the electric field 0.460 m from a very long uniform line of charge is 900 n/c..How much charge is contained in a section of the line of length 2.30cm?

Answer:

a)     1: 100  F₂ = 100 F₁,  b) P₁ = P₂   1:1

Explanation:

The pressure in a system is the same for a given horizontal line, therefore

          P₁ = P₂

where subscript 1 is for small piston and index 2 is for large piston 2

a) they ask the relation of the forces

pressure is defined by

        P = F / A

for the small piston

        P₁ = F₁ / A₁

the area of ​​the piston is

        A₁ =π r₁²

        P₁ = F₁ /π r₁²

for big piston

         P₂ = F₂ / A₂

in the exercise indicates that the diameter of the large piston is 10 times the diameter of the small piston

         A = π r₂²

         r₂ = 10 r₁

          r₂ = π 10² r₁²

we substitute

         P₂ = \(\frac{F_2}{ \pi \ 100 \ r_1^2}\)

we equalize the pressures

          \(\frac{F_1 }{ \pi \ r_1^2 } = \frac{F_2}{ \pi \ 100 r_1^2}\)

           F₁ = F₂ / 100

            F₂ / F₁ = 100

therefore the force ratio is

             1: 100

b) according to Pascal's principle for the same height the pressure is the same regardless of the shape of the container, therefore the pressure of the two pistons is the same

           P1 = P2

             1: 1

Answer:

C) The average speed of the air molecules in the tyre is greater.

Explanation:

As temperature increases the speed of the molecule increases too.

Answer:

acceleration= 0.01 m/s²

Explanation:

\(a = \frac{v - u}{t} \)

\(a = \frac{1.3 - 1.1}{20} \)

\(a = \frac{0.2}{20} \)

\(a = 0.01 \frac{m}{ {s}^{2} } \)

The force of gravity depends on the mass of objects and the distance between them. This is true statement.

Physics defines force as the push or pull that modifies the velocity of a massed object.

The ability to change a body's resting or moving condition is referred to as an external force. There is a magnitude and a direction to it.

You may determine the Force using a spring balance. The SI's measure of force is the Newton.

The force of gravity between two objects is directly proportional to the mass of the object and inversely proportional to the square of the distance between them.

Hence, the force of gravity depends on the mass of objects and the distance between them. This is true statement.

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Answer: the first is positive and second is equal

Explanation:

Answer: 1. Positive

Explanation:

Because there is negative charges and positive charges

Answer:

electrical energy is energy derived from electric potential energy or kinetic energy. when loosely electrical energy refers to energy that has been converted from electric potential energy

Answer:

electrical energy is energy derived from electric potential energy or kinetic energy. when loosely electrical energy refers to energy that has been converted from electric potential energy

Explanation:

Answer:

The values of gravitational force and gravitational constant become same or equal when product of masses involved equals the square of distance between them.

The height of the plane delivering a food package to people stranded on an island is 722.2 m.

The time taken for the food package to hit the ground level is calculated as follows;

X = vt

where;

t = X/v

t = 789/65

t = 12.14 seconds

h = ¹/₂gt²

where;

h = (0.5)(9.8)(12.14²)

h = 722.2 m

Thus, the height of the plane delivering a food package to people stranded on an island is 722.2 m.

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Answer:

722.2

Explanation:

600

mph

Velocity is the distance traveled in a given time, or

v

=

x

t

where

v

is velocity,

x

is distance and

t

is time.

Here,

x

=

3000

and

t

=

5.0

, so

v

=

x

t

=

3000

5

=

600

Don't forget units. Since the question's data is in miles and hours, the units will be miles per hour, or mph, so

3000

miles

5

hours

=

600

miles

hour

=

600

mph

The average velocity for the given time intervals are calculated by finding the displacement and dividing it by the time elapsed using the provided height function.

In this scenario, the height of the arrow at time t is given by the function h(t) = 30t - 0.83t^2.

