At 27 degrees Celsius, the rms speed of nitrogen molecules is roughly 515 m/s, which is faster than the sound speed in air.
How come we figure out rms velocity?The square root of the average of the square of the velocity is the root mean square velocity. It has velocity units as a result. As the particles in a typical gas sample are flowing in all directions, the average velocity for that sample is zero, which is why we use the rms velocity instead of the average.
The following formula determines a gas molecule's root mean square (rms) speed: v(rms) = √(3kT/m)
where T is the temperature in Kelvin, m is the molar mass of the gas in kg/mol, and k is Boltzmann's constant (1.38 10-23 J/K).
We must change the molar mass from g/mol to kg/mol in order to determine the rms speed of nitrogen molecules at 27 °C (300 °F):
m = 28.0 g/mol / 1000 g/kg = 0.028 kg/mol
Now we can plug in the values and solve for v(rms):
v(rms) = √(3kT/m)
v(rms) = √(3 × 1.38 × 10^-23 J/K × 300 K / 0.028 kg/mol)
v(rms) = 515 m/s (rounded to three significant figures)
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How does the number of fins affect energy transfer?
Answer:
Because the more coolant passed through the fins, the more energy can be emitted
Describe how the location of the oxygen molecules will change after the divider swings open.
Find the freezing point of the material and contrast it to that of other metals. Measure the metal's length and contrast it with the lengths of other metals. Also, contrast the metal's shape with those of other metals.
Which of the following best describes how heat energy flows in the concentrated solar layout?The air within the solar cooker receives energy from the water through the edges of the cook pot. The air outside solar cooker receives energy that is transferred from the gas within the solar cooker through sidewalls of the solar cooker.
What kind of energy is transferred in a solar cooker?Radiation is utilized to bake the s'mores in the hot cooker that is created in this exercise. When heat is transported without the presence of Sun and s'mores were in close proximity to one another Electromagnetic waves that are passing through the air convey the heat.
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A sample of 66 observations will be taken from an infinite population. The population proportion equals 0. 12. The probability that the sample proportion will be less than 0. 1969 is.
The likelihood that the sample percentage will be smaller than 0.1969 in accordance with the normal distribution is 0.9222 = 92.22%.
What kind of observation would this be?A simple sight may be seeing an apple drop from a tree. Another finding was that the goldfish primarily frequent a certain area of the water at morning. Another example of detection is the smell of decaying trash.
The metric X's z-score for a normal curve variable with a mean and standard deviation is provided by:
Z = X - μ / σ
The z-score computes the standard deviation of the measure's divergence from the mean.
The p-value for this z-score, which corresponds to the percentile of X, may be obtained by looking somewhere at z-score table.
Using the Fundamental Theorem, the polling distribution of the sample proportion for a percentage p in a subset n is roughly normal with mean = p and standard deviation \(s = \sqrt{\frac{P (1-P)}{n} }\) , if np & n (1 - p) are both more than 10.
The percentage and sample size for this issue are provided by:
p = 0.12, n = 66.
The mean and standard error are thus:
μ = p = 0.12
\(s = \sqrt{ \frac{0.12(0.88)}{66} }\)
The p-value for Z where X = 0. 1969 is the likelihood that the sample percentage will be smaller than 0. 1969, so:
Z = X - μ / σ
By the Central Limit Theorem:
Z = X - μ / s
Z = 0.1969 -0.12/ 0.04
Z = 1.92
Z = 1.92 has a p-value of 0.9222
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Suppose two objects attract each other with a gravitational force of 32000 Newtons. If the distance between the two objects is quartered (times 1/4).
then what is the new force of attraction between the two objects
The new force of attraction between the two objects will be 16 times the old case.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
\(\rm F =\frac{GmM}{r^2}\)
For case 1;
r₁=r
For case 2;
r₂=r/4
\(\rm F'=\frac{GmM}{(\frac{r}{4})^2} \\\\ F'=16 F\)
Hence,the new force of attraction between the two objects will be 16 times the old case.
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What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid
The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.
Magnetic field at the center of a solenoidThe magnetic field at the center of a solenoid is given by the following formula,
B = μ₀nI
where;
μ₀ is permeability of free space n is number of turnsI is current in the solenoidCurrent in the solenoidI = B/μ₀n
I = (0.00394) / (4π x 10⁻⁷ x 1580)
I = 1.98 A
Thus, the current required in the windings of the given long solenoid is 1.98 A.
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Which compound is an acid?
a. hydrogen sulfide.
b. water.
c. sodium hydroxide.
d. cannot be determined
Answer:
a. hydrogen sulfide.
if you stand on a bathroom scale, the spring inside the scale compresses 0.542 mm, and it tells you your weight is 728 n. now if you jump on the scale from a height of 1.06 m, what does the scale read at its peak?
The scale reads 764 N at its peak, which is slightly more than your weight of 728 N when you're just standing on it.
This is because the additional compression of the spring due to your jump adds some extra force. When you jump on the bathroom scale from a height of 1.06 m, the scale will read a higher value than 728 N at its peak. This is because the added kinetic energy from jumping will increase the force exerted on the scale, causing the spring to compress more than 0.542 mm. However, without knowing the spring constant, we cannot precisely determine the scale's reading at its peak.
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why would a bicycle fairing be helpful on a hand powered vehicle
Answer: AERODYNAMIC BENEFITS
Explanation: The reason why a bicycle fairing will be helpful on a hand powered vehicle is because the fairing design is very important that is a long and also sealed fairing provides the best compensation for the added weight. However,for road riding,a tailbox may actually will not be able to repay the weight penalty.
code talker: the first and only memoir by one of the original navajo code talkers of wwii
"Code Talker: The First and Only Memoir by One of the Original Navajo Code Talkers of WWII" is a book written by Chester Nez in collaboration with Judith Schiess Avila. It is an autobiography of the author and his experiences in World War II as a Navajo code talker.
The Navajo Code Talkers were an elite group of Navajo Marines who used their language to develop a code that could not be deciphered by the enemy. The Japanese had broken all American codes, so the Marines wanted to create an unbreakable code. The Navajo language, which had no written form, was the perfect solution. Navajo Code Talkers developed an intricate code that used their language's complex syntax, tonal qualities, and dialects. It proved to be the only code that the Japanese couldn't break.
The Navajo Code Talkers took part in every major Marine operation in the Pacific, from Guadalcanal to Okinawa. Chester Nez, the book's author, was one of the original Navajo Code Talkers. He was born in New Mexico in 1921 and was educated in a boarding school where he was forbidden from speaking his native Navajo language. Chester Nez was a U.S. Marine who was recruited in 1942 and became a part of the Navajo Code Talkers program. He was a member of the 382nd Platoon and served in the Pacific, where he worked as a radio operator.
Code Talker is about the Navajo Code Talkers, the Marine unit that used the Navajo language to develop an unbreakable code that played a crucial role in the U.S. victory over Japan in World War II. The book offers a first-hand account of what it was like to be a Navajo Code Talker during the war, as well as the impact that the code talkers had on the outcome of the war. Chester Nez provides an in-depth look at Navajo culture and history while telling his own personal story of growing up on the Navajo reservation and joining the Marine Corps.
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Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms, 314 K. The room serviced by unit A is kept at a temperature of 292 K, while the room serviced by unit B is kept at 298 K. The heat removed from either room is 4430 J. For both units, find (a), (b) the magnitude of the work required and (c), (d) the magnitude of the heat deposited outside for A and B conditioners respectively
Answer:
(a) 333.77 J
(b) 237.85 J
(c) 4763.77 J
(d) 4667.85 J
Explanation:
Temperature of source, TH = 314 K
Temperature of A, Tc = 292 K
Temperature of B, Tc' = 298 K
heat taken out, Qc = 4430 J
Let the heat deposited outside is QH and QH' by A and B respectively.
\(\frac{Q_H}{Q_c}=\frac{T_H}{T_c}\\\\Q_H = \frac{4430\times314}{292}=4763.77 J\)
Now
\(\frac{Q_H'}{Q_c}=\frac{T_H}{T_c'}\\\\Q_H' = \frac{4430\times314}{298}=4667.85 J\)
(a) Work done for A
W = QH - QC = 4763.77 - 4430 = 333.77 J
(b) Work done for B
W' = QH' - Qc = 4667.85 - 4430 = 237.85 J
(c) QH = 4763.77 J
(d) QH' = 4667.85 J
The spectra of most galaxies show redshifts. This means that their spectral lines Group of answer choices always are in the red part of the visible spectrum. have wavelengths that are longer than normal. have a higher intensity in the red part of the spectrum. have wavelengths that are shorter than normal.
have a higher intensity in the red part of the spectrum
Because of the Doppler effect, the spectra of most galaxies show redshifts. This means that their spectral lines Group of answer choices always are in the red part of the visible spectrum
Most galaxies' spectra have been redshifted, which means that their spectral lines are now pushed away from their normal or rest wavelengths and towards longer wavelengths. When an object travels away from an observer, the Doppler effect causes the shift phenomenon.
