Two balloons have equal and opposite charges. Balloon one has N = 107 excess electrons. The balloons are separated by d = 1.4 m and each electron has a negative charge of e = 1.602 × 10-19 C. What is the charge on balloon two, Q2, in C?
Answers
The charge on balloon two, Q2, is +1.602 × 10⁻¹² C.
To find the charge on balloon two, first determine the total charge on balloon one. Since balloon one has N = 10⁷ excess electrons, each with a charge of e = 1.602 × 10⁻¹⁹ C, we can calculate the total charge by multiplying the number of electrons by the charge per electron:
Q1 = N × e = 10⁷ × 1.602 × 10⁻¹⁹ C = 1.602 × 10⁻¹² C
Since the balloons have equal and opposite charges, the charge on balloon two, Q2, is the opposite of the charge on balloon one:
Q2 = -Q1 = -1.602 × 10⁻¹² C = +1.602 × 10⁻¹² C
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Related Questions
What are some common positive and negative attitudes toward physical activities? What
is your personal attitude toward exercise and physical activity? What three emotions do
you immediately feel when you think about your health and fitness? What is the
relationship between physical fitness and health? How does physical fitness affect your
personal health?
Answers
the common attributes are positive and negatively charged
Question 1
1 points)
Will any two objects dropped from the same height hit the ground at the same time if air resistance is not a
factor?
A) scientific
B) non-scientific
Answers
Based on the Radioactive Decay chart in the reading, which of the following elements would emit destructive radioactive material? a. Plutonium b. Carbon c. Hafnium d. Thorium
Answers
Based on the Radioactive Decay chart in the reading, Plutonium is the element that would emit destructive radioactive material, therefore the correct answer is option A
What is radioactivity?This radiation is released when a nucleus undergoes radioactive decay and transforms into a different isotope that may be radioactive (unstable) or non-radioactive depending on the number of neutrons and protons in the nucleus (stable).in other words one can say The ability of some unstable atoms to emit nuclear radiation spontaneously
Thus, Plutonium is the element that would emit destructive radioactive material, according to the radioactive decay chart in the reading, so option A is the appropriate response.
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A 4.3-kg bat is traveling 21 m/s just before it strikes a 2.5-kg baseball that’s moving 37 m/s. After the collision, the bat travels in the same direction at 19 m/s. What is the baseball’s speed just after impact?
Answers
The speed of the baseball is 30.38m/s .
We are given that,
The mass of bat = m₁ = 4.3 kg
The mass of baseball = m₂ = 2.5 kg
The initial velocity of bat = v₁ = 37 m/s
The final velocity of bat = v₁' = 19 m/s
So that the speed in baseball can be calculated from the law of conservation of momentum which can be given as,
mₙvₙ = m₁v₁ +m₂v₂
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
Where, vₙ is the speed of the baseball after impact, mₙ is the total mass of the system ,
(4.3kg + 2.5kg)vₙ = (4.3kg × 37m/s) + (2.5kg × 19m/s)
(6.8kg) vₙ = 159.1kg-m/s + 47.5kg-m/s
vₙ = (206.6kg-m/s)/6.8kg
vₙ = 30.38 m/s
Therefore, the speed of the baseball would be 30.38m/s after impact.
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A car accelerates from rest to a speed of v. Later, on a highway it accelerates from v to 2v. Which takes more energy, going from 0 to v, or from v to 2v?
Answers
Answer:
I believe 0 to V sorry if im wrong
Explanation:
What is something that you would like to see a physicist develop in the future?
Answers
Answer:
teleportation (artificial or natural over wormholes )
Which of the following is NOT considered to be an acceptable use for recycled water?
a.
drinking
b.
irrigating
c.
concrete mixing
d.
toilet flushing
Answers
Answer:
A. DrinkingHope it helps
Brainliest po
a is right answer
Order the following transportation modes by propulsive efficiency, with the lowest first. Medium size U.S. car - one passenger Peak hour city bus Helicopter Small motor cycle
Answers
The order of transportation modes by propulsive efficiency, from the lowest first, would be:
1. Helicopter
2. Small motorcycle
3. Medium size U.S. car - one passenger
4. Peak-hour city bus
This is because helicopters and small motorcycles typically have less efficient motors and require more fuel to operate compared to cars and buses. Additionally, peak-hour city buses tend to have larger and more efficient motors to transport a larger number of passengers at once.
Keep in mind that factors such as load, fuel efficiency, and operating conditions can influence the actual propulsive efficiency of each transportation mode.
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A reheat Rankine cycle operates with water as the working fluid. Steam enters the first turbine at 8 MPa and 450°C and exits at 0.8 MPa. It is then reheated to 400°C before entering the second turbine, where it exits at 10 kPa. If the amount of work into the pump is 8.04 kJ/kg and the net work per cycle produced is 1410.25 kJ/kg, determine the thermal efficiency of the cycle
Answers
Answer:
The thermal efficiency, \(\eta _{reheat}\), of the Rankine cycle with reheat is 36.81%
Explanation:
p₁ = 8 MPa = 80 Bars
T₁ = 450°C = 723.15 K
From steam tables, we have;
v₁ = 0.0381970 m³/kg
h₁ = 3273.23 kJ/kg
s₁ = 6.5577 kJ/(kg·K) = s₂
The p₂ = 0.8 MPa
T₂ = Saturation temperature at 0.8 MPa = 170.414°C = 443.564 K
h₂ = 2768.30 kJ/kg
\(T_{2'}\) = 400°C = 673.15 K
\(h_{2'}\) = at 400°C and 0.8 MPa = 3480.6 kJ/kg
p₃ = 10 kPa = 0.1 Bar
T₃ = Saturation temperature at 10 kPa = 45.805 °C = 318.955 K
h₃ = 2583.89 kJ/kg
h₄ = \(h_{3f}\) = 191.812 kJ/kg
The thermal efficiency, \(\eta _{reheat}\), of a Rankine cycle with reheat is given as follows;
\(\eta _{reheat} = \dfrac{\left (h_{1}-h_{2} \right )+\left (h_{2'}-h_{3} \right )-W_{p}}{h_{1}-\left (h_{4}+W_{p} \right )+\left (h_{2'}-h_{2} \right )}\)
Therefore, we have;
\(\eta _{reheat} = \dfrac{(3273.23 -2768.30 ) + (3480.6 -2583.89 ) - 8.04)}{(3273.23 -(191.812 + 8.04) + (3480.6 -2768.30 ) } = 0.3681\)
Which in percentage is 36.81%.
A 10cm long, 2cm wide wooden wedge is pushed into a soft wood block calculate the load on the soft wood if the effort applied id 30 N
Answers
The velocity ratio of the wedge is 0.1
The load on the soft wood is 300 N.
PLEASE HELP!! HURRYY
If a step down transformer has 220 V coming into the primary coil of 30 turns and 140 V is coming out of the second coil, how many turns in are in the secondary coil?
a.) 30
b.) 19
c.) 0.05
d.) 7
Answers
Answer:
We can use the formula for the transformer voltage ratio, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage:
Np/Ns = Vp/Vs
where Np is the number of turns in the primary coil, Ns is the number of turns in the secondary coil, Vp is the input voltage, and Vs is the output voltage.
We know that Vp = 220 V and Vs = 140 V, and we are trying to find Ns. We also know that Np = 30, since that is the number of turns in the primary coil. Substituting these values into the formula, we get:
30/Ns = 220/140
Simplifying the right side of the equation, we get:
30/Ns = 11/7
Cross-multiplying, we get:
11Ns = 210
Dividing both sides by 11, we get:
Ns = 19
Therefore, the answer is b.) 19.
Consider the system shown in the figure. The rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the 8.00-kg block and the tabletop is m_k=.25 . The blocks are released from rest.Use energy methods to calculate the speed of the 6.00-kg block after it has descended 1.50 m. How do i calculate work on the 8kg block.
Answers
Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m. In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.
Energy Method Block SpeedTo calculate the speed of the 6.00-kg block after it has descended 1.50 m, you can use the conservation of mechanical energy. The initial mechanical energy of the system is the potential energy of the 6.00-kg block (mgh) and the potential energy of the 8.00-kg block (mgh). As the blocks move, some of this energy is converted into kinetic energy, and some is lost to friction. The equation for the conservation of mechanical energy is:
E_initial = E_final + W_friction
Where E_initial is the initial mechanical energy of the system, E_final is the final mechanical energy of the system, and W_friction is the work done by friction.
The final mechanical energy of the system is the kinetic energy of the 6.00-kg block (1/2 mv²) and the potential energy of the 8.00-kg block (mgh).
To calculate the work done by friction, you can use the equation:
W_friction = force x distance x cos(theta)
Where force is the force of friction, distance is the distance over which the force of friction acts, and theta is the angle between the force of friction and the displacement. The force of friction is the coefficient of kinetic friction times the normal force.
In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.
W_friction = m_kF_nd
Where m_k = 0.25 is the coefficient of kinetic friction, F_n = 8*9.8 N is the normal force, and d = 1.5m is the distance that the 8kg block moves.
Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m.
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What do the lines and numbers on the chromosome represent?
A) Organelles
B) Mutations
C) Genes
D) Proteins
Answers
Which force requires contact?
Answers
Answer:
Explanation:
where is the question
A rock falls off a cliff with an acceleration of -9.8 m/s^2 and hits the ground 5 s later . How high is the diff?
Answers
3. The potential energy of an object is determined by: a. the movement of the object b. the position of the object c. the speed of the object d. Objects cannot have potential energy.
Answers
Answer:
B. the position of the object
What variable affects the natural frequency of an organ pipe?A) Pipe WidthB) Pipe lengthC) Pipe areaD) Pipe use
Answers
The resonance frequency relies simply on the length of both the organ pipe. The right answer is (c), which states that the frequency of the open organ pipe is 300 Hz.
Why does natural frequency change?
The object's content, size, construction, weight, and form all affect the natural frequency measurement. If we exert a vibrating force on the item that possesses a frequency equal to the inherent frequency of the material, it is a resonance situation.
What impact does a pipe's length have on frequency?
The diameter of the tube should not matter because lengthening the tube reduces frequency. According to a more detailed prediction, the diameter does have a minor effect by mildly raising the actual length of the conduit as the diameter expands.
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Which statement about Sagittarius A* is true?
A: It is a quasar.
B: It orbits our sun.
C: It is 26,000 light-years away from earth.
D: It is set to subsume the earth in 100,000 years.
Answers
Answer:
It orbits our sun is the correct answer
Sagittarius A* is 26,000 light-years away from earth. Hence, option (C) is correct.
What is Sagittarius A*?Sagittarius A* (Sgr A*), a supermassive black hole at the center of the Milky Way Galaxy with a mass equal to four million Suns, is seen in the constellation of Sagittarius. It is a powerful radio source that is a part of the larger Sagittarius A complex.
One of Chandra's largest observing missions to date led to these new discoveries. In order to obtain the first-ever X-ray photos and energy fingerprints of the multi-million degree plasma swirling around Sgr A*, a black hole with around 4 million times the mass of the Sun, Chandra made observations over the course of nearly five weeks in 2012.
Sgr A* is one of the very few black holes in the cosmos where we can really observe the flow of stuff close by, and it is only 26,000 light years away from Earth.
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a satellite is deployed from a space shuttle into an orbit which goes alternately north and south of the equator. its distance from the equator over time can be approximated by a sine wave. it reaches 4500 km, its farthest point north of the equator, 15 minutes after the launch. half an orbit later it is 4500 km south of the equator, its farthest point south. one complete orbit takes 2 hours. (a) find an equation of a sinusoidal function that models the distance of the satellite from the equator as a function of time in hours.
Answers
A. =4500 60 (+15) an equation of a sinusoidal function that models the distance of the satellite from the equator as a function of time in hours. ,B. -3181.98 km south of the equator .
How would you represent a sinusoidal function in an equation?The methods below show how to build a sinusoidal functions equation in the form y = Asin(B(x - C)) + D given its graph. D: Calculate D by averaging the sinusoid's regional maximum and minimum. The "midline," or the line on which the sinusoid is centered, is defined as y=D.
What can a sinusoidal function model?A sinusoidal function can be used as a model for items that display periodic behavior since these functions.
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can anyone help me plsss
Answers
#a
Distance travelled=30m#b
Distance travelled=50m#c
Total distance =50m+30m=80m#d
\(\\ \sf\bull\dashrightarrow Avg\:speed=\dfrac{Total\:Distance}{Total\:Time}=\dfrac{30}{10}=3m/s\)
#e
\(\\ \sf\bull\dashrightarrow Avg\:Speed=\dfrac{50}{5}=10m/s\)
#f
\(\\ \sf\bull\dashrightarrow Avg\:Speed=\dfrac{50+30}{10+5}=\dfrac{80}{15}=5.3m/s\)
#g
Displacement=30m#h
Displacement=50m#i
Total displacement=30-50=|-20|=20m#j
Same answer as option d#k
Same ans as option e#l
\(\\ \sf\bull\dashrightarrow Avg\:velocity=\dfrac{Total\:Displacement}{Time}=\dfrac{20}{15}=1.3m/s\)
If an object moves 21m north 16m east and 26m south what is the displacement of the object?
Answers
Explanation:
the net displacement of an object is
X-coordinate is
16.
Y-coordinate is
21-26=-5.
The magnitude of displacement is
d=√(〖16〗^2+(-5)^2 )=17 blocks.
The direction is
θ=tan^(-1)〖5/16〗=17° east of south.
therefore, I think it helps you.
which of the following sequences correctly describe the evolution stage of the low-massive star like our sun?A).. White dwarf, red giant, main-sequence, protostar
B)..Red giant, main-sequence, white dwarf, protostar
C).. Protostar, red giant, main-sequence, white dwarf
D)..Protostar, main-sequence, white dwarf, red giant
E)..Protostar, main-sequence, red giant, white dwarf
Answers
The correct sequence describing the evolution stage of a low-massive star like our sun is option E: Protostar, main-sequence, red giant, white dwarf. During its formation, the star starts as a protostar, where gravitational forces contract the gas and dust into a dense core.
As the protostar accumulates more mass, it enters the main-sequence phase, where nuclear fusion occurs and the star emits energy. After exhausting its hydrogen fuel, the star swells into a red giant, where the outer layers expand and cool.
Finally, the red giant sheds its outer layers, exposing the core, which collapses into a white dwarf.
This sequence is typical for low-massive stars like our sun, while high-massive stars follow a different evolution path.
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The volume of air in the room is 76.4 m³. The density of the air is 1.2 kg/m³.
Calculate the mass of air in the room.
Answers
Answer:
The mass of air in the room is 91.68 kg.
Explanation:
In order to find the mass of air in the room, given that the volume of the air is 76.4 m³ and its density is 1.2 kg/m³, we can use the following formula:
\(\boxed{\mathrm {Mass = Density \times Volume}}\)
Substituting the given values into the equation, we get:
\(\mathrm{Mass = 1.2 \: kg/m^3 \times 76.4 \: m^3}\)
\(= \bf 91.68 \: \mathrm{\bf kg}\)
We have that this is an exercise on the density of liquids and gases.
We have that your data is:
Volume (v) = 76.4 m³Density (d) = 1.2 kg/m³.Mass (m) = ?To calculate the mass. We multiply the density by the volume. Therefore, we apply the following formula:
m = d·v
We substitute our data in the formula and solve
m = (1.2 kg/m³)·(76.4 m³)
m = 91.7 kg
Therefore, the mass of air in the room is 91.7 kg.
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what do you understand by the term current state and define its SI unit.........
Answers
Answer:
Explanation:
Current refer to the rate at which electric charge flow or run or move in an electric circuit . It is measured in Ampere or coulumb per second.
The SI unit is Ampere and it is represented by A. It is a scalar quantity.
1 Ampere is the current that will produce an attractive force of 2 × 10^-7 Newton per meter of length between two parallel conductors.
Near the surface of the Earth a block of mass M and initial velocity 16.97 m/s is sliding to the
right along the (negative) x-axis. The surface is frictionless for x < 0. At x = 0 the block encounters a 45° incline ramp. If the block stops at a height h = 9.8 m, what is the kinetic
coefficient of friction of the ramp?
a. 0.50
b. 0.25
c. 0.75
d. 0.35
e. 0.20
Answers
The correct answer for the kinetic coefficient of friction of the ramp is 0.25.
First, we need to find the initial kinetic energy of the block. We can do this using the equation KE = (1/2)mv², where m is the mass of the block and v is its initial velocity. Plugging in the given values, we get:
KE = (1/2)M(16.97)² = 144.32M
Next, we need to find the work done by friction on the ramp. This can be found using the equation W = Fd, where F is the force of friction and d is the distance the block travels up the ramp. The force of friction can be found using the equation F = μN, where μ is the coefficient of friction and N is the normal force. The normal force on an inclined plane is equal to mgcosθ, where m is the mass of the block, g is the acceleration due to gravity, and θ is the angle of the incline. Plugging in the given values, we get:
F = μM(9.8)cos45° = 6.93μM
The distance the block travels up the ramp can be found using the Pythagorean theorem, since the ramp forms a right triangle with the horizontal and vertical distances. The horizontal distance is equal to the height of the ramp, which is given as 9.8 m. So we get:
d = √(9.8² + 9.8²) = 13.86 m
Now we can plug the values for F and d into the equation for work to get:
W = (6.93μM)(13.86) = 96.03μM
The work done by friction is equal to the change in kinetic energy, so we can set the two equations equal to each other and solve for μ:
144.32M - 96.03μM = 0
μ = 144.32/96.03 = 1.502
Finally, we can plug this value of μ into the equation for the coefficient of friction to get:
μ = F/N = (6.93μM)/(M(9.8)cos45°) = 0.25
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Which two types of electromagnetic waves have higher frequencies than the waves that make up ultraviolet light?
o radio waves and infrared light
O visible light and X-rays
O microwaves and gamma rays
gamma rays and X-rays
Answers
Answer:
Gamma rays and x rays
Explanation: just took the test
Gamma rays and X-rays have higher frequencies than the waves that make up ultraviolet light. Hence option D is correct.
What is Electromagnetic Spectrum ?Electromagnetic spectrum is nothing but the range of wavelengths or frequencies on which electromagnetic radiation extend. it is whole distribution of electromagnetic waves according to frequency or wavelength. Electromagnetic wave is nothing but a photon which carries energy. Photon wave has frequency, wavelength as well as amplitude.
Electromagnetic spectrum is show in figure.
There is inverse relation between wavelength and frequency as υ = c/λ
where υ is the frequency, λ is the wavelength and c is the speed of light.
as wavelength increases, frequency decreases vice verse.
In this figure we can see that radio waves has highest wavelength hence it has lowest frequency. X ray and gamma rays has lowest wavelength hence it has highest frequency.
Hence option D is correct.
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what do you mean by pressure
Answers
P=F/A
A certain car is capable of accelerating at a rate of 0.56 m/s2. How long does it take for this car to go from a speed of 54 mi/h to a speed of 62 mi/h
Answers
The time it takes for the car to go from 54 mi/h to 62 mi/h is: Total time = 43.1 s + 6.43 s = 49.53 s.
A car that can accelerate at a rate of 0.56 m/s2 can go from a speed of 54 mi/h to a speed of 62 mi/h within 10.8 seconds. We will use the following formula to solve this problem. vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time interval. Since we are dealing with different units (mi/h and m/s2), we will convert the initial and final velocities into m/s and use the same unit for acceleration.54 mi/h = 24.13 m/s62 mi/h = 27.73 m/sΔv = 27.73 - 24.13 = 3.6 m/st = Δv / a = 3.6 / 0.56 = 6.43 s Since the problem asks for the time interval it takes for the car to go from 54 mi/h to 62 mi/h, we need to find the time it takes for the car to accelerate from 54 mi/h to 62 mi/h.
To do that, we need to subtract the time it takes for the car to go from 0 mi/h to 54 mi/h from the total time it takes for the car to go from 0 mi/h to 62 mi/h. Using the same formula, we can find the time it takes for the car to go from 0 mi/h to 54 mi/h: vi = 0 mi/h = 0 m/svf = 54 mi/h = 24.13 m/sΔv = 24.13 - 0 = 24.13 m/st = Δv / a = 24.13 / 0.56 = 43.1 s Therefore, the time it takes for the car to go from 54 mi/h to 62 mi/h is: Total time = 43.1 s + 6.43 s = 49.53 s.
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In 1912, Alfred Wegener proposed his continental drift theory and was widely rejected. Imagine if you had to assist Wegener in proving that we live on huge plates that are constantly in motion. Luckily, you also have provided resources such as videos and articles to compile your evidence and help Wegener. Present your research using an interactive PowerPoint or Storyboard while answering the below questions.
1. What does the theory of plate tectonics state?
2. What was Pangaea?
3. Why was Wegener's original idea about continental drift referred to as intuition and not science?
4. What did Wegener find that he believed was evidence to support his theory?
Evidence for plate tectonics
Research the evidence that scientists used to prove the theory that continents move.
Research rock formation evidence and give examples.
Research fossils evidence
o Research fossil evidence of the following organisms: Glossopteris, Mesosaurus, Cynognathus and Lystrosaurus. Summarize the type of organisms, their habitat and climate conditions.
5. Research evidence from glaciers and coal deposits.
Answers
Answer:
1. The theory of plate tectonics states that the Earth's outer shell is divided into several plates that move and interact with each other. These plates are made up of the Earth's crust and the upper part of the mantle, and they move due to the convection currents in the mantle.
2. Pangaea was a supercontinent that existed about 300 million years ago. It was made up of all the continents that we know today, and it began to break apart about 200 million years ago.
3. Wegener's original idea about continental drift was referred to as intuition and not science because he did not have a mechanism to explain how the continents moved. Additionally, he did not have enough evidence to support his theory.
4. Wegener found several pieces of evidence that he believed supported his theory of continental drift. He noticed that the coastlines of South America and Africa fit together like puzzle pieces, and he also found similar rock formations and fossils on both continents.
Evidence for plate tectonics:
Rock formation evidence: Scientists have found similar rock formations on different continents that were once connected. For example, the Appalachian Mountains in North America and the Caledonian Mountains in Europe have similar rock formations.
Fossil evidence: Scientists have found fossils of the same species on different continents that were once connected. For example, the Glossopteris plant was found in South America, Africa, India, Australia, and Antarctica. This suggests that these continents were once connected and had similar climates.
Glossopteris: Glossopteris was a plant that lived about 250 million years ago. It was found on several continents that were once connected, including South America, Africa, India, Australia, and Antarctica. This suggests that these continents were once connected and had similar climates.
Mesosaurus: Mesosaurus was a freshwater reptile that lived about 300 million years ago. Its fossils have been found in South America and Africa, which suggests that these continents were once connected and had similar habitats.
Cynognathus: Cynognathus was a carnivorous mammal-like reptile that lived about 250 million years ago. Its fossils have been found in South America, Africa, and Antarctica, which suggests that these continents were once connected and had similar habitats.
Lystrosaurus: Lystrosaurus was a herbivorous mammal-like reptile that lived about 250 million years ago. Its fossils have been found in South America, Africa, India, and Antarctica, which suggests that these continents were once connected and had similar habitats.
Glacier and coal deposit evidence: Scientists have found evidence of glaciers and coal deposits in areas that are now near the equator. This suggests that these areas were once located near the poles and have moved due to plate tectonics. Additionally, coal deposits found in Antarctica suggest that it was once located in a warmer climate.
Reference frame definitely changes when also changes