The inaugural attendance at an annual music
Festival is 60,000 people. Find the attendance
at the festival in the fifth Year


Give detailed steps please

The police dog spends 1/6 of its workday at the police station.

To find the fraction of the police dog's workday spent at the police station, we need to add up the fractions of time spent in each location and subtract them from 1, since the dog spends the rest of the day at the police station.

Fraction of time spent in police car =  \(1/3\)

Fraction of time spent in public = \(1/2\)

To add these fractions, we need to find a common denominator:

\(1/3 = 2/6\\1/2 = 3/6\)

So, the fraction of the dog's day spent at the police station is:

\(1 - (2/6 + 3/6) = 1 - 5/6\)

                        = \(1/6\)

Therefore, the police dog spends 1/6 of its workday at the police station.

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The developer can build a maximum of 275 residential lots on the land, given the zoning regulations and the reservation of 25% of the land for streets and green space.

First, we need to find out how much land the developer has reserved for streets and green space:

25% of 80 acres = 0.25 x 80 = 20 acres

Now, we need to subtract this from the total area to get the area available for residential lots:

80 acres - 20 acres = 60 acres

Next, we need to convert the area into square feet:

60 acres x 43,560 square feet/acre = 2,613,600 square feet

Finally, we can divide the available area by the minimum required area per lot to find the maximum number of permissible lots:

2,613,600 square feet ÷ 9,500 square feet/lot ≈ 275 lots

Therefore, the developer can build a maximum of 275 residential lots on the land, given the zoning regulations and the reservation of 25% of the land for streets and green space.

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The shape of the histogram is expected to be symmetric.

A histogram is a graphical representation of the distribution of a dataset. It is an estimate of the probability distribution of a continuous variable. The histogram is plotted with bin ranges on the x-axis and the frequency (count) of data points that fall within each bin on the y-axis.

The shape of the histogram can give you a sense of the underlying distribution of the data, such as whether it is symmetric or skewed.

Standardized test scores, like the SAT, are typically designed to have a normal distribution, meaning that the majority of scores fall in the middle range, with fewer scores at the extremely high or low ends.

Additionally, because the data is being collected from a large and diverse population of students from one state, it is unlikely that there would be a significant skew in one direction or another.

However, some factors such as socioeconomic status, family background, school district, and student ethnicity may affect the distribution.

Therefore, The shape of the histogram is expected to be symmetric.

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Therefore, the probability that in any given minute there will be 2 or fewer arrivals is approximately 0.4231 or 42.31%.

To find the probability of 2 or fewer arrivals in a given minute, we can use the Poisson distribution formula.

The formula for the Poisson distribution is:

P(X = k) = (e*(-λ) * λ\(^k\)) / k!

Where:

P(X = k) is the probability of k arrivals,

e is the base of the natural logarithm (approximately 2.71828),

λ is the average rate of arrivals,

k is the number of arrivals.

In this case, the average rate of arrivals is given as 3 per minute.

Let's calculate the probabilities for k = 0, 1, and 2.

For k = 0:

P(X = 0) = (e⁻³ * 3⁰) / 0! = e⁻³ ≈ 0.0498

For k = 1:

P(X = 1) = (e⁻³ * 3¹) / 1! = 3e⁻³ ≈ 0.1493

For k = 2:

P(X = 2) = (e⁻³ * 3²) / 2! = 9e⁻³ / 2 ≈ 0.224

To find the probability of 2 or fewer arrivals, we sum up the probabilities for k = 0, 1, and 2:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= 0.0498 + 0.1493 + 0.224

≈ 0.4231

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There are approximately 0.976 grams of carbon (C) in the given sample of the carbohydrate (C9H11O6).

To find the number of grams of carbon (C) in the sample, we need to first determine the molar mass of the carbohydrate.

The molar mass of C is approximately 12.01 g/mol. The molar mass of H is approximately 1.01 g/mol, and the molar mass of O is approximately 16.00 g/mol.

The molar mass of the carbohydrate (C9H11O6) can be calculated as follows:

(9 * 12.01 g/mol) + (11 * 1.01 g/mol) + (6 * 16.00 g/mol) = 162.18 g/mol

Next, we can use the Avogadro's number (6.022 x 10^23) to determine the number of moles in the sample:

4.9 x 10^22 molecules / 6.022 x 10^23 molecules/mol = 0.0813 mol

Finally, we can calculate the mass of carbon in the sample by multiplying the number of moles by the molar mass of carbon:

0.0813 mol * 12.01 g/mol ≈ 0.976 g

So, there are approximately 0.976 grams of carbon in this sample.
There are approximately 0.976 grams of carbon (C) in the given sample of the carbohydrate (C9H11O6).

To find the mass of carbon in the sample, we first need to determine the molar mass of the carbohydrate. The molar mass of an element or compound is the mass of one mole of that substance. In this case, we have the formula C9H11O6, which indicates that the carbohydrate consists of 9 carbon atoms (C), 11 hydrogen atoms (H), and 6 oxygen atoms (O).

The molar mass of carbon is approximately 12.01 g/mol, hydrogen is approximately 1.01 g/mol, and oxygen is approximately 16.00 g/mol. To calculate the molar mass of the carbohydrate, we multiply the number of atoms of each element by their respective molar masses and sum them up.

Therefore, the molar mass of C9H11O6 is

(9 * 12.01 g/mol) + (11 * 1.01 g/mol) + (6 * 16.00 g/mol) = 162.18 g/mol.

Next, we can use the Avogadro's number (6.022 x 10²³) to determine the number of moles in the given sample. The given sample contains 4.9 x 10²²molecules of the carbohydrate. Dividing this by Avogadro's number gives us the number of moles:

4.9 x 10 molecules / 6.022 x 10^23 molecules/mol = 0.0813 mol.

Finally, we can calculate the mass of carbon in the sample by multiplying the number of moles by the molar mass of carbon: 0.0813 mol * 12.01 g/mol ≈ 0.976 g. Therefore, there are approximately 0.976 grams of carbon in the given sample.

In conclusion, the sample of the carbohydrate (C9H11O6) contains approximately 0.976 grams of carbon (C).

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Answer:

Well, 6.94 - 4.99 = 1.95 also that divided by 0.65 = 3 So it is 3  pounds of bananas

Step-by-step explanation:

P.S can I have brainliest?

Answer:

1. Reflection

2. Dilation

3. Rotation

Step-by-step explanation:

Hey!

You can tell number one is a reflection because it didn’t change side or turn upside down or anything, it just flipped over to the other side.

You can tell number two is a dilation because it changes size.

You can tell number three is rotation because it rotated.

Hope this helps! :D

If you have any further questions, comment down below!

Using the normal distribution, it is found that 56.78% of the penguins from the population have a weight between 13.0 kg and 16.5 kg.

The z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:

\(Z = \frac{X - \mu}{\sigma}\)

In this problem, the mean and the standard deviation are given, respectively, by \(\mu = 15.1, \sigma = 2.2\).

The proportion of penguins from the population have a weight between 13.0 kg and 16.5 kg is the p-value of Z when X = 16.5 subtracted by the p-value of Z when X = 13.

X = 16.5:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{16.5 - 15.1}{2.2}\)

Z = 0.64

Z = 0.64 has a p-value of 0.7389.

X = 13:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{13 - 15.1}{2.2}\)

Z = -0.95

Z = -0.95 has a p-value of 0.1711.

0.7389 - 0.1711 = 0.5678.

0.5678 = 56.78% of the penguins from the population have a weight between 13.0 kg and 16.5 kg.

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Answer:

y-intercept is -9

Step-by-step explanation:

g(0) = -3(0)² - 5(0) - 9

g(0) = 0 - 9

g(0) = -9

The radical form of the number √ ( - 27 ) is given by the equation A = 3i√3

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the number be represented as n

The value of n = √( -27 )

Now , the value -1 can be represented as the complex number i

where i² = 1

So , the number n can be written as

A = √ ( 3i )² 3

A = √9i² (3)

A = √27i²

A = √-27

On simplifying the equation , we get

A = 3i√3

Therefore , the value of A is A = 3i√3

Hence , the equation is A = 3i√3

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The pie chart accurately represents the data from the poll, as it accurately shows the proportion of people who agreed with each candidate's positions.

The pie chart presents a good representation of the data from the poll taken asking people if they agreed with the positions of the 4 candidates for a county office. This is because the pie chart accurately shows the proportion of people who agreed with each candidate's positions. For example, the chart indicates that 26% of the people agreed with Candidate A's positions, 28% agreed with Candidate B's positions, 29% agreed with Candidate C's positions, and 17% agreed with Candidate D's positions. In order to calculate the proportions, the total number of people who responded to the poll was divided by each individual candidate's number of supporters. For example, for Candidate A, the proportion of people who agreed with their positions was calculated by dividing the total number of people responding to the poll (100) by the number of people who agreed with Candidate A's positions (26), resulting in a proportion of 0.26 or 26%. This same approach was used to calculate the proportions of each candidate's supporters. Therefore, the pie chart accurately presents the data from the poll and is a good representation of the data.

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The solution set is,

\(\theta = \left \{ {{0^0+360^0n, 120^0+ 360^0n} \atop {240^0+ 360^0}} \right.\)

option A is the correct answer.

From the question, we have

2cos⁡(θ)=2cos⁡(2θ)

cos⁡(2θ)-cos⁡(θ)=0

2cos^2⁡(θ)-cos⁡(θ)-1=0

cos⁡(θ)=(1±√(1+8))/(2×2)

cos⁡(θ)=1, cos⁡(θ)=-1/2

      \(\theta = \left \{ {{0^0+360^0n, 120^0+ 360^0n} \atop {240^0+ 360^0}} \right.\)

The solution is,

\(\theta = \left \{ {{0^0+360^0n, 120^0+ 360^0n} \atop {240^0+ 360^0}} \right.\)

Multiplication:

Mathematicians use multiplication to calculate the product of two or more numbers. It is a fundamental operation in mathematics that is frequently utilized in everyday life. When we need to combine groups of similar sizes, we utilize multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are multiplied are referred to as the factors. Repeated addition of the same number is made easier by multiplying the numbers.

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Answer:

x = 5 ft

y = 5 ft

h = 2.5 ft

Step-by-step explanation:

The surface area of the base of the box will be at its maximum when the difference between the length and width at its minimum.

Therefore, let y = x.

Therefore, the equation for the surface area of box is:

\(\implies A=xy+2xh+2yh\)

Substituting y = x:

\(\implies A=x^2+2xh+2xh\)

\(\implies A=x^2+4xh\)

Given the surface area of the box is 75 square feet:

\(\implies 75=x^2+4xh\)

Rearrange the equation to create an expression for h in terms of x:

\(\implies h=\dfrac{75-x^2}{4x}\)

The equation for the volume of the box is:

\(\implies V=xyh\)

Substitute y = x and the expression for h to create an equation for volume in terms of x:

\(\implies V= \dfrac{x^2(75-x^2)}{4x}\)

\(\implies V= \dfrac{x(75-x^2)}{4}\)

\(\implies V= \dfrac{75}{4}x-\dfrac{1}{4}x^3\)

To find the value of x that maximizes the volume, differentiate V with respect to x and find the value(s) of x that makes dV/dx = 0.

\(\implies \dfrac{\text{d}V}{\text{d}x}=\dfrac{75}{4}-\dfrac{3}{4}x^2\)

Set it to zero and solve for x:

\(\implies \dfrac{75}{4}-\dfrac{3}{4}x^2=0\)

\(\implies \dfrac{3}{4}x^2=\dfrac{75}{4}\)

\(\implies 3x^2=75\)

\(\implies x^2=25\)

\(\implies x=5\)

Check to see if this value of x gives a minimum for V by inputting it into the second derivative:

\(\implies \dfrac{\text{d}^2V}{\text{d}x^2}=-\dfrac{3}{2}x\)

\(x=5\implies \dfrac{\text{d}^2V}{\text{d}x^2}=-\dfrac{3}{2}(5)=-\dfrac{15}{2} < 0 \implies \sf maximum\)

Finally, substitute the found value of x into the expression for h to find the height of the box:

\(x=5 \implies h=\dfrac{75-(5)^2}{4(5)}=\dfrac{5}{2}=2.5\)

Therefore, the dimensions that will produce a pen with maximum volume are:

The Cartesian equation of the line that contains the points A and B, where A is the intersection point of the given plane with the x-axis and B is the intersection point with the z-axis, is x = 1 and z = 3.

To find the Cartesian equation of the line, we need to determine the values of x and z while allowing y to vary freely. Since point A lies on the x-axis, its y-coordinate is 0, so we have x = 1 and y = 0 for point A. Similarly, since point B lies on the z-axis, its y-coordinate is also 0, so we have z = 3 and y = 0 for point B.

Thus, the equation x = 1 represents the line that contains point A, and the equation z = 3 represents the line that contains point B. Since y can vary freely, we do not include it in the equations. Therefore, the Cartesian equation of the line that contains points A and B is x = 1 and z = 3.

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The area bounded by the graphs of y = x^2 + 2 and y = 6x - 6 over the interval -1 ≤ x ≤ 2 is 25 square units. To find the area bounded we need to calculate the definite integral of the difference of the two functions within that interval.

The area can be computed using the following integral:

A = ∫[-1, 2] [(x^2 + 2) - (6x - 6)] dx

Expanding the expression:

A = ∫[-1, 2] (x^2 + 2 - 6x + 6) dx

Simplifying:

A = ∫[-1, 2] (x^2 - 6x + 8) dx

Integrating each term separately:

A = [x^3/3 - 3x^2 + 8x] evaluated from x = -1 to x = 2

Evaluating the integral:

A = [(2^3/3 - 3(2)^2 + 8(2)) - ((-1)^3/3 - 3(-1)^2 + 8(-1))]

A = [(8/3 - 12 + 16) - (-1/3 - 3 + (-8))]

A = [(8/3 - 12 + 16) - (-1/3 - 3 - 8)]

A = [12.667 - (-12.333)]

A = 12.667 + 12.333

A = 25

Therefore, the area bounded by the graphs of y = x^2 + 2 and y = 6x - 6 over the interval -1 ≤ x ≤ 2 is 25 square units.

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The absolute minimum value of the function 4 - 6x^2 on the interval is -596.

To find the absolute minimum value of the function f(x) = 4 - 6x^2 on a given interval, we need to consider the critical points and the endpoints of the interval.

Since the function is a quadratic, it is a continuous function and its minimum value will occur either at the critical points or at the endpoints.

To find the critical points, we take the derivative of the function:

f'(x) = -12x

Setting f'(x) = 0, we find the critical point:

-12x = 0

x = 0

Now we evaluate the function at the critical point and at the endpoints of the interval:

f(0) = 4 - 6(0)^2 = 4

f(10) = 4 - 6(10)^2 = 4 - 600 = -596

Comparing the values, we see that the absolute minimum value is -596.

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Answer:

??? what do you mean?

Step-by-step explanation:

The sketch of the crane and box is done below

The crane is moving at a constant speed. This represents a horizontal motion for the box. On a graph, this would be a straight horizontal line.

The box is being lifted with a constant acceleration, meaning its vertical speed is increasing over time. On a graph, this would be a line curving upwards.

Since the box is moving both horizontally and vertically, the path will combine these two components. Because the horizontal movement is constant and the vertical movement is accelerating, the line on the graph will be diagonal and getting steeper as it moves to the right.

x = 0.5 t

y = 1 / 2 at²

t = x / 0.5

1 / 2 * (x / 0.5)²

y = 2x²

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p(A or B) = P(A) + P(B) - p(A and B)

The missing probability is P(B)

Sets are an organized collection of objects. Usually, sets are represented in curly braces {}, for example, A = {1,2,3,4} is a set.

In set theory, the operations of the sets are carried when two or more sets combine to form a single set under some of the given conditions. The basic operations on sets are:

p(A or B) = P(A) + P(B) - p(A and B) is a formula used in finding the probability of an event in a set sample.

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Using Algebraic expression solution ,

The cost of three hats is $18 .

We have given that,

A hat company charge for design fee $4 per hat .

i.e design fee of one hat = $4

total cost of 5 hats = $30

let the cost of one hat without design fee be $x and total cost of one hat is $(x+4) .

using the above statement, we get an algebraic expression,

5( x+ 4)= 30

we solve the above algebra expression,

=> 5x + 20 = 30

=> 5x = 10

=> x = 2

so, cost of a hat without design fee is $2

and total cost of one hat is $6.

we have to calculate cost of 3 hats .

cost of one hat in hat company= $ 6

cost of three hats in hat company= $(6×3)

= $18

Hence, the total cost of 3 hats is $18.

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According to the question The equilibrium constant \((K_{eq})\) relates the concentrations of reactants and products \(K_{eq} \ for\ 2AB \rightleftharpoons 2A + 2B \ is\ 49.\)This indicates that the equilibrium position favors formation of products.

The equilibrium constant \((K_{eq})\) relates the concentrations of reactants and products in a chemical reaction at equilibrium. In the given reaction,

\(A + B \rightleftharpoons AB, the\ K_{eq}\ is\ 7\).

When considering the reaction \(2AB \rightleftharpoons 2A + 2B\), the stoichiometric coefficients are doubled on both sides. According to the principles of equilibrium, the equilibrium constant for the modified reaction can be obtained by squaring the original \(K_{eq}\).

Therefore, the \(K_{eq}\) for \(2AB \rightleftharpoons 2A + 2B is (K_{eq})^2 = (7)^2 = 49\). This indicates that the equilibrium position favors the formation of products in the double reaction compared to the original reaction.

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Answer:

Step-by-step explanation:

19?

Answer:

5 km

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Your answer is 1 because hundredths position is the second number after the decimal other answers include.

Ten=3

Ones place=8

Tenths place=7

Thousandths place=6

Hundred thousandths=5

Hope it helps have a great day:)

Answer:

Step-by-step explanation:

Relations are only functions if they do not share any x values at all! The 2 graphs there that do not have any of the same x values are graphs A and D. Notice that on graph B, there are several y values that share the x value of 2; on graph C, there are several y values that share the x value of 2.

Answer:

A and D only

Step-by-step explanation:

A function is a relation where each input has its own output ( each x values has its own corresponding y value ) If an input has more than one output than the relation is not a function.

We can tell if a graph shows a function or not by using the vertical line test. If you draw vertical lines on the graph and more than one point is on the vertical line drawn then the graph does not show a function.

For graph B if you draw a vertical line at x = -2 more than 1 point will be on the line meaning that the graph does not show a function.

For Graph C if you draw a vertical line at x = 2 more than 1 point will be on the line meaning that Graph C also does not show a function.

For Graphs A and D you can draw a vertical line anywhere on the graph and no more than 1 point will be on the line therefore Graphs A and D show functions.

Answer:

2 1/9

Step-by-step explanation:

Answer:

2.1×10=21

Step-by-step explanation:

.°.2,1/10

=2.1

Answer:

Unit 9 Answer Key.pdf

Step-by-step explanation:

Search that up and you'll see all the answers

Please give me Brainliest and like and rate please hope this helps BYE!

Answer:

hope this helps...

answer in the diagram

9514 1404 393

Answer:

  Jaime: yes: 29·31 = 900 -1 = 899

  Raquel: 24·26 = 25^2 -1 = 624

Step-by-step explanation:

The difference of squares factors as the product of the sum and difference of the roots:

  a^2 -b^2 = (a -b)(a +b)

Jaime

  29·31 = (30 -1)(30 +1) = 30^2 -1^2 = 900 -1 = 899

  Jaime can subtract 1 from 30^2 to find 29·31

__

Raquel

  24·26 = (25 -1)(25 +1) = 25^2 -1^2 = 625 -1 = 624

  Raquel can subtract 1^2 from 25^2 to find 24·26.

The Probability that the third student will draw a red or blue marble is 20/44, which simplifies to 5/11 or approximately 0.45.

To find the probability that the third student will draw a red or a blue marble, we need to first calculate the total number of marbles remaining in the bag after the first two students draw theirs.

The first student draws a yellow marble, leaving 9 yellow, 10 red, 10 blue, 8 green, and 8 purple marbles in the bag.

The second student draws a purple marble, leaving 9 yellow, 10 red, 10 blue, 8 green, and 7 purple marbles in the bag.

Therefore, the total number of marbles remaining in the bag is 44.

Of those 44 marbles, there are 10 red and 10 blue marbles, for a total of 20 marbles that the third student could potentially draw.

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