tickets to the zoo cost $4 for children, $5 for teenagers and $6 for adults. in the high season, 1200 people come to the zoo every day. on a certian day, the total revenue at the zoo was $5300. for every 3 teenagers, 8 children went to the zoo. how many teenagers went to the zoo? a. 100 teenagers c. 300 teenagers b. 200 teenagers d. 400 teenagers please select the best answer from the choices provided a b c d

Answer:

6. vbq and jet are congruent I think rotation

8. ekaf and mdkc are congruent

The square mil area for a 2 inch wide by 1/4 inch thick copper busbar is 500 square mils.

To find the square mil area for a 2 inch wide by 1/4 inch thick copper busbar, we need to multiply the width and thickness of the busbar in mils.

1 inch = 1000 mils

So, the width of the busbar in mils = 2 inches x 1000 mils/inch = 2000 mils

And, the thickness of the busbar in mils = 1/4 inch x 1000 mils/inch = 250 mils

Therefore, the square mil area of the copper busbar = width x thickness = 2000 mils x 250 mils = 500,000 square mils.

Hence, the square mil area for a 2 inch wide by 1/4 inch thick copper busbar is 500,000 square mils.

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Answer:

Ryan 113, Alex 101

Step-by-step explanation:

Ryan beats Alex by 12 points

101+101=202

202+12=214

113+101=214

The correct answer for the given expression is 99.22.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

The expression will be solved as:-

E = \(({5 -\dfrac{10}{27}})^3\)

E = \((\dfrac{135-10}{27})^3\)

E =\(\dfrac{125}{27}^3\)

E = 99.22

Therefore the correct answer for the given expression is 99.22.

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The graph of the system of inequality is plotted and attached

In mathematics,  the term inequality refers to a relationship between two expressions or values that is not equal to each other.

Therefore, inequality emerges from a lack of balance.

The graph of the inequality is represented by two horizontal lines one is a dashed line and the other is a solid line

y < 8

This is a dashed line at point y = 8, the dashed line is because the inequality does not have the "equal to".

Also the shading is below the line since it is less than

y ≥ 3

This is a solid line at point y = 3, the solid line is because the inequality have the "equal to". as in greater than or equal to.

Also the shading is above the line since it is greater than symbol.

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Areas under the standard normal probability distribution are: a)0.4772   b)0.9987  c) 0.3413  d)0.3145

To find the area under the standard normal probability distribution between different pairs of z-scores, we can use a standard normal distribution table or a calculator that provides the cumulative probability function for the standard normal distribution.

a. For z = 0 and z = 2.00:
To find the area under the curve between z = 0 and z = 2.00, we need to find the cumulative probability for z = 0 and subtract it from the cumulative probability for z = 2.00.

The cumulative probability for z = 0 is 0.5000 (which represents 50% of the area under the curve), and the cumulative probability for z = 2.00 is 0.9772 (which represents 97.72% of the area under the curve).

So, the area under the standard normal probability distribution between z = 0 and z = 2.00 is 0.9772 - 0.5000 = 0.4772 (or 47.72%).

b. For z = 0 and z = 3.00:
Using the same approach, we find the cumulative probability for z = 0 is 0.5000 and the cumulative probability for z = 3.00 is 0.9987.

Thus, the area under the standard normal probability distribution between z = 0 and z = 3.00 is 0.9987 - 0.5000 = 0.4987 (or 49.87%).

c. For z = 0 and z = 1.00:
Similarly, the cumulative probability for z = 0 is 0.5000 and the cumulative probability for z = 1.00 is 0.8413.

Therefore, the area under the standard normal probability distribution between z = 0 and z = 1.00 is 0.8413 - 0.5000 = 0.3413 (or 34.13%).

d. For z = 0 and z = 0.89:
The cumulative probability for z = 0 is 0.5000 and the cumulative probability for z = 0.89 can be found using the standard normal distribution table or calculator, which is approximately 0.8145.

Hence, the area under the standard normal probability distribution between z = 0 and z = 0.89 is 0.8145 - 0.5000 = 0.3145 (or 31.45%).

Remember, the area represents the probability of obtaining a z-score within the given range on the standard normal distribution.

This answers the question: " Find the area under the standard normal probability distribution between the following pairs of z-scores. a. z =0 and z =2.00 b. z= 0 and z= 3.00 c. z=0 and z =1.00 d. z=0 and z =0.89 "

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Answer:

Step-by-step explanation:

I think it the choice of A and D

Answer:

Step-by-step explanation:

1.

\(-7x+16=58\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\-7x+16-16=58-16\\\\-7x=42\\\\\mathrm{Divide\:both\:sides\:by\:}-7\\\\\frac{-7x}{-7}=\frac{42}{-7}\\\\x =-6\)

2.

\(-2x+15=-9\\\\\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}\\\\-2x+15-15=-9-15\\\\-2x=-24\\\\\mathrm{Divide\:both\:sides\:by\:}-2\\\\\frac{-2x}{-2}=\frac{-24}{-2}\\\\x=12\\\)

3.

\(5x-4=36\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\5x-4+4=36+4\\\\5x=40\\\\\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x}{5}=\frac{40}{5}\\\\x=8\)

4.

\(25-3x=88\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\\\25-3x-25=88-25\\\\\mathrm{Divide\:both\:sides\:by\:}-3\\\\\frac{-3x}{-3}=\frac{63}{-3}\\\\x=-21\)

5.

\(-11=7-x\\\\\mathrm{Add\:}x\mathrm{\:to\:both\:sides}\\\\-11+x=7-x+x\\\\-11+x=7\\\\\mathrm{Add\:}11\mathrm{\:to\:both\:sides}\\\\-11+x+11=7+11\\\\x=18\)

6.

\(65+15x=35\\\\\mathrm{Subtract\:}65\mathrm{\:from\:both\:sides}\\\\65+15x-65=35-65\\\\\mathrm{Divide\:both\:sides\:by\:}15\\\\\frac{15x}{15}=\frac{-30}{15}\\\\x=-2\)

7.

\(\frac{1}{2} x-18=2\\\\\mathrm{Add\:}18\mathrm{\:to\:both\:sides}\\\\\frac{1}{2}x-18+18=2+18\\\\\frac{1}{2}x=20\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\\\2\times\frac{1}{2}x=20\times \:2\\\\x=4\)

8.

\(\frac{2}{3}x-10=-12 \\\\\mathrm{Add\:}10\mathrm{\:to\:both\:sides}\\\\\frac{2}{3}x-10+10=-12+10\\\\\frac{2}{3}x=-2\\\\Divide\:both\:sides\:by\: 2/3\\\\\frac{2}{3}x\div \frac{2}{3} =-2\div \frac{2}{3} \\\\\frac{2}{3} x\times \frac{3}{2} =-2\times\frac{3}{2} \\\\x =-3\)

9.

\(6-\frac{1}{3}x=-1 \\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-\frac{1}{3}x-6=-1-6\\\\-\frac{1}{3}x=-7\\\\\mathrm{Multiply\:both\:sides\:by\:}-3\\\\\left(-\frac{1}{3}x\right)\left(-3\right)=\left(-7\right)\left(-3\right)\\\\x=21\)

10.

\(4-9x=-14\\\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\\\4-9x-4=-14-4\\\\-9x=-18\\\\\mathrm{Divide\:both\:sides\:by\:}-9\\\\\frac{-9x}{-9}=\frac{-18}{-9}\\\\x=2\)

11.

\(11-x=29\\\\\mathrm{Subtract\:}11\mathrm{\:from\:both\:sides}\\\\-x=18\\\\\mathrm{Divide\:both\:sides\:by\:}-1\\\\\frac{-x}{-1}=\frac{18}{-1}\\\\x=-18\)

12.

\(-9-11x=68\\\\\mathrm{Add\:}9\mathrm{\:to\:both\:sides}\\\\-9-11x+9=68+9\\\\-11x=77\\\\\mathrm{Divide\:both\:sides\:by\:}-11\\\\\frac{-11x}{-11}=\frac{77}{-11}\\\\x=-7\)

13.

\(45+\frac{5}{6}x =50\\\\\mathrm{Subtract\:}45\mathrm{\:from\:both\:sides}\\\\45+\frac{5}{6}x-45=50-45\\\\\frac{5}{6}x=5\\\\\mathrm{Divide\:both\:sides\:by\:}5/6\\\\\frac{5}{6} x\div\frac{5}{6}=5\div\frac{5}{6}\\\\\frac{5}{6}x\times \frac{6}{5}= 5\times\frac{6}{5}\\\\ x=6\)

14.

\(-5x+17=-33\\\\\mathrm{Subtract\:}17\mathrm{\:from\:both\:sides}\\\\-5x+17-17=-33-17\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\\\frac{-5x}{-5}=\frac{-50}{-5}\\\\x=10\)

15.

\(95=-4+33x\\\\-4+33x=95\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\-4+33x+4=95+4\\\\\mathrm{Divide\:both\:sides\:by\:}33\\\\\frac{33x}{33}=\frac{99}{33}\\\\x=3\)

Answer:

64,890

Step-by-step explanation:

105×3 =315

103×2= 206

315×206= 64,890

Answer:

6.489× 10⁴

Step-by-step explanation:

(3×105)×(2×103)

315× 206

64,890

6.489×10⁴

The lower limit for the central 95% of all possible sample means, drawn from a population distribution with a mean of 600 and a standard deviation of 112, is approximately 551.66.

To determine the lower limit of the central 95% of sample means, we use the formula for the confidence interval:

Lower limit = sample mean - margin of error

The margin of error is calculated by multiplying the critical value (obtained from the Z-table for a 95% confidence level) by the standard deviation of the population divided by the square root of the sample size:

Margin of error = Z * (σ/√n)

In this case, the mean is 600, the standard deviation (σ) is 112, and the sample size (n) is 19. From the Z-table, the critical value for a 95% confidence level is approximately 1.96.

Plugging in the values, we get:

Margin of error = 1.96 * (112/√19) ≈ 23.33

Therefore, the lower limit is:

Lower limit = 600 - 23.33 ≈ 551.66

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Answer: $66.20; close

Step-by-step explanation:

The down arrow indicates the stock price has decreased from yesterday’s price of $ 66.20  at the  close  of the market day.

The mean height of the hexagon is 21.33 in.

To find the length of the sides of a regular hexagon with a perimeter of 372 inches, you must divide the perimeter by 6. This gives you a result of 62 inches for the length of each side. The other steps are:

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The correct option is  B) increase.

To decrease sample error, a pollster must increase the number of respondents. The larger the sample size, the more representative it is likely to be of the target population, leading to a lower margin of error.

When conducting surveys or polls, it is essential to obtain responses from a diverse and random group of individuals. By increasing the number of respondents, the pollster can capture a broader range of perspectives, which helps to reduce sampling bias and increase the accuracy of the results.

For example, let's say a pollster wants to understand the political preferences of voters in a particular city. If they only survey 50 people, the sample may not accurately reflect the larger population, and the margin of error could be high. However, if they survey 500 or even 1000 people, the results are more likely to provide a reliable estimate of the overall population's preferences.

Therefore, to decrease sample error, pollsters should increase the number of respondents in their surveys or polls. This approach helps to ensure a more accurate representation of the population's views and minimize the potential for misleading or biased results.

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Answer:  when it is morning time to get up and you put your clothes and your shoe and your backpack and your  coat and you wait for the bus

Step-by-step explanation:

Answer:

Two other exponents that results in 256 are \(16^2\) and \(4^4\)

Step-by-step explanation:

Given

\(2^8 = 256\)

Required

Write two exponential expression that equals 256

\(2^8 = 256\)

Expand 8 as 4 * 2

\(2^{4*2} = 256\)

Using laws of indices, we have

\((2^4)^2 = 256\)

2⁴ = 16; So, we have

\(16^2 = 256\) --- This is one

Recall that

\(2^{4*2} = 256\)

This can also be rewritten as

\(2^{2*4} = 256\)

Using laws of indices, we have

\((2^2)^4 = 256\)

2² = 4; So, we have

\(4^4 = 256\) --- This is another one

Hence, two other exponents that results in 256 are \(16^2\) and \(4^4\)

Answer:

the answer to your question is 21

We can prove that 25k² + 15k is an even integer whenever 5k - 3 is an integer by considering two cases: when k is even and when k is odd.

Let's assume that 5k - 3 is an integer. Then, we can write k as k = (5k - 3 + 3)/5 = (5k - 3)/5 + 3/5. Since (5k - 3)/5 is an integer, we can write it as (5k - 3)/5 = n, where n is an integer. Thus, we have k = n + 3/5.

Now, we can substitute this expression for k into 25k² + 15k as follows:

25k² + 15k = 25(n + 3/5)² + 15(n + 3/5)

Expanding the square, we get:

25(n² + 6n/5 + 9/25) + 15n + 9 = 25n² + 45n/5 + 34/5

Simplifying, we get:

25k² + 15k = 5(5n² + 9n) + 34/5

Since 5n² + 9n is an integer, we can write it as m, where m is an integer. Thus, we have:

25k² + 15k = 5m + 34/5

Now, we can consider two cases:

Case 1: k is even. In this case, k can be written as k = 2p, where p is an integer. Substituting this expression into 5k - 3, we get:

5k - 3 = 5(2p) - 3 = 10p - 3

Since 10p is even, we can conclude that 10p - 3 is odd. Therefore, m must be odd, since 5m + 34/5 is even. Thus, 25k² + 15k is even, since it can be written as 5m + 34/5, where 5m is even and 34/5 is even.

Case 2: k is odd. In this case, k can be written as k = 2p + 1, where p is an integer. Substituting this expression into 5k - 3, we get:

5k - 3 = 5(2p + 1) - 3 = 10p + 2

Since 10p is even, we can conclude that 10p + 2 is even. Therefore, m must be even, since 5m + 34/5 is even. Thus, 25k² + 15k is even, since it can be written as 5m + 34/5, where 5m is even and 34/5 is even.

In both cases, we have shown that 25k² + 15k is an even integer whenever 5k - 3 is an integer. Therefore, the statement is proved.

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Answer:

I think its 8

Step-by-step explanation:

The value of f[ -4 ] and g°f[-2] are \(\frac{14}{3}\) and 13 respectively.

Given the function;

For f[ -4 ], we substitute -4 for every variable x in the function.

\(f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}\)

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

\(g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13\)

Therefore, the value of f[ -4 ] and g°f[-2] are \(\frac{14}{3}\) and 13 respectively.

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Answer:

The number 2, so answer choice A.

Answer:

2/25

Step-by-step explanation:

The first polynomial has 2 incongruent roots modulo 13, and the second polynomial has 0 incongruent roots modulo 13.

To find the number of incongruent roots modulo 13 for the given polynomials, we will examine them separately.

For the polynomial \(x^2 + 3x + 2\), we can test each possible value of x (0 to 12) to check for roots modulo 13. After testing, we find that x=4 and x=9 are roots, as they satisfy the equation\((4^2 + 3*4 + 2)\) ≡ 0 (mod 13) and \((9^2 + 3*9 + 2)\) ≡ 0 (mod 13).

Therefore, there are 2 incongruent roots modulo 13 for this polynomial.

For the polynomial \(x^4 + x^2 + x + 1\), we again test each possible value of x (0 to 12) modulo 13. In this case, we find no values of x satisfying the equation\(x^4 + x^2 + x + 1\) ≡ 0 (mod 13). Thus, there are 0 incongruent roots modulo 13 for this polynomial.

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Answer:

-4 and 13.

Step-by-step explanation:

I found this by finding the factors of 52- 1, 2, 4, 13, 26, and 52. You can then look at those and see how they interact. I knew that you had to multiply with a negative to get a negative product and that you can't get 9 by adding any two of those factors, so I started seeing how I could subtract to make 9. Once I found that I could take 4 from 13 and get 9 I checked the multiplication for -4 * 13 and it all worked out.

Answer:

I  know the x and y are 5 and 11 but I wanted to see if I could algebraically solve it, and found I couldn't.

In x+y=16, I know x=16/y but when I plug it back in I get something like 16/y+y=16, then I multiply the left side by 16 to get 2y=256 and then ultimately y=128. Am I doing something wrong?

Step-by-step explanation:

i don't have an answer to your specific request, but this example can help you fortunatly i was doing a problem about that type of question.

Answer:

C.-1.6

Step-by-step explanation:

distance: -1 - (-2) = 1

1 ÷ 5 = 1/5

-1 - 1/5 × 3 = -1 3/5 = -1.6

The rectangle with dimensions 21 m by 21 m has the largest area among rectangles with a perimeter of 84 m.

To find the dimensions of a rectangle with a perimeter of 84 m that maximizes the area, we need to use the properties of rectangles.

Let's assume the length of the rectangle is l and the width is w.

The perimeter of a rectangle is given by the formula: 2l + 2w = P, where P is the perimeter.

In this case, the perimeter is given as 84 m, so we can write the equation as: 2l + 2w = 84.

To maximize the area, we need to find the dimensions that satisfy this equation and give the largest possible value for the area. The area of a rectangle is given by the formula: A = lw.

Now we can solve the perimeter equation for l: 2l = 84 - 2w, which simplifies to l = 42 - w.

Substituting this expression for l into the area equation, we get: A = (42 - w)w.

To maximize the area, we can find the critical points by taking the derivative of the area equation with respect to w and setting it equal to zero:

dA/dw = 42 - 2w = 0.

Solving this equation, we find w = 21.

Substituting this value of w back into the equation l = 42 - w, we get l = 42 - 21 = 21.

Therefore, the dimensions of the rectangle that maximize the area are l = 21 m and w = 21 m.

In summary, the dimensions of the rectangle are 21 m by 21 m, so the answer is A. 21, 21.

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Here the correct answer is (8,4) means option B.

Given equations are,

y=x-4 -----------------(1)

y= -0.5x+8-----------(2)

Option A.(4,2): If we put x=4 in equation one then y=0 which does not satisfy equation 2.

Option B.(8,4): If we put x=8 in equation one then y=4 and which satisfies equation 2.

Option C.(2,4): If we put x=2 in equation one then y=-2 which does not satisfy equation 2.

Option D.(4,8): If we put x=4 in equation one then y=0 which does not satisfy equation 2.

Therefore the solution of the equations y=x-4 and y=-0.5x+8 is (8,4) which is option B.

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if  RS=x+4, ST=8 and RT=3x then value of RS is 10 units.

Two or more expressions with an Equal sign is called as Equation.

Given that RS=x+4, ST=8 and RT=3x

We have to find RS

RS=RT-ST

x+4=3x-8

Take the variable terms on one side and constants on other side

12=2x

Divide both sides by 2

x=6

So RS is 6+4=10 units

Hence, if  RS=x+4, ST=8 and RT=3x then value of RS is 10 units.

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We have the general solution of the beam equation: y = 1/2 x⁴ - (1/6)q₁ x³ + (1/2) x

Given that y'' (1) = 3

So we can find the second derivative of y:  y' = 2x³ - (1/2)q₁x² + (1/2)and y'' = 6x² - q₁x

Therefore, y''(1) = 6 - q₁

From the given information: y''(1) = 3

Putting this value into the above equation:3 = 6 - q₁=> q₁ = 6 - 3=> q₁ = 3

The value of q₁ is 3.

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The values are

First plot two dots on 8

Then rest two on -8

Answer:

See below ~

Step-by-step explanation:

Solving :

Answer:

Step-by-step explanation:

The difference between a number and five:  \((n-5)\)

Multiplied by negative two: \(-2(n-5)\)

The resulting product equals fourteen: \(-2(n-5)=14\)

SOLVE:

 \(-2(n-5)=14\)     (We divide both sides of the equation by -2)

     \(\frac{-2(n-5)}{-2} =\frac{14}{-2}\)  

    \(n-5=-7\)       (Now add 5 to each side)

\(n-5+5=-7+5\)

              \(n=-2\)