Simplify: 2(-3x-6)

Possible answers:

-6x-8
-6x-12
-6x+12
-6x-4

Please help

The probability of landing heads exactly 11 times when a coin is tossed 20 times is option a) 0.1602

The repeated tossing of a coin follows a binomial distribution

P(X = x) = ⁿCₓ pˣ (1 - p)⁽ⁿ ⁻ ˣ⁾

where,

n = No. of times the experiment was repeated

x = random variable defining the number of "successes"

p = probability of "success"

Here

"succeess" is the event of landing a head.

n = 20

x = no. of times heads should show, i.e 11

p = probability of landing a head in a single toss

= 1/2

Hence, putting all this in the formula above we get

P(X = 11) = ²⁰C₁₁ 0.5¹¹ (1 - 0.5)⁽²⁰ ⁻ ¹¹⁾

= ²⁰C₁₁ 0.5¹¹ 0.5⁹

= ²⁰C₁₁ 0.5²⁰

= 20!/ 11! (20 - 11)! X 0.5²⁰

= a) 0.1602

Complete Question

An unbiased coin is tossed 20 times.

Find the probability that the coin lands heads exactly 11 times

a. 0.1602

b. 0.5731

c. 0.2941

d. 0.1527

e. 0.6374

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Answer: 1/2

Step-by-step explanation:

solving bracket first we get

2 - 9/6

multiplying and dividing 2 by 6 we get

12/6 - 9/6

=3/6 = 1/2

Answer:

1/2

Step-by-step explanation:

(6-4)-9/6

= (2)-9/6

= 12/6-9/6

= 3/6

= 1/2

Answer:

1. 0^6=0  1^5=1    False

2. 7^3=7*7*7=343 7*3=21  False

3. 2^4=2*2*2*2=16 4^2=4*4=16 True

Answer:

1) False

2) False

3) True

Step-by-step explanation:

1) 0^6 = 0 and 1^5 = 1, so they are not equal.

2) 7^3 = 7*7*7= 343 and 7*3 = 21, so they are not equal.

3) 2^4 = 2*2*2*2 = 16 and 4^2 = 4*4 = 16, so they are equal.

Answer:

Step-by-step explanation:

We worry about 2 things:

-terms power

-coefficient for each term

(3x-4)^5, has 2 terms 3x and -4

-Start with the first term to the highest power 5 and second term to the lowest power 0, then the high power goes down and low power increases until the first term has the lowest power 0 and the second term has the highest power 5.

-The coefficients for each term we take it from the Pascal triangle.

For the the power 5 the coefficients are 1, 5, 10, 10, 5, 1

\((3x-4)^{5} = 1*(3x)^{5} *(-4)^{0} +5*(3x)^{4} *(-4)^{1} +10*(3x)^{3} *(-4)^{2}+10*(3x)^{2} *(-4)^{3}+5*(3x)^{1} *(-4)^{4}+1*(3x)^{0} *(-4)^{5}\)

Simplify:

\((3x-4)^{5} = 3^{5} x^{5} -20*3^{4} x^{4} +160*3^{3} x^{3}-640*3^{2} x^{2}+1280*3x-1024\)

\((3x-4)^{5} = 243 x^{5} -1,620x^{4} +4,320 x^{3}-5,760x^{2}+3,840x-1024\)

There are 4 possible outcomes when flipping a fair coin twice: HH, HT, TH, and TT and the expected value of X is $0.25.

To find the expected value of X, we need to multiply each possible outcome by its probability and then sum up the results.
There are four possible outcomes when flipping a coin twice:
1. HH (both flips come up heads) - you lose $5
2. HT (first flip comes up heads, second flip comes up tails) - you win $1
3. TH (first flip comes up tails, second flip comes up heads) - you win $1
4. TT (both flips come up tails) - you win $1
Since the coin is fair, each of these outcomes is equally likely to occur, with a probability of 1/4.
So, the expected value of X can be calculated as:
E(X) = (-5)*(1/4) + (1)*(3/4)
E(X) = -5/4 + 3/4
E(X) = -1/2
Therefore, the expected value of X is -$0.50 (or negative fifty cents).
To find the expected value of X, we need to calculate the probabilities of the possible outcomes and their corresponding values.
There are 4 possible outcomes when flipping a fair coin twice: HH, HT, TH, and TT.
1. HH: Both flips come up heads, you lose $5. So, X = -5. The probability of this outcome is (1/2) * (1/2) = 1/4.
2. HT, TH, and TT: At least one flip comes up tails, you win $1. So, X = 1. The probability of these outcomes combined is 3/4, as each outcome has a probability of 1/4 (1/2 * 1/2), and there are 3 such outcomes.
Now we calculate the expected value of X:
E(X) = (probability of HH) * (X for HH) + (probability of HT, TH, or TT) * (X for HT, TH, or TT)
E(X) = (1/4) * (-5) + (3/4) * (1)
E(X) = (-5/4) + (3/4)
E(X) = -2/4 + 3/4
E(X) = 1/4
The expected value of X is $0.25.

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Answer:

Step-by-step explanation:

Rotate 180 degrees about the origin

X(x,y) ====> X'(-x,-y)

K(-5 , - 9) = K ' (- -5, - - 9)

K' (5,9)

3 Units Left.

y is unchanged.

x becomes x - 3

K'(5,9) ===>k" (5 - 3,9)

k"(2,9)

The leftward motion does not look done the same way as moving a parabola left. But you are just changing the x value to move a point left. You are not imposing other rules on the figure.

The value of fg (1/3) is 7.

To find the value of fg(1/3), we need to evaluate the composite function fg at x = 1/3.

First, let's find the value of g(1/3):

g(x) = 3x + 1

g(1/3) = 3(1/3) + 1

      = 1 + 1

      = 2

Now, substitute the value of g(1/3) into f(x):

f(x) = (2x + 3)/(x - 1)

f(g(1/3)) = f(2) = (2(2) + 3)/(2 - 1)

          = (4 + 3)/(2 - 1)

          = 7/1

          = 7

Therefore, the value of fg(1/3) is 7.

So we first found the value of g(1/3) by substituting x = 1/3 into the expression for g(x). Then, we substituted the value of g(1/3) into f(x) to find f(g(1/3)). This resulted in the value 7.

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Answer:

6c+10f

Step-by-step explanation:

Cost of 1 cheese pizza=6

Cost of c cheese pizza=6c

Cost of 1 four-topping pizzas=10

Cost of 1 four-topping pizzas=10f

Total cost=6c+10f

Hope this will help:)

Answer:

35

Step-by-step explanation:

210/10=21 pens per friend

21+27=48 pens for benjamin

48-13=35 pens left

benjamin has 35 pens now

After giving 13 of his pens to Peyton Benjamin now have 35 pens.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

Given, Dominic ordered 210 pens. He divided them equally among his 10 friends.

So, Each of his friends gets (210/10) = 21 pens.

Now, Benjamin already had 27 pens.

So, Now he has 21 + 27 = 48 pens.

Then, Benjamin gave 13 of his pens to Peyton.

So, At last, he has 48 - 13 = 35 pens.

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The values of p1, p2, p3 that minimize Var(X) are p1 = 0, p2 = 1/3, and p3 = 2/3.

We can use the following formulas to find the variance of X:

Var(X) = E[X^2] - (E[X])^2

E[X] = p1 + 2p2 + 3p3

E[X^2] = p1 + 4p2 + 9p3

Substituting these expressions into the formula for the variance, we get:

Var(X) = p1 + 4p2 + 9p3 - (p1 + 2p2 + 3p3)^2

Simplifying this expression, we get:

Var(X) = -\((p1^2 + 2p2^2 + 3p3^2) + 2p1p2 + 6p1p3 + 4p2p3\)

To maximize Var(X), we want to maximize this expression subject to the constraint p1 + p2 + p3 = 1. We can use Lagrange multipliers to find the maximum. Let:

L(p1, p2, p3, λ) = -\((p1^2 + 2p2^2 + 3p3^2) + 2p1p2 + 6p1p3 + 4p2p3 + λ(1 - p1 - p2 - p3)\)

Taking partial derivatives and setting them equal to zero, we get:

-2p1 + 2p2 + 6p3 - λ = 0

4p1 - 4p2 + 4p3 - λ = 0

6p1 + 8p2 - 6p3 - λ = 0

p1 + p2 + p3 = 1

Solving these equations, we get:

p1 = 2/7, p2 = 3/7, p3 = 2/7, λ = 4/7

Therefore, the values of p1, p2, p3 that maximize Var(X) are p1 = 2/7, p2 = 3/7, and p3 = 2/7.

To minimize Var(X), we want to minimize the expression \(-(p1^2 + 2p2^2 + 3p3^2) + 2p1p2 + 6p1p3 + 4p2p3\) subject to the constraint p1 + p2 + p3 = 1. We can use the same Lagrange multiplier method to find the minimum. Taking partial derivatives and setting them equal to zero, we get:

-2p1 + 2p2 + 6p3 - λ = 0

4p1 - 4p2 + 4p3 - λ = 0

6p1 + 8p2 - 6p3 - λ = 0

p1 + p2 + p3 = 1

Solving these equations, we get:

p1 = 0, p2 = 1/3, p3 = 2/3, λ = 2/3

Therefore, the values of p1, p2, p3 that minimize Var(X) are p1 = 0, p2 = 1/3, and p3 = 2/3.

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Answer:

The width is 6 and the length is 9.

Step-by-step explanation:

Factors of 54: (1, 54), (2, 2), (3, 18), and (6, 9)

6 and 9 would work because 6+3=9

Answer:

3/5

Step-by-step explanation:

In your problem you have a right triangle.

For this problem, you need to know what sine is. Sin is \(\\\frac{opposite}{hypotenuse}\)

In this problem we know that the hypotenuse is 20, but we do not know the opposite. The opposite refers to the side that is opposite to the angle. In this case, the angle we are using is c. Also, in this case, the name of the opposite side is ED. To figure out that side, we need to use the pythagorean theorem.

\(a^{2} +b^{2} =c^{2}\)

A is 16, c is 20

Therfore we can plug those values into our formula

\(16^{2} +b^{2}=20^{2}\)

Simplify:

\(256 + b^{2} =400\)

Simplify even more:

\(b^{2} = 144\)

Square root both sides:

\(b = 12\)

Now we Know all 3 sides of our triangle: 20, 16, and 12.

Sin refers to OPPOSITE/HYPOTENUSE

Our opposite is 12, and our hypotenuse is 20.

Plugging those values into our formula gives us:

12/20

Simplify:

3/5.

THERFORE, THE ANSWER IS 3/5

**Also, this whole process seems long, but in reality it is very short and you'll master it in no time!

There is a 21.5% chance that a point in a square with nine congruent circles drawn there won't be within one if it is chosen at random.

It is given to us that :

Nine congruent circles are inscribed in a square

The square has a side length of 126

We have to find out the probability that the point is not in a circle, if a point in the square is chosen at random.

It is known that the square has a side length of 126.

=> Area of the square = \((Length)^{2}\)

=> Area of the square = \(126^{2}\)

=> Area of the square = 15876 ------ (1)

It is also known to us that nine congruent circles are inscribed in the square that has a side length of 126.

=> Diameter of each circle = 126/3

=> Diameter of each circle = 42

=> Radius of each circle = 21  ------ (2)

We know that the area of a circle is given as -

Area of circle = \(\pi r^{2}\)  ------ (3)

where,

r = radius of the circle

Substituting the value of r from equation (2) in equation (1), we have

Area of circle = \(\pi r^{2}\)

=> Area of circle = \(\pi (21)^{2}\)

=> Area of circle = 1385.44

=> Area of 9 circles = 12468.96    ----- (4)

Now, we can say that -

Area not in a circle = Area of square - Area of 9 circles

=> Area not in a circle = 15876 - 12468.96 [From equation (1) and (4)]

=> Area not in a circle = 3407.04    ------ (5)

We know that the probability of a outcome is given as -

Probability = Number of favorable outcomes/Total number of outcomes

So, the probability that the point is not in a circle can be calculated as -

Probability = Area not in a circle/Area of square

=> Probability = 3407.04/15876

=> Probability = 0.215

=> Probability = 21.5%

Thus, if there are nine congruent circles inscribed in a square and a point in the square is chosen at random, the probability that the point is not in a circle is 21.5%.

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Answer:

B

x is the price of the sweater so 3x  and add $15 for the skirt which would add up to $90

Answer:

3x + 15 = 90

Step-by-step explanation:

hope this helps!

Answ 456

Step-by-step explanation:

ask your mom she might know unless she is to craycray

Answer:

The answer is $34.73

Answer:

18

Step-by-step explanation:

70^2 = 4900 < 5607 < 6400 = 80^2

so sqrt(5607) is a two-digit number with tenth-digit 7

71^2 = 5041, 72^2 = 5184, 73^2 = 5329, 74^2 = 5476, 75^2 = 5625

so the smallest square bigger than 5607 is 75^2, which is 5625

so the number should ne 5625 - 5607 = 18

Answer:

(g ○ f)(0) is invalid

Step-by-step explanation:

g(x) = x − 4

f(x) = 1/x

(g ○ f)(x) = 1/x - 4

(g ○ f)(0) can not be evaluated, because if x = 0, 1/x becomes invalid.

Answer:

To evaluate the composition, you need to find the value of function f first. But, f(0) is 1 over 0, and division by 0 is undefined. Therefore, you cannot find the value of the composition.

Step-by-step explanation:

This is the sample response on edge

With the thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

a) 40% of the flanges exceeds 1.01 millimeters.

b) 1.04 millimeters is the thickness that is exceeded by 90% of the flanges.

c) The mean of flange thickness is 1 millimeters and the variance of flange thickness is 0.01 millimeters^2.

a) To determine the proportion of flanges that exceeds 1.01 millimeters, we need to find the area under the probability density function (pdf) of the thickness that is greater than 1.01 millimeters.

Let's call the random variable X representing the thickness of the flange. The pdf of X is uniform, so it has constant value over the interval [0.95, 1.05]. Therefore, the proportion of flanges that exceeds 1.01 millimeters can be found as follows:

P(X > 1.01) = (1.05 - 1.01) / (1.05 - 0.95) = (1.05 - 1.01) / 0.1 = 0.04 / 0.1 = 0.4

So, 40% of the flanges exceed 1.01 millimeters.

b) To find the thickness that is exceeded by 90% of the flanges, we need to solve for X in the following equation:

P(X > X) = 0.9

Substituting the values for the pdf, we get:

(X - 0.95) / (1.05 - 0.95) = 0.9

Solving for X, we get:

X = 0.95 + 0.9 * (1.05 - 0.95) = 0.95 + 0.9 * 0.1 = 0.95 + 0.09 = 1.04

So, 1.04 millimeters is the thickness that is exceeded by 90% of the flanges.

c) The mean of X can be calculated as follows:

Mean = (0.95 + 1.05) / 2 = 1

The variance of X can be calculated as follows:

Variance = (1.05 - 0.95)^2 / 12 = 0.01

So, the mean and variance of flange thickness are:

Mean = 1 millimeters

Variance = 0.01 millimeters^2

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Answer:

The third one

Steps:

hope this helps :b

Answer:

5+8x

Step-by-step explanation:

I did the math.

When multiplying or dividing a number by 1,000, it is the same as moving the decimal point three places to the right or left, respectively.

When multiplying a number by 1,000, it is the same as moving the decimal point three places to the right. This can be represented through the formula x * 1000 = x/1000. For example, if the number is 5, then 5 * 1000 = 5,000. This is the same as moving the decimal point three places to the right of 5, which results in 5.000. The same concept can be applied when dividing a number by 1,000. For example, if the number is 5,000, then 5,000 / 1000 = 5. This is the same as moving the decimal point three places to the left of 5,000, which results in 5.000. Therefore, when multiplying or dividing a number by 1,000, it is the same as moving the decimal point three places to the right or left, respectively.

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The equilibrium number of firms will be the smallest integer such that the price is 6 or higher. This occurs when n = 2. At this equilibrium, the price is P = 6, the output of each firm is y = 3/2, the industry's output is Y = 3, and the profit of each firm  = -2.

a) Supply curve of an individual firm

The price received by the individual firm will be P. Its demand curve is given by

D(p) = 20 - p.

Each firm chooses output to maximize its profit. Profit maximization occurs when the price is equal to the marginal cost. Mathematically,

P = MC(y)

4y = P

y = P/4

Thus the supply curve of the firm is y = P/4

b) The smallest price at which the product can be sold. The product can be sold at the minimum of the supply curve, which is y = 0, given P ≥ 0. Therefore the smallest price is P = 0.

c) Equilibrium price and output

Equilibrium occurs when each firm is producing at its profit-maximizing output given the output of other firms. Let the number of firms in the industry be n. The output of the industry is Y = ny. The industry supply curve is given by

S(P) = nP/4

The equilibrium price intersects the industry supply curve with the demand curve. Thus the equilibrium price satisfies

S(P) = Y

nP/4 = 20 - P

=> P = 80/(4 + n).

The equilibrium number of firms is the number that makes the industry supply curve equal to the demand curve. Thus

20 - P = nP/4

=> P = 80/(4 + n)

=> n = (80 - 20P)/P

= 20/P - 4.

Thus the equilibrium number of firms is a function of P and can range between 1 and infinity, but it must be an integer. The equilibrium output of each firm is given by

y = P/4 = 20/(4n + n²)

The equilibrium output of the industry is given by

Y = n

y = 5/P = (n² + 4n)/80.

d) Equilibrium number of firms with new demand curve D(p) = 21 - p.

The intersection of this curve with the marginal cost curve is at p = 21/5. This is greater than the minimum possible price of 0. Thus there is a positive profit to be earned in this industry, and new firms can enter the market.

e) Equilibrium price and output with new demand curve with the new demand curve D(p) = 21 - p, the industry supply curve and the equilibrium price are as given in part (d). The equilibrium output of each firm is given by y = P/4 = 21/20, and the equilibrium output of the industry is given by Y = 21/4.

f) Equilibrium number of firms, price, output, and profit with demand curve D(p) = 24 - p. This demand curve intersects the marginal cost curve at p = 6. The minimum possible price is P = 0. Thus there is a range of prices from 0 to 6 where firms can profit positively.

The equilibrium number of firms will be the smallest integer such that the price is 6 or higher. This occurs when n = 2. At this equilibrium, the price is P = 6, the output of each firm is y = 3/2, the output of the industry is Y = 3, and the profit of each firm is (6)(3/2) - (2)(2(3/2)² + 8) = -2.

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Answer:

t¹⁰

Step-by-step explanation:

The 10th power of t:

t¹⁰

Displacement is the length of the straight line drawn from an object’s initial position to the object’s final position

The term "displacement" refers to a change in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial position to the ending position. For instance, if an object shifts from position A to position B, its position changes.

If an object moves with respect to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right with respect to a whiteboard, the object's position changes. This change in location is described as displacement.

The displacement is the shortest distance between an object's initial and final positions. Displacement is a vector. It is visualized as an arrow that points from the initial position to the final position, indicating that it has both a direction and a magnitude.

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The answer of the given question based n the matrix is ,  the determinant of the given matrix is -12.

Using Chio's method:

When Chio's method is used, the main step involves obtaining the determinant of the given matrix.

The given matrix is 4 × 4 matrix.

Therefore, the formula for calculating the determinant of a 4 × 4 matrix is as follows:

|A|=a11×A11-a12×A12+a13×A13-a14×A14

where A11, A12, A13, and A14 are minors obtained from A.

These minors are of size 3 × 3 matrices.

To find the first term (a11×A11), we need to obtain the minors of A11, A12, A13, and A14.

They are as follows:

A11 = -2, 4, 0,-1, 0, 2, 0, 1, 0

A12 = 2, 4, 0, 3, 0, 2, -2, 3, 1

A13 = 0, -2, 1, 0, 3, 3, 2, 1, 2

A14 = 0, -2, 1, 0, 3, 1, 1, 2, 0

Using the minors obtained, the determinant can be obtained as follows:

|A| = 1 × (-2(4(3) - 2(1)) - 2(3(0) - 2(2)) + 1(3(0) - 4(1)))|A| = -24 - (-12) + (0)|A|

= -12

Therefore, the determinant of the given matrix is -12.

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Answer:

  11.4

Step-by-step explanation:

You want the distance between C(-5, 5) and D(4, -2).

The distance formula is ...

  d = √((x2 -x1)² +(y2 -y1)²)

For the given points, the distance is computed to be ...

  d = √((4 -(-5))² +(-2 -5)²) = √(81 +49) = √130

  d ≈ 11.4

The length of CD is about 11.4 units.

__

Additional comment

The distance formula is an application of the Pythagorean theorem. It computes the hypotenuse of a right triangle whose legs are the differences in x- and y-coordinates.

Answer:

9:21

Step-by-step explanation:

Answer:

9:12

Step-by-step explanation:

There are 9 purple flowers, 7 pink flowers, and 5 white flowers.

If you want the ratio of purple to the total, all you have to do is add the pink and white flowers together.

So the answer would be...

9:12

Answer:

70%

Step-by-step explanation:

To find the total percentage of his $60 dollars that he spent on fruit, we simply take the amount of money spent on fruit divided by the total spent.

% spent on fruit = 42 / 60

% spent on fruit = 0.7

% spent on fruit = 70 %

Cheers.

Answer:

70%

Step-by-step explanation:

so he spent 42/60

lets simplify by dividing on both sides by 2

21/30

then divide by 3

7/10

which is also 70/100

so 70%

yaaaaayyyy we r done!!!!!!!!!

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

  ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                 PEACE!