technician a says that reducing refrigerant pressure causes the refrigerant to absorb heat. technician b says reducing refrigerant pressure causes it to evaporate. who is correct?

Answer:

35 feet

Explanation:

Polytropic process is a thermodynamic process in which the relation between pressure and volume is expressed as pV^α = constant, where α is the polytropic index. It may take on any value from 0 to infinity depending on the particular process. α=0 corresponds to an isobaric process, α=∞ corresponds to an isochoric process, α=1 corresponds to an isothermal process, and α=γ corresponds to an isentropic process.

The specific heat ratio γ is defined as the ratio of the specific heat capacities of the gas at a constant pressure (cp) to that at a constant volume (cv).Hence, γ = cp/cv. Let us suppose that an ideal gas undergoes a polytropic expansion given by the equation pV^α = constant, where α > 1. For this process, the gas transfers heat to the surroundings. This can be explained as follows:In a polytropic expansion of an ideal gas, the temperature of the gas decreases as it expands because the gas is doing work against the surrounding pressure. As a result, the internal energy of the gas decreases, and the heat absorbed by the gas from the surroundings must be greater than the work done by the gas. This means that the gas absorbs heat from the surroundings.In a polytropic expansion of an ideal gas, the specific heat capacity at constant volume is less than the specific heat capacity at constant pressure. The ratio of the specific heat capacities, γ, is defined as cp/cv. Hence, the value of γ for an ideal gas is always greater than 1. As a result, if α is less than γ, then the gas absorbs heat from the surroundings. If α is greater than γ, then the gas transfers heat to the surroundings. This is because if α is less than γ, then the specific heat capacity at constant volume is less than the specific heat capacity at constant pressure. Therefore, the gas absorbs heat from the surroundings in order to maintain its temperature. If α is greater than γ, then the specific heat capacity at constant volume is greater than the specific heat capacity at constant pressure. Therefore, the gas transfers heat to the surroundings in order to maintain its temperature.

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The specific fuel requirement for flight under VFR during daylight hours in an airplane is to have enough fuel to fly to the first point of intended landing and then to fly for 30 minutes at normal cruising speed after that.

This fuel requirement is outlined in Federal Aviation Regulations (FAR) 91.151 and is designed to ensure that pilots have enough fuel to safely complete their planned flight and still have a reserve in case of unexpected circumstances. It is important for pilots to accurately calculate their fuel needs before each flight and to carry the appropriate amount of fuel to comply with this regulation.

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Answer:

\(T_o = 141.81 ^0C\)

Explanation:

Given that;

Thermal diffusivity \(\alpha = 5 \times 10 ^{-6} m^2/s\)

Thermal conductivity \(k = 20 \ W/m.K\)

Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K

Initial temperature = 150 ° C = (150+273) K = 423 K

Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K

Time = 40 seconds

Length = 20mm = 0.02 m

The objective is to determine the  temperature at the surface  at a depth of 20 mm after 40 seconds.

\(Bi = \dfrac{hL}{k}\)

\(Bi = \dfrac{20*0.02}{20}\)

Bi == 0.02

\(\tau = \dfrac{\alpha t}{L^2}\)

\(\tau= \dfrac{5*10^{-6 }* 40}{0.020^2}\)

\(\tau = 0.5\)

For a wall at 0.2 Bi

\(A_1 = 1.0311\)

\(\lambda _1 = 0.4328\)

Therefore;

\(\dfrac{T_o - T_{\infty}}{T_i - T_{\infty}}= A_1 e ^{-( \lambda_1^2 \ \tau)\)

\(\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.438^2 \times 0.5 )\)

\(\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.0959 )\)

\(\dfrac{T_o - 293 }{130}= 1.0311 \times 0.9085\)

\(\dfrac{T_o - 293 }{130}= 0.937\)

\(T_o - 293= 0.937 \times 130\)

\(T_o - 293= 121.81\)

\(T_o = 121.81+ 293\)

\(T_o = 414.81 \ K\)

\(T_o = (414.81 - 273)^0C\)

\(T_o = 141.81 ^0C\)

\(\boxed{ℒ_t[f(t)] =\frac{30}{{s}^{4} } - \frac{9}{s} + \frac{6}{s + 5} + \frac{1}{s - 3}} \)

This holds true because:

\(\lim_{s\to\infty} [\frac{30}{{s}^{4} } - \frac{9}{s} + \frac{6}{s + 5} + \frac{1}{s - 3}] =0 \)

[The answer is throughly verified, hence you can trust this :)]

Answer:

Explanation:

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged.

Answer:

Tech A is correct.          

Explanation:

A front-wheel-drive pulling to the left can result from several factors. One of them is definitely a faulty break.

A correct diagnosis linking the problem to the brakes is when there is an internal restriction and the pull is constant to one side and gets worse when the brakes are applied.

To confirm this, one would need to lift the vehicle and rotate each wheel by hand to check for excessive friction.