The Big Bang hypothesis and the concept of the expanding universe, show that galaxies are moving away from us, observed from the redshift lines.
The waves' apparent wavelengths shift as a result, changing the color of light waves or the pitch of sound waves.
Hence, because of the Doppler effect, the spectra of most galaxies show redshifts. This means that their spectral lines Group of answer choices always are in the red part of the visible spectrum.
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please answer this time question in do not send a link to an unknown website or you are getting reported.
(1) Use Newton's second law: The force F required to accelerate a mass m with acceleration a satisfies
F = m a
So the force needed to accelerate the lion-stretcher system is
F = (175 kg) (2 m/s²) = 350 N
(2) Average speed is defined as the ratio of distance traveled to the time it takes to travel that distance, so in this case the bus's average speed is
(280 km) / (4 h) = 70 km/h
(3) The vertical lines in the plot split up the distance function into 5-minute chunks. The one with the highest average speed is the one over which the distance changes the most. Roughly, the average speeds over each of the given choices is
• 0 to 5 min : (1500 m - 0 m) / (5 min) = 300 m/min
• 10 to 15 min : (3250 m - 2500 m) / (5 min) = 150 m/min
• 15 to 20 min : (3750 m - 3250 m) / (5 min) = 100 m/min
• 25 to 30 min : (4500 m - 4250 m) / (5 min) = 50 m/min
(4) Velocity is a vector, so it has both magnitude and direction. A car moving at constant velocity would be traveling at the same magnitude and direction. But a car on the circular track is constantly turning and changing direction.
suppose a 61.5 kg gymnast climbs a rope. what is the tension (in n) in the rope if he accelerates upward at a rate of 1.35 m/s2?
If he accelerates upward at a rate of 1.35 m/s², the tension in the rope is 83.03 N.
To find the tension in the rope, we need to use Newton's second law of motion which states that force is equal to mass multiplied by acceleration. In this case, the force is the tension in the rope, the mass is the mass of the gymnast, and the acceleration is the upward acceleration of the gymnast.
Tension = mass x acceleration
T = m x a
Substituting the given values, we get:
T = 61.5 kg x 1.35 m/s²
T = 83.03 N
Explanation: When the gymnast climbs the rope, he exerts a force on the rope, and the rope exerts an equal and opposite force on him. This force is the tension in the rope. According to Newton's second law of motion, this force is proportional to the mass of the object and the acceleration it experiences.
In this case, the tension in the rope is directly proportional to the mass of the gymnast and the acceleration at which he climbs. Therefore, we can use the formula T = m x a to find the tension in the rope.
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How many Magnesium atoms are in 10MgCl2?
The person above me is an idiot
Answer:
The correct answer is 10
Explanation:
10 times the singular magnesium which means: 10 times 1
There are 10 magnesium atoms in 10 MgCl₂ as depicted in the chemical formula.
What is an atom?
An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.
The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.
Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.
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The SI unit of refractive index is ___
a)km/s. b)m/s. c)sec. d)no unit
Answer:
d)no unit
Explanation:
refractive index is a unit less quantity.
ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
A 1.00-kg glider attached to a spring with a force constant 25.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = -2.80 cm (that is, the spring is compressed by 2.80 cm). (a) Find the period of the glider's motion. How does the period depend on the mass and the spring constant? Does it depend on the amplitude of oscillation? s (b) Find the maximum values of its speed and acceleration. speed m/s acceleration m/s2 (c) Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s2, and t is in s. Use the following as necessary: t.) x(t) = v(t) = a(t) =
Answer:
a) T = 1.26 s , b) v_max = 0.14 m / s , a_max = 0.7 m / s²
c) x = 0.028 cos (5 t) , v = - 0.14 sin 5t, a = - 0.7 cos 5t
Explanation:
This is a simple harmonic motion exercise that is described by the equation
x = A cos (wt +Ф)
with
w = √ (k / m)
let's apply this expression to our case
a) Angular velocity is related to frequency
w = 2π f
frequency and period are related
f = 1 / T
we substitute
2π / T = √ (k / m)
T = 2π √(m / k)
let's calculate
T = 2π √(1/25)
T = 1.26 s
In the expression for the period, the amplitude does not appear, therefore there is no dependence, as long as Hooke's law is fulfilled, which is correct for small amplitudes.
b) in the initial equation we have the position as a function of time, let's use the definition of speed and acceleration
v = dx / dt
v = - A w sin (wt + Ф)
the speed is maximum when the sine is -1
v_max = A w
w = √ (k / m)
w = √ 25/1
w = 5 rad / s
the amplitude of the movement is equal to the maximum compression of the spring
A = 2.8 cm = 0.028 m
we substitute
v_max = 0.028 5
v_max = 0.14 m / s
acceleration
a = dv / dt
a = - A w² cos (wt + Ф)
the acceleration is maximum when the cosine is -1
a_max = A w²
let's calculate
a_max = 0.028 5²
a_max = 0.7 m / s²
c) let's start by finding the phase constant
v = -A w cos (wt + Ф)
at t = 0 they indicate that the system has v = 0
0 = -A w sin (0 + Ф)
Ф = sin⁻¹ 0
Ф = 0
we write the equation
x = 0.028 cos (5 t)
v = - A w sin (wt + Ф)
v = - 0.028 5 sin (5t + 0)
v = - 0.14 sin 5t
acceleration
a = - A w² cos (wt + Ф)
a = - 0.028 5 2 cos (5 t + 0)
a = - 0.7 cos 5t
What is the acceleration of a 65 kg object pushed with a force of 500 newtons?
Answer:
7.69 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the force
m is the mass
From the question we have
\(a = \frac{500}{65} = 7.692307... \\ \)
We have the final answer as
7.69 m/s²Hope this helps you
nich
Imagine that two birds leave the
same tree at the same time. They
both fly at 10 km/h for 5 minutes.
Why don't they end up at the
same place?
Answer:
hello
Explanation:
a ball is thrown horizontally from the top of a building 100 m high. the ball strikes the ground at a point 200 m horizontally away from and below the point of release. what is the speed of the ball just before it strikes the ground?
V= 50.95m/s is the speed of the ball just before it strikes the ground for the given question
Given that
Height , h= 100 m
Horizontal distance , x = 200 m
Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.
In vertical direction :
vy^2=Uy^2+2gh
vy^2=0^2+2*9.81x100
Assume that g=9.81m/s^2
Thus
Vy^2=1962
Vy=√(1962) m/s
Vy=44.29 m/s
We also know that
Vy=Uy+gxt
44.29=9.81 x t
t=44.29/9.81
t=4.514s
In horizontal direction
x=Ux*t
Ux=200/4.514
Ux=44.30 m/s
Thus the resultant velocity
V= √ Vy^2+Ux^2
V=√44.29+44.30
V=50.95m/s
Therefore Velocity will be 50.95m/s
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Use the great circle distance calculation to determine the distance between the following two locations. Use 6378 km as the radius of the Earth and round your answer to the nearest whole km. Your answer must be within 10km of the correct answer to receive credit.
Location A: 75° Lat -128° Lon
Location B: -56° Lat -77° Lon
The distance between Location A and Location B, rounded to the nearest whole km, is approximately 16951 km calculated using the Haversine formula.
The great circle distance is the shortest distance between two points on the surface of a sphere, such as the Earth. To calculate the great circle distance between Location A and Location B, we can use the Haversine formula.
First, we need to convert the latitude and longitude from degrees to radians. The formula for converting degrees to radians is: radians = degrees * π/180.
For Location A:
Latitude = 75° * π/180 ≈ 1.3089969389957472 radians
Longitude = -128° * π/180 ≈ -2.230717410285017 radians
For Location B:
Latitude = -56° * π/180 ≈ -0.9773843811168246 radians
Longitude = -77° * π/180 ≈ -1.343903524035633 radians
Next, we can use the Haversine formula to calculate the great circle distance. The Haversine formula is:
distance = 2 * radius * arcsin(√(sin²((latitude2 - latitude1)/2) + cos(latitude1) * cos(latitude2) * sin²((longitude2 - longitude1)/2)))
where radius is the radius of the Earth, which is given as 6378 km.
Substituting the values into the formula, we get:
distance = 2 * 6378 * arcsin(√(sin²((-0.9773843811168246 - 1.3089969389957472)/2) + cos(1.3089969389957472) * cos(-0.9773843811168246) * sin²((-1.343903524035633 - (-2.230717410285017))/2)))
After evaluating the formula, the calculated distance between Location A and Location B is approximately 16951 km.
Therefore, the distance between Location A and Location B, rounded to the nearest whole km, is approximately 16951 km.
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You are at a 4-way stop, and it is your turn to go. However, the car across from you starts to go. Explain.
The other cars across from you go first because you are at a traffic light and your light is red and their light is green.
Or
Since they are across from you both of you are going straight so he can go first
Hope this helps! : )
What is the phase of the moon during a total solar eclipse?
Answer:
The moon should be in the New phase.
