The per-unit standards for direct materials are 2 gallons at $4 per gallon. Last month, 12800 gallons of direct materials that actually cost $37400 were used to produce 7500 units of product. The direct materials quantity variance for last month was

Answer:

A incresing speading up

Explanation:

Answer:

v=u+at

30=0+a×12

30=12a

a=\(\frac{30}{12}\)

a=2.5ms⁻²

Answer:

2.5 m/s^2

Explanation:

There is this thing in Physics called the BIG 4 equations that help us determine one or more of the missing variables. In this case, we know the initial velocity, final velocity, and time. We're asked to find the acceleration.

This equation has all the criteria to find acceleration:

Vf = at + Vi    --->  Final Velocity is equal to acceleration times time plus initial velocity

Plugging in the values and using algebra, we can find the acceleration.

30 = 12a + 0

a = 2.5

Answer:

Explanation:

The resistance of this device is determined by using the formuia from Ohms Law:

V = IR

where; V = voltage

I = current

R = resistance

From the above equation:

R = V/ I ---- (1)

And

I = P/V    --- (2)

If 1 unit = 1 KWH = 3.6 × 10⁶ J

Then;

2.2 units = (3.6 × 10⁶ × 2.2)

= 7.92 × 10⁶ J

So, Energy = 7.92 × 10⁶ J

Also:

Power = energy/time

Power =  7.92 × 10⁶ J / 1 hour

Power = 7.92 × 10⁶ J / 3600 seconds

Power = 2200 Watts

From equation (2)

I = P/V

I = 2200/220

I = 10 A

Recall that:

Resistance R = V/I

Resistance R = 220/10

Resistance R = 22 ohms

SO, if 1 unit costs = Ts 6.00

Then the cost of 2.2 unit = 2.2 ( Rs  6.00)

= Rs 13.20

The map provided in the passage shows the location of the epicenter of a major earthquake that occurred about 1700 years ago.

Point A represents a location on a tectonic plate boundary. The names of the major tectonic plates X and Y have not been explicitly stated in the passage or on the map. However, it is mentioned that the Anatolian Plate, which is a minor tectonic plate, is located near the island of Crete and the Hellenic Trench. The Hellenic Trench is associated with the fault responsible for the earthquake that occurred in the year 365. The arrows on the map indicate the relative directions of plate motion. It can be inferred that the tectonic plates X and Y are adjacent to each other and their movements along the fault caused the earthquake and subsequent tsunami. The earthquake caused uplift of the southwestern coastal region of Crete and resulted in the remains of corals and other sea life now found on land 10 meters above sea level. Earthquakes along the fault, associated with the Hellenic Trench, may occur about every 800 years.

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If you own an old screw drive Chamberlain Liftmaster garage door opener, then there may come a time when you need to adjust the end of travel limits on it. The good news is that it's a fairly easy process that can be done with just a few simple steps. Here's how to do it:

Step 1: Close the garage door completely.

Step 2: Locate the "down" limit adjustment screw, which is usually located near the motor unit.

Step 3: Turn the "down" limit adjustment screw clockwise to decrease the travel of the garage door, or counterclockwise to increase the travel of the garage door.

Step 4: Open the garage door completely.

Step 5: Locate the "up" limit adjustment screw, which is usually located near the motor unit.

Step 6: Turn the "up" limit adjustment screw clockwise to decrease the travel of the garage door, or counterclockwise to increase the travel of the garage door.

Step 7: Test the adjustment by closing and opening the garage door several times.

If you find that the adjustment is still not correct, then you may need to repeat the process until you get it just right. Remember to test the garage door after each adjustment to ensure that it is working properly.

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The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.

The launching of a cannonball is a case of projectile motion.

The formula for the range(R) of a projectile is

R = 2 u² sin(θ) cos(θ)/g

Here,

u = initial speed with which the projectile is launched = 35 m/s

θ = Angle at which projectile is launched = 50°

R = 2 (35)² sin(50) cos(50)/ 9.8

R = 2 x 1225 x 0.76 x 0.64/9.8

R = 119.1 m

Thus, The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.

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Responding variable

Explanation:

Ideally in no air resistance, the ball will return to the thrower's hand with a speed of 10 m/s. Thus, the correct option is B.

Speed is the distance covered by an object with respect to time taken. It can also be defined as the change in the position of an object with respect to time. It is a scalar quantity as it has only magnitude and no direction.

The ball which is thrown straight upward in the sky with a speed of 10 m/s will return back to the thrower's hands with a speed of 10m/s in the ideal case of no air resistance because during this situation, no acceleration takes place. At the highest point, the velocity of the ball is zero however the ball is still under the influence of gravity, here the acceleration due to gravity is acting downwards on the ball.

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b)

Given that,

A=10 N at 0°

B=20 N at 180°

As we can see these two vectors are in opposite directions.

Thus the resultant vector will be in the direction of the vector with the higher magnitude.

In vector addition we can write,

Where C is the resultant vector.

Thus magnitude of R will be equal to,

The negative sign indicates that the direction of the C is along the negative x-axis.

Thus the magnitude of C is 10 N and the direction of the C is 180°

a)

Given,

A= 10 N at 0°

B=20 N at 0°

The the vector C is

The direction of R will be along the direction of these two vectors, as they are in the same direction.

Thus the magnitude of the vector C will be 30 N and the direction of the vector C is 0°

c)

Given,

A=10 N at 180°

B=20 N at 180°

Thus the vector C is

The direction of the vector C will be along the direction of the negative x-axis, as these two vectors are along the negative x-axis.

Thus the magnitude of the vector C is 30 N and the direction of the vector C is 180°

d)

Given,

A= 10 N at 0°

B=20 N at 90°

The x-component of the vector C will be,

The y- component of C will be,

The magnitude of vector C is given by,

The direction of the vector C will be,

Thus the magnitude of C will be 22.36 N and the direction of C will be 63.43°

e)

Given that

A= 10 N at 90°

B=20 N at 0°

The x-component of the vector C will be

The y-component of the vector C will be

The magnitude of the vector C will be

The direction of vector C will be,

Thus the magnitude of the vector C will be 22.36 N and the direction of the vector C will be 26.56°

The molar volume of saturated vapor of n-butane at 350K is approximately 0.154 L/mol. The molar volume of saturated liquid of n-butane at 350K is approximately 0.000548 L/mol.

Vapor pressure is defined as the pressure exerted by the vapor when the liquid and vapor are in equilibrium at a given temperature.

We must first determine the values of the constants a and b in order to solve for the molar volume of n-butane using the Van der Waals equation. The Van der Waals equation is presented as follows:

(P + a(n/V)²)(V - nb) = nRT

where:

P = vapor pressure

n = number of moles

V = molar volume

R = gas constant

T = temperature

The constants a and b are given by:

a = (27/64)(R²)(Tc²)/Pc

b = (RTc)/(8Pc)

where:

Tc = critical temperature

Pc = critical pressure

For n-butane, Tc = 425.2 K and Pc = 38.0 bar.

a = (27/64)(R²)(Tc²)/Pc = (27/64)(8.3145²)(425.2²)/(38.0) = 8.3456 bar*(L/mol)²

b = (RTc)/(8Pc) = (8.3145425.2)/(838.0) = 0.1462 L/mol

a. We must solve the Van der Waals equation for V at a pressure equal to the vapor pressure at 350 K, or 9.4573 bar, in order to determine the molar volume of saturated vapor.

(P + a(n/V)²)(V - nb) = nRT

(9.4573 + 8.3456(n/V)^2)(V - 0.1462n) = n(8.3145)(350)

To find V, we can solve using an iterative approach. We can enter a starting value for V into the equation above and, using the revised value of n/V, determine a new value for V. Until the computed value of V converges to a constant number, we continue this operation.

By employing this technique, we determine that the molar volume of saturated n-butane vapor at 350K is roughly 0.154 L/mol.

b. When the pressure is equal to the saturation pressure at 350 K, we need to solve the Van der Waals equation for V in order to determine the molar volume of saturated liquid, which may be done by using Antoine's equation:

log10(P) = A - (B / (T + C))

where:

P = pressure (in bar)

T = temperature (in K)

A, B, and C are constants

For n-butane, the constants for Antoine's equation are:

A = 4.00959

B = 1435.264

C = -48.37

Substituting these values and T = 350 K into Antoine's equation, we get:

log10(P) = 4.00959 - (1435.264 / (350 - 48.37)) = 3.0278

\(P = 10^{(3.0278)\) = 20.318 bar

Now, we can use the Van der Waals equation with P = 20.318 bar to solve for the molar volume of saturated liquid.

(20.318 + 8.3456(n/V)²)(V - 0.1462n) = n(8.3145)(350)

Using the same iterative method as before, we find that the molar volume of saturated liquid of n-butane at 350K is approximately 0.000548 L/mol.

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You have to know the group of the atom in the periodic table and the number of the valence electrons present in it.

Determine the atom's periodic table group number. The group number is related to the atom's valence electron count. Draw the element's symbol to show the nucleus and inner electrons.

In order to depict the valence electrons, place dots all around the symbol. One valence electron is represented by each dot. To begin, place one dot on each side of the sign. After that, pair the remaining electrons and place one on each side of the symbol until all of them have been used. Verify if the atom has reached an octet.

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true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

Hi there!

Voltage in a series can be expressed by the following:

\(V_T = V_1 + V_2\)

In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

\(V_T = 10 + 10 = \boxed{\text{ D. 20 V}}\)

Answer:

20 v

Explanation:

Answer:

A. NaF and MgS

Explanation:

The reaction equation is given as:

             Na₂S  +  MgF₂  →   2NaF  + MgS

The product of this reaction is  NaF and MgS.

In a double displacement reaction there is an actual exchange of partners to form new compounds. This reaction takes place between ionic compounds.

The driving force for the reaction is:

First, draw a diagram to visualize the situation:

The average velocity v is defined as the quotient of the total displacement over the time that it takes to perform the displacement:

Notice that both velocity and displacement are vector quantities.

For that reason, the direction of the average velocity will be the same as the direion of the displacement.

Find the displacement by adding the three displacements as vectors. To do so, find the x and y components of each displacement, add the components to find the x and y components of the total displacement, and finally use the vertical and horizontal components of the total displacement to find the direction.

9.90 km East:

Since this vector points towards the East, its vertical component is 0.

The horizontal component is 9.90 km.

9.00 km 15.0º East of North

Since the angle of 15.0º is measured with respect to the positive Y axis, use the cosine function to find the vertical component and the sine function to find the horizontal component.

Vertical component:

Horizontal component:

9.90 km East:

Since this vector points towards the East, its vertical component is 0.

The horizontal component is 9.90 km.

Vertical component of the displacement:

Horizontal component of the displacement:

To find the direction in degrees north of east, notice that:

Then:

The magnitude of a vector V with components V_x and V_y is:

Then, the magnitude of the displacement is:

Divide the magnitude of the displacement by the total travel time to find the magnitude of the average velocity. The total time was 0.5h+0.77h+0.5h=1.77h.

Therefore, the answers are:

When two mirrors are placed facing each other, it creates a phenomenon known as "mirror reflection" or "infinite reflection." This occurs as the light reflects back and forth between the mirrors, creating multiple reflections that appear to stretch infinitely into the distance.

The reflection continues on and on until it becomes too small to see. In this way, a person sees many reflections of themselves, and each reflection is smaller than the previous one. This is called an infinity mirror or a mirror tunnel.An infinity mirror is a visual illusion that looks like the mirror has no end. It is accomplished by placing a mirror in front of another and allowing a small amount of space between the two. Then, light is reflected back and forth in the space between the mirrors, generating an infinite loop of images.

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Answer:

The correct option is;

(b) The end A of the solenoid behaves like a north pole

Explanation:

According to Lenz's law we have that the induced emf direction in the solenoid due to the rapid introduction of the bar magnet will be such that the electric current induced will have a resultant magnet field that will  oppose to the movement of the north pole of the bar magnet that resulted in the magnetic field

Therefore, the opposing magnetic pole to the north pole of a magnet is a north pole and the solenoid end A will act like the north pole.

The radius of curvature of the concave makeup mirror is 230 cm.

To calculate the radius of curvature of the concave makeup mirror, we can use the mirror equation:

1/f = 1/v - 1/u,

where:

f = focal length of the mirror,

v = image distance,

u = object distance.

In this case, the person is 23 cm in front of the mirror, which means the object distance (u) is -23 cm (negative because it is in front of the mirror).

We are given that the person sees an upright image magnified by a factor of 4. Since the image is upright, the magnification (M) is positive. We can use the magnification formula:

M = -v/u,

where M = 4.

Substituting the values into the magnification formula, we get:

4 = -v/(-23),

Simplifying, we have:

4 = v/23.

Solving for v, we find:

v = 4✕ 23,

v = 92 cm.

Now, we can substitute the values of v and u into the mirror equation:

1/f = 1/92 - 1/(-23).

Simplifying, we have:

1/f = (1 + 4)/92,

1/f = 5/92.

To find the radius of curvature, we use the formula:

f = R/2,

where R is the radius of curvature.

Substituting the values, we get:

1/R = 2/5 ✕ 1/92,

1/R = 2/460,

R = 460/2,

R = 230 cm.

Therefore, the radius of curvature of the concave makeup mirror is 230 cm.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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The force is different because of the amount of weight applied so the answer is A

The force that makes a difference in the weight of each person is Gravitational. Correct option is B.

Gravitational force is a fundamental force of nature that exists between any two objects with mass. It's the force that keeps us and everything else on Earth anchored to its surface. This force is proportional to the mass of the objects involved and inversely proportional to the square of the distance between them.

For example, if you were standing on a bathroom scale, the reading on the scale represents the force of the Earth's gravity acting on your body, which is why it's often referred to as your "weight." The actual mass of an object remains constant regardless of its location, but its weight can vary depending on the strength of the gravitational field at different locations (e.g., the weight on the Moon would be less than on Earth due to the Moon's weaker gravitational pull).

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Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

Answer:

1.Tackle

2.helmet

3.touchdown

4.quarterback

5.interference

6.touchback

7.safety

8.cornerback

9.handoff

10.lateral

11. reciever

12.completion

13.interception

14.center

15.referee

16.huddle

17.overtime

18. facemask

19.pigskin

20.penalty

Explanation:

The correct words are "Tackle, Theme, Touchdown, Quarterback, Interference, Touchdown, Safety, Cornerback, Offhand, Aerial, Receiver, Completion, Receptionist, Center, Referee Huddle, Overtime, Safesmack, Kicking, and  Penalty."

A football word scramble is a game where a series of letters are provided in a scrambled order, and the goal is to rearrange those letters to form words related to football. Players need to unscramble the letters to identify the correct football-related terms, such as positions, equipment, or actions in the game. It is a fun and engaging activity that challenges players' knowledge and word-solving skills while connecting to the theme of football.

1. Tackle

2. Theme

3. Touchdown

4. Quarterback

5. Interference

6. Touchdown

7. Safety

8. Cornerback

9. Offhand

10. Aerial

11. Receiver

12. Completion

13. Receptionist

14. Center

15. Referee

16. Huddle

17. Overtime

18. Safesmack

19. Kicking

20. Penalty

Therefore, The correct answers are "Tackle, Theme, Touchdown, Quarterback, Interference, Touchdown, Safety, Cornerback, Offhand, Aerial, Receiver, Completion, Receptionist, Center, Referee, Huddle, Overtime, Safesmack, Kicking, and  Penalty."

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Telescopes have to have a good motorized drive system to move them quickly and smoothly so that they can continue to point at the object being observed.

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky. The original telescopes employed lenses, which were curved pieces of clear glass, to focus light. The ability of an optical telescope to gather light is its most crucial ability. This capability is solely dependent on the telescope's aperture, or the diameter of the clear objective.

The telescope has a motorized drive mechanism that drives it smoothly from east to west at precisely the same rate that Earth is rotating from west to east in order to maintain the telescope's pointing at the object being seen because Earth is revolving.

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Using the lens formula and magnification equation, we find that the position of the image relative to the lens is real and upright.

Object distance (u) = -6.0 cm (since the object is located to the left of the lens)

Focal length (f) = 3.0 cm

We have already determined that the position of the image relative to the lens is -6.0 cm.

Now, we calculate the magnification (m) using the formula:

m = -v/u

where:

v = image distance from the lens

Plugging in the values:

m = -(-6.0 cm) / (-6.0 cm)

m = 1

The positive magnification value (m = 1) indicates that the image is of the same size as the object.

Now, based on the magnification value and the position of the image, we can determine the nature and orientation of the image:

If the magnification (m) is positive and the image is formed on the same side as the object (left of the lens), the image is real and upright.

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The corresponding angle of refraction for the light from the floodlight that is transmitted into the water.

θ_B = arctan(n2/n1)

where n1 and n2 are the refractive indices of the two media involved, in this case, air and water. The refractive index of air is approximately 1, and the refractive index of water is approximately 1.33. Plugging these values into the equation, we can calculate the Brewster's angle for air-to-water reflection:

θ_B = arctan(1.33/1) ≈ 53.13 degrees

Therefore, the angle of reflection at which the light becomes completely polarized is approximately 53.13 degrees.

n1 * sin(θ_i) = n2 * sin(θ_r)

where n1 and n2 are the refractive indices of the two media, θ_i is the angle of incidence, and θ_r is the angle of refraction.

For this case, the angle of incidence is equal to the Brewster's angle (θ_B), which we calculated in part (a). Plugging the values into Snell's law, we can solve for the angle of refraction (θ_r):

1 * sin(θ_B) = 1.33 * sin(θ_r)

sin(θ_r) = sin(θ_B) / 1.33

θ_r = arcsine(sin(θ_B) / 1.33)

θ_r ≈ arcsine(sin(53.13°) / 1.33) ≈ 40.12 degrees

Therefore, the corresponding angle of refraction for the light that is transmitted into the water is approximately 40.12 degrees.

The corresponding angle of refraction for the light that is transmitted into the water can be calculated using Snell's law, similar to part (b). However, in this case, the light is traveling from water to air, so we need to consider the refractive indices of water and air:

n1 * sin(θ_i) = n2 * sin(θ_r)

where n1 and n2 are the refractive indices of the two media, θ_i is the angle of incidence, and θ_r is the angle of refraction.

For this case, the refractive indices are reversed compared to part (b). Plugging the values into Snell's law, we can solve for the angle of refraction (θ_r):

1.33 * sin(θ_i) = 1 * sin(θ_r)

sin(θ_r) = sin(θ_i) / 1.33

θ_r = arcsine(sin(θ_i) / 1.33)

Since the angle of incidence (θ_i) is equal to the Brewster's angle (θ_B), we can use the same value calculated in part (a):

θ_r = arcsine(sin(53.13°) / 1.33) ≈ 40.12 degrees

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On a wet road, you would need to adjust your speed to 5-10 mph slower than normal.So option a is correct.

On a wet road, you should adjust your speed to ensure that you can drive safely. This is because water causes tyres to lose traction with the road. If you increase your speed on a wet road, you'll have less control over your vehicle. When the road is wet, your vehicle's tyres may not be able to grip the road as well as they would on a dry road.When driving on wet roads, you should maintain a safe distance between your vehicle and the car in front of you. This provides you with enough space to stop safely if the car in front of you stops suddenly.In addition, when driving on wet roads, it's best to avoid sudden steering or braking movements. This will cause your car to skid. Therefore, you should slow down and move more gently on a wet road, and always adjust your speed to 5-10 mph slower than normal.Therefore option a is correct.

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The causes of change in equity can include several factors. Based on the information provided, the following causes of change in equity could apply:

Net Income: If the company earned a profit during the year, it would contribute to an increase in equity. Net income represents the revenue earned by the company minus its expenses, and it adds to the overall equity.

Share Issuance: If the company issued additional shares of stock during the year, it would result in an increase in equity. When new shares are issued and sold to investors, the company receives additional capital, which is reflected in the equity.

Dividends: If the company distributed dividends to its shareholders during the year, it would lead to a decrease in equity. Dividends are payments made to shareholders as a portion of the company's profits. Since dividends are distributed to shareholders, they reduce the retained earnings portion of equity.

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