Taiwan is one of the targeted jurisdictions of the "bay area trade finance
blockchain platform".
true
false

In order to produce molten iron and carbon dioxide in a blast furnace, the following steps are typically taken:

Place limestone, coal, and iron ore in a blast furnace. (c)

Heat the blast furnace to high temperatures, causing the limestone to break down and release carbon dioxide. (d)

The carbon dioxide reacts with the coal to produce carbon monoxide, which then reacts with the iron ore to reduce it to molten iron. (a)

Pour off the molten iron from the bottom of the blast furnace. (b)

These steps are part of the process of producing iron in a blast furnace, which is a common method used in the production of steel and other iron-based products. It is important to follow proper procedures and safety protocols when working with blast furnaces, as they involve high temperatures and potentially hazardous materials.

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Answer:the answer is a

Explanation:

The density of a gas at standard temperature and pressure conditions is 1.40 grams per liter.

Standard temperature and pressure are defined as a standard set of conditions required for experimental measurements which are established to allow comparison between different sets of data.

Standards which are commonly used are those International Union of pure and applied chemistry and national institute of standards and technology.These are not universally accepted standards but are the ones which are commonly used.

Standard conditions of pressure and temperature are necessary to define standard reference conditions used to express volumes of liquids and gases.These values are important to physicists, chemists ,engineers ,pilots and navigators.

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Answer:

\(0.12g/cm^3\)

Explanation:

Firstly, you should use this formula :

\(Density=\frac{mass}{volume}\)

We know the mass is 16.14g, and volume as \(138.4ml\).

Also remember to convert \(ml\) to \(cm^3\), where \(1ml = 1cm^3\)

Therefore, \(138.4ml=138.4cm^3\).

Substitute the value :

\(\frac{16.14g}{138.4cm^3}=0.1166g/cm^3\)

Rounding it to 2 significant figure :

\(0.12g/cm^3\)

Answer:

m=0.000107 kg

Explanation:

H=m*cp*change in temperature

0.296=m*4182*0.661

m=0.000107 kg

The different methods that can be used to create electrodes on a Borosilicate wafer are of standard and thin wall configurations.

The use of standard with filament configuration and thin wall configurations comes in different barrel sizes of one, two, three, five, and seven barrels. The capillaries that line the wall of the glass have the electrodes with the association, if needed, a wire that runs along to the record.

The thin wall single barrel configurations may be fitted with two electrodes. They do not use filings like with the standard configurations.

In order to use a silicon wafer, the additional step that is done is doping. Doping is the introduction of some impurities to the semiconductors to make them more electrically active.

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d) 22.1 moles of sulfur

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

707 g S (Sulfur)

Step 2: Identify Conversions

Molar Mass of S - 32.07 g/mol

Step 3: Convert

Step 4: Round

Our closest answer is d) 22.1 moles of sulfur

This is due to dividing different rounded values.

Answer:

\(\boxed {\boxed {\sf D. \ 22.1 \ moles \ of \ sulfur}}\)

Explanation:

To convert from moles to grams, we must use the molar mass. This can be found on the Periodic Table.

We are given a sample of sulfur. Look for the symbol S on the table.

This tells us the mass of 1 mole of sulfur. Use this molar mass as a ratio.

\(\frac{32.07 \ g \ S}{1 \ mol \ S }\)

Multiply by the given number of grams (707).

\(707 \ g \ S *\frac{32.07 \ g \ S}{1 \ mol \ S }\)

Flip the fraction so the grams of sulfur will cancel out.

\(707 \ g \ S *\frac{ 1 \ mol \ S }{32.07 \ g \ S}\)

\(707 *\frac{ 1 \ mol \ S }{32.07 }\)

\(\frac{ 707 \ mol \ S }{32.07 }\)

\(22.0455254 \ mol \ S\)

The number we caluclated is the closest to answer choice D: 22.1 moles of sulfur

Answer:

B : 4.6 billion years

Credits go to the person above me.

;)

Explanation:

EDGE 2021

The sun is about 4.6 billion years old. Therefore, option (B) is correct.

The Sun is made primarily of the elements hydrogen and helium. They account for 74.9% and 23.8% mass of the Sun in the photosphere. All heavier elements, called metals account for less than 2% of the mass, with oxygen (<1%), carbon (0.3%), neon (0.2%), and iron (0.2%) being the most abundant.

The hydrogen and helium in the Sun would have been produced by Big Bang nucleosynthesis and the heavier elements were produced by former generations of stars before the Sun was formed.

The amount of helium and its location within the Sun has gradually changed over the past 4.6 billion years. The proportion of helium has raised from about 24% to 60% due to fusion, and some of the He and heavy elements have settled from the photosphere toward the center due to gravity.

Therefore, the age of the sun is about 4.6 billion years.

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The quantity of heat absorbed may be calculated by dividing the number of moles of ice by the molar heat of fusion. 3. After heating the water to 0oC, the temperature is increased to 100oC using the equation

H=cpmT

+40.7kJ/7.0  =5.81

and the water specific heat.

Heat is an example of energy. When a substance absorbs heat, the inter-particle linkages between the particles weaken and break, resulting in a change in the state of the substance. Heat does not cause a significant phase shift to raise the temperature.

Because of its low cost, large heat capacity, and excellent transport qualities, water is the most often utilised heat transfer fluid. However, depending on the system pressure, the range of practical temperatures is confined by boiling at high temperatures or freezing below 0 °C.

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Answer: 284.9

Explanation:

acellus verified

Explanation:

Caesium (Cs) has a smaller ionic radius than it's neutral atom.

because Caesium belong to Group 1 and It loses 1 electron. After losing 1 electron it gains 1 positive charge that's why caesium ionic radius become smaller as compared to neutral atom.

Therefore,

Option B is correct.

To determine the phases present, a fraction of each phase, and the composition of each phase in a carbon-fe alloy containing 1.5 wt% C cooled down to 800°C, you would need to refer to the phase diagram for carbon-iron (Fe-C) alloy, also known as the iron-carbon phase diagram.

1. Consult the phase diagram: Look for the region that corresponds to the composition of the alloy, which is 1.5 wt% C.

Find the temperature range of 800°C.

2. Determine the phases present: From the phase diagram, identify the phases present at 800°C for an alloy with 1.5 wt% C.

3. Determine the fraction of each phase present: The phase diagram may provide information about the fraction of each phase present at 800°C for the given composition.

4. Determine the composition of each phase: The phase diagram should also indicate the composition of each phase present at 800°C.

Please refer to the specific phase diagram for the carbon-fe alloy you are working with to find the exact information on phases, fractions, and compositions at 800°C for an alloy with 1.5 wt% C.

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Explanation:

To calculate the volume of the container that the gas is in, we can use the ideal gas law, which is given by the equation:

PV = nRT

where:

P = pressure of the gas (in atm)

V = volume of the gas (in liters)

n = amount of gas in moles

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature of the gas (in Kelvin)

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15 to it:

T = 62°C + 273.15 = 335.15 K

Now we can plug in the given values into the ideal gas law equation and solve for V:

P = 9 atm

n = 8.3 moles

R = 0.0821 L·atm/(mol·K)

T = 335.15 K

PV = nRT

9 V = 8.3 * 0.0821 * 335.15

V = (8.3 * 0.0821 * 335.15) / 9

V ≈ 26.79 liters

So, the volume of the container that the gas is in is approximately 26.79 liters.

Answer: C. Na2B4O7•10H2O

Explanation:

Hope this helps :)

The formula is tetrasodium borate-Na2B4O7.10H2O

Given- 0.0132 mol Na2B4O7 and 0.1311 mol H2O

Using the molar mass of the anhydrous Na2B4O7 and its mass percentage, we can calculate the molar mass of the hydrate (if we look at it as 100% of the mass) by stoichiometry.

Molar mass of Na = (22.990 g/mol)

Molar mass of B = (10.811 g/mol)

Molar mass of O = (15.999 g/mol)

Molar mass of Na2B4O7= 2⋅22.990 g/mol +4⋅10.811 g/mol +7⋅15.999 g/mol = 201.217 g/mol

201.217g/mol : 52.8%=x g/mol : 100%

​x g/mol = 201.217 g/mol⋅100%÷52.8 %

x g/mol= 381.093 g/mol

In 381.093 g of hydrate, we have 201.217 g of anhydrous Na2B4O7 , the rest of the mass is water.

381.093g−201.217g= 179.876 g of water

Molar mass of H = 1.008 g/mol

Molar mass of O = 15.999 g/mol

Molar mass of  H2O= 1.008 g/mol+ 15.999g/mol  = 18.015 g/mol

179.876g ÷18.015 = 9.98= 10 moles of water per mole of hydrate.

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Answer:

¹/₂₄ dm³ or 0.417 dm³

Explanation:

6.0 M = 6.0 mol/dm³

0.5 M = 0.5 mol/dm³

500 ml = 0.5 dm³

V = volume of 6.0 M solution required (dm³)

Volume × concentration = moles:

0.5 × 0.5 = 0.25

500 ml or 0.5 dm³ of 0.5 M solution contains 0.25 moles of HNO₃

We have 6.0 M solution available, we need 0.25 moles;

Using the formula, we can find the volume of the solution that contains this amount of moles:

6.0 × V = 0.25

V = 0.25/6

V = ¹/₄(¹/₆)

V  = ¹/₂₄

¹/₂₄ dm³ of the 6.0 M solution has the necessary moles of HNO₃ to achieve the desired volume of solution at the desired concentration;

Another liquid (or solution), such as water, without any HNO₃ must be used to make up the total 500 ml or 0.5 dm³, diluting the HNO₃ to the desired concentration:

0.5 - ¹/₂₄ = ¹²/₂₄ - ¹/₂₄

= ¹¹/₂₄

¹/₂₄ dm³ of the 6.0 M solution should be diluted with the ¹¹/₂₄ dm³ of liquid (0 M HNO₃ solution) to produce 0.5 dm³ of 0.5 M solution

Answer: (B) −198 kJ.

Answer:C - 3.115 g

Explanation:Correct

Option C. is a molecule of hydrocarbon.

Hydrocarbons are organic compounds made up of only hydrogen and carbon atoms. They are the building blocks of organic chemistry and are the main component of fossil fuels such as coal, oil, and natural gas.

Molecules of hydrocarbons can be simple or complex, and can exist as gases, liquids, or solids. Some common examples of hydrocarbon molecules include methane (CH₄), ethane (C₂H₆), propane (C₃H₈), and butane (C₄H₁₀). Alkanes, alkenes, and alkynes are all types of hydrocarbons that have different chemical and physical properties based on the arrangement of their atoms.

Therefore, the correct answer is as given above. It could then be concluded that only option C is made up of hydrogen and carbon atoms.

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Answer: Mass of solution is 80.4 g

Explanation: 15.8 % = 0.158.   Mark mass of solution with x

You can make an equation for mass of sugar: 0.158 x = 12.7 g

x = 12.7 g / 0.158  

The result of all of these scientific contributions except Rutherford's gold foil experiment proved the existence of the nucleus.

The valence electrons mainly determine the chemical houses of the elements. The elements inside the equal group have comparable chemical homes because they have identical valence shell electron configurations. The electrons in the power degrees with the highest range are in common the farthest from the nucleus.

Because variations in electrons placed inside the outermost stage distinguish an atom from its nearest noble fuel these are the electrons accountable for the atom's chemical conduct. Electrons located inside the outermost shell of the electron cloud are called valence electrons and feature the best power. Valence electrons determine the chemical homes of an element or how the valence electrons of 1 element are shared or traded with valence electrons of other elements to create new molecules.

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The volume of the gas changed by approximately 0.280 m³ during the process.

To find the change in volume of the gas during the process, we can use the equation:

ΔQ = nCvΔT

where: ΔQ is the heat absorbed (3870 J),

n is the number of moles of the gas (7.70 mol),

Cv is the molar heat capacity at constant volume,

ΔT is the change in temperature (24.2 °C = 24.2 K).

Since the change in internal energy is zero (ΔU = 0), we know that ΔU = ΔQ + ΔW, where ΔW is the work done by the gas. In this case, since the process is at constant pressure, we can write ΔW = PΔV, where P is the pressure (1.62E+5 Pa) and ΔV is the change in volume.

Now, using the ideal gas law, we can express ΔV in terms of ΔT:

ΔV = (nRΔT) / P

where R is the ideal gas constant (8.314 J/(mol·K)).

Substituting the given values into the equations:

ΔQ = nCvΔT

3870 J = 7.70 mol × Cv × 24.2 K

From the equation ΔV = (nRΔT) / P, we have:

ΔV = (7.70 mol × 8.314 J/(mol·K) × 24.2 K) / (1.62E+5 Pa)

Simplifying the equations and performing the calculations:

ΔQ = nCvΔT

3870 J = 7.70 mol × Cv × 24.2 K

Cv ≈ 2.00 J/(mol·K) (calculated from the above equation)

ΔV = (7.70 mol × 8.314 J/(mol·K) × 24.2 K) / (1.62E+5 Pa)

ΔV ≈ 0.280 m³

Therefore, the volume of the gas changed by approximately 0.280 m³ during this process.

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Answer and Explanation:

Your mass is the same no matter where you go in the universe; your weight, on the other hand, changes from place to place. Mass is measured in kilograms; even though we usually talk about weight in kilograms, strictly speaking, it should be measured in newtons, the units of force. (according to cosmicmagazine.com)(not my writing or explanation)

Density is a crucial physical quantity for a variety of materials, including liquids, gases, and solids. The temperature at which density is measured is usually specified because density is temperature-dependent and changes with temperature.

This implies that a small change in temperature will have a substantial effect on density.Let's have a look at the connection between temperature and density:T and ρ are the symbols used to represent temperature and density, respectively. It is common knowledge that substances expand when heated and contract when cooled. In the same vein, as temperature increases, the space between the molecules increases, resulting in a decrease in density. Conversely, if the temperature decreases, the molecules move closer together, and the density increases. When we consider the relationship between temperature and density, we can infer that density is directly proportional to temperature. As a result, when the temperature changes, so does the density, and this fluctuation must be specified. Therefore, specifying the temperature at which density is measured ensures accuracy and consistency in measurements. It also allows us to make appropriate comparisons between density values obtained from various sources. In conclusion, specifying temperature when measuring density ensures consistency and accuracy in results.

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Answer:

Scientific theories are testable and make falsifiable predictions. They describe the causes of a particular natural phenomenon and are used to explain and predict aspects of the physical universe or specific areas of inquiry (for example, electricity, chemistry, and astronomy).

A good theory in the theoretical sense is (1) consistent with empirical observations; is (2) precise, (3) parsimonious, (4) explanatorily broad, and (5) falsifiable; and (6) promotes scientific progress (among others; Table 1.1).

Answer:

Mass.

Si Unit Measurement.

volume.

milliliters.

The answer is 0.027426610504282. We assume you are converting between moles HCl and gram. You can view more details on each measurement unit: molecular weight of HCl or grams This compound is also known as Hydrochloric Acid. The SI base unit for amount of substance is the mole.

i hope this one helps, hehe.

The sample of oxygen will occupy approximately 18.5 mL at -70 °C and the same pressure.

The force exerted by a gas on specific area is known as gas pressure..

As we know, (P₁ V₁) /(T₁) = (P₂V₂) /(T₂)

Given, P₁ is the initial pressure (452 torr); V₁ is initial volume (32.2 mL)

T₁ is initial temperature in Kelvin (30 °C + 273.15 = 303.15 K)

P₂ is final pressure (452 torr); V₂ is final volume (what we want to find)

T₂ is the final temperature in Kelvin (-70 °C + 273.15 = 203.15 K)

Now, V2 = (P₁ V₁ T₂) / (P2 T₁)

V₂ = (452 torr x 32.2 mL x 203.15 K) / (452 torr x 303.15 K)

V₂ ≈ 18.5 mL

Therefore, the sample of oxygen will occupy approximately 18.5 mL at -70 °C and the same pressure.

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The null hypothesis (H0) in symbolic form would be: p ≥ 0.0001. This means that the true proportion of male fireflies unable to produce light is equal to or greater than 0.0001.

The alternative hypothesis (Ha) in symbolic form would be: p < 0.0001. This means that the true proportion of male fireflies unable to produce light is less than 0.0001.
In other words, the null hypothesis states that the proportion of male fireflies unable to produce light is not significantly different from 0.0001, while the alternative hypothesis suggests that it is significantly lower than that. The entomologist's claim would support the alternative hypothesis if their research findings show that the proportion is indeed lower than 0.0001. In this case, the null hypothesis (H₀) and alternative hypothesis (H₁) can be represented using the parameter p, which is the true proportion of male fireflies unable to produce light due to a genetic mutation.

The null hypothesis would state that the proportion is equal to 10 in ten thousand, while the alternative hypothesis would state that the proportion is less than 10 in ten thousand.

Symbolically, this can be expressed as:

H₀: p = 0.001 (10/10,000)
H₁: p < 0.001

These hypotheses will help test the entomologist's claim in the scientific journal.

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Answer:

the ice becomes -20 degrees celcius colder

Explanation:

The naturally occurring the element x exists in three isotopic forms. The average atomic weight of x 28.544 amu.

Given that :

x- 28, Abundance % = 67.14 % = 0.6714

The atomic mass = 27.343 amu

x-29, Abundance % = 10.50 % = 0.1050

The atomic mass = 28.889 amu

x- 32, Abundance %  = 22.36 % = 0.2236

The atomic mass = 31.993 amu

The average atomic weight = ( 27.343 × 0.6714 ) + ( 28.889 × 0.1050) +

                                                          ( 31.993 × 0.2236)

                                                 = 18.358 + 3.0333 + 7.153

                                                 = 28.544 amu

Thus, the average atomic weight of naturally occurring element x exists in three isotopic forms 28.544 amu.

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