Answer: The base is going to be 6 inches.
Step-by-step explanation:
So to find the area of a triangle we need to know the formula which is A= 1/2bh (A= one half times base times height) So, all we need to do is multiply the area by 2
32*2=72 Then to find the missing length, we divided the area by 12 which is 6.
Find the area of the figure below.
A. 288.62
B. 266.22
C. 186.66
D. 236.6
Answer:
A
Step-by-step explanation:
hope this helps
From the above mentioned problem, suppose that Noname has 23,000 Dram chips in invetory. It anticipates receiving a lot of 3,000 chips in week 3 from another firm that has gone out of business. At the current time, Noname purchases the chips from two vendors, A and B. A sells the chips for less, but will not fill an order exceeding 10,000 chips per week.
With 23,000 Dram chips in inventory and a lot of 3,000 chips anticipated in week 3, Noname's total inventory will be 26,000.
No name purchases chips from two vendors, A and B, with A offering lower prices but with a limit of 10,000 chips per week. No name could potentially purchase 10,000 chips from vendor A and 13,000 chips from vendor B to meet its inventory needs. However, it's important to consider the cost of purchasing from both vendors and weigh it against the savings from vendor A's lower prices. Noname should also consider the reliability of both vendors to ensure a consistent supply of chips.
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SOMEBODY PLEASE HELP ME I WILL MARK BRAINLIEST
Answer:x=52
Step-by-step explanation:as SRQ is a right triangle,
<SQR=180°-(90+34)°
=56°
again, < SQR+<SQP=180°
< SQP=124
x+72°=124
x=52°
Answer:
x=52
Step-by-step explanation:
the answer is x=52.
Least common denominator of 6 and 9
Answer:
18 because 6 x 3 = 18 and 9 x 2 =18
Step-by-step explanation:
Write an expression to represent:
4 times the difference of x and 2.
Answer:
4 times the difference of x and 2 is 4(x-2)
the variance inflation factor (vif) is another measure that can detect a high correlation between three or more predictor variables even if no pair of predictor variables has a particularly high correlation. what is the smallest possible value of vif? (absence of multicollinearity).
Variance inflation factor can have a value as low as one (absence of multicollinearity). A VIF number greater than 5 or 10 generally denotes collinearity that is problematic.
The variance of bj is not inflated at all if the VIF is 1, which indicates that there is no association between the jth predictor and the other predictor variables.
VIF equal to 1 signifies that there is no correlation between the variables. A VIF of 1 to 5 indicates a moderate correlation between the variables. Variables are highly linked when the VIF is greater than correlated2.
VIF = 1.0 if all independent variables are orthogonal to one another. VIF = infinity if there is perfect correlation.
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There are 8 red, 4 green, and 6 blue point on a circle. All the points are distinct. Find the number of triangles with vertices of three different colors.
To find the number of triangles with vertices of three different colors, we need to consider the combinations of colors we can choose from the given set of points.
We have 8 red points, 4 green points, and 6 blue points. To form a triangle with vertices of three different colors, we need to choose one point from each color group.
First, let's choose one red point. We have 8 options for this.
Next, let's choose one green point. We have 4 options for this.
Finally, let's choose one blue point. We have 6 options for this.
To determine the total number of triangles, we need to multiply the number of options for each color:
Total number of triangles = Number of options for red points × Number of options for green points × Number of options for blue points
= 8 × 4 × 6
= 192
Therefore, there are 192 triangles with vertices of three different colors.
It's worth noting that the order in which we choose the points does not matter because we are counting the number of distinct triangles. So, we are not considering permutations but rather combinations of colors.
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what is the third step in scientific investigation ?
Answer:
Cleaning
Step-by-step explanation:
how many strings of length 5 are there over the alphabet {0, 1, 2}?
The length of the string is 5 and the alphabet is {0, 1, 2}.Therefore, the number of strings of length 5 that can be formed over the given alphabet is:$$3^5 = 243$$ Therefore, there are 243 strings of length 5 over the alphabet {0, 1, 2}.
To calculate the number of strings of length 5 over the alphabet {0, 1, 2}, we need to determine the number of choices for each position in the string. Since each position can be filled with one of three possible characters (0, 1, or 2), we have three choices for each position.
Therefore, the total number of strings of length 5 can be calculated as:
Number of strings = Number of choices for position 1 × Number of choices for position 2 × Number of choices for position 3 × Number of choices for position 4 × Number of choices for position 5
Number of strings = 3 × 3 × 3 × 3 × 3 = 3^5 = 243
So, there are 243 strings of length 5 over the alphabet {0, 1, 2}.
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The information given in question is that the length of the string is 5.
Alphabet {0,1,2}
Therefore, there are 243 strings of length 5 over the alphabet {0, 1, 2}.
To find the number of strings of length 5 over the alphabet {0, 1, 2}, we need to consider the number of choices we have for each position in the string.
There are three choices (0, 1, or 2) for each position, and since we have five positions, the total number of strings of length 5 is given by:
\($$3^5 = \boxed{243}$$\)
Therefore, there are 243 strings of length 5 over the alphabet {0, 1, 2}.
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statistical power is a measure of the ability to reject the null hypothesis when:
Statistical power is a measure of the ability to reject the null hypothesis when it is false. It represents the probability of correctly identifying a true effect or relationship in a statistical hypothesis test.
A high statistical power indicates a greater likelihood of detecting a significant result if the null hypothesis is indeed incorrect. The power of a statistical test depends on several factors, including the sample size, the effect size (the magnitude of the true effect or difference), the chosen significance level (often denoted as α), and the variability or noise in the data. Increasing the sample size or effect size generally increases the statistical power, while a lower significance level or higher variability decreases it.
Power analysis is commonly used to determine an appropriate sample size for a study, ensuring that it is adequately powered to detect the desired effect. A higher power is desirable as it reduces the chances of a Type II error (failing to reject the null hypothesis when it is false) and increases the chances of correctly detecting real effects or relationships.
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Review the proof.
A 2-column table with 8 rows. Column 1 is labeled Step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine (2 x) = 1 minus 2 sine squared (x), let 2 x = theta, then x = StartFraction theta Over 2 EndFraction, cosine (theta) = 1 minus 2 sine squared (StartFraction theta Over 2 EndFraction), negative 1 + cosine (theta) = negative 2 sine squared (StartFraction theta Over 2 EndFraction), 1 + cosine (theta) = 2 sine squared (StartFraction theta Over 2 EndFraction), StartFraction 1 minus cosine (theta) Over 2 EndFraction = sine squared (StartFraction theta Over 2 EndFraction), sine (StartFraction theta Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 minus cosine (theta) Over 2 EndFraction EndRoot.
Which step contains an error?
Answer:
Half Angle & X
Step-by-step explanation:
edge 2022
The step contains an error is Half Angle & X.
We have given that,
A 2-column table with 8 rows. Column 1 is labeled Step with entries 1, 2, 3, 4, 5, 6, 7, and 8.
What is the expression?An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
Column 2 is labeled Statement with entries cosine (2 x) = 1 minus 2 sine squared (x), let 2 x = theta, then x = StartFraction theta Over 2 EndFraction, cosine (theta) = 1 minus 2 sine squared (StartFraction theta Over 2 EndFraction), negative 1 + cosine (theta) = negative 2 sine squared (StartFraction theta Over 2 EndFraction), 1 + cosine (theta) = 2 sine squared (StartFraction theta Over 2 EndFraction), StartFraction 1 minus cosine (theta) Over 2 EndFraction = sine squared (StartFraction theta Over 2 EndFraction), sine (StartFraction theta Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 minus cosine (theta) Over 2 EndFraction EndRoot.
We have determined the step contains an error.
Half Angle & X.
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.Use any basic integration formula or formulas to find the indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.)
x − 1/3x dx
the required indefinite integral is x³/3 - x²/6 + C.
Given: x − 1/3x dx We need to find the indefinite integral. To integrate the above function, we can use the following basic integration formulas.
∫x dx = 1/2x² + C∫k dx
kx + C∫xⁿ dx = xⁿ⁺¹ / (n + 1) + C,
where n ≠ -1The given function is of the form x - 1/3x. We can write it as (3x² - x)/3.Now,
we can integrate (3x² - x)/3 using the basic integration formula.
∫(3x² - x)/3 dx= 3/3 ∫x² dx - 1/3 ∫x dx
∫x² dx - 1/3 ∫x dx= x³/3 - x²/6 + C On substituting the value of x, we get
∫(x - 1/3x) dx= ∫(3x² - x)/3 dx
x³/3 - x²/6 + C
Hence, the required indefinite integral is x³/3 - x²/6 + C.
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There is a 0 9988 probability that a randomly selected 33-year-old male lives through the year. A life insurance company charges $195 for insuring that the male will live through the year. If the male does not survive the year, the policy pays out $90,000 as a death benefit Complete parts (a) through (c) below. a. From the perspective of the 33-year-old male, what are the monetary values corresponding to the two events of surviving the year and not surviving? The value corresponding to surviving the year is $ The value corresponding to not surviving the year is (Type integers or decimals Do not round) b. If the 33-yem-old male purchases the policy, what is his expected value? The expected value is (Round to the nearest cent as needed) c. Can the insurance company expect to make a profit from many such policies? Why? because the insurance company expects to make an average profit of $on every 33-year-old male it insures for 1 year (Round to the nomest cent as needed)
a. The value corresponding to surviving the year is $0, and the value corresponding to not surviving the year is -$90,000.
b. The expected value for the 33-year-old male purchasing the policy is -$579.06.
c. Yes, the insurance company can expect to make a profit from many such policies because the expected profit per 33-year-old male insured for 1 year is $408.06.
a. The monetary value corresponding to surviving the year is $0 because the individual would not receive any payout from the insurance policy if he survives. The monetary value corresponding to not surviving the year is -$90,000 because in the event of the individual's death, the policy pays out a death benefit of $90,000.
b. To calculate the expected value for the 33-year-old male purchasing the policy, we need to multiply the probability of each event by its corresponding monetary value and sum them up. The probability of surviving the year is 0.9988, and the value corresponding to surviving is $0. The probability of not surviving the year is (1 - 0.9988) = 0.0012, and the value corresponding to not surviving is -$90,000.
Expected value = (Probability of surviving * Value of surviving) + (Probability of not surviving * Value of not surviving)
Expected value = (0.9988 * $0) + (0.0012 * -$90,000)
Expected value = -$108 + -$471.06
Expected value = -$579.06 (rounded to the nearest cent)
c. The insurance company can expect to make a profit from many such policies because the expected value for the 33-year-old male purchasing the policy is negative (-$579.06). This means, on average, the insurance company would pay out $579.06 more in claims than it collects in premiums for each 33-year-old male insured for 1 year. Therefore, the insurance company expects to make an average profit of $579.06 on every 33-year-old male it insures for 1 year.
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A zoo charges a rental fee plus $2 per hour for strollers. The total cost of 5 is $13. Assume the relationship is linear. Find and intercept the rate of change and initial value
The y-intercept is 3.
The rate of change is 2 and the initial value 5.
What is a linear equation?Equations whose variables have a power of one are called linear equations. One example with one variable is where ax+b = 0, where a and b are real values and x is the variable.
Given:
A zoo charges a rental fee plus $2 per hour for strollers.
The total cost of 5 is $13.
Assume the relationship is linear.
Let x be the number of hours.
And y be the total cost.
So,
y = 2x + m, where m is the rental fee.
Here, x = 5 and y = 13
So,
13 = 10 + m, where m is the rental fee.
m = 3
So, the equation is y = 2x + 3.
When x = 1,
y = 5.
Here, 3 is the y-intercept and 2 is the rate of change.
Hence, 3 is the y-intercept and 2 is the rate of change.
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IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.
Out of a randomly selected 2550 people from the population, how many of them
would have an IQ higher than 86, to the nearest whole number?
Therefore, about 83 percent of the population would have an IQ score higher than 86.
