Solve for r.
(-3,r) and (2,14)
m = 5

the parallel line is 2x+5y+15=0.

Step-by-step explanation:

ok I hope it will work

soo,

Solution

given,

given parallel line 2x+5y=15

which goes through the point (-10,1)

now,

let 2x+5y=15 be equation no.1

then the line which is parallel to the equation 1st

2 x+5y+k = 0 let it be equation no.2

now the equation no.2 passes through the point (-10,1)

or, 2x+5y+k =0

or, 2*-10+5*1+k= 0

or, -20+5+k= 0

or, -15+k= 0

or, k= 15

putting the value of k in equation no.2 we get,

or, 2x+5y+k=0

or, 2x+5y+15=0

which is a required line.

Answer:

Natalie arrived at 3:55 pm or 15:25

Step-by-step explanation:

Start time is 3:00

The first two friends arrived at 10 minutes after 3. Arrival time = 3:10

Natalie arrived 45 minutes later. Arrival time is 3:10 + 45 = 3:55

Natalie arrived at 3:55, using 24-hour formats, the arrival time is 15:55

The money left is $13.25.

Given data,

Your parents handed you $50 to spend on movie tickets for your sister and brother. You paid $8.25 for your ticket, while your siblings paid $4.25.

To know how much money you bring home after spending an extra $20 on soda and popcorn,

Your entry cost is $8.25

$4.25 for the brother's ticket

Sister's entry fee is $4.25.

$20 for soda and popcorn.

Total = 8.25 + 4.25 + 4.25 + 20.00 = $36.75

You received $50 from your parents.

You have spent $36.75.

Balance: 50.00 - 36.75 = $13.25

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Jupiter is 5,751.51 times more massive than Mercury.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The mass of the planet Jupiter is given below.

1,898,000,000,000,000,000,000,000,000 kg.

The scientific notation is:- 2 x 10²⁷ kg.

The mass of the planet Mercury is given below.

330,000,000,000,000,000,000,000 kg.

The scientific notation is:- 3.30 x 10²³ kg.

Divide the mass of the planet Jupiter by the mass of the planet Mercury. Then we have

Jupiter / Mercury =  2 x 10²⁷  / 3.30 x 10²³

Jupiter / Mercury = 5,751.51

Your question was incomplete, but the complete question was given below.

The most massive planet in the solar system, Jupiter, has a mass of about 1,898,000,000,000,000,000,000,000,000 kg.

The least massive planet is Mercury, which has a mass of about 330,000,000,000,000,000,000,000 kg.

Use your estimates to find out how many times more massive Jupiter is than Mercury. Express your answer in standard form (without using a power of 10).

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Answer: 2 or 3

Step-by-step explanation:

Which ever line is going through the most points

What’s thee answer hello

Answer:

true

Step-by-step explanation:

<3

Answer:

Step-by-step explanation:

A regular quadrilateral has 4 congruent sides and 4 angles

Step-by-step explanation:

The formula of a circumference of a circle with radius r:

\(C=2\pi r\)

Solve for r:

\(2\pi r=C\)     subtitute  \(\pi\approx\dfrac{22}{7}\)

\(2\cdot\dfrac{22}{7}r=C\)

\(\dfrac{44}{7}r=C\)       multiply both sides by 7

\(44r=7C\)      divide both sides by 44

\(r=\dfrac{7C}{44}\)

Substitute the values of the circumference from your question:

\(i.\ C=88cm\\\\r=\dfrac{7\cdot88}{44}=\dfrac{7\cdot2}{1}=12(cm)\\\\=================\)

\(ii.\ C=1.4m\\\\r=\dfrac{7\cdot1.4}{44}=\dfrac{9.8}{44}=\dfrac{98}{440}=\dfrac{49}{220}(m)\\\\====================\)

\(iii.\ C=16m\\\\r=\dfrac{7\cdot16}{44}=\dfrac{7\cdot4}{11}=\dfrac{28}{11}(m)\\\\=================\)

\(iv.\ C=33ft\\\\r=\dfrac{7\cdot33}{44}=\dfrac{7\cdot3}{4}=\dfrac{21}{4}(ft)\\\\=================\)

\(v.\ C=5m\\\\r=\dfrac{7\cdot5}{44}=\dfrac{35}{44}(m)\\\\===============\)

\(vi.\ C=66m\\\\r=\dfrac{7\cdot66}{44}=\dfrac{7\cdot3}{2}=\dfrac{21}{2}(m)\\\\================\)

I am not pretty sure of the answer but maybe it's 5/10

Answer:

the number half way between 1-5 is 3. and the number half way between 9/10 is 9.5

Step-by-step explanation:

to find the number half way between 1/5 just write out all the numbers (1 2 3 4 5) and 3 is the halfway point because there are two numbers on the right and to numbers on the left

the number halfway between 9 and 10 is 9.5. all you do is add 9 +10 then divide by 2

9+10=19

19÷2= 9.5

Step-by-step explanation: The solution to this system of equations will be where the two lines on the graph intersect with each other.

Notice that both of them intersect to the left of the y-axis which means our x - coordinate must be negative.

They also intersect above the x-axis so our y-coordinate must be positive.

So the only option with a negative x-coordinate

and a positive y-coordinate is (-1/4, 3/4).

Answer:

88.8888888889% or 88% rounded

plz Brainliest?!?!?

The given double integral is ∫ ∫ (x² + y²)dx dy, and we need to evaluate it over the region in the positive quadrant where x+y≤1.

To evaluate this double integral, we can first determine the limits of integration for both x and y based on the given region. In the positive quadrant, x and y both range from 0 to 1.

Now, integrating the inner integral with respect to x, we get:

∫ (x² + y²)dx = (1/3)x³ + y²x + C1,

where C1 is the constant of integration.

Next, we integrate the resulting expression with respect to y:

∫ [(1/3)x³ + y²x + C1] dy = (1/3)x³y + (1/3)y³x + C1y + C2,

where C2 is another constant of integration.

Finally, we evaluate this double integral over the given region by substituting the limits of integration:

∫∫ (x² + y²)dx dy = ∫[0 to 1] ∫[0 to 1-x] (x² + y²)dy dx.

Performing the integration, we can find the numerical value of the double integral within the given region.

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Answer:

25,709.4

Step-by-step explanation:

First you would multiply 3.5 x 24,000, and then divide by 100, to get 840, and then add that to the original  amount to get 24,840, and that is the cost for one year. And then you would multiply 24,840 by 3.5 and then divide by 100 to get 869.4. Finally just add that to 24,840 to get 25,709.4, and that is the cost for 2 years. I hope this helps :)

The cost of college in two years is $25709.4.

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Cost of Faber college  = $24000

Rate of increase = 3.5%

The cost of college after one year.

= 103.5% of 24,000

= 103.5/100 x 24000

= $24,840

The cost of their college after two years.

= 103.5% of 24,000

= 103.5/100 x 24,840

= $25709.4

Thus,

The cost of college in two years is $25709.4.

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The point P along the directed line segment from X(-3, 3) to Y(6,-3) that divides the segment in a 2:1 ratio is  (3, -1).

In coordinate geometry, Section formula is used to find the ratio in which a line segment is divided by a point internally or externally. It is used to find out the centroid, incenter and ex centers of a triangle

Given

\((x_{1} ,y_{1})\) = X(-3, 3)

\((x_{2},y_{2} )\) = Y(6,-3)

m: n = 2:1

Section formula = \((\frac{mx_{2}+nx_{1} }{m+n},\frac{my_{2}+ny_{1} }{m+n} )\)

P(a, b) = \((\frac{2(6)+1(-3)}{2+1} ,\frac{2(-3)+1(3)}{2+1} )\)

P(a, b) = \((\frac{12-3}{3},\frac{-6+3}{3} )\)

P(a, b) = \((\frac{9}{3} ,\frac{-3}{3} )\)

P(a, b) = (3, -1)

The point P along the directed line segment from X(-3, 3) to Y(6,-3) that divides the segment in a 2:1 ratio is  (3, -1).

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Suppose A=BC, where B is invertible. Show that any sequence of row operations that reduces B to also reduces A to C. The zero matrix may be factored as 0= B.

To show that any sequence of row operations that reduces B to also reduces A to C, the following pieces of information in the problem statement are relevant:

A. The zero matrix may be factored as 0= B * 0. This is not relevant for showing that any sequence of row operations that reduces B to also reduces A to C.B. A=B.

This is not relevant for showing that any sequence of row operations that reduces B to also reduces A to C.C. B is invertible. This is relevant for showing that any sequence of row operations that reduces B to also reduces A to C.D. The converse not true. This is relevant for showing that any sequence of row operations that reduces B to also reduces A to C.

Given the relevant pieces of information from the previous step, there exist elementary matrices E1, ..., Ep  corresponding to row operations that reduce B to I, in the sense that Ep...E2E1B=I. Applying the same sequence of row operations to A amounts to left-multiplying by the product E1E2...Ep.

Therefore, A is transformed to C, since

C = IB = E1

E2...Ep

B = E1E2...EpA.

The proof is complete because C = IC = C.

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It will cost approximately $0.0249 to purchase the necessary seam binding for Hana's 18 pennants.

To calculate the cost of seam binding for Hana's pennants, we need to determine how much seam binding she will require and then calculate the total cost based on the package size and cost.

Each pennant will require seam binding for three edges (top, bottom, and diagonal), as it needs to be finished on all sides.

Calculate the total length of seam binding needed:

Since each pennant has three edges, the total length of seam binding required is:

Length of seam binding = 3 * 1/2 inch = 3/2 inch

Convert the length to yards:Since the seam binding is sold in 3-yard packages, we need to convert the length from inches to yards:

Length in yards = (3/2) inch * (1 yard / 36 inches)

= (3/2) / 36 yard

= 1/24 yard

Determine the number of packages required:

Since each package contains 3 yards of seam binding, we divide the total length required by the package size:

Number of packages required = (1/24 yard) / (3 yards/package)

= 1/72 package

Calculate the cost:

The cost of each package is given as $1.79. Since we need 1/72 of a package, we can calculate the total cost:

Total cost = (1/72 package) * ($1.79/package)

= $1.79/72

≈ $0.0249 (rounded to four decimal places)

Therefore, it will cost approximately $0.0249 to purchase the necessary seam binding for Hana's 18 pennants.

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Answer:

3 hours

Step-by-step explanation:

Let's express number of hours required for servicing as: x

The auto repair on First Street charges a flat fee of $15 plus $10 an hour for servicing a car.

This is expressed mathematically as:

$15 + $10 × x

= 15 + 10x

The auto repair shop on Second Avenue charges no flat fee but $15 an hour for servicing a car

This is expressed as:

$15 × x

= 15x

The number of hours Malik's car needs to be serviced in order to be able to pay the same amount of money at both shops is calculated as:

Charges by Auto repair shop on First street = Charges by Auto repair shop on Second Avenue

15 + 10x = 15x

15 = 15x - 10x

15 = 5x

5x = 15

x = 15/5

x = 3 hours

Therefore, the number of hours Malik's car needs to be serviced in order to be able to pay the same amount of money at either auto repair shops is 3 hours

The labor hours required for the eighth satellite are calculated to be 51,200 based on a learning curve value of 0.5120 and an expected improvement curve of 80%.

The learning curve concept suggests that as the cumulative production doubles, the labor hours required to produce each unit decrease by a certain percentage. In this case, the learning curve value for the eighth unit is given as 0.5120, which means that the labor hours needed for the eighth satellite is 51.20% of the labor hours required for the first unit.

To calculate the actual number of labor hours, we multiply the learning curve value by the total labor hours required for the first unit. Given that the total labor hours for the first unit is 100,000, we can calculate the labor hours for the eighth satellite as follows: 0.5120 * 100,000 = 51,200.

Therefore, based on the given learning curve value and the expected improvement curve of 80%, the number of labor hours for the eighth satellite is determined to be 51,200.

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For conservative forces, force can be fouind as being the negative of the deriviation of potential energy.

It should be noted that a conservative force simply means the force in moving a particle from a particular point to another. In this case, the force is independent of the path that's taken by the particle.

It should be noted that F = du/dr as u is the potential energy. Therefore, force is the negative derivative of the potential energy.

Therefore, for conservative forces, force can be fouind as being the negative of the deriviation of potential energy.

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Complete question

For conservative forces, force can be fouind as being the negative of the deriviation of?

momentum

kinetic energy

impulse

work

potential energy

Solving a differential equation with an integrating factor involves the following steps:

1. Identify the differential equation: Determine if the given equation is a first-order linear differential equation of the form dy/dx + P(x)y = Q(x).
2. Find the integrating factor: Compute the integrating factor (IF) by calculating the exponential of the integral of P(x) with respect to x, i.e., IF = e^(∫P(x)dx).
3. Multiply by the integrating factor: Multiply the entire differential equation by the integrating factor, which will transform the left-hand side into the derivative of the product of y(x) and the integrating factor.
4. Integrate both sides: Integrate both sides of the equation with respect to x. The left-hand side will yield the product of y(x) and the integrating factor, while the right-hand side will yield the integral of Q(x) multiplied by the integrating factor.
5. Solve for y(x): Divide both sides by the integrating factor to obtain the solution y(x).

The flowchart for this process can be summarized as follows:
1. Identify first-order linear differential equation
2. Compute integrating factor
3. Multiply equation by integrating factor
4. Integrate both sides of the equation
5. Solve for y(x)

Remember, always ensure the given differential equation is in the appropriate form before applying this method.

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Answer:  (0,3) in the top right corner

There is only one solution to this system of equations.

The graph is shown below.

============================================================

Explanation:

Because we're given a list of choices, we can plug in each (x,y) coordinates into each equation. The goal is to see if we get true or equations or not. True equations have the same number on both sides after fully simplifying.

Let's try (x,y) = (4,1) and we'll plug this into the first equation.

\(y = \sqrt{9-x}\\\\1 = \sqrt{9-4}\\\\1 = \sqrt{5}\\\\\)

The last equation is false, so the first equation must be false for those x,y values. We don't need to check the other equation. We have enough to rule out any answer choice involving (4,1). So that means we can cross off the two answer choices on the left side.

---------------------

Let's try (x,y) = (0,3) in the first equation

\(y = \sqrt{9-x}\\\\3 = \sqrt{9-0}\\\\3 = \sqrt{9}\\\\3 = 3\\\\\)

We get a true equation. So far, so good.

Now we need to check the other equation

\(x+2y = 6\\\\0+2*3 = 6\\\\6 = 6\\\\\)

That works as well. Therefore, the point (0,3) is confirmed to be a solution to this system. Since the top right corner is the only thing remaining that has (0,3), this must be the final answer. So we can stop here.

---------------------

For the sake of completeness, let's try (8,1)

\(y = \sqrt{9-x}\\\\1 = \sqrt{9-8}\\\\1 = \sqrt{1}\\\\1 = 1\\\\\)

Looking good so far. Now the second equation

\(x+2y = 6\\\\8+2*1 = 6\\\\10 = 6\\\\\)

which is false. The point (8,1) must make both equations true in order for it to be considered a solution. Therefore, we rule out (8,1). If you didn't check (4,1) earlier, then ruling out (8,1) will let you cross off the top left corner answer choice.

A quick way to find the solution(s) is to graph the two curves and see where they cross. They intersect at (0,3) which is the only solution of this system. See below.

To decrease the width of the confidence interval, the researcher can take the following steps:

1. Decrease the confidence level: The confidence interval width is inversely proportional to the confidence level. By decreasing the confidence level, the researcher can have a narrower interval. However, it is important to note that decreasing the confidence level also increases the chance of the interval not capturing the true population mean.

2. Increase the sample size: The sample size affects the precision of the estimate. Increasing the sample size reduces the standard error, which leads to a narrower confidence interval. This is because a larger sample provides more information about the population.

Therefore, the researcher can decrease the width of the confidence interval by either decreasing the confidence level or increasing the sample size. Both approaches will result in a narrower interval, providing a more precise estimate of the mean fat content of hen's eggs.

The researcher can decrease the width of the confidence interval by either decreasing the confidence level or increasing the sample size. Both approaches will result in a more precise estimate of the mean fat content of hen's eggs.

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The food percentage would be 19%, 51% and 30%.

Given that we've done it

Number of meals consumed by X = 57

Food consumed by Y = 153.

Number of meals consumed by Z = 90

Total amount of meals consumed = 57 + 153 +90 = 300

Food proportion of flock X thus Equals 57 / 300 * 100 = 19 %

flock food percentage Y =153/300 * 100 = 51 %

flock food percentage Z = 90/300 * 100 = 30 %

This means that the percentages are 19%, 51%, and 30%.

Based on the given information, we have:

Flock X ate 57 pieces of food.

Flock Y ate 153 pieces of food.

Flock Z ate 90 pieces of food.

The total number of pieces of food eaten is 300 (sum of the individual flock's food).

The food percentage for Flock X is 57/300 ≈ 0.19 or 19%.

The food percentage for Flock Y is 153/300 ≈ 0.51 or 51%.

The food percentage for Flock Z is 90/300 = 0.3 or 30%.

The total number of birds for the second generation is 30 (given).

To find the simulated number of birds in each flock for the second generation, we multiply the food percentage for each flock by the total number of birds (30).

For Flock X: 0.19 × 30 = 5.7 (rounded to the nearest whole number: 6 birds)

For Flock Y: 0.51 × 30 = 15.3 (rounded to the nearest whole number: 15 birds)

For Flock Z: 0.3 × 30 = 9 (rounded to the nearest whole number: 9 birds)

Therefore, the simulated number of birds in Flock X, Flock Y, and Flock Z for the second generation are 6, 15, and 9 birds, respectively.

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Complete Question

Flock X Flock Y Flock z Total Pieces of Food Eaten 57 153 90 Food Percentage* % 1% % Simulated Number of Birds in Flock for 2nd Generation ** * Divide each flock's total pieces of food by 300, the total number of pieces of food eaten. ** Multiply the food percentage for each flock by the total number of birds (30). DONE

Answer:

19 51 30

6 15 9

second part Is Y then X

Step-by-step explanation:

The equation first, third, fifth and seventh are equivalent to the fifth, second, fourth and eighth equation.

Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.

Equivalent expression can be found out by simplifying the given equation.

First equation given as,

\(\left(-14+\dfrac{3}{2}b\right)-\left(1+\dfrac{8}{2}b\right)\)

Simplify it further,

\(\left(-14+\dfrac{3}{2}b\right)-\left(1+\dfrac{8}{2}b\right)\\-14+\dfrac{3}{2}b-(1+4b)\\-14+\dfrac{3}{2}b-1-4b\\-15-\dfrac{5}{2}b\)

Third equation in the problem given as,

\(\left(5+2b\right)+\left(2b+\dfrac{3}{2}\right)\\5+2b+2b+\dfrac{3}{2}\\4b+\dfrac{13}{2}\)

Simplify it further,

\(\left(-14+\dfrac{3}{2}b\right)-\left(1+\dfrac{8}{2}b\right)\\-14+\dfrac{3}{2}b-(1+4b)\\-14+\dfrac{3}{2}b-1-4b\\-15-\dfrac{5}{2}b\)

Similarly, the fifth and seventh equation are simplified and equivalent to the fourth and eight respectively.

Thus, the equation first, third, fifth and seventh are equivalent to the fifth, second, fourth and eighth equation.

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Answer:

The vertices of the quadrilateral after a dilation with scale factor \(\frac{2}{3}\) are \(J'(x,y) = (0,0)\), \(K'(x,y) = (0,4)\), \(L'(x,y) = (6, 8)\) and \(M'(x,y) = (8,0)\).

Step-by-step explanation:

Let suppose that center of dilation is located at origin, that is \(O(x,y) = (0,0)\). Vectorially speaking, dilation is described by following expression:

\(D'(x,y) = O(x,y) + r\cdot [D(x,y)-O(x,y)]\) (1)

Where:

\(O(x,y)\) - Center of dilation.

\(D(x,y)\) - Original point.

\(D'(x,y)\) - Dilated point.

\(r\) - Dilation factor.

If we know that \(O(x,y) = (0,0)\), \(r = \frac{2}{3}\), \(J(x,y) = (0,0)\), \(K(x,y) = (0,6)\), \(L(x,y) = (9,12)\) and \(M(x,y) = (12,0)\), then the dilated points are, respectively:

\(J'(x,y) = O(x,y) + r\cdot [J(x,y)-O(x,y)]\)

\(J'(x,y) = (0,0) +\frac{2}{3}\cdot [(0,0)-(0,0)]\)

\(J'(x,y) = (0,0)\)

\(K'(x,y) = O(x,y) + r\cdot [K(x,y)-O(x,y)]\)

\(K'(x,y) = (0,0)+\frac{2}{3}\cdot [(0,6)-(0,0)]\)

\(K'(x,y) = (0,4)\)

\(L'(x,y) = O(x,y) +r\cdot [L(x,y)-O(x,y)]\)

\(L'(x,y) = (0,0) + \frac{2}{3}\cdot [(9,12)-(0,0)]\)

\(L'(x,y) = (6, 8)\)

\(M'(x,y) = O(x,y) +r\cdot [M(x,y)-O(x,y)]\)

\(M'(x,y) = (0,0) +\frac{2}{3}\cdot [(12,0)-(0,0)]\)

\(M'(x,y) = (8,0)\)

The vertices of the quadrilateral after a dilation with scale factor \(\frac{2}{3}\) are \(J'(x,y) = (0,0)\), \(K'(x,y) = (0,4)\), \(L'(x,y) = (6, 8)\) and \(M'(x,y) = (8,0)\).

  Option B will be the correct option.

        (a, b) → (ka, kb)

Following the rule for dilation,

If a quadrilateral J(0, 0), K(0, 6), L(9, 12) and M(12, 0) is dilated by a scale factor \(\frac{2}{3}\), coordinates of the image points will be,

\(J(0,0)\rightarrow J'(0, 0)\)

\(K(0,4)\rightarrow K'(0, 4)\)

\(L(9,12)\rightarrow L'(6,8)\)

\(M(12,0)\rightarrow M'(8,0)\)

     Therefore, Option B will be the correct option.

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Answer:

9.6

Step-by-step explanation:

6.4/x = sin42

x = 6.4/sin42

x = 9.56

What is 16% of 78? Round to the nearest tenth.

16% = 0.16

so:

0.16 * 78 = 12.48

round:

12.5

Average waiting time for FCFS: 8.75

Average waiting time for SJF: 4.75

To solve this scheduling problem using FCFS (First-Come, First-Served) and SJF (Shortest Job First) algorithms, let's go step by step:

Schedule order for FCFS:

The FCFS algorithm schedules processes based on their arrival time. So, the schedule order for FCFS is as follows:

Pl -> P2 -> P3 -> P4

Average waiting time for FCFS:

To compute the average waiting time for FCFS, we need to calculate the waiting time for each process and then take the average.

Process | Arrival Time | Running Time | Waiting Time

Pl | 0 | 3 | 0

P2 | 3 | 10 | 3

P3 | 4 | 6 | 13

P4 | 5 | 1 | 19

Average waiting time = (0 + 3 + 13 + 19) / 4 = 8.75

Therefore, the average waiting time for FCFS is 8.75.

Schedule order for SJF:

The SJF algorithm schedules processes based on their running time. The process with the shortest running time gets executed first. If multiple processes have the same running time, the process with the earliest arrival time is selected first. The schedule order for SJF is as follows:

Pl -> P4 -> P3 -> P2

Average waiting time for SJF:

To compute the average waiting time for SJF, we need to calculate the waiting time for each process and then take the average.

Process | Arrival Time | Running Time | Waiting Time

Pl | 0 | 3 | 0

P4 | 5 | 1 | 3

P3 | 4 | 6 | 6

P2 | 3 | 10 | 10

Average waiting time = (0 + 3 + 6 + 10) / 4 = 4.75

Therefore, the average waiting time for SJF is 4.75.

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Answer:

x^2-8x+16

Step-by-step explanation:

(x-4)^2

x^2-4x-4x+16

x^2-8x+16