The expression 148 – 24d gives the number of pizzas a store has in stock, where d is the number of days. How many pizzas will the store have in stock after five days?

My own multi-step combination problem is given below:

To solve this problem, Amanda  need to use the formula for combinations and it is:

nCr = n! / (r! x (n-r)!)

where:

n = total number of items to select from

r is the number of items to select.

First, we have to calculate the number of ways to select 3 fruit from 5, hence it will be:

5C3

=  5! / (3! x (5-3)!)

= 10

Next, we have to calculate the number of ways to select 2 meatpie from 4 and it will be

4C2

= 4! / (2! x  (4-2)!)

= 6

Lastly,, we need to calculate the number of ways to select 2 desserts from 3 and it will be:

3C2

= 3! / (2! x  (3-2)!)

= 3

To have the total number of dinner menus, we have to multiply these three numbers together:

= 10 x 6 x 3

= 180

Therefore, one can say that Amanda have 180 different dinner menus that she can be create.

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Answer:

96

Step-by-step explanation:

i did 32 times 3

Answer:

x= the second one I hope I helped

well, the interest is going to be the increase factor on both cases, so we can simply check how much each will accumulate to in those 4 years

\(~~~~~~ \stackrel{\textit{\LARGE University Bank}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &4 \end{cases}\)

\(A = 4000\left(1+\frac{0.05}{4}\right)^{4\cdot 4} \implies A=4000(1.0125)^{16}\implies \boxed{A \approx 4879.56} \\\\[-0.35em] ~\dotfill\)

\(~~~~~~ \stackrel{\textit{\LARGE Rosemont Savings Bank}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &4 \end{cases}\)

\(A = 4000\left(1+\frac{0.055}{2}\right)^{2\cdot 4} \implies A=4000(1.0275)^8\implies \boxed{A \approx 4969.52} ~~ \textit{\LARGE \checkmark}\)

Answer:

12 pages

Step-by-step explanation:

1 week = 7 days

84 ÷ 7 = 12 pages

The magnitude of the vector C that satisfies the expression is 6.48m

Given the following magnitude;

Vector A = 5.1m

Vector B = 4.0m (upward)

Taking the resultant vector of A and B we will have:

\(R=\sqrt{A^2+B^2}\\R=\sqrt{5.1^2+4.0^2}\\R= \sqrt{26.01+16}\\R=\sqrt{42.01}\\R= 6.48m\)

Given the expression A⃗ +B⃗ +C⃗ =0⃗

R + C = 0

C = 0 - R

C = 0 - 6.48

C = -6.48m

Hence the magnitude of the vector C that satisfies the expression is 6.48m

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Erick just needed to open the compass more to create arcs that have a radius of more than half the length of the segment AB. Option C

The steps involved in constructing a perpendicular bisector are:

Thus, Erick just needed to open the compass more to create arcs that have a radius of more than half the length of the segment AB. Option C

The complete question

Eric was attempting to construct a perpendicular bisector to the segment AB with a compass and straight edge. Which of the below statements explains what Eric may have done wrong?

a. Eric should have started by putting the compass needle point at the midpoint of the segment AB.

b. On the second step, Eric should have placed the compass needle point where the first arc intersected the segment AB.

c. Erick just needed to open the compass more to create arcs that have a radius of more than half the length of the segment AB.

d. Erick didn’t do anything wrong he just needs to connect the opposite endpoints of each arc to finish the construction.

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The function g(x) is g(x)= (1/3x)^2

The complete question is in the image

From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 1/3 to form g(x).

This means that:

g(x) = f(1/3x)

So, we have:

g(x)= (1/3x)^2

Hence, the function g(x) is g(x)= (1/3x)^2

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The inequality tha calculates the possible values of x is x < 2

From the question, we have the following parameters that can be used in our computation:

The figure

Where, we have

3x + 2 < 10

And, we have

2x + 6 < 10

Evaluate the expressions

So, we have

3x < 8 and 2x < 4

Evaluate

x < 8/3 and x < 2

Hence, the inequality tha calculates x is x < 2

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Answer:

4000

Step-by-step explanation:

36kg = 36000g

36000g/9 bags = 4000g

The weight of one bag of potatoes is 4 Kg,

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

The total weight of 9 bags of potatoes is 36 kilograms.

Then, weight of one bag of Potato is

= 36/9

= 4 Kg

Thus, One bag weigh 4 Kg.

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Question: As their financial advisor, what part of Kyle and Linda's financial plan would you encourage them to work on and why?

ANSWER:

Their plan for protecting their assets.

They should have life insurance on Linda.

Answer:

Step-by-step explanation:

To write the logarithmic form of the given exponential equation, we need to recall the definition of logarithms.If we have an exponential equation in the form of a^b = c, then we can write its logarithmic form as log_a(c) = b.

Using this definition, we can write the logarithmic form of the given exponential equation 3^5 = (2x - 6) as:log_3(2x - 6) = 5

log_{3}(2x - 6) = 5

To convert the given exponential equation into logarithmic form, we can use the following formula:

If b^x = y,  then   log_b(y) = x

Using this formula, we can write the logarithmic form of the given exponential equation as:

log_{3}(3^5) = log_{3}(2x - 6)

The left side simplifies to:

5 = log_{3}(2x - 6)

Therefore, the logarithmic form of the exponential equation 3^5 = (2x - 6) is:

log_{3}(2x - 6) = 5

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The true expression about the account is D.) It is the sum of the initial amount and the additional amount after d days.

The answer is D because it represents the sum of the initial amount and the additional amount after d days. The initial amount is $10 and Owen adds $0.50 to the account each day for a number of days, represented by d.

By subtracting 1 from d, the expression ensures that on the first day (when d=1), only the initial $10 is counted. On each subsequent day, the additional amount of $0.50 is added to the total. Therefore, the expression 10+0.5(d−1) gives the amount of money in Owen's account after d days.

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Answer:

y = x + 18

Step-by-step explanation:

slope:

  m = (y₂ - y₁) / (x₂ - x₁)

      = (10 - 18) / (-8 - 0)

      = -8 / -8

      = 1

y-intercept using m from above and anyone of given points, let's use (0, 18):

  y = mx + b

  (18) = 1(0) + b

  b = 18

Using m and b from above form equation of line:

  y = mx + b

  y = 1x + 18 or y = x + 18

The equations that can be used to solve for y, the length of the room, are: y(y + 5) = 750, y² – 5y = 750, and y(y – 5) + 750 = 0.

It states that when multiplying a number by a group of numbers added together, you can multiply the number by each individual number in the group and add the products together to get the same answer.

In order to find the length of the room, we need to solve for y in each of the equations given.

First, let's solve for y in the equation y(y + 5) = 750. We can use the distributive property to expand the equation to y² + 5y = 750.

Then, we can subtract 750 from both sides of the equation to get y² + 5y - 750 = 0.

To solve the equation, we need to factor it. We can use the difference of squares formula to factor the equation, yielding (y + 25)(y - 30) = 0. Therefore, one solution for y is y = -25, and the other solution is y = 30.

Second, let's solve for y in the equation y² – 5y = 750.

To solve this equation, we can add 5y to both sides to get y² = 5y + 750. Then, we can divide both sides by y to get y = 5y + 750.

We can then subtract 5y from both sides to get y - 5y = 750. Finally, we can divide both sides by 5 to get y = 150.

Third, let's solve for y in the equation y(y – 5) + 750 = 0.

To solve this equation, we can use the distributive property to expand the equation to y² – 5y + 750 = 0.

Then, we can subtract 750 from both sides to get y² – 5y = -750.

To solve the equation, we need to factor it. We can use the difference of squares formula to factor the equation, yielding (y + 25)(y - 30) = 0. Therefore, one solution for y is y = -25, and the other solution is y = 30.

In conclusion, the equations that can be used to solve for y, the length of the room, are y(y + 5) = 750, y2 – 5y = 750, and y(y – 5) + 750 = 0. The solutions for y are y = -25 and y = 30.

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Answer:

12 m2

Step-by-step explanation:

because 3 times 4 is 12  and i do odyseyware to so that's why i know the answer

Answer:

9/11

Step-by-step explanation:

(6 × 3)/22

18/22 = 9/11

Answer:

formulas to solve 3 overlapping sets in vent diagram for example cat/ by vetting there are two basic formulas that we already know total=n (no set) + n (exactly two sets) + n (exactly three sets)

Answer: X- (6,8)   Y- (9,8)   Z-(6,4)

Step-by-step explanation:

Answer:

\(d < 20\)

Step-by-step explanation:

The key words in this question are fewer than, which signifies the less than sign. So, the number of days that Byron worked is less than 20.

The angle measures for this problem are given as follows:

The sum of the measures of the internal angles of a triangle is of 180º.

The triangle in this problem is ABC, hence the measure of a is obtained as follows:

a + 68 + 50 = 180

a = 180 - (68 + 50)

a = 62º.

c and d are corresponding angles to angle a, as they are on the same position relative to parallel lines, hence their measures are given as follows:

Angle b is a corresponding interior angle with angle a, hence they are supplementary and it's measure is given as follows:

a + b = 180

62 + b = 180

b = 118º.

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Answer:

I think your answer would be 5.6

Step-by-step explanation:

56% of 10 = 5.6

The area of triangle ADE is,

⇒ A = 48 square units

We have to given that,

In the diagram , DE is a midsegment of triangle ABC.

And, The area of triangle ABC is 96 square units

Now, We know that,

Since DE is a midsegment of triangle ABC, it is parallel to AB and half the length of AB. Therefore, DE is half the length of AB.

Hence, the area of triangle ADE is half the area of triangle ABC,

That is,

A = 96 / 2

A = 48 square units

Thus, The area of triangle ADE is,

⇒ A = 48 square units

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Answer: (In order)

25/4 / 6 1/4 = 1

3 1/7 / 2/7 = 11

5/4 / 1/4 = 5

11 1/4 / 9/4 = 5

8 1/4 / 3/4 = 11

3 1/3 / 10/3 = 1

Step-by-step explanation:

Answer:

\(Q(-2,3) \longrightarrow Q'(-1/3, 1/2) \\ \\ R(-3,1) \longrightarrow R'(-1/2, 1/6) \\ \\ T(2,-1) \longrightarrow T'(1/3, -1/6) \\ \\ W(2,4) \longrightarrow W'(1/3, 2/3)\)

Step-by-step explanation:

For a dilation at the origin, multiply each of the coordinates by the scale factor.

\(Q(-2,3) \longrightarrow Q'(-1/3, 1/2) \\ \\ R(-3,1) \longrightarrow R'(-1/2, 1/6) \\ \\ T(2,-1) \longrightarrow T'(1/3, -1/6) \\ \\ W(2,4) \longrightarrow W'(1/3, 2/3)\)

Answer:

y = 4\(\sqrt{5}\) , ? = 10

Step-by-step explanation:

using Pythagoras' identity on the smallest right triangle

x² = 4² + 2² = 16 + 4 = 20 ( take square root of both sides )

x = \(\sqrt{20}\) = \(\sqrt{4(5)}\) = \(\sqrt{4}\) × \(\sqrt{5}\) = 2\(\sqrt{5}\)

using Pythagoras' identity on the middle right triangle

y² = 8² + 4² = 64 + 16 = 80 ( take square root of both sides )

y = \(\sqrt{80}\) = \(\sqrt{16(5)}\) = \(\sqrt{16}\) × \(\sqrt{5}\) = 4\(\sqrt{5}\)

using Pythagoras' identity on the largest right triangle

?² = x² + y² = (2\(\sqrt{5}\) )² + (4\(\sqrt{5}\) )² = 20 + 80 = 100

Take square root of both sides

? = \(\sqrt{100}\) = 10

The limit of the difference quotients for f(x) = x^2 + 2x + 1 as x approaches -1 is indeterminate.

To find the limit of the difference quotients for the function f(x) = x^2 + 2x + 1 as x approaches -1, we need to evaluate the following expression:

lim(x→-1) [f(x) - f(-1)] / (x - (-1))

First, let's substitute the values into the expression:

lim(x→-1) \([(x^2 + 2x + 1) - (-1^2 + 2(-1) + 1)] / (x + 1)\)

Simplifying further:

lim(x→-1) \([(x^2 + 2x + 1) - (1 - 2 + 1)] / (x + 1)\)

lim(x→-1)\([x^2 + 2x + 1 - 0] / (x + 1)\)

lim(x→-1) \((x^2 + 2x + 1) / (x + 1)\)

Now, we can directly substitute x = -1 into the expression:

\((-1^2 + 2(-1) + 1) / (-1 + 1)\)

(1 - 2 + 1) / (0)

0 / 0

We have obtained an indeterminate form of 0/0. This indicates that we need to further simplify the expression or use other techniques, such as L'Hôpital's rule, to evaluate the limit. However, without additional information or simplification, we cannot determine the precise value of the limit at x = -1.

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The solution of the composite function fog(x) = 3x + 3 at x > 2.

Let the two function f(x) and g(x) generate a new function h(x) using an operation.

The operation is composition of functions and h(x) is a composite function.

We have three piecewise function.

First we have to show that,

the composite function,

fog(x) at x > 2.

For that,

g(x) at x > 2 is,

g(x) = 3x.

Now, f(g(x)),

= f(3x)

= 3x + 3 at x > 2.

Therefore, the function is fog(x) = 3x + 3.

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The complete question:

Find the fog(x) at x > 2

Answer:

1x0.8=0.8 ,10x0.08=0.8 and 100x0.008=0.8

Step-by-step explanation: