the half-life of iodine-123 is 13.3 hours. how much of a 25.0 mg sample will remain after 39.9 hours?

Answers

Answer 1

If iodine has a 13.3 hour half life, 3.12 mg of the original sample will still be present after 39.9 hours.

what is The meaning of half-life?

The reaction rate must decrease to half its initial value before the process has reached its half life. The split of that first order chemical reaction is a quantity related to the rate constant of the reaction.

Briefing:

Given, the iodine half-life is 13.3 hours. As a result, half-life t1/2 Equals ln 2/ K

k = 0.693 .... t1/2

≈ 0.693 /13.3 hours

= 5.21 *10-2

The rate law sets the flow timetime is set by the rate law, which varies for each emotion. When only one reactant's quantity influences the speed of chemical reaction, this is referred to as a first-order contact. Because of this, it is occasionally referred to as unimolecular process. The rate is as follows for this type of reaction: k= 1/t ln [A]0 / [A] is the rate constant for the first order reaction. 5.21 * 10-2 hours are in 39.9 hours.

By including all the numbers in the initial order reaction's rate constant equation, we obtain [A].

t = 3.12mg

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Related Questions

How many micromoles of A- and HA are present in the solution?I've got a Phosphate buffer, pH 7.5 and pKa 2.12. The ratio calculated of A-/HA is 0.73. I'm having trouble calculating micromoles in the 0.1M solution. Maybe its just mistyping into the calculator, but I can't seem to get the correct answer! Help would be most appreciated. Or just how to correctly use a calculator.

Answers

[HA] is equal to the 58 X \(10^{3}\) ц mole In the 0.1M solution, micromoles.

According to the question we get

HA ⇄ \(A^{-}\) \(H^{+}\)

HA= 0.1M

\(A^{-}\) = 0

\(H^{+}\) = 0

HA ⇄ \(A^{-}\) \(H^{+}\)

0.1 M  ⇄ 0 0

0.1 - x  ⇄ 0 0   {at equilibrium}

Now given ration of x and 0.1-x = 0.73

Therefore (\(\frac{x}{0.1-x}\)) = 0.73

Now solving for the value of x we will get

x=0.73-0.73x

x=1.73x=0073

x=0.073M

‘The value for the HA is 0.1-0.042 = 0.058 M.

Assuming the solution to be of 1litre.

Moles of x (A") in 1 litre of solution is calculated as follows:

x=0042Mx1L

x= \(\frac{0.042moles}{1L}\) x 1L

x= 42 X \(10^{3}\)

Similarly, for the acid as follows

HA =0058Mx1L

\(\frac{0.058moles}{1L}\) x 1L

[HA] is equal to the 58 X \(10^{3}\) ц mole.

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how do you calculate how many grams of an element are produced using the limiting reactant? (formula?)

Answers

The technique to calculate how many grams of element are produced using limiting reactant is shown.

What is limiting reactant?

The term "limiting reactant" refers to the reactant that is entirely consumed in a chemical reaction and restricts the quantity of product that can be produced.

How to calculate how many grams of elements are produced using limiting reactant?

1. Determine the limiting reactant by comparing the amount of each reactant to the stoichiometric ratio given in the balanced equation.

2. Use the stoichiometric ratio to calculate the number of moles of the element produced from the limiting reactant.

3. Convert the moles of the element to grams using its molar mass.

The formula is:

Grams of element produced = Moles of element produced x Molar mass of element

where Moles of element produced is calculated using the stoichiometric ratio from the balanced equation, and Molar mass of element is the atomic mass of the element in grams per mole.

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Medium fine steel wool has a strand diameter of 0.002 inch. If 100 g of this steel wool were burned, what mass of iron oxide would you expect to be produced?

Answers

To determine the mass of iron oxide produced when 100 g of medium fine steel wool with a strand diameter of 0.002 inch is burned, we need to calculate the percentage of iron in the steel wool, and then use stoichiometry to determine the mass of iron oxide produced.

Assuming that the steel wool is made entirely of iron, the percentage of iron in the steel wool is 100%. We can then calculate the mass of iron in the steel wool by multiplying the total mass by the percentage of iron:

Mass of iron = 100 g x 100% = 100 g

Next, we need to use the balanced chemical equation for the combustion of iron:

4Fe + 3O2 → 2Fe2O3

From the equation, we can see that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron oxide.

The molar mass of iron is 55.845 g/mol, and the molar mass of iron oxide (Fe2O3) is 159.69 g/mol.

Using the mole ratio from the balanced chemical equation, we can calculate the moles of iron oxide produced:

Moles of Fe2O3 = (2/4) x (100 g / 55.845 g/mol) = 0.714 mol

Finally, we can use the molar mass of iron oxide to calculate the mass of iron oxide produced:

Mass of Fe2O3 = 0.714 mol x 159.69 g/mol = 113.97 g

Therefore, when 100 g of medium fine steel wool with a strand diameter of 0.002 inch is burned, we would expect to produce 113.97 g of iron oxide

Victor put a match on a balance and found that its mass was 6.0 grams. Then he lit the match and put it out after a few seconds.



He put the partially burned match on the balance again. This time, its mass was 4.5 grams.

Which of the following best explains what happened as the match burned?
A.
Some of the matter changed from solid to gas and went into the air.
B.
The matter moved to a different part of the match.
C.
Some of the mass was destroyed by the fire.
D.
The mass of the match combined with the mass of the fire.

Answers

Place the cursor at the start of the text, then press CTRL+SHIFT+DOWN ARROW. Press CTRL+SHIFT+UP ARROW after advancing the cursor to the end of the paragraph. The Correct option is B.

How do you move the first sentence to the end of the paragraph in Word?The Ctrl+A keyboard shortcut in Word allows you to select all text in a document, and you can also use the mouse or keyboard to pick out individual words or objects from tables. Text or objects that are located in various locations can also be chosen. You can choose, for instance, a sentence from one page and a paragraph from another.The entire textIn the document, click anywhere.You can pick every word in the document by pressing Ctrl+A on your computer.The particular wording you wantAdditionally, you have the option of choosing a specific word, line of text, or one or more paragraphs.Your cursor should be placed in front of the first letter of the word, sentence, or paragraph you want to pick.To pick a text block, click and hold while dragging the cursor over it.Other options for selecting textQuickly click and drag the mouse over a word to choose it.By positioning your cursor at the beginning of a line of text and pressing Shift + down arrow, you can pick that line of text.Put your cursor at the beginning of the paragraph, then hit the down arrow while holding down the Ctrl and Shift keys to select the paragraph.

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Provide 2 reasons why it is important to add the same amount of alkyl halide to each test tube in the nucleophilic substitution experiment you carried out.

Answers

It is important to add the same amount of alkyl halide to each test tube in the nucleophilic substitution experiment for two main reasons.

Firstly, the amount of reactants used in a chemical reaction can greatly affect the outcome of the reaction. If different amounts of the alkyl halide are added to each test tube, the reaction rates will differ and the products obtained will be inconsistent, making it difficult to draw accurate conclusions from the experiment.

Secondly, by adding the same amount of alkyl halide to each test tube, the experiment can be considered fair and controlled. This means that any differences observed in the reactions can be attributed solely to the changes in the nucleophile used in each reaction. It allows for accurate comparison of the reactions and the identification of trends or patterns in the reactivity of different nucleophiles.

Overall, adding the same amount of alkyl halide to each test tube in the nucleophilic substitution experiment ensures that the results obtained are reliable and can be used to draw meaningful conclusions.

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20) Study
of
reaction
heat
is caused
A. Organic Chemistry
B. Thermodynamic
C.Inorganic Chemistry.
D.Physical Chemistry​

Answers

Answer:

The answer is thermodynamic because in this branch branch we study heat and Temperature and their relationship

Explanation:

I hope this will help you:)

i need a chemistry questions about separating method

Answers

Distillation, crystallisation, adsorption, membrane procedures, absorption and stripping, and oxidation

Here are a few topics you could use

Question:

Different liquids boil and evaporate at different temperatures is the principle of?
Sedimentation

Fraction distillation mainly depends on?
Boiling point

A common example of fractional distillation in industries is the separation of various components of?
Crude oil


There are a few questions I would ask. Tell me if I answered this wrong cause I was a little confused

The relationship between the change in Gibbs free energy and the emf of an electrochemical cell is given by

Answers

The relationship between the change in Gibbs free energy and the emf of an electrochemical cell is given by the equation ΔG = -nFE. The equation shows that the magnitude of ΔG is inversely proportional to the emf of the cell and is dependent on the number of electrons transferred during the reaction and the Faraday constant.

The Gibbs free energy change (ΔG) of a chemical reaction is a measure of the potential energy released or absorbed during the reaction. In an electrochemical cell, the chemical reaction that occurs involves the transfer of electrons from one species to another.

This transfer of electrons is associated with a change in the electrical potential energy of the system, which is measured by the electromotive force (emf) of the cell.
The relationship between ΔG and the emf of an electrochemical cell is given by the following equation:
ΔG = -nFE
Where n is the number of electrons transferred during the reaction, F is the Faraday constant (96,485 C/mol), and E is the emf of the cell. The negative sign in the equation indicates that the change in Gibbs free energy is inversely proportional to the emf of the cell.

This means that as the emf of the cell increases, the magnitude of ΔG decreases.
The equation also shows that the relationship between ΔG and the emf of an electrochemical cell is dependent on the number of electrons transferred during the reaction.

This means that the magnitude of ΔG is proportional to the number of electrons transferred. Additionally, the equation shows that the relationship is dependent on the Faraday constant, which is a constant that relates the number of coulombs of charge to the number of moles of electrons transferred.
In summary, the relationship between the change in Gibbs free energy and the emf of an electrochemical cell is given by the equation ΔG = -nFE.

The equation shows that the magnitude of ΔG is inversely proportional to the emf of the cell and is dependent on the number of electrons transferred during the reaction and the Faraday constant.

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1. If a sample of matter is uniform throughout and cannot be separated into other substances byphysical means, it is _______.A) a compoundB) either a compound or an elementC) a homogeneous mixtureD) a heterogeneous mixtureE) an element2. What volume of 10.0 M H2SO4 is required to prepare 4.0 L of 0.50 M H2SO4?A) 0.20 LB) 0.40 LC) 0.50 LD) 1.0 LE) 4.0 L3. A solution of silver nitrate is mixed with a solution of potassium fluoride. If a precipitate forms,the precipitate is:A) Silver fluorideB) Potassium nitrateC) Potassium fluorateD) Nitric fluorideE) No precipitate is formed

Answers

The answer to the first question is E) an element. The answer to the second question is C) 0.50 L. The answer to the third question is A) Silver fluoride.

A substance is a material that has a fixed composition and set of properties, and can not be separated into simpler components by physical means. It can be a pure chemical element such as iron or a compound made up of two or more elements combined in a fixed ratio, such as water (H2O). Substances can exist as solids, liquids, or gases and can be characterized by their chemical and physical properties, such as density, melting point, and boiling point. A substance is a material that has a fixed composition and set of properties, and can not be separated into simpler components by physical means. It can be a pure chemical element such as iron or a compound made up of two or more elements combined in a fixed ratio, such as water (H2O).

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What mass of iron should be produced if 11. 0g of aluminum react with 30. 0g of iron (III) oxide?

Answers

The mass of iron should be produced if 11. 0g of aluminum reacts with 30. 0g of iron (III) oxide is 10.50 g.

To determine the mass of iron produced, we need to use stoichiometry and the balanced chemical equation for the reaction between aluminum and iron(III) oxide.

The balanced chemical equation is:

2 Al + \(Fe_{2} O_{3}\) →  + 2 Fe

From the equation, we can see that 2 moles of aluminum react with 1 mole of iron(III) oxide to produce 1 mole of iron.

First, we need to determine the limiting reactant by comparing the number of moles of aluminum and iron(III) oxide.

Moles of aluminum = mass of aluminum / molar mass of aluminum

= 11.0 g / 26.98 g/mol (molar mass of aluminum)

= 0.407 mol

Moles of iron(III) oxide = mass of iron(III) oxide / molar mass of iron(III) oxide

= 30.0 g / 159.69 g/mol (molar mass of iron(III) oxide)

= 0.188 mol

Since the stoichiometric ratio of aluminum to iron(III) oxide is 2:1, we can see that 0.188 mol of iron(III) oxide requires 0.376 mol of aluminum. However, we have only 0.407 mol of aluminum, which is in excess.

Therefore, the limiting reactant is iron(III) oxide. The amount of iron produced is determined by the moles of iron(III) oxide used. Moles of iron = 0.188 mol (same as moles of iron(III) oxide)

Now we can calculate the mass of iron produced using its molar mass (55.85 g/mol):

Mass of iron = Moles of iron × Molar mass of iron

= 0.188 mol × 55.85 g/mol

= 10.50 g

Therefore, the mass of iron produced is approximately 10.50 grams.

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A dog barks to alert his owner. What is the medium for the sound waves produced
by the dog barking? lesson 4.01
A. Air
B. ground
C. water
D. the ocean

Answers

Answer:

The Answer is ground or air

a 31.5 g wafer of pure gold initially at 69.9 ∘c is submerged into 63.3 g of water at 26.9 ∘c in an insulated container. the specific heat capacity for gold is 0.128 j/(g⋅∘c) and the specific heat capacity for water is 4.18 j/(g⋅∘c). what is the final temperature of both substances at thermal equilibrium?

Answers

To find the final temperature at thermal equilibrium, we can use the principle of conservation of energy. The heat lost by gold is equal to the heat gained by water. The heat lost by gold can be calculated using the formula: q = m * c * ∆T, where q is the heat lost, m is the mass of gold, c is the specific heat capacity of gold, and ∆T is the change in temperature.

The heat gained by water can be calculated using the same formula, but with the mass and specific heat capacity of water.Setting these two equations equal to each other, we can solve for the final temperature.

Using the given values:
m(gold) = 31.5 g
m(water) = 63.3 g
c(gold) = 0.128 J/(g⋅∘C)
c(water) = 4.18 J/(g⋅∘C)
∆T(gold) = T(final) - 69.9 ∘C
∆T(water) = 26.9 ∘C - T(final)
Solving the equation gives the final temperature of both substances at thermal equilibrium.

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A straight chain hydrocarbon with the formula C^3H^4 _____.

has a triple C-C bond
has a double C-C bond
is essentially inert
has two double C-C bonds

Answers

Answer:

has two double C-C bonds

Explanation:

A saturated compound is a compound having the full complement of hydrogen atoms for every carbon atom while an unsaturated compound does not contain the full complement of hydrogen atoms for every atom of carbon.

If we look at C3H4, the only possible structure of the compound is H2C=C=CH2. We can see from this arrangement that the compound contains a cumulative double bond. This is the specific structure that fits into one of the descriptions in the options, the compound contains two double bonds.

After you plug it into the wall, it can be used to measure the mass of objects

Answers

This isn’t a question..

In the reaction: I2 + ClO3− → IO3− + Cl−, indicate:a. the element that is oxidized: b. the element that is reduced: c. the reducing agent: d. the oxidizing agent: e. Balance the reaction

Answers

1) Which element is oxidized

\(I_2+ClO^-_3\rightarrow IO^-_3+Cl^-\)

Oxidation numbers

I2: 0

ClO3-: for Cl +5 and for O is -2

IO3-: for I is +5 and for O -2

Cl-: -1.

According to the oxidation number

a. Iodine (I) has been oxidized. It changed from 0 to +5.

b. Chlorine has been reduced. It changed from +5 to -1

2) reducing agent and oxidizing agent

c. A reducing agent donates electrons. In the reaction, Iodine is the reducing agent.

d. An oxidizing agent accepts electrons. In the reaction, Chlñorine is the oxidizing agent.

3) Balancing the chemical equation

\(I_2+ClO^-_3\rightarrow IO^-_3+Cl^-\)

Step 1: break the reaction into two half-reactions.

Oxidation half-reaction

\(I_2\rightarrow IO^-_3\)

Reduction half-reaction

\(ClO^-_3\rightarrow Cl^-\)

Step 2: balance all elements EXCEPT for hydrogen and oxygen

Oxidation half-reaction

\(I_2\rightarrow2IO^-_3\)

Reduction half-reaction

\(ClO^-_3\rightarrow Cl^-\)

Step 3: Balance OXYGEN. We do so by adding water molecules to the half-reactions as needed.

Oxidation half-reaction

\(I_2+6H_2O\rightarrow2IO^-_3\)

Reduction half-reaction

\(ClO^-_3\rightarrow Cl^-+3H_2O\)

Step 4: Balance HYDROGEN. We do so by adding protons (H+) to the half-reactions as needed.

Oxidation half-reaction

\(I_2+6H_2O\rightarrow2IO^-_3+12H^+\)

Reduction half-reaction

\(ClO^-_3+6H^+\rightarrow Cl^-+3H_2O\)

Step 5: Balance CHARGES. We do so by adding electrons

Oxidation half-reaction

\(I_2+6H_2O\rightarrow2IO^-_3+12H^++10e^-\)

Reduction half-reaction

\(ClO^-_3+6H^++6e^-\rightarrow Cl^-+3H_2O\)

Step 6: Multiply each half-reaction in such a way we can cancel the electrons.

Oxidation half-reaction

\(3\cdot(I_2+6H_2O\rightarrow2IO^-_3+12H^++10e^-)\)

New oxidation half-reaction

\(3I_2+18H_2O\rightarrow6IO^-_3+36H^++30e^-\)

Reduction half-reaction

\(5\cdot(ClO^-_3+6H^++6e^-\rightarrow Cl^-+3H_2O)\)

New reduction half-reaction

\(5ClO^-_3+30H^++30e^-\rightarrow5Cl^-+15H_2O\)

Step 7: combine the half-reactions. We have 30e in the reactants and 30e in the products. We can cancel them and combine the remaining species.

New oxidation half-reaction

\(3I_2+18H_2O\rightarrow6IO^-_3+36H^++30e^-\)

New reduction half-reaction

\(5ClO^-_3+30H^++30e^-\rightarrow5Cl^-+15H_2O\)

Overall reaction

\(3I_2+18H_2O+5ClO^-_3+30H^+\rightarrow6IO^-_3+36H^++5Cl^-+15H_2O\)

Step 8: Balance the reaction by reducing the number of water molecules and protons.

Overall reaction

\(3I_2+3H_2O+5ClO^-_3^{}\rightarrow6IO^-_3+6H^++5Cl^-\)

e. Balance the reaction

\(3I_2+3H_2O+5ClO^-_3^{}\rightarrow6IO^-_3+6H^++5Cl^-\)

.

Choose the correct formula for each acid.
Carbonic acid
-HC
-H2CO3
-HCO

Answers

The formula for carbonic acid is H2CO3.

Answer:

H₂CO₃

Explanation:

Water + Carbon di oxide

H20+ CO2

= H2CO3

What kind of industrial facilities release Nitrous Oxide?

Answers

Answer:

the agriculture sector is an industrial facility that releases nitrous oxide

Explanation:

Answer: Hello!

Agriculture sector. The agriculture sector dominates emissions of N2O: emissions from agricultural soils in 2019 account for 55% of total UK emissions, and other agricultural sources add another 12%.

Explanation:

Feel Free to ask me anything if questions. Mark me brainest please. Hope I helped! Hope you make an 100%

-Anna♥

A carbonated drink is a
a. mixture of gases and liquids.
b. heterogeneous mixture.
C. mixture of two immiscible liquids.
d. compound.


Help!

Answers

B. Heterogeneous mixture i think

how many moles are in 7.90g of C

Answers

The number of amount of moles contained in 7.90 grams of carbon is 0.66 moles.

How to calculate number of moles?

Mole is the base unit of amount of substance i.e. the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities.

The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:

no of moles = mass ÷ molar mass

According to this question, 7.90g of carbon is given.

molar mass of carbon is 12g/mol

moles = 7.90g ÷ 12g/mol

moles = 0.66 moles

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If a current of 5 amperes is passed through an electrolytic cell containing agno3 for 2.5 hours, how many teaspoons of silver will precipitate?

Answers

To calculate the amount of silver that will precipitate, we need to use Faraday's laws of electrolysis, which relate the substance produced or consumed in a cell to the amount of electric charge passed through it.

What are Faraday's laws of electrolysis?

The first law of electrolysis states that the amount of substance produced or consumed in an electrolytic cell is proportional to the amount of electric charge passed through the cell. The proportionality constant is known as the Faraday constant, which is equal to 96,485 coulombs per mole of electrons.

The second law of electrolysis states that the amount of different substances produced or consumed in an electrolytic cell is proportional to their respective chemical equivalents.

In this problem, the substance being produced is silver, which has a chemical equivalent of 1 (i.e., one mole of electrons produces one mole of silver). The electric charge passed through the cell can be calculated as follows:

electric charge = current x time

electric charge = 5 A x 2.5 hours x 3600 s/hour

electric charge = 45,000 C

The amount of silver that will precipitate can be calculated using the first law of electrolysis and the Faraday constant:

moles of silver = electric charge / Faraday constant

moles of silver = 45,000 C / 96,485 C/mol

moles of silver = 0.467 mol

To convert moles of silver to mass, we need to know the molar mass of silver. The molar mass of silver is 107.87 g/mol. One teaspoon is approximately 5 mL.

mass of silver = moles of silver x molar mass

mass of silver = 0.467 mol x 107.87 g/mol

mass of silver = 50.4 g

number of teaspoons = mass of silver / (density of silver x volume of teaspoon)

Assuming the density of silver is 10.5 g/mL, we get:

number of teaspoons = 50.4 g / (10.5 g/mL x 5 mL)

number of teaspoons = 0.96 teaspoon

Therefore, approximately 0.96 teaspoons of silver will precipitate.

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In order for a reaction to occur, which action must happen?(1 point) Molecules must divide at a high enough energy to break bonds. Molecules must divide at a high enough energy to break bonds. Molecules must collide at a low enough energy to break bonds. Molecules must collide at a low enough energy to break bonds. Molecules must divide at a low enough energy to break bonds. Molecules must divide at a low enough energy to break bonds. Molecules must collide at a high enough energy to break bonds

Answers

Based on effective collision, in order for a reaction to occur, molecules must collide at a high enough energy to break bonds.

What are effective collisions?

Effective collision are collision between reactant particles which result in the formation of product from reactant molecules.

For effective collisions to occur, the reactant molecules must possess a minimum amount of energy known as activation energy which is required  to break the bonds present in the reactant molecules.

Therefore, in order for a reaction to occur, molecules must collide at a high enough energy to break bonds.

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Answer:

1.) Molecules must collide at a high enough energy to break bonds.

2.) the minimum amount of energy required to break bonds and start a chemical reaction

3.) Which change can encourage a reaction? adding heat

4.) More energy is released when forming the bonds of the products because a lot of heat is given off, which indicates energy was released.

5.) Two H–H bonds are broken, one O=O bond is broken, and four H–O bonds are

formed.Explanation:

^^ (be carefull with the last question, the answers look very similar)

A chemist divides a large sample of a mixture into three smaller portions. each of these portions contains different ratios of the component substances that make up the mixture. which description best fits the mixture? a. compound b. element c. heterogeneous mixture d. homogeneous mixture e. pure substance

Answers

A heterogeneous mixture is not uniform in composition. Hence, option C is correct.

What is a heterogeneous mixture?

A heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture.

This substance is not an element or compound, because different components could be observed in the substance.  

A pure substance is made up of only one type of atom (element) or only one type of molecule (compound), mixtures and solutions are made from two or more types of pure substances.

For example, aluminium is an element and ammonia is a compound.

This substance is not a homogeneous mixture, because different samples of the substance appeared to have different proportions of the components.

Hence, this substance is a heterogeneous mixture.

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Answer:

heterogeneous mixture

Explanation:

If [H+] = 1.0 x 10-11 M, what is the pH of the solution?

Answers

Answer:

use the pH equation :

pH: -log [H+]

pH: -log 1×10^-11

pH: 11.00

the pH of the solution is 11.00 and the solution is basic.

and make sure to remember :pH does not have a value .

a solution merely has pH(11.00)

Two or more atoms that have been chemically combined are
called a

Answers

Answer:

compound

Explanation:

How many formula units are present in 24. 65 g CaCl2

Answers

There are 8.59 × 10^22 formula units in 24.65 g CaCl2.

The formula unit for CaCl2 is CaCl2, which indicates that there are one Ca and two Cl atoms bonded together. The number of formula units in 24.65 g of CaCl2 can be calculated using the mole-mass relationship. Since the molecular weight of CaCl2 is 111 g/mol, the number of moles of CaCl2 in 24.65 g is given by: 0.143 mol CaCl2

The number of formula units of CaCl2 can be calculated using Avogadro's number (6.022 × 10^23 formula units/mol).

6.022 × 10^23 formula units/mol = 1 molCaCl2 X formula units /mol × 0.143 mol CaCl2 = 0.859 × 10^23 formula units. Therefore, there are 8.59 × 10^22 formula units in 24.65 g CaCl2.

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Why does paper "brown" after a while?

Answers

Answer:

Exposure to oxygen (especially when combined with sunlight) alters the molecular structure of lignin, causing a change in how the compound absorbs and reflects light, resulting in the substance containing oxidized lignin turning a yellow-brown color in the human visual spectrum.

How much energy is required to vaporize 18.32 grams of water at its boiling point?​

Answers


That is, water has a high heat of vaporization, the amount of energy needed to change one gram of a liquid substance to a gas at constant temperature. Water's heat of vaporization is around 540 cal/g at 100 °C, water's boiling point.

The diagram below shows two identical and isolated charges, X and Y, of −6μC each, initially at rest in a vacuum. The initial separation of the two charges is 3.0 mm. The two charges subsequently move apart in the directions shown. (a) Calculate the initial electric force acting on each charge due to the other charge. (b) Discuss the motion of one of the two charges after it begins to move.

Answers

The initial electric force acting on each charge due to the other charge is F = (1/4πε) * (q1q2 / r²)= (1/4π(8.85 × 10⁻¹² C² N⁻¹ m⁻²)) * (-6 × 10⁻⁶ C)² / (0.003 m)²= -5.94 × 10⁻² N = -0.0594 N .  The path of the charge is a hyperbola.

Given that two identical and isolated charges, X and Y, of −6μC each, initially at rest in a vacuum.

The initial separation of the two charges is 3.0 mm and they subsequently move apart in the directions shown. To find (a) the initial electric force acting on each charge due to the other charge, and (b) to discuss the motion of one of the two charges after it begins to move.

(a) The initial electric force acting on each charge due to the other charge is given by Coulomb's law, that is F = (1/4πε) * (q1q2 / r²),

where q1 and q2 are the charges,

r is the separation distance and

ε is the permittivity of free space.

Here q1 = q2 = -6μC, r = 3 mm = 0.003 m and ε = 8.85 × 10⁻¹² C² N⁻¹ m⁻²So, the initial electric force acting on each charge due to the other charge is

F = (1/4πε) * (q1q2 / r²)= (1/4π(8.85 × 10⁻¹² C² N⁻¹ m⁻²)) * (-6 × 10⁻⁶ C)² / (0.003 m)²= -5.94 × 10⁻² N = -0.0594 N (repulsive force

)(b) When one of the charges begins to move, its kinetic energy increases and it experiences a decrease in potential energy. Thus, its total energy remains constant. Hence, the charge moves away from the other charge with a constant speed. The direction of the velocity vector is along the straight line that joins the charges, and the acceleration vector is perpendicular to it. The path of the charge is a hyperbola.

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CHEMISTRY PLS HELP!!!!!!

CHEMISTRY PLS HELP!!!!!!

Answers

Answer: .04544 or 4.544 x 10^-2

Explanation: Simply divide 923.0 by 20312. Use 4 significant figures because it is the least amount of significant figures present in your calculation.

The answer for the given equation in significant figures is 0.045.

What is significant figure?

The number of digits in a value, often a standard measure, that make a contribution to the precision of the value is referred to as significant figures. The first non-zero digit is used to begin counting significant figures.

All zeros to the right and left of a decimal point are never significant. For example, the number 0.00798 had three significant digits.

In the given equation, let us assume the number is X.

X = 923.0/20312

X = 0.0454.

Thus, the answer is 0.045.

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Can somebody plz help answer these true or false questions correctly (only the ones you know that are right)
Thanks :3

WILL MARK BRAINLIEST WHOEVER ANSWERS FIRST..promise! :DDDD

Can somebody plz help answer these true or false questions correctly (only the ones you know that are

Answers

Explanation:

1.False

2.False

3.True

4.True

5.False

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