To obtain the approximate short-circuit current values when two hot conductors of a 3-phase system are shorted together, use _____ percent of the 3-phase current value.
Answers
To obtain the approximate short-circuit current values when two hot conductors of a 3-phase system are shorted together, use _maximum percent of the 3-phase current value.
short circuit- It is an electrical circuit in which current finds a way to bypass the appliances on a path that has little or no resistance.
In the 3- phase system, there are three power wires which carries load.
most common. Types of three phase system are known as wye and delta.
Delta configuration has only three wires. Wye configuration may have a fourth, neutral ,wire.To obtain the approximate short-circuit current values when two hot conductors of a 3-phase system are shorted together, use _maximum percent of the 3-phase current value.
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Related Questions
Dizzy is speeding along at 27.9 m/s as she approaches the level section of track near the loading dock of the Whizzer roller coaster ride.A braking system abruptly brings the 339-kg car (rider mass included) to a speed of 3.25 m/s over a distance of 5.19 meters. Determine the magnitude of the braking force (in newtons) applied to Dizzy's car.Answer: ____________ N (round to the nearest whole number)
Answers
The magnitude of the braking force is given by:
\(f=ma=m\frac{{v_f}^2-v_0^2}{2d}\)Replace the values of m=339kg, v_f=3.25m/s, v_0=27.9m/s and d=5.19m to find the magnitude of the braking force:
\(f=(339kg)\times\frac{(3.25\frac{m}{s})^2-(27.9\frac{m}{s})^2}{2(5.19m)}=-25,077.1...N\)The minus sign accounts for the fact that the car is decelerating.
Therefore, the magnitude of the braking force is approximately 25,077N.
a box having a mass of 5.00 kg is lifted 75.0 cm from the ground level to the top of a desk what is the gravitional energy of the box on the desktop
Answers
The box on the desk has a gravitational potential energy of 36.9 J.
How can you figure out the gravitational field strength using height and mass?Weight divided by mass equals the strength of the gravitational field. Different planets have various strengths of gravitational fields. The Moon's gravitational field is 1.6 N/kg strong.
The following formula must be used to get the box's gravitational potential energy: PE = mgh, where mgh is the height the box is raised to, m is the mass of the box, g is the acceleration caused by gravity, and PE is the gravitational potential energy.
The height must first be converted to metres:
h = 75.0 cm = 0.75 m
The values may now be plugged in, and PE can be solved:
PE = (5.00 kg)(9.81 m/s^2)(0.75 m) = 36.9 J
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Consider a buggy being pulled by a horse.
Which is correct?
1. The horse can pull the buggy forward only
if the horse weighs more than the buggy.
2. The force on the buggy is as strong as the
force on the horse. The horse is joined to the
Earth by flat hoofs, while the buggy is free to
roll on its round wheels.
3. The horse pulls before the buggy has time
to react so they move forward.
4. The horse pulls forward slightly harder
than the buggy pulls backward on the horse,
so they move forward.
Answers
Answer:
Option 2
Explanation:
Answer:B
Explanation:because she started of with no money and now she made her money up
what is the most similar to the Sun in luminosity and temperature
Answers
Explanation:
At a distance of 4.25 light years, Proxima is the closest-known star to our solar system. Science of the Alpha Centauri system. The two stars that make up Alpha Centauri, Rigil Kentaurus and Toliman, are quite similar to our sun
Which of the following is an example of potential energy?
A kite flying in the sky.
B dog chasing his tail.
C book sitting on a shelf.
D basketball player running down the court.
Answers
Answer:
C book sitting on a shelf.
Explanation:
An object can store energy as the result of its position. For example, the heavy ball of a demolition machine is storing energy when it is held at an elevated position
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The most common form of a Retail channel is
__________________________ .
a catalog
a store
a mobile device
social media
Answers
The most common form of a retail channel is a store. A store refers to a physical location where goods or services are sold directly to customers. It serves as a place where customers can browse, touch, and try products before making a purchase.
In a store, customers can interact with sales representatives, receive personalized assistance, and get immediate answers to their questions. Examples of retail stores include supermarkets, clothing boutiques, electronics stores, and department stores. Stores offer a wide range of benefits for both customers and retailers. For customers, they provide a tangible and immersive shopping experience, allowing them to see, touch, and try products before buying.
Additionally, stores often have knowledgeable staff who can provide guidance and recommendations. For retailers, stores provide a physical presence in the market, enabling them to build brand awareness, establish customer relationships, and offer additional services such as returns and exchanges. Overall, stores are a fundamental and widely utilized form of retail channel.
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with the enterprise of video-gaming technology growing every year, researchers have ercently become interested in the effects of violent video games
Answers
Meta-analysis indicates that violent video games increase aggressive thoughts, aggressive affect, and aggressive behavior.
What are the effects of Violent video games ?Children who play violent video games have increased aggressive cognitions, aggressive behavior, psychological arousal as well as antisocial behavior.
Furthermore, exposure to violence in the games leads to desensitization- “a reduction in emotion-related physiological reactivity to real violence”The downside of video games is that the more time children and teens spend playing violent video games the more likely they are to display aggressive behavior.Learn more about Violent video games here:
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Once the brick and the iron are cooled down, do they have the same thermal energy? Do they have the same temperature? Does the room temperature water have more or less thermal energy?
Answers
Once the brick and the iron are cooled down, they will not have the same thermal energy. Thermal energy depends on the mass and temperature of an object. Brick and iron may have different masses, and even if they have the same mass, their temperatures could be different after cooling. Therefore, their thermal energies would be different.
Regarding temperature, once the brick and the iron reach thermal equilibrium with their surroundings, they will have the same temperature. Thermal equilibrium means that there is no net transfer of heat between the objects and their surroundings.
As for the room temperature water, it will have more thermal energy compared to both the cooled brick and iron. This is because water has a higher specific heat capacity compared to most solid materials. Even at the same temperature, water can store more thermal energy due to its higher heat capacity.
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It was a children versus grown-ups competition at school. One event required the adult to throw a basketball as far as he could. When it was the child's turn, he had to throw a baseball instead. The event coordinator said, "It's only fair!" Based on Newton's laws, was this event fair?
Yes, because acceleration doesn't depend on the size of the object.
Yes, because an adult can apply more force than a child can. Making the adult's object bigger than the child's object helps to even out the acceleration.
No, because you must have the same size object in a competition.
No, because a basketball is bigger than a baseball, and objects that are bigger accelerate slower.
Answers
Answer:
No, because a basketball is bigger than a baseball, and objects that are bigger accelerate slower.
Explanation:
a water break at the entrance to a harbor consists of a rock barrier with a 50.0-m-wide opening. ocean waves of 30.0-m wavelength approach the opening straight on. at what angle to the incident direction are the boats inside the harbor most protected against wave action?
Answers
The boats inside the harbor are most protected against wave action when the incident waves create a diffraction pattern with a minimum at the harbor, at an angle of approximately 19.5 degrees.
When ocean waves approach an opening in a breakwater, they will diffract or bend around the opening. The amount of diffraction depends on the wavelength of the waves and the size of the opening. The waves will diffract most when the opening is approximately the same size as the wavelength. In this scenario, the wavelength of the ocean waves is 30.0 meters and the width of the opening is 50.0 meters. Therefore, the waves will diffract most when they approach the opening at an angle of approximately 53 degrees to the incident direction. At this angle, the waves will bend around the opening and produce the smallest waves inside the harbor.
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Name two ways to decrease the electric force between two charged objects.
Answers
Answer:
Inverse relationships are common in nature. In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.
Explanation:
Two ways to decrease the electric force between two charged objects:
by lessen charge of the test objects.by increasing distance between test change and source charge.What is coulomb force?As a result of their electric charge, particles or objects are attracted to or repelled by the Coulomb force, also known as electrostatic force or Coulomb interaction. Charles-Augustin de Coulomb, a French scientist who published the findings of an experimental inquiry into the proper quantitative description of this force in 1785, gave the electric force its name. The electric force is one of the fundamental physical forces.
Positive or negative electric charges that are similar to one another repel one another in a straight line between their centers. Positive and negative charges that are opposite each other are drawn together along a straight line connecting their centers.
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A spring scale is a device that uses a spring with a known spring constant to measure the weight of objects. You have a spring scale with a spring constant of 13 Nm. How much will the spring stretch when a 12-N weight is hung from one end?
Answers
Answer:
It would stretch about 6 inches, but it depends on the metal.
Explanation:
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3. With a mass of 114 kg, Baby Bird is the smallest monoplane ever flown.
Suppose the Baby Bird and pilot are coasting along the runway when the pilot
jumps horizontally to the runway behind the plane. The pilot’s velocity upon
.
leaving the plane is 5.32 m/s backward. After the pilot jumps from the plane,
the plane coasts forward with a speed of 3.40 m/s. If the pilot's mass equals
60.0 kg, what is the velocity of the plane and pilot before the pilot jumps?
Answers
The speed of the plane and pilot before the pilot jumps is 17.8 m/s.
Conservation of linear momentumWe know that the principle of conservation of linear momentum states that the total momentum of a system is constant. This means that the momentum "before" and "after" must be equal.
Thus;
Momentum before = (114 Kg + 60.0 kg) v
Momentum after = (60.0 kg × -5.32 m/s) + (114 Kg × 3.40 m/s)
Hence;
(114 Kg + 60.0 kg) v = 3100.8
v = 3100.8/(114 + 60.0)
v = 17.8 m/s
The speed of the plane and pilot before the pilot jumps is 17.8 m/s.
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
Answers
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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For brainliest !!!!!!! Do it
Answers
Answer and Explanation:
Using a = F/m, we get:
Acceleration for Road A = 480/62 = ~7.74 m/s^2
Acceleration for Road B = 240/62 = ~3.87 m/s^2
Acceleration for Road C = 600/62 = ~9.68 m/s^2
If the net force becomes higher than 600N and the mass stays constant, the acceleration will increase proportionally to how much the force increases and the acceleration will be greater than the acceleration when the force is 600N.
I hope this helps! :)
Calculate the magnetic force of 10C charged particle which is moving with a velocity of 2m/s in an magnetic field of 0.5T? The direction of magnetic field is same as that of path of the second particle.
Answers
Answer:
i think it is 20.5
Explanation:
How many minutes are in 240 days?
Answers
Answer:
Hi there!
Your answer is;
345,600 mins per 240 days
Explanation:
First, start small
How many minutes are in one hour?
60mins per 1 hr
How many minutes per one day?
60 × 24= 1440
1440 mins per 1 day
How many minutes per 240 days?
1440× 240= 345600
345,600 mins per 240 days
Hope this helps
A 67.3-kg climber is scaling the vertical wall of a mountain. His safety rope is made of a material that, when stretched, behaves like a spring with a spring constant of 1.23 x 103 N/m. He accidentally slips and falls freely for 0.921 m before the rope runs out of slack. How much is the rope stretched when it breaks his fall and momentarily brings him to rest
Answers
Answer:
\(d=0.59m\)
Explanation:
From the question we are told that:
Mass \(m=67.3 kg\)
Spring constant \(\mu=1.23 * 10^3 N/m\)
Fall Height \(h=0.921m\)
Generally the Energy theorem equation for momentum is mathematically given by
Change in KE=Work done by gravity + work done by spring
\(0=mg*(h + d) - \frac{\mu d^2}{2}\)
\(0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}\)
\(0=608.1-660.213d-615d^2\)
Solving Quadratic equation
\(d=0.59m\)
a uniform electric fi eld of magnitude 327 n/c is directed along the y-axis. a 5.40-mc charge moves from the ori- gin to the point (x, y) (15.0 cm, 32.0 cm). (a) what is the change in the potential energy associated with this charge? (b) through what potential difference did the charge move?
Answers
The change in potential energy associated with the charge is 0.056 J and the charge moved through a potential difference of 118 V
(a) To calculate the change in potential energy associated with the charge, we can use the formula:
ΔPE = qΔV
where,
ΔPE is the change in potential energy,
q is the charge, and
ΔV is the change in electric potential.
Since the charge is moving in a uniform electric field, the electric potential is given by:
V = Ed
where,
E is the magnitude of the electric field and
d is the distance moved.
Thus, the change in potential energy is:
ΔPE = q(Vf - Vi)
= q(EΔy)
where ,
Vi is the initial potential,
Vf is the final potential, and
Δy is the vertical displacement of the charge.
Plugging in the given values, we get:
ΔPE = (5.40 × 10^-6 C)(327 N/C)(0.32 m)
= 0.056 J
Therefore, the change in potential energy associated with the charge is 0.056 J.
(b) To find the potential difference through which the charge moved, we can use the formula:
ΔV = Vf - Vi
where,
Vi is the initial potential and
Vf is the final potential.
Since the potential at the origin is zero, the initial potential is zero. The final potential can be found using the formula:
Vf = Ed
where,
d is the total distance moved by the charge.
The distance moved by the charge is the hypotenuse of a right triangle with sides of 0.15 m and 0.32 m, so we have:
d = √(0.15^2 + 0.32^2)
= 0.36 m
Thus, the final potential is:
Vf = (327 N/C)(0.36 m)
= 118 V/m
Therefore, the potential difference through which the charge moved is:
ΔV = Vf - Vi
= 118 V
Therefore, the charge moved through a potential difference of 118 V.
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The si unit for acceleration is blank
Answers
Answer:
meters per second squared
Explanation:
Because acceleration is equal to velocity over time where velocity is meters per second and time is measured in seconds making acceleration ms-2
Convert 350.0mL at 740 K to its new volume at standard temperature
Answers
Answer:
129.12 ml
Explanation:
If answer is correct feel free to replay me for explanation.
What type of circuit is seen in this picture?
-Open
-Parallel
-Series
-AC
Answers
Answer:
You need the attachment, sorry I can't answer :(
Answer:
It is short thats what the awnser is
Bill is farsighted and has a near point located 125 cm from his eyes. Anne is also farsighted, but her near point is 75.0 cm from her eyes. Both have glasses that correct their vision to a normal near point (25.0 cm from the eyes), and both wear the glasses 2.0 cm from the eyes. Relative to the eyes, what is the closest object that can be seen clearly (a) by Anne when she wears Bill's glasses and (b) by Bill when he wears Anne's glasses
Answers
Answer:
a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes
b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes
Explanation:
The point where Bill has a near point = 125 cm
The point where Anne has a near point = 75.0 cm
Their vision are both corrected to the normal near point = 25.0 cm
The distance of their glasses from the eye, d = 2.0 cm
The lens formula is presented as follows;
\(\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}\)
The required distance of the of the object from Bill's glass, \(d_{oB}\) = 25 cm - 2.0 cm = 23.0 cm
The distance of the of the image from Bill's glass, \(d_{iB}\) = -(125 cm - 2.0 cm) = -123 cm
Therefore, for Bill, we have;
\(\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}\)
Plugging in the values gives;
\(\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}\)
Therefore;
\(f_B\) = 2,829/100 cm = 28.29 cm
The required distance of the of the object from Anne's glass, \(d_{oA}\) = 25 cm - 2.0 cm = 23.0 cm
The distance of the of the image from Anne's glass, \(d_{iA}\) = -(75 cm - 2 cm) = -73 cm
The focal length for Anne is therefore;
\(\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}\)
Plugging in the values gives;
\(\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}\)
Therefore, we have;
\(f_A\) = 1,679/50 cm = 33.58 cm
a) When Anne wears Bill's lasses, we have;
\(\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}\)
Therefore, we get;
\(\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}\)
\(\dfrac{1}{d_{0A}} = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}\)
\(d_{0A}\) ≈ 20.39 cm
The distance of the closest object Anne can see, from her eye, \(d_{oe}\) = \(d_{0A}\) + d
∴ \(d_{oe}\) ≈ 20.39 cm + 2.0 cm = 22.39 cm
The distance of the closest object Anne can see, from her eye, \(d_{oe}\) ≈ 22.39 cm
b) The closest object that can be seen when Bill wears Anne's glasses, we have;
\(\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}\)
Therefore;
\(\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}\)
\(\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}\)
∴ \(d_{oB}\) ≈ 26.38 cm
The closest object Bill can see while wearing Anne's glasses, \(d_{oB}\) ≈ 26.38 cm.
]
If you use the same force to push a truck and push a car which one
will have more acceleration and why?
O The car because it has less mass
O The truck because it has more mass
O The truck because it has less mass
The car because it has more mass
Answers
Answer:
I think is the The truck because it has more mass
how is mass related to momentum???
Answers
the formula for (momentum) P = (force) F * (Mass) M
P = FM
if mass = 0 momentum = 0
Hope this helps...
Answer:
In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object. ... The equation illustrates that momentum is directly proportional to an object's mass and directly proportional to the object's velocity. The units for momentum would be mass units times velocity uni
Explanation:
the energy gap in intrinsic silicon is 1.1 ev. assuming the fermi energy lies at the middle of the gap, a. what is the occupation probability at the bottom of the conduction band at 300 k? b. what is the occupation probability at the top of the valence band at 300 k? hint: the answer is not exactly 1.
Answers
a. The probability of occupation of states in the conduction band can be calculated using the Fermi-Dirac distribution function:
f(E) = 1 / [exp((E - Ef)/(kT)) + 1]
where E is the energy of the state, Ef is the Fermi energy, k is Boltzmann's constant, and T is the temperature. At the bottom of the conduction band, the energy is E = Ec = 1.1 eV. Assuming room temperature (T = 300 K), we can calculate the occupation probability:
Therefore, the occupation probability at the top of the valence band is 0.9995.
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an am radio transmitter radiates 500 kw at a frequency of 760 khz. how many photons per second does the emitter emit?
Answers
The AM radio transmitter emits approximately 9.94 x \(10^{31}\) photons per second.
To calculate the number of photons emitted per second by an AM radio transmitter, we'll need to use the following terms and equations:
Power (P): This is the amount of energy transferred or converted per unit time. In this case, the transmitter radiates 500 kW (kilowatts).
Frequency (f): The number of cycles of a periodic wave that occur in a unit of time. In this case, the frequency is 760 kHz (kilohertz).
Planck's constant (h): A fundamental constant with a value of approximately 6.626 x \(10^{-34}\) Js (joule-seconds). This constant relates the energy of a photon to its frequency.
The energy (E) of a single photon can be calculated using the equation:
E = h x f
Next, we need to convert the power and frequency to the appropriate units:
P = 500 kW x 1,000 (to convert kW to W) = 500,000 W
f = 760 kHz x 1,000 (to convert kHz to Hz) = 760,000 Hz
Now, we can calculate the energy of a single photon:
E = (6.626 x 10^-34 Js) * (760,000 Hz) = 5.035 x \(10^{-28}\) J
To find the number of photons emitted per second (n), we will divide the total power (P) by the energy per photon (E):
n = P / E
n = (500,000 W) / (5.035 x \(10^{-28}\) J)
n ≈ 9.94 x \(10^{31}\) photons per second
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When light shines on a sample, each element emits specific wavelengths producing a unique fingerprint called its ______ spectra.
Answers
When light shines on a sample, each element emit specific wavelength producing a fingerprint called its line spectra.
When light falls on a shining surface it makes a specific pattern.
These patterns are either in the form of bright lights are in the form of dark lights which are uniform in nature providing a particular pattern for each and every light.
This line spectra is the result of the light of different frequencies emitted by the excitation and releasing of electrons from there respective orbitals in an atom.
Basically these line spectra provides a fingerprint of the specific wavelength emitted by each element.
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a force of 10n causes a spring to extend by 2mm find a,the spring constant of the spring in N/w b,the extension of the spring when 25N is applied c,the force applied that caused an extension of 5mm
Answers
a. Use Hooke's law to find the spring constant k :
F = kx ⇒ 10 N = k (2 mm) = k (0.002 m) ⇒ k = 5000 N/m
b. Use Hooke's law again to find the extension x given a force of 25 N :
F = kx ⇒ 25 N = (5000 N/m) x ⇒ x = 0.005 m = 5 mm
c. We end up with the same force as in part (b) :
F = kx ⇒ F = (5000 N/m) (5 mm) = (5000 N/m) (0.005 m) = 25 N
A plane electromagnetic wave of intensity 8 W/m^2 strikes a dark surface of area 51 cm^2 perpendicular to the approaching wave and is completely absorbed. Find the force that the wave exerts on the mirror in picoNewton.
Enter an interger.
Answers
To find the force that the electromagnetic wave exerts on the surface in pico-Newtons,
1. Convert the intensity and area into SI units:
Intensity (I) = 8 W/m^2
Area (A) = 51 cm^2 = 51 * 10^-4 m^2
2. Calculate the energy absorbed per second by the surface:
Energy per second (E) = Intensity * Area = 8 W/m^2 * 51 * 10^-4 m^2 = 0.408 W
3. Find the momentum transferred per second to the surface:
Momentum per second (p) = Energy per second / speed of light (c)
p = 0.408 W / (3 * 10^8 m/s) = 1.36 * 10^-9 kg m/s
4. Calculate the force exerted on the surface:
Force (F) = Momentum per second / time
Since momentum is transferred per second, the force will be equal to the momentum per second.
F = 1.36 * 10^-9 N
5. Convert the force into pico-Newtons:
Force (F) = 1.36 * 10^-9 N * (10^12 pN/N) = 1360 pN
So the force that the wave exerts on the surface is approximately 1360 pico-Newtons.
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