IQ scores are typically distributed in a bell-shaped or normal distribution. A normal distribution is a continuous probability distribution in which a random variable has an equal probability of taking any value between its minimum and maximum values.IQ scores, like many other phenomena, are generally distributed. The average IQ score for the population is 100, and the standard deviation is 15. This means that the majority of people score between 85 and 115 on IQ tests. However, we may use standard deviation to calculate the proportion of individuals that have an IQ above or below a particular value.The mean IQ score is 100, so any IQ score higher than 100 is considered above average, whereas an IQ score of less than 100 is considered below average. We can utilize the standard deviation to calculate the proportion of individuals who score above or below the mean. Since the standard deviation is 15, we can convert the IQ score of 86 to a z-score to determine how far above the mean it is.Z = (X - μ) / σ.Where,Z = the z-scoreX = the raw scoreμ = the meanσ = the standard deviationIf we put the values in the above formula we get,Z = (86 - 100) / 15Z = -0.93.Therefore, the z-score for an IQ of 86 is -0.93. We can look at the z-score chart to see what proportion of individuals have a z-score less than -0.93.According to the chart, around 17% of people have a z-score less than -0.93. As a result, around 17% of people would have an IQ lower than 86. As a result, the percentage of people who would have an IQ higher than 86 is 100% - 17% = 83% or around 83 people out of 100.For such more question on phenomena
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The sum of four consecutive integers is 390. Find the integers (Please show your work)
Answer:
The integers are 96, 97, 98, and 99
Step-by-step explanation:
first integer = x
second integer = x+1
third integer = x+2
fourth integer = x+3
(that what consecutive means, like 4, 5, 6, 7 are just adding 1 more each time
The sum (add them all up) is (=) 390 so
x+(x+1)+(x+2)+(x+3) = 390
4x+6=390
4x+6-6=390-6
4x=384
4x/4=384/4
x=96
x+1=97
x+2=98
x+3=99
The integers are 96, 97, 98, and 99
how do I do this question?
Answer:
x = (y +2)/3
Step-by-step explanation:
y= 3x-2
y+2=3x
x=(y +2)/3
16. diagonal the perimeter of a rectangle is 32 feet. the length is three times as long as the width. find the length of the diagonal. round to the nearest tenth.
The length of the diagonal is 12.6 feet.
"Information available from the question"
The perimeter of a rectangle is 32 feet.
The length is three times as long as the width.
We have to find the length of the diagonal.
Let w = width
then
3w = length.
Because we know the perimeter:
Perimeter of the rectangle is : 2(l + w)
32 = 2(w + 3w)
32 = 2(4w)
16 = 4w
4 feet = w (width)
Length:
3w = 3(4) = 12 feet
Diagonal, we use the Pythagorean theorem:
Let d = diagonal
then,
\(d^2 = 4^2 + 12^2\)
\(d^2\) = 16 + 144
\(d^2\) = 160
d = 12.6 feet
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What is the z-score of x = -2, if it is 2.78 standard deviations to the left of the mean?A. Less than 0B. 1.6 – 2.5C. 0 – 0.5D. More than 2.5E. 0.6 – 1.5
The z-score of x = -2, if it is 2.78 standard deviations to the left of the mean, is D. More than 2.5.
A z-score is a measure of how many standard deviations a data point is from the mean. In this case, the data point x = -2 is 2.78 standard deviations to the left of the mean. This means that the z-score is -2.78. Since the absolute value of -2.78 is greater than 2.5, the correct answer is D. More than 2.5.
Here's how to calculate the z-score:
z = (x - μ) / σ
where z is the z-score, x is the data point, μ is the mean, and σ is the standard deviation.
In this case, we are given that x = -2 and that it is 2.78 standard deviations to the left of the mean. This means that:
z = -2.78
So the z-score is -2.78, which is greater than 2.5 in absolute value. Therefore, the correct answer is D. More than 2.5.
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a disease is caused by homozygosity for the g allele (g is the corresponding wild-type allele). however, the penetrance of the disease is 75%. two individuals known to be heterozygotes have a child. what is the probability that the child exhibits the disease?
The probability that the child exhibits the disease is 18.75%
To determine the probability that the child exhibits the disease, we need to first find the probability of the child inheriting the disease-causing genotype and then multiply it by the penetrance of the disease.
Step 1: Determine the genotype probabilities
Since both parents are heterozygotes, their genotypes are Gg. Using a Punnett square, we can determine the probabilities of the child's possible genotypes:
Parent 1: G | g
Parent 2: G | GG | Gg
g | Gg | gg
The child's possible genotypes and their probabilities are:
- GG: 1/4 (25%)
- Gg: 1/2 (50%)
- gg: 1/4 (25%)
Step 2: Determine the probability of the child exhibiting the disease
The disease is caused by homozygosity for the g allele, meaning the child must have the gg genotype to potentially have the disease. The probability of the child inheriting the gg genotype is 1/4 (25%).
Step 3: Factor in the penetrance of the disease
Since the penetrance of the disease is 75%, this means that 75% of individuals with the gg genotype will exhibit the disease. To find the probability of the child exhibiting the disease, multiply the probability of inheriting the gg genotype (1/4) by the penetrance (75%):
(1/4) * (75%) = 0.25 * 0.75 = 0.1875
Therefore, the probability that the child exhibits the disease is 18.75%.
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Guys PLZ I need ur helpppppp
Answer:
1. 12
2. 6
3. 8
4. 20
5. 4
Step-by-step explanation:
1. 60/5= 12
The sky diver fall 12 feet per second.
2. 42/7=6
The pump will move 6 gallons per minute.
3. 48/6=8
He scored 8 points every game.
4. 60/3=20
20 miles were driven every gallon.
5. 12/3=4
She walked 4 miles every 1 hour.
information retrieval tools include database management systems, reporting tools, and ________________ tools.
Information retrieval tools include database management systems, reporting tools, and search engine tools.
Search tools employ various algorithms and techniques to index and search through vast amounts of data. They create indexes or catalogs of the content, allowing users to search for specific keywords or criteria. These tools utilize techniques like keyword matching, relevance ranking, and advanced search operators to refine search results and provide relevant information to users.
Indexing tools, on the other hand, focus on creating structured representations of data for efficient retrieval. They organize and categorize data based on predefined criteria, such as document types, dates, or categories. These tools help users navigate and explore information repositories more easily.
Overall, search and indexing tools are essential components of information retrieval systems. They enhance the accessibility and usability of data by enabling users to locate, retrieve, and analyze information quickly and accurately.
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state the dimensions of the matrix. identify the indicated element
Answer:
D; 2 * 3; -4
Step-by-step explanation:
The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column
In a row, we have 2 elements, in a column , we have 3 elements
So the matrix is of 2 * 3 dimension
a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4
In the major course requirement in a math department, a student needs to choose one each from algebra, analysis, statistics, and geometry. There are 4 algebra courses, 3 analysis courses, 5 statistics courses, and 2 geometry courses available for major requirement. How many different ways can a student choose major requirement courses from these 4 areas
There are 120 different ways that a student can choose major requirement courses from these four areas.
In order to solve this problem, we need to use the concept of combinations. A combination is a selection of items from a set, without regard to the order in which they are chosen. The formula for the number of combinations of n objects taken r at a time is:
C(n,r) = n! / (r! * (n-r)!)
where n! means n factorial, which is the product of all positive integers up to n. For example, 5! = 5 * 4 * 3 * 2 * 1 = 120.
To solve this problem, we need to choose one course from each of the four areas: algebra, analysis, statistics, and geometry. The number of choices in each area are:
4 algebra courses
3 analysis courses
5 statistics courses
2 geometry courses
To find the total number of ways to choose one course from each area, we can use the multiplication rule of counting. This states that if there are n1 ways to do the first task, n2 ways to do the second task, and so on up to nk ways to do the kth task, then there are n1 * n2 * ... * nk ways to do all k tasks together.
In this case, there are 4 ways to choose an algebra course, 3 ways to choose an analysis course, 5 ways to choose a statistics course, and 2 ways to choose a geometry course. Therefore, the total number of ways to choose one course from each area is:
4 * 3 * 5 * 2 = 120
Thus, there are 120 different ways that a student can choose major requirement courses from these four areas.
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Suzanne has purchased a car with a list price of $23,860. She traded in her previous car, which was a Dodge in good condition, and financed the rest of the cost for five years at a rate of 11. 62%, compounded monthly. The dealer gave her 85% of the listed trade-in price for her car. She was also responsible for 8. 11% sales tax, a $1,695 vehicle registration fee, and a $228 documentation fee. If Suzanne makes a monthly payment of $455. 96, which of the following was her original car?.
Given:
Suzanne has purchased a car with a list price of$23,860.
She traded in her previous car, which was a Dodge in good condition, and financed the rest of the cost for five years at a rate of 11.62, compounded monthly. The dealer gave her 85 of the listed trade-in price for her car. She was also responsible for 8.11 sales tax, a $1695 vehicle registration fee, and a $228 documentation fee. If Suzanne makes a monthly payment of $455.96, then we need to calculate the original cost of the car.
Method of Solution:
We need to apply the following formula to get the original cost of the car:
\($$A=P(1+\frac{r}{n})^{nt}$$\)
Where, A is the future value, P is the principal amount, r is the rate of interest, t is the time, n is the number of times the interest is compounded per year.
Using the given data,Let the original cost of the car be ‘P’.
Then, she financed the rest of the cost of the car after the trade-in,
So,
the amount financed = $P − Trade-in value
Rate of interest = 11.62% compounded monthly
= 0.1162/12 = 0.00968 per month
Time period = 5 years
Number of times interest is compounded per year = 12
Sales tax = 8.11%
Registration fee = $1,695
Documentation fee = $228
Trade-in value = 85% of the listed trade-in price for her car = 0.85LTP
Now, we have to calculate the value of ‘P’ as per the formula stated above
.Step-by-step Solution:
Amount financed = $P − Trade-in value principal
amount = $PInterest rate
= 0.1162/12 per monthTime
= 5 yearsNumber of times interest is compounded per year
= 12Sales tax
= 8.11%
Registration fee = $1,695
Documentation fee = $228
Trade-in value = 85% of the listed trade-in price for her car = 0.85LTP
Now, we have, Monthly payment = $455.96
Using the formula,
Future value (A) = $455.96*60
= $27,357.6.$A
\(= P(1 + $\frac{r}{n}$)$^{nt}$\)
∴ $27,357.6
=\((P – 0.85 LTP)(1 + \frac{0.1162}{12})^{12*5}$∴ $27,357.6\)
= \((P – 0.85LTP)(1.01082)^{60}$\)
Now, we can add the sales tax, registration fee, and documentation fee to get the value of ‘P
.∴ P – 0.85LTP
\(= $\frac{27,357.6}{1.01082^{60}}$ + 0.0811P + 1,695 + 228\)
∴\(P – 0.7225 LTP = 23,860.01 + 0.0811P + 1,695 + 228\)
∴ \(P – 0.0811P + 0.7225 LTP = 23,860.01 + 1,695 + 228\)
∴ \(0.9189 P = 25,783.01 + 0.7225 LTP --- (i)\)
Now, let's calculate the monthly payment if LTP
(listed trade-in price) = $16,000.
First, let’s calculate the amount Suzanne paid for the car:
Amount financed = $P − Trade-in value amount financed
= $P − 0.85LTP
Amount financed = P − 0.85(16,000)
Amount financed = P − 13,600
Now, we can add the sales tax, registration fee, and documentation fee to get the amount financed.
∴ Amount financed = P – 13,600 + 0.0811P + 1,695 + 228
∴ Amount financed = 1.0811 P – 11,677 --- (ii)
Now, we can calculate the monthly payment:
\(Monthly payment = $\frac{A*r}{n*(1 + \frac{r}{n})^{nt}}$\)
\($$A=P(1+\frac{r}{n})^{nt}$$\\\\Future value (A) = $455.96*60= $27,357.6.$A = P(1 + $\frac{r}{n}$)$^{nt}$∴ $27,357.6 = (P – 0.85 LTP)(1 + \frac{0.1162}{12})^{12*5}$∴ $27,357.6 = (P – 0.85LTP)(1.01082)^{60}$\\\\∴ P – 0.85LTP = $\frac{27,357.6}{1.01082^{60}}$ + 0.0811P + 1,695 + 228∴ P – 0.7225 LTP = 23,860.01 + 0.0811P + 1,695 + 228∴ P – 0.0811P + 0.7225 LTP = 23,860.01 + 1,695 + 228∴ 0.9189 P = 25,783.01 + 0.7225 LTP --- (i)\\\\Monthly payment = $\frac{A*r}{n*(1 + \frac{r}{n})^{nt}}$\\\\\)
therefore
$ Monthly payment = 455.96
Using a graphing calculator, we can find that P = $22,328.44
Therefore, the original cost of the car was $22,328.44. Therefore, option (a) is the correct answer.
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can someone pls help
The required area of the parallelogram and pentagon is 91 unit² and 75 unit².
What is surface area?The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.
A parallelogram in is shown in figure 1 with the dimensions height = 7 and base = 13,
Area of the parallelogram = 13 × 7 = 91 unit²
Now,
A pentagon is shown in figure 2,
Area of the pentagon = 5 [1/2 × height × side]
= 5 [1/2 × 5 × 6]
= 75 suqare units.
Thus, the required area of the parallelogram and pentagon is 91 unit² and 75 unit².
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Solve each equation. 4 y-6=2 y+8
The solution of the linear equation in one variable 4y - 6 = 2y + 8 is at y = 7.
According to the given question.
We have a linear equation in one variable.
4y - 6 = 2y + 8
As we know that, the linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers, and x is a variable and has only one solution.
Thereofre, the solution of the linear equation in one variable 4y - 6 = 2y + 8 is given by
4y - 6 = 2y + 8
⇒ 4y - 2y - 6 = 8 ( subtracting 2y from both the sides)
⇒ 2y -6 -8 = 0 (subtracting 8 from both the sides)
⇒ 2y - 14 = 0
⇒ 2y = 14
⇒ y = 14/2
⇒ y = 7
Hence, the solution of the linear equation in one variable 4y - 6 = 2y + 8 is at y = 7.
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Solve negative one sixth times the quantity 3 minus 15 times the quantity one third squared end quantity end quantity.
two thirds
18 over 54
negative two ninths
negative two and 42 over 54
The value of the expression given as negative one sixth times the quantity 3 minus 15 times the quantity one third squared is 2/9
How to solve the expression?The expression is given as:
negative one sixth times the quantity 3 minus 15 times the quantity one third squared
Rewrite the above expression properly as
-1/6(3 - 15) * (1/3)^2
Evaluate the square in the above expression
-1/6(3 - 15) * 1/9
Evaluate the difference in the above expression
-1/6 * - 12 * 1/9
Evaluate the product in the above expression
2/9
Hence, the value of the expression given as negative one sixth times the quantity 3 minus 15 times the quantity one third squared is 2/9
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Answer:
The value of the expression given as negative one sixth times the quantity 3 minus 15 times the quantity one third squared is 2/9
How many significant digits are there in exact numbers?
A) Exact numbers have only eight significant figures.
B) Exact numbers have only three significant figures.
C) All the figures written in the exact number are significant.
D) Exact numbers have an unlimited number of significant figures.
Exact numbers have an unlimited number of significant figures and is therefore denoted as option D.
What are Exact numbers?These are the numbers which are used in counting and defining other quantities which are assumed to be exact and usually have no remainders and they have an infinite number of significant figures.
An example is number “3” is exact as well and could be expressed as 3.0000000000000. This means that the number of significant figures can be unlimited because any amount of figures can be placed after the number which is therefore the reason why it was chosen as the correct choice.
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make triangles and find the central angle
Answer:
Step-by-step explanation:
It 14
Answer:
this is like related to fractions right?
Step-by-step explanation: