Suppose that liquid Nickel is undercooled until homogeneous nucleation occurs. Calculate: (a) the expected critical radius of the required nucleus, and (b) the number of Nickel atoms in that nucleus. Assume a 480o C amount of undercooling, and that the lattice parameter ao for Nickel is 0.365 nm.

a) For a perfect gas, the pressure exerted by 1.0 mol of C2H6 at 273.15 K in 22.414 dm³ is 1.0 atm, and at 1000 K in 100 cm³ is 820 atm.

b) Considering a van der Waals gas, the pressure exerted by 1.0 mol of C2H6 at 273.15 K in 22.414 dm³ is approximately 0.997 atm, and at 1000 K in 100 cm³ is about 819 atm.

To calculate the pressure exerted by a gas, we can use the ideal gas law for a perfect gas and the van der Waals equation for a van der Waals gas.

a) Perfect Gas:

The ideal gas law is given by:

PV = nRT

Where:

P = Pressure

V = Volume

n = Number of moles

R = Ideal gas constant

T = Temperature

(i) At 273.15 K in 22.414 dm³:

P = (nRT) / V

P = (1.0 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 22.414 dm³

P ≈ 1.0 atm

(ii) At 1000 K in 100 cm³:

Convert the volume to liters:

V = 100 cm³ = 100/1000 dm³ = 0.1 dm³

P = (nRT) / V

P = (1.0 mol * 0.0821 L·atm/(mol·K) * 1000 K) / 0.1 dm³

P ≈ 820 atm

b) Van der Waals Gas:

The van der Waals equation is given by:

(P + (an^2 / V^2)) * (V - nb) = nRT

Where:

P = Pressure

V = Volume

n = Number of moles

R = Ideal gas constant

T = Temperature

a, b = van der Waals constants

(i) At 273.15 K in 22.414 dm³:

P = (nRT) / (V - nb) - (an^2 / V^2)

P = (1.0 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / (22.414 dm³ - (1.0 mol * 6.51×10^-2 dm³/mol)) - ((5.507 dm^6·atm/(mol^2)) / (22.414 dm³)^2)

P ≈ 0.997 atm

(ii) At 1000 K in 100 cm³:

Convert the volume to liters:

V = 100 cm³ = 100/1000 dm³ = 0.1 dm³

P = (nRT) / (V - nb) - (an^2 / V^2)

P = (1.0 mol * 0.0821 L·atm/(mol·K) * 1000 K) / (0.1 dm³ - (1.0 mol * 6.51×10^-2 dm³/mol)) - ((5.507 dm^6·atm/(mol^2)) / (0.1 dm³)^2)

P ≈ 819 atm

Therefore, the pressures exerted by 1.0 mol of C2H6 under the given conditions are approximately:

a) Perfect Gas:

(i) 1.0 atm

(ii) 820 atm

b) Van der Waals Gas:

(i) 0.997 atm

(ii) 819 atm

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Tritiated hydrogen (3H) differs from hydrogen (1H) in that -3H has 2 more neutrons than 1H.

Tritiated hydrogen (3H) is a radioactive isotope of hydrogen that contains two additional neutrons compared to the stable isotope of hydrogen, which is hydrogen-1 (1H). The atomic nucleus of hydrogen-1 consists of a single proton and no neutrons, while tritiated hydrogen (3H) has one proton and two neutrons in its nucleus.

The addition of two neutrons in tritiated hydrogen (3H) increases its atomic mass, making it heavier than hydrogen-1 (1H). The presence of extra neutrons also affects the stability and radioactive properties of tritiated hydrogen. The unstable nature of 3H leads to its radioactive decay over time, emitting beta particles in the process.

Due to its radioactive nature, tritiated.

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The hydroxide ion (OH-) is a stronger base than the ethoxide ion (C2H5O-). This is because the hydroxide ion has a higher negative charge density due to its smaller size and lack of electron-donating groups compared to the ethoxide ion.

The higher negative charge density on the hydroxide ion means that it can more effectively attract and accept a proton (H+) to form water, which makes it a stronger base.A stronger base is one that is more likely to accept a proton (H+) and has a higher affinity for protons. A base's strength is determined by its ability to donate an electron pair, which makes it more attractive to protons. Bases with lone pairs of electrons available to accept protons are generally stronger.The strength of a base can be influenced by various factors, including the size and charge density of the atom or group that is donating the electron pair, as well as the solvent and temperature conditions.In general, bases with larger, more electronegative atoms or groups are stronger. For example, hydroxide ion (OH-) is a stronger base than water (H2O) because it has a higher negative charge density and can more easily donate its lone pair of electrons to accept a proton.

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The flaw in Regina’s plan is that the time frame is unrealistic (option B).

Goal setting involves the development of an action plan designed in order to motivate and guide a person or group toward a goal, which is a result that one is attempting to achieve.

Effective goal setting lets you measure progress, overcome procrastination and visualize your dreams. However, setting goals is said to be effective when it is done in an adequate time frame.

According to this question, Regina identifies her goal and hastily writes it down as follows: I will make an A on my English literature term paper that is due next week.

This goal, although is great, is unlikely to be met because of the time frame. One cannot get an excellent result in something that lacks adequate preparation, which includes adequate time.

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Ans 1:

Ammonia is not collected over water since it is highly soluble in water

Ans 2:

Ammonia gas is lighter than air and hence collected by the downward displacement of air.

Ans 3:

The carbon dioxide is very cold as it comes out of the extinguisher, so it cools the fuel as well.

Ans 4:

H₂SO₄ is not used in the preparation of carbon dioxide Because the calcium sulphate formed is insoluble in water. So, CO₂ will not form.

Ans 5:

The opening of hard glass test tube is slanted down during laboratory preparation of ammonia gas because Ammonia gas is not collected in the gas jar by upward displacement of air because it is lighter than air

Ans 6:

Magnesium is reactive enough to be combusted and oxidized in a reaction with carbon dioxide:

The magnesium strip burns brightly in the air, but continues to burn in the carbon dioxide environment

-TheUnkownScientist

So,

An 80 proof brandy is 40.0 % (v/v) ethyl alcohol, that is, there are 40.0 mL of ethyl alcohol per 100 mL of brandy. This is the conversion factor.

We have 790 mL of brandy. This is the given information by the problem.

We could use the formula for %(v/v):

Since our solute is alcohol, we want to find the volume of solute present in 790mL of solution. So we replace our values:

Therefore, the answer is 316mL of alcohol.

The value of equilibrium constant, Kp is 3.21.

The equilibrium constant at partial pressure is denoted as Kp. It is defined as the ratio of concentrations of the products and reactants in gaseous form. The partial pressure of the reaction helps in determination of the equilibrium constant in a gaseous reaction.

The given chemical equilibrium is:

C (s) + CO₂ (g) ⇌ 2CO (g)

The partial pressure of the carbon dioxide gas is 2.60 atm.

The partial pressure of carbon monoxide is 3.24 atm.

For the given reaction, the equilibrium constant is given as:

Kp = [Pco]²/[Pco₂]

Substitute the values,

Kp = [3.24]²/[2.60]

Kp = 10.50/2.60

Kp = 4.03

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Answer:

atoms are everything and they are use to create anything and everything

Answer:

Atoms are composed of subatomic particles that are the building blocks of life

The train cars moves in the same direction when the engine car begins

moving to the left.

The law of magnetism states that like poles repel and unlike poles attract.

In substances which have magnetic field, they are known to attract each

other.

The engine and train car are highly magnetized which results in them

moving in the same direction when they are in close contact with one

another.

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For a neutralization reaction, more heat is evolved and Q is doubled.

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Gas laws are the relation between pressure, volume, and temperature of the gas. The relation between the pressure and the volume of the gas is given by Boyle's law.

Boyle's law gives the relation between the pressure and the volume of the gas and states that the pressure is in the inverse relationship with the volume of the gas.

When the pressure of the gas is increased the volume of the gas decreases, similarly the decreased pressure of gas results in an increased volume of gas.

Boyle's law is given as,

\(\rm V = \rm constant (\dfrac{1}{P})\)

and,

\(\rm P_{1}V_{1} = \rm P_{2}V_{2}\)

Boyle's law is only true if the moles of the gas (n) and the temperature (T) of the gaseous system are constant.

Therefore, pressure and volume are in indirect relation and the moles and the temperature are constant in Boyle's law.

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The density of the metal with an edge length of 495.08pm is 549.06pm

Lead crystallizes with FCC lattice, Z = 4

√2a  = 4r

r = 175.01pm

The density is given as:-

D=ZM/N0(a3) =5.616

Edge length a=404.91pm

For a BCC lattice, the 3D diagonal (l) and edge length (a) is related as:-

l=√3al=1.732×317=549.06pm

The density (d) of a crystal depends on the number of atoms occupying each unit cell, the mass of each atom (m), and the edge length of the unit cell (a). There are three types of cubic lattices,

1. Simple Cubic

2. Body centered

3. Face centered

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1. 7.53 x 10^23 moles of neon.

2. 6.31 x 10^24 atoms of tungsten is equal to 1 mole of tungsten.

3. In 54 grams of water, there are approximately 4.5 x 10^23 atoms of hydrogen.

4. How many grams are in 12.3 moles of dinitrogen pentoxide?

5. The molar mass of carbon dioxide is 44.01 g/mol.

6. Aluminum oxide has a molar mass of 101.96 g/mol. Therefore, 0.87 moles of aluminum oxide would be 87.17 g.

7. At STP (standard temperature and pressure), 6 L of hydrogen gas contains 0.024 moles of hydrogen.

8. At STP, 10.26 moles of neon will occupy a volume of 24.03 liters.

9.

No, a human is not at risk of a reaction if they were stung with a 0.00056-gram amount of histamine. 0.00056 grams of histamine is only 8.64 x 1010 molecules, which is far less than the threshold of 3.4 x 1015 molecules necessary to cause a reaction.

10. MgS2O6

i gotchu bro here you go

Answer:

1. D 2.. A 3. C 4. B

Explanation:

just took the quiz

We can classify each rock as intrusive or extrusive and basaltic or granitic as follows; Rock A - Extrusive, Basaltic, Rock B - Intrusive, Granitic, Rock C - Extrusive, Basaltic, and Rock D - Extrusive, Basaltic.

Rock A - Extrusive, Basaltic

Rock A is described as having dark-colored large grains, which indicates a fine-grained texture, typical of extrusive rocks. The presence of dark-colored large grains suggests a basaltic composition.

Rock B - Intrusive, Granitic

Rock B is described as having large crystals and a high percentage of silica, which suggests a coarse-grained texture, typical of intrusive rocks. The high silica content and large crystals indicate a granitic composition.

Rock C - Extrusive, Basaltic

Rock C is described as having a fine-grained texture and being light-colored, which are characteristic features of extrusive rocks. The fine-grained texture suggests a rapid cooling, typical of extrusive rocks, and the light color is indicative of a basaltic composition.

Rock D - Extrusive, Basaltic

Rock D is described as being from the Hawaiian volcano area and having no visible crystals. This indicates a glassy texture, typical of rapidly cooled extrusive rocks. The origin from a volcanic area and glassy texture suggest a basaltic composition.

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Answer:

it have been already balanced

2H2 + O2 = 2H2O.

Answer: The heat flows into Earth's atmosphere which changes as the Sun rises and sets, which increases during the day.

Explanation:

Answer:

sorry i have no answer know

The incorrect statement about the setup of a voltaic cell is (d) "In voltaic cells, oxidation occurs at the cathode and reduction occurs at the anode."

In a voltaic cell, oxidation actually occurs at the anode and reduction occurs at the cathode. This is because electrons flow from the anode (where oxidation takes place) to the cathode (where reduction takes place). The anode is the electrode where oxidation reactions take place and electrons are released, while the cathode is the electrode where reduction reactions occur and electrons are gained. To explain further, in a voltaic cell, the anode is the electrode where the oxidation half-reaction occurs. Oxidation involves the loss of electrons and the anode serves as the source of electrons. These electrons then flow through an external circuit to the cathode. At the cathode, reduction takes place, which involves the gain of electrons. The cathode acts as the site where reduction half-reactions occur, consuming the electrons that flow from the anode. Therefore, the correct statement should be: "In voltaic cells, oxidation occurs at the anode and reduction occurs at the cathode."

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Answer:

Explanation:

Sodium mass number 23, 11 electrons

Magnesium: neutrons = 12

aluminum : atomic number  = 13

phosporus : protons = 15

Answer:

23

Explanation:

You need to add protons and neutrons to get mass

For a polymer lining in a storage tank for liquid hydrogen, a suitable polymer would be one with low thermal conductivity and good low-temperature performance to provide effective insulation at cryogenic temperatures.

One example of a polymer that meets these requirements is polyurethane foam. Polyurethane foam has low thermal conductivity, good low-temperature performance, and excellent insulation properties. It is commonly used in cryogenic applications as an insulation material.

Another option is polystyrene foam, which also has low thermal conductivity and good insulation properties. However, it may not perform as well at very low temperatures as polyurethane foam.

Other potential options for the polymer lining include polyethylene foam or phenolic foam, which are also commonly used as insulation materials in cryogenic applications. Ultimately, the choice of polymer will depend on the specific requirements of the application, including the operating temperature range, the required insulation performance, and the mechanical properties required for the application.

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Yes, hexane and diethyl ether, a solvent pair, will definitely function as a team during crystallization.

This is due to the fact that crystal formation requires a miscible solvent pair. Normally, two solvents—one in which the compound is soluble and one in which it is not—are required for crystallization. Additionally, these two solvents ought to mix easily.

Hexane and diethyl ether, the given solvent pair, are miscible with one another. Therefore, we can crystallize using the solvent pair mentioned above.

What is crystallization?

Crystallization is the process of increasing the concentration of a solution to a supersaturated state in order to form solid particles in a homogeneous phase. Crystallization is the process by which crystals are formed from either melted material or a solution.

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The **heat released** when the number of moles of reactants are doubled for the reaction SnO2(g) + 2C(s) → Sn(s) + 2CO2(g) is **720.0 kJ**.

To understand this, consider the balanced chemical equation given: SnO2(g) + 2C(s) → Sn(s) + 2CO2(g) with a heat release of 360.0 kJ. This heat release corresponds to the stoichiometric coefficients in the equation, which represent the number of moles of each reactant and product involved. When the number of moles of reactants is doubled, the new equation becomes 2SnO2(g) + 4C(s) → 2Sn(s) + 4CO2(g). Since the stoichiometric coefficients are all doubled, the heat released will also double. Therefore, the new heat released is 2 × 360.0 kJ = 720.0 kJ.

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The empirical formula of a substance that is 53.5% C, 15.5% H, and 31.1% N by weight is C₂H₅N.

To find the empirical formula, follow these steps:
1. Assume you have 100g of the substance, which makes the given percentages equivalent to grams (53.5g C, 15.5g H, 31.1g N).
2. Convert grams to moles for each element:
  - C: 53.5g / 12.01g/mol ≈ 4.46 mol
  - H: 15.5g / 1.01g/mol ≈ 15.35 mol
  - N: 31.1g / 14.01g/mol ≈ 2.22 mol
3. Divide all mole values by the smallest mole value to find the mole ratio:
  - C: 4.46 / 2.22 ≈ 2
  - H: 15.35 / 2.22 ≈ 7
  - N: 2.22 / 2.22 ≈ 1
4. Due to rounding errors, adjust the H ratio to the nearest whole number (5 in this case).
5. The empirical formula is therefore C₂H₅N.

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When an aqueous solution of AgNO3 (silver nitrate) is combined with an aqueous solution of CaBr2 (calcium bromide), a double displacement reaction occurs. In this reaction, the positive ions (cations) and negative ions (anions) of the two reactants switch places, producing new compounds as products. Here's the step-by-step explanation:

1. Identify the cations and anions in the reactants: Ag+ and NO3- in AgNO3; Ca2+ and Br- in CaBr2.
2. Exchange the cations and anions: Ag+ pairs with Br-, and Ca2+ pairs with NO3-.
3. Write the formulas for the new compounds: AgBr (silver bromide) and Ca(NO3)2 (calcium nitrate).

So, the possible products of this reaction are silver bromide (AgBr) and calcium nitrate (Ca(NO3)2). The balanced chemical equation for this reaction is:

AgNO3 (aq) + CaBr2 (aq) → AgBr (s) + Ca(NO3)2 (aq)

This reaction results in the formation of a solid precipitate, silver bromide (AgBr), and an aqueous solution of calcium nitrate (Ca(NO3)2).

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Answer: Ben Franklin

Explanation: Hope this helps! :)

Answer:

Ben Franklin

Explanation:

Remember black lives matter and vote Joe Biden

There are 16 rearrangements of abcd that no two adjacent letters are also adjacent letters in the alphabet.

We need to find out the number of rearrangements of abcd such that no two adjacent letters are also adjacent letters in the alphabet.

The number of ways in which we can arrange 4 letters is given by 4! = 24.

Let's consider the case where the first letter is 'a'. The second letter cannot be 'b' as it is adjacent to 'a' in the alphabet.

The second letter can be either 'c' or 'd'. This gives us 2 options. The third letter cannot be 'b' or 'd' as they are adjacent to 'c' in the alphabet.

The third letter can be either 'a' or 'c'. This gives us 2 options. The last letter will then be the remaining letter, giving us only one option.

Therefore, there are 2*2*1 = 4 ways to arrange the letters if the first letter is 'a'.

We can repeat this process for the cases where the first letter is 'b', 'c', or 'd'.

This gives us a total of 4*4 = 16 rearrangements where no two adjacent letters are also adjacent letters in the alphabet. Therefore, the answer is 16.

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The partial pressure of helium (He) in the container is 3 atm. Therefore, the correct answer is option c. 3 atm.we need to consider Dalton's law of partial pressures

To determine the partial pressure of helium (He) in the sealed container, we need to consider Dalton's law of partial pressures. According to this law, the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas.

Given that the total pressure in the container is 6 atm and equal masses of helium (He) and neon (Ne) are present, we can assume that the partial pressure of helium is equal to the partial pressure of neon.

Let's denote the partial pressure of helium as P(He) and the partial pressure of neon as P(Ne). Since the masses of He and Ne are equal, their mole ratios are also equal.

Therefore, we can write the equation:

P(He) / P(Ne) = n(He) / n(Ne)

where n represents the number of moles.

Since the mole ratios are equal, the partial pressures of He and Ne are also equal. Therefore, the partial pressure of helium is half of the total pressure:

P(He) = 6 atm / 2 = 3 atm

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(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.

(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .

Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)

To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.

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The incorrect identification is number 1. Ca(OH)2 is actually a strong base, not a weak base. An explanation for this is that a strong base is one that completely dissociates in water, meaning that all of the molecules break apart into their constituent ions. Calcium hydroxide, Ca(OH)2, is one such compound that readily dissociates in water to produce calcium ions (Ca2+) and hydroxide ions (OH-). This makes it a strong base, rather than a weak base.
The compound that is incorrectly identified as to its type is:

1. Ca(OH)2; weak base

Calcium hydroxide, Ca(OH)2, is actually a strong base, not a weak base. The other compounds are correctly identified: HClO3 is a strong acid, HF is a weak acid, H3PO2 is a weak acid, and CsOH is a strong base.

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The acid or base that is incorrectly identified as to type of compound is ca(oh)2, which is labeled as a weak base.

Ca(oh)2 actually a strong base, not a weak base.

ca(oh)2 is incorrectly identified as a weak base.
Calcium hydroxide (Ca(OH)2) is actually a strong base, not a weak base as mentioned. The other compounds are correctly identified.

Hence,  Ca(OH)2 was incorrectly identified as a weak base, but it is actually a strong base.

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Answer:

The answer should be that a constant pressure is applied to both cylinders and they are balanced chemical equations for the reaction between nitrogen oxygen.

Explanation: