Applying the scale factor of 1:5, Lisa del Giocondo's face was 1.6 inches long in the sketch.
How to Apply Scale Factor?If the scale factor from the sketch to real life is 1:5, then it means that every inch in the sketch represents 5 inches in real life.
Therefore, to find out how long Lisa del Giocondo's face was in the sketch, we need to multiply the real-life length of her face by the inverse of the scale factor, which is 1/5.
If her face was 8 inches long in real life, then her face in the sketch would be:
8 inches * (1/5) = 1.6 inches
Therefore, based on the scale factor given, Lisa del Giocondo's face was 1.6 inches long in the sketch.
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Combine into a single logarithm.
3log(x+y)+2log(x-y)-log(x^2 +y^2)
Answer:
\(3\log _{10}\left(x+y\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)\)
Step-by-step explanation:
Given the expression
\(3log\left(x+y\right)+2log\left(x-y\right)-log\left(x^2\:+y^2\right)\)
solving to write into a single logarithm
\(3log\left(x+y\right)+2log\left(x-y\right)-log\left(x^2\:+y^2\right)\)
\(\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\)\(3\log _{10}\left(x+y\right)=\log _{10}\left(\left(x+y\right)^3\right)\)
so
\(=\log _{10}\left(\left(x+y\right)^3\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)\)
\(\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\)\(2\log _{10}\left(x-y\right)=\log _{10}\left(\left(x-y\right)^2\right)\)
so
\(=\log _{10}\left(\left(x+y\right)^3\right)+\log _{10}\left(\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)\)
\(\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)\)\(\log _{10}\left(\left(x+y\right)^3\right)+\log _{10}\left(\left(x-y\right)^2\right)=\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)\)
so
\(=\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)\)
\(\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)\)\(\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)\)
\(=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)\)
Thus,
\(3\log _{10}\left(x+y\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)\)
Several years ago, Belle invested in some gold. Gold is currently valued at $2,622 per ounce, which is 90% more than Belle originally paid for it. What was the purchase price of the gold?
Answer:
262.20
Step-by-step explanation: she originally payed for 10%=.10
2,622x.10=262.2
what is the solutiion to this system 3x+2y=8 -x=+y=-11
Answer:
2, 19, -3
Step-by-step explanation:
7x + 8 − 3x = −6 + 10
Answer:
x=-1
Step-by-step explanation:
7x + 8 − 3x = −6 + 10
4x+8=4
4x=4-8
4x=-4
x=-4/4
x=-1
Please mark Brainliest!!! Hope I helped!
Answer:x=-1
Step-by-step explanation:
Find the QT plzzzzzzz
Step-by-step explanation:
I didn't write language hope u get it
18. In AABC, 44 is a right angle, and m4B 45°. What is the length of BC? If the answer is not an integer, leave it in simplest radical form. The
diagram is not drawn to scale.
054 ft
17√3 ft
17√2 ft
017
Answer:
17√3
Step-by-step explanation:
In a 45-45-90 triangle, the hypotenuse is √3 times larger than the legs.
17*√3 = 17√3
Which expression is equivalent to the following expression?
(3x²y²) ³
3x^5y^5
9x^5y^5
27x^6y^6
9x^6y^6
Answer:
When you raise a power to another power, you multiply the exponents. Therefore, to simplify (3x²y²)³, you need to multiply the exponent 3 by each of the exponents in the parentheses:
(3x²y²)³ = 3³ x (x²)³ x (y²)³
= 27x^6y^6
So, the expression that is equivalent to (3x²y²)³ is 27x^6y^6, which is option C.
help this is over a lot of points and if you get this correct I will give you brainly of course
Answer:
First option is the correct answer
Step-by-step explanation:
Speed of car = 450/9 = 50 mph
Speed of Bus = 510/12 = 42.5 mph
Speed of train= 300/8 = 37.5 mph
So,
The car has the fastest speed at 50 miles per hour.
PLS HELP I WILL GIVE BRAINIEST If triangle BCD were rotated over the y-axis from point (0, 0), what would be the coordinates of the new triangle's vertices?
A. (0, -1) , (-4, -3), (-2, -1)
B. (-1, 0), (-5, -2), (-3, 4)
C. (1, 0), (5, 2), (3, 0)
D. (1, 0), (1, -2), (-3, -4)
The coordinates of the new triangle's vertices are (0, -1), (-4, -3), and
(-2, -1). Hence option A is true.
Used the rule of a point (x, y) when rotated over the y-axis of 90° clockwise rotation from point (0, 0),
(x, y) → (y, - x)
Given that the triangle BCD is shown in the image.
Here, the coordinates of the vertices of BCD are,
B = (1, 0)
C = (3, - 4)
D = (1, - 2)
Now apply the rotation rule, the coordinates of the new triangle's vertices are;
B' = (0, - 1)
C' = (- 4, - 3)
D' = (- 2, - 1)
Therefore, the option A is true.
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a card is drawn from a standard deck and replaced. after the deck is shuffled, another card is pulled. what is the probability that the first card drawn is a heart and the second card is a spade? (enter your probability as a fraction.)
If a card is drawn from a standard deck and replaced. after the deck is shuffled, another card is pulled. Then the probability that the first card drawn is a heart and the second card is a spade is 1/16.
The probability of drawing a heart on the first card is 1/4 since there are 13 hearts out of a total of 52 cards in a standard deck.
After replacing the card and shuffling the deck, the probability of drawing a spade on the second card is also 1/4 since there are 13 spades out of a total of 52 cards in the deck (assuming the deck is well-shuffled).
To find the probability of both events happening (drawing a heart and then a spade), we multiply the individual probabilities together:
Probability = (1/4) * (1/4) = 1/16
Therefore, the probability that the first card drawn is a heart and the second card is a spade is 1/16.
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Find the measure of each angle in the isosceles trapezoid.
L
K 118°
J
M
Answer:
∠L & ∠M are 62°
∠J = 118°
Step-by-step explanation:
check:
all 4 angles should total 360°
118°+118°+62°+62° = 360°
360° = 360°
kelly has read 5/6 of a book helen has read 9/12 of the same book who read more of the book?
Answer:
Kelly has read more of the book
what is a congruent polygon
A congruent polygon refers to two or more polygons that have the same shape and size. There must be an equal number of sides between two polygons for them to be congruent.
Congruent polygons have parallel sides of equal length and parallel angles of similar magnitude. When two polygons are congruent, they can be superimposed on one another using translations, rotations, and reflections without affecting their appearance or dimensions. Concluding about the matching sides, shapes, angles, and other geometric properties of congruent polygons allows us to draw conclusions about them.
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A supervisor at an electric bulb factory examines bulbs
produced in the factory for defects. She usually finds that there
are 14 defective bulbs in a week (7 days).
What is the probability that ther
The probability that there will be less than or equal to 2 defective bulbs in a day is 0.6767 or 67.67%.
The supervisor at an electric bulb factory usually finds that there are 14 defective bulbs in a week (7 days). The supervisor is interested in knowing the probability that there will be less than or equal to 2 defective bulbs in a day. Using the Poisson distribution, we can calculate this probability.
The formula for the Poisson distribution is P(x) = (e^ᵃ (a=-λ) * λˣ) / x!,
where x is the number of events, e is the constant 2.71828, λ is the mean number of events, and x! is the factorial of x. In this case, λ = 14/7 = 2, since there are 14 defective bulbs in a week.
Plugging in x = 0, 1, or 2, we get P(0) = 0.1353, P(1) = 0.2707, and P(2) = 0.2707. Therefore, the probability that there will be less than or equal to 2 defective bulbs in a day is 0.6767 or 67.67%.
The probability that there will be less than or equal to 2 defective bulbs in a day is 0.6767 or 67.67%.
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Can someone help me on dividing fractions, please
2x-2y =22
4x+2y=38
How to solve using systems elimination
Answer: x=10; y=-1
Step-by-step explanation:
To solve this via elimination:
get rid of the y's like this:
4x+2y=38 + 2x-2y=22
6x=60
x=10
20-2y=22
y=-1
A TV priced at £600 is reduced by 15% in a sale. What is the sale price of the TV?
(It’s not 90)
Answer:
It's 510!
Step-by-step explanation:
15% of 600 = 90
600-90 = 510
3x+2y−z=82x+2z=−4x+3y=4
Enter your answer, in the form (x,y,z), in the boxes in simplest terms.
Answer: (1/14, 10/7, -13/14)
Step-by-step explanation:
3x+2y−z=82x+2z=−4x+3y=4 ==> convert this to system of equations
3x+2y−z=4
82x+2z=4
−4x+3y=4
(3x+2y−z=4)*2
6x+4y−2z=8 ==> add this equation
82x+2z=4 ==> add this equation
88x+4y=12 ==> add the top 2 equations
(−4x+3y=4)*4
-16x+12y=16
(88x+4y=12)*3 ==> multiply by 3 to get 12y
264x+12y=36
-16x+12y=16
264x-(-16x)=36-16
264x+16x=20
280x=20
280x/280=20/280
x=1/14
−4x+3y=4
−4(1/14)+3y=4
-4/14 + 3y=4
-2/7 + 3y=4
(-2/7 + 3y=4)*7 ==> multiply equation by 7 to remove fractions
-2+21y=28
21y=30
y=30/21
y=10/7
3x+2y−z=4
3(1/14)+2(10/7)−z=4
3/14 + 20/7 - z=4
(3/14 + 20/7 - z=4)*14 ==> multiply equation by 14 to remove fractions
3 + 20*14/7 - 14z=56
3 + 280/7 - 14z=56
3+40-14z=56
43-14z=56
43-43-14z=56-43
-14z=13
z=-13/14
Answer: (1/14, 10/7, -13/14)
It costs Chevrolet $20,000,000 to develop and market a
new model of a car. The company sells this car model
for $25,000 each. How many cars must Chevrolet sell
in order to profit more than $5,000,000?
Oscar is offered jobs at two different dog-walking companies. At company A he would earn $50 a day, plus $6 for each dog walk. At Company B, he would earn $20 a day, plus $9 for each dog walk. How many dogs would Oscar have to walk to earn the same amount at both companies in a day? How much would he earn for walking that number of dogs? *
Answer:
he should walk 4 dogs in order to earn same amount
Determine the average rate of return for a project that is
estimated to yield total income of $382,000 over four years, cost
$695,000, and has a $69,000 residual value.
_ %
The average rate of return for a project that is estimated to yield a total income of $382,000 over four years, cost $695,000, and has a $69,000 residual value is 4.5% .
Here's how to solve for the average rate of return:
Total income = $382,000
Residual value = $69,000
Total cost = $695,000
Total profit = Total income + Residual value - Total cost
Total profit = $382,000 + $69,000 - $695,000
Total profit = -$244,000
The total profit is negative, meaning the project is not generating a profit. We will use the negative number to find the average rate of return.
Average rate of return = Total profit / Total investment x 100
Average rate of return = -$244,000 / $695,000 x 100
Average rate of return = -0.3518 x 100
Average rate of return = -35.18%
Rounded to one decimal place, the average rate of return is 35.2%. However, since the average rate of return is negative, it does not make sense in this context. So, we will use the absolute value of the rate of return to make it positive.
Average rate of return = Absolute value of (-35.18%)
Average rate of return = 35.18%Rounded to one decimal place, the average rate of return for the project is 4.5%.
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Estimate Jupiter’s mass using a one-digit whole number times a power of 10. Be sure to include units.
The most appropriate choice for exponent will be given by-
Mass of jupiter = 1.898 \(\times\) \(10^{27}\) kg
What are exponent?
Exponent tells us how many times a number is multiplied by itself.
For example : In \(2^4 = 2 \times 2 \times 2 \times 2\)
Here, 2 is multiplied by itself 4 times.
If \(a^m = a\times a \times a\times....\times a\) (m times), a is the base and m is the index.
The laws of index are
\(a^m \times a^n = a^{m+n}\\\\\frac{a^m}{a^n} = a^{m - n}\\\\a^0=1\\\\(a^m)^n = a^{mn}\\\\(\frac{a}{b})^m =\frac{a^m}{b^m}\\\\a^{-m} = \frac{1}{a^m}\)
Here,
Mass of jupiter = 1.898 \(\times\) \(10^{27}\) kg
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Juan recorded the total number of free throws he attempted during practices. His results are shown in the table.
Total Number of Free
Throws Attempted (y)
Number of
Practices (x)
1
234
45
80
115
150
Juan's coach told him to attempt 10 free throws before the first practice and then 35 free throws each practice. Did Juan follow his coach's instructions?
OYes, his free throws can be represented by y 35x + 10.
OYes, his free throws can be represented by y = 45x.
No, his free throws can be represented by y = 35x.
No. his free throws can be represented by y = 45x.
The equation of line is y = 35x + 10 and Juan followed the instructions
The solution is Option A. Yes, his free throws can be represented by
y = 35x + 10
What is an Equation of a line?The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept
And y - y₁ = m ( x - x₁ )
y = y-coordinate of second point
y₁ = y-coordinate of point one
m = slope
x = x-coordinate of second point
x₁ = x-coordinate of point one
The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )
Given data ,
Let the equation of line be represented as A
Now , the value of A is
Let the first point be P ( 1 , 45 )
Let the second point be Q ( 2 , 80 )
Now , the slope of the line is m = ( y₂ - y₁ ) / ( x₂ - x₁ )
Substituting the values in the equation , we get
Slope m = ( 80 - 45 ) / 2 - 1
Slope m = 35
Now , the equation of line is y - y₁ = m ( x - x₁ )
Substituting the values in the equation , we get
y - 45 = 35 ( x - 1 )
On simplifying the equation , we get
y - 45 = 35x - 35
Adding 45 on both sides of the equation , we get
y = 35x + 10
Hence , the equation of line is y = 35x + 10
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The complete question is :
Juan recorded the total number of free throws he attempted during practices. His results are shown in the table.
Number of practices = { 1 , 2 , 3 , 4 }
Number of throws attempted = { 45 , 80 , 115 , 150 }
Juan's coach told him to attempt 10 free throws before the first practice and then 35 free throws each practice. Did Juan follow his coach's instructions?
A) Yes, his free throws can be represented by y = 35x + 10.
B) Yes, his free throws can be represented by y = 45x.
C) No, his free throws can be represented by y = 35x.
D) No. his free throws can be represented by y = 45x.
2 - 3х + 5y +11+у? + 4х +9
Generating the sampling distribution of M
3. Generating the sampling distribution of M Let's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 by drawing samples from these values, calculating the mean of each sample, and then
The process of generating the sampling distribution of M involves drawing samples from a given population, calculating the mean of each sample, and then plotting these means to create a distribution.
Here is how to generate the sampling distribution of M using the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10:1. Determine the population mean (μ)The population mean (μ) is the mean of the entire population. For this example, the population mean is:
(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10) / 10 = 5.52.
Draw samples from the population the size of the sample does not matter, but for the purpose of this example, we will use a sample size of 3. Therefore, the possible samples are:
(1, 2, 3), (2, 3, 4), (3, 4, 5), (4, 5, 6), (5, 6, 7), (6, 7, 8), (7, 8, 9), (8, 9, 10)3. Calculate the mean of each sample For each sample, calculate the mean using the formula:
(x1 + x2 + ... + xn) / n
For example, for the sample (1, 2, 3), the mean is: (1 + 2 + 3) / 3 = 2
For the sample (2, 3, 4), the mean is: (2 + 3 + 4) / 3 = 3
For the sample (3, 4, 5), the mean is: (3 + 4 + 5) / 3 = 4
And so on, until all the means have been calculated. 4. Plot the means to create a distribution.
Finally, plot the means on a graph to create the sampling distribution of M. In this example, the sampling distribution of M should have a mean of 5.5 (the same as the population mean) and a standard deviation of approximately 0.98.
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find the equation of the circle below
Answer:
x² + y² = 16
Step-by-step explanation:
the circle has its centre at the origin (0, 0 )
the equation of a circle centred at the origin is
x² + y² = r² ( r is the radius )
the radius r of the circle is 4 , then
x² + y² = 4² , that is
x² + y² = 16
The marked price of fan is Rs.1250, and the shopkeeper allows a discount of 6% on it . Find the selling price of the fan .
Given:;
Marked price of a fan = Rs. 1250.
Discount percent = 6%.
To find:
The selling price of the fan.
Solution:
We have,
Marked price of a fan = Rs. 1250.
Discount percent= 6%.
So,
Selling price = Marked price - Discount
\(S.P.=1250-\dfrac{6}{100}\times 1250\)
\(S.P.=1250-75\)
\(S.P.=1175\)
Therefore, the selling price of the fan is Rs. 1175.
Please help me
What is 8/1 ÷ 4/3
Answer:
6
Step-by-step explanation:
To check my work I used desmos
Child Health and Development Studies (CHDS) has been collecting data about expectant mothers in Oakland, CA since 1959. One of the measurements taken by CHDS is the weight increase (in pounds) for expectant mothers in the second trimester. In a fictitious study, suppose that CHDS finds the average weight increase in the second trimester is 14 pounds. Suppose also that, in 2015, a random sample of 40 expectant mothers have mean weight increase of 16 pounds in the second trimester, with a standard deviation of 6 pounds. At the 5% significance level, we can conduct a one-sided T-test to see if the mean weight increase in 2015 is greater than 14 pounds. Statistical software tells us that the p-value = 0.021.Which of the following is the most appropriate conclusion?There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds.There is a 2.1% chance that mean second trimester weight gain for all expectant mothers is 14 pounds in 2015.There is a 2.1% chance that mean second trimester weight gain for all expectant mothers is 16 pounds in 2015.There is 2.1% chance that the population of expectant mothers will have a mean weight increase of 16 pounds or greater in 2015 if the mean second trimester weight gain for all expectant mothers was 14 pounds in 1959.Find the p-value for the hypothesis test. A random sample of size 50 is taken. The sample has a mean of 420 and a standard deviation of 81.H0: µ = 400Ha: µ > 400The p-value for the hypothesis test is
We accert H1 alternative that is result is population mean greater than 400.
There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.
What is standard deviation?
The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the established mean.
We have given: μ = 14, x bar = 16, n = 40, s = 6, α = 5%, = 0.05
To test μ0 : μ = 14 Vs H1: μ > 14
Test statistics = (X bar - μx)√n / sx = (2 x 6.3245) / 6 = 2.1081
So, P value = 0.021
Conclusion: There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.
P value for the hypothesis test
n = 50, x bar = 420, sx = 81, μ = 400,
To test: H0: μ 400 Vs H1: μ > 400
It is right tail test
Test statistics = (X bar - μx)√n / sx = (420 - 400) √50 / 81 =
z = 1.7459
P value = 0.04093
Declsion: We reject H0 is p value < α
Here α = 0.05
Hence P value < α
Conclusion: We accert H1 alternative that is result is population mean greater than 400.
Hence, we accert H1 alternative that is result is population mean greater than 400.
There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.
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Answer the question below.
Answer:
1247.03
Step-by-step explanation:
if £1=$1.35
?=$125(crisscross them to get an answer.)
$125×£1÷$1.35=£92.59
if £1=$1.35
?=$6(crisscross to get an answer.)
$6×£1÷$1.35=£4.44
so you add them all up
£1150+£4.44+£92.59= £1247.03