T/F the construction of psychological profiles is a process of mapping the characteristics of offenders of previously solved crimes and applying them to offenders of unsolved ones.

The cart travels approximately 3.33 meters when a man is pulling a cart having a mass of 2kg and an acceleration of 3 m/s².

To find the distance traveled by the cart, we'll use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. The formula for work is:
Work = Force x Distance x cos(θ)
Since the man is pulling the cart, the angle (θ) between the force and the distance is 0 degrees, and cos(0) = 1.

So the formula simplifies to:
Work = Force x Distance
The force acting on the cart can be found using Newton's second law of motion:
Force = Mass x Acceleration
Given that the mass of the cart is 2 kg and its acceleration is 3 m/s², we can calculate the force:
Force = (2 kg) x (3 m/s²) = 6 N
Now we can find the distance traveled using the work done (20 J) and the force (6 N):
20 J = (6 N) x Distance
To solve for distance, divide both sides by 6 N:
Distance = 20 J / 6 N = 10/3 meters ≈ 3.33 meters

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Therefore, Weber is the unit of magnetic flux. Magnetic flux density (B) is measured in tesla (T). option 1

The SI unit for magnetic flux is Weber. Magnetic flux is a measure of the amount of magnetic field passing through a given area. It is expressed in Weber (Wb) which is the SI unit of magnetic flux.

The magnetic flux passing through a surface is given by the formula

ϕ = B.A

where B is the magnetic field and A is the area of the surface.

A magnetic field of one Tesla (1 T) passing through an area of 1 m2 perpendicular to it produces a flux of 1 Wb.

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A sheet of paper in the rim of a foolscap is roughly 6 micrometres thick.

Example of calculating paper thickness: divide 2 inches by 500 since a ream of paper has 500 sheets. The thickness of a single sheet of paper will be calculated to be equal to 0.004 inches (or roughly 0.0102 cm) using this number. We can utilise the calliper unit of measure for values as small as that number.

Find the volume of a single sheet of paper first:

Volume of one sheet = (300 mm) x (200 mm) x (thickness)

So, we can also find the volume of the whole rim of foolscaps:

Volume of rim of foolscaps = (300 mm) x (200 mm) x (thickness of one sheet) x (500)

We can now set up an equation using the mass of the rim and the density of paper:

mass of rim = density of paper x volume of rim

We can assume that the density of paper is approximately 800 kg/m³. Converting the units to meters, we get:

mass of rim = density of paper x (0.3 m) x (0.2 m) x (thickness of one sheet) x (500) = 2 kg

Solving for the thickness of one sheet, we get:

thickness of one sheet = 2 kg / (density of paper x 0.3 m x 0.2 m x 500) = 6 x 10⁻⁶ m = 6 micrometers

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Answer:

the time with the force combined divided by time times the force

The exact value that would produce resonance in the system is 1.64. The amplitude of the oscillation when the system is at resonance is 9.32. The value of 8 is 1.46

Given the equation for the motion of a mass and spring is 3y″ + 8y' + 11y = 30 cos(yt). To find the value that would produce resonance in the system, we can use the formula for natural frequency.

f = √(k / m)

In the given context, "k" represents the spring constant, which characterizes the stiffness of the spring, and "m" denotes the mass of the object attached to the spring. Here, comparing the given equation to the standard second-order differential equation of an oscillator, we have:

3y″ + 8y' + 11y = 0

By comparing the given equation with the standard form Ay″ + By' + Cy = 0, we can assign the values A = 3, B = 8, and C = 11.

We can solve for the characteristic equation using: α = (-B ± √(B² - 4AC)) / 2A

Substituting the values, we get: α = (-8 ± √(8² - 4(3)(11))) / 2(3)α = (-8 ± √8) / 6

Thus, the two roots are α = -1.19 and -2.94.

Therefore, the value that would produce resonance in the system is the natural frequency, which is given by:

f = √(k / m)

We can solve for the unknown value by first determining the mass, m and then finding the spring constant, k. Using one of the roots of the characteristic equation, say α = -1.19, we can substitute this into the formula:

m = α²/k

Substituting the known values, we get: m = (-1.19)²/km = 1.416/k

To find the spring constant, we can use another known value. Let's use the value of y when t = 0. Thus,

3y″ + 8y' + 11y = 30 cos(0)3y″ + 8y' + 11y = 30 ⇒ 3(0)² + 8(0) + 11y = 30y = 30/11

Hence, the spring constant is given by:

k = (11/30)y''

Substituting the values, we get:

k = (11/30)(-1.19)²/1.416k = 3.22

Therefore, the natural frequency is: f = √(k/m)f = √(3.22/1.416)f = 1.64

The exact value that would produce resonance in the system is 1.64. The amplitude of the steady-state solution when the system is at resonance is given by: A = F/(k√(1 - (f/f₀)²))

where f₀ is the driving frequency, which is equal to the natural frequency, f = f₀ = 1.64, and F is the amplitude of the driving force, which is 30.

Substituting the values, we get: A = 30/(3.22√(1 - (1.64/1.64)²))A = 30/(3.22√(1 - 0))A = 30/3.22A = 9.32

The steady-state solution reaches an amplitude of 9.32 (rounded to two decimal places) when the system is at resonance.

In the absence of an external force, the oscillation of the spring can be expressed as Asin(Bt + φ), where A represents the amplitude, B corresponds to a certain parameter, t denotes time, and φ represents the phase constant.

B = √(k/m)

Substituting the known values, we get:

B = √(3.22/1.416)

B = 1.46

Therefore, the value of 8 is 1.46 (rounded to two decimal places).

The question should be:

The motion of a mass and spring is described by the following equation: 3y " + 8y + lly = 30 cos(yt) Identify the value of that would produce resonance in the system. Give an exact value, but you don't need to simplify radicals. What is the amplitude of the steady-state solution when the system is at resonance? Round your answer to two decimal places_ The amplitude is If there was no external force, the oscillation of the spring could be described in the form Asin( Bt + $). What is the value of 8? Give an exact value, but you don't need to simplify radicals.

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When electrons are emitted from the cathode, they can have zero velocity, one velocity, or a range of velocities depending on the conditions under which they are emitted.

For example, in a vacuum tube, electrons are emitted from the cathode due to thermionic emission and they typically have a range of velocities.

However, in a photoelectric effect experiment, electrons are emitted from the cathode due to the absorption of photons and they typically have a well-defined velocity determined by the energy of the incident photons.

Similarly, in a field emission experiment, electrons are emitted from the cathode due to a high electric field and they typically have a high velocity.

Therefore, the velocity of the electrons emitted from the cathode depends on the mechanism of emission and the conditions under which they are emitted.

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Answer: The minimum distance needed from the slits to the screen is approximately 2.46 meters when a He-Ne laser (λ = 633 nm) is used.

Explanation: The distance between successive bright fringes in a double-slit interference pattern is given by the equation:

d(sinθ) = mλ

where d is the distance between the slits, θ is the angle between the line connecting the center of the two slits and the line connecting a point on the screen to the center of the slits, m is an integer representing the order of the bright fringe, and λ is the wavelength of the light.

To find the minimum distance from the slits to the screen that will produce a fringe spacing of at least 1.25 cm, we can use the equation for the first-order bright fringe:

d(sinθ) = λ

where m = 1.

We can solve this equation for sinθ:

sinθ = λ/d

Substituting the values we were given, we get:

sinθ = (633 nm) / (0.250 mm) = 0.002532

Now we can use the small-angle approximation, which states that sinθ ≈ θ for small angles, to find the angle θ:

θ ≈ sinθ = 0.002532

Finally, we can use the following formula to find the distance from the slits to the screen:

y = L*tanθ

where y is the distance from the central maximum to the first-order bright fringe, L is the distance from the slits to the screen, and θ is the angle we just found.

Since we want the distance between successive bright fringes to be at least 1.25 cm, we can set y equal to 1.25 cm and solve for L:

L = y/tanθ = (1.25 cm) / tan(0.002532) ≈ 2.46 m

Therefore, the minimum distance needed from the slits to the screen is approximately 2.46 meters when a He-Ne laser (λ = 633 nm) is used.

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The tension in a tow rope,

a ) If it is completely horizontal = 850 N

b ) If it is 40° above the horizontal = 1103.9 N

F = m a

F = Net force

m = Mass

a = Acceleration

m = 1700 kg

a = 0.5 m / s²

∑ \(F_{x}\) = m a

T = m a

T = 1700 * 0.5

T = 850 N

b ) Assuming the tow rope is 40° above the horizontal,

θ = 40°

Resolving the tension force into its horizontal component,

Tx = T cos θ

∑ \(F_{x}\) = m \(a_{x}\)

Tx = 1700 * 0.5

T cos 40° = 850

T = 1103.9 N

Therefore, the tension in a tow rope,

a ) If it is completely horizontal = 850 N

b ) If it is 40° above the horizontal = 1103.9 N

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An electric dipole is in a uniform electric field. For The positive end of the dipole is in the direction of the electric field produces the least potential energy of the dipole.

The electric dipole moment is a condition that shows the properties of a dipole in an electric field based on a vector. The existence of a moment is the result of a dipole which consists of a pair of equal electric charges. In the calculation, each charge is given a different sign. Another marker is the relatively close distance to each other.

The electric dipole moment will give information about the electric field generated by a dipole. The electric potential that arises due to the electric field is affected by the distance and the length of the dipole.

The total amount of electric potential generated can be known at each point of the charge that appears. The observation of the electric dipole moment is beyond the reach of the standard model.

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Answer:

repeat using same variables

Explanation:

have peer repeat using same variables

Answer:

51.96 inches

Explanation:

Multiply 1.32 by 39.37

Answer:

52.0 inches

Explanation:

1.32 meters * 39.37  = 51.96 inches ~ 52.0 inches

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 35

We have the final answer as

Hope this helps you

Given data:

* The change in gravitational potential energy is 26500 J.

* The change in height of the diver is 33.0 m.

Solution:

The change in gravitational potential energy in terms of change in height of the diver is,

where m is the mass of diver, g is the acceleration due to gravity, dh is the change in height, and dU is the change in gravitational potential energy,

Substituting the known values,

The weight of the diver is,

Thus, weight of the diver is 803.03 N.

In a Zigbee device, the layer responsible for detecting the presence of an RF (Radio Frequency) signal in the currently selected channel is the Physical Layer (PHY).

The PHY layer in Zigbee is responsible for managing the transmission and reception of RF signals. It handles functions such as channel selection, modulation, demodulation, and signal detection. When a Zigbee device is operating in a specific channel, the PHY layer continuously monitors that channel for incoming RF signals. It performs energy detection, which involves measuring the power level of the received signal. By analyzing the received signal strength, the PHY layer can detect the presence of an RF signal in the selected channel.

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SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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Answer:

The leaves of an electroscope will return to their original position if the electroscope is not grounded because the final condition of the electroscope is the same as it was originally.

If however if one touches the terminal of an electroscope while the scope is exposed to a source of static electricity, and then the contact with the terminal is removed before the source of static electricity is taken away, then any excess electrons will remain on the electroscope and the leaves will remain diverged.

The minimum possible coefficient of static friction between the bike tires and the ground is 0.734.

The minimum possible coefficient of static friction is that at which the moving object is on the verge of the stopping state.

Radius of the curve, (R) = 20 m.

Velocity of the cyclist, (v) = 12 m/sec

g = 9.81 m/s²

On a circular curve, the cyclist will experience the centrifugal force(F) which acts outwards. This force is,

F = mv²/R

This centrifugal force(F) is balanced by the static friction force(Fₓ). Which is,

Static friction force = mg × coefficient of static friction(Ц)

mv²/R = mg × coefficient of static friction(Ц)

coefficient of static friction(Ц) = v²/gR

= (12×12)/(9.81×20)

= 0.734

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The frequency of the violet light is\(7.5 x 10^14 Hz (Hertz).\)

The frequency of the wave is determined by dividing the velocity of light by its wavelength.

\(v=f/λWhere:v = velocity of light f = frequency λ = wavelength of the light\)

The speed of light is\(3.00 x 10^8\) meters per second (m/s).

To convert 400 cm into meters, divide 400 by 100. 400 cm = 4 m

Therefore,λ = 4 meters

Plugging these values into the formula, \(v = (3.00 x 10^8 m/s) / (4 m) = 7.5 x 10^14 Hz\)

So, the frequency of the violet light with a wavelength of \(400 cm is 7.5 x 10^14 Hz.\)

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Answer: 1.51 km

Explanation:

Coulomb's Law: The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or,   \(\vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}\)

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

Given:

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N

k = 8.99 x 109Nm^2/C^2

So,

\(\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514 \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}\)

Therefore, the separation between the two charges (r) = 1.51 km

The Anti-Federalists argues against the expansions of the national power.

Anti-Federalism was able to late-18th-century politically movement that opposes the creations of a stronger U.S. federalism Government and whichs later opposes the notification of the 1787 Constitution. The previous constitutional, called the Articles of Confederation and Perpetually Union, gave state government's more authority.

The Anti-Federalists opposed the ratifications of the 1787 U.S. Constitutional because they're feared that the new national government wouldn't be too powerful and thus threaten individuals libertines, given the absence of a bill of rights.

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Answer

  96mph

Explanation:

You are given "144 miles in 90 minutes" and what you need to figure out is "144 km in X hours." To go from 90 min to hours, you can do 90 min * 1hr/60min = 1.5 hrs or 144 km in 1.5 hrs or 144 km per 1.5 hours. 144/1.5 = 96.

The mass of the mallard duck is approximately 1.24 kg if  the mass of a mallard duck whose speed is 8. 9 m/s

The mass of the mallard duck can be calculated using the equation for momentum:

momentum = mass x velocity

Given that the magnitude of the momentum is 11 kg·m/s and the speed is 8.9 m/s, we can rearrange the equation to solve for mass:

mass = momentum / velocity

Plugging in the given values:

mass = 11 kg·m/s / 8.9 m/s

Calculating this:

mass ≈ 1.24 kg

So, the mass of the mallard duck is approximately 1.24 kg.

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The angle of incline of the hill above the horizontal is 8.81°.

Since the hill has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction.

The tangent of the angle of the incline of the hill, Ф is

tanФ = vertical rise/horizontal distance = grade of hill

Now, the vertical rise = 15.5 m and the horizontal distance = 100.0 m

So, substituting the values of the variables into the equation, we have

tanФ = vertical rise/horizontal run

tanФ = 15.5 m/100.0 m

tanФ = 0.155

Taking inverse tan of both sides, we have

Ф = tan⁻¹(0.155)

Ф = 8.81°

So, the angle of incline of the hill above the horizontal is 8.81°.

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At equilibrium, the correct answer is option f) a and d. This means that at equilibrium, the concentrations of the reactants and products are constant (option a) and the rates of the forward and reverse reactions are equal (option d).

In a chemical reaction, equilibrium is the state in which the rate of the forward reaction is equal to the rate of the reverse reaction. This means that there is no net change in the concentrations of the reactants and products, and the reaction appears to have stopped. However, the reaction is still occurring at the molecular level, with the forward and reverse reactions happening at the same rate. This is why the concentrations of the reactants and products remain constant at equilibrium.

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Answer:

Período del tambor: \(T = 0.25\,s\), fuerza sobre la prenda: \(F \approx 80.852\,N\), velocidad lineal del tambor: \(v \approx 10.053\,\frac{m}{s}\), velocidad angular del tambor: \(\omega \approx 25.133\,\frac{rad}{s}\).

Explanation:

La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:

"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."

El tambor gira a velocidad angular constante (\(\omega\)), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga (\(a\)), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor (\(T\)), en segundos:

\(T = \frac{1}{f}\) (1)

Donde \(f\) es la frecuencia, en hertz.

(\(f = 4\,hz\))

\(T = \frac{1}{4\,hz}\)

\(T = 0.25\,s\)

Ahora determinamos la fuerza aplicada sobre la prenda (\(F\)), en newtons:

\(F = m\cdot a\) (2)

\(F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}\) (2b)

Donde:

\(m\) - Masa de la prenda, en kilogramos.

\(r\) - Radio interior del tambor, en metros.

(\(m = 0.32\,kg\), \(r = 0.4\,m\), \(T = 0.25\,s\))

\(F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}\)

\(F \approx 80.852\,N\)

La velocidad lineal de la lavadora es:

\(v = \frac{2\pi\cdot r}{T}\) (3)

(\(r = 0.4\,m\), \(T = 0.25\,s\))

\(v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}\)

\(v \approx 10.053\,\frac{m}{s}\)

Y la velocidad angular del tambor de la lavadora:

\(\omega = \frac{2\pi}{T}\)

(\(T = 0.25\,s\))

\(\omega = \frac{2\pi}{0.25\,s}\)

\(\omega \approx 25.133\,\frac{rad}{s}\)

If two identical airplanes are loaded such that one has the CG at the forward limit, and the other then the correct answer is: CG will not affect speed.

The position of the center of gravity (CG) affects the stability and control of an airplane, but it does not directly affect its speed. The speed of an airplane is determined by factors such as engine power, aerodynamic design, and external conditions (e.g., wind). The position of the CG primarily influences the longitudinal stability of the aircraft and its tendency to pitch up or down.

Therefore, the speed of the airplanes, in this case, would not be affected by the position of the CG. The airplane with the CG at the forward or aft limit may have different stability characteristics, but their speeds would not be inherently different due to CG placement alone.

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