Answer:
133.33J/kg°C
Explanation:
Given parameters:
Mass = 5kg
Temperature change = 3°C
Thermal energy = 2000J
Unknown:
Specific heat of the block = ?
Solution:
To find the specific heat capacity, use the formula below;
H = mCФ
where H is amount of heat
m is the mass
C is the specific heat capacity
Ф is the temperature change
Input the parameters and solve;
2000 = 5 x C x 3
C = \(\frac{2000}{15}\)
C = 133.33J/kg°C
If a car can exert 2000N of force to move a trailer 50 m is 20 seconds how much power did the car use?
Answer:
5000 W
Explanation:
Applying,
P = W/t................. Equation 1
Where P = Power, W = work done by the car, t = time.
But,
W = F×d ............. Equation 2
Where F = Force, d = distance
Substitute equation 2 into equation 1
P = (F×d)/t.............. Equation 3
From the question,
Given: F = 2000 N, d = 50 m, t = 20 seconds.
Substitute these values into equation 3
P = (2000×50)/20
P = 5000 W
A spaceship with a constant speed of 0. 800c relative to earth travels to a star that is 4. 30 light-years from earth. how much time for this trip would elapse on a clock on board the spaceship?
The answer is time for this trip would elapse on a clock on board the spaceship is \(1.02 \times 10^{8} secends\)
\(V_{0}=0.800 \mathrm{C}\)
Distance from Earth (x)=4.30 light-years
Time req. to do in earth frame of reference \($=\frac{4.30 \text { light years }}{0.800 \mathrm{c}}$\)
\($=\frac{4.3 \times 9.46 \times 10^{15} \mathrm{M}}{0.8 \times 3 \times 10^{8} \mathrm{~m} / \mathrm{s}}$\)
\($=1.695 \times 10^{8}$\) seconds
proper time = Time in earth's reference\($\sqrt{1-\frac{v^{2}}{C^{2}}}$\)
\(=1.698 \times 10^{8} \times 0.6=1.02 \times 10^{8} secends\)
What is Space contraction?
The contraction of space is a notion presented in spatial relativity in which an object's distance travelled when moving at a percentage of the speed of light is smaller than that measured by an observer in an inertial reference frame \(\mathrm{x}_{0}=\mathrm{x} \times \sqrt{1-\frac{\mathrm{v}^{2}}{\mathrm{c}^{2}}}\)Lorentz-FitzGerald contraction, also known as space contraction, is the shortening of an object in the direction of its motion relative to an observer in relativity physics.To learn more about Space contraction visit:
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Which of the following statements best describes a difference between
nuclear fission and nuclear fusion reactions?
Nuclei gain electrons during fission and release electrons during fusion.
Fission generates potential energy, and fusion generates kinetic energy.
С
C
Heavy nucleus split during fission and two light nuclei bind together during
fusion.
O
Fission forms heavier elements, and fusion forms lighter elements.
Answer:
C
Heavy nucleus split during fission and two light nuclei bind together during
fusion.
What makes carbohydrates good at storing energy?
After we eat, our glucose levels rise when carbohydrates are fully broken down. This alarms beta cells (in the pancreas) to release insulin into our bloodstream and altogether insulin allows the glucose to enter our cells and be utilized for energy. Some carbs are used for energy and the rest is stored as fat!
Hope I helped in some way :)
PLEASE HELP
Fill in the blanks to correctly complete the statement.
The motion of an object moving with uniform circular motion is always_______
to the circle, so the speed of an object moving in a circle is known as _______
speed.
Answer:
The first one is tangent, second is tangential.
Is visible light a form of
radiation? Explain.
Answer:
Yes,in fact visible 'light' is a form of radiation, which can be defined as an energy that travels in the form of electromagnetic waves. It can also be described as a flow of particle-like 'wave-packets', called photons, that travel constantly at the speed of light (about 300 000 kilometres per second).
Explanation:
If you know the answer please answer the following question down in the picture below.
Collision 1: Blue Cart Initially at Rest Set the initial blue cart velocity to 0 m/s. Set the mass values to different values. Run the simulation and record the mass and velocity values. Before Collision After Collision mRed = _________ kg mBlue = _________ kg Use mass and velocity values to complete the following momentum table. Before Collision After Collision ∆Momentum Red Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s Blue Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s
Answer:
it is very hard but i am trying to help you.
Explanation:
A metal wire, initially 1.000m long, extends by 4mm when a loaded of 2N is added to it. What will the length of the wire be if a further 3N is added, assuming it does not extend beyond its limit of proportionally?
Explanation:
you should first find the proportionality constant or the spring constant(as we see it as a spring).the find the value of x so that the force is 3N
David drove the first 6 hours of his journey at 65 km / hour and the last 3 hours of his journey at 80 km / hour . How far is the whole journey in km ?
Answer:
630 km.
Explanation:
To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.
Case 1:
Speed 1 (S₁) = 65 km / hour
Time 1 (t₁) = 6 hours
Distance 1 (d₁) =?
Speed = Distance /time
S₁ = d₁ / t₁
65 = d₁ / 6
Cross multiply
d₁ = 65 × 6
d₁ = 390 Km
Case 2:
Speed 2 (S₂) = 80 km / hour
Time 2 (t₂ ) = 3 hours
Distance 2 (d₂) =?
Speed = Distance /time
S₂ = d₂ / t₂
80 = d₂ / 3
Cross multiply
d₂ = 80 × 3
d₂ = 240 Km
Finally, we obtained the total distance travelled by David as follow
Distance 1 (d₁) = 390 Km
Distance 2 (d₂) = 240 Km
Total Distance travelled (dₜ) =?
Total distance = distance 1 + distance 2
dₜ = d₁ + d₂
dₜ = 390 + 240
dₜ = 630 km
Therefore, the total distance travelled by David is 630 km
Read the following paragraph from the introduction
[paragraphs 1-4].
Energy cannot be created or
destroyed, meaning that the total
amount of energy in the universe has
always been and will always be
constant. However, this does not mean
energy is unchangeable. It can change
form and even transfer between
objects.
Which answer choice BEST supports the idea that
energy remains constant during an energy
transformation?
The statement 'energy cannot be created or destroyed' BEST supports the idea that energy remains constant during an energy transformation. It is the first law of thermodynamics.
Law of Conservation of EnergyThe law of conservation of energy, also known as the first law of thermodynamics, indicates that energy can neither be created nor destroyed.
According to this law, the energy can be interchanged from one type of energy (e.g., kinetic energy) form to another (e.g., potential energy).
The first law of thermodynamics is fundamental for understanding major science disciplines, and it is a rosetta stone in physics.
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RNA is ______________________stranded. It _______________ leave the nucleus, unlike DNA. It still consists of __________________, however the _____________ in the backbone of the strand is different than in DNA.
The nitrogenous bases are different in RNA; instead of Thymine, Adenine now pairs with _____________________.
Answer:
See below
Explanation:
RNA is single-stranded. It does leave the nucleus, unlike DNA. It still consists of strands, however, the ribose in the backbone of the strand is different than in DNA.
The nitrogenous bases are different in RNA; instead of Thymine, Adenine now pairs with Cytosine.
PLEASE ANSWER ILL GIVE BRAIN!!!
Answer:
what's the question?........
Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across the yard in 12 s? Round your answer to the nearest whole number.
It takes
J of work to get the wheelbarrow across the yard.
Answer:
9600
Explanation:
Answer:
Hey... your answer is 9,600
Explanation:
Hope this helps :)
Here is prove just in case...
Best of luck <3
during which of piaget's stages of sensorimotor development does adaptation first occur?
According to Piaget's theory of cognitive development, adaptation first occurs during the sensorimotor stage, specifically in the substage called the "circular reactions" stage.
This stage occurs between the ages of 8 to 12 months. During this period, infants engage in repetitive actions to explore and interact with their environment.
They begin to adapt their behaviors based on the responses they receive from their actions. The circular reactions involve repetitive behaviors that serve a purpose, such as shaking a rattle to hear the sound.
Through these actions, infants start to develop a basic understanding of cause and effect relationships and adapt their behaviors to achieve desired outcomes.
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you have two vectors. one has a magnitude of 1.8 cm and an angle of 75.0 while the other has a magnitude of 3.8 cm at an angle of 36.8 . both angles are measured counterclockwise from the positive x-axis. what direction (as an angle counterclockwise from the positive x-axis in degrees) does the sum of these two vectors point?
The sum of the two vectors points in a direction of approximately 52.4°. This angle is measured counterclockwise from the positive x-axis.
To find the direction of the sum of the two vectors, we first need to calculate their individual components. For Vector A with magnitude 1.8 cm and angle 75.0°, we have Ax = 1.8*cos(75) and Ay = 1.8*sin(75). For Vector B with magnitude 3.8 cm and angle 36.8°, we have Bx = 3.8*cos(36.8) and By = 3.8*sin(36.8). Now, sum up the x and y components: Rx = Ax + Bx and Ry = Ay + By. Calculate the angle between the resultant vector (Rx, Ry) and the positive x-axis using the formula: θ = atan(Ry/Rx). Thus, the sum of these two vectors points in a direction of approximately 52.4° counterclockwise from the positive x-axis.
Calculation steps:
1. Calculate Ax: 1.8*cos(75) ≈ 0.467
2. Calculate Ay: 1.8*sin(75) ≈ 1.742
3. Calculate Bx: 3.8*cos(36.8) ≈ 3.057
4. Calculate By: 3.8*sin(36.8) ≈ 2.194
5. Calculate Rx: 0.467 + 3.057 ≈ 3.524
6. Calculate Ry: 1.742 + 2.194 ≈ 3.936
7. Calculate θ: atan(3.936/3.524) ≈ 0.914 radians (52.4°)
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True or false question scientists can predict when an earthquake will occur
Answer:
False
Explanation:
Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.
which are cardiovascular drug classes? select all that apply
Cardiovascular drug classes are Beta-blockers, Diuretics, Calcium channel blockers, and ACE inhibitors. The correct answer is options are A, B, D, and F.
Cardiovascular drug classes refer to categories of medications specifically designed to treat conditions related to the cardiovascular system. These medications target various aspects of cardiovascular health, such as blood pressure regulation, heart rhythm management, and the prevention of clot formation. Several recognized cardiovascular drug classes include:A) Beta-blockers: These drugs block the effects of adrenaline on the heart and blood vessels, reducing heart rate and blood pressure.B) Diuretics: Also known as water pills, diuretics help eliminate excess fluid from the body, reducing fluid buildup and decreasing blood pressure.D) Calcium channel blockers: These medications relax and widen blood vessels, improving blood flow and reducing blood pressure. They also help regulate heart rate.F) ACE inhibitors: ACE (angiotensin-converting enzyme) inhibitors lower blood pressure by blocking the production of a hormone that narrows blood vessels.Therefore, the correct options for cardiovascular drug classes are A) Beta-blockers, B) Diuretics, D) Calcium channel blockers, and F) ACE inhibitors. These medications play crucial roles in managing cardiovascular conditions and promoting overall heart health.For more questions on the cardiovascular system
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The correct question would be as
Which of the following are cardiovascular drug classes? Select all that apply.
A) Beta-blockers
B) Diuretics
C) Antibiotics
D) Calcium channel blockers
E) Antidepressants
F) ACE inhibitors
A pendulum is made of a rod of mass 1.7 kg and length 2.8 m whose moment of inertia about its center of mass is 1/12M L2 and a thin cylindrical disk of mass 1.5 kg and radius 1.8 m whose moment of inertia about its center ofmass is 1/2M R2. What is the moment of inertia of the pendulum about the pivot point? Answer in units of kg · m2
The answer is I = 9.24kgm².
Solution:
\(I = \frac{ML^{2} }{I2} +M(\frac{L}{2}) +mR^{2} +ml^{2}\)
\(= \frac{ML^{2} }{3} +\frac{mR^{2} }{2} +mL^{2}\)
\(= \frac{1*2.8^{2} }{3} + \frac{1.5 *1.8^{2} }{2} +1.5 *2.8\)
= 2.61 + 2.43 + 4.2
= 9.24 kgm².
It is sometimes called a bob because its vertical position rocks up and down and its lateral movement moves left and right. A pendulum cord is attached to overhead support via a pivot point. A pivot could simply be a knot that ties the string to the ceiling hook. A compound pendulum is an object composed of a collection of particles or continuous shapes that rotate tightly around a pivot. Its moment of inertia is the sum of the moments of inertia of each particle that composes it.
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Describe two instruments or methods that can be used to determine the speed of an object. Be sure to describe how the tool or tools are used to get a value for the speed.
How could the speed value determined to be converted to a velocity value?
The instruments used to determine the speed of the object are a speedometer and a tachometer.
A speedometer, an instrument that indicates the speed of a vehicle/object, is usually combined with a device called an odometer that records the distance traveled. Gear motion produces a current that is directly proportional to the speed of rotation of the gear. A computer chip processes the current and converts it into a number corresponding to the speed of travel (miles or kilometers per hour).
A speedometer is a counting device. Used to indicate the revolutions per minute (RPM) of an aircraft engine. This instrument has a typical measurement accuracy of ±0.5% and is widely used as an automobile speedometer and aircraft engine speedometer.
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I need to find the total mechanical energy. I think the first one is correct but the second one is wrong
Answer:
di ko po alam ang sagot baka
po pang grade 9 po yan
Explanation:
sana po magets nyo po
two loudspeakers, one with a power of 100 w and the other with a power of 200 w, are playing simultaneously in a room. if you stand 2.0 m away from each speaker what intensity of sound will you hear in db? a)
To determine the sound intensity in decibels (dB) at a certain distance from the speakers, we can use the formula for sound intensity level:
L = 10 log10(I/I0)Where L is the sound intensity level in dB, I is the sound intensity, and I0 is the reference intensity (usually taken as the threshold of hearing, which is 1.0 x 10^-12 W/m^2).
First, we need to calculate the sound intensity at the specified distance from each speaker using the formula:
I = P/(4πr^2)Where I is the sound intensity, P is the power of the speaker, and r is the distance from the speaker.
For the first speaker with a power of 100 W and a distance of 2.0 m:
I1 = 100/(4π(2.0)^2) = 3.98 W/m^2For the second speaker with a power of 200 W and a distance of 2.0 m:
I2 = 200/(4π(2.0)^2) = 7.96 W/m^2Next, we can calculate the sound intensity level (L) at the specified distance using the formula mentioned earlier:
L = 10 log10(I/I0)For the first speaker:
L1 = 10 log10(3.98/1.0 x 10^-12) ≈ 129 dBFor the second speaker:
L2 = 10 log10(7.96/1.0 x 10^-12) ≈ 132 dBSince the two speakers are playing simultaneously, the total sound intensity at the specified distance is the sum of the intensities from each speaker:
lTotal = I1 + I2 = 3.98 + 7.96 = 11.94 W/m^2The total sound intensity level (Ltotal) can be calculated using the same formula:
Ltotal = 10 log10(Itotal/I0) = 10 log10(11.94/1.0 x 10^-12) ≈ 140 dBTherefore, at a distance of 2.0 m from each speaker, you would hear a sound intensity of approximately 140 dB.
About decibelsThe decibel is a unit for measuring sound intensity. One decibel is equivalent to one tenth of a bel. The "B" in dB is capitalized because it is part of the name of its inventor, Bell. The decibel is also a logarithmic unit for describing a ratio. The unit of measurement for sound noise is the decibel (dB). The higher the sound noise, the higher the decibel size. Sound that has a high decibel has the possibility of causing damage to the ear.
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What is the relationship between wavelength and frequency Mcq?
The equation =c/f relates wavelength and frequency. There is an inverse relationship between wavelength and frequency.
What connection exists between the frequency and wavelength of EM waves?
One crucial equation connects them all: The speed of light is equal to the frequency times the wavelength of any electromagnetic wave. If we know the other measurement, we can use this connection to calculate the wavelength and frequency of the any electromagnetic wave.
What is a wavelength differs from a frequency in ways?The distance between the crests of two waves is known as the wavelength, which also applies to troughs. The number of vibrations that pass across a certain area in a second is the frequency, which is expressed in seconds per cycle (Hz) (Hertz). This article discusses how wavelength and frequency relate to one another.