Let's calculate the average velocity for each given time interval:

1. [7, 8]:

  - Initial time: t1 = 7 seconds

  - Final time: t2 = 8 seconds

  - Displacement: h(t2) - h(t1) = [30(t2) - 0.83(t2)^2] - [30(t1) - 0.83(t1)^2]

  - Average velocity: Displacement / Time elapsed = (h(t2) - h(t1)) / (t2 - t1)

2. [7, 7.5]:

  - Initial time: t1 = 7 seconds

  - Final time: t2 = 7.5 seconds

  - Displacement: h(t2) - h(t1) = [30(t2) - 0.83(t2)^2] - [30(t1) - 0.83(t1)^2]

  - Average velocity: Displacement / Time elapsed = (h(t2) - h(t1)) / (t2 - t1)

3. [7, 7.1]:

  - Initial time: t1 = 7 seconds

  - Final time: t2 = 7.1 seconds

  - Displacement: h(t2) - h(t1) = [30(t2) - 0.83(t2)^2] - [30(t1) - 0.83(t1)^2]

  - Average velocity: Displacement / Time elapsed = (h(t2) - h(t1)) / (t2 - t1)

4. [7, 7.001]:

  - Initial time: t1 = 7 seconds

  - Final time: t2 = 7.001 seconds

  - Displacement: h(t2) - h(t1) = [30(t2) - 0.83(t2)^2] - [30(t1) - 0.83(t1)^2]

  - Average velocity: Displacement / Time elapsed = (h(t2) - h(t1)) / (t2 - t1)

By substituting the respective values into the displacement formula and performing the calculations, we can determine the average velocities for each time interval.

The average velocity represents the change in position per unit of time and provides insight into the average rate at which the arrow is moving during the given time intervals.

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1) The magnitude of electric field at (3.0 m, 2.6 m) is approximately 74.12 V/m.

2) The direction of the electric field at (3.0 m, 2.6 m) is approximately 50.68° ccw from the positive x-axis.

1) In order to calculate the electric field at a point (x, y) given the electric potential V, the following equation can be utilised :

E = -∇V

Here, ∇V is the gradient of the electric potential V.

Considering the gradient of V with respect to x and y,

∂V/∂x = -200V⋅m/x(x^2+y^2)^(1/2)

∂V/∂y = -200V⋅m/y(x^2+y^2)^(1/2)

Putting the values of x = 3.0 m and y = 2.6 m, we get:

∂V/∂x = -200V⋅m/(3.0 m)(3.0^2 + 2.6^2)^(1/2) ≈ -48.43 V/m

∂V/∂y = -200V⋅m/(2.6 m)(3.0^2 + 2.6^2)^(1/2) ≈ -56.06 V/m

Therefore the electric field at (3.0 m, 2.6 m) is found to be,

E = -∇V = -(-48.43 V/m i - 56.06 V/m j) ≈ 48.43 V/m i + 56.06 V/m j

Thereforethe magnitude of the electric field is  calculated to be

|E| = (48.43 V/m)^2 + (56.06 V/m)^2 ≈ 74.12 V/m

2) Now finding the direction of the electric field, following method is used:

θ = tan⁻¹(Ey/Ex)

(where θ is the angle ccw from the positive x-axis)

Inserting the values of Ex and Ey, we get:

θ = tan⁻¹(56.06 V/m/48.43 V/m) = 50.68° (approx.)

Hence, the direction of the electric field at point (3.0 m, 2.6 m) is approximately 50.68° ccw from the positive x-axis.

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Answer:

Answer: hydraulic press and hydraulic brakes. ... This law is useful in designing instruments like Bramah press ,Hydraulic press , Hydraulic jack etc. It is the principle in the development of hydraulic brakes , that are used in automobiles. It is also known as law of transmission of fluid pressure

Answer:

To find the mass using density and volume we just multiply them against each other which causes ml to cancel and just leaves us with grams which represents how much the item weights.

\(mass=density*volume\)

\(mass=0.875\frac{g}{ml}*4.0\ ml\)

\(mass=3.5\ g\)

Therefore, our final answer is that our pencil weight 3.5 grams

Hope this helps!  Let me know if you have any questions

Two kids of different masses take part in a tug of war with no friction. The distance of their center of mass can be calculated, and if child B pulls on the rope towards child A, the distance he will move before colliding with child A can also be calculated.

A. To find the center of mass (CM) of the system, we need to take into account both the masses and their distances from each other. The formula for the position of the CM is:

CM = (m1x1 + m2x2) / (m1 + m2)

where m1 and m2 are the masses, x1 and x2 are their distances from a chosen reference point.

In this case, let's take child A as the reference point, so x1 = 0 (since child A is at the origin), and x2 = 11 m. Then we have:

CM = (m1x1 + m2x2) / (m1 + m2)

= (26 kg * 0 + 49 kg * 11 m) / (26 kg + 49 kg)

= 7.6 m

Therefore, the center of mass of the system is located 7.6 m from child A.

B. As child B pulls on the rope, he will move towards child A, and their separation distance will decrease. At the same time, the center of mass of the system will move towards child B. Since there is no external force acting on the system, the position of the center of mass will not change.

Let's assume that child B moves a distance of x towards child A before they collide. Then the distance between child A and the CM of the system will be (11 - x), and the distance between child B and the CM will be x. Using the formula for the position of the CM, we can set up an equation:

CM = (m1x1 + m2x2) / (m1 + m2)

= ((26 kg) * 0 + (49 kg) * (11 - x)) / (26 kg + 49 kg)

= (539 - 49x) / 75

Since the CM does not move, this must be equal to the initial position of the CM, which we found to be 7.6 m from child A:

(539 - 49x) / 75 = 7.6

Solving for x, we get:

x = 6.4 m

Therefore, child B will have moved a distance of 6.4 m towards child A before they collide.

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Answer:

ADHD, also called attention-deficit disorder, is a behavior disorder, usually first diagnosed in childhood, that is characterized by inattention, impulsivity, and, in some cases, hyperactivity.

Explanation:

Answer:

Environment

Explanation:

Your Environment, More Than Genetics, Determines Your Immune Health. When it comes to immunity, the environment you grow up in, or how you were 'nurtured' , is more important than nature, a new study suggests. Particularly as you get older.

Answer:

150 N= 15 or 150 N= 1.1

Explanation:

What I did was subtract 165kg and 150 N and I divided it too but I got 1.1 so yuhh

The static friction coefficient is higher than the kinetic friction coefficient.

What is static friction?

Friction is the obstruction or resistance that prevents one solid object from rolling or sliding over another. F indicates this. Any solid and liquid layer motion is opposed by a force. When two materials slide over one another, this force is created. There is friction all around us. For instance, when we walk, the ground is in contact with our feet. When we walk, one foot advances while the other moves backward, applying pressure to the ground. When this force is applied to the ground, the ground applies an equal and opposing force to our feet. One of the laws of motion is being followed in this situation.

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If a kiloparsec (kpc) is equal to 1000 parsecs, light years is a kiloparsec equal to: 3, 260 light years.

The distance that light travels in a light-year is one year. At 186,000 miles (300,000 kilometres) per second and 5.88 trillion miles (9.46 trillion kilometres) per year, light travels through interstellar space.

Since a light-year is the maximum distance light can travel in one year and nothing can move faster than that, the answer appears to be 13.8 billion light-years.

Thus, 3,260 many light years is a kiloparsec.

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Hey I'm working on this test right now, did you ever get the answers?

Granulation is the visible surface pattern of the sun, consisting of many small cells caused by convective motions. This is evidenced by the fact that the cells are roughly hexagonal, which is the shape expected from convective fluid motions.

Additionally, the cells are seen to rise and fall, consistent with convection currents, and the temperature variations across the cells are also consistent with convective heating and cooling. Finally, models of the sun's interior suggest that granulation is indeed caused by convection driven by heat flow from the core to the surface.

Granulation is a process in which small particles are agglomerated or fused together to form larger particles. The resulting particles, or granules, are more uniform in size and shape than the original particles and have improved flow, packing, and handling properties. Granulation is a common process in many industries, including pharmaceuticals, chemicals, food, and mining.

The process of granulation typically involves three stages: wetting, nucleation, and growth. In the wetting stage, the smaller particles are moistened or coated with a liquid binder, such as water or a solvent. In the nucleation stage, the wetted particles begin to form small aggregates, or nuclei, as the binder dries and the particles come into contact with each other. In the growth stage, the nuclei grow by further aggregation and consolidation, resulting in larger granules.

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Answer:

Explanation:

whale speed = 8 m/s for 17 sec.

find distance traveled in km

distance = velocity x time

              = 8 m/sec. x 17 sec.

              = 136 meters  x        1   km      

                                           1000 meters

              =  0.136 km

Metals have shiny apperances

The heat required for the change of state of the materials in the question  are;

4. a. 894000 J, b. 423000 J, c. 8040 J

5. 0.096 kg

6. 321 kJ/kg

7. a. Copper; 287625 J, Silver; 108307 J, Gold; 67795 J

b. 0.0598 kg

8 a. 1302.46 °C

b. 11157 J

Specific latent heat is the amount of heat energy required to change the state of a substance while the temperature of the substance remain the same.

4. The energy needed to evaporate;

a. 3 kg of petrol (octane) = 3 kg × 298000 J/kg = 894000 J

b. 500 g of ethanol = 0.5 kg × 846000 J/kg = 423000 J

c. 20 g of vineger (acetic acid) = 0.02 kg × 402000 J/kg = 8040 J

5. The mass of the liquid ethanol that can be evaporated by supplying 80 kJ of energy = (80 kJ)/(846 kJ/kg) ≈ 0.096 kg

6. The specific latent heat of melting of aluminium = (6420 kJ)/(20 kg) = 321 kJ/kg

7. a. The energy needed to heat each sample to its melting point:

Copper: m·c·ΔT = (0.5 kg)×(390 J/kg°C)×(1495°C - 20°C) = 287625 J

Silver: m·c·ΔT = (0.5 kg)×(230 J/kg°C)×(961.8°C - 20°C) = 108307 J

Gold: m·c·ΔT = (0.5 kg)×(130 J/kg°C)×(1063°C - 20°C) = 67795 J

7. b. The amount of copper that melts:

Energy needed to heat copper to its melting point: Q1 = m·c·ΔT = (0.5 kg)×(390 J/kg·°C)×(1495°C - 20°C) = 287625 J

Energy remaining for melting; Q2 = (300 kJ) - Q1 = (300000 J) - (287625 J) = 12375 J

Mass of copper that melts; m = Q2/Lf = (12375 J)/(207000 J/kg) ≈ 0.0598 kg

Extra challenge:

8a. Final temperature of the liquid silver;

Energy needed to heat silver to its melting point; Q1 = m·c·ΔT = (0.5 kg)×(230 J/kg·°C)×(961.8°C - 20°C) = 108307 J

Energy needed to melt silver: Q2 = m·L·f = (0.5 kg)×(88000 J/kg) = 44000 J

Energy remaining for heating liquid silver: Q3 = (200 kJ) - Q1 - Q2 = 200000 J - 108307 J - 44000 J = 47693 J

Final temperature of the liquid silver: ΔT = Q3/(m·c) = 47693/(0.5×280) ≈ 340.66

\(T_f\) ≈ 961.8 + 340.66 = 1302.46

The final temperature is about 1302.46 °C

8 b. Energy needed to obtain liquid gold at a temperature of 1200°C

Energy needed to heat gold to its melting point; Q1 = m·c·ΔT = (0.05 × 130 × (1063 - 20) = 6779.5

Energy needed = 6779.5 J

Energy needed to melt gold; Q2 = m·Lf = (0.05 kg)×(67000 J/kg) = 3350 J

Energy needed to heat liquid gold from its melting point to final temperature; Q3 = m·c·ΔT = (0.05 kg) × (150 J/kg·°C) × (1200°C - 1063°C) = 1027.5 J

The sum of the energy required, Q = Q1 + Q2 + Q3 = 6779.5 + 3350 + 1027.5 = 11157

The total energy required is 11157 J

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A kangaroo jumps straight up to a vertical height of 1.45 m. The time the kangaroo was in the air before returning to the ground was 0.5304 seconds. The given data can be used to calculate the time the kangaroo was in the air before returning to the ground.

The initial velocity of the kangaroo is zero since it was at rest, and it jumps straight up to a height of 1.45 m from the ground.

Using the formula for vertical motion,

vf = u + gt,

where

We can substitute these values and gett = 0.5304 seconds

Therefore, the kangaroo was in the air for 0.5304 seconds.

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When hot tea is mixed to chilled coke, tea loses heat and coke gains heat. Thus, tea cools down but coke gets heated. Because it is liquid and liquid does not totally cool down to the ambient temperature, it and the iced drink will eventually reach the same temperature.

1.) The AMA is 2.5

2.) The VR is 5.

3.) The efficiency is 50%.

Given that the object has a weight of 250 N and the effort needed to push it up the ramp is 100 N, we can calculate the AMA as follows:

AMA = Load / Effort

AMA = 250 N / 100 N

AMA = 2.5

Therefore, the AMA is 2.5.

To calculate the VR, we need to find the distance moved by the effort and the distance moved by the load. The distance moved by the effort is the length of the ramp, which is 50 m. The distance moved by the load is the height it is raised, which is 10 m. Therefore, we have:

VR = Distance moved by effort / Distance moved by load

VR = 50 m / 10 m

VR = 5

Therefore, the VR is 5.

To calculate the efficiency, we need to find the work done by the load and the work done by the effort. The work done by the load is:

Work done by load = Load x Distance moved by load

Work done by load = 250 N x 10 m

Work done by load = 2,500 J

The work done by the effort is:

Work done by effort = Effort x Distance moved by effort

Work done by effort = 100 N x 50 m

Work done by effort = 5,000 J

Therefore, the efficiency is:

Efficiency = (Load x Distance moved by load) / (Effort x Distance moved by effort)

Efficiency = (2,500 J) / (5,000 J)

Efficiency = 0.5 or 50%

Therefore, the efficiency is 50%.

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Answer:

33 m/s

Explanation: