there is an equilateral triangle with sides 2 meters in length. at one of the points is a 1 microcoulomb charge, at the second point there is a 2 microcoulomb charge, and at the third point there is a 3 microcoulomb charge. what is the magnitude of the force on the 2 microcoulomb charge?
Answers
With the concept of Coulomb's Law, the net force acting on the 2μC charge is 2.06 × 10⁻² newton.
What is Coulomb's Law?Coulomb's Law states that the force of attraction or repulsion exerted by a charged particle on another charged particle is given by,
F=kq₁q₂ / r²
Here q₁ and q₂ are the charges on the particles,
r is the separation between them
k is a constant known as Coulomb's constant, whose value is, k = 9 × 10⁹ N m²/C²
So here in the question, we have been given an equilateral triangle of side 2 meters with three-point charges at its vertices
q₁ = 1μC ,
q₂ = 2μC ,
q₃ = 3μC ,
r=2 m
From Coulomb's law,
F₂₁ = kq₁q₂/r²
F₂₁ = (9 × 10⁹ × 1 × 2 × 10⁻¹²) / 2²
F₂₁ =4.5 × 10⁻³ N
This is the force on charge q₂ because of q₁.
Similarly,
F₂₃ = kq₂q₃ / r²
F₂₃ = (9 × 10⁹ × 2 × 3 × 10⁻¹²) / 2²
F₂₃ = 18 × 10⁻³ N
Now, the resultant of the two forces will be,
F(net) = \(\sqrt{F_{21} ^2 + F_{23}^2 +2F_{21}F_{23}cos60}\)
On substituting all the values the net force will be
F(net) = 2.06 × 10⁻² N
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Related Questions
4) Un péndulo tiene un período de oscilación de 4 seg (T) , realizando su
movimiento desde su posición de equilibrio, si la aplitud del movimiento es de
10 cm y el ángulo de desfase es de 20 grados. Calcular:
La posición en la que se encuentra a los 5 segundos de haber iniciado el
movimiento.
Answers
Answer:
x = 1.43 cm
Explanation:
The horizontal displacement of the pendulum can be found using the following equation:
\( x(t) = x_{0}*sin(\omega*t + \phi) \)
Where:
x₀: is the initial horizontal displacement = 10 cm
ω: is the angular frequency
t: is the time = 5 s
Φ: is the phase shift = 20° = 20*2π/360 = 0.35 rad
The angular frequency can be calculated using the oscillation perid (T):
\( \omega = \frac{2\pi}{T} = \frac{2\pi}{4 s} = 1.57 rad/s \)
The horizontal displacement is:
\( x(t) = x_{0}*sin(\omega*t + \phi) = 10 cm*sin(1.57 rad/s*5 s + 0.35 rad) = 1.43 cm \)
Therefore, the displacement of the pendulum at 5 s is 1.43 cm.
I hope it helps you!
an electric bulb has power 500 watt. what does it means
Answers
Answer:
The bulb consumes electrical energy at the rate of 500 Watts
1 Watt = 1 Joule/sec where the joule is the unit of energy
Electric energy is often expressed in kw-hrs
This means that 1 kilowatt of power is used for 1 hour
1 kw-hr = 1000 joules/sec * 3600 sec = 3.6E6 joules of energy
This is a direct calculation question. You are in a spacecraft orbiting Venus. This is a direct calculation question. You are in a spacecraft orbiting Venus.
The mass of Venus is 4.87E+24 kg, and it's radius is 6.05E+3 km.
What is the escape velocity from the surface? ______m/s.
At a height of 13 radii above the surface of the Venus, what is the circular orbital velocity (orbital velocity, not escape velocity)? _____m/s
Answers
The escape velocity of the spacecraft, launched from the surface, is about 10.3km/s, and when launched from a height of 13R, its orbital velocity would be around 7.53km/s.
We need to understand the basics of how human-made objects are launched into space and the effect of gravity on such bodies.
Any satellite or spacecraft launched into space first needs a certain speed to orbit around the planet. Any speed less than this would result in the spacecraft falling back into the planet due to its gravity. This speed is needed to beat the centripetal force on the satellite.
This velocity is known as the orbital velocity of the body.
In a few cases, we need the body to be sent out of the gravitational field of the planet, thus allowing it to explore planets and moons outside the field. This would require an even larger velocity, by inference. We need the body to not stop before it crosses the boundaries of the planet's field
This velocity is known as the escape velocity of the body.
Now, we define the expressions for these velocities, from the surface.
V (Orbital) = √(G*M/R)
V (Escape) = √(2*G*M/R)
Notice that escape velocity is √2 times the orbital velocity for any planet.
In the question, we have
M = 4.87E + 24
R = 6.05E + 3 for Venus
So,
The escape velocity from the surface
V = √2 *√[6.67*10⁻¹¹ *(4.87E + 24)/6.05E + 3]
V ≈ 10,356 m/s = 10. 35 km/s
For orbital velocity, we need to take into consideration the height of the body.
Thus, in place of R (dist. from the center), we use
new R = R + 13R = 14R
So, the orbital velocity from the given height is:
V = √[6.67*10⁻¹¹ *(4.87E + 24)/14(6.05E + 3)]
V = 7531 m/s = 7.53km/s
Thus, the orbital velocity for the body is 7.53km/s from the height of 13R, and the escape velocity is 10.35km/s.
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five adaptive features of guava fruite
Answers
Guava fruit exhibits several adaptive features that contribute to its survival and reproduction in its environment. Here are five adaptive features of guava fruit:
1)Hard, protective outer layer
2)High vitamin C content
3)Numerous seeds
4)Aromatic scent
5)Tolerance to varied environmental conditions
Hard, protective outer layer: The outer layer of guava fruit is tough and thick, providing protection against physical damage and potential threats from herbivores and pathogens.
High vitamin C content: Guava fruit has a high concentration of vitamin C, which acts as an antioxidant. This feature helps the fruit endure exposure to sunlight and prevents oxidative damage caused by free radicals.
Numerous seeds: Guava fruit typically contains numerous small seeds. This adaptive feature increases the chances of successful reproduction, as more seeds are available for dispersal and potential germination.
Aromatic scent: Guava fruit emits a pleasant and distinct aroma. This scent attracts animals, especially birds and insects, which can aid in seed dispersal by consuming the fruit and subsequently dispersing the seeds through their droppings.
Tolerance to varied environmental conditions: Guava fruit is resilient and can tolerate a range of environmental conditions, including high temperatures, drought, and acidic soils. This adaptability enables guava plants to thrive in diverse habitats and ensures the survival of the fruit in different climates and ecosystems.
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How does Tata 1mg maintain its competitive advantage?
Answers
Tata 1mg maintains its competitive advantage through factors such as strong brand reputation, technological innovation, and strategic partnerships.
Tata 1mg, a leading online healthcare platform, sustains its competitive advantage by leveraging several key factors. Firstly, Tata's strong brand reputation and credibility in the market contribute to its competitive edge. This enables them to build trust with customers and attract a large user base. Additionally, Tata 1mg invests in technological innovation to enhance its platform's features, user experience, and efficiency.
By incorporating advanced technologies such as artificial intelligence and machine learning, they can provide personalized healthcare solutions and stay ahead of competitors.
Furthermore, strategic partnerships with healthcare providers, pharmaceutical companies, and diagnostic labs allow Tata 1mg to offer a comprehensive range of services, ensuring convenience and access to a wide network of healthcare resources for their customers. These factors collectively contribute to Tata 1mg's ability to maintain its competitive advantage in the online healthcare industry.
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A wave has a frequency of 6 Hz, how long is the period?
A 6
B 12
C .17
D 36
Answers
Answer:
C.
Explanation:
What is the smallest, most basic level of organization in an animal or
plant?
Answers
Answer:
hhmmmmmhmmmm hmhmmmm hmmm yeah i got nothing
Explanation:
please hurry write the symbol that completes the following nuclear equation
88 ^ 21 Rn : 2 He+?
15 ^ 29P +1 ^ 0 e+ ?
Answers
The symbols that completes the given nuclear equation are written as follows:
²²⁶Ra₈₈ ----> ²²²Rn₈₆ + ⁴He₂²⁹P₁₅ e ----> ⁰⁻e₁⁺ + ²⁹Si₁₄What is an alpha decay?An alpha decay can be defined as a type of radioactive decay in which the atomic nucleus of a radioactive element emits an alpha particle, thereby, producing chemical elements with a different atomic nucleus.
During an alpha decay, the radioactive element has a mass number that is decreased by four (4) and an atomic number that is decreased by two (2), which is typically an atom of Helium (⁴He₂).
What is a beta particle?A beta particle can be defined as an isotope which typically undergoes radioactive decay through the emission of a radiation with a -1 charge. This ultimately implies that, an atom of neutron becomes a proton and an electron (₀e⁻¹) and an atom of proton also becomes a neutron and a positron (⁰⁻e₁⁺) during beta decay.
In conclusion, the symbols that completes the given nuclear equation are written as follows:
²²⁶Ra₈₈ ----> ²²²Rn₈₆ + ⁴He₂²⁹P₁₅ e ----> ⁰⁻e₁⁺ + ²⁹Si₁₄Read more on alpha decay here: https://brainly.com/question/23303931
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Part B You are given two circuits with two batteries of emf & and internal resistance Ri each. Circuit A has the batteries connected in series with a resistor of resistance R2, and circuit B has the batteries connected in parallel to an equivalent resistor. What is the current through the resistor of resistance R2 in circuit A? Express the current in terms of E (not the epsilon symbol €), R1, and R2. (Figure 1) View Available Hint(s) IVO AO ? 2€ IA = 2R, +2R Figure 1 of 1 Submit Previous Answers X Incorrect; Try Again ER R E R APWEW HW R Part C R2 E R2 w Calculate the current Ig through the resistor of resistance R2 for circuit B. Express your answer in terms of E, R1, and R2. Circuit A Circuit B View Available Hint(s)
Answers
The current through the resistor of resistance R2 in circuit A is 2ε/(2R₁ + R₂) and the current through the resistor of resistance R2 in circuit B is 2ε/(2R₂ + R₂).
Given information,
Resistance, R₁ and R₂
emf, ε
current, I
The energy provided by a battery or cell per coulomb (Q) of charge moving through it is known as the EMF or electromotive force.
According to Ohm's law, a conductor's current flow is directly proportional to the voltage is applied to it.
V = IR
From the definition of Ohm's law, the emf can be expressed as,
ε = I(R+r)
The current through the resistor R₂ in circuit A,
Iₐ = 2ε/(2R₁ + R₂)
The current through the resistor R₂ in circuit B,
Iₙ = 2ε/(2R₂ + R₂)
Hence, the current through circuits A and B is 2ε/(2R₁ + R₂) and 2ε/(2R₂ + R₂) respectively.
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best explanation for why oceans have 2 different types of currents
Answers
Answer:
Hunubunununununununnunu
Which types of electromagnetic waves have wavelengths that are longer than those of visible light but shorter than those of microwaves?
Answers
Answer: last one radio waves
Or d
Explanation:
Answer:
infrared
Explanation:
ed2020
What is your instantaneous speed at the instant you turn around to move in the opposite direction?
Answers
When you turn while moving, your speed zeros out before rising.
What is instantaneous speed?
The speed of an object can change as it moves. The speed of an object at a certain instant of time is known as the instantaneous speed. If the position is a function of time, then the speed depends on the change in the position as time changes.
Turning around while moving causes your speed to drop to zero before rising in the opposite direction at the same location.
While you might maintain a steady pace if you made a semicircle turn, you wouldn't be traveling along the same road in the other direction.
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A spring is compressed between two blocks, one with a mass of 2 kg and the other with a mass of 3 kg. If the 2 kg block has an average acceleration of 6 m/s^2 when the spring acts on it, what will be the average acceleration of the 3 kg block???
Answers
Answer:
2=6
3=9
Explanation:
I think this is right I'm not sure but I have done problems like this and did based on what I remember.
The average acceleration of the 3 kg block is 4 m/s².
The given parameters;
mass of first block = 2 kgmass of second block = 3 kgacceleration of the first block, = 6 m/s/sAccording to Newton's third law of motion, action and reaction are equal and opposite.
The force exerted on both blocks are equal and opposite.
\(F = ma\\\\m_1 a_1 = m_2a_2\\\\a_2 = \frac{m_1 a_1}{m_2}\\\\a _2 = \frac{2\times 6}{3} \\\\a_2 = 4 \ m/s^2\)
Thus, the average acceleration of the 3 kg block is 4 m/s².
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 70.8-kg man just before contact with the ground has a speed of 6.33 m/s. (a) In a stiff-legged landing he comes to a halt in 1.99 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.147 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answers
(a) The man comes to a halt in 1.99 ms = 1.99 × 10⁻³ s, so his average acceleration slowing him from 6.33 m/s to a rest is
a = (6.33 m/s - 0) / (1.99 × 10⁻³ s) ≈ 3180 m/s²
so that the average net force on the man during the landing is
F = (70.8 kg) a ≈ 225,000 N
i.e. with magnitude 225,000 N.
(b) With knees bent, the man has an average acceleration of
a = (6.33 m/s - 0) / (0.147 s) ≈ 43.1 m/s²
and hence an average net force of
F = (70.8 kg) a ≈ 3050 N
(c) The net force on the man is
∑ F = n - w = m a
where
n = magnitude of the normal force, i.e. the force of the ground pushing up on the man
w = the man's weight, m g ≈ 694 N
m = the man's mass, 70.8 kg
g = mag. of the acceleration due to gravity, 9.80 m/s²
a = the man's acceleration
Using the acceleration in part (b), we have
n = m g + m a = m (g + a)
n = (70.8 kg) (9.80 m/s² + 43.1 m/s²) ≈ 3740 N
An element of atomic number 88 decays radioactively to an element of atomic number 82.
Part A
Which of the following emissions achieve this result?
Check all that apply.
a.) one alpha particle and one beta-minus particle
b.) three alpha particles
c.) one alpha particle
d.) six beta-minus particles
An element of atomic number 82 and mass number 214 decays radioactively to an element of atomic number 82 and mass number 210.
Part B
Which of the following emissions achieve this result?
Check all that apply.
a.) four beta-minus particles
b.) two beta-minus particles and one alpha particle
c.) two alpha particles
d.) one alpha particle
Answers
An element of atomic number 88 decays radioactively to an element of atomic number 82. The emissions that achieve this result is one alpha particle. The correct option is D. The emission that achieves this result is one alpha particle. The correct option is C.
To determine the emissions that achieve the radioactive decay from an element with atomic number 88 to an element with atomic number 82, we need to consider the changes in atomic number and mass number during the decay process.
In a radioactive decay, the atomic number decreases by the emission of a particle, and the mass number decreases by a specific amount as well.
Atomic number of initial element = 88
Atomic number of final element = 82
From this information, we can conclude that the decay process involves the emission of an alpha particle.
The emission of an alpha particle corresponds to the emission of a helium nucleus, which consists of two protons and two neutrons. This emission reduces the atomic number by 2 and the mass number by 4.
Therefore, the emission that achieves this result is C, one alpha particle.
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How do you calculate relative velocity?
Answers
Answer:
Vab=Va-VbVab=Vb-VaExplanation:Vab is velocity of a relative to b
Vba is velocity of b relative to a
a satellite is orbiting at a distance of 4.2x10⁶ m from the surface of the Earth. The radius of the Earth is 6.4x10⁶ m. What is the ratio of gravitational force on the satellite in orbit to gravitational force on the surface of the Earth?
Answers
Answer:
372 252
Explanation:
While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL.
Answers
The mass of the blood denoted is 501.6 g.
What is the mass of the blood she denoted?The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.
density = mass/volume
mass = density x volume
The given parameters include;
density of the blood = 1.06 g/mLvolume of the blood, = 473.176 mLThe mass of the blood is calculated as follows;
mass = 1.06 g/mL x 473.176 mL
mass = 501.6 g
Thus, the mass of the blood is calculated from the formula of density.
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The complete question is below
While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.
What is elastic potential energy and give and a example
Answers
Answer:
Many objects are designed specifically to store elastic potential energy, for example: The coil spring of a wind-up clock. An archer's stretched bow. A bent diving board, just before a divers jump
Explanation:
Answer:
Elastic Potential Energy is stored in elastic items.
A example of Elastic Potential Energy is a rubber band. When you stretch it, and it shoots off your finger. Where the rubber band gives off Elastic Potential Energy, is when you stretch it on your fingers, before you let it go.
Efficiency of a machine if energy input is 7.55 and energy output is 5.05
Answers
The efficiency of this machine is 66.67%.
What is efficiency?
Efficiency is a measure of how well a machine or system is able to convert input energy into useful output energy. It is a ratio of the output energy to the input energy, expressed as a percentage.
An efficient machine or system is one that is able to convert a large portion of the input energy into useful output energy, with minimal energy loss. Conversely, an inefficient machine or system is one that loses a significant portion of the input energy as waste heat, sound, or other forms of energy that are not useful to the desired output.
The efficiency of a machine can be calculated using the formula:
Efficiency = (Energy Output / Energy Input) x 100%
In this case, the energy input is 7.55 and the energy output is 5.05, so we can calculate the efficiency as follows:
Efficiency = (5.05 / 7.55) x 100% = 66.67%
Therefore, the efficiency of this machine is 66.67%.
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In the absence of air resistance, a ball of mass m is tossed upward to reach a height of 20 m. at the 10 m position, halfway up, the net force on the ball is?
Answers
On the ball, there is mg of net force.
How would one describe air resistance?Air exerts a force known as air resistance. The force works in the opposite direction of an object traveling through the air. While a sports vehicle with a streamlined design will encounter reduced air resistance and experience less drag, the automobile will be able to move more quickly than a truck with a flat front.What Causes Air Resistance?Air resistance, also referred to as "drag," is a force brought on by air. When air specks collide with an object's front, it slows down. The more air particles that impact the object and the larger its surface area, the more resistance it faces.
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a string that is stretched between fixed supports separated by 75.0 cm has resonant frequencies of 420 and 315 hz, with no intermediate resonant frequencies.what are (a) the lowest resonant frequency and (b) the wave speed?
Answers
To get the resonant frequencies of a single cohesive wave, just use formula v = f.The wave velocity is denoted by the letter "v," while the wave's distance is denoted by the symbol "."
The length of the string:
L=75.0 cm=0.75 m
The two resonant frequencies:
450 Hz Λ 308 Hz
a) f1=142 Hzf1=142 Hz
b)v=213 msv=213 sm
What has the lowest frequency and lowest magnitude among the following?Gamma rays often have the greatest frequency, while radio waves typically have the lowest.
Is the lowest frequency the first harmonic?The fundamental frequency is the lowest frequency that can be produced by a certain instrument.A first harmonic of a instrument is another name for the fundamental frequency.
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The reference evapotranspiration at the peak demand for matured grape plantation is 6.5 mm/d with a crop coefficient, Kc of 1.2. The groundcover is estimated to be 80 % whiles Kr is taken to be 0.94 based on Keller and Karmeli. Determine:
I. The localized ETc at the peak demand
II. The peak net and gross requirements for the mango if grown on sandy soil with Ks = 0.91; assuming no rainfall and no leaching requirement and EU is taken to be 85 %.
b. Assuming a tree spacing of 6 m x 6 m, a percent wetted area (Pw) of 50 % and wetted area for sandy soil being 2 m2, determine the number of emitters per plant.
c. What is the irrigation frequency and irrigation period if effective rooting depth = 1000 mm; soil available moisture content = 15 cm/m; manageable allowable depletion for drip irrigation system is 25 %; Drip emitter discharge = 0.005 m3/h
Answers
The irrigation frequency is approximately 88.89 and the irrigation period is 3000 hours.
I. To determine the localized ETc (crop evapotranspiration) at peak demand for matured grape plantation, we can use the following formula:
ETc = ETo × Kc × Kr × Groundcover
Given:
ETo (reference evapotranspiration) at peak demand = 6.5 mm/d
Kc (crop coefficient) = 1.2
Kr (reduction coefficient) = 0.94
Groundcover = 80% (0.8)
Calculating:
ETc = 6.5 × 1.2 × 0.94 ×0.8
ETc = 5.11744 mm/d
Therefore, the localized ETc at peak demand for the matured grape plantation is approximately 5.12 mm/d.
II. To calculate the peak net and gross water requirements for mango plantation on sandy soil, we use the formula:
Net Requirement = ETc / Ks
Gross Requirement = Net Requirement / EU
ETc (localized ETc) = 5.12 mm/d
Ks (soil water stress coefficient) = 0.91
EU (water use efficiency) = 85% (0.85)
Calculating Net Requirement:
Net Requirement = 5.12 / 0.91
Net Requirement = 5.62 mm/d
Calculating Gross Requirement:
Gross Requirement = 5.62 / 0.85
Gross Requirement = 6.62 mm/d
Therefore, the peak net water requirement for mango plantation on sandy soil is approximately 5.62 mm/d, and the peak gross water requirement is approximately 6.62 mm/d.
b. To determine the number of emitters per plant, we can use the following formula:
Number of emitters = Wetted area per plant / Wetted area per emitter
Tree spacing = 6 m x 6 m
Percent wetted area (Pw) = 50%
Wetted area for sandy soil = 2 m²
Calculating Wetted area per plant:
Wetted area per plant = Tree spacing ×Tree spacing ×Pw
Wetted area per plant = 6 ×6 × 0.5Wetted area per plant = 18 m²
Calculating Number of emitters per plant:
Number of emitters per plant = Wetted area per plant / Wetted area per emitter
Number of emitters per plant = 18 / 2
Number of emitters per plant = 9 emitters
Therefore, the number of emitters per plant is 9.
c. To determine the irrigation frequency and irrigation period, we need to consider the effective rooting depth, soil available moisture content, manageable allowable depletion, and drip emitter discharge.
Effective rooting depth = 1000 mm
Soil available moisture content = 15 cm/m
Manageable allowable depletion = 25% (0.25)
Drip emitter discharge = 0.005 m³/h
Calculating Irrigation Frequency:
Irrigation Frequency = Effective Rooting Depth / (Soil Available Moisture Content × (1 - Manageable Allowable Depletion))
Irrigation Frequency = 1000 / (15 × (1 - 0.25))
Irrigation Frequency = 1000 / (15 × 0.75)
Irrigation Frequency = 1000 / 11.25
Irrigation Frequency ≈ 88.89
Calculating Irrigation Period:
Irrigation Period = Wetted Depth / Drip Emitter Discharge
Irrigation Period = 15 / 0.005
Irrigation Period = 3000 hours
Therefore, the irrigation frequency is approximately 88.89 and the irrigation period is 3000 hours.\
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Jared's business debt, which was previously deducted as partially worthless, became totally worthless in 2021. Only the amount not previously deducted can be deducted in 2021. True False
Answers
The statement is false. Jared's business debt, which was previously deducted as partially worthless, became totally worthless in 2021. Only the amount not previously deducted can be deducted in 2021.
When a business debt becomes totally worthless, the entire amount of the debt can be deducted in the year it becomes worthless. This includes any portion of the debt that was previously deducted as partially worthless. The tax regulations allow for a deduction of the full amount of the debt when it is determined to be completely uncollectible or without any expectation of recovery.
Therefore, in the given scenario, Jared can deduct the full amount of the debt that became totally worthless in 2021, irrespective of whether any portion of it was previously deducted.
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a block is tied to a post with a cable and rotating with a constant velocity, on a horizontal smooth surface. what is the direction of its acceleration?
Answers
When a block is tied to a post with a cable and rotating with a constant velocity, on a horizontal smooth surface, the direction of its acceleration is towards the center of rotation.
Acceleration is a vector quantity that represents a change in velocity in terms of magnitude and direction. When an object changes direction, it is accelerating, and its direction of acceleration is perpendicular to its direction of motion. When an object rotates with a constant velocity, its speed remains constant, but its direction changes continuously. As a result, it is continuously accelerating towards the center of rotation, as in the case of a block tied to a post with a cable rotating on a horizontal smooth surface.
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the sun tends to bloat outward by nuclear fusion, and contract due to
Answers
The Sun's outward bloating is driven by nuclear fusion, while its contraction is due to the force of gravity. The balance between these forces maintains the Sun's size and shape, ensuring its stability over billions of years.
The sun is a dynamic and complex celestial body that undergoes constant change and evolution. One of the main processes that affects the sun's size and shape is nuclear fusion. This process involves the merging of atomic nuclei to form heavier elements, releasing a tremendous amount of energy in the process. As the sun undergoes fusion, it tends to bloat outward, expanding in size and becoming less dense. However, this expansion is not infinite, as the gravitational force of the sun's mass ultimately pulls it back together. In fact, the sun also undergoes a process of contraction, as gravity causes it to compress and become more dense. This cycle of expansion and contraction is essential for the sun's stability, as it helps maintain a delicate balance between the forces of nuclear fusion and gravity.
The sun's size and shape are influenced by the opposing forces of nuclear fusion and gravity. While fusion causes the sun to bloat outward, gravity pulls it back together and causes it to contract. This cycle of expansion and contraction is a crucial factor in the sun's overall stability and longevity. The Sun tends to bloat outward due to nuclear fusion and contract due to gravity. In the core of the Sun, nuclear fusion occurs, converting hydrogen into helium. This process releases a tremendous amount of energy in the form of light and heat, which creates an outward pressure that counteracts the force of gravity.
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3. The runner ran a distance 100m with a force of 45N. How much work
was done? (W=Fx d)
Answers
Answer:
Hope my answer is understandable to you.
A disk of mass M is spinning freely at 7.53 rad/s when a second identical disk, initially not spinning, is dropped onto it so that their axes coincide. In a short time the two disks are corotating. What is the angular speed of the new system (in rad/s)? If a third such disk is dropped on the first two, find the final angular speed of the system (in rad/s).
Answers
The final angular speed of the system when a third disk is dropped is approximately 2.51 rad/s.
To answer your question, we need to consider the conservation of angular momentum. When the first disk of mass M is spinning freely at 7.53 rad/s and a second identical disk, initially not spinning, is dropped onto it with coinciding axes, the angular speed of the new system can be calculated using the formula:
Initial angular momentum = Final angular momentum
I1ω1 + I2ω2 = (I1 + I2)ωf
Since both disks are identical, their moments of inertia (I) are the same. The second disk is initially not spinning, so ω2 = 0. The formula becomes:
Iω1 = 2Iωf
Now, we can solve for the final angular speed (ωf):
ωf = ω1 / 2
ωf = 7.53 rad/s / 2
ωf ≈ 3.77 rad/s
When a third identical disk is dropped onto the first two, we can again use the conservation of angular momentum:
(I1 + I2)ωf + I3ω3 = (I1 + I2 + I3)ωf'
As before, the moments of inertia are the same, and the third disk is initially not spinning, so ω3 = 0. The formula becomes:
2Iωf = 3Iωf'
Solve for the final angular speed (ωf'):
ωf' = (2/3)ωf
ωf' = (2/3)(3.77 rad/s)
ωf' ≈ 2.51 rad/s
So, the final angular speed of the system when a third disk is dropped is approximately 2.51 rad/s.
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(E) V = kQ/r so the smaller sphere is at the lower potential (more negative = lower) Negative charge
flows from low to high potential so the charge will flow from the smaller sphere to the larger.
The flow of charge ceases when there is no difference in potential.
Two conducting spheres of different radii, as shown above, each have charge -Q. Which of the following
occurs when the two spheres are connected with a conducting wire?
(A) No charge flows.
(B) Negative charge flows from the larger sphere to the smaller sphere until the electric field at the surface of
each sphere is the same.
(C) Negative charge flows from the larger sphere to the smaller sphere until the electric potential of each
sphere is the same.
(D) Negative charge flows from the smaller sphere to the larger sphere until the electric field at the surface of
each sphere is the same.
(E) Negative charge flows from the smaller sphere to the larger sphere until the electric potential of each
sphere is the same.
Answers
The correct statement is " Negative charge flows from the smaller sphere to the larger sphere until the electric potential of each sphere is the same." The correct Option (E).
When the two spheres are connected with a conducting wire, the negative charge will flow from the smaller sphere to the larger sphere until the electric potential of each sphere is the same. This is because the electric potential at a point in space is proportional to the amount of charge present at that point and inversely proportional to the distance from the point to the center of the charged sphere.
Option (A) is not true because charge will flow due to the difference in potential between the two spheres.
Option (B) is not true because the electric field at the surface of each sphere will not necessarily be the same after charge flows.
Option (C) is not true because the electric potential at a point in space is the same for all charged conductors connected by a wire.
Option (D) is not true because the negative charge will flow from the smaller sphere to the larger sphere, not the other way around.
Therefore, The correct answer is option E.
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Two conducting spheres of different radii with each negative charge connected with a conducting wire, Negative charges flow from the smaller sphere to the larger sphere until the potential becomes the same. Thus, option E is correct.
The potential V = kQ / r, Potential and charge are directly proportional to each other, more potential gives more negative charge. More negative charge gives lower potential. The potential always flows from a lower to a higher potential. Thus the negative charge flows from the smaller sphere to the larger sphere to equal the potential.
Thus, the correct option is E.
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Answer for 50pts
1. Draw a free body diagram for each of the following objects:
a. a projectile accelerating downward in the presence of air resistance
b. a crate being pushed across a flat surface at constant speed
2. A bag of sugar has a mass of 2.0 kg
a. What is its weight in newtons on the moon, where acceleration due to gravity is one-sixth of that on Earth?
b. What is its weight on Jupiter, where acceleration due to gravity is 2.64 times that on Earth?
3. A 3.0 kg block on an incline at a 50.0o angle is held in equilibrium by a horizontal force.
a. Determine the magnitude of this horizontal force (disregard friction)
b. Determine the magnitude of the normal force on the block
4. A 60 kg ice skater is at rest on a flat skating rink. A 200 N horizontal force is needed to set the skater in motion. However, after the skater is in motion, a horizontal force of 180 N keeps the skater moving at a constant velocity. Find the coefficients of static and kinetic friction between the skates and the ice.
Answers
Explanation:
1a. Free body diagram of a projectile accelerating downward in the presence of air resistance:
Free body diagram of a projectile accelerating downward in the presence of air resistance
b. Free body diagram of a crate being pushed across a flat surface at constant speed:
Free body diagram of a crate being pushed across a flat surface at constant speed
2a. Weight of the bag of sugar on the moon:
Weight = mass x acceleration due to gravity
On the moon, acceleration due to gravity is one-sixth of that on Earth, so
Weight on the moon = 2.0 kg x (1/6) x 9.81 m/s^2 = 3.27 N
b. Weight of the bag of sugar on Jupiter:
On Jupiter, acceleration due to gravity is 2.64 times that on Earth, so
Weight on Jupiter = 2.0 kg x 2.64 x 9.81 m/s^2 = 51.6 N
3a. To hold the block in equilibrium, the horizontal force must balance the component of the weight force that acts parallel to the incline. The weight force is given by:
Weight = mass x gravity
Weight = 3.0 kg x 9.81 m/s^2 = 29.43 N
The component of the weight force parallel to the incline is given by:
Force_parallel = Weight x sin(50.0o)
Force_parallel = 29.43 N x sin(50.0o)
Force_parallel = 22.58 N
Therefore, the magnitude of the horizontal force required to hold the block in equilibrium is 22.58 N.
b. The normal force on the block is equal in magnitude and opposite in direction to the component of the weight force that acts perpendicular to the incline. This is given by:
Force_perpendicular = Weight x cos(50.0o)
Force_perpendicular = 29.43 N x cos(50.0o)
Force_perpendicular = 22.52 N
Therefore, the magnitude of the normal force on the block is 22.52 N.