The following two lists give the diameters and sound frequencies for three loudspeakers. Pair each diameter with a frequency, so that the diffraction angle is the same for each of the speakers, and then find the common diffraction angle. Take the speed of sound to be 343 m/s. Answer should be in degrees
Diameter, D Frequency, f
0.1 m, 5 kHz
0.5 m, 10 kHz
0.2 m, 2 kHz

Answer:

I think its C or A

Explanation:

Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

The moment of inertia, denoted as I, is the measure of an object's resistance to rotational acceleration. It depends on the shape, mass distribution, and orientation of the object. For a thin, uniform disk rotating around its center of mass, the moment of inertia can be calculated using the formula Icm = (1/2)mr^2, where m is the mass of the disk and r is the radius of the disk.

The moment of inertia of a thin, uniform disk rotating around its center of mass is given by the formula Icm = (1/2)mr^2, where m is the mass of the disk and r is the radius of the disk.

In summary, the moment of inertia is the measure of an object's resistance to rotational acceleration. For a thin, uniform disk rotating around its center of mass, the moment of inertia can be calculated using the formula Icm = (1/2)mr^2.

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Answer:

The correct answer is B.

The astronaut will know due to the light from the explosion.

Explanation:

Sound and vibrations require a medium such as air to travel through. Space, there is no air. Only a vacuum. So sound and vibrations are unable to travel. Light requires no medium to travel. It can go through a vacuum.  

Therefore the Astronaut will see a bright flash of light as it travels from the explosion to outer space. It is also important to note that light can travel very far because nothing else interacts with its wave particles and as such, it cannot be impeded.

Cheers!

A magnetic field is experienced by the charged particle in the +y direction.

Discussion:

Fleming's left-hand rule:

In accordance with Fleming's Left Hand Rule, the thumb, forefinger, and middle finger of the left hand should be positioned perpendicular to one another. The thumb should point in the path of the power exerted by the conductors, the forefinger should point in the magnetic field direction, and the middle finger should point in the path of the electric current.

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Answer:

a) given that mass=0.6kg,distance of stretching from equilibrium position x=0.9m from new ton's second law,F=ma where a is acceleration of the body.Therefore,force on the spring -mass syste

Explanation:

hope it helps

Answer:

17.565 kgm/s

Explanation:

Momentum = mass × velocity

I = mv..................... Equation 1

But we can calculate the value of v  using the equation of motion under gravity.

v² =  u²+2gs............. Equation 2

Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.

Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.

Constant: g = 9.8 m/s²

Substitute these values into equation 2

v² = 0²+ 2×7×9.8

v² = 137.2

v = √137.2

v = 11.71 m/s.

Also given: m = 1.50 kg

substitute these values into equation 1

Therefore,

I = 1.5×11.71

I = 17.565 kgm/s

If a teacher wanted to be as exact as possible in recording frequently occurring aggressive behaviors such as hitting, kicking, and biting during a 20-minute activity period, the recording procedure that the teacher should use is Interval recording technique.

The interval recording technique is a behavior observation method that entails determining whether specific behaviors occur or not. The observation period is divided into intervals, each lasting a specific amount of time. At the conclusion of each period, the observer records whether or not the behavior occurred during that period. This method is commonly used to determine whether a behavior occurs frequently or not.

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The value by which the smallest sample observation could be increased without affecting the value of the sample mean is 1749.7 km.

We need to compute the values of the sample mean and the sample median. The given data has 16 values. Therefore,n = 16.  Here are the steps to find the mean and median:

Add up all the values. Divide the sum by n.

If n is even, find the mean of the two middle values. If n is odd, the median is the middle value. After we have arranged the given data from smallest to largest, the mean is given by:

Mean = 1/16 [73.6 + 86.3 + 86.5 + 91.3 + 91.5 + 93.7 + 98.3 + 100.7 + 101.1 + 106.4 + 110.9 + 113.2 + 114.0 + 115.3 + 125.3 + 139.4]

Mean = 104.05625

The median can be found as the average of the two middle values, which are 100.7 and 106.4.

Hence,Median = (100.7 + 106.4)/2 = 103.55 .The sample median is the middle value of the data when it is arranged in ascending order. If the smallest sample observation is increased, it will not affect the value of the sample median if the new value is less than or equal to the original median.

The original median was found to be 103.55. The smallest observation is 73.6. Therefore, the value by which the smallest sample observation could be increased without affecting the value of the sample median is:103.55 - 73.6 = 29.95 km

The sample mean is the sum of all the data divided by the number of observations. If the smallest sample observation is increased, it will increase the sum of all the data.

Therefore, it will affect the value of the sample mean. The original sample mean was found to be 104.05625 km. If the smallest sample observation is increased by x km, the new mean is given by:

New mean = 1/16 [x + 86.3 + 86.5 + 91.3 + 91.5 + 93.7 + 98.3 + 100.7 + 101.1 + 106.4 + 110.9 + 113.2 + 114.0 + 115.3 + 125.3 + 139.4]

We need to find the value of x for which the new mean is equal to the original mean. Therefore,

104.05625 = 1/16 [x + 86.3 + 86.5 + 91.3 + 91.5 + 93.7 + 98.3 + 100.7 + 101.1 + 106.4 + 110.9 + 113.2 + 114.0 + 115.3 + 125.3 + 139.4]16 x 104.05625 = x + 1485.8x = 1823.3 km

Therefore, the smallest sample observation could be increased by 1823.3 - 73.6 = 1749.7 km without affecting the value of the sample mean.

The sample means and sample median of the given data was found to be 104.05625 km and 103.55 km, respectively. The value by which the smallest sample observation could be increased without affecting the value of the sample median is 29.95 km.

The length of the internet optical cable to avoid becoming unrecognizable should be less than or equal to the smallest value of the sample data, which is 73.6 km.

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Answer:

Grades ... gravity affects them and the potential energy is converted into kinetic energy. Watching a Slinky move down the stairs or vibrating while ... and kinetic energy, and finally into sound waves.

Explanation:

Answer:

A wave as seen above will start losing energy by transferring it to kinetic and rotational energy at the shallow bottom including sand transfers, which finally will become heat (extra kinetic energy). ... In the end all energy will end up as a higher temperature in the region and ground than if the ocean were calm.

Explanation:

plz mark me has brainlist

Explanation:

Generally, stream flows are measured in CFS   = Cubic Feet per Second

The angle of incidence in the glass is approximately 31.8°.

To find the angle of incidence in the glass, we can use Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction:

n1 * sin(angle of incidence) = n2 * sin(angle of refraction)

In this case, n1 is the index of refraction for flint glass (1.61), n2 is the index of refraction for ethanol (1.36), and the angle of refraction in ethanol is 27.2°.

Plugging in these values into Snell's law, we get:

1.61 * sin(angle of incidence) = 1.36 * sin(27.2°)

To find the angle of incidence, we can rearrange the equation:

sin(angle of incidence) = (1.36 * sin(27.2°)) / 1.61

Now, we can solve for the angle of incidence by taking the inverse sine (or arcsine) of both sides:

angle of incidence = arcsin((1.36 * sin(27.2°)) / 1.61)

Calculating this value, the angle of incidence in the glass is approximately 31.8°.

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Answer:

Part A: 2.24

Part B: 551 nm

Explanation:

\(n_1*v_1=n_2*v_2\) (n1 and n2 are the indexes of refraction, and v1 and v2 are the velocities of light)

Rearrange to isolate n2: \(\frac{n_1*v_1}{v_2} =n_2\)

Speed of light in a vacuum is 3*10^8 m/s, and a vacuum has index of refraction of 1.

\(n_2=\frac{1*3*10^8}{1.34*10^8}\) = 2.24

Air has index of refraction of about 1, so speed of light in air is about 3*10^8 m/s.

Speed of light is its frequency times its wavelength. Travelling through different mediums does not affect the frequency of the light.

v = λ*f (c is speed of light in diamond, λ is wavelength of light, and f is frequency of light)

Rearrange to isolate f: f = v/λ

246 nm = 2.46*10^-7 m

f = \(\frac{1.34*10^8}{2.46*10^{-7}}\) = 5.45*10^14 Hz

To find wavelength of light in air, rearrange v = λ*f to λ = v/f = \(\frac{3*10^8}{5.45*10^{14}}\) = 5.51*10^-7 m = 551 nm

Part a. The index of refraction of diamond at this wavelength is 0.0434.

Part b. The wavelength of the light in air is approximately 1.06× \(10^8\) m/s.  

The index of refraction of diamond at this wavelength, we need to use the formula:

n = c/v

here n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium. We know that the speed of light in a vacuum is 299,792,458 m/s, so we can substitute this value into the formula:

n = (1.34× \(10^8\) m/s)/(299,792,458 m/s)

n = 0.0434

The index of refraction of diamond at this wavelength is 0.0434.

The wavelength of the light in air, we can use the formula:

wavelength = c/n

here wavelength is the wavelength of the light in air, and n is the index of refraction of air. We know that the index of refraction of air is 1, so we can substitute this value into the formula:

wavelength = (1.34× \(10^8\) m/s)/(1)

wavelength = 1.34× \(10^8\) m/s

Therefore, the wavelength of the light in air is approximately 1.06× \(10^8\) m/s.  

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The intensity of 1 MeV gamma-rays incident on a thin slab of water required to give an absorption rate of 1 rad/sec is approximately \(6.25 * 10^{13} MeV/sec\).

To calculate the radiation intensity, we need to convert the absorption rate of 1 rad/sec to the dose rate in Gray/sec, and then to the radiation intensity in MeV/sec. Since 1 rad/sec is equivalent to an absorption rate of 0.01 Gy/sec, we have:

0.01 Gy/sec = (energy absorbed per second) / (mass of material x 1 sec)

For water, the mass per unit volume is \(1 gram/cm^3\) or \(1000 kg/m^3\). Therefore, we have:

\(0.01 Gy/sec = (energy absorbed per second) / (1000 kg * 1 m^2 * 1 sec)\)

Solving for the energy absorbed per second, we get:

energy absorbed per second = 0.01 Gy/sec x 1000 kg = 10 J/sec

The energy of 1 MeV gamma-rays is equal to \(1.6 * 10^{-13} J\). Therefore, the radiation intensity required to deposit 10 J of energy per second in the water is:

\(intensity = (10 J/sec) / (1.6 *10^{-13} J/MeV) = 6.25 *10^{13} MeV/sec\)

Therefore, the intensity of 1 MeV gamma-rays incident on a thin slab of water required to give an absorption rate of 1 rad/sec is approximately \(6.25 * 10^{13} MeV/sec\).

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Answer:

I have tried 27.12 and 26.95

Explanation:

which is not its actual value

Answer: Attach it to clothing, personal flotation device or the person's person.

Explanation:

This particular Question or problem has to do with the rules and regulations or laws governing the use of Personal Watercraft(PWC) in the state of Florida in the United States of America. Hence, one of the rules that is applicable to the use of boats and waterways or the use of personal watercraft in Florida is that in florida, if ones pwc is equipped with an engine cut-off lanyard the person operating it must ATTACH IT TO THE CLOTHING, PERSONAL FLOATATION DEVICE IR THE OPERATORS' PERSON.

Another rule band the use of flammable personal flotation device with Personal Watercraft(PWC) in the state of Florida. All this rules and guildlines are made to limit or minimize hazards.

F=m*a

T = 142N

Work = Force x distance

distance = 6.1 M

Force = 142 x cos 37 = 113.4 N

W= 113.4N x 6.1M = 691.78 J

Answer:

We can use Hooke's law, which states that the extension of a spring is proportional to the force applied to it, as long as the elastic limit is not reached. Mathematically, this can be expressed as:

F = kx

where F is the force applied to the spring, x is the extension of the spring, and k is the spring constant.

We can use the given information to find the spring constant k:

50N = k(25cm - 20cm)

50N = 5cm k

k = 10N/cm

Now we can use Hooke's law to find the extension of the spring when a force of 100N is applied:

100N = (10N/cm)x

x = 10cm

Therefore, the length of the spring when stretched by 100N is:

20cm + 10cm = 30cm

The behavior of springs is governed by Hooke's Law, which states that the force required to stretch or compress a spring by some distance is proportional to that distance. Mathematically, this is expressed as:

\($$F = kx$$\)

where:

- \(\(F\)\) is the force applied,

- \(\(k\)\) is the spring constant, and

- \(\(x\)\) is the displacement from the spring's original position.

Given that a 50N force stretches the spring from 20cm to 25cm (a 5cm or 0.05m stretch), we can first calculate the spring constant \(\(k\)\). Then, we can use this spring constant to find the displacement when a 100N force is applied.

Let's calculate the spring constant \(\(k\)\) first.

It seems there was a misunderstanding in the interpretation of the equation. The goal is to solve for \(\(k\)\), the spring constant, not \(\(N\)\), the force. Let's correct this and solve for \(\(k\)\) in the equation \(\(50N = k * 0.05m\)\).

The spring constant \(\(k\)\) is found to be \(\(1000 \, \text{N/m}\)\).

Now, let's use this spring constant to find the displacement when a 100N force is applied. We rearrange Hooke's Law to solve for \(\(x\)\):

\($$x = \frac{F}{k}$$\)

Substituting \(\(F = 100N\)\) and \(\(k = 1000N/m\)\), we can find the displacement \(\(x\)\).

The displacement \(\(x\)\) when a 100N force is applied is 0.1 meters or 10 cm.

Remember, this displacement is the amount the spring stretches from its original length due to the applied force. So, to find the total length of the spring when a 100N force is applied, we add this displacement to the original length of the spring (20 cm).

Let's calculate the total length of the spring.

The total length of the spring when a 100N force is applied will be 30 cm, assuming that the elastic limit is not reached.

Answer:

At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.

Explanation:

The statement itself is true. But to be completely and compulsively correct, that's Newton's FIRST law of motion, not the third.

20.94 m is the horizontal distance R' from a point directly below the center of the loop to the impact point.

When the car leaves the track, it moves along a straight line tangent to the loop, forming a tangent. From the given information, it is observed that the radius of the loop is 20 m and the speed is 10 m/s. In the given diagram, θ represents the angle made by the line joining the center of the circle and the point where the car leaves the track. Let’s answer the given questions.

Step 1: Find the angle θ

Using the formula,v² = rg

From the given information,N² = rgN²

= 20g(g

= 9.8 m/s²)θ

= sin⁻¹(N²/rg)θ

= sin⁻¹((10)²/20(9.8))θ

= 49.03°

Step 2: Find the horizontal distance R

'The horizontal distance from a point directly below the center of the loop to the impact point can be found using the formula

,R' = (2r + h) tan(θ/2)

where h is the height of the center of the loop from the ground.

R' = (2 × 20 + 0.6) tan(49.03/2)

R' = (40 + 0.6) tan(24.51)

R' = (40.6) (0.516)

R' = 20.94 m

Therefore, the angle θ when the car leaves the track is 49.03° and the horizontal distance R' from a point directly below the center of the loop to the impact point is 20.94 m.

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Answer:

c

Explanation:

all the others r physical

Answer:

Air temperature and air pressure both decreases

Answer: A

Explanation:

Answer:

mars is a fourth planet of the sun and the second planet in the solar system

moon is a natural satellite of the earth it isthe fifth largest moon in the solar system

Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{p}{v} \\ \)

p is the momentum

v is the velocity

From the question we have

\(m = \frac{10}{20} = \frac{1}{2} \\ \)

We have the final answer as

Hope this helps you

Answer:

B

Good luck! Have a great day!

Answer:

y e s

Explanation: