The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time? (Note: Ignore the percent symbol when entering your answer. For example, if the answer is 42.1%, enter 42.1)

Answer:

its 84 dollars sorry I'm late

Step-by-step explanation: Make a proportional relationship.

make 120% into a fraction. 120/100

then make 70 into a fraction using a variable. For example, x/70

Then cross multiply 120 and 70. 120x70=8,400

Last divide 8,400 by 100 and that equals $84.

Hope this helps!

Answer:

- 1/2

Step-by-step explanation:

In order to find a slope intercept we need to use,

Equation : y= mx + b to find the slope (m)

• Equation 1:, y = 2x - 4

• Equation 2: ,y = -1/2 x + 1

Choosing point ( 2, 0 ) -where the equations intersect-:

• Equation 1:

• Equation 2:

Answer: ( 2, 0 )

percent of water is: 32/80*100= 40%

To solve this problem, we need to set up two equations to represent the amount of money that Nina and Brianna each have after working for a certain number of hours. Let H be the number of hours that Nina works and K be the number of hours that Brianna works.

What in mathematics is a linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables."

We can set up the following two equations:

N = 371 + 31H

B = 362 + 26K

Next, we need to add the two equations to find the total amount of money that they have between them. This will give us:

N + B = 371 + 31H + 362 + 26K

N + B = 733 + 31H + 26K

Since Nina and Brianna need a total of $650 for their honeymoon, we can set up the equation:

733 + 31H + 26K = 650

To solve for H and K, we can subtract 733 from both sides of the equation to get:

31H + 26K = -83

Next, we can divide both sides of the equation by 7 to get:

H + K = -11.857142857

Since H and K represent the number of hours that Nina and Brianna need to work, they must be whole numbers. Therefore, we need to find two whole numbers that add up to -11.857142857.

The only such pair of numbers is -12 and 1. Therefore, Nina needs to work -12 hours and Brianna needs to work 1 hour.

It's important to note that the solution to this problem does not make sense in the context of the problem, as it is not possible for someone to work a negative number of hours. This suggests that there is something wrong with the problem or with the way that it was written. It is possible that some information is missing or that there is a mistake in the problem statement.

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Answers:

Note: your teacher may want you to type in a positive value for r

=========================================================

Explanation:

The given equation y = 8(1-0.15)^t is in the form y = a(1+r)^t

We have a = 8 as the initial value, or what we start with.

r = -0.15 converts to -15%, so we have a decay of 15%

Plug in t = 3 to find the corresponding value of y

y = 8(1-0.15)^t

y = 8(1-0.15)^3

y = 8(0.85)^3

y = 8(0.614125)

y = 4.913

y = 4.9

Answer:

a = 8

r = 85%

y = 4.913

Step-by-step explanation:

For a, the exponential decay function is y=a*r^t. In order to find the initial amount, you are solving for when t = 0 or, y(0). Thus, t, or time, is 0. Solve the equation with time of 0.

y = 8(1-0.15)^0 = 8*1 (anything to the 0 power equals 1)

a = 8 is the initial amount

In order to solve for r, you need to solve (1 - 0.15) = 0.85. Now, multiply by 100 to get the percent 100 * 0.85 = 85%

Lastly, when t = 3 solve the equation filling in the exponent, t with 3 like below:

y = 8(1-0.15)^3 (PEMDAS; parenthesis and exponents first)

y = 8(0.85)^3 = 8*(0.614125)

y = 4.913

The name "parabola" is due to Apollonius, who discovered many properties of conic sections. It means "application",

The equation of the parabola with vertex (-8,5) and directrix y= -3 is given by .

It is given to us that -

The vertex of the parabola = (-8,5)

The directrix of the parabola is y = -3

We have to find the equation of the parabola with the given vertex and directrix.

We know that any point on a given parabola represented as () is equidistant from the directrix and the focus.

So, the equation for the point can be represented as

\([y-(-3)]=\sqrt{([x-(-8} ]^{2} +(y-5)^{2}\)

\((y+3)^2} =(x+8)^{2} +(y-5)^{2} \\=y^{2}+9+2*y*3=(x+8)^{2} +y^{2}+25-2*y*(-5)=6y-10y=(x+8)^{2} +16=-4y=(xx+8)^{2} +16=y=\frac{-1}{4} (x+8)^{2}+4\)

Thus, the equation of the parabola with vertex (-8,5) and directrix y= -3 is given by .\(=y=\frac{-1}{4} (x+8)^{2} +4\)

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The given vector field F = (2xy, x², y²) is conservative because its curl is zero. The potential function for this vector field can be found by integrating each component of the vector field with respect to the corresponding variable, resulting in a potential function of f(x, y, z) = x²y + xy² + C, where C is an arbitrary constant.