So the restriction may be caused by:

Cheers

When a marble is known to rolls on a track, it is one that is said to have kinetic energy (due to its motion) as well as potential energy (that is due to its position which is said to be relative to some reference point).

The potential energy of the marble is one that is based on its height that is seen above the reference point. The higher the marble is  said to be above the reference point, the  higher potential energy it has.

Therefore, If the track is shifted to go up the height of the marble and when it is above the reference point, the potential energy of the marble is one that will go up.

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Wood is a composite type of CMC. What is Wood. Wood is a natural composite that is formed from cellulose fibers embedded in a matrix of lignin.

It is a natural material that has been used for thousands of years to make structures, furniture, and other useful items. What are Composites. Composite materials are made up of two or more materials with distinct and they can be made by combining any type of material. The goal of combining different materials is to create a new material with better overall properties than any of the individual components. Wood is made up of cellulose fibers embedded in a matrix of lignin. Wood, which is a natural composite, is an example of a composite made up of organic materials. CMC (Ceramic matrix composites) and MMC (Metal matrix composites) are the other two composite types.
Wood is a natural composite material and does not fall under the categories of (a) CMC (Ceramic Matrix Composite), (b) MMC (Metal Matrix Composite), or (c) PMC (Polymer Matrix Composite).

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Explanation:

To determine the material's toughness in terms of energy absorbed, we need to calculate the area under the stress-strain curve up to the point of fracture. The energy absorbed is equal to the area under the curve.

Given:

Cross-sectional area (A) = 0.004 m²

Load (F) = 380 kN = 380,000 N

Young's modulus (E) = 200 GPa = 200,000 MPa = 200,000,000 N/m²

First, we need to calculate the stress (σ) using the formula:

σ = F / A

σ = 380,000 N / 0.004 m²

σ = 95,000,000 N/m² = 95 MPa

Next, we need to determine the strain (ε) using Hooke's law:

ε = σ / E

ε = 95,000,000 N/m² / 200,000,000 N/m²

ε = 0.475

Now, we can calculate the energy absorbed (U) using the formula:

U = 0.5 * σ * ε * A

U = 0.5 * 95,000,000 N/m² * 0.475 * 0.004 m²

U = 90,250 J = 90.25 kJ

Therefore, the material's toughness in terms of energy absorbed is 90.25 kJ.

Explanation:

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Decision variables are the number of fans and air conditioners, the objective function is to maximize the profit, and constraints are available wiring and drilling hours.

In this manufacturing problem, the Electrocomp Corporation produces two electrical products: air conditioners and large fans. The assembly process for each product requires a certain amount of wiring and drilling. To formulate the linear programming (LP) problem, we need to identify the decision variables, the objective function, and the constraint equations.

Decision variables: Decision variables represent the quantities of the products to be produced. In this case, we use x to represent the number of air conditioners produced and y to represent the number of large fans produced.

Objective function: The objective is to maximize the profit. The profit for each air conditioner sold is $30, and the profit for each fan assembled is $10. Thus, the objective function can be written as: Profit = 30x + 10y.

Constraint equations: The constraints are based on the available wiring and drilling hours. The problem states that there are 200 hours of wiring time available and up to 120 hours of drilling time. The wiring constraint equation is given by 5x + 3y ≤ 200, which represents the total wiring hours used by producing x air conditioners and y large fans. The drilling constraint equation is 6x + 2y ≤ 120, which represents the total drilling hours used. Additionally, the variables x and y should be non-negative, as we cannot produce negative quantities of products: x ≥ 0 and y ≥ 0.

By formulating the LP problem in this way, we have established the decision variables, objective function, and constraint equations that will guide the optimization process to determine the optimal production mix of air conditioners and large fans.

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Answer:

Explanation:

The idea of designing products with 100% performance while keeping the costs at only 10% is absurd and unrealistic.

Designing high-performance products requires investments in quality materials, advanced technologies, research and development, and skilled engineering expertise. These factors contribute to higher costs. Achieving such a drastic difference between performance and cost is not practically feasible.

Companies strive to find a balance between performance and cost by employing cost optimization strategies, value engineering, and efficiency improvements. They aim to maximize the performance-to-cost ratio but understand the inherent trade-offs involved.

While companies continuously work towards improving performance and reducing costs, it is crucial to have realistic expectations and understand the practical limitations of product design.

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Answer:

La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.

La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.

Explanation:

De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:

1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.

2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.

Mientras que el intercambiador de calor en contracorriente tiene que:

1) El fluido caliente y el fluido frío entran por lados opuestos.

2) El fluido caliente y el fluido frío salen por lados opuestos.

A continuación, anexamos los esquemas de perfil de cada intercambiador.

Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:

\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)

Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.

Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:

Intercambiador en paralelo

\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)

\(\Delta T_{1} = 177\,^{\circ}C\)

\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)

\(\Delta T_{2} = 23\,^{\circ}C\)

\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)

\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)

La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.

Intercambiador en contracorriente

\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)

\(\Delta T_{1} = 125\,^{\circ}C\)

\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)

\(\Delta T_{2} = 75\,^{\circ}C\)

\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)

\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)

La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.

Answer:

The issues related to the privacy are:

1. Informational privacy

2. Discrimination factors

3. Biased grouping on the basis of Data mining

4. Lack of consent

5. Morally wrong

6. Illegal distribution of information risks

7. Possibility of threat to life

Let's look at some major concerns:

1. Informational privacy : The concept of privacy of the personal information is totally nullified when the information is being used for a purpose other than the intended one for which it was given. This unethical use of information even for general purposes is not correct and is a matter of concern. It is more like using the sensitive data of others for personal benefit which is purely objectionable and raises security issues. Sometimes the data is also shared with the potential employers which might have certain impacts we are unaware of.

2. Data mining issues : The process of using a certain information to arrive and understand the trend and outcomes is called data mining. In this case, the consumer's data undergoes grouping and might get placed in the wrong group rather than the actual one. Also, there can be a case of biasing towards the groups which are not be focused on, or are not a part of the intended audience. This leads to the discrimination factors if we see it from a social point of view.

3. Lack of consent : Use of information without the consent or awareness of the consumers raises concern over the business ethics followed by the company. No one deserves the right to misuse information for his personal benefits without any of its information to the consumer. It is morally wrong and againt the work ethics. Moreover, it raises trust issues between the two involved, and hence is socially unacceptable.Explanation:

Answer:

engine suspension brake and more

Explanation:

Answer:

25 mins into hours = 0.416667 hours

25 inches as mm = 635

Explanation:

these categories

THE NATURE OF MATERIALS

Review Questions

2.1

The elements listed in the Periodic Table can be divided into three categories. What are these categories and give an example of each?

Answer

. The three types of elements are metals (e.g., aluminum), nonmetals (e.g., oxygen), and semimetals

Answer:

The FEM is a general numerical method for solving partial differential equations in two or three space variables (i.e., some boundary value problems). To solve a problem, the FEM subdivides a large system into smaller, simpler parts that are called finite elements.

The correct answer is  Valve clearance is not typically part of the check of the engine compartment done for a pre-trip inspection.

The other items you mentioned, such as engine oil level, condition of belts and hoses, and worn wiring insulation, are commonly included in a pre-trip inspection of the engine compartment.Engine oil level: This is a check to ensure that there is sufficient engine oil to lubricate the engine and that it is at the correct level.Coolant level: This is a check to ensure that there is sufficient coolant to maintain the engine at a safe operating temperature.Belts and hoses:

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The formula for axial compressive stress isσa = F/Awhere,σa is axial compressive stress F is force A is cross-sectional area.

How to find the axial compressive stress? A 1/2 - 0.5 lead screw's compressive force is 14 lbf. The formula for the area of a screw is A = πd²/4Where A is the cross-sectional area and d is the screw's diameter. Now, d = 1/2 - 0.5 = 0To find the cross-sectional area of the screw,

we will use the formula A = πd²/4 = π(0)²/4 = 0 As a result, we must consider the pitch of the screw to be the length we're compressing since the screw's diameter is negligible. The pitch of the screw is 0.5 inches. So, F = 14 lbfA = pitch = 0.5 in = 0.0417 ftσa = F/A = 14 lbf/0.0417 ft = 335.7 psithe axial compressive stress in psi is 335.7.

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The scale of the blueprint tells us the boundary of the drawing to real space. The correct option is a.

It is a photographic print in white on a bright blue background or blue on a white background, particularly useful for copying maps, mechanical drawings, and architect's designs

The plan of the construction is a project prediction that is slightly auto cad. The scale factor provides information on the dimensions and measurements of things represented by smaller copies in maps, blueprints, scale drawings, and scale models. The scale tells us how much actual length some length on the scale graphic represents.

Therefore, the correct option is a, Boundary.

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Answer: quarter turn

Explanation:  There are two basic types of valves ball valves and quarter turn valves or unblocks the hole, either allowing or preventing fluid flow.

Answer:

When a loss of charge exists, There is not a sufficient force to throttle the value open to it's correct position.

Answer:

yes

Explanation:

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A data professional must regularly deal with the issue of missing data. Although there are currently a lot of articles, blogs, and videos available.

I discovered that it is challenging to locate a piece of condensed, short information in a single location. That is why I made the effort to put this together in the hopes that any data enthusiast or practitioner will find it useful. Unavailable numbers that would have meaning if observed are referred to as missing data. Lost data might include a variety of things, such as a missing sequence, an incomplete feature, missing files, incomplete information, data entry errors, etc. In the actual world, most datasets have missing information. Prior to using missing data fields, those fields must be transformed so that they may be used for analysis and modeling.

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Answer:

The GMAW process commonly uses a constant voltage power source (GMAW-CV) that allows for a relatively constant welding voltage output over a range of welding currents. For GMAW-CV the welder selects the wire feed speed (WFS) on the wire feeder unit and an appropriate voltage on the welding power supply.