The displacement of a transvers wave travelling on a string is represented by D1 = 4.2sin(0.84.x - 47t + 21) where D1 and x are in cm and t in s.Find an equation that represents a wave which, when traveling in the opposite direction, will produce a standing wave when added to this one

The kinetic energy of the cylinder and crank at the moment when the bucket is moving with a velocity of 5.0 m/s can be determined by making use of the law of conservation of energy. The law states that the total energy of a closed system remains constant provided that no energy is lost to the surroundings, and this law is applicable for the present scenario since the system consists of the bucket, rope, cylinder, and crank.

According to this law, the initial potential energy (PEi) of the bucket when it is raised to the top of the well is equal to the final kinetic energy (KEf) of the cylinder and crank when the bucket is moving with a velocity of 5.0 m/s.

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The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Answer:

495.5 Joules

Explanation:

Given data

Mass= 10kg

Height= 5meters

g= 9.81m/s^2

Yes the rock will possess potential energy before it hits the ground

The potential energy is expressed as

PE=mgh

substitute

PE= 10*9.91*5

PE= 495.5 Joules

Explanation:

Answer:

0.0377

Explanation:

Trust brother

Answer:

0.0377

Explanation:

Answer:

velocity = 44.3m/s

Explanation:

From the law of motion.

v = u + at

v = 8.6 + (2.1 x 17)

v = 8.6 + (35.7)

v = 44.3m/s after 2.1m/s²

Answer:

120 mph

Explanation:

Given:

Δx = 0.25 mi

v₀ = 0 mi/s

t = 15 s

Find: v

Δx = ½ (v + v₀) t

0.25 mi = ½ (v + 0 mi/s) (15 s)

v = 0.0333 mi/s

v = 120 mi/h

Explanation:

The answer is C thick carpet

PLEASE MARK ME AS BRAINLIEST

Answer:

it is C

Explanation:

Answer:

0.54

Explanation:

2.7÷5 = 0.54

Hope this helps!

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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Answer:

\(kinetic \: energy = \frac{1}{2} m {v}^{2} \\ m = mass \: of \: the \: object \\ v = velocity \: \)

Answer:

Diffraction is correct :)

Explanation:

Diffraction of sound waves is commonly observed; we notice sound diffracting around corners or through door openings, allowing us to hear others who are speaking to us from adjacent rooms.

Answer:

The equation of momentum for a linear system is simply P = mv where P = momentum (kg·m/sec or lb·ft/sec); m = mass (kg or lb); and v = velocity (m/s or ft/sec). ... By reducing her inertia (I = mr2 where r has been decreased) her angular velocity, ω, must increase in order for the angular momentum to remain constant.

https://www.gstatic.com/education/formulas2/355397047/en/moment_of_inertia.svg

hope this helps?

Explanation:

Answer:

C. Acetylcholine; dopamine

Acetylcholine is to Alzheimer's disease dopamine as is to Parkinson's disease. That is option C.

The neurological disorders are does diseases that affect the nervous system of an individual.

Examples of the neurological disorder include:

Therefore, Acetylcholine is to Alzheimer's disease dopamine as is to Parkinson's disease.

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Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.

Explanation:

Good Question

The list of the object in order of least to greatest momentum is Y, W, X, Z (last option)

To obtain the list in order of least to greatest momentum, we shall obtain the momentum of each object. Details below:

For W

Momentum = mass × velocity

= 12 × 5 m/s

= 60 Kg.m/s

For X

Momentum = mass × velocity

= 15 × 8 m/s

= 120 Kg.m/s

For Y

Momentum = mass × velocity

= 18 × 2 m/s

= 36 Kg.m/s

For Z

Momentum = mass × velocity

= 28 × 10 m/s

= 280 Kg.m/s

From the above, we have the following:

Thus, the list from least to greatest of the momentum is Y, W, X, Z (last option)

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Complete question:

See attached photo

42 times must he repeat this exercise to burn off the energy in one slice of pizza.

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Energy burn by the weightlifter = potential energy

Potential energy = mgh

Potential energy = 25.(9.8)(0.50)

Potential energy = 122.5 Joule.

Assume 25% of efficiency so energy burn = 122.5*25/100

energy burn = 30.625 joule

Number of times = 1260/30.625

Number of times = 42 times.

42 times must he repeat this exercise to burn off the energy in one slice of pizza.

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Answer:

T= In(2)/___ =__ In(2)

Explanation:

the equation pices arnt on the keyboard so i put the blanks

sorry

jope it helps some. Have a good day ir night! :)

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

the formula of mechanical advantage is

MA = load / effort

VR = effort distance / load distance

hope it is helpful to you

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Explanation:

Mass of carte 1 is 110 kg and that of crate 2 is 230 kg

Force required to lift crates is equal to its crate i.e. W = mg

On Moon, a = 1.625 m/s²

Weight of crate 1, W = 110 kg × 1.625 m/s²  = 178.75 N

Weight of crate 2, W = 230 kg × 1.625 m/s²  = 373.75 N

On Earth, g = 9.8 m/s²

Weight of crate 1, W = 110 kg × 9.8 m/s²  = 1078 N

Weight of crate 2, W = 230 kg × 9.8 m/s²  = 2254 N

Hence, this is the required solution.

The forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.

Given the following data:

Scientific data:

Mathematically, the weight of an object is given by the formula;

\(Weight = mg\)

Where;

\(Weight \;A= 110 \times 1.6\)

Weight A = 176 Newton.

\(Weight \;B=230 \times 1.6\)

Weight B = 368 Newton.

\(Weight \;A= 110 \times 9.8\)

Weight A = 1,078 Newton.

\(Weight \;B=230 \times 9.8\)

Weight B = 2,254 Newton.

In conclusion, the forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.

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The ratio of M/m is approximately 0.155, which is closest to option (b) 1/4.

Let's consider the motion of the system before and after the collisions. We'll use the conservation of momentum and the conservation of energy to solve the problem.

Before the collisions, the leftmost block of mass m has velocity v towards the right and the other two blocks are at rest. The total initial momentum of the system is therefore mv.

At the first collision, the leftmost block collides with the middle block of mass m. The two blocks stick together and move as a single unit. By conservation of momentum, the velocity of the combined block after the collision is mv/(2m) = v/2 towards the right.

At the second collision, the combined block collides with the block of mass M. Again, the two blocks stick together and move as a single unit. By conservation of momentum, the velocity of the combined block after the collision is (mv/2 + 0)/ (m+M) = v/2(m+M) towards the right.

After the collisions, the three blocks move as a single unit with velocity v/2(m+M) towards the right. The total final momentum of the system is therefore (m+2m+M)(v/2(m+M)) = mv/2.

The loss in kinetic energy after all the collisions is given as 5/6th of the initial kinetic energy. Therefore, the final kinetic energy is 1/6th of the initial kinetic energy. Let's use this to solve for M/m.

The initial kinetic energy of the system is (1/2)m(v^2) = (1/2)mv^2.

The final kinetic energy of the system is;

(1/2)(m+2m+M)((v/2(m+M))^2) = (1/2)(mv^2)/(4(m+M)^2).

Therefore, we have:

(1/2)mv^2 - (1/2)(mv^2)/(4(m+M)^2) = (1/6)(1/2)mv^2

Multiplying both sides by 12 and simplifying, we get:

3(m+M)^2 = 8m

Expanding the left side and simplifying, we get:

3M^2 + 6mM - 4m^2 = 0

Solving for M/m using the quadratic formula, we get:

M/m = (-6 ± √(36 + 48))/6 = (-6 ± 2√(3))/6 = (-1 ± √(3))/3

Since M/m is a ratio of masses, it must be positive, so we take the positive root:

M/m = (-1 + (3))/3 ≈ 0.155 ≈ 1/4

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Heya!!

For calculate velocity, lets applicate formula

                                                 \(\boxed{d = v * t}\)

                                               Δ   Being   Δ

                                         d = Distance = 3790 m

                                             t = Time = 249 s

                                             v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

\(\boxed{v= 3790\ m / 249\ s}\)

⇒ Resolving

\(\boxed{ v = 15,22 \ m/s }\)

Result:

The velocity is 15,22 meters per second.

Good Luck!!

The temperature remains constant while the substance is changing state.The correct answer is option C.

When a substance undergoes a change of state, such as melting, boiling, or condensing, the temperature of the substance remains constant during the phase transition. The process of changing state requires the absorption or release of heat energy without a change in temperature.

For example, when a solid is heated, its temperature increases until it reaches the melting point. At this point, the substance starts to change from a solid to a liquid, but the temperature remains constant until all the solid has melted.
The absorbed heat energy is used to break the intermolecular forces holding the particles together, rather than increasing the kinetic energy of the particles.

Similarly, during the process of condensation or freezing, a substance releases heat energy as it changes state. This released energy is used to form intermolecular forces and convert the substance from a gas to a liquid or a liquid to a solid. The temperature remains constant until the phase transition is complete.
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He goes 400 m straight then goes 500m to the left side then goes backwards 400m so walking north is cancelled out he covers only 500 m to the west.

If u mean how much distance he travelled from starting point then this is the answer

Answer: He goes 400 m straight then goes 500m to the left side then goes backwards 400m so walking north is cancelled out he covers only 500 m to the west.

If you mean how much distance he travelled from starting point then this is the answer

The speed of the artillery shell when it hits its target is approximately 118.0 m/s.

The problem is asking for the velocity of the artillery shell when it hits the target. Since it has already been given that the speed of the shell at a height of 100 m is 100 m/s, we can make use of the conservation of energy to find the final velocity.

The total energy of the artillery shell at a height of 100 m above the ground can be given as:

K + U = E(1)where K is the kinetic energy, U is the potential energy, and E is the total energy of the artillery shell.

The kinetic energy of the artillery shell at a height of 100 m is given as:

K = (1/2)mv²

where m is the mass of the artillery shell and v is its velocity at a height of 100 m above the ground.

The potential energy of the artillery shell at a height of 100 m is given as:

U = mgh

where m is the mass of the artillery shell, g is the acceleration due to gravity (taken to be 9.81 m/s²), and h is the height of the artillery shell above the ground (in this case, h = 100 m).

Substituting the values of K and U into Equation (1), we have:

(1/2)mv² + mgh = E

where E is the total energy of the artillery shell.

The total energy of the artillery shell when it hits the target can be given as:

E = K' + U'

where K' is the kinetic energy of the artillery shell just before it hits the target, and U' is its potential energy just before it hits the target.

Since the problem states that there is no air friction, the total energy of the artillery shell is conserved (i.e., E = K + U = K' + U').

Therefore:

(1/2)mv² + mgh = K' + U'(1/2)mv² + mgh = (1/2)mv'² + mgh'(where v' is the velocity of the artillery shell just before it hits the target, and h' is its height just before it hits the target).

Solving for v', we have:

v' = sqrt(v² + 2gh)

Substituting the given values, we get:

v' = sqrt((100 m/s)² + 2(9.81 m/s²)(200 m)) = sqrt(10000 + 3924.4) m/s = sqrt(13924.4) m/s = 118.0 m/s

Therefore, the speed of the artillery shell when it hits its target is approximately 118.0 m/s.

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Given what we know, we can confirm that option D,  Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency is true.

High-frequency waves are synonymous with short wavelengths. This means that the waves are oscillating much quicker and therefore carry more kinetic energy within them. This is transformed and released as electromagnetic radiation, which is the reason why high-frequency waves are more energetic than low-frequency electromagnetic waves.

Therefore, we can confirm that the statement "Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency" is true.

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