (T) of the orbit, we can use Kepler's third law:

T² = (4π² / G * M) * a³

where G is the gravitational constant and M is the mass of the star. By rearranging the equation and substituting the known values, we can calculate the period.

b) The speed of the planet at aphelion (v_a) and perihelion (v_p) can be determined using the vis-viva equation:

v = sqrt(G * M * ((2 / r) - (1 / a)))

where v is the speed of the planet, G is the gravitational constant, M is the mass of the star, r is the distance of the planet from the star, and a is the semimajor axis of the orbit. By substituting the given values into the equation, we can calculate the speeds at aphelion and perihelion.

Therefore, by applying the appropriate equations and substituting the given values, we can determine the semimajor axis, period, and speeds at aphelion and perihelion for the planet's elliptic orbit.

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A reduction of the masses of the objects.

Answer:

Which action will decrease the gravitational force between two objects?

A.

Explanation:

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the lowest theoretical temperature that can exist in the universe on the Kelvin scale is zero kelvin (0 K)

Absolute zero, technically known as zero Kelvin, corresponds to -273.15 degrees Celsius or -459.67 degrees Fahrenheit and marks the point on the thermometer where the system reaches the lowest possible energy or thermal motion. However, there is a catch.

Absolute zero cannot be reached.

Two of the most commonly used temperature measurement scales in the thermometer industry are the Kelvin and Celsius scales. A value of 1 degree on the Kelvin scale is the same as a value of 1 degree on the Celsius scale. That is, the temperature difference or temperature change is the same on both scales.

You can use this relationship to convert Celsius to Kelvin.

Celsius = (Kelvin - 273.15)

0r

Kelvin = (Celsius + 273.15)

The Kelvin to Celsius formula is used to convert temperature expressed in Kelvin to Celsius.  

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Answer:

Displacement = 7 meters

Explanation:

Given that,

Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.

The attached figure shows the motion of Jaune.

We know that, Displacement = final position - initial position

Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.

Displcement = 15 m - 8 m

Displacement = 7 m

So, the displacement of Jaune is 7 meters.

Answer:

The answer is 1/16

Explanation:

1. Persistence of vision refers to the optical illusion that occurs when visual perception of an object does not cease for some time after the rays of light proceeding from it have ceased to enter the eye. 2. The persistence of vision for normal eye is 1/16 if a second.

The expression for the capacitance per meter of a coaxial cable is C = \frac{2\pi\epsilon_0}{\ln(b/a)}

The capacitance per unit length of a coaxial cable with inner radius a and outer radius b is given by:

C = \frac{2\pi\epsilon_0}{\ln(b/a)}

where \epsilon_0 is the permittivity of free space.

To find the capacitance per meter of the coaxial cable, we divide this expression by the length of the cable, L:

C_{\text{per meter}} = \frac{C}{L} = \frac{2\pi\epsilon_0}{L\ln(b/a)}

Since the cable is assumed to have air as the insulating material between the cylinders, we can assume that \epsilon_r = 1 and \epsilon = \epsilon_0 (the permittivity of free space), which gives us the above expression.

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Answer:

Explanation:

In order for one to carry something, they need to be exerting a force that is equal to the weight of the object. For Antonio therefore to hold the 1-pound bag, he needs to apply a 1-pound force.

Pounds measure the mass of an object. On his left hand Antonio has 1 pound and on the right he has 2. He is therefore carrying more mass on his right hand than on his left.

Explanation:

Optics is a branch of physics that is the study of light and vision. ... The branch of physics dealing with the nature and properties of electromagnetic energy in the light spectrum and the phenomena of vision. In the broadest sense, optics deals with infrared light, visible light, and ultraviolet light.

The truck was 75 meters away from the mirror when the driver glanced in the passenger-side mirror.

To solve this problem, we can use the mirror equation for a convex mirror:

\(1/f = 1/d_o + 1/d_i\) Where:

f is the focal length of the mirror

\(d_o\) is the object distance (distance of the truck from the mirror) \(d_i\) is the image distance (distance of the image from the mirror)

Given that the radius of curvature (R) of the convex mirror is 150 cm, we can calculate the focal length (f) using the formula:

f = R/2

Substituting the given value, we have:

f = 150 cm / 2 = 75 cm = 0.75 m

Let's assume the image distance \((d_i)\) is negative since the image is formed behind the mirror.

Now, we'll use the given information:

The relative speed of the truck and the mirror's vertex \((d_i)\) is 2.0 m/s.

The relative speed of the truck and the highway is 52 m/s.

The relative speed of the image \((d_i)\) and the truck is the difference between their relative speeds:

Relative speed of image = Relative speed of truck - Relative speed of mirror \(d_i/1 = 52 m/s - 2 m/s \\ d_i = 50 m/s

\)

We also know that the object distance is the sum of the distances traveled by the truck and the image from the mirror's vertex.

\(d_o = d_i + d_t\)

Where:

\(d_t\) is the distance traveled by the truck.

Since the truck is moving at a constant speed of 25 m/s, we can use the formula:

\(d_t = v * t\)

Where:v is the velocity (speed) of the truck

t is the time it takes for the truck to reach the mirror's vertex.

The time (t) can be calculated by dividing the image distance \((d_i)\) by the relative speed between the truck and the mirror:

\(t = d_i / (52 m/s - 2 m/s) \\ t = d_i / 50 m/s\)

Substituting the given value of \(d_i\)

t = 50 m/s / 50 m/s = 1 second

Now we can calculate the distance traveled by the truck:

\(d_t = v * t \\ d_t = 25 \: m/s * 1 \: second \\ d_t = 25 meters\)

Finally, we can calculate the object distance :

\(d_o = d_i + d_t \\ d_o = 50 \: meters + 25 \: meters \\ d_o = 75 \: meters\)

Therefore, the truck was 75 meters away from the mirror when the driver glanced in the passenger-side mirror.

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Answer:

3m/s^2

Explanation:

acceleration=velocity/time

acceleration= 30/10=3m/s^2

Answer:

Principle Archimedes is applied in building a ship and submarine using the manipulating that buoyancy, is controlled the ballast tank system.

Explanation:

Submarine is rather had they focused on main parts of the submarine,he is complex and long process implementation,the most submarine design like submarine stability.

Submarine stability is complete and the fundamental Archimedes principle to arrive the weight of submarine is equal to buoyancy force.

Submarine into the parts and components of ballast tank the sequence in diving and surfacing,there two vital parts:-  flood parts and air vents

flood parts:- at the bottom position and allow water to enter or leave that tank.

air vents:- air vents at the top of the pressure hall,and that they submarine dive.

this time submarine is most modern system is depth is 300 to 450 meters,high pressure  air is 15 bar is tank air valve.

submarine is basic of the effective volume of all the submarine surfaced condition,submarine minus to the free water flood is equal to the fully pressure hull,submarine is the surfaced condition.

Answer:

i) 5 \(m\)/\(s^{2}\)  ii) 54 \(N\)  iii) 54 \(N\)

Explanation:

i) \(a = \frac{v^{2}}{r}\) ⇒ \(a\) = 5² ÷ 5 = 5 \(m/s^{2}\)

ii) \(m = \frac{W}{g}\) ⇒ \(m\) = 108 ÷ 10 = 10.8 \(kg\) , \(F = ma\) ⇒ \(F =\) 10.8 × 5 = 54 \(N\)

iii) F1 = F2 = 54 \(N\)

Answer:

Explanation: Please help me

The Saturn V rocket got faster as more fuel burned due to a combination of factors, including the decreasing mass of the rocket and the conservation of momentum.

As the rocket burned its fuel, its mass gradually decreased. Since the force generated by the engines remained constant, the acceleration experienced by the rocket increased due to Newton's second law of motion (F = ma). This means that as the mass of the rocket decreased, the acceleration increased, resulting in the rocket gaining speed.

Additionally, as the rocket climbed higher into the atmosphere, the air resistance it encountered decreased, allowing the rocket to accelerate more quickly. The air resistance force acting against the rocket decreases because the air density becomes thinner as the altitude increases.

Furthermore, the principle of conservation of momentum played a role in the increasing speed of the Saturn V rocket. As the rocket burned fuel, the exhaust gases were expelled at high velocity, causing the rocket to gain momentum in the opposite direction. Since the rocket's mass was decreasing, this additional momentum translated into a higher velocity.

In summary, the Saturn V rocket got faster as more fuel burned due to the decreasing mass of the rocket, reduced air resistance, and the conservation of momentum. The rocket's acceleration increased as the mass decreased, while the air resistance decreased and the momentum gained from expelling exhaust gases contributed to the increasing velocity.

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The density of sugar, which is in 1.58 g/cm³, is equivalent to 0.05708 in/in³.

Density is a measure of the mass of matter contained by a unit volume.

Density is a function of mass and density, hence, it is measured in units of grams (g) and cubic centimeters (cm³).

However, cubic centimeters can be converted to pounds per cubic inch as follows:

1 gram / cubic centimetre = 0.0361 pound / cubic inch

According to this question, the density of sugar is 1.58 g/cm³. This value is equivalent to;

= 1.58 × 0.0361 = 0.05708

Therefore, the density of sugar, which is in 1.58 g/cm³, is equivalent to 0.05708 in/in³.

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Answer:

9.45 kWh

Explanation:

Energy = Power × time

E = 900 W × (1.5 h/day × 7 day)

E = 9450 Wh

E = 9.45 kWh

The number of the different ways can be 4. The correct option is C.

The total resistance of four identical resistors in series is 4R, while the total resistance of four identical resistors in parallel is R. Therefore, there are two ways to connect the four resistors in order to achieve a total resistance of R: connecting them in series or connecting them in parallel.

(i) In the first way, we connect two pairs of resistors in series, and then, these pairs are connected in parallel.

(ii) In a second way, we connect two resistors in series, and then, this pair is connected in parallel with the other pair of resistors that are also connected in series.

(iii) In a third way, we connect three resistors in series and connect this combination in parallel with the remaining resistor.

(iv) In a fourth way, we connect all four resistors in series.

We need to connect four identical resistors of resistance R so that the equivalent resistance of the resulting combination is R. The number of ways we can do it is 4. So, the correct option is (C) 4.

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The kinetic energy of a 75 kg skater is 600 Joule.

energy energy is a shape of strength that an item or a particle has by using the cause of its movement. If work, which transfers electricity, is completed on an item by applying a net force, the object hurries up and thereby gains kinetic strength. the kinetic strength of an object is the electricity that it possesses because of its motion. it's far defined as the work needed to accelerate a frame of a given mass from relaxation to its said velocity. Having received this strength during its acceleration, the body continues this kinetic electricity unless its speed.

Kinetic energy = 1/2 mV²

                        = 1/2 *75 * 4²

                      = 1/2 * 75 * 4 * 4

                     = 600 Joule.

Disclaimer: your question is incomplete, please see below for the complete question.

How much kinetic energy does the 75 kg skater have at 4 m/s?

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The ratio of the energy levels is 4:9. From this, we can deduce that the quantum numbers are in a ratio of 2:3.

\(E = (n^2 * h^2) / (8 * m * L^2)\)

For the energy level of 12 eV:

\(12 eV = (1^2 * h^2) / (8 * m * L^2)\)

For the energy level of 27 eV:

\(27 eV = (2^2 * h^2) / (8 * m * L^2)\)

For the energy level of 48 eV:

\(48 eV = (3^2 * h^2) / (8 * m * L^2)\)

By comparing these equations, we can see that the ratio of the energy levels is the square of the ratio of the quantum numbers:

(27 eV / 12 eV) = \((2^2 / 1^2) = 4\)

(48 eV / 12 eV) = \((3^2 / 1^2) = 9\)

Quantum numbers are mathematical values used to describe the fundamental properties of particles within the framework of quantum mechanics. These numbers provide a way to characterize various aspects of a particle, such as its energy, angular momentum, and intrinsic properties like spin. The four main quantum numbers are the principal quantum number (n), the azimuthal quantum number (l), the magnetic quantum number (m), and the spin quantum number (s).

The principal quantum number determines the energy level and size of an electron's orbital. The azimuthal quantum number describes the shape of the orbital and determines the angular momentum of the electron. The magnetic quantum number specifies the orientation of the orbital within a given energy level. The spin quantum number denotes the intrinsic angular momentum of the electron.

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As a result, the suspended bulk strikes the ground at a speed of 4.43 m/s.

One of three methods exists for objects to accelerate or alter their rate of velocity. They can speed up in response to a shift in pace. In reaction to a shift in direction, they can accelerate. They can also speed up as a consequence of shifts in direction and speed.

The pace of change of movement is known as velocity. The pace at which motion changes is called acceleration. Due to the fact that it includes both amount and direction, velocity is also a vector number. As the rate at which motion changes, kinetic energy additionally serves as a vector variable.

To solve this problem, we can use Newton's laws of motion and the fact that the tension in the rope is the same throughout the system.

(a) The acceleration of the system can be found by applying Newton's second law to both masses:

ΣF = ma

For the hanging mass, the only force acting on it is its weight, which is given by:

Fh = mgh = (1.0 kg)(9.81 m/s²) = 9.81 N

For the block on the table, the tension in the rope is pulling it to the right, and its weight is pulling it down. Therefore, we have:

Ft - mg = ma

where Ft is the tension in the rope, and mg is the weight of the block on the table. Substituting in the given values, we get:

Ft - (4.0 kg)(9.81 m/s²) = (4.0 kg + 1.0 kg) a

Ft - 39.24 N = 5.0 kg a

Since the tension is the same throughout the rope, we can use the tension in the rope to solve for the acceleration of the system:

a = (Ft - mg) / (m1 + m2)

a = (Ft - 39.24 N) / (4.0 kg + 1.0 kg)

(a) a = (Ft - 39.24 N) / 5.0 kg

(b) To find the tension in the rope, we can use the equation we derived above and solve for Ft:

Ft = m1 a + mg

Ft = (4.0 kg)(a) + (4.0 kg)(9.81 m/s²)

(b) Ft = 4.0 kg (a + 9.81 m/s²)

(c) To find the speed with which the hanging mass hits the floor, we can use the kinematic equation:

vf² = vi² + 2ad

where vf is the final velocity (which we want to find), vi is the initial velocity (which is zero), a is the acceleration of the system (which we found in part (a)), and d is the distance the mass falls (which is 1.0 m).

Substituting in the values we know, we get:

vf² = 0 + 2(a)(1.0 m)

vf² = 2a

Taking the square root of both sides, we get:

vf = √(2a)

Substituting in the value of a that we found in part (a), we get:

(c) vf = √(2a) = √(2(9.81 m/s²)) = 4.43 m/s

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The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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Gaps in the asteroid belt, commonly known as Kirkwood gaps, are caused by orbital resonances with Jupiter.

Jupiter's strong gravitational influence affects the orbits of asteroids in the asteroid belt. As asteroids orbit the Sun, they can experience gravitational interactions with Jupiter that cause their orbits to become unstable. These interactions occur when the orbital period of an asteroid becomes a simple fraction (such as 1/2, 2/3, 3/4, etc.) of Jupiter's orbital period.

These orbital resonances with Jupiter result in gravitational perturbations that can lead to the gradual clearing of asteroids from specific regions in the asteroid belt, creating gaps or zones of lower asteroid density. The gravitational influence of Jupiter causes asteroids in these resonant orbits to experience repeated gravitational interactions, which can increase their eccentricity and eventually lead to their ejection from the resonance region.

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Answer:

2N

Explanation:

works one=force/weight

10N/5m

2N

The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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Answer:

  a = -1,33 m / s²

Explanation:

This problem is kinematic in one dimension, let's use the equations

         v = v₀ + a t

         v₀ = v - at

          x = v₀ t + ½ a t²

we substitute the first in the second equation

         x = (v-at) t + ½ a t²

         x -v t = a t² (1 + ½)

         a = (x -vt) / t² (1.5)

we calculate

         a = (100 - 30 10) / 10² (1.5) =-200 / 150

         a = -1,33 m / s²

The wavelength of the laser is 0.4464 mm.

The equation for the diffraction grating is given as:

dsinθ = mλ

where d is the distance between the slits (in meters), θ is the angle between the central maximum and the mth bright fringe (in radians), m is the order of the bright fringe, and λ is the wavelength of the light (in meters).

The equation to calculate the wavelength of a laser is λ = d × sin θ/m, where d is the distance between two adjacent slits on the diffraction grating (in this case, 1000 slits/mm, which is equivalent to 1 mm), θ is the angle of the fringe relative to the central axis (in this case, 26 degrees), and m is the order of the fringe (in this case, m=1). Therefore, plugging in the values:

λ = 1 mm × sin 26°/1 = 0.4464 mm

The wavelength of the laser is 0.4464 mm.

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The wind tunnel speed that must be used to test the car 1 / 5 model of a car that normally runs at 30 mph is 150 mph

Re = u L / ν

Re = Reynold's number

u = Flow speed

L = Characteristic linear dimension

ν = Kinematic viscosity

ν\(_{p}\) = 1.516 * \(10^{-5}\) m² / s

ν\(_{p}\) = ν\(_{m}\) = 1.516 * \(10^{-5}\) m² / s

L\(_{m}\) = L\(_{p}\) / 5

u\(_{p}\) = 30 mph

Re\(_{m}\) = u\(_{m}\) L\(_{p}\) / 5 * 1.516 * \(10^{-5}\)

Re\(_{p}\) = 30 L\(_{p}\) / 1.516 * \(10^{-5}\)

In tunnel,

Re\(_{m}\) = Re\(_{p}\)

u\(_{m}\) L\(_{p}\) / 5 * 1.516 * \(10^{-5}\) = 30 L\(_{p}\) / 5 * 1.516 * \(10^{-5}\)

u\(_{m}\) = 30 * 5

u\(_{m}\) = 150 mph

Therefore, the wind tunnel speed that must be used to test the car is 150 mph

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This would not work well for trying to tell the difference between the heliocentric and mercury-centric models.

Heliocentric is the astronomical model of the Solar System in which the Sun is at the center and all the planets and other objects orbit around it. This model is in contrast to the geocentric model, in which the Earth is at the center of the Solar System. The heliocentric model was first proposed in the 16th century by Nicolaus Copernicus and later refined by Johannes Kepler and Galileo Galilei. This revolutionary idea overturned centuries of scientific thought and had profound implications for our understanding of the universe.

This is because the heliocentric model states that the sun is at the centre of the solar system, while the mercury-centric model states that the planet Mercury is at the centre. As such, there is no real way to tell the difference between the two models without more information about the specific positions of the planets in relation to each other.

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The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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