Suppose you want to change the default port for RDP as a security precaution. What port does RDP use by default, and from what range of numbers should you select a private port number? (pg66,65) 3389 is the default port and the range of numbers should be from 49152 to 65535.
Answers
The default port used by RDP (Remote Desktop Protocol) is 3389. To change the default port for RDP as a security precaution, a private port number should be selected from the range of 49152 to 65535.
Explanation: RDP is a protocol developed by Microsoft that allows users to remotely access and control a computer over a network. By default, RDP uses port 3389 for communication. However, it is often recommended to change the default port as a security measure, as using non-standard ports can help protect against automated scanning and potential attacks targeting the default port.
When selecting a private port number to replace the default port for RDP, it is advisable to choose a port from the range of 49152 to 65535. This range of port numbers is designated for private or ephemeral use and is commonly referred to as the "dynamic" or "private" port range. Private port numbers are not officially assigned to specific protocols or services, which makes them a suitable choice for custom configurations, including changing the default RDP port. It is important to ensure that the selected private port is not already being used by another application or service on the system to avoid conflicts.
Learn more about private port here:
https://brainly.com/question/27749713
#SPJ11
Related Questions
What systems can you think of that are open-loop systems? (Provide three examples) Would they be improved if feedback was added to the loop? Why or why not?
Answers
Answer:
what do we do
Explanation:
) A regenerative vapor power cycle has three turbine stages with steam entering the first stage at 2500 lbf/in2 , 1100 o F. The cycle has two feedwater heaters, a closed feedwater heater using extracted steam at 500 lbf/in2 and an open feedwater heater operating at 50 lbf/in2 . Saturated liquid condensate drains from the closed feedwater heater at 500 lbf/in2 and passes through a trap into the open heater. The feedwater leaves the closed heater at 2500 lbf/in2, 478 o F. Saturated liquid leaves the open heater at 50 lbf/in2 and the condenser pressure is 1 lbf/in2 . For isentropic operation of the turbines and pumps, determine the efficiency of this cycle.
Answers
Answer:
do the wam wam
Explanation:
Appliances that use force voltage analogy
Answers
Explanation: Not quite sure. Need more research
in which direction will the block move
Answers
According to the diagram, the block should be moving The block should move to the left. Thus option D is correct.
What is movement?Movement describes teh motion of an object. It can be in any direction based on the location left, right, up, and down describing the certain path.
In the given diagram it is indicated that 20 N left - 10 N right based on the magnitude and force it will be moved to the left. The magnitude and location of the block are determined by the difference between the pressures because they are acting in opposing directions.
Therefore, option D is appropriate.
Learn more about block movement, here:
https://brainly.com/question/11884479
#SPJ1
The complete question is Probably
According to the diagram, the block should be moving in which direction?
A. There is no way to tell which way the block should move.
B. The block should move to the right.
C. The block should not move at all.
D. The block should move to the left.
Two added to four times a number, minus 3 times the number, equals 5.
Answers
x= 3.
Explanation:What is presented in this problem is basically an equation in verbal form.
1. Write the equation.
\(2+4x-3x=5\)
2. Solve for x.\(2+4x-3x=5\\ \\2+x=5\\ \\x=5-2\\ \\x=3\)
3. Express the result.x= 3.
Refrigerant-134a at 1 MPa and 100 C is to be cooled to 1 MPa and 28 C in a condenser by air. The air enters at 125 kPa and 25 C with a mass flow rate of 697 kg/min and leaves at 97 kPa and 58 C. Determine the mass flow rate of the refrigerant. Assume air has a constant heat capacity determined at room temperature. Report the mass flow rate of the refrigerant in kg/min with one decimal digit, for example 95.3 or 105.6.
Answers
The yield stress of a steel is 250Mpa. A steel rod used for implant in a femurneeds to withstand 29KN. What should the diameter of the rod be not to deform
Answers
Answer:
r = 1.922 mm
Explanation:
We are given;
Yield stress; σ = 250 MPa = 250 N/mm²
Force; F = 29 KN = 29000 N
Now, formula for yield stress is;
σ = F/A
A = F/σ
Where A is area = πr²
Thus;
r² = 2900/250π
r² = 3.6924
r = √3.6924
r = 1.922 mm
a venturi meter with a 7 in diameter throat is installed in a 14 in diameter water line. the venturi is perfectly smooth, so that the discharge coefficient is 1.00. an attached mercury manometer registers a 3 in differential. what is the volumetric flow rate?
Answers
Micrometer for brake rotors. For air disc brakes, the steering axle brake lining/pad thickness must be at least 3.2 mm (1/8 inch), and for hydraulic disc, drum, and electric brakes, it must be at least 1.6 mm (1/16 inch).
Every 45° (1/8 of a rotation), take a measurement of the brake rotor thickness of 0.40 inches (10mm) inside the outside circumference of the brake rotor. 6. Compare the lowest result obtained to the brake rotor's minimum thickness requirements. Depending on the vehicle, replacement brake pads can range in thickness from roughly 3/8" to 1/2". When the pads are down to around 1/4 inch, some shops advise changing them; others advise doing so at 1/8 or when only 20 to 25 percent of the original thickness remains.
Learn more about brakes here-
https://brainly.com/question/13439091
#SPJ4
The lattice parameter of copper is 0.362 nanometer. The atomic weight of copper is 63.54 g/mole. Copper forms a fcc structure. Answer the following questions.
a. Volume the unit cell in cubic centimeters in cubic centimeters is:______
b. Density of copper in g/cm^3 is:________
Answers
Answer:
a) 4.74 * 10^-23 cm^3
b) 8.9 g/cm^3
Explanation:
Given data :
Lattice parameter of copper = 0.362 nM
Atomic weight of copper = 63.54 g/mole
Given that copper forms a fcc structure
a) Calculate the volume of the unit cell
V = a^3
= ( 0.362 * 10^-7 cm )^3 = 4.74 * 10^-23 cm^3
b) Calculate density of copper in g/cm^3
Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )
where: NA = Avogadro's number = 6.022 * 10^23 atoms/mol
n = number of atoms per unit cell = 4
A = atomic weight = 63.54 g/mol
Vc = volume of unit cell = 4.74 * 10^-23 cm^3
Input values into equation 1
Density = 8.9 g/cm^3
What is the meaning of beauty and completeness? In relation to these what are the attributes a Muslim should adopt?
Answers
ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.
ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.
Consider the language consisting of all strings of the form uvw where:u is an arbitrary sequence of one or more a’s and b’s;w takes a substring u′ of u consisting of the first 1 to n characters of u and reverts it while replacing all a’s by TWO c’s;v is a, possibly empty, sequence of c’s that "fills in" the characters that were not reverted in w with the condition that |v| = |u| − |u′ |.Construct a context-free grammar for the language in BNF (do not use EBNF shortcuts). Keep it as clean and concise as possible. Guideline: use at most 3 non-terminal symbols! Use upper-case letters for non-terminals symbols.Then, give a production for each of the following strings. You do not need to write them as trees but can write them as sequence of sequences of terminals and nonterminals. For example, if you use the terminal symbols S, T and R, then a production may look like S → RT → RabT → bRabTb → ...→ baabcb Note: this is not a correct production for the described language; it is just an example of the notation to be used for your answer.• babbcbccb where u = babb, u′ = bab, v = c, and w = bccb which reverts u′ while replacing the a therein by two c’s• ababbccbcc where u = abab, u′ = abab, v = λ, and w = bccbcc as the reverse of u′ with the a’s replaced by two c’s each.Finally, construct a PDA for the language you create. Hint: Use separate sets of states for processing the parts u, v and w. As a guideline, aim for using 4-5 states altogether. Assume that the PDA terminates when the stack is empty, that is, you do not need an explicit accepting state. You may use the underscore notation of a transition applies regardless of what is currently on the stack
Answers
The language consisting of all strings of the form uvw where grammar:
S -> aSb | C
C -> cC | λ
What is strings?Strings are an essential data type in programming languages. They are sequences of characters that form words, sentences, and other types of information.
S, A, and B are three non-terminal symbols that will be used.
S → AB
Aa | b | AAa | ABa | BAa | BBa
B → cBc | c
The non-terminal S generates the entire language by generating the substrings u and v, while the non-terminal A generates u and B generates w.
babbcbccb production:
S → AB
A → bA
A → aB
ccBccb ccBccb ccBccb ccB
B → c
As a result, the production sequence for babbcbccb is: S → AB → bA → bB → bccBccb → bccBccbc → bccbccbccb
Therefore, the sequence of productions for ababbccbcc is: S → AB → aA → aaA → aacBcc → aacbBcc → aacbccBcc → aacbccbcc
To learn more about strings visit:-
brainly.com/question/25324400
#SPJ4
A long corridor has a single light bulb and two doors with light switch at each door.
Design logic circuit for the light; assume that the light is off when both switches are
in the same position.
Answers
Answer:
Light = A xor B
Explanation:
If switches A and B produce True or False, then Light will be True for ...
Light = A xor B
Find the transfer function of the given translational mechanical
system shown below. Provide a solution that will match to
the answer key given below
Answers
The given translational mechanical system is shown below. The transfer function of this system can be determined as follows:Firstly, the free-body diagram of the mechanical system is shown below, in which F is the input force applied to the mass m and x is the output position of the mass.
Therefore, we can write the force balance equation for the mass as:
F - kx - c(dx/dt) - mg = m(d²x/dt²)
where k, c, and m are the spring constant, damping constant, and mass of the mechanical system respectively.
The transfer function can be determined by taking the
Laplace transform of the above equation as follows:F(s) - kX(s) - csX(s)s - mg = ms²X(s)
Rearranging the above equation,
we get:X(s)/F(s) = 1/[ms² + cs + k + mg/s]
Therefore, the transfer function of the given translational mechanical system is X(s)/F(s) = 1/[ms² + cs + k + mg/s].
To know more about force visit:
https://brainly.com/question/30507236
#SPJ11
Based on the code shown, which query finds how many items are incategory TOY? Item (ItemNum, Description, OnHand, Category, Storehouse, Price) a.SELECT COUNT* FROM Item WHERE Category='TOY' ;b.SELECT COUNT(*) FROM Item WHERE Category='TOY' ;c.SELECT COUNT FROM Item WHERE Category='TOY' ;d.SELECT SUM(*) FROM Item WHERE Category='TOY' ;
Answers
The correct query to find how many items are in category TOY based on the given code is:
b. SELECT COUNT(*) FROM Item WHERE Category='TOY';
The COUNT function is used to count the number of rows that meet the specified conditions in the WHERE clause. In this case, we want to count the number of items that have a category of TOY.
The (*) after the COUNT function is used to count all the rows that meet the condition. Alternatively, we could have specified a column name to count the number of non-null values in that column.
Therefore, the correct query to find how many items are in category TOY is the second option: SELECT COUNT(*) FROM Item WHERE Category='TOY';
Learn more about category here:
https://brainly.com/question/31766837
#SPJ11
Refrigerant 134a at p1 = 30 lbf/in2, T1 = 40oF enters a compressor operating at steady state with a mass flow rate of 200 lb/h and exits as saturated vapor at p2 = 160 lbf/in2. Heat transfer occurs from the compressor to its surroundings, which are at T0 = 40oF. Changes in kinetic and potential energy can be ignored. The power input to the compressor is 2 hp. Determine the heat transfer rate for the compressor, in Btu/hr, and the entropy production rate for the compressor, in Btu/hr·oR.
Answers
Answer:
a) \(\mathbf{Q_c = -3730.8684 \ Btu/hr}\)
b) \(\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}\)
Explanation:
From the properties of Super-heated Refrigerant 134a Vapor at \(T_1 = 40^0 F\), \(P_1 = 30 \ lbf/in^2\) ; we obtain the following properties for specific enthalpy and specific entropy.
So; specific enthalpy \(h_1 = 109.12 \ Btu/lb\)
specific entropy \(s_1 = 0.2315 \ Btu/lb.^0R\)
Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at \(P_2 = 160 \ lbf/in^2\) ; we obtain the following properties:
\(h_2 = 115.91 \ Btu/lb\\\\ s_2 = 0.2157 \ Btu/lb.^0R\)
Given that the power input to the compressor is 2 hp;
Then converting to Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr
2 hp = 2 × 2544.4342 Btu/hr
2 hp = 5088.8684 Btu/hr
The steady state energy for a compressor can be expressed by the formula:
\(0 = Q_c -W_c+m((h_1-h_e) + \dfrac{v_i^2-v_e^2}{2}+g(\bar \omega_i - \bar \omega_e)\)
By neglecting kinetic and potential energy effects; we have:
\(0 = Q_c -W_c+m(h_1-h_2) \\ \\ Q_c = -W_c+m(h_2-h_1)\)
\(Q_c = -5088.8684 \ Btu/hr +200 \ lb/hr( 115.91 -109.12) Btu/lb \\ \\\)
\(\mathbf{Q_c = -3730.8684 \ Btu/hr}\)
b) To determine the entropy generation; we employ the formula:
\(\dfrac{dS}{dt} =\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c\)
In a steady state condition \(\dfrac{dS}{dt} =0\)
Hence;
\(0=\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c\)
\(\sigma _c = m( s_1 -s_2) - \dfrac{Qc}{T}\)
\(\sigma _c = [200 \ lb/hr (0.2157 -0.2315) \ Btu/lb .^0R - \dfrac{(-3730.8684 \ Btu/hr)}{(40^0 + 459.67^0)^0R}]\)
\(\sigma _c = [(-3.16 ) \ Btu/hr .^0R + (7.4667 ) Btu/hr ^0R}]\)
\(\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}\)
-. Which format is correct for entering dimensions in an architectural drawing?
a
50 12"
b. 4'212"
C.
4' 2.5"
d.
50.5"
Answers
Answer:
d.
50.5" is the answer for this question
GMA MIG weiding is a
Answers
Gas metal arc welding (GMAW), sometimes referred to by its subtypes metal inert gas (MIG) welding or metal active gas (MAG) welding, is a welding process in which an electric arc forms between a consumable MIG wire electrode and the workpiece metal(s), which heats the workpiece metal(s), causing them to melt and join.
Explanation:
GMA MIG weiding is aiejrjjrkdkff
car people i need some advice
what should be my first super car
Answers
Answer:
The first one.
Explanation:
The first one without a doubt
this is perfect.........
a 50mm cube of steel is subject to a uniform (compressive) pressure of 200 mpa on all faces. find the change in dimension between parallel faces of the cube. for the steel, e = 210 gpa and q = 0.25.
Answers
The change in dimension between parallel faces of the cube is -1/84 mm, meaning that the cube's dimensions have decreased due to the compressive pressure.
Since the problem involves a cube of steel subjected to a compressive pressure, we'll use the concept of stress and strain to find the change in dimensions.
Given:
- Pressure (P) = 200 MPa
- Young's modulus (E) = 210 GPa
- Poisson's ratio (q) = 0.25
1. Convert the given units:
P = 200 MPa = 200 * 10^6 N/m^2
E = 210 GPa = 210 * 10^9 N/m^2
2. Calculate the axial strain (ε) using the formula:
ε = P/E = (200 * 10^6) / (210 * 10^9) = 1/1050
3. Calculate the lateral strain (ε_L) using the formula:
ε_L = -q * ε = -0.25 * (1/1050) = -1/4200
4. Calculate the change in dimension between parallel faces of the cube using the original dimension (50mm) and the lateral strain:
ΔL = original dimension * lateral strain = 50 * (-1/4200) = -1/84 mm
The change in dimension between parallel faces of the cube is -1/84 mm, meaning that the cube's dimensions have decreased due to the compressive pressure.
To know more about parallel faces visit:
https://brainly.com/question/16627095
#SPJ11
When your workplace obtains new materials, you should add them to the chemical list:
Answers
Answer:
immediately
Explanation:
what is the transfer function? what is the steady-state error, ess? what is the natural frequency? you can assume ra
Answers
The transfer function is a mathematical representation of the relationship between the input and the output of a system. The steady-state error, or ess, is the difference between the desired output and the actual output when the system reaches a steady state. The natural frequency is the frequency of the system's response without any external forces.
Transfer Function: Transfer Function is used in signal processing, control engineering, and other disciplines that deal with systems or signals. The ratio of output to input in Laplace transform is known as the transfer function.
Steady-State Error: The error that happens when the system is at a stable state is referred to as a steady-state error. The difference between the desired and actual response is known as steady-state error. A system's ability to track a specific input as time progresses is characterized by this kind of error. If the input signal is a unit step, then the steady-state error is referred to as the static error coefficient. The coefficient of the steady-state error is frequently used to classify systems in control engineering.
Natural Frequency: Natural frequency is a term used in physics to describe how quickly an object vibrates when it is set in motion. The number of oscillations made by a system in a given time period without any external force acting on it is referred to as its natural frequency. A natural frequency is a measure of a system's stiffness and mass. In a control system, it is the frequency at which the system oscillates in the absence of any input.
A natural frequency is also known as an undamped natural frequency or a resonance frequency, and it is represented by the symbol \(\omega_n\).You can assume the following in the problem. If you have any specific values, kindly provide them.
Learn more about Transfer Function here:
https://brainly.com/question/24241688
#SPJ11
a si p-n junction has an area of 1 cm2. on the p-side of the junction, there are 2 x 1017 acceptors/cm3. on the n-side of the junction, there are 1 x 1017 donors/cm3. find the built-in potential.
Answers
Assuming that the intrinsic carrier concentration is roughly 1 × 10¹⁰ cm³, the built-in potential is given by: Therefore, the p-n junction has a built-in potential of about -0.18 V.
The difference in electron and hole concentrations on the p-side and n-side of a p-n junction controls its intrinsic potential. The equation can be used to compute it.
\(V_{bi} = \frac{kT}{q} \times \ln \frac{N_{d} \times N_{a}}{n_{i}^{2}}\)
where,
\(V_{bi}\) is the intrinsic potential (measured in volts),
k is the Boltzmann constant (8.62 × 10⁻⁵ eV/K),
T is the temperature (measured in kelvin),
q is the electronic charge (1.6 × 10⁻¹⁹ C),
\(N_{d}\) is the donor concentration (measured in cm³).
Nₐ is the acceptor (measured in cm³), and
\(n_{i}\) is the intrinsic carrier concentration (measured in cm³).
Now,
\(V_{bi} = \frac{kT}{q} \times \ln \frac{(1 \times 10^{17}) \times (2 \times 10^{17})}{n_{i}^{2}}\)
\(= \frac{(8.62 \times 10^{-5}) \times (300)}{1.6 \times 10^-{19}} \times \ln \frac{2 \times 10^{17}}{n_{i}^{2}}\)
\(= 0.0259 \times \ln \frac{2 \times 10^{17}}{n_{i}^{2}}\)
\(V_{bi} = 0.0259 \times \ln \frac{2 \times 10^{17}}{(1 \times 10^{10})^{2}}\)
= \(0.0259 \times \ln \frac{2 \times 10^{17}}{1 \times 10^{20}}\)
= 0.0259 × ln(2 × 10⁻³)
= 0.0259 × (-6.9078)
= -0.18 V
Learn more about junction Visit: brainly.com/question/13507783
#SPJ4
(15 points) Case hardening of a steel (Fe-C alloy) gear with initial concentration of 0.10 wt.% C is accomplished by raising the composition 7 mm below the surface to at least 0.35 wt% C. An engineer has proposed elevating the surface concentration to 1.10 wt% C for 307.787 hours at 1,000 °C. Note that the diffusion coefficient of carbon in steel at 1,000 °C is 1.6x10-1 m²/s. What is the concentration of carbon in the steel at a distance 8 mm from the surface? Note: If point is close to tabulated value you can use value from table and avoid linear interpolation.
Answers
The concentration of carbon in the steel at a distance of 8 mm from the surface is 0.224 wt%.
Here's a step-by-step explanation:
1. First, convert the distance from the surface from millimeters to meters: 8 mm = 0.008 m.
2. Calculate the diffusion parameter (z) by dividing the distance by the square root of the diffusion coefficient multiplied by time: \(z = x / \sqrt(Dt)\)
\(z = 0.008 m / \sqrt(1.6*10^(-1) *307.787 *3600)\)
\(z = 0.008 / \sqrt(1.6*10^(-1) * 307.787 * 3600)\)
\(z =0.112\)
3. Consult the error function table to find the corresponding value for z ≈ 0.112, which is erf(z) ≈ 0.124.
4. Calculate the concentration of carbon at the specified depth using the initial concentration, surface concentration, and error function value:
\(C(x) = C_(initial) + (C_(surface) - C_(initial)) * erf(z)\)
\(C(x) = 0.10 + (1.10 - 0.10 ) * 0.124\)
\(C(x) = 0.10 + 1.00 * 0.124\)
C(x)≈ 0.224 wt.%
The concentration of carbon in the steel at a distance of 8 mm from the surface is approximately 0.224 wt.%.
Learn more about steel at:
https://brainly.com/question/26217574
#SPJ11
in lab you propel a cart with four known forces while using an ultrasonic motion detector to measure the cart's acceleration your data is as follows
A. FORCE(N) ACCELERATION (m/s^2)
B. 0.25 0.5
C. 0.50 0.8
D. 0.75 1.3
E. 1.8
is there another data point that would be reasonable to add even though you made no measurements? if so, what is it?
Answers
A data professional must regularly deal with the issue of missing data. Although there are currently a lot of articles, blogs, and videos available.
I discovered that it is challenging to locate a piece of condensed, short information in a single location. That is why I made the effort to put this together in the hopes that any data enthusiast or practitioner will find it useful. Unavailable numbers that would have meaning if observed are referred to as missing data. Lost data might include a variety of things, such as a missing sequence, an incomplete feature, missing files, incomplete information, data entry errors, etc. In the actual world, most datasets have missing information. Prior to using missing data fields, those fields must be transformed so that they may be used for analysis and modeling.
Learn more about data here:
https://brainly.com/question/10980404
#SPJ4
PLEASE HELPPP
Chlorinated hydrocarbon pesticides, such as DDT, were introduced during World War II to control insects
in agricultural crops. All of the following statements about chlorinated hydrocarbons are true EXCEPT:
A. They are safe for all organisms except insect pests.
B. They are inexpensive and easy to apply.
C. They persist for a long time in the environment.
D. They boost crop yields by killing pests.
Answers
Answer:
it's A. They are safe for all organisms except insect pests.
Explanation:
Comment if it's wrong or right! Thank you :)
On a TXV system, the temperature sensing bulb is located at the
A condenser outlet
B evaporator outlet
C condenser inlet
D evaporator inlet
Answers
Answer:
Explanation:
B evaporator outlet: on the suction line between the evaporator and the compressor
froce and motion worksheet
Answers
Answer:
The following description of the problem is provided.
Explanation:
If somehow the system seems to be in movement it'll still relax, and it becomes moving whether it sits. An externality is a cost, that either affects or threatens that can modify the bodily condition.The phenomenon of anything changing their position, altering or completely replacing. Whenever moment anything keeps moving, several components are found.Design a 3-bit binary counter using S-R flip flops.
Answers
Answer:
This is an asynchrnous 3-bit counter. Just note that this design is different and works differently than its synchronous counterpart. It's an easier design than its synchronous counterpart, and is not as reliable because it has delays.
How would you increase the size of the base unit of length in the metric system
Answers
For this problem, you will write a module that holds sets over a type a. Our goal is to
represent the set as a sorted list with NO repeated elements. Therefore, the type a will
always be of the classes:
• Eq: so that == and /= are defined for elements of type a
• Ord: so that we can compare using <, etc.
• Enum: So that we can make lists of the form [x..y] where x and y are elements of type
a.
• Bounded: so that minBound::a and maxBound::a are the smallest and largest elements
of a.
(Note that this means we can form [minBound..maxBound]::[a], a list of all the elements of
a.)
So our declaration of the Set type is:
data Set a = Set [a]
deriving (Show, Eq, Ord)
I also have 2 functions that let you go back and forth between sets and lists, primarily for
testing purposes. You need to import Data.List for these to work, so I’m giving the syntax
for that below:
import qualified Data.List as L
list2set :: Ord a => [a] -> Set a
list2set = Set . L.nub . L.sort
set2list :: Set a -> [a]
set2list (Set xs) = xs
The temptation in implementing the set operations below is the overrely on list2set which
results in code that is simple, clear, and slow!! For example, for the union operation we could
define:
unionS_slow :: (Ord a) => Set a -> Set a -> Set a
unionS_slow (Set xs) (Set ys) = list2set (xs ++ ys)
The problem is that this will result in worst case O(n 2 ) running time (where n is the max
of the length of the 2 sets) and this is much too slow. To speed things up, we need to take
advantage of the fact that the lists are sorted and have no repeat elements. So a much better
implementation of union is the following, which has a O(n) running time:
unionS :: (Ord a) => Set a -> Set a -> Set a
unionS (Set xs) (Set ys) = Set $ merge xs ys
where
merge [] ys = ys
merge xs [] = xs
merge (x:xs) (y:ys)
| x
| x>y = y:merge (x:xs) ys
| otherwise = x:merge xs ys
Note that on any of these problems, I will be looking for (at worst) an O(n) running time,
so be careful about using list2set! In particular, you don’t want to use those for intersectS or
diffS.
(a) Write two functions:
singS :: a -> Set a
emptyS :: Set a
which (respectively) create a single element set of the input and an empty set.
(b) Write the function:
addToS :: (Ord a) => a -> Set a -> Set a
so that the first input will be added to the set in the appropriate location.
(c) Write the function:
intersectS :: (Ord a) => Set a -> Set a -> Set a
so that intersectS s1 s2 returns a set representing the intersection of s1 and s2.
(d) Write the function:
diffS :: (Ord a) => Set a -> Set a -> Set a
So that diffS s1 s2 returns a set representing the set-difference of s1 and s2, which is
precisely the elements contained in s1 that are not in s2.
(e) Write the function:
subseteq :: (Ord a) => Set a -> Set a -> Bool
So that subseteq s1 s2 returns true whenever s1 is a subset of s2.
(f) Now, put all these in a module named sets, and test your functions. I would like you to
submit either a haskell script or a set of instructions you run at the command prompt
after loading your module that indicate success of each of your functions.
Answers
In Haskell, a module named 'Set's is created with functions for set operations. The functions include 'singS' to create a set with a single element, 'emptyS' to create an empty set, 'addToS' to add an element to a set, 'intersectS' to find the intersection of two sets, 'diffS' to find the difference between two sets, and 'subseteq' to check if one set is a subset of another. The module provides a convenient way to work with sets in Haskell.
a) Two functions `singS` and `emptyS` are to be written as follows in Haskell:
singS :: a -> Set a
singS x = Set [x]
emptyS :: Set a
emptyS = Set []
Here, `singS` takes an input of type `a` and returns a `Set` containing only that input element while `emptyS` returns an empty `Set`.
b) The function `addToS` is to be written as follows:
addToS :: (Ord a) => a -> Set a -> Set a
addToS x (Set []) = Set [x]
addToS x (Set xs)
| x == head xs = Set xs
| x < head xs = Set (x:xs)
| otherwise = Set $ head xs : set
where Set set = addToS x (Set (tail xs))This function takes an input of type `a` and a `Set a` and returns the `Set` with the input element added to it.
c) The function `intersectS` is to be written as follows:
intersectS :: (Ord a) => Set a -> Set a -> Set a
intersectS (Set []) _ = Set []
intersectS _ (Set []) = Set []
intersectS (Set xs) (Set ys) = Set $ intersect xs ys
Here, the `intersect` function from `Data.List` is used to calculate the intersection of two sets and returns the resulting `Set`.
d) The function `diffS` is to be written as follows:
diffS :: (Ord a) => Set a -> Set a -> Set a
diffS (Set []) _ = Set []
diffS xs (Set []) = xs
diffS (Set xs) (Set ys) = diff (Set xs) ys
where
diff xs (Set []) = xs
diff (Set []) _ = Set []
diff (Set (x:xs)) (Set (y:ys))
| x == y = diff (Set xs) (Set ys)
| x < y = diff (Set xs) (Set (y:ys))
| otherwise = diff (Set (x:xs)) (Set ys)
Here, `diffS` function takes two `Set` and returns a `Set` which is the difference between the two input `Set`s.
e) The function `subseteq` is to be written as follows:
subseteq :: (Ord a) => Set a -> Set a -> Bool
subseteq (Set xs) (Set ys) = all (`elem` ys) xs
This function checks whether all the elements of the first input `Set` are in the second input `Set`. If yes, it returns `True`, otherwise `False`.
f) The functions will be grouped into a module named `Sets`.
The `Sets.hs` file will look as follows:
```module Sets whereimport qualified Data.List as Ldata Set a = Set [a]deriving (Show, Eq, Ord)singS :: a -> Set a
singS x = Set [x]
emptyS :: Set a
emptyS = Set []addToS :: (Ord a) => a -> Set a -> Set a
addToS x (Set []) = Set [x]
addToS x (Set xs)
| x == head xs = Set xs
| x < head xs = Set (x:xs)
| otherwise = Set $ head xs : set
where Set set = addToS x (Set (tail xs))intersectS :: (Ord a) => Set a -> Set a -> Set a
intersectS (Set []) _ = Set []
intersectS _ (Set []) = Set []
intersectS (Set xs) (Set ys) = Set $ intersect xs ysdiffS :: (Ord a) => Set a -> Set a -> Set a
diffS (Set []) _ = Set []
diffS xs (Set []) = xs
diffS (Set xs) (Set ys) = diff (Set xs) ys
where
diff xs (Set []) = xs
diff (Set []) _ = Set []
diff (Set (x:xs)) (Set (y:ys))
| x == y = diff (Set xs) (Set ys)
| x < y = diff (Set xs) (Set (y:ys))
| otherwise = diff (Set (x:xs)) (Set ys)subseteq :: (Ord a) => Set a -> Set a -> Bool
subseteq (Set xs) (Set ys) = all (`elem` ys) xs```To test the functions, open the terminal and run the following command:
```ghci
:l Sets.hs```
After this, the following commands can be run to check the functions:
`singS 1` will output `Set [1]``emptyS` will output `Set []``addToS 1 (Set [2, 3, 4])` will output `Set [1,2,3,4]``intersectS (Set [1,2,3]) (Set [2,3,4])` will output `Set [2,3]``diffS (Set [1,2,3]) (Set [2,3,4])` will output `Set [1]``subseteq (Set [1,2]) (Set [1,2,3])` will output `True` and `subseteq (Set [1,2,3]) (Set [1,2])` will output `False`.
Learn more about Haskell at:
brainly.com/question/31492615
#SPJ11