the amount of friction between train wheels and the track is based on the normal force and the coefficient of friction between the dry steel of the wheel and the dry steel of the track. If the train has a mass of 188000kg and the coefficient of friction on dry steel is 0.41(static) and 0.38(kinetic) what is the amount of static and kinetic friction force available to the wheels? show your work

Answer:

The period of a simple pendulum is the time it takes for the pendulum to complete one full swing. This is equal to the reciprocal of the frequency, which means that if the frequency of a simple pendulum is 0.263 Hz, its period would be 1/0.263 = 3.80 seconds. This is the time it would take for the pendulum to swing back and forth once at the same location on the Earth's surface.

Explanation:

Answer:

5m/s²

Explanation:

The force exerted on an object is calculated using the formula ;

F = ma

Note that the upward force (F) is 148N

Where;

F = force (N)

m = mass (kg)

a = acceleration (m/s²)

The downward force towards gravity is F' = mg

F' = 10 × 9.8m/s²

F' = 98N

Net force (F - F') = m × a

148 - 98 = 10 × a

50 = 10a

a = 50/10

a = 5m/s²

Newton's third law of motion sates that force is directly proportional to the rate of change of momentum produced

(a) The final speeds of the ice sleds is approximately 0.49 m/s each

(b) The impulse on the cat is 11.0715 kg·m/s

(c) The average force on the right sled is 922.625 N

The reason for arriving at the above values is as follows:

The given parameters are;

The masses of the two ice sleds, m₁ = m₂ = 22.7 kg

The initial speed of the ice, v₁ = v₂ = 0

The mass of the cat, m₃ = 3.63 kg

The initial speed of the cat, v₃ = 0

The horizontal speed of the cat, v₃ = 3.05 m/s

(a) The required parameter:

The final speed of the two sleds

For the first jump to the right, we have;

By the law of conservation of momentum

Initial momentum = Final momentum

∴ m₁ × v₁ + m₃ × v₃ = m₁ × v₁' + m₃ × v₃'

Where;

v₁' = The final velocity of the ice sled on the left

v₃' = The final velocity of the cat

Plugging in the values gives;

22.7 kg × 0 + 3.63 × 0 = 22.7 × v₁' + 3.63 × 3.05

∴  22.7 × v₁'  = -3.63 × 3.05

v₁' =  -3.63 × 3.05/22.7 ≈ -0.49

The final velocity of the ice sled on the left, v₁' ≈ -0.49 m/s (opposite to the direction to the motion of the cat)

The final speed ≈ 0.49 m/s

For the second jump to the left, we have;

By conservation of momentum law,  m₂ × v₂ + m₃ × v₃ = m₂ × v₂' + m₃ × v₃'

Where;

v₂' = The final velocity of the ice sled on the right

v₃' = The final velocity of the cat

Plugging in the values gives;

22.7 kg × 0 + 3.63 × 0 = 22.7 × v₂' + 3.63 × 3.05

∴  22.7 × v₂'  = -3.63 × 3.05

v₂' =  -3.63 × 3.05/22.7 ≈ -0.49

The final velocity of the ice sled on the right = -0.49 m/s (opposite to the direction to the motion of the cat)

The final speed ≈ 0.49 m/s

(b) The required parameter;

The impulse of the force

The impulse on the cat = Mass of the cat × Change in velocity

The change in velocity, Δv = Initial velocity - Final velocity

Where;

The initial velocity = The velocity of the cat before it lands = 3.05 m/s

The final velocity = The velocity of the cat after coming to rest =

∴ Δv = 3.05 m/s - 0 = 3.05 m/s

The impulse on the cat = 3.63 kg × 3.05 m/s = 11.0715 kg·m/s

(c) The required information

The average velocity

Impulse = \(F_{average}\) × Δt

Where;

Δt = The time of collision = The time it takes the cat to finish landing = 12 ms

12 ms = 12/1000 s = 0.012 s

We get;

\(F_{average} = \mathbf{\dfrac{Impulse}{\Delta \ t}}\)

∴ \(F_{average} = \dfrac{11.0715 \ kg \cdot m/s}{0.012 \ s} = 922.625 \ kg\cdot m/s^2 = 922.625 \ N\)  

The average force on the right sled applied by the cat while landing, \(\mathbf{F_{average}}\) = 922.625 N

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Answer:

Title) 50 (Bii) 45

Explanation:reflection, same angle as incidence

Answer:45

Explanation:

Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Answer:

did u know there's no such thing as "pear cider."

Explanation:

Answer:

V = 0.0283 m³ = 28300 cm³

T₂ = 1200 K

Explanation:

The volume of the gas can be determined by using General Gas Equation:

PV = nRT

where,

P = Pressure of Gas = (72 cm of Hg)(1333.2239 Pa/cm of Hg) = 95992.12 Pa

V = Volume of Gas = ?

n = no. of moles = mass/molar mass = (35 g)/(32 g/mol) = 1.09 mol

R = General Gas Constant = 8.314 J/ mol.k

T = Temperature of Gas = 27°C + 273 = 300 k

Therefore,

(95992.12 Pa)(V) = (1.09 mol)(8.314 J/mol.k)(300 k)

V = 2718.678 J/95992.12 Pa

V = 0.0283 m³ = 28300 cm³

The Kinetic Energy of gas molecule is given as:

K.E = (3/2)(KT)

Also,

K.E = (1/2)(mv²)

Comparing both equations, we get:

(3/2)(KT) = (1/2)(mv²)

v² = 3KT/m

v = √(3KT/m)

where,

v = r.m.s velocity

K = Boltzamn Constant

T = Absolute Temperature

m = mass of gas molecule

At T₁ = 300 K, v = v₁

v₁ = √(3K*300/m)

v₁ = √(900 K/m)

Now, for v₂ = 2v₁ (double r.m.s velocity), T₂ = ?

v₂ = 2v₁ = √(3KT₂/m)

using value of v₁:

2√(900 K/m) = √(3KT₂/m)

4(900) = 3 T₂

T₂ = 1200 K

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Answer:

74.0 meters

Explanation:

We can use the kinematic equation for displacement with constant acceleration to solve this problem:

Δy = v0t + 1/2at^2

where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.

Plugging in the given values, we get:

Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2

Δy = 74.0 m

Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.

Answer:

both

the cleen soap is falling on a nasty floof cleans the floor and gets dirty

Explanation:

Answer:

UH UH

Explanation:

When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

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Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

Answer:

t = 66.7 s

Explanation:

Given that,

Speed of a hare, v = 15 m/s

Speed of a turbocharged tortoise, v' = 3 m/s

The hare in a 250 meter race

Let the Hare takes time t. It can be calculated as follows :

\(t=\dfrac{250}{15}=16.67\ s\)

Let a turbocharged tortoise takes t'. It can be calulated as follows :

\(t'=\dfrac{250}{3}= 83.33\ s\)

To tie the race, required time is given by :

\(\Delta t = t'-t\\\\=83.33-16.67\\\\=66.66\ s\\\\\approx 66.7\ s\)

Hence, the correct option is (b) i.e. 66.7 seconds.

Answer:

a) the torque required is  10.53 N-m

b) The magnitude force applied tangentially is 12.33 N

Explanation:

Given the data in the question;

mass m = 1.765 kg

radius r = 0.854 m

first we calculate the moment of inertia;

\(I\) = \(\frac{2}{5}\)mr²

we substitute

\(I\) = \(\frac{2}{5}\) × 1.765 × (0.854)²

\(I\) = 0.514897 kg.m²

a)

Find the torque required to bring the sphere from rest to an angular velocity of 317 rad/s, clockwise, in 15.5 s

ω\(_{initial\) = 0

ω\(_{final\) = 317 rad/s

t = 15.5 s

we know that; ω\(_{final\) = ω\(_{initial\) + ∝t

so we substitute

317 = 0 + ∝(15.5)

∝ = 317 / 15.5

∝ = 20.4514 rad/s²

so

ζ = \(I\) × ∝

we substitute

ζ = 0.514897 × 20.4514

ζ = 10.53 N-m

Therefore, the torque required is  10.53 N-m

b)

What magnitude force applied tangentially at the equator would provide the needed torque.

ζ = F × r

we substitute

10.53  = F × 0.854

F = 10.53 / 0.854

F = 12.33 N

Therefore, magnitude force applied tangentially is 12.33 N

Answer:

The “smoke” coming from dry ice is actually carbon dioxide gas, which is turning from a solid into a gas.

Explanation:

The type of power plant burns material to make electricity is Fossil fuel. The correct option is C.

Energy is the ability to do work.

There are different kind of energies like kinetic energy, potential energy, gravitational energy and  heat energy.

The energy obtained from burning different type of materials like Coal, gas and oil and produces heat.

Fossil fuel power plants burn coal or oil to create heat and generate steam to run turbines which generate electricity.

Thus, the correct option is C.

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Answer:

\(Velocity=\frac{dx}{dt}\)

Explanation:

Remember that instantaneous velocity is just a measure to know the velocity that any object has at any point given in time, so we just need to know the distance it has travel, which would be the change in position, and the time it took that change in position to occurr, this means distance by time, so we just divide dx by dt and we have the solution for instantaneous velocity.

If a change in position as denoted by \(dx\) and \(dt\) change in time, the instantaneous velocity will be given by,

\(v = \dfrac {dx}{dt}\)

\(v = \dfrac {dx}{dt}\)

Where,

\(v\) - instantaneous velocity

\(dt\)   - change in distance (position)

\(dt\)- change in time

Therefore, if a change in position as denoted by \(dx\) and \(dt\)change in time, the instantaneous velocity will be given by,

\(v = \dfrac {dx}{dt}\)

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Answer:

Electromagnetic waves

Electromagnetic waves bring energy into a system by virtue of their electric and magnetic fields. These fields can exert forces and move charges in the system and, thus, do work on them. However, there is energy in an electromagnetic wave itself, whether it is absorbed or not.

So the answer is B electrical energy

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Answer:

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Class 11

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>>Measurement of Area, Volume and Density

>>Antarctica is roughly semicircular, with

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Antarctica is roughly semicircular, with a radius of 2000 km.The average thickness of its ice cover is 3000 m.How many cubic centimetres of ice does Antarctica contain? (Ignore the curvature of Earth.)

1765107

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Solution

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Area of the Antarctica ice A=π×(R)

2

where, R is the radius .

A=(π×2000×2000)m

2

A=1.257×10

13

m

2

Volume of the ice in Antarctica V=A∗H

where, H is the height

V=(1.257×10

13

×3000)m

3

V=3.77×10

16

m

3

Now, to convert cubic meter to cubic cm

V=3.77×10

16

/10

−6

cm

3

V=3.77×10

22

cm

3

Antarctica contains approximately \(\(5.59447 \times 10^{24}\)\) cubic centimeters of ice.

To calculate the volume of ice that Antarctica contains, we can treat it as a hemisphere (half of a sphere) since it is roughly semicircular and ignore the curvature of the Earth. The formula to calculate the volume of a hemisphere is: \(\[ V = \frac{2}{3} \pi r^3 \]\)

where:

r = 2050 km (convert to meters: \(\( 2050 \, \text{km} \times 1000 \, \text{m/km} = 2,050,000 \) m)\)

h = 3100  m

Let's calculate the volume:

\(\[ V = \frac{2}{3} \pi (2050000 \, \text{m})^3 \]\[ V = \frac{2}{3} \pi (8.41025 \times 10^{18} \, \text{m}^3) \]\)

Now, we need to convert the volume to cubic centimeters since 1 m³ = 1,000,000 cm³:

\(\[ V = \frac{2}{3} \pi (8.41025 \times 10^{18} \, \text{m}^3) \times 1,000,000 \, \text{cm}^3/\text{m}^3 \]\[ V = \frac{2}{3} \pi (8.41025 \times 10^{24} \, \text{cm}^3) \]\)

Now, calculate the final value:

\(\[ V = 5.59447 \times 10^{24} \, \text{cm}^3 \]\)

So, Antarctica contains approximately \(\(5.59447 \times 10^{24}\)\) cubic centimeters of ice.

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Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.

Answer:

1/9 E0

Explanation:

The computation is shown below:

As we know that

\(E_0 = K \frac{Q}{r2}\)

where,

E = Electric field strength

k = Coulomb's constant

Q = charge on the sphere

r = distance from the center of the sphere

It is given that

The radius of the larger sphere is three times larger than that of the smaller sphere i.e

\(R'=3R\)

\(E'=k\frac{Q}{R'^2}\)

\(=k\frac{Q}{(3R)^2}\)

\(=\frac{1}{9}(k\frac{Q}{R^2})\)

\(=\frac{E_0}{9}\)

hence, the last option is correct

Compressibility of a substance is defined as the ratio of volumetric strain to the change in pressure. It is also equal to the reciprocal of the bulk modulus of the substance. It is denoted by K (kappa).

, for an isothermal process.

As we know that, work done for isothermal reversible expansion is given by-

Answer: This (random) thermal motion of the particles due to the temperature is also called Brownian motion. ... The higher the temperature, the faster the diffusion will be, because the stronger the molecule movement and thus the “mixing”.

Explanation:

According to the question the two charges are -7.5 µC and -7.5 µC.

Charges are fees or payments for services or goods. Charges can be one-time payments, recurring payments, or fees associated with using a product or service. Charges can be for products, services, or activities. Examples of charges include fees for using a credit card, fees for using a bank account, fees for renting a car, fees for using a mobile phone plan, fees for using a subscription service, fees for using a streaming service, and fees for using a gym membership.

Let the two charges be x and ( -15 - x ) µC.

According to Coulomb's law,

F = (k × x × ( -15 - x ))/r2

Where k is the Coulomb's constant,

k = 9 × 109 N × m2/C2

Given, F = 9 × 10-2 N

r = 5 m

Substituting these values in the equation,

9 × 10-2 = (9 × 109 × x × ( -15 - x ))/252

⇒ x2+ 15x - 4.5 × 10-4 = 0

Solving this equation,

x = -7.5 µC and ( -15 - x ) = -7.5 µC

Therefore, the two charges are -7.5 µC and -7.5 µC.

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Answer:bdsh c

Explanation:

An  ice cube changing from a solid to a liquid is melting and then to a gas is vaporization.

A change of state process describes a process whereby a substance changes from one physical state to another.

The change of state processes are:

Therefore, an ice cube changing from a solid to a liquid is melting and then to a gas is vaporization.

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