The experimental set-up shown in the figure was designed to test option D: competition between slime mold slugs and amoebas.
The experimental setup shown in the figure was designed to test the competition between slime mold slugs and amoebas. The experiment was conducted by Mark Fricker, who placed amoeboid fungus on a map of England with “little oat flakes at every city.”
The fungus was able to plan a route through the nation that "really replicated - and was in many ways superior" than the network of railways that was constructed by humans.
Slime moulds are an uncommon group of organisms that were formerly categorised as fungi, plants, and mammals. Slime moulds have cellulose in the cell walls of their spores, just like plants do.
Slime moulds are heterotrophs, in contrast to plants. Slime Moulds have a diplontic life cycle and lack chitin in their cell walls, despite the fact that they were previously classified as fungi.
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which of the following claims is best supported by the information above? choose 1 answer: choose 1 answer: (choice a) a e1b-55k causes infected cells to transition out of the cell cycle and into g 0 0 start subscript, 0, end subscript phase. (choice b) b e1b-55k causes infected cells to undergo programmed cell death. (choice c) c e1b-55k increases the likelihood of cell cycle arrest in infected cells. (choice d) d e1b-55k decreases the likelihood of apoptosis in infected cells.
Answer:
what is botany .and scope of botany
A lake has begun to degrade due to an increase in human activity and urbanization. The main cause of this degradation is that the oxygen carrying capacity of the water has decreased due to an increase in the discharge of organic substances (especially phosphates) in the lake due to fertilizer runoff from local farms. This increase in organic substances has allowed aquatic plants, including algae, in the lake to grow at an increased rate. As these aquatic plants die, excessive oxygen is used in the decomposition process, which leads to oxygen deprivation and fish kills. This results in reduced animal populations in the lake, and the decomposition process releases more phosphates back into the water to feed even more plant growth. This dramatic increase in plant growth is called eutrophication and can make water unfit for human consumption.
A scientist wants to come up with a solution to help minimize eutrophication as a way to maintain the lake’s natural ecosystem without eliminating any of the lake’s native populations. Which of the following would be the best solution for the scientist to implement?
A.
treating all runoff with metal complexes that are poisonous to algae populations
B.
asking the farmers in the area to only use fertilizer on their crops when it is raining or windy outside
C.
spraying clay on the aquatic plants so that they sink to the bottom of the lake to decompose
D.
creating buffer strips around the lake using land vegetation to trap fertilizer runoff and prevent it from reaching the water
Answer: The best solution for the scientist to implement would be D, creating buffer strips around the lake using land vegetation to trap fertilizer runoff and prevent it from reaching the water. This solution would help to reduce the amount of organic substances, particularly phosphates, in the lake, which is the main cause of the eutrophication. Buffer strips would help prevent runoff from reaching the lake by trapping it in the vegetation surrounding the lake. This solution is environmentally friendly and would not harm any of the lake's native populations. Option A, treating all runoff with metal complexes that are poisonous to algae populations, could be harmful to the ecosystem of the lake and would not be a sustainable solution. Option B, asking farmers to only use fertilizer on their crops when it is raining or windy, may not be a practical solution as farmers need to fertilize their crops, and weather conditions may not always allow for it. Option C, spraying clay on the aquatic plants, may not be effective in the long run as it would not address the root cause of the problem, which is the excess nutrients in the lake.
Explanation:
Why does the velocity of blood slow greatly as blood flows from arterioles into capillaries?.
Because the cross-sectional area is much greater in capillary beds than in the arteries or any other part of the circulatory system, there is a dramatic decrease in velocity from the arteries to the capillaries.
What happen when blood flow in Capillaries ?The capillaries, where blood flow is the slowest, provide time for the exchange of gases and nutrients. A force that opposes a fluid's flow is called resistance. The majority of blood vessel resistance is caused by the size of the vessel. Blood flow slows and resistance rises as vessel diameter shrinks.
Although the aorta's diameter is much smaller than the diameter of each individual arteriole and capillary, the rate is really slower since the aggregate diameter of all the capillaries is much larger than the diameter of each individual aorta.Learn more about Capillaries here:
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Mutações cromossômicas diferem de mutações genéticas clássicas e me geral trazem graves desvantagens aos seus portadores, cite pelo menos 3 desvantagens com relação aos erros cromossômicos em humanos.
Answer:
Desvantagens:
sofrendo de síndromes como Kinefelter que levam à deficiência de testosterona, gerando uma diminuição na massa muscular, cabelos e aumento dos seios.
Sofrendo de distúrbios de aprendizagem, distúrbios de crescimento, distúrbios cardíacos e distúrbios da puberdade, como a síndrome de Turner.
Hipogonadismo como a síndrome do duplo Y.
Explanation:
As mutações cromossômicas são caracterizadas por serem diferentes das mutações genéticas, pois são a perda ou o ganho dos cromossomos.
Os cromossomos estão, portanto, sofrendo anomalias e sem distinção de que tipo de cromossomo será afetado, é por isso que pode afetar os autossomos, bem como os não-autossomos.
Quando os cromossomos sexuais alterados são aqueles que dão frutos ao turner e às síndromes duplas e entre outros.
Outro exemplo disso é que as pessoas que têm multiplicação do cromossomo 21 sofrem da síndrome de Down, essa síndrome consiste em triplicar o conteúdo cromossômico.
Using the Karvonen Method, what is the target heart rate range for an 18-year-old with a resting heart rate of 60 who wants to work between 60 and 80 percent of her maximum heart rate? (6 Points) Heart Rat Max (HRmax) Target Heart Rate - 60 % ( THR 60%) Heart Rate Reserve (HRR) Target Heart Rate - 80% (THR 80%)
The target heart rate range for an 18-year-old with a resting heart rate of 60 who wants to work between 60 and 80 percent of her maximum heart rate is 141.2 bpm to 170.6 bpm.
Using the Karvonen Method:
The maximum heart rate (HRmax) :
HRmax = 220 - age.
For an 18-year-old, the maximum heart rate (HRmax) will be:
HRmax = 220 - 18
HRmax = 202 bpm
Therefore, the maximum heart rate (HRmax) for an 18-year-old is 202 bpm.
Heart rate reserve (HRR) :
HRR = HRmax - RHR (Resting Heart Rate).
RHR is the resting heart rate of the individual. For an 18-year-old with a resting heart rate of 60 :
HRR = HRmax - RHR
HRR = 202 - 60HRR = 142 bpm
Therefore, the heart rate reserve (HRR) for an 18-year-old is 142 bpm.
The target heart rate - 60% (THR 60%) :
THR 60% = (HRR x 0.6) + RHR
THR 60% = (HRR x 0.6) + RHR
THR 60% = (142 x 0.6) + 60
THR 60% = 141.2 bpm
Therefore, the target heart rate - 60% (THR 60%) for an 18-year-old is 141.2 bpm.
The target heart rate - 80% (THR 80%) :
THR 80% = (HRR x 0.8) + RHR
THR 80% = (HRR x 0.8) + RHR
THR 80% = (142 x 0.8) + 60
THR 80% = 170.6 bpm
Therefore, the target heart rate - 80% (THR 80%) for an 18-year-old is 170.6 bpm.
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Imagine that you forgot to flame the loop before streaking the inoculum from the first quadrant into the second quadrant. what is the most likely consequence of this error?
Answer:
too much bacterial growth in the first quadrant
Explanation:
If you forgot to flame the loop before streaking the inoculum from the first quadrant into the second quadrant. Then, the most likely consequence of this error would be : too much bacterial growth in the first quadrant
The streak for isolation method is one way to get isolated bacterial colonies. This method involves scratching bacteria onto one side of a petri dish containing culture medium using an inoculation loop. The inoculating loop is placed under the flame during the streaking process, where it becomes extremely hot. The goal of doing this is to eliminate all contaminants.
This allows some of the bacteria in the first quadrant to spread into the second. The vaccination loop must go back through the second quadrant in order to vaccinate the third, and so on.
In this case, it is clear that the flaming loop is necessary for the second quadrant to be crossed out before bacterial colonies can develop in all four quadrants. If not, the first quadrant will contain only bacterial colonies.
As a result, if the flame loop is not properly sterilized, it will carry a variety of microbes to the Petri plate, which could result in contamination.
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What is the nature of reality? Is it objective or subjective?
các cặp gen trong phép lai sau là di truyền độc lập AaBbDdXX AaBbDdXYcho thế hệ F
Answer:
rjwosxjudua9e8r7xj, hq9rbfsi48t8fidjxh hd
Explanation:
6482hfjziso37bh7r9w9qhzh
Where in the cell is the rough endoplasmic reticulum located?
Answer:
Rough ER is named for its rough appearance, which is due to the ribosomes attached to its outer (cytoplasmic) surface. Rough ER lies immediately adjacent to the cell nucleus, and its membrane is continuous with the outer membrane of the nuclear envelope.
Explanation:
Food web:
1. Hawk
2. snake
3. mouse
4.grass
suppose 10,000 units of energy are available at the level of the grasses. What is the total number of energy units lost by the time the energy reaches the hawk? How did you get your answer?
(Please help me!)
GREETINGS!
10 units of energy because in food chain the energy is lost and this energy loss is 90% at each trophic level so only 10% of energy is passed soo if grass has 10000 energy units mouse will have 1000, snake will have 100 and then hawk will have only 10 units
HOPE IT HELPS YOU
what is circulatory system?
Answer:
the system that circulates blood and lymph through the body, consisting of the heart, blood vessels, blood, lymph, and the lymphatic vessels and glands.
Explanation:
Complete the table to show the benefits and disadvantages of each type of reproduction. pic attached. kinda easy
1.benefit of sexual reproduction
- it provides genetic variety to the population.
2.disadvantages of sexual reproduction
- requires more time and energy
3.benefit of asexual reproduction
- can happen more quickly and with less energy
4.disadvantages of asexual reproduction
- less genetic variation in the population
A of isolation in which two populations with complex courtship displays or rituals become
different enough that they no longer respond to the other's actions.
a. Geographic isolation
b. Behavioral isolation
c. Temporal isolation
Answer:
The term you are referring to is behavioral isolation. Behavioral isolation is a type of isolation in which two populations with complex courtship displays or rituals become different enough that they no longer respond to the other's actions. This can occur as a result of geographic or temporal isolation, but it ultimately results in the two populations being unable to mate and reproduce with each other. This can eventually lead to the formation of two distinct species.
Explanation:
It is common in early childhood
a. conjunctivitis
b. astigmatism
c. amblyopia
Amblyopia, also known as "lazy eye," is a common condition in early childhood. Option C is the correct answer.
Amblyopia occurs when there is a disruption in the normal development of vision, typically due to an imbalance in the visual input between the two eyes. This can result in reduced visual acuity in the affected eye, even with the use of corrective lenses.
Conjunctivitis refers to an inflammation of the conjunctiva (the clear tissue covering the white part of the eye and the inner surface of the eyelids) and is not specifically associated with early childhood.
Astigmatism, on the other hand, is a refractive error that affects the way light enters the eye, causing blurred or distorted vision, but it is not specific to early childhood either.
Amblyopia, however, is a condition that commonly occurs in early childhood and is characterized by reduced vision in one eye.
Thus, option C is answer.
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. Which event in a star's life cycle can create heavy metals like gold, platinum, or lead?
Answer:
Most of the heavy metals on earth came from outer space from supernovas
This occurs when stars die
Explanation:
Visit Ted-Ed on You Tube
Type in the origins of gold and take notes
Happy to help
A situation where the bones are connected exclusively by ligaments, cords, or bands of fibrous tissue is a ________. gomphosis syndesmosis suture synchondrosis
Gomphoses are fibrous joints whose bones are joined by fibrous tissue, ligaments, cords, or bands.
What is gomphosis?They are unions that are verified by multiple collagen fibers, which extend between the two joint surfaces and constitute the periodontium.
These joints without mobility, characterized by the presence of fibrous tissue, are the articulation of the dental roots with the alveolar cavity in which they are housed.
Therefore, we can conclude that gomphoses are fibrous joints whose bones are joined by fibrous tissue, ligaments, cords, or bands..
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Which plant tissue is the part of the plant that is edible?
ground
dermal
meristematic
vascular
Answer:
ground
Explanation:
PLSSS HELP IF YOU TURLY KNOW THISS
Answer: All of the above.
How I find this answer is because all animals need food, shelter, and a living space.
Answer:
pretty sure its all of the above.
body temperature can be regulated around a set point of 37 celsius by antagonistic mechanisms. an example is
Body temperature can be regulated around a set point of 37 celsius by antagonistic mechanisms. an example is sweating, shivering, and other mechanisms.
An organism's ability to maintain stable internal conditions is referred to as homeostasis. As part of homeostasis, human conditions like temperature and blood pressure are controlled.
The hypothalamus is a part of the brain that controls our internal body temperature. Our current temperature is checked by the hypothalamus and compared to the average temperature, which is about 37°C. The hypothalamus ensures that the body generates and maintains heat if our temperature is too low. The body regulates temperature through four mechanisms: radiation, conduction, convection, and evaporation We most heavily rely on evaporation to control our body temperature through sweating.
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PLEASE HELP
Which combination of activities reflects AEROBIC vs ANAEROBIC?
A. mile-run vs 100 yard dash
B. badminton vs tennis
C. yoga vs stretching
D. softball vs hockey
Help PLEASEEEEEE. WHAT DO I PUT IN THE GRAPH !!!!!111
in the photosynthesis reaction in plants, ________ is given off as a by-product of the reaction.
Answer:
Oxygen
Explanation:
What acceleration would be produced if a 25 N force acts on a 5.0 kg mass? (a = F/m) *
Answer:
5 m/s
Explanation:
Using the formula, the force is 25 N, and the mass is 5 kg.
Simply divide 25/5.0
Then, you would get 5 m/s
I hope this helps.
The cells produced in mitosis are called what
Answer:
I am pretty sure it's haploid sex cells
Answer:
the cells produced in mitosis are diploid body cells
The photo shows muscle tissue.
What is the function of muscle tissue?
O A. To contract to cause movement in the body
B. To cover the body to protect other cells
C. To transport materials and defend the body
OD. To send signals to control the body
Elevation and Red Blood Cell Count
It is hypothesized that runners who live "high" and train "low" have higher EPO and RBC counts. Below is the data to predict the RBC count based on the living elevation of various Olympic athletes.
a = 6.06
b = .00067
Find the following athlete's RBC count (in uL's) based on their housing elevation of 1400 meters
Select one:
a. 6.998 uL's
b. None of the answers provided
c. 8484.067 uL's
d. 6.067 uL's
To find the athlete's RBC count (in uL's) based on their housing elevation of 1400 meters, we can use the given equation:
RBC count (in uL's) = a + b * elevation
Substituting the values provided:
a = 6.06
b = 0.00067
elevation = 1400
RBC count = 6.06 + 0.00067 * 1400
RBC count = 6.06 + 0.938
RBC count ≈ 6.998 uL's
Therefore, the athlete's RBC count based on their housing elevation of 1400 meters would be approximately 6.998 uL's.
The correct answer is:
a. 6.998 uL's
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The oceans formed as a result of:
(1) oxygen producing organisms
(2) out gassing from volcanoes
(3) meteorite impacts bringing water from outer space
(4) transpiration from early plants
In pine trees, pollen grains get to the ovule via the _____. a) eggs b) integument c) megaspore d) pollen cone e) micropyle.
Pollen grains enter the ovule via the micropyle in pine trees. A small opening in the ovule's integuments through which sperm can enter the ovum.
The micropyle is a small opening in the ovule near the hilum that is retained in the seed after fertilization. Seeds absorb water primarily through the micropyle when soaked. Micropyle also assists in respiration and gas exchange. Five carpels, or sometimes fewer, fuse to form an ovary with the same number of chambers. Each chamber contains one to two pendulous anatropous ovules connected to the central column with the raphe facing the placenta and the micropyle pointing outward.
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Mendel did a parental cross with true-breeding tall pea plants and true-
breeding short pea plants. The plants in the F1 generation were 100% tall
plants. What did he find for the plants in the F2 generation? *
*
a. A 4:0 ratio of tall plants to short plants since the F1 plants used in that cross were
all tall.
b. A 3:1 ratio of tall plants to short plants since the F1 generation was heterozygous.
c. A 4:1 ratio of tall plants to short plants since the allele for tall plants is dominant.
d. A 1:1 ratio of tall plants to short plants since the F2 generation had the same
characteristics as the parent plants.
Mendel evaluated in his pea plants were each expressed as one of two versions, or traits. Mendel deduced from his results that each individual had two discrete copies of the characteristic that are passed individually to offspring. We now call those two copies genes, which are carried on chromosomes. The reason we have two copies of each gene is that we inherit one from each parent. In fact, it is the chromosomes we inherit and the two copies of each gene are located on paired chromosomes. Recall that in meiosis these chromosomes are separated out into haploid gametes. This separation, or segregation, of the homologous chromosomes means also that only one of the copies of the gene gets moved into a gamete. The offspring are formed when that gamete unites with one from another parent and the two copies of each gene (and chromosome) are restored.
For cases in which a single gene controls a single characteristic, a diploid organism has two genetic copies that may or may not encode the same version of that characteristic. For example, one individual may carry a gene that determines white flower color and a gene that determines violet flower color. Gene variants that arise by mutation and exist at the same relative locations on homologous chromosomes are called alleles. Mendel examined the inheritance of genes with just two allele forms, but it is common to encounter more than two alleles for any given gene in a natural population.
ASAP!! DESCRIBE WHAT IS FOUND IN THE NUCLEUS OF THE CELL?!!
Explanation:
The semifluid matrix found inside the nucleus is called nucleoplasm.
DNA
RNA
Nucleolus
Chromosomes
Nucleoplasm