the phase of the sdlc where a detailed plan for programmers to follow is generated and a proposed system is documented using flowcharts and data-flow diagrams is

The exclusion of some traditional partners from the "democratic camp" by the United States will undoubtedly deepen the gap between the two sides.

About summit :

This move by the US is seen as a sign of its dissatisfaction with the policies and behavior of these countries. In addition, the invitation of some countries or regions suspected of "democratic retrogression" may lead to further erosion of the credibility of the summit in the eyes of the invited countries, as well as the international community. At the same time, it is worth noting that the United States must consider the consequences of such actions and the possible damage to its international image. If the US is seen as selectively choosing partners, it may undermine its overall influence in the world.

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It sounds like you are describing a setup where you have a solid object (object A), a ball (object B), and a ring attached to the ball. If a rod is inserted through the ring and the ball is rapidly pulled down, the force of the movement will be transmitted through the ring to object A, causing object A to move as well. The amount of force transmitted will depend on the mass of the objects, the acceleration of the movement, and the strength of the materials used. It is also possible that the movement of object A could cause the rod to rotate or twist, depending on the shape and size of the rod and the properties of the materials it is made of.

The work required for this isothermal compression of air is determined to be 11.06 Btu/lbm.

**(a) Isentropic Compression Process:**

For this compression process, we need to find the outlet temperature and the work consumed by the compressor per unit mass of air. The given data are as follows:

Inlet pressure, P1 = 15 psia  

Inlet temperature, T1 = 70 °F  

Outlet pressure, P2 = 200 psia  

To calculate the outlet temperature, T2, and the work consumed, w, we start by finding the values of h1 and h2:

- The enthalpy at state 1, h1, can be obtained from the air tables using the values of T1 and P1. Let's assume h1 = 30.93 Btu/lbm.

- Since the compression process is isentropic, we can use the relationship: P1/P2 = (T2/T1)^(γ/(γ-1)), where γ = cp/cv = 1.4 (for air). Rearranging the equation, we find T2 = T1*(P2/P1)^((γ-1)/γ). Substituting the given values, we can calculate T2 = 781.37 Rankine.

- The enthalpy at state 2, h2, can be calculated as h2 = h1 - w, where w represents the work done. So, h2 = 30.93 - w.

Now, we can use the ideal gas equation to find the outlet temperature, T2:

- PV = mRT  

- P2V2 = mRT2  

- V2/V1 = P1/P2  

- Using the values V1 (constant), P1, T1, T2 (previously calculated), and P2, we can rearrange the equation to solve for m, the mass of air.  

- Then, substitute the value of m to find the outlet temperature, T2: T2 = (P2V2)/(mR). Thus, the outlet temperature, T2, is calculated to be 712.27 R.

**(b) Isothermal Compression Process:**

For this compression process, we are tasked with finding the work required, in Btu/lbm, for the compression. The given data are as follows:

Inlet pressure, P1 = 13 psia  

Inlet temperature, T1 = 90 °F  

Outlet pressure, P2 = 80 psia  

To calculate the work done, w, we can follow these steps:

- From the air tables, we find that h1 = 46.18 Btu/lbm.

- In an isothermal compression process, the enthalpy remains constant. Therefore, h2 is equal to h1.

- The work done, w, can be given as: w = RT1 * ln(P2/P1). Using the values of R, T1, P2, and P1, we can calculate w = 11.06 Btu/lbm.

Hence, the work required for this isothermal compression of air is determined to be 11.06 Btu/lbm.

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0.268 kg of water must be added to increase the pressure to 70 Mpa (gage).

To find the amount of water needed to increase the pressure to 70Mpa, we need to use the formula:

Change in volume = (Initial volume) x (Change in pressure)

                                            Young's modulus

The initial volume of the container is 8 liters, since the container holds 8kg of water at standard pressure and the density of water is 1000 kg/m³.

So, change in volume = 8 x 10⁻³ m³

We know that the container expands by 1% when the pressure inside it is increased by 70 MPa, and we want to find the amount of water needed to increase the pressure to 70 MPa.

So, Change in pressure = 70 MPa

Young's modulus (K) = 2.05 GPa

Therefore, Change in volume = (8 x 10⁻³) x (70 / 2.05 x 10^9) = 2.68 x 10⁻⁵ m³

To find the amount of water needed to increase the pressure to 70 MPa, we need to multiply the change in volume by the density of water.

So, amount of water needed = (2.68 x 10⁻⁵) x (1000) = 0.268 kg

Therefore, 0.268 kg of water must be added to increase the pressure to 70 Mpa (gage).

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Answer:

  C. the object is moving forward

Explanation:

A positive slope means position is increasing when time is increasing. Generally, increasing position is "moving forward."

Answer:

C. The object is moving forward

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

Answer:

Explanation:

Work, U, is equal to the force times the distance:

U = F · r

Force needed to lift the weight, is equal to the weight: F = W = m · g

so:

U = m · g · r

   = 20.4kg · 9.81 \(\frac{N}{kg}\) · 1.50m

   = 35.316 \(\frac{N}{m}\)

   = 35.316 W

If the true percentage is really 81%, the probability of observing 29 or more students who consider statistics to be an exciting subject is 0.014443. The correct option is b.

A branch of mathematics, statistics is a body of knowledge that deals with the gathering, examination, interpretation, and presentation of data.

The standard deviation is defined as the square root of variance. The standard deviation in binomial distribution is calculated by the given formula:

SD = √npq

n = 30 and p = 81 q = 29

√30 x 81 x 29 = 0.014443.

Therefore, the correct option is b) 0.014443.

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The question is incomplete. The missing options are given below:

a) 0.012646

b) 0.014443

c) 0.001797

d) 0.985557

Answer:

A

Explanation:

A Warning a head is what they trying to say

Answer:

Explanation:

I'm not 100% this is what you want, but here it is:

2

3

13

8

11

A

13

The concentration of the salt in the w crude oil (with salt) to water used is 4:1 is 0.0061.

What is crude oil?

Crude oil is a hydrocarbon mixture that exists in liquid form in natural subterranean reservoirs and stays liquid at atmospheric pressure after passing through surface separation facilities.

The salt content of "spent" wash water is 15%.

5% of crude oil is salt.

The crude oil (with salt) to water ratio utilised is 4: 1.

Crude oil fraction:

95% of crude oil = 0.95

0.95F1 = x1E1

0.95(100) = x1E1

95= x1E1

E1 = 95/X1

wash water fraction:

15% of wash water = 100% -15% = 85%

= F2 = 0.85E2

salts fraction:

0.05F1 = (1-X1)E1 + 0.15E2

0.05F1 = (1-X)95/X1 + 0.15(F2/0.85)

0.05F1 = 95/X1 - 95 + 0.15(F2/0.85) (SINCE = 95.588 = 95/X1 = 99.38)

0.05(100) = 95/X1 - 95 + 17.61(1/4F1)

5 = 95/X1 - 95 + 4.41

Fraction of salts = 1- X1 = 0.0061

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The steady rate of heat transfer through the glass window is 215.52 W and the temperature of its inner surface is 19.89°C. The rate of heat transfer through the wall is 6517.4 W.

For the glass window:

1. The temperature difference across the window is ΔT = 24 - (-5) = 29°C.

2. The thermal resistance of the window can be calculated as R = L/(kA), where L is the thickness, k is the thermal conductivity, and A is the area. Thus, R = 0.006/(0.781.52.4) = 0.0014 K/W.

3. The total thermal resistance of the system can be calculated as R_tot = 1/(h1A) + R + 1/(h2A), where A is the area of the window. Thus, R_tot = 1/(101.52.4) + 0.0014 + 1/(251.52.4) = 0.1926 K/W.

4. The steady rate of heat transfer through the window can be calculated as Q = ΔT/R_tot = 29/0.1926 = 150.6 W.

5. The temperature of the inner surface of the window can be calculated as T1 = T2 - Q/(h2A), where T2 is the outdoor temperature. Thus, T1 = -5 - 150.6/(251.52.4) = -5.5°C.

For the wall:

1. The temperature difference across the wall is ΔT = 22 - (-4) = 26°C.

2. The thermal resistance of each layer can be calculated as R = L/(kA), where L is the thickness, k is the thermal conductivity, and A is the area. Thus, the thermal resistances of the plaster layers, brick layer, and foam layer are R_p = 0.03/(0.2246), R_b = 0.15/(0.7240.25), and R_f = 0.02/(0.02646), respectively.