To determine whether a vector field is conservative, we can use the curl of the vector field. If the curl of the vector field is zero, then the vector field is conservative.

Let's consider a sample vector field F = (2xy, x², y²).

To determine if this vector field is conservative, we need to calculate its curl:

Curl(F) = (∂F₃/∂y - ∂F₂/∂z, ∂F₁/∂z - ∂F₃/∂x, ∂F₂/∂x - ∂F₁/∂y)

Calculating the partial derivatives, we have:

∂F₁/∂x = 2y

∂F₂/∂y = 0

∂F₃/∂z = 0

∂F₂/∂x = 0

∂F₃/∂y = 2y

∂F₁/∂z = 0

Substituting these values into the curl formula, we get:

Curl(F) = (0 - 0, 0 - 0, 2y - 2y)

       = (0, 0, 0)

Since the curl of the vector field is zero, we can conclude that the vector field F = (2xy, x², y²) is conservative.

To find a potential function for this vector field, we integrate each component of the vector field with respect to the corresponding variable:

∫F₁ dx = ∫2xy dx = x²y + C₁(y, z)

∫F₂ dy = ∫x² dy = xy² + C₂(x, z)

∫F₃ dz = ∫y² dz = y²z + C₃(x, y)

Here, C₁, C₂, and C₃ are arbitrary functions of the variables that do not depend on the integration variable.

The potential function for the vector field F is given by:

\(f(x, y, z) = x^2y + xy^2 + y^2z + C\)

Where C is an arbitrary constant that incorporates the integration constants from each component of the vector field.

Thus, the potential function for the vector field \(F = (2xy, x^2, y^2)\) is \(f(x, y, z) = x^2y + xy^2 + y^2z + C\).

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To determine the concentration of the analyte in the unknown using the fit parameters and the linear model, you need to substitute the given signal value into the equation y = mx + b.

In this case, the linear model is represented by the equation y = mx + b, where:

y is the signal value (80.77 in this case),

m is the slope obtained from the regression analysis, and

b is the y-intercept obtained from the regression analysis.

You haven't provided the values of m and b, so I'll use placeholders for now.

Let's assume the slope (m) obtained from the LINEST formula is m = 2.5 and the y-intercept (b) is b = 10.

Substituting these values into the equation:

y = mx + b

80.77 = 2.5x + 10

To find the concentration (x), we can rearrange the equation:

2.5x = 80.77 - 10

2.5x = 70.77

x = 70.77 / 2.5

x ≈ 28.31

Therefore, based on the given fit parameters and the linear model, the concentration of the analyte in the unknown is approximately 28.31 ppm Co2+.

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The IR spectrum described could be an alkyl chloride with a carbonyl group, such as chloroform (\(CHCl_{3}\)).

The IR spectrum described suggests the presence of several functional groups in the compound.

The strong, broad band in the 3600 to 3100 inverse centimeter range corresponds to the stretching vibration of the O-H bond in alcohols, while the strong, spiked peak in the 3000 to 2800 inverse centimeter range corresponds to the stretching vibration of the C-H bond in alkanes. The weak peak near 1850 inverse centimeters corresponds to the stretching vibration of the C=O bond in ketones, while the sharp peak near 1640 inverse centimeters corresponds to the stretching vibration of the C=C bond in alkenes.

The series of spiked bands in the 1500 to 1200 inverse centimeter range corresponds to the bending vibrations of the C-H bond in alkanes, while the two strong bands at 990 and 910 inverse centimeters correspond to the stretching vibration of the C-Cl bond in alkyl chlorides.

Based on this information, the compound that matches the IR spectrum described could be an alkyl chloride with a carbonyl group, such as chloroform (\(CHCl_{3}\)).

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The sample variances for n=8 SS= 42 is 6 ,for N=8 SS= 28 is 4 and for N=8 SS=98 is 14.And the MS within SS is 168,DF is 21 and MS is 8.

To calculate the sample variance and the mean square within for each of the three samples.

To calculate the sample variance (S²) for each sample,

we can use the formula:
S² = SS / (n - 1)
I. Sample variance (S²) for the first sample:
S² = 42 / (8 - 1) = 42 / 7 = 6

II. Sample variance (S²) for the second sample:
S² = 28 / (8 - 1) = 28 / 7 = 4

III. Sample variance (S²) for the third sample:
S² = 98 / (8 - 1) = 98 / 7 = 14

Now, let's calculate the mean square within (MS within) for the ANOVA.

First, find the total sum of squares (SS total) and total degrees of freedom (DF total):
SS_total = SS1 + SS2 + SS3 = 42 + 28 + 98 = 16
DF_total = (n1 - 1) + (n2 - 1) + (n3 - 1) = (8 - 1) + (8 - 1) + (8 - 1) = 7 + 7 + 7 = 21

Then, calculate the mean square within (MS_within) using the formula:

MS within = SS total / DF total

= 168 / 21 = 8

So, the mean square within for the ANOVA is:
SS = 168, DF = 21, MS = 8
Our answer:
I. S² = 6
II. S² = 4
III. S² = 14
MS_within (ANOVA within treatments): SS = 168, DF = 21, MS = 8

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c) It would be larger, because higher confidence requires a larger margin of error.

When increasing the confidence level from 95% to 99%, the margin of error of the confidence interval tends to increase. This is because a higher confidence level means we want to be more certain or have a higher level of confidence in capturing the true population parameter.

To achieve a higher confidence level, we need to widen the interval to account for more potential variability in the population. As a result, the margin of error increases, reflecting the increased uncertainty and the need for a larger range of values to capture the true population parameter with higher confidence.

Therefore, the margin of error of a 99% confidence interval, based on the same sample, would be larger compared to the 95% interval.

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Answer:

1/4=25 minutes an hour

25×2=50

it will take him 50 minutes

Answer:

2 pound

Step-by-step explanation:

Im legit doing this question right now

The number of packs of paper each classroom get is 3(2/3).

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Number of classrooms = 3

Number of packs of paper = 11

The number of packs of paper each classroom gets.

= 11/3

= 3(2/3)

Thus,

Each classroom gets 3(2/3) packs of paper.

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Answer:

y=-9/2x plus 4

Step-by-step explanation:

y=ax plus b

Use points from the task.

4=0x plus b

so b=4

-5=-2a plus 4

-2a = -9

a = -9/2

y=-9/2x plus 4

Answer:

Step-by-step explanation:

To minimize the variance of the portfolio, the closest option is A) Asset A: 0.4, Asset B: 0.6.

In order to minimize the variance of a portfolio, the weights assigned to each asset should be non-negative and sum up to 1. Option A) Asset A: 0.4, Asset B: 0.6 satisfies these conditions, with weights totaling 1.

Option B) Asset A: 1.3, Asset B: -0.3 violates the requirement of non-negative weights, and Option C) Asset A: 1.2, Asset B: -0.6 also has negative weights and does not sum up to 1.

By allocating 40% to Asset A and 60% to Asset B, we achieve a combination that minimizes the variance of the portfolio while adhering to the constraints of weight allocation.

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If m and n are relatively prime, the numerator (an + bm) and denominator (mn) have no common factors other than 1, and therefore, (an + bm)/(mn) is in lowest terms.

To prove that (an + bm)/(mn) is in lowest terms if and only if m and n are relatively prime, we will need to establish two separate claims:

Claim 1: If (an + bm)/(mn) is in lowest terms, then m and n are relatively prime.

Claim 2: If m and n are relatively prime, then (an + bm)/(mn) is in lowest terms.

Proof of Claim 1:

Let's assume that (an + bm)/(mn) is in lowest terms. This means that the numerator (an + bm) and the denominator (mn) have no common factors other than 1.

Suppose m and n are not relatively prime, which means they have a common factor greater than 1.

Let's say that factor is d, where d > 1. Then we can express m and n as follows: m = dx and n = dy, where x and y are integers.

Now, we rewrite the numerator (an + bm) as follows:

an + bm = an + b(dx) = n(a + bx/d)

Since m = dx and n = dy, we have (an + bm)/(mn) = (n(a + bx/d))/(dx * dy) = (a + bx/d)/(xy).

We can see that both the numerator (a + bx/d) and the denominator (xy) have the factor d.

This contradicts our assumption that (an + bm)/(mn) is in lowest terms, as they have a common factor greater than 1.

Therefore, m and n must be relatively prime.

Proof of Claim 2:

Now, let's assume that m and n are relatively prime, which means they have no common factors other than 1.

To show that (an + bm)/(mn) is in lowest terms, we need to demonstrate that its numerator and denominator have no common factors other than 1.

Let's suppose that the numerator (an + bm) and the denominator (mn) have a common factor d, where d > 1.

This implies that d divides both an + bm and mn.

Since d divides mn, we can express m and n as follows: m = dx and n = dy, where x and y are integers.

Now, let's rewrite the numerator (an + bm) as follows:

an + bm = an + b(dx) = n(a + bx/d)

We can see that d divides both n and the expression (a + bx/d). Therefore, d also divides the numerator (an + bm).

However, we initially assumed that (an + bm)/(mn) is in lowest terms, which means the numerator and denominator have no common factors other than 1. This contradicts the assumption that they have a common factor d > 1.

Thus, if m and n are relatively prime, the numerator (an + bm) and denominator (mn) have no common factors other than 1, and therefore, (an + bm)/(mn) is in lowest terms.

By proving both Claim 1 and Claim 2, we have established that (an + bm)/(mn) is in lowest terms if and only if m and n are relatively prime.

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The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify \([\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\)   and to find the value of s in \(x^s\).

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

\(=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}\)
Comparing with \(x^S\)
s = -16/3

Thus, the required value of the s = -16/3. None of these are correct.

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Answer:

AB slope is 1/2

CD slope is 1/3

Since the slopes of the lines aren't the same, the lines aren't parallel.

Step-by-step explanation:

Answer:

10.29 u

Step-by-step explanation:

Given :-

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

\(:\implies\) D = √{(x2-x1)² + (y2-y1)²}

\(:\implies\) D =√[ (7+2)² +(9-4)²]

\(:\implies\) D =√[ 9² +5²]

\(:\implies\) D =√[ 81 +25]

\(:\implies\) D = 10.29

Answer:

6.32455532034

Step-by-step explanation:

Pythogreans theorem:

a^2 + b^2 = c^2 (we want c)

(9-7)^2+(-2-4)^2 = c^2

2^2 + (-6)^2 = c^2

4+36 = c^2

c = sqrt(40)

c = 6.32455532034

The account balance after 9 years is $528.28. The result is obtained by adding the interest to the initial deposit.

The simple interest of an amount of money can be counted by the following formula.

I = P₁ - P

I = P × r × t

Where

We have

Find the final account balance!

After 9 years, the simple interest of the savings is

I = P × r × t

I = $425.00 × 2.7% × 9 years

I = $3,825.00 × 0.027

I = $103.28

The final account balance would be

I = P₁ - P

$103.28 = P₁ - $425.00

P₁ = $425.00 + $103.28

P₁ = $528.28

Hence, after 9 years, the account balance would be $528.28.

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Answer: \(n=5\)

Add -10 to each side of the equation

\(10 + -10 + 8n = 50 + -10\)

Combine like terms

\(0 + 8n = 50 + -10\\8n = 50 + -10\\8n = 40\)

Divide each side by 8

\(8n/8=40/8\\n=5\)

Answer:

n = 5

Step-by-step explanation:

8n +10 = 50

     -10    -10

     8n  = 40

      8      8

       n   = 5

Answer:

x=5,1,4

Step-by-step explanation:

a

Answer:

\(x=\pm \sqrt{11} \\y=-4.\)

Step-by-step explanation:

\(\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \: 2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.\)

Answer: 29

Step-by-step explanation:

The obtained value of x after solving the equation (x-3)² + 9 = 0 by the square root principle will be x=3+31,3-3i. Option d is correct.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that,

(x-3)² + 9 = 0

(x-3)²= -9

(x-3)=√-9

(x-3)=√9×√-1

(x-3)=±3i

x=3±3i

Thus, the obtained value of x after solving the equation (x-3)² + 9 = 0 by the square root principle will be x=3+31,3-3i. Option d is correct.

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Answer:

The correct answer is 1/42x^5.

Step-by-step explanation:

7 • 6 = 42

-8 + 6 = -5 (When multiplying, you must add the exponents.)

= 42x^(-5) (To remove the negative sign, switch it to a fraction.)

= 1/42x^5