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DLite Dry Cleasers is owned and operatod by Joel Paik. A buidng and ecuipment are curtently Eeng reieed, pencting expansoon fo new facities The actiat werk durng dwy an w4frraxieed as folown. b. Pas 150000 for the purshase of land adjacent to land currentty owned by DL he Dry Cleaners as a kute buitsing site 6. Recelied casb from cistomars fot tory deaning fevenue. $34.125 if Paid rent for to month, 56 co9 e: Puichaned aupplies of account, 62,600 1. Paid creators on acoount st2 800 . a. Charbed eublomen for dre deatina revenue on account sH4.750. a Charged culfomers for dry cleaning rovenue on acooumt, $34.750. In. Fiece, ed mantefy nocice for dry clessng expense lor July (to be paid on August 10), $29,500. I Recoviad each form customorn on acoount, 568000 4. Detemined that the cest of supples on hand was $5,900; therofore. the cost of sipples used duting the month was 33.600 1 Pais dividends, $12000, Reauired; 1 Detemine the amount of fetaned compgs as of Juy 1,20rd. bebiw the equation, indicate increases and deeresses resulting fom cach transaction and the new balancos affer each transachion. 3.a Reare an boome atakenent tor the mantm endod Juy 31.20YA. 1. Pad ovisends, s12:000. Required: 4. Prepare a tatmentof cad inws tor duy.
To determine the new retained earnings as of July 31, 20rd, we can use the given information:
Retained earnings, July 1, 20rd: $259,725
Increases: Net income (Part B) = $10,325
Decreases: Dividends (Part C) = $12,000
The calculation for new retained earnings, July 31, 20rd would be:
Retained earnings, July 31, 20rd = Retained earnings, July 1, 20rd + Increases - Decreases
Retained earnings, July 31, 20rd = $259,725 + $10,325 - $12,000
Retained earnings, July 31, 20rd = $258,050
Therefore, the new retained earnings as of July 31, 20rd is $258,050.
The statement of cash flows for July would be as follows:
Statement of Cash Flows for July
Cash flows from operating activities:
Cash inflows:
Cash from customers $68,000
Cash outflows:
Payments for rent $(5,600)
Payments for supplies $(62,600)
Payments to creditors $(12,800)
Payments for utilities $(4,750)
Net cash flows from operating activities $(17,750)
Cash flows from investing activities:
Cash outflows:
Purchase of land $(150,000)
Net cash flows from investing activities $(150,000)
Net increase (decrease) in cash $(179,750)
Plus: Cash balance, July 1, 20rd $294,000
Cash balance, July 31, 20rd $114,250
Please note that the information provided assumes a cut-off date of July 31, 20rd.
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Please help me I swear will mark you brainiest
Answer:
C
Explanation:
please mark as brainliest
A traffic signal is supported by two cables, each of which makes an angle of 34.0 degrees with the vertical. If each cable can exert a maximum force of 675 N, what is the largest weight they can support?
The largest weight each of the cable can support if they make an angle of 34 degree to the vertical, with a maximum force of 675 N acting and each is 599.6 N.
What is weight?
Weight can be defined as the gravitational pull of a body.
To calculate the largest weight, we use the formula below.
Formula:
W = Fcos∅............. Equation 1Where:
W = largest weight F = Maximum force∅ = angleFrom the question,
Given:
F = 675 N∅ = 34 degreeSubstitute these values into equation 1
W = 675cos34°W = 599.6 NHence, the largest weight they can support is 599.6 N.
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a scaffold of mass 60 kg and length 5.0 m is supported in a horizontal position by a vertical cable at each end. a window washer of mass 80 kg stands at a point 1.5 m from one end. what is the tension in (a) the nearer cable and (b) the farther cable?
(a) The tension in the nearer cable is 941 N, and (b) the tension in the farther cable is 1373 N.
We need to find the tension in both the nearer and farther cables supporting the scaffold with a window washer on it.
a) To find the tension in the nearer cable, we must first calculate the total torque acting on the system, keeping in mind that the torque must be zero for the system to be in equilibrium. The torque contributions are:
1. The torque due to the window washer's weight (80 kg * 9.81 m/s²) acting at a distance of 1.5 m from the nearer cable.
2. The torque due to the scaffold's weight (60 kg * 9.81 m/s²) acting at the midpoint of the scaffold, which is 2.5 m from each cable.
Now, we can set up the torque equation:
T_near * 5.0 m = (80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)
Solve for T_near:
T_near = ((80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)) / 5.0 m
T_near ≈ 941 N
b) To find the tension in the farther cable, we can use the fact that the sum of the tensions in both cables must equal the total weight of the system (scaffold + window washer):
T_far + T_near = (80 kg + 60 kg) * 9.81 m/s²
Solve for T_far:
T_far = (140 kg * 9.81 m/s²) - T_near
T_far ≈ 1373 N
Therefore, the tension in the nearer cable (a) is approximately 941 N, and the tension in the farther cable (b) is approximately 1373 N.
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Calculate the amount of extension of a spring with a spring constant of 3 kN/m, if the amount of work done in extending it is 35 N. Give your answer in m.
The extension of the spring is 4.83 m, if work done is 35 Newton and spring constant is 3 k N/m.
The spring constant, k, is a measure of the stiffness of the spring. it's far one of a kind for unique springs and materials. the larger the spring regular, the stiffer the spring and the greater.
Spring constant of 3 k N/m,
The amount of work done in extending is 35 N
WORK DONE by spring force = 1/2 k X²
⇒0.5 * 3 * X²
35 N = 0.5 * 3 * X²
X² = 35/1.5
x = \(\sqrt{23.33}\)
X = 4.83 m
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The extension of the spring is can be found out by using the Work Done due to extension in Spring Constant K. The extension in the spring is 4.83m.
The spring constant, k, is a measure of the stiffness of the spring. It is for springs and materials which measures the ratio of force that affects the spring and the displacement caused by the force action.
Spring constant depends on the stiffness of the spring, wire thickness, number of turns in wound coil, length of spring and diameter of the coil.
Given:
Spring constant = 3000 N/m
Work Done in extension= 35 N
Let the extension in spring by x.
∴ Work Done by spring force = 1/2 kx²
Work done = 0.5 × 3 × x²
⇒ 35 N = 0.5 × 3 × x²
⇒ x² = 35/1.5
⇒ x = 4.83m
Hence, the extension of spring is 4.83m.
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a model can represent an object, system, or process. why do all models have limitations? 7.n.3.2 group of answer choices because a model includes every factor that affects it because a model is never exactly the same as the thing it represents because all models are two-dimensional because a model is smaller than the thing it represents
All models have limitations because a model is never exactly the same as the thing it represents.
While a model can be used to represent an object, system, or process, it is a simplified version of the real thing and may not include every factor that affects it.
Additionally, all models are limited by their size and dimensions, which can impact their accuracy and usefulness.
Therefore, it is important to recognize the limitations of a model and use it appropriately to gain insights and understanding.
A model can represent an object, system, or process, but all models have limitations primarily because a model is never exactly the same as the thing it represents.
Hence, Models are simplifications and abstractions of reality, and as such, they may not include every factor that affects the real-world object, system, or process.
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A copper wire has a circular cross section with a radius of 1.75 mm.(a) If the wire carries a current of 3.40 A, find the drift speed of the electrons in the wire. (Assume the density of charge carriers (electrons) in a copper wire is n = 8.46 1028 electrons/m3.)......... m/s(b) All other things being equal, what happens to the drift speed in wires made of metal having a larger number of conduction electrons per atom than copper? Explain
(a) The drift velocity of the electrons in the wire is 0.00202 m/s. (b) Drift speed in wires made of metals having a larger number of conduction electrons per atom than copper
(a) Given that radius, r = 1.75 mm = 1.75 x 10^(-3) m, Current, I = 3.4 A, Resistivity of copper, ρ = 1.68 x 10^(-8) ohm-m, Density of electrons, n = 8.46 x 10^(28) electrons/m^3. The formula used to calculate drift velocity,
v_d = I/nAe
Where, A = πr^2 is the area of the cross-section of the wire, and e = 1.6 x 10^(-19) C is the charge on an electron.
Substituting the given values,
v_d = I/nAe
= 3.4/(8.46 x 10^(28) x π x (1.75 x 10^(-3))^2 x 1.6 x 10^(-19))
= 0.00202 m/s
Therefore, the drift velocity of the electrons in the wire is 0.00202 m/s.
(b) The drift velocity of electrons is related to the density of charge carriers (electrons) in the material. Metals having a larger number of conduction electrons per atom than copper have a higher density of electrons. Hence, in such metals, the drift velocity of electrons is higher than in copper as the higher density of electrons provides more opportunities for the free electrons to collide with each other, leading to an increase in the drift speed of the electrons.
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