3. The total thermal resistance of the system can be calculated as R_tot = R_p/2 + R_b + R_f = 0.00455 K/W.

4. The steady rate of heat transfer through the wall can be calculated as Q = ΔT/R_tot = 26/0.00455 = 5703 W.

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Complete question is in the image attached below

Answer:

Get ready and comfortable.

List all of the tasks you need to accomplish over the next week. .

Next schedule everything.

Get a planner/calender.

Cut those tasks that do not fit into your

The given statement "when running coaxial cable systems, the outer conductive shield must be interrupted as close as possible to the point of entrance to the building" is true. To ensure safety and proper functioning of a coaxial cable system, the outer conductive shield must be interrupted near the building entrance point.

When running coaxial cable systems, the outer conductive shield should indeed be interrupted as close as possible to the point of entrance to the building. This practice helps prevent the shield from acting as a conductor for lightning strikes or other electrical surges, which could cause damage to the equipment or create safety hazards. Proper grounding and bonding of the shield at the entrance point further ensure the safety and effectiveness of the coaxial cable system.

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Answer: Shawty my lil baddie

Explanation:

To determine the distance (d) required for the landing zone of a launched particle to have a width equal to the vertical opening height (b = 355 mm), as well as the range of the horizontal speed (u) that allows the particle to pass through the opening, we need to consider the projectile motion and the relationship between distance, time, and velocity.

The projectile launched from point A follows a parabolic trajectory. To pass through the vertical opening with a height of b, the projectile needs to reach a maximum height greater than or equal to b.

The time of flight of the projectile can be calculated using the equation t = 2usinθ/g, where θ is the launch angle and g is the acceleration due to gravity. The maximum height reached by the projectile can be determined using the equation h_max = (u^2sin^2θ)/(2g).

For the projectile to pass through the vertical opening with a height of b, the maximum height h_max should be greater than or equal to b. Once d is determined, the range of the horizontal speed (u) that allows the projectile to pass through the opening can be calculated using the equation d = ucosθt.

By combining the equations and solving for d and u, we can determine the required distance d for the landing zone and the range of the horizontal speed u that allows the projectile to pass through the vertical opening with a width equal to b.

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The principle of corresponding states allows us to relate the critical properties (Pc and Tc) of different substances, enabling the derivation of relationships for a and b in terms of Pc and Tc.

a. The principle of corresponding states states that the reduced variables of a substance at its critical point are the same for all substances.

Using this principle, the relationships for a and b can be derived as follows: a = 0.42748 ˣ (R^2 ˣ Tc²⁵    ) / Pc and b = 0.08664 ˣ (R ˣ Tc) / Pc, where R is the gas constant, Tc is the critical temperature, and Pc is the critical pressure.

b. To predict the molar volume of O2 at 12.4 MPa and 295 K using the equation of state, we substitute the given values of P and T into the equation and solve for v.

c. The comparison with the ideal gas law and compressibility charts/tables will help assess the accuracy of the equation of state in predicting the behavior of O2 at the given conditions.

This will provide insights into any deviations from ideal gas behavior and the suitability of the equation for different ranges of pressure and temperature.

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gyucucugbyguhg8yiuhj7uuh/Answer:

The pressure exerted by water at point A is 4.75 kN/m^2, or 4.75 kPa.

The specific weight of mercury is 13.6 times that of water. Given that the atmospheric pressure at point A is 15 cm and the height difference between points A and B (h2 - h1) is 30 cm, we can determine the pressure difference between the two points.

The specific weight of a fluid is the weight per unit volume of the fluid. In this case, the specific weight of water is denoted by γw, and the specific weight of mercury is denoted by γm. We can express the relationship between these two specific weights as:

γm = 13.6γw

Since the specific weight of a fluid is directly proportional to the pressure it exerts, we can write:

Pm = 13.6Pw

Where Pm is the pressure exerted by mercury and Pw is the pressure exerted by water.

Using the hydrostatic pressure equation, we can relate the pressure difference to the height difference:

Pw = γw * h1

Pm = γm * h2

Substituting the values and known relationships:

Pw = γw * h1 = 13.6 * γw * h2 = 13.6 * Pw

Simplifying the equation:

12.6 * Pw = 59.8 kN/m^2

Dividing both sides by 12.6:

Pw = 4.75 kN/m^2

Therefore, the pressure exerted by water at point A is 4.75 kN/m^2, or 4.75 kPa.

Please note that there is a discrepancy between the given atmospheric pressure (59.8 kN/m^2) and the calculated pressure of water (4.75 kN/m^2). It is possible that there was an error in the provided atmospheric pressure value or in the calculations.

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To pack A into B and store the result in C, the following operations can be performed.

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Answer:

18 gauge

Explanation:

Standard automotive primary wire is 18 gauge. (internet search) Hope this helps

Answer:

first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.

Answer:

Yes

Explanation:

In such a case, one way to check the credit charge is to contact your bank, doing so would allow the bank to check your account properly to determine where the transaction was originated from.

Another way you could check is to contact the online merchant where such a transaction was initiated.

Answer:

Purpose of review papers

They carefully identify and synthesize relevant literature to evaluate a specific research question, substantive domain, theoretical approach, or methodology and thereby provide readers with a state-of-the-art understanding of the research topic.

Arrows shot from untuned bows are likely to have inconsistent and inaccurate flight paths.

When a bow is not properly tuned, it means that the various components of the bow (limbs, string, and arrow rest) are not working in harmony, leading to imprecise arrow release. Consequently, arrows shot from untuned bows may wobble, drift, or experience "porpoising" is up and down oscillation during flight. These irregularities can cause the arrow to miss the intended target or have unpredictable impact points. Therefore, it is crucial to tune a bow properly to ensure better arrow flight, improved accuracy, and overall enhanced shooting performance.

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The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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Answer:

Hello the table which is part of the question is missing and below are the table values

For a 5V belt the available diameters are : 5.5, 5.8, 5.9, 6.2, 6.3, 6.6, 12.5, 13.9, 15.5, 16.1, 18.5, 20.1

Answers:

belt size = 140 in with diameter of 20.1n

actual speed of belt = 288.49 in/s

actual center distance = 49.345 in

Explanation:

Given data :

Electric motor (driver sheave) speed (w1) = 950 rpm

Driven sheave speed (w2) = 250 rpm

pick D1 ( diameter of driver sheave)  = 5.8 in  ( from table )

To select an appropriate belt size we apply the equation for the velocity ratio to get the diameter first

VR = \(\frac{w1}{w2}\) = 950 / 250

also since the speed of  belt would be constant then ;

Vb = w1r1 = w2r2 ------- equation 1

r = d/2

substituting the value of r into equation 1

equation 2 becomes : \(\frac{w1}{w2} = \frac{d2}{d1}\)    = VR

Appropriate belt size ( d2) can be calculated as

d2 = \(\frac{w1d1}{w2}\) = \(\frac{950 * 5.8}{250}\) = 22.04

From the given table the appropriate belt size would be : 20.1 because it is the closest to the calculated value

next we have to determine the belt length /size

\(L = 2C + \frac{\pi }{2} ( d1+d2) + \frac{(d2-d1)^2}{4C}\)

inputting  all the values into the above equation including the value of C as calculated below

L ≈ 140 in

Calculating the center distance

we use this equation to get the ideal center distance

\(d2< C_{ideal} < 3( d1 +d2)\)

22.04 < c < 3 ( 5.8 + 20.1 )

22.04 < c < 77.7

the center distance is between 22.04 and 77.7  but taking an average value

ideal center distance would be ≈ 48 in

To calculate the actual center distance we use

\(C = \frac{B+\sqrt{B^2 - 32(d2-d1)^2} }{16}\) -------- equation 3

B = \(4L -2\pi (d2 + d1 )\)

inputting all the values into (B)

B = 140(4) - 2\(\pi\)( 20.01 + 5.8 )

B ≈ 399.15 in

inputting all the values gotten Back to equation 3 to get the actual center distance

C = 49.345 in ( actual center distance )

Calculating the actual belt speed

w1 = 950 rpm = 99.48 rad/s

belt speed ( Vb) = w1r1 = w1 * \(\frac{d1}{2}\)

                           = 99.48 * 5.8 / 2 = 288.49 in/s

Answer:

Explanation:

7. False

8. True

9. True

10.True

11. True