the __________ is a value used to indicate the ability of a material to resist heat flow.

Answer:

Explanation:

Wow

Answer:

Increase in stroke volume brings about increase in pump rate .the relationship between them is linearly proportional.

Explanation:

Increase in stroke volume brings about increase in pump rate .the relationship between them is linearly proportional.

The rate at which blood is been pumped by the heart depends on the Stroke volume as well as heart rate. The stroke volume gives the quantity of blood that is been pumped by the heart Everytime it beats.

One of the important factor that determine the Cardiac output is Stroke volume. And injection fraction is calculated as (stroke volume/

end-diastolic volume)

Answer:

----------

Explanation:

Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!

Answer:

Betbtybrbytntrnyrnrynunjhjhnthnnhtnnthnhtnnhnhrnntnthhnhnhtnthn

Explanation:

Answer:

a)  316 stainless steel

b)  316 stainless steel

c)  Carbon steel

d)  stainless steel 316

e)  stainless steel 316

f )   Carbon steel

Explanation:

A) A 10,000 M' storage tank for Toluene

The best material for building this tank is 316 stainless steel this is because it is relatively cheaper than other materials such as Hest Alloy C while still maintaining  the required tensile strength needed to build the storage tank for Toluene

B) A 5.0 m' tank for storing a 30% w/w aqueous solution of sodium chloride

The suitable material for building this tank is 316 stainless steel as it is cheaper than Titanium and Hest Alloy C and it is compatible with sodium chloride

C) A 2 m diameter, 20 m high distillation column, distilling acrylonitrile

The best material for constructing this column is  Carbon steel and this is because  it has a very high compressive strength which is approximately . 1320 MPa

D)  A 100 m storage tank for strong nitric acid.

The best material is stainless steel 316 and this is due to its high tensile strength

E) 316 stainless steel

F) Carbon steel is suitable for building this absorption column because  it has a very high compressive strength which is approximately . 1320 MPa

Fiber optic cabling is preferred over copper cabling for interconnecting buildings due to several reasons. One of the most significant advantages of fiber optic cabling over copper cabling is the high bandwidth. Fiber optic cables can transmit more data over longer distances than copper cables.

This feature makes fiber optic cabling ideal for high-speed data transfers over a long distance and in data centers. Fiber optic cabling also has a higher capacity than copper cabling, which makes it a better option for use in high-density installations.The next benefit of fiber optic cabling over copper cabling is security. The data transmitted via fiber optic cables is more secure than data sent through copper cables. Copper cables are vulnerable to interception and electromagnetic interference (EMI). On the other hand, fiber optic cabling is immune to electromagnetic interference (EMI) and radio-frequency interference (RFI). This characteristic makes fiber optic cabling an excellent option for military, financial, and government applications where security is of utmost importance.Another benefit of fiber optic cabling is the reliability of data transmissions. Copper cables are prone to interference, which can result in data corruption and packet loss. In contrast, fiber optic cables are immune to electromagnetic interference and are resistant to environmental factors such as temperature changes and moisture. This feature makes fiber optic cabling ideal for outdoor installations where copper cables would fail.Finally, fiber optic cabling is lightweight, compact, and less susceptible to damage than copper cabling. Copper cables are bulkier and less flexible than fiber optic cables, which makes them more challenging to install. In contrast, fiber optic cables are more flexible and can be bent without affecting their performance. This feature makes fiber optic cabling ideal for use in tight spaces and challenging installations.

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Answer:

None of the above cause thats what i put

Answer:

Condensation

Explanation:

Consequently, the correct answer is B. Involuntary lien.

A mechanic's lien would be properly classified as a(n) involuntary lien.

What is a mechanic's lien?

A mechanic's lien is a type of legal claim granted to builders, contractors, and other professionals who provide labor or supplies for the construction or improvement of buildings and structures on behalf of the property owner.

The mechanic's lien is the professional's right to sue the owner of the building or land for non-payment if they have delivered materials or services to the property but have not been paid.

In the context of real estate law, a mechanic's lien is an involuntary lien, which means that the lien is imposed on the owner's property by operation of law and without the owner's consent. This sort of lien is known as a general lien.Involuntary liens are imposed on a property by law or without the property owner's consent, such as taxes, judgments, or mechanic's liens. In contrast to voluntary liens, which are agreements made between the owner and the creditor, involuntary liens are imposed by law without the owner's consent

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Answer:

See explanation below

Explanation:

Hypo-eutectoid steel has less than 0,8% of C in its composition.

It is composed by pearlite and α-ferrite, whereas Hyper-eutectoid steel has between 0.8% and 2% of C, composed by pearlite and cementite.

Ferrite has a higher tensile strength than cementite but cementite is harder.

Considering that hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains whereas hypereutectoid steel contains a higher amount of cementite, the following properties are obtainable:

Hypo-eutectoid steel has higher yield strength than Hyper-eutectoid steel

Hypo-eutectoid steel is more ductile than Hyper-eutectoid steel

Hyper-eutectoid steel is harder than Hyper-eutectoid steel

Hypo-eutectoid steel has more tensile strength than Hyper-eutectoid steel.

When making a knife or axe blade, I would choose Hyper-eutectoid steel alloy because

1. It is harder

2. It has low cost

3. It is lighter

When making a die to press powders or stamp a softer metals, I will choose hypo-eutectoid steel alloy because

1. It is ductile

2. It has high tensile strength

3. It is durable

Answer:

(a)

Steels having carbon within 0.02% – 0.8% which consist of ferrite and pearlite are known as hypoeutectoid steel.

Steels having greater than 0.8% carbon but less than 2.0% are known as hypereutectoid steel.

(b)

The proeutectoid ferrite formed at a range of temperatures from austenite in the austenite+ferrite region above 726°C. The eutectoid ferrite formed during the eutectoid transformation as it cools below 726°C. It is a part of the pearlite microconstiutents . Note that both hypereutectoid and hypoeutectoid steels have proeutectoid phases, while in eutectoid steel, no proeutectoid phase is present.

Proeutectoid signifies is a phase that forms (on cooling) before the eutectoid austenite decomposes. It has a parallel with primary solids in that it is the first phase to crystallize out of the austenite phase. If the steel is hypoeutectoid it will produce proeutectoid ferrite and if it is hypereutectoid it will produce proeutectoid cementite.  The carbon concentration for both ferrites is 0.022 wt% C.

(c)

(i) Yield strength: The hypoeutectoid steel have good yield strength and hypereutectoid steels have little higher yield strengh.

(ii) Ductility: The hypoeutectoid steel is more ductile and the ductility has decreased by a factor of three for the eutectoid alloy. In hypereutectoid alloys the additional, brittle cementite on the pearlite grain boundaries further decreases the ductility of the alloy. The proeutectoid cementite restricts plastic deformation to the ferrite lamellae in the pearlite.

(iii) Hardness:  hypoeutectoid steels are softer and hypereutectoid steel contains low strength cementite at grain boundary region which makes it harder than hypoeutectoids.

(iv) Tensile strength: Grain boundary regions of hypereutectoid steel are high energy regions prone to cracking because of cementite in the grain boundaries, its tensile strength decreases drastically even though pearlite is present. Hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains, so grain boundaries being the high energy state region, it has a higher tensile strength.

(d)

I would recommend hypereutectoid steel alloy to make a knife or ax blade

1- Hardness is required at the surface of the blades.

2- Ductility is not needed for such application.

3- Due to constant impact, the material will not easily yield to stress.

(e)

I would choose a hypoeutectoid steel alloy to make a steel that was easy to machine.

1- hypoeutectoid steel alloys have high machinability, hence better productivity

2- It will be used on softer metals, hence its fitness for the application

3- Certain amount of ductility is required which hypoeutectoid steel alloys possess.

Explanation:

See all together above

Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

Answer:

there are generally two types of toilet bowl types- round and elongated.

Answer:

When are resistors in series? Resistors are in series whenever the flow of charge, called the current, must flow through devices sequentially. For example, if current flows through a person holding a screwdriver and into the Earth, then  

R

1

 in Figure 1(a) could be the resistance of the screwdriver’s shaft,  

R

2

 the resistance of its handle,  

R

3

 the person’s body resistance, and  

R

4

 the resistance of her shoes.

Figure 2 shows resistors in series connected to a voltage source. It seems reasonable that the total resistance is the sum of the individual resistances, considering that the current has to pass through each resistor in sequence. (This fact would be an advantage to a person wishing to avoid an electrical shock, who could reduce the current by wearing high-resistance rubber-soled shoes. It could be a disadvantage if one of the resistances were a faulty high-resistance cord to an appliance that would reduce the operating current.)

Two electrical circuits are compared. The first one has three resistors, R sub one, R sub two, and R sub three, connected in series with a voltage source V to form a closed circuit. The first circuit is equivalent to the second circuit, which has a single resistor R sub s connected to a voltage source V. Both circuits carry a current I, which starts from the positive end of the voltage source and moves in a clockwise direction around the circuit.

Figure 2. Three resistors connected in series to a battery (left) and the equivalent single or series resistance (right).

To verify that resistances in series do indeed add, let us consider the loss of electrical power, called a voltage drop, in each resistor in Figure 2.

According to Ohm’s law, the voltage drop,  

V

, across a resistor when a current flows through it is calculated using the equation  

V

=

I

R

, where  

I

 equals the current in amps (A) and  

R

 is the resistance in ohms  

(

Ω

)

. Another way to think of this is that  

V

 is the voltage necessary to make a current  

I

 flow through a resistance  

R

.

So the voltage drop across  

R

1

 is  

V

1

=

I

R

1

, that across  

R

2

 is  

V

2

=

I

R

2

, and that across  

R

3

 is  

V

3

=

I

R

3

. The sum of these voltages equals the voltage output of the source; that is,

V

=

V

1

+

V

2

+

V

3

.

This equation is based on the conservation of energy and conservation of charge. Electrical potential energy can be described by the equation  

P

E

=

q

V

, where  

q

 is the electric charge and  

V

 is the voltage. Thus the energy supplied by the source is  

q

V

, while that dissipated by the resistors is

q

V

1

+

q

V

2

+

q

V

3

.

Explanation:

Answer:

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Explanation:

From Heat Transfer we determine that heat transfer rate due to electromagnetic radiation (\(\dot Q\)), measured in BTU per hour, is represented by this formula:

\(\dot Q = \epsilon\cdot A\cdot \sigma \cdot (T_{s}^{4}-T_{b}^{4})\) (1)

Where:

\(\epsilon\) - Emissivity, dimensionless.

\(A\) - Surface area of the student, measured in square feet.

\(\sigma\) - Stefan-Boltzmann constant, measured in BTU per hour-square feet-quartic Rankine.

\(T_{s}\) - Temperature of the student, measured in Rankine.

\(T_{b}\) - Temperature of the bus, measured in Rankine.

If we know that \(\epsilon = 0.90\), \(A = 16.188\,ft^{2}\), \(\sigma = 1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}}\), \(T_{s} = 554.07\,R\) and \(T_{b} = 527.67\,R\), then the heat transfer rate due to electromagnetic radiation is:

\(\dot Q = (0.90)\cdot (16.188\,ft^{2})\cdot \left(1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}} \right)\cdot [(554.07\,R)^{4}-(527.67\,R)^{4}]\)

\(\dot Q = 417.492\,\frac{BTU}{h}\)

Under the consideration of steady heat transfer we find that the net energy transfer from the student's body during the 20 min-ride to school is:

\(Q = \dot Q \cdot \Delta t\) (2)

Where \(\Delta t\) is the heat transfer time, measured in hours.

If we know that \(\dot Q = 417.492\,\frac{BTU}{h}\) and \(\Delta t = \frac{1}{3}\,h\), then the net energy transfer is:

\(Q = \left(417.492\,\frac{BTU}{h} \right)\cdot \left(\frac{1}{3}\,h \right)\)

\(Q = 139.164\,BTU\)

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Answer: Spent lead acid batteries (SLABs) are considered hazardous waste under the Resource Conservation and Recovery Act (RCRA) in the United States. However, they are exempt from the regulations that apply to other hazardous waste if they are recycled properly.

According to the Environmental Protection Agency (EPA), when spent lead acid batteries are recycled, they are considered a "universal waste" under RCRA. Universal wastes are certain types of hazardous waste that are considered less hazardous than other hazardous wastes and are subject to less stringent regulations. The regulations for universal waste are intended to encourage the collection and proper recycling or disposal of these materials.

To be considered for this exemption, the spent lead-acid batteries must be managed in accordance with the regulations for universal waste, which include proper labeling, storage, and transportation, as well as the requirement that the batteries be sent to a facility that is authorized to manage universal waste.

It is important to note that individual states may have different regulations regarding management and disposal of spent lead-acid batteries, so it is best to check with your state's environmental agency for specific information.

Answer:

forced convection

Explanation:

When a fan, pump or suction device is used to facilitate convection, the result is forced convection. Everyday examples of this can be seen with air conditioning, central heating, a car radiator using fluid, or a convection oven.

Answer:

yes i do.

Explanation:

it's pretty easy in my opinion but i dont know about you why do you ask?

Answer:

10.203 Volts

Explanation:

For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.

First, we need to find the voltage in the circuit.  To do this, we need to find the total resistance of the circuit.  When two resistors are in series, you sum the resistance.  So we can say the following:

R_Total = R1 + R2

R_Total = 570 Ω + 560 Ω

R_Total = 1130 Ω

Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.

V_Total = I_Total * R_Total

V_Total = 17.9 mA * 1130 Ω

V_Total = 20.227 V

Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more.  Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).

V_Total = V_1 + V_2

V_Total = V_1 + I_2*R2

V_Total - I_2*R2 = V_1

20.227 V - (17.9 mA * 560 Ω) = V_1

20.227 V - (10.024 V) = V_1

10.203 V = V_1

Hence, the voltage drop across R1 is 10.203 Volts.

Cheers.

Note that a milling machine can do all of the following tasks except: " ream a highly accurate hole with a fine finish" (Option D).

A milling machine is a tool that is used to machine flat and contoured surfaces, and it can also be used to rotate a multitoothed cutter into the workpiece to remove material. It is also capable of machining threads, gears, and spirals.

However, a milling machine is not typically used to ream holes, as reaming is a finishing operation that is usually done with a reamer, which is a specialized tool designed for this purpose. Reaming is used to create highly accurate holes with a fine finish, and it is typically done after the hole has been drilled or milled to its rough size.

There are several advantages to using a milling machine, including:

Versatility: Milling machines can be used to machine a wide range of parts and materials, including flat and contoured surfaces, threads, gears, and spirals.

Precision: Milling machines are capable of producing highly precise parts, as they can be accurately positioned and controlled using computer numerical control (CNC) technology, etc.

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Technician A says that a good cross hatch pattern helps to trap and retain oil in the cylinder bore.

Cylinder honing is a process of smoothing out and creating a specific cross-hatch pattern on the inside of a cylinder bore.

The purpose of the cross-hatch pattern is to trap oil and retain it in the cylinder bore where it is needed for lubrication.

The cross-hatch pattern also helps with piston ring seating and overall engine performance.

Technician A is correct in stating that a good cross-hatch helps to trap the oil and retain it in the cylinder bore.

Proper cylinder honing is an important aspect of engine rebuilding and maintenance to ensure efficient engine operation and longevity.

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Answer:A cookie

Explanation:To track interests.

Answer:

true

I hope it helps mate

I will always help you understanding your assingments

enjoy your day

#Captainpower:)

Answer:

the highest rate of heat transfer allowed is 0.9306 kW

Explanation:

Given the data in the question;

Volume = 4L = 0.004 m³

V\(_f\) = V\(_g\) = 0.002 m³

Using Table ( saturated water - pressure table);

at pressure p = 175 kPa;

v\(_f\) = 0.001057 m³/kg

v\(_g\) = 1.0037 m³/kg

u\(_f\) = 486.82 kJ/kg

u\(_g\) 2524.5 kJ/kg

h\(_g\) = 2700.2 kJ/kg

So the initial mass of the water;

m₁ = V\(_f\)/v\(_f\) + V\(_g\)/v\(_g\)

we substitute

m₁ = 0.002/0.001057  + 0.002/1.0037

m₁ = 1.89414 kg

Now, the final mass will be;

m₂ = V/v\(_g\)

m₂ = 0.004 / 1.0037

m₂ = 0.003985 kg

Now, mass leaving the pressure cooker is;

m\(_{out\) = m₁ - m₂

m\(_{out\) = 1.89414  - 0.003985

m\(_{out\) = 1.890155 kg

so, Initial internal energy will be;

U₁ = m\(_f\)u\(_f\) + m\(_g\)u\(_g\)

U₁ = (V\(_f\)/v\(_f\))u\(_f\)  + (V\(_g\)/v\(_g\))u\(_g\)

we substitute

U₁ = (0.002/0.001057)(486.82)  + (0.002/1.0037)(2524.5)

U₁ = 921.135288 + 5.030387

U₁ = 926.165675 kJ

Now, using Energy balance;

E\(_{in\) -  E\(_{out\) = ΔE\(_{sys\)

QΔt - m\(_{out\)h\(_{out\) = m₂u₂ - U₁

QΔt - m\(_{out\)h\(_g\) = m₂u\(_g\) - U₁

given that time = 75 min = 75 × 60s = 4500 sec

so we substitute

Q(4500) - ( 1.890155 × 2700.2 ) = ( 0.003985 × 2524.5 ) - 926.165675

Q(4500) - 5103.7965 = 10.06013 - 926.165675

Q(4500) = 10.06013 - 926.165675 + 5103.7965

Q(4500) = 4187.690955

Q = 4187.690955 / 4500

Q = 0.9306 kW

Therefore, the highest rate of heat transfer allowed is 0.9306 kW

Answer:

Steel alloy is a alloy which inside has alot of elements and are broken down to 2 groups because of there weight; low alloy steels and high alloy steels, which they are both steel alloys. Alot of these have uses in turbine blades of jet engines, and in nuclear reactors.

Explanation:

Answer:

kindly check the explanation section.

Explanation:

The word ''sprawl'' as it is related to people and population simply means an irregular expansion and the word ''urban'' simply means a city. So, putting both together as "urban sprawl" simply means an irregular expansion of cities or town.

Urban sprawl is majorly caused by race and land and the characteristics of urban sprawls are: [1]. there is High dependency on automobiles, [2]. the development is dispersed, and [3]. there is low density.

the torque is required to rotate the inner cylinder at 12 r min, the outer cylinder remaining stationary is 11.0807 N-m.

we have left out some other important details, such as the time required to reach that rpm, whether the beginning state is at rest, and the axis around which the cylinder is revolving. However, we'll suppose that it will be 60 seconds (time is necessary to convert rpm to angular acceleration)

rotation around the center axis

Angular acceleration = torque + MOI

Currently, angular acceleration equals 2 rpm/(t 60).

In order to avoid getting an extremely high figure, we estimated that the diameter of the cylinder was 600 mm rather than 600 meters: angular acceleration= 1.047 rad/s² MOI for cylinder across center dia= 1/4MR²+ 1/12ML²

MOI= 10.5833 kg-m

Now, the product of these two is torque.

11.0807 N-m of torque

Various MOI equations can be used to compute for different axes of rotation.

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The complete question is:

Crude oil at 20 c fills the space between two concentric cylinders 250 mm high and with diameters of 150 mm and 156 mm. Find the torque is required to rotate the inner cylinder at 12 r min, the outer cylinder remaining stationary.

Answer:

C

Explanation:

For a wear indicator type ball joint, when the grease fitting boss is flush with the base: B. The ball joint should be replaced.

A wear indicator can be defined as a type of technology that is designed to alert and warn a car owner or driver that the car's brake pad is needs a replacement.

Generally, a wear indicator is designed and fitted with a small boss. Thus, this small boss would continuously recede into its housing as wear occurs. However, when it recedes into the cover plate or flush with the base, it simply means that the ball joint should be replaced.

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