Answer:
r = 0.174 m
Explanation:
gravitational force equation
F is the force of attraction,
G is the gravitational constant (6.6743 x 10^-11 N*m^2/kg^2),
m1 and m2 are the masses of the two students, and
r is how far apart are the students sitting
F = G * (m1 * m2) / r^2
N = Newtons = kg⋅m/s^2
2.30 x 10^-8 N = (6.6743 x 10^-11 N*m^2/kg^2) * (45.0 kg * 55.0 kg) / r^2
r^2 = (6.6743 x 10^-11 N*m^2/kg^2) * (45.0 kg * 55.0 kg) / (2.30 x 10^-8 N)
r^2 = (6.6743 x 10^-11 kg⋅m/s^2*m^2/kg^2) * (45.0 kg * 55.0 kg) / (2.30 x 10^-8 kg⋅m/s^2)
Take the square root of both sides, we get:
r = 0.174 m
ChatGPT
What is the pressure transmitted in the liquid on a hydraulic pump where an elephant with a weight of 40 000 N is placed on top of the large piston with an area of 40 m2. The small piston area is 4 m2.
Answer:
What is the pressure transmitted in the liquid on a hydraulic pump where an elephant with a weight of 40 000 N is placed on top of the large piston with an area of 40 m2. The small piston area is 4 m2.
Question 4 of 10
You add 100 mL of water at 20°C to 200 mL of water at 80°C. What is the
most likely final temperature of the mixture?
A. 50°C
OB. 60°C
C. 100°C
OD. 30°C
(asons
Heat received by cold water equals heat lost by hot water. 60°C is the ultimate temperature.
What does the term temperature mean?An evaluation of an object or substance's warmth or coolness in relation to a reference value.
a measurement of how much heat is required to raise the temperature of a material by one degree Celsius for every gramme.
The unit of measurement for specific heat is Joules per gramme per degree Celsius (J/g °C).
Let c represent the water's specific heat.
based on the calorimetry concept.
Heat received by cold water equals heat lost by hot water.
200 * c * (80 - T) = 100 * c * (T - 20) (T - 20)
∴ 200c (80-T) = 100c(T-20) (T-20)
∴2 (80-T) = T - 20
∴160-2T=T-20
∴ 160+20 = T +2T
∴180 = 3T
∴T = 60 C.
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How does the Coriolis effect impact the Gulf Stream and the Brazil Current?
Answer: The Coriolis effect results in bending the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere. The Coriolis effect causes winds and currents to form the circular patterns. The direction in which they spin depends upon the hemisphere in which they are present.Coriolis Effect is named after the French mathematician and physicist Gaspard-Gustave de Coriolis. It affects the weather patterns of an area, it affects the ocean currents, and it also affects air quality.
The further away the galaxy is, the ___________ the shift found by Hubble.A. Not enough infoB. SmallerC. Same sizeD. Greater
Given the statement:
The further away the galaxy is, the ____________ the shift found by the Hubble.
Let's complete the statement.
According the Hubble's brilliant observation, the shift of the galaxy is directly proportional to the distance of the galaxy from the Earth.
This means that as the distance of the galaxy increases, the shift also increase.
Therefore, the further away a galaxy is, the greater the shift found by the Hubble telescope.
ANSWER:
D. Greater
help me!
Bill left a hammer out in the rain all day. The next morning it had rust on it.
Oxygen and a metal chemically combine to form rust. What is rust an example of?
O a mixture
• a solution
an element
a compound
Answer:D.Compound
Explanation: internet
Paraphrase of the story Ligeia by Edgar Allan Poe in a paragraph.
A man becomes obsessed with the memory of his deceased wife and remarries, only to have strange and supernatural occurrences happen.
"Ligeia" is a short story written by Edgar Allan Poe, first published in 1838. The story follows an unnamed narrator and his love for the beautiful and intelligent Ligeia, whom he marries. After Ligeia falls ill and dies, the narrator marries again, but cannot forget his first wife. Strange occurrences and mysterious events lead the narrator to question whether Ligeia has truly left him, or if she has found a way to return from beyond the grave. The story explores themes of love, death, grief, and the supernatural.
The paragraph is "In Edgar Allan Poe's story "Ligeia," the narrator is haunted by the memory of his deceased wife, Ligeia, whom he believes to possess supernatural qualities. He later marries Lady Rowena, but her death leads the narrator to believe that Ligeia has returned to him through her body. The story explores themes of obsession, grief, and the blurred lines between reality and fantasy."
Therefore, "Ligeia" is a story by Edgar Allan Poe about a man who becomes obsessed with his beautiful and intelligent wife, Ligeia, who dies and mysteriously returns to life in the form of another woman after his second marriage to Lady Rowena.
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At a shorting range, a bullet is fired horizontally from a rifle with a velocity of 800m/s.Find how far it will fall?
Explanation:
You left out some important information.....but the bullet will fall the vertical distance ( the height) from which it was fired.
A hot air balloonist puts 125,000 Liters of air into their balloon at 27 °C and atmospheric pressure. When they heat the air to 200 °C at constant pressure, what is the final volume of the air in the balloon?
The final volume of the balloon is 197,083 L.
They are proportional to each other if the pressure does not change. However, there are pitfalls. To perform calculations we have to use the so-called absolute temperature. Increased external air pressure compresses the balloon.
Using equation;
PV =nRT
here constants are P,n, R
so the relation between P and T is
V₁ /T₁= V₂/T₂
V₂ = (V₁ /T₁)×T₂
= (125,000/300)×473
= 197,083 L.
As the volume of the balloon decreases the pressure inside the balloon increases. After all external air pressure can compensate. It becomes a balloon filled with dense cold air. According to Boyle's law, the volume of a gas of constant mass at constant temperature is inversely proportional to its pressure. The air around you has weight and pushes away everything it touches. This pressure is called atmospheric pressure or barometric pressure. This is the force exerted on a surface by the air above as gravity pulls the surface toward the Earth.
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A player prefers to make high passes that lift the puck above the ice. Which stick should the
player choose?
Answer:
i dont know
Explanation:
hello
A puppy weighing 3 kilograms races through the dog park. If she slows from a speed of 2 meters/second to 1 meter/second, what will happen to her kinetic energy? Use the kinetic energy equation.\(KE=\frac{1}{2} mv^{2}\)
A.
Her kinetic energy decreases to 1.5 J.
B.
Her kinetic energy increases to 1.5 J.
C.
Her kinetic energy remains unchanged.
D.
Her kinetic energy decreases to 1 J.
Answer: B Hope I helped ^^
Explanation:
Use the following information to calculate the gradient of River X. If the vertical change is 20 meters in 1 kilometer, then the gradient expressed in m/km is ______.
The gradient of River X expressed in m/km is 20 m/km.
Why do we compute gradient?Any line or curve's gradient will reveal the pace at which one variable is changing in relation to another. In all mathematical fields, this idea is crucial.
By dividing the difference between the -coordinates by the difference between the -coordinates, the gradient of a line is calculated. This can also be referred to as the vertical divided by the horizontal or the change in divided by the change in.
A river's gradient is a measurement of how steeply it declines over a specific distance.
Gradient = vertical change / horizontal distance = 20 meters / 1 kilometer = 20 m/km
Therefore, the gradient of River X expressed in m/km is 20 m/km.
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(PLS HELP ME NOW!!!!!) Ospreys are birds that eat fish. Where would an osprey MOST likely live?
A.
near a forest
B.
near a marsh
C.
near a desert
D.
near a prairie
Dizzy is speeding along at 22.8 / as she approaches the level section of track near the loading dock of the Whizzer roller coaster ride. A braking system abruptly brings the 328 car (rider mass included) to a speed of 2.9 / over a distance of 5.55 . Determine the braking force applied to Dizzy's car
The braking force applied to Dizzy's car is approximately 50,600 Newtons in the opposite direction to the car's motion.
What is braking force?Braking force is the force applied by a vehicle's brakes to slow down or stop the vehicle. To determine the braking force applied to Dizzy's car, we can use the equation:
force = mass x acceleration
where the acceleration is the rate at which the car's velocity changes during braking.
First, we need to calculate the initial velocity of the car before braking:
v0 = 22.8 m/s
Next, we need to calculate the final velocity of the car after braking:
vf = 2.9 m/s
The change in velocity, or delta-v, is:
delta-v = vf - v0 = 2.9 m/s - 22.8 m/s = -19.9 m/s
Note that the negative sign indicates a decrease in velocity.
We also need to calculate the time it takes for the car to come to a stop. We can use the equation:
delta-x = (v0 + vf) / 2 x t
where delta-x is the distance traveled during braking, which is given as 5.55 m.
Rearranging the equation, we get:
t = 2 x delta-x / (v0 + vf)
Substituting the given values, we get:
t = 2 x 5.55 m / (22.8 m/s + 2.9 m/s) = 0.393 s
Now we can calculate the acceleration:
acceleration = delta-v / t = (-19.9 m/s) / (0.393 s) = -50.6 m/s^2
Again, the negative sign indicates a deceleration or braking acceleration.
Finally, we can calculate the force applied to the car:
force = mass x acceleration
The mass of the car is not given, but we can assume it is approximately the same as the average mass of a roller coaster car, which is around 1000 kg.
Substituting the values, we get:
force = 1000 kg x (-50.6 m/s^2) = -50,600 N
Therefore, the braking force applied to Dizzy's car is approximately 50,600 Newtons in the opposite direction to the car's motion.
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Which one is right??
Answer:
Evaporation of water
Explanation:
\(\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}\)
ur answer is
Evaporation of water.
a car drives 16 m east, then 25 m south, then 16 m west. calculate the distance travelled by car
Answer:
16m + 25m + 16m = 57m
the car travelled 57 m
in how many ways can five basketball players be placed in three postitions?
Answer:
Well if they playing a game like that
the swirling gas that collects around a compact object, as its binary companion transfers material to it, is called
NOT an event horizon is its binary counterpart, which transports matter to it.
What is an object in a sentence?To refer to the item or person that is the target of an action, we typically use the word "object." Alternatively, the recipient. In a sentence, a verb's action is transferred to a noun or pronoun as a direct object. It typically responds to the what- or whom-questions regarding the verb.
What is a picture or an object?Icons, cursors, buttons, sprites, and other complicated artworks can be made from a collection of simple visual pieces called image objects. Without having to sketch a single pixel, Image Objects let you express creativity.
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On some early automobiles both headlights went out when one bulb burned out. The headlights must have been connected in On some early automobiles both headlights went out when one bulb burned out. The headlights must have been connected in haste. series. perpendicular. parallel.
Answer:
Series
Explanation:
Wired in 'series' means there is only one path for current.....so when either light burns out, the circuit is broken and there is no path for current so the other light will be unlit
If I keep F constant in F=ma, what is the relationship between m and a?
Answer:
If F is a constant, we can take f = 1
f = m×a
ma = 1
therefore we can say that force is hence proportinal to the product of mass and acceleration.
Consider a collision in one dimension that involves two objects of masses of 4.5 kg and 6.5 kg. The smaller Mass has an initial velocity of 12m/s and the larger mass is initially at rest. The final velocity of the smaller mass is 8.0m/s and calculate the final velocity of the larger object.
Answer:
Approximately \(2.8\; {\rm m\cdot s^{-1}}\).
Explanation:
If an object of mass \(m\) is travelling at a velocity of \(v\), the momentum \(p\) of that object would be \(p = m\, v\).
Momentum before collision:
\(4.5\; {\rm kg}\) mass: \((4.5\; {\rm kg})\, (12\; {\rm m\cdot s^{-1}}) = 54\; {\rm kg \cdot m\cdot s^{-1}}\).\(6.5\; {\rm kg}\) mass: \(0\; {\rm kg \cdot m \cdot s^{-1}}\) (since \(v = 0\; {\rm m\cdot s^{-1}}\).)Total momentum before collision:
Momentum after collision:
\(4.5\; {\rm kg}\) mass: \((4.5\; {\rm kg})\, (8.0\; {\rm m\cdot s^{-1}}) = 36\; {\rm kg \cdot m\cdot s^{-1}}\).\(6.5\; {\rm kg}\) mass: needs to be found.Momentum is conserved immediately before and after collisions. Hence, the total momentum of the two masses after the collision would be equal to the sum of their momentum before the collision, \(54\; {\rm kg \cdot m\cdot s^{-1}}\).
Subtract the momentum of the \(4.5\; {\rm kg}\) mass after the collision from the sum of momentum after the collision: \(54\; {\rm kg \cdot m\cdot s^{-1}} - 36\; {\rm kg \cdot m \cdot s^{-1}} = 18\; {\rm kg \cdot m \cdot s^{-1}}\).
Hence, the momentum of the \(6.5\; {\rm kg}\) mass after the collision would be \(18\; {\rm kg \cdot m \cdot s^{-1}}\). The velocity of this mass would be:
\(\begin{aligned}v &= \frac{p}{m} \\ &= \frac{18\; {\rm kg\cdot m \cdot s^{-1}}}{6.5\; {\rm kg}} \approx 2.8\; {\rm m\cdot s^{-1}}\end{aligned}\).
A 100g bead slides along a frictionless wire with the parabolic
shapely (2m
a. Find an expression for ay, the vertical component of acceleration, in terms of x, vx, and ax. Hint: Use the basic definitions of velocity and acceleration.
b. Suppose the bead is released at some negative value of x and has a speed of 2.3m/s as it passes through the lowest point of the parabola. What is the net force on the bead at this instant? Write your answer in component form
The net force can also be written in component form as Fnet = <0, 0.455> N.
a) The vertical component of acceleration, ay, is given by the second derivative of the position with respect to time (t) and can be expressed as:
ay = d²y/dt²
= d/dt(dy/dt)
= d/dt(vy)
Using the chain rule and the fact that x = 0 when y = 0, we can express vy in terms of x, vx, and ax as follows:
vy = dy/dt = d/dt(√(2ax)x) = √(2ax)(dx/dt) + x(1/√(2ax))(d/dt(2ax)) = vx√(2/x) + ax√(x/2)
Substituting this expression for vy into the equation for ay yields:
ay = d/dt(vy)
= (d/dt(vx))(√(2/x)) + vx(d/dt(√(2/x))) + (d/dt(ax))(√(x/2)) + ax(d/dt(√(x/2)))
= ax/2 - vx²/x³/2
b. At the lowest point of the parabola, x = -1 m and vx = 2.3 m/s. Using the expression for ay derived in part (a), we can find the vertical component of acceleration at this instant:
ay = ax/2 - vx²/x³/2
= (9.8 m/s²)/2 - (2.3 m/s)²/(-1 m)³/2
= 4.55 m/s²
The net force on the bead at this instant is equal to its mass (0.1 kg) times the vertical component of acceleration:
Fnet = may = (0.1 kg)(4.55 m/s²)
= 0.455 N upward,
where the upward direction is defined as positive. The net force may alternatively be expressed as a component as Fnet = <0, 0.455> N.
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A train travelled 500 meters in 25 seconds
\(\huge\mathfrak\red {Answer:}\)
Speed = Distance/TimeIf a train travelled 500 meters in 25 seconds then,
Speed = 500m/25sec
→ 20 m/sec\(\mathfrak\purple {Hope\: this\: helps\: you...}\)
speed=500m/25sec
20m/sec
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s east. Find the velocity of the tennis racket after the collision.
A long metal cylinder with radius a is supported on an insulating stand on the axis of a long, hollow, metal tube with radius b. The positive charge per unit length on the inner cylinder is λ, and there is an equal negative charge per unit length on the outer cylinder.A) Calculate the potential V(r) for rb.D) Show that the potential of the inner cylinder with respect to the outer is Vab=(λ/2πϵ0)ln(b/a)E) What is the potential difference between the two cylinders if the outer cylinder has no net charge?Please show all steps.
The potential V(r) for r<b is V(r) = (λ/2πϵ0)ln(b/a) - (λ/2πϵ0)ln(r/a). The potential of the inner cylinder with respect to the outer is Vab = (λ/2πϵ0)ln(b/a). If the outer cylinder has no net charge, the potential difference between the two cylinders is Vab = (λ/2πϵ0)ln(b/a).
To calculate the potential V(r) for r<b, we use the formula for the potential due to a uniformly charged line. The potential at a distance r from the axis of the cylinder can be found by summing the potentials due to the positive and negative charges on the inner and outer cylinders. Using the formula V = (λ/2πϵ0)ln(b/a), where λ is the charge per unit length, ϵ0 is the permittivity of free space, and a and b are the radii of the cylinders, we can derive the expression V(r) = (λ/2πϵ0)ln(b/a) - (λ/2πϵ0)ln(r/a).
The potential of the inner cylinder with respect to the outer cylinder, denoted as Vab, can be calculated by substituting r = a into the expression for V(r). This simplifies the equation to Vab = (λ/2πϵ0)ln(b/a).
If the outer cylinder has no net charge, the potential difference between the two cylinders is equal to the potential of the inner cylinder with respect to the outer cylinder. Therefore, the potential difference Vab is given by Vab = (λ/2πϵ0)ln(b/a).
In summary, the potential V(r) for r<b can be determined using the charge per unit length λ, the radii a and b, and the permittivity of free space ϵ0. The potential of the inner cylinder with respect to the outer cylinder is Vab, and it is equal to (λ/2πϵ0)ln(b/a). If the outer cylinder has no net charge, the potential difference between the two cylinders is also Vab.
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A three phase, 50 Hz overhead line has regularly transposed conductors are horizontally 4 m apart. The capacitance of such line is 0.01 μF/km. Recalculate the capacitance per km to neutral when conductors are placed equilaterally spaced 4 m apart and regularly transposed.
A. 0.0101 μF/km
B. 0.0102 μF/km
C. 0.0103 μF/km
D. 0.0104 μF/km
The capacitance per kilometer to neutral in the equilateral arrangement is approximately 0.00667 μF/km.
To calculate the capacitance per kilometer to neutral when conductors are placed equilaterally spaced 4 m apart and regularly transposed, we can use the formula for the capacitance of an equilateral triangle arrangement of conductors:
Ceq = (2/3) * C
where Ceq is the capacitance per kilometer to neutral in the equilateral arrangement, and C is the capacitance per kilometer in the original arrangement.
Given that the capacitance of the original arrangement is 0.01 μF/km, we can calculate the capacitance per kilometer to neutral in the equilateral arrangement:
Ceq = (2/3) * C
= (2/3) * 0.01 μF/km
≈ 0.00667 μF/km
Therefore, the capacitance per kilometer is approximately 0.00667 μF/km.
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4. A lens has a focal length of 2m. A pencil is placed 3m from the lens.
a. Where will the image of the pencil be formed? (show all work) (3 marks)
I
b. Is the image inverted or upright? How do you know? (1 mark)
(a) The distance of the image of the pencil from the lens is determined as 6 m.
(b) The image formed is upright, because it is magnified.
Image distance
The distance of the image formed is determined by applying lens formula as shown below;
1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = 1/2 - 1/3
1/v = (3 - 2)/6
1/v = 1/6
v = 6 m
Magnification of the imageM = v/u
M = 6/3
M = 2
A convex lens forms an upright and magnified image.
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A person with M1=65kg stands at the left end of a uniform beam with mass M2= 106kg and a length L=3.8m. Another person with mass M3=70kg stands on the far right end of the beam and holds a medicine ball with mass M4=16kg (Assume that the medicine ball is at the far right end of the beam as well). Let the origin of our coordinate system be the left end of the original position of the beam as shown in the bellow drawing and also assume there is no friction between the beam and floor.1) What is the center of mass of the system? 2) The medicine ball is thrown to the left end of the beam and caught. What is the location of the center of mass now?3) What is the new x-position at the left end of the beam? (How far did the beam move when the ball was thrown from person to person).4) To return the medicine ball to the other person, both people walk to the center of the beam. At what x-position do they end up?
We have the next information
Which is true? if the angle between them is smaller than that given by Rayleigh's criterion. Two objects are resolvable Two objects are resolvable if the angle between them is equal to that given by Rayleigh's criterion. O Two objects are resolvable if the angle between them is greater than that given by Rayleigh's criterion.
The correct statement is: Two objects are resolvable if the angle between them is smaller than that given by Rayleigh's criterion.
Rayleigh's criterion, also known as the Rayleigh criterion of resolution, provides a criterion for determining the minimum angle at which two objects can be resolved as separate entities in an optical system, such as a telescope. According to Rayleigh's criterion, two point sources are just resolvable if the central maximum of the diffraction pattern produced by one source coincides with the first minimum of the diffraction pattern produced by the other source.
In practical terms, this means that if the angle between the objects is smaller than the angle determined by Rayleigh's criterion, they will appear as separate and distinct objects. On the other hand, if the angle between the objects is equal to or greater than the angle given by Rayleigh's criterion, they will blend together and cannot be resolved as separate entities.
Therefore, for two objects to be resolvable, the angle between them must be smaller than the angle specified by Rayleigh's criterion. This criterion defines the limit of resolution and is influenced by factors such as the wavelength of light and the aperture size of the optical system.
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A potter’s wheel moves from rest to an angular speed of 0.40 rev/s in 37.5 s.
Assuming constant angular acceleration,
what is its angular acceleration in rad/s2
The angular acceleration of the potter's wheel is 0.067 rad/s².
The given parameters:
Final angular speed, ωf = 0.4 rev/sTime of motion, t = 37.5 sWhat is angular acceleration?Angular acceleration of an object is the rate of change of angular speed of the object.The angular acceleration of the potter's wheel is calculated as follows;
\(\alpha = \frac{\Delta \omega }{t} \\\\\alpha = (0.4\ rev/s \times \frac{2 \pi \ rad}{1 \ rev} ) \times \frac{1}{37.5 \ s} \\\\\alpha = 0.067 \ rad/s^2\)
Thus, the angular acceleration of the potter's wheel is 0.067 rad/s².
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Students push a swing with a hard push and a soft push. Each time the students count how many time the swing moves back and forth before stopping. What variable is tested in this investigation?
a. differences in pushes and pulls
b. force of the push
c. number of time the swing moves
d. distance the swing moves