If the length of a guitar string that vibrates freely is 64 cm and its fundamental frequency is 330 Hz. If the string is pressed down at a certain fret, the length of the vibrating section of the string is reduced to two-thirds of its original length. The new fundamental frequency is 401 Hz.
When a string is played, it vibrates at a certain frequency that is determined by the length, tension, and mass per unit length of the string. This frequency is called the fundamental frequency. When a finger is pressed on a string, the length of the vibrating section of the string is shortened, which causes the frequency to increase. The length of the string that vibrates is determined by the position of the fret. So, if the string is pressed down at the fret, the length of the vibrating section of the string is reduced to two-thirds of its original length.
Here, the length of the vibrating section of the string is 2/3 times the original length
= (2/3) x 64.0 cm
= 42.7 cm.
Now, we can calculate the new fundamental frequency using the formula:
f = (v/2L) where f is the frequency, v is the velocity of the wave, and L is the length of the vibrating section of the string. We know that the velocity of the wave is constant for a given medium, and we can assume that it is equal to the speed of sound in air (v = 343 m/s). Therefore, the new fundamental frequency is:
f = (343/2 x 0.427) Hz
= 401 Hz.
As a result, the pitch of the note being played changes. In this case, the length of the vibrating section of the string is two-thirds of the original length because the fret is located at that position. The new fundamental frequency of the string is calculated to be 401 Hz using the formula.
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An airplane with an airspeed of 120.0 km/h has a heading of 30.0° east of north in a wind that is blowing toward the west at 30.0 km/h. What is the approximate speed of the plane relative to the ground?
The airplane's airspeed is 120.0 km/h, with a heading of 30.0° east of north. We can break this down into northward and eastward components. The northward component is 120.0 km/h * cos(30.0°) ≈ 103.9 km/h, and the eastward component is 120.0 km/h * sin(30.0°) ≈ 60.0 km/h.
The wind is blowing towards the west at 30.0 km/h, so it has a westward component of 30.0 km/h.
To find the airplane's ground speed, we need to combine these components. The northward component remains unchanged at 103.9 km/h, while the eastward component gets reduced due to the westward wind, giving us 60.0 km/h - 30.0 km/h = 30.0 km/h.
Now, we can find the resultant ground speed using the Pythagorean theorem: √((103.9 km/h)^2 + (30.0 km/h)^2) ≈ 107.9 km/h.
So, the approximate speed of the plane relative to the ground is 107.9 km/h.
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A 56 kg student stands atop aspring in an elevator that is acceleratingupward at 3.5 m/s2m/s2. The springconstant is 2900 N/mN/m. Part A Byhow much is the spring compressed
Given data,
Mass,
\(m=56\text{ kg}\)Acceleration,
\(a=3.5m/s^2\)Spring constant,
\(k=2900\text{ N/m}\)Acceleration due to gravity,
\(g=9.8m/s^2\)Accelerating upward,
\(\begin{gathered} a^{\prime}=(a+g) \\ a^{\prime}=3.5m/s^2+9.8m/s^2 \\ a^{\prime}=13.3m/s^2 \end{gathered}\)Comsider the formula for force.
\(\begin{gathered} F=kx \\ ma^{\prime}=kx \\ 56kg\times13.3m/s^2=2900\text{ N/m}\times x \\ x=25.68\text{ cm} \end{gathered}\)Thus, the spring compression is 25.68 cm.
Select the correct answer. An object has one force acting on it. It is a 33-newton force pointing downward. To create a net force of zero on the object, which force must be applied to it? Group of answer choices a 1-newton force pointing right a 0-newton force pointing downward a 33-newton force pointing upward a 33-newton force pointing left a 1-newton force pointing upward
Answer:
33 Newton upwards to get a net force of zero.
Answer:
The answer is 33 newtons with a net force of 0
Explanation:
A disk with mass m = 9. 4 kg and radius r = 0. 3 m begins at rest and accelerates uniformly for t = 17. 9 s, to a final angular speed of ω = 27 rad/s. What is the angular acceleration of the disk?
A disk with mass m = 9. 4 kg and radius r = 0. 3 m begins at rest and accelerates uniformly for t = 17. 9 s, to a final angular speed of ω = 27 rad/s. The angular acceleration of the disk is 1.51 rad/s².
The angular acceleration of the disk can be calculated using the following formula:α=ωf−ωi/t
whereα is the angular acceleration of the disk,ωf is the final angular speed of the disk,ωi is the initial angular speed of the disk, and t is the time taken for the disk to accelerate uniformly.
Given that the disk has a mass of m = 9.4 kg and a radius of r = 0.3 m and starts from rest and accelerates uniformly for t = 17.9 s, to a final angular speed of ω = 27 rad/s, we can calculate its angular acceleration as follows:α = ω/t = (27 rad/s) / (17.9 s) = 1.51 rad/s²
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If the region between the plates is filled with a material whose dielectric constant is 5.6, what is the new capacitance (in pf)?
The new capacitance can be calculated by multiplying the original capacitance by the dielectric constant of the material.
The capacitance of a parallel plate capacitor is given by the formula C = ε₀A/d, where C is the capacitance, ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.
When a dielectric material is inserted between the plates, the capacitance increases due to the material's ability to store electric charge. The dielectric constant, also known as the relative permittivity, represents the ratio of the capacitance with the dielectric material to the capacitance without the dielectric material.
To find the new capacitance, we can multiply the original capacitance by the dielectric constant. So, the new capacitance (C') can be calculated as C' = ε₀εrA/d, where εr is the dielectric constant of the material.
In this case, since the dielectric constant is given as 5.6, we can simply multiply the original capacitance by 5.6 to obtain the new capacitance. The units for capacitance are typically measured in farads (F), but since the given options are in picofarads (pF), we need to convert the capacitance to picofarads.
Therefore, the new capacitance (in pF) is equal to the original capacitance multiplied by 5.6.
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Un vehículo que desciende hacia la luna tiene una velocidad vertical hacia la superficie de la luna de 35 m/s. Al mismo tiempo, tiene una velocidad horizontal de 55m/s. ¿Cuál es la velocidad del vehículo en su trayectoria de descenso? ¿Qué ángulo forma la trayectoria con la vertical?
Answer:
1. La velocidad del vehículo en su trayectoria de descenso es 65.2 m/s.
2. El vehículo forma un ángulo de 57.5° con la vertical.
Explanation:
1. La magnitud de la velocidad del vehículo está dada por la suma de las componentes del vector en la dirección vertical (y) y horizontal (x):
\( v^{2} = v_{x}^{2} + v_{y}^{2} \)
\( v = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(55 m/s)^{2} + (35 m/s)^{2}} = 65.2 m/s \)
Entonces, la velocidad del vehículo en su trayectoria de descenso es 65.2 m/s.
2. El ángulo que forma la trayectoria con la vertical se puede calcular con trigonometría:
\( tan(\theta) = \frac{v_{x}}{v_{y}} \)
\( \theta = tan^{-1}(\frac{v_{x}}{v_{y}}) = tan^{-1}(\frac{55}{35}) = 57.5 ^{\circ} \)
Por lo tanto, el vehículo forma un ángulo de 57.5° con la vertical.
Espero que te sea de utilidad!
A skater holds her arms outstretched as she spins at 120 rpm. Part A What is the speed of her hands if they are 140 cm apart? Express your answer with the appropriate units
According to the question the speed of the skater's hands is 528 m/min.
To calculate the speed of the skater's hands, we can use the formula:
Speed = Circumference * Revolutions per minute
Given that the skater's hands are 140 cm apart and she spins at 120 rpm, we need to calculate the circumference of the circle formed by her hands.
The circumference of a circle is given by the formula:
Circumference = 2 * π * radius.
In this case, the radius is half the distance between the skater's hands, which is 140 cm / 2 = 70 cm.
Converting the radius to meters, we have 70 cm = 0.7 m.
Now we can calculate the circumference:
Circumference = 2 * π * 0.7 m = 4.4 m (rounded to one decimal place).
Finally, we can calculate the speed of the skater's hands:
Speed = Circumference * Revolutions per minute
= 4.4 m * 120 rpm
= 528 m/min.
Therefore, the speed of the skater's hands is 528 m/min.
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For a series circuit, as lights are added, the voltage across each bulb increases/ decreases/ remains the same ?
For a series circuit, as lights are added, the current across each bulb increases/ decreases/ or remains the same ?
For a series circuit, as lights are added, the current across each bulb decreases.
What is the speed of sound (in m/s) in carbon dioxide at the normal boiling temperature of water?
The speed of the sound in carbon dioxide at normal boiling temperature of water is approximately 268.5 m/s.
The speed of sound in a gas depends on the temperature, pressure, and molecular properties of the gas. The speed of sound in carbon dioxide (CO₂) can be calculated using the following formula;
v = √(γRT/M)
where v is speed of sound, γ is adiabatic index (a property of the gas), R is universal gas constant, T is temperature in Kelvin, and M is molar mass of the gas.
At the normal boiling temperature of water (100°C or 373 K), the density of carbon dioxide is approximately 1.98 kg/m³ and the molar mass of CO₂ is 44.01 g/mol. The adiabatic index for CO₂ is 1.3.
Substituting these values into the formula, we get;
v = √(γRT/M) = √[(1.3)(8.314 J/mol·K)(373 K)/(0.04401 kg/mol)]
≈ 268.5 m/s
Therefore, the speed of sound is 268.5 m/s.
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the wavelength of blue light is greater than red light and its energy is greater. True or False
Answer:
False
Explanation:
The wavelength of red light is greater than blue light. Its energy is less.
Both statements are false. Search for a graphic of the "electromagnetic spectrum." Many will note the wavelengths of the various regions (IR, UV, Visible, Microwave, etc. Observe the relationships. Red has less energy than blue. That sounds counterintuitive, based on artist's use of red to connote fire or some energetic situation. But the red in a fire obscures human vision to the blues and UV radiation from the same source. A welder uses a UV shield to blocjk these wavelengths, to avoid eye damage.
A ball is thrown up into the air with an initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed for the ball to reach its max height.
Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f} =v_{o} -g*t\)
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
\(y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\\)
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
A child is perched perilously above a 150m ravine. The child has a mass of 45kg. How much
gravitational potential energy does the child have?
Answer:
U = 66,150 J
Explanation:
Gravitational Potential Energy
Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or \(9.8\ m/s^2\).
The child of mass m=45 Kg is perched above a h=150 m ravine. His gravitational potential energy is:
\(U=45~Kg\cdot 9.8\ m/s^2\cdot 150\ m\)
U = 66,150 J
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Can be Doppler shifted, reflected, refracted,
diffracted, and can undergo constructive and
destructive interference.
A wave experiences reflection, refraction, Doppler effect, diffraction, and it can undergo both constructive and destructive interference.
A wave can be defined as a disturbance in a medium that progressively transports energy from its source to another location, without transporting matter.
In Physics, there are two main (2) types of wave and these are;
Mechanical waves: an example is sound wave, which requires a medium for its propagation.Electromagnetic waves: an example is light wave, which doesn't require a medium for its propagation and can travel through a vacuum or an empty space.Basically, some of the phenomenon and properties associated with waves include the following:
I. Doppler shift (Doppler effect).
II. Reflection.
III. Refraction.
IV. Diffraction.
V. Constructive interference.
VI. Destructive interference.
In conclusion, all waveform can be Doppler shifted, reflected, refracted, diffracted, and can undergo constructive and destructive interference.
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A boy holds a toy soldier in front of a concave mirror. The focal length of the mirror is 0.45m and the boy holds the toy soldier at a distance of 0.25m from the mirror. Find the image distance.
The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.
What is image distance?When an object is put in front of a plane mirror, this is the distance between the image that results and the focus.
To calculate the image distance, we use the formula below.
Formula:
1/f = 1/u+1/v Equation 1
Where:
f = Focal length of the mirror
v = Image distance
u = object distance
From the question,
Given:
f = 0.45 m
u = 0.25 m
Equation 1 can be changed to reflect these numbers to determine the image distance.
1/0.45 = 1/0.25 + 1/v
2.22 = 4+1/v
1/v = 2.22-4
1/v = -1.78
v = 1/(-1.78)
v = -0.56 m
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In the original Milgram study, what percentage of participants displayed complete compliance, administering shocks of 450 volts ____ that they believed were lethal.
In the original Milgram study, what percentage of participants displayed complete compliance, administering shocks of 450 volts About 40% that they believed were lethal.
Overview on original Milgram studyThe Milgram experiment(s) on conformity to authoritative persons were a series of social psychology research carried out by Yale University psychologist Stanley Milgram. The willingness of 40 research participants, males from various occupations and educational levels, to follow orders from an authority figure that conflicted with their own moral values was examined.
The volunteers were led to believe that they were taking part in a different experiment in which they had to administer electric shocks to a "learner." If these electric shocks had been real, they would have increased over time to lethal levels.
Unexpectedly, the experiment revealed that a very high percentage of the lab rats would fully comply with the instructions, with every person reaching 300 volts and 65% reaching the full 450 volts.
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Explain how electrostatic works on an atom level
At an atomic level, electrostatics is responsible for most of the physical phenomena that we encounter in our everyday life. Every object we see around us, such as chairs, buildings, and people, are made up of atoms, and every atom has electrons that are negatively charged, protons that are positively charged, and neutrons that have no charge.
Electrostatics is the study of electric charges at rest and of the forces and fields associated with these charges. Electrons are held in atoms by the attraction of the positive nucleus for the negative charge of the electrons. This attraction is known as electrostatic force. The protons in the nucleus are also held together by electrostatic forces, which are much stronger than those that bind electrons to the nucleus.
The forces between charged objects are governed by Coulomb's Law. This law states that the force between two charged objects is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges have the same sign, the force is repulsive; if they have opposite signs, the force is attractive.
Electrostatic forces play an important role in many physical phenomena, such as the attraction of dust particles to a TV screen, and the Van de Graaff generator, which uses electrostatic forces to build up very high voltages.
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13. To see cars in your blind spots, you should: A. Look in the inside rearview mirror B. Look in the outside rearview mirror C. Turn your head
To see cars in your blind spots, the most effective method is to turn your head (option C). While inside and outside rearview mirrors (options A and B) provide valuable assistance in monitoring the traffic behind your vehicle, they have limitations when it comes to detecting vehicles in your blind spots.
Blind spots are areas around your vehicle that are not visible in your mirrors or through peripheral vision. They exist due to the design and positioning of the vehicle's pillars, windows, and rearview mirrors. Depending on your vehicle's size and configuration, blind spots can vary in size and location.
By turning your head and physically looking over your shoulder, you can directly check the blind spots and gather more accurate information about any vehicles that may be in those areas. This action provides an additional level of assurance before changing lanes or making any lateral movements on the road.
While checking your blind spots, it's important to maintain control of the steering wheel and keep your eyes on the road ahead as much as possible. Use a quick glance over your shoulder to check the blind spots without excessively turning your body or taking your eyes off the road for an extended period.
Relying solely on the inside rearview mirror or outside rearview mirrors may not provide a complete view of the blind spots. Depending on factors such as the size and positioning of your vehicle, the blind spots can vary. Therefore, developing the habit of turning your head and visually checking the blind spots is crucial for safe driving.
In conclusion, to see cars in your blind spots, it is best to turn your head (option C). While rearview mirrors are valuable tools for monitoring traffic, they have limitations when it comes to detecting vehicles in the blind spots. By physically looking over your shoulder, you can ensure a comprehensive view of the surrounding traffic and minimize the risk of accidents caused by cars in the blind spots. Remember to maintain control of the steering wheel and keep your eyes on the road while checking the blind spots.
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imagine you are an astronomer outside our solar system, how long would you have to observe the sun in order to deetect four dips in the suns brightness due to earth?
The time required to detect four dips in the sun's brightness caused by Earth passing in front of it would depend on several factors, such as the distance between our solar system and the observer, the sensitivity of the observer's instruments, and the timing of the observations.
The further away the observer is, the longer it would take for them to observe the Earth passing in front of the sun. For instance, if the observer were located in the nearest star system to ours, Proxima Centauri, which is approximately 4.2 light-years away, it would take about 8.4 years for the observer to detect four dips in brightness caused by Earth passing in front of the sun. This is because it would take that long for the light emitted by the sun to reach Proxima Centauri, making it possible for the observer to detect the changes in brightness caused by the Earth's transit.
Additionally, the sensitivity of the observer's instruments would also impact the time required to detect these dips in brightness. The more sensitive the instruments, the easier it would be to detect small changes in the sun's brightness caused by the Earth's transit. However, if the instruments are not sensitive enough, it could take longer to detect the dips in brightness, even if the observer is relatively close to our solar system.
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when you are on the top floor of a building, your weight is how large compared to when you are on the ground floor?
When you are on the top floor of a building, your weight is the same as when you are on the ground floor.
What is weight?The weight of an object is the measure of the force of gravity acting on the object. The weight of an object is proportional to its mass and the acceleration due to gravity acting on it. The mass of an object is the measure of the amount of matter it contains. The mass of an object is constant, whereas its weight varies with the acceleration due to gravity acting on it.
Since the acceleration due to gravity acting on an object near the surface of the Earth is almost constant, the weight of an object on the ground floor of a building is the same as its weight on the top floor of the same building. In other words, the weight of an object does not change with height as long as the object is at rest or moving with a constant velocity.
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A vector starts at the point (0, 0) and ends at (3, 1). What is the magnitude and direction of the displacement?
Answer:
tbh vector does not have any direction at all the answer is 0
A 30 kg kid on a bike is moving in the positive direction at 7 m/s.
6. A) Calculate: What is the kid's momentum (give the magnitude and the direction)? Show your work on your answer sheet: defined variables, formula used, numbers plugged in, answer with units. Round your answer to the nearest tenth if necessary.
The momentum of the kid weighing 30kg is 210kgm/s.
How to calculate momentum?Momentum in physics refers to the tendency of a body to maintain its inertial motion i.e. the product of its mass and velocity, or the vector sum of the products of its masses and velocities.
According to this question, a 30kg kid on a bike is moving in the positive direction at 7 m/s. The momentum is calculated thus;
Momentum = 30kg × 7m/s = 210kgm/s
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Question 66 Marks: 1 It is estimated that at any given time, there is/are _____ times more water stored underground than in all the surface streams and lakes.
Choose one answer. a. 5 times as much b. 20 to 30 times as much c. one-half as much d. one-tenth as much
It is estimated that there is b. 20 to 30 times as much more water stored underground than in all the surface streams and lakes.
This significant amount of water is found in aquifers, which are underground layers of rock, sand, and gravel that hold water. These underground reservoirs play a crucial role in providing freshwater to communities, agriculture, and industries worldwide.
Surface water, on the other hand, consists of lakes, rivers, and streams, which are visible and more commonly utilized sources of water. While both underground and surface water sources are essential for sustaining life on Earth, it's crucial to understand the vast difference in their quantities to efficiently manage and protect these valuable resources. It is estimated that there is b. 20 to 30 times as much more water stored underground than in all the surface streams and lakes.
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Prompt. Explain the difference between a solar eclipse and a lunar eclipse. Be sure to explain the positions of the earth moon and sun for each scenario
Answer:
Explanation:
Eclipse happens when a large object gets in the way of another object; casting its shadow over it.
Solar eclipse happens when the moon get in between the sun and earth. It blocks sun light and causes its shadow over the sun as seen from earth.
Lunar eclipse happens when the earth is in between the sun and moon. It blocks sun light from reflecting off the moon surface so there is a shadow on the moon as seen from earth.
A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.
Help me with this please !!
Answer:the basic building block of chemistry
an atom
1. How much work is done when a 24 kg object
accelerates 2m/s² and moves 4 m?
Answer:
192 joules
Explanation :
W=Force*distance
Force=m*a
mass=24kg
acceleration=2m/s²
Force=24*2=48
Work done=Force*distance
Force=48
distance=4
Force*distance=48*4=192J
name the proces by which heat flows in solids
Answer:
conduction
Explanation:
conduction is the movement of heat from one point to another on a metal.
Hope it helps.
The units of energy on your parents' power bill are kWh (kilowatt hour) and a Watt is a J/s (joule per second). If your family uses 3000 kWh, how many joules did your family use?
Answer:
3000000
Explanation:
1 kilowatt=1000 watts
3000×1000
3000000
the pressure exerted by a phonograph needle on a record is surprisingly large. if the equivalent of 1.00 g is supported by a needle, the tip of which is a circle 0.200 mm in radius, what pressure is exerted on the record in n/m2 (1 pa
77,985.92 N/m^2 pressure is exerted on the record in n/m2
Equation: Pressure, P = Force, F / Surface Area, A
Force, F = Weight, mg = 1/1000*9.81 = 9.81 * 10-3 N
Surface area, A = πr^2
= π*(0.200 / 1000)^2
= 1.2566 * 10-7 m2
P = F / A = (9.81*10^–3)/(1.2566*10^–7) = 77,985.92 N/m^2 as a result.
The normal force exerted by the record is supporting the needle of the record player, and this normal force will be equal to the force of gravity pulling the needle downward. If we were to look at the end of the needle, its radius would be a circle with a radius of 0.200 millimeters. Since the prefix "milli-" indicates times 10 to minus 3, we will translate that into 0.200 times 10 to minus 3 meters.
And since this region of the circle will be r squared, we can calculate the pressure at that point. The force per area, or mg, is what determines pressure. Therefore, mg equals the force, and r squared equals the area. Therefore, the pressure equals 7.80 times 10 to the 4 pascals, or 1.00 times 10 to the minus 3 kilograms times 9.80 newtons per kilogram divided by times its radius in meters squared.
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