Explanation:
Based on your investigations with the same in the energy token model which of the following statements is the most accurate claim
A. increase carbon dioxide or methane makes more sunlight into earth system.
B. increased carbon dioxide or methane, hold energy in the atmosphere permanently.
C. increase carbon dioxide or methane redirect, some energy that was leaving back to the earth surface.
The Energy Internet Foundation owns the cryptocurrency known as the Energy Internet Token. Building accessible operating systems of energy grids that can support a zero-carbon economy is the focus of the Energy.
Correct option is, C.
What stores sell energy Web tokens?On CoinMarketCap, look up Energy Web Token. Press the "Trade" button next to the price chart. In this view, you will discover a full list of stores where you can purchase Energy Web Token, in addition to the currencies you can do so with.
What will EWT cost in the future?The price for Energy Web Tokens is anticipated to increase by 570.81% inside the best case situation by 2026 based on our assessment of the expansion of the IT industry, which places the estimated price of EWT between $5.19 and $ 27.02.
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A linear elastic spring can be compressed 10.0 cm by an applied force of 5.0 N. A 4.5 kg crate of apples, moving horizontally at 2.0 mis collides with the spring. What will be the maximum compression of the spring?
A 4.5 kg crate of apples, moving horizontally at 2.0 m is collides with the spring, the maximum compression of the spring is 0.6 m or 60 cm.
In order to find out the maximum compression of the spring, we need to use the law of conservation of energy. When the crate collides with the spring, its kinetic energy will be transferred to the spring and the spring will compress until it reaches its maximum point.
The maximum compression of the spring can be determined by calculating the work done by the kinetic energy of the crate and equating it to the elastic potential energy stored in the spring.
Calculate the initial kinetic energy of the crate: KE = 1/2 * m * v²
where m = mass of the crate = 4.5 kg
v = velocity of the crate = 2.0 m/s
KE = 1/2 * 4.5 kg * (2.0 m/s)² = 9.0 J
Calculate the spring constant of the spring: k = F/x
where F = force required to compress the spring by a distance of x = 5.0 N and x = 10.0 cm = 0.1 m
k = 5.0 N / 0.1 m = 50 N/m3.
Calculate the maximum compression of the spring: KE = 1/2 * k * x²
where x = maximum compression of the spring
9.0 J = 1/2 * 50 N/m * x²x² = (2 * 9.0 J) / 50 N/mx² = 0.36 mx = √(0.36 m) = 0.6 m
Therefore, the maximum compression of the spring is 0.6 m or 60 cm.
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a 1 -mm diameter wire is made up of a 3- m steel wire connected end to end to a 2-m copper wire if the tension in the wire is 100 n, what is the speed of a transverse wave on this wire
A 1-mm diameter wire is made up of a 3-m steel wire connected end to end to a 2-m copper wire. If the tension in the wire is 100 N, The speed of a transverse wave on this wire is 202 m/s
The speed of a transverse wave on the wire can be found using the formula:
v = √(T/μ),
where v is the speed of the wave, T is the tension in the wire, and μ is the linear density of the wire.
The linear density of the wire can be found by adding the linear densities of the steel and copper wires:
μ = μsteel + μcopper = (3 m)(π/4)(0.001 m)²(7850 kg/m³) + (2 m)(π/4)(0.001 m)²(8900 kg/m³)
μ = 0.0188 kg/m
Plugging in the values for T and μ, we get:
v = √(100 N/0.0188 kg/m)
v ≈ 202 m/s
Therefore, the speed of a transverse wave on the wire is approximately 202 m/s.
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What is the work done in stretching a spring by a distance of 0.5 [m] if the restoring force is 48 [n] ?
The work done in stretching springs is 12 joules.
We need to know about the work on stretching springs to solve this problem. Work can be determined by how much potential energy on springs changes
W = ΔPE
W = 1/2 . k . (Δx)²
where W is work, PE is potential energy, k is spring constant and x is position.
Work also depends on the restoring force which has formula
F = k . Δx
Hence, by substituting force we can use this formula
W = 1/2 . F . Δx
From the question above, we know that:
Δx = 0.5 m
F = 48 N
By substituting the parameter, we get:
W = 1/2 . F . Δx
W = 1/2 . 48 . 0.5
W = 12 Joule
Hence, the work done in stretching springs is 12 joules.
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As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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What statement about energy transfer in a wave is true?
Answer:
Energy moves between the particle of the medium.
Explanation:
The best way to know if a force is applied on an abject is if the object:
A. Doesn’t move
B. moves
C. Distorts shape in some way
Other: