two people part company and walk along perpendicular paths. one person walks 1 km/h faster than the other. they are 6 km apart after one hour. we need to find the rate at which each person walks.

Answers

Answer 1

The rate at which each person walks is 3.71 km/h and 4.71km/h.

Let's call the rate of speed of the slower person "r" (in km/h). Then the rate of the faster person is "r + 1" km/h.

We know that after one hour, the distance between them is 6 km. This means that the slower person has traveled a distance of "r" km, and the faster person has traveled a distance of "r + 1" km. Since they are walking along perpendicular paths, these distances form the legs of a right triangle, with the distance between them forming the hypotenuse:

r² + (r + 1)² = 6²

Simplifying the left side:

r² + r² + 2r + 1 = 36

Combining like terms:

2r² + 2r - 35 = 0

Using the quadratic formula:

r = (-2 ± √(2^2 - 4(2)(-35))) / (2(2))

r = (-2 ± √(284)) / 4

r ≈ 3.71 km/h or r ≈ -4.71 km/h

We can ignore the negative value since the rate should be positive. So, the slower person walks at a rate of approximately 3.71 km/h, and the faster person walks at a rate of approximately 4.71 km/h (since the faster person walks 1 km/h faster than the slower person).

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Related Questions

consider two straight wires lying on the x axis, sep- arated by a gap of 4 nanometers. the potential ener- gy in the gap is about 3 ev higher than the energy of a conduction electron in either wire. what is the probability that a conduction electron in one wire ar- riving at the gap will pass through the gap into the other wire

Answers

The probability of a conduction electron in one wire passing through the gap into the other wire is very low.

This is because the potential energy in the gap is about 3 eV higher than the energy of a conduction electron in either wire. The energy difference is too large for the electron to simply jump across the gap, and it would need to gain energy from somewhere in order to do so.

Tunneling is a quantum mechanical phenomenon that allows particles to pass through barriers that would classically be impossible to cross. In the case of an electron in a semiconductor, tunneling could occur if the electron were to gain enough energy from the electric field of the other wire.

However, the electric field would need to be very strong in order to provide enough energy for the electron to tunnel across the gap. The probability of this happening is very low, and it is much more likely that the electron will simply reflect off of the barrier and remain in the original wire.

The probability of tunneling can be calculated using a mathematical equation called the Fermi golden rule. This equation takes into account the energy difference between the two states, the strength of the electric field, and the mass of the electron.

The probability of tunneling is very small for small energy differences and weak electric fields. However, the probability of tunneling increases as the energy difference and electric field strength increase.

In the case of the two wires described in the question, the energy difference is 3 eV and the electric field is very weak. This means that the probability of tunneling is very low. It is much more likely that the electron will simply reflect off of the barrier and remain in the original wire.

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in an oscillating lc circuit, the maximum charge on the capacitor is 7.0 ✕ 10−6 c and the maximum current through the inductor is 9.5 ma. (a) What is the period of the oscillations?(b) How much time elapses between an instant when the capacitor is uncharged and the next instant when it is fully charged?

Answers

T = 2π√(L * C)Assuming we have the capacitance value, we can calculate the period (T) and then find the time elapsed between the uncharged and fully charged instants by dividing T by 2.

To determine the period of the capacitancein the LC capacitance, we can use the relationship between the capacitance(L) and the capacitance (C):

(a) The capacitance(T) of the oscillations can be calculated using the formula:

T = 2π√(L * C)

(b) The time elapsed between the instant when the capacitor is capacitanceand the next instant when it is fully charged is half of the period, since the charging and capacitancecycles of the LC circuit are capacitance.

Let's solve the equations using the given values:

(a) Maximum charge on the capacitor: \(Q = 7.0 × 10^(-6) C\)

Maximum current through the inductor: \(I = 9.5 × 10^(-3) A\)

We can calculate the capacitance using the formula:

Q = C * V, where V is the voltage across the capacitor when it is fully charged.

Since the voltage across the capacitor is not provided, we need more information to calculate the capacitance accurately.

(b) Assuming we have the capacitance value, we can calculate the period (T) and then find the time elapsed between the uncharged and fully charged instants by dividing T by 2.

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In a uniform electric field, which statement is correct? A All charged particles experience the same force. B All charged particles move with the same velocity. C All electric field lines are directed towards positive charges. D All electric field lines are parallel.

Answers

Answer:

D. All electric field lines are parallel in a uniform electric field

In an action-reaction pair
a. action force is exerted first

b. action force and the reaction force are equal in magnitude and act in the same direction.

c. action force and the reaction force are contact forces only.

d. action force and the reaction force act on two different objects.

Answers

In an action-reaction pair, action force and th reaction force act on two different objects.Newton's Third Law of Motion states, "To every action, there is an equal and opposite reaction; action and reaction act on two different bodies."The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.

Answer:

d. action force and the reaction force act on two different objects.

Hope you could understand.

If you have any query, feel free to ask.

In an action-reaction pair, action force and the reaction force act on two different objects.

What is Newton's Third Law of Motion?

Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."

It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.

When considering the options,

The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.

So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.

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What is the mass of a tennis ball traveling with a velocity of 3 m/s and a momentum of
0.25 m/s? (1 point)
a. 0.08 kg
b. 0.5 kg
c. 9 kg
d. 18 kg

Answers

Answer:

Explanation:

P = mv  

m = P/v

m = .25/3 = .08 Kg ... A

Ethics are deliberately learned from the family. Please select the best answer from the choices provided

Answers

Answer:

what are the choices provided?

Explanation:

Answer:

True

Explanation:

On Edg

If a ball is rolling down a hill, it has both kinetic and potential energy. The ball has
38 J of potential energy because of its height and 80J of kinetic energy because
of its motion. How much mechanical energy does the ball have

Answers

The answer is 118 J :)

Explanation:

38 +80 = 118.

A positive charge of 0.049 C moves horizontally to the right at a speed of 272.4 m/s and enters a magnetic field directed vertically downward. If it experiences a force of 22.394 N, what is the magnetic field strength ?

Answers

The magnitude of the force F experienced by a charge q that moves in a direction perpendicular to a magnetic field B with a speed v is given by:

\(F=qvB\)

Isolate B from the equation:

\(B=\frac{F}{qv}\)

Replace F=22.394N, q=0.049C and v=272.4m/s to find the strength of the magnetic field:

\(B=\frac{22.394N}{(0.049C)(272.4\frac{m}{s})}=1.6778...T\approx1.7T\)

Therefore, the magnetic field strength is approximately 1.7T.

x Methane, has a molar mass of 16.03 grams per mole. How many particles o of methane are present in 120 grams?

Answers

In order to determine the number of particles of methane, use the following expression:

number of particles = (mass /molar mass ) x Avogadro's number

in this case, you have:

molar mass = 16.03 grams/mole

mass = 120 grams

Avogadro's number = 6.02*10²³ particles/mol

replace the previos values of the parameters into the formula for the number of particles:

number of particles=(120 grams/ 16.03 grams/ mol)x(6.02*10²³particles/mol)

= (7.46 mol) x (6.02*10²³ particles/mol)

= 4.50*10²⁴ particles

Hence, the number of particles of methane, in 120 grams, is 4.50*10²⁴

the total amount of fresh water on earth is estimated to be 3.73 x 108 km3 . what is this volume in cubic meters?

Answers

The total amount of fresh water on Earth is approximately 3.73 x 10¹⁷ cubic meters.

To convert the volume of fresh water on Earth from cubic kilometers (km³) to cubic meters (m³), you can use the following conversion:

1 km³ = 1,000,000,000 m³ (since 1 km = 1,000 m)

Given that the total amount of fresh water on Earth is estimated to be 3.73 x 10⁸ km³, you can calculate the volume in cubic meters as follows:

(3.73 x 10⁸ km³) * (1,000,000,000 m³/km³) = 3.73 x 10^17 m³

So, the total amount of fresh water on Earth is approximately 3.73 x 10¹⁷ cubic meters.

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If a person could travel at the speed of light, it would still take 4.3 years to reach the nearest
star, Proxima Centauri. How far away, in meters, is Proxima Centauri?

Answers

Answer:

4 × 10^16 m

Explanation:

\(c=\frac{d}{t}\)

d = c × t

\(d = 3 * 10^{8} *4.3 * 365.25 * 24 * 60 60 = 4 * 10^{16} meters\)

Answer:

proxima centauri Is 40208000000000km or ( about 268.770AU.) away from our planet

what is a rocket engine that fires against the direction a spacecraft is headed so the spacecraft slows down?

Answers

The rocket engine that fires against the direction a spacecraft is headed so the spacecraft slows down is called Retro engine.

Spacecraft are the space automobiles that might be capable of flying out of doors of the Earth’s ecosystem in the area. They offer us a method of transportation from the Earth to the area and objects in it. There may be numerous spacecraft that are familiar to most of people e.g. Apollo 11 which took Neil Armstrong and his group to the Moon.

Crewed Spacecraft – Crewed spacecraft are the ones that carry people to the area. There have been several crewed spacecraft to the area consisting of Vostok 1 – the first crewed spacecraft in records dispatched by way of the United States of America.

Earth-Orbit Satellites – all of the satellites, which orbit across the Earth, fall in this class. The maximum tremendous satellite in orbit on the Earth is Hubble Telescope.

Space Probe – these are unmanned spacecraft that might be fitted with medical instruments for exploring objects in space e.g. planets, Moon, and solar.

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In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The collision is cushioned by a spring (k = 1200 N/m).
a) Determine the velocity of each cart after the collision.
b) Determine the maximum compression of the spring.

Answers

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

\(m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m\)

a)

The final velocity of cart 1 after collision is given as:

\(v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\ Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s\)

The final velocity of cart 2 after collision is given as:

\(v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\ Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s\)

b) Using the law of conservation of energy:

\(\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm\)

what property of gases describes the amount of space taken up by the gas?

Answers

Answer:

High pressure

The amount of space a gas's molecules take up compared to the total space in the container—the molecules' relative volume—gets bigger.

Explanation:

A spring-mass system has a spring constant of 20 lb/in and the mass weighs 25 lb. If the system's amplitude in resonance after 2.25 cycles is 1.57 inches, what is the system's amplitude in resonance after 7.75 cycles?

Answers

The system's amplitude after 7.75 cycles is determined as 2.9 inches.

What is the system's amplitude in resonance after 7.75 cycles?

The system's amplitude after 7.75 cycles is calculated by applying the following equations as follows;

A ∝ √ n

where;

A is the amplitude of the waven is the number of cycles

A = k√ n

A₁ /√n₁  = A₂/√n₂

A₂ = √n₂ x (A₁ /√n₁)

when the initial amplitude is 1.57 in, at 2.25 cycles, the amplitude of the wave after 7.75 cycles is calculated as;

A₂ = √7.75 x (1.57 /√2.25)

A₂ = 2.9 inches

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How does information travel during transcription?
a) RNA to amino acid
b) DNA to amino acid
c) DNA to RNA
d) RNA to DNA

Answers

Answer: c) DNA to RNA

Which is NOT a part of transverse waves?
A. wavelength
B. trough
C. compression
D. crest

Which is NOT a part of transverse waves?A. wavelengthB. troughC. compressionD. crest

Answers

Answer:

C. Compression

Explanation:

✧✧✧EMOTIONAL DAMAGE✧✧✧

kleann

1. Which will speed up the rate of a chemical
reaction?
A Lower the temperature
B. Use less substance
C. Increase the surface area
D. Increase the amount of time

Answers

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The cosmic background radiation is observed to come from:.

Answers

The cosmic background radiation is observed to come from all directions in space.

The cosmic background radiation is a faint glow of electromagnetic radiation that pervades the entire universe. It was first discovered in 1964 by two astronomers, Arno Penzias and Robert Wilson, who were working on a radio antenna at Bell Labs in New Jersey. They found that their antenna was picking up a constant noise from all directions in the sky, even when they pointed it away from known sources of radiation.
Further studies showed that this noise was not coming from any nearby sources, but rather from the entire universe itself. The cosmic background radiation is thought to be the leftover heat from the Big Bang, the event that created the universe around 13.8 billion years ago. As the universe expanded and cooled, this radiation became stretched out and cooled down as well, until it reached the microwave frequencies that we can observe today.

Thus, the cosmic background radiation is observed to come from all directions in space, and it is thought to be the residual heat left over from the Big Bang. Its discovery was a key piece of evidence for the Big Bang theory and has greatly contributed to our understanding of the origins and evolution of the universe.

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a uniform solid sphere rolls down an incline_ (a)What must be the incline angle if the linear acceleration of the center of the sphere is to have magnitude 0f 0.70g7 78,5217
(b)if a frictionless block were to slide down the incline at that angle, would its acceleration magnitude be more less than; or equal to 0.70g? a. The acceleration magnitude would be equal to 0.70g_ b. The acceleration magnitude would be less than 0.70g. c. The acceleration magnitude would be more than 0.70g Be sure that you can explain why?

Answers

A.The incline angle needs to be around 78.52° for the sphere to accelerate linearly at 0.70g.

B. The right answer is c. More than 0.70g of acceleration would be experienced.

(a) To find the incline angle for the uniform solid sphere with linear acceleration 0.70g, we can use the equation for the acceleration of a rolling sphere down an incline:

a = (5/7) * g * sin(theta)

Where a is the linear acceleration, g is the gravitational acceleration (9.81 m/s²), and theta is the incline angle. We are given a = 0.70g, so we can solve for theta:

0.70g = (5/7) * g * sin(theta)

Divide both sides by g:

0.70 = (5/7) * sin(theta)

Now, divide both sides by (5/7):

(0.70 * 7)/5 = sin(theta)

0.98 = sin(theta)

To find the angle, take the inverse sine of 0.98:

theta = sin^(-1)(0.98) ≈ 78.52°

So, the incline angle must be approximately 78.52° for the sphere to have a linear acceleration of 0.70g.

(b) If a frictionless block were to slide down the incline at that angle, its acceleration magnitude would be more than 0.70g. This is because the sphere's acceleration is reduced due to its rotation. A frictionless block doesn't have any rotation, so its acceleration down the incline is given by:

a_block = g * sin(theta)

Since sin(theta) is greater than the (5/7) factor in the sphere's acceleration equation, the acceleration of the frictionless block will be more than 0.70g. Therefore, the correct answer is c. The acceleration magnitude would be more than 0.70g.

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A uniform solid sphere rolls down an incline, the incline angle if the linear acceleration of the center of the sphere is to have magnitude 0.70g can be determined using-

The linear acceleration of the center of a uniform solid sphere rolling down an inclined plane is determined by the inclination angle of the plane.

It is determined by the formula a= g sin θ, where g is the acceleration due to gravity and θ is the angle of inclination.

For the linear acceleration of the center of the sphere to have a magnitude of 0.70g, we substitute 0.70g for a in the formula.

\(θ = sin⁻¹ (0.70) = 44.92°\)

Therefore, the inclination angle must be approximately 44.92 degrees for the linear acceleration of the center of the sphere to have a magnitude of 0.70g.

(b) If a frictionless block were to slide down the incline at that incline angle, would its acceleration magnitude be more less than or equal to 0.70g?

The acceleration of a frictionless block sliding down an inclined plane is determined by the formula a= g sin θ, where g is the acceleration due to gravity and θ is the angle of inclination.

Since the inclination angle of the plane is the same as in part (a), we can substitute 44.92° for θ in the formula

\(a= g sin θ = 9.81 × sin 44.92° = 6.78 m/s²\)

Since the magnitude of the acceleration of the block is less than 0.70g, the acceleration magnitude would be less than 0.70g. Therefore, option (b) is the correct answer.

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9 Two wells are located at points A and B respectively. Point C is the middle point between A and B. When water is pumped out from Well A only, the drawdown at C is 7 in. if water is pumped out from well A whle water is poured in from well B at the same rate, what is the drawdown(ft) at point C?

Answers

Answer:

0

Explanation:

When water is pumped out of well A, it causes a drop of 7 inches at point C; if water is pumped from well B into well A (at the same rate the water is pumped out of well A), then it will give a rise of 7 inches at well C. Therefore the net drawdown at well C is:

S = 7-7 = 0

Which energy source contributes to the greatest emissions of gases in the environment during the energy production process?-bio fuels-fossil fuels-nuclear energy-solar energy

Answers

"The energy source that contributes to the greatest emissions of gases in the environment during the energy production process is fossil fuels." The correct option is B.

Fossil fuels, such as coal, oil, and natural gas, release large amounts of carbon dioxide (CO₂) and other pollutants into the atmosphere when burned for energy production. CO₂ is the primary greenhouse gas responsible for climate change and global warming. In addition, the extraction and transportation of fossil fuels also results in emissions of methane and other pollutants.

While nuclear energy (c) produces minimal emissions during energy production, the mining and processing of nuclear fuel can result in emissions of greenhouse gases.

Solar energy (d) and biofuels (a) are considered to be cleaner sources of energy, as they produce much lower emissions of greenhouse gases and other pollutants during energy production. However, the manufacturing and transportation of solar panels and biofuel crops can result in emissions of greenhouse gases.

Therefore, the energy source that contributes to the greatest emissions of gases in the environment during the energy production process is fossil fuels.

The given question is incomplete. The complete question is 'a. bio fuels

b. fossil fuels

c. nuclear energy

d. solar energy'

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Convert 149 °F into a °C, (b) Kelvin ​

Answers

Answer:

a.149 °F into °C

149 - 32 = 117

117 x 5 = 585

585 / 9 = 65

149 °F = 65 °C

b.149 °F into Kelvin

(149°F − 32) × 5/9 + 273.15 = 338.15K

How would the mass and weight of an object on the moon compare to the mass and weight of the same object on earth?.

Answers

The mass would stay the same, but the weight would be only 16.5%.

Explanation:

Mass is the amount of "matter" in an object, which stays the same everywhere. Weight is the force acting on an object by gravity, which changes depending on nearby bodies. In this case, weight on the moon is 16.5% of that on Earth.

the plane x y 2z = 30 intersects the paraboloid z = x2 y2 in an ellipse. find the points on the ellipse that are nearest to and farthest from the origin.

Answers

The points nearest to the origin on the ellipse of intersection are (1, 1, 2) and (-1, -1, 2), while the farthest points are (3, 3, 18) and (-3, -3, 18).

What are the nearest and farthest points on the ellipse?

To find the points on the ellipse of intersection that are nearest and farthest from the origin, we need to solve the system of equations formed by the plane equation and the paraboloid equation.

Substituting the expression for z from the paraboloid equation into the plane equation, we have xy2 - x²*y² = 30. This equation represents the ellipse of intersection.

To find the nearest and farthest points, we can minimize and maximize the distance from the origin, which is equivalent to minimizing and maximizing the square of the distance.

By considering the distance squared function D² = x²+ y² + z², we can substitute the expression for z from the paraboloid equation and rewrite D^2 in terms of x and y.

Minimizing D² is equivalent to minimizing x² + y². This occurs when x = ±1 and y = ±1, resulting in the nearest points (1, 1, 2) and (-1, -1, 2).

Maximizing D²is equivalent to maximizing x² + y². This occurs when x = ±3 and y = ±3, resulting in the farthest points (3, 3, 18) and (-3, -3, 18).

Therefore, the points nearest to the origin on the ellipse of intersection are (1, 1, 2) and (-1, -1, 2), while the farthest points are (3, 3, 18) and (-3, -3, 18).

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true or false

The lower the slope of a ramp the more force needed to lift the object in an inclined plane.

Answers

if im not mistaken it is true

i’m willing to give anybody extra points plus brainliest if anybody is willing to help me with this. please help!! this is due soon.

im willing to give anybody extra points plus brainliest if anybody is willing to help me with this. please

Answers

1. The box will move to the right with a force of 50 N when a 75 N force is applied to the left.

2. The box will not move if a 50 N force us applied to the left.

For  Balanced, B or Unbalanced forces, U the correct option are:

B A person jogging at a constant speedU  A car accelerating at a green light.U Pushing a lawnmower across the yardB A cookie sitting on a plate.U Slowing down to stop at a red light.U A bowling ball knocking over pins.B A book sitting on a shelf.U A linebacker tackling a running back.B A person sitting on a chair.B A plane flying at a constant speed.

What are balanced and unbalanced?

Balanced forces are forces that do not produce an acceleration of an object. Net force will be zero.

Unbalanced forces are forces that produce an acceleration of a body. Net force will be greater than zero.

Considering the boxes:

1. Net force = 50 N

Forces to the left = 25 N + x

Forces to the right = 50 N

Net force = Force to the left + force to the right

50 N = 25 N + x - 50

x = 75 N

2. Net force = 0 N

Forces to the left = 75 N + x

Forces to the right = 125 N

Net force = Force to the left + force to the right

0 N = 75 N + x -125

x = 50 N

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sam drove 44 meters to the right . she drove 13 meter to the left . what was her displacement ? what is displacement ?

Answers

the displacement was 31

The spring mass system shown in Figure 2 is released from rest. The mass m slides vertically on the smooth rod. If the spring has a spring constant k and is unstretched at the position shown in the figure, determine the equations of motion for the mass.

Answers

Since I don't have access to the specific Figure 2 you mentioned, I won't be able to provide you with the exact equations of motion for the mass in the given system. However, I can provide you with a general framework for determining the equations of motion for a spring-mass system.

In a spring-mass system, the forces acting on the mass include the gravitational force (mg) and the spring force (kx), where m is the mass of the object, g is the acceleration due to gravity, k is the spring constant, and x is the displacement of the mass from its equilibrium position.

Using Newton's second law (F = ma), we can set up the equation of motion for the mass:

m * (d^2x/dt^2) = -kx - mg

This is a second-order linear differential equation, where (d^2x/dt^2) represents the acceleration of the mass with respect to time.

To solve this equation and obtain the equations of motion for the mass, you would need to apply appropriate initial conditions, such as the initial position and velocity of the mass.

If you can provide more specific information or a detailed description of the system in Figure 2, I can assist you further in determining the equations of motion.

About Velocity

Velocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second. Velocity or speed: the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed ​​or velocity is the quotient of the displacement with the time interval. Speed ​​or velocity is a vector quantity.

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A weightlifter lifts two 300 newton weights 1. 5 meters off the ground. How much work has he done?.

Answers

So, the value of work that he had done is 900 J.

Introduction

Hi ! Here I will discuss about the effort to raise an object. Previously, when we raised an object, the energy that we put out had to be equal to the change in potential energyHi ! Here I will discuss about the effort to raise an object. Previously, when we raised an object, the energy that we put out had to be equal to the change in potential energy that happened. This is because, the higher the height of an object, the greater value of potential energy. The equation that applies is as follows :

\( \sf{\bold{W = \Delta PE}} \)

\( \boxed{\sf{\bold{W = m \times g \times \Delta h}}} \) ... (i)

\( \boxed{\sf{\bold{W = m \times g \times (h_2 - h_1)}}} \) ... (ii)

With the following condition :

W = work (J)\( \sf{\Delta PE} \) = potential energy (J)m = mass of the object (kg)g = acceleration of the gravity (m/s²)\( \sf{\Delta h} \) = change of the height (m)\( \sf{h_1} \) = initial height or position (m)\( \sf{h_2} \) = final height or position (m)

However, because the value of w (weight of the object) is already mass multiplied by gravity (w = m × g). So :

\( \sf{W = m \times g \times \Delta h} \)

\( \boxed{\sf{\bold{W = w \times \Delta h)}}} \)

With the following condition :

W = work (J)w = weight of the object (N)m = mass of the object (kg)g = acceleration of the gravity (m/s²)

Problem Solving :

We know that :

w = weight of the object = 600 N >> See the words "two 300 N object". \( \sf{\Delta h} \) = change of the height = 1.5 m

What was asked :

W = work = ... J

Step by step :

\( \sf{W = w \times \Delta h} \)

\( \sf{W = 600 \times 1.5} \)

\( \boxed{\sf{W = 900 \: J}} \)

Conclusion :

So, the value of work that he had done is 900 J.

See More :Converting work to potential energy https://brainly.com/question/26